Find the total number of atoms in a sample of cocaine hydrochloride, C17H22CINO4 of mass 23.0 mg

Answer:

2 or more

Explanation:

There are 2 or more valid electron dot formulas—having the same number of electron pairs for a molecule or ion—can be written when a resonance structure occur as we know that Sharing of electrons takes place so that atoms achieve noble gas configurations. So, How is it that an electron dot arrangement reflects a covalent bond? An electron dot arrangement represents a pair of dots with the mutual electrons of a covalent bond.  A great energy of dissociation from bonds leads to a solid covalent bond.

Answer: 2 or more

Explanation:

Answer:

4.00 moles

Explanation:

Avogadro´s number is 6.022 x 10²³ molecules, atoms, particles, etc.

Here we are talking of atoms of copper, so 1 mol of copper is equal to 6.022 x 10²³ atoms, and we only need to setup the proportion to find the number of mol in 2.41 x 10²⁴ atoms. ( Think of it like a dozen, avogadro´s is 6.022 x 10²³ )

( 1 mol copper/ 6.022 x 10²³ atoms of copper ) x  2.41 x 10²⁴ atoms

= 4.00 moles

Answer:

The color of solution at the end point will be blue.

Explanation:

EBT is used as an indicator for complexometric titrations and acts as a chelating agent. It has a blue color, in its free form, when the pH is adjusted to 10.

On the addition of CaCl₂, EBT binds with Ca(II) and gives a red color, due to its EBT-Ca (II) complex. So, the color at the start of the titration is red.

When EDTA is added, it starts to form EDTA-Ca(II) complex. Near the endpoint, it starts to replace EBT bound to Ca, because it has a higher formation constant (Kf) for its EDTA-Ca(II) complex than EBT-Ca(II) complex. The EDTA-Ca(II) has no color so the solution shows the colour of free EBT, which is blue. Hence the color at the endpoint will be blue.

Answer:

I and II

Ionization and. Dissociation

Explanation:

Dissociation,

Is to unbundle a compound into smaller, less complex constituents that are generally able to recombine under different conditions.

Ionization or ionisation,

Is the process in which an atom or a molecule accepts or loses electrons to become negatively or positively charged, it often is accompanied by with chemical changes.

Dispersion

The act of distributing things over a wide area.

The dissolving processes that change the identity of a substance in chemistry are ionization and dissociation.

The dissolving processes that change the identity of a substance are ionization and dissociation.

Ionization occurs when a substance forms ions in a solution. For example, when hydrochloric acid (HCl) dissolves in water, it ionizes into hydrogen ions (H+) and chloride ions (Cl-).

Dissociation happens when a compound breaks apart into its constituent ions in a solution. One example is table salt (NaCl) dissociating into sodium ions (Na+) and chloride ions (Cl-) when dissolved in water.

Dispersion is the process of solute particles spreading evenly throughout a solvent, without forming ions or breaking apart into ions. Dispersion does not change the identity of the substance.

Answer:

Mass of aluminium foil = 387.57_g

Explanation:

density of aluminium foil 2.70 g/cm³,

1_yd = 91.44_cm

1_in = 2.54_cm

Length of aluminum foil = 63.2_yd = 5779.008_cm

Width of aluminium foil = 11 in = 27.94_cm

Thickness of aluminium foil = 0.00035_in. = 0.000889_cm

Volume of aluminium foil = length × width × thickness = 5779.008_cm × 27.94_cm × 0.000889_cm = 143.54_cm^3

Mass of aluminium foil = (volume of aluminium foil) × (density of aluminium foil) = 143.54_cm³ × 2.70 g/cm³ = 387.57_g

To find the mass of the aluminium foil, calculate the volume and multiply it by the density. The mass of the foil is 0.3878 grams.

To find the mass of the aluminium foil, we need to calculate the volume and then multiply it by the density. First, let's convert the dimensions to the same unit. The aluminium foil is 63.2 yd long, which is equivalent to 190.4 ft. The width is 11 in, which is 0.92 ft, and the thickness is 0.00035 in, which is 2.92e-5 ft.

The volume of the foil can be calculated by multiplying the length, width, and thickness.

V = (190.4 ft) * (0.92 ft) * (2.92e-5 ft).

This gives us a volume of 5.0634e-3 cubic feet.

Next, we need to convert the volume to cubic centimetres because the density is given in g/cm³.

There are 28.3168 cubic centimetres in one cubic foot, so the volume in cm³ is

5.0634e-3 * 28.3168 = 0.1433 cm³.

Finally, we can calculate the mass by multiplying the volume by the density.

Mass = 0.1433 cm³ * 2.70 g/cm³ = 0.3878 grams.

So, The mass of the foil is 0.3878 grams.

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Answer:

Empirical formula will be (NH₄)₃PO₄, which matches the molecular formula

Explanation:

This is the reaction:

NH₃ + H₃PO₄ → 28.2% N, 20.8% P, 8.1% H, 42.9% O

In 100 g of compound we have:

28.2 g N

20.8 g of P

8.1 g of H

42.9 g of O

Now we divide each  between the molar mass:

28.2 g / 14 g/mol = 2.01 mol

20.8 g / 30.97 g/mol = 0.671 mol

8.1 g / 1 g/mol = 8.1 mol

42.9 g / 16 g/mol =  2.68 mol

And we divide again between the lowest value of moles

2.01 mol / 0.671 mol → 3

0.671 mol / 0.671 mol → 1

8.1 mol / 0.671 mol → 12

2.68 mol / 0.671 mol → 4

Molecular formula will be: N₃PH₁₂O₄ → (NH₄)₃PO₄

Empirical formula will be (NH₄)₃PO₄, which matches the molecular formula

Answer: The acetaminophen

Explanation: Liquid-Liquid is a very important and commercial separation method used for the chemical separation and analyst of chemical mixtures. It is also known as PARTITIONING. In this technique the solute is transferred from one solvent to another of which both solvents are IMMISCIBLE OR PARTLY MISCIBLE. example in the mixture involving sodium bicarbonate,acetylsalicylic acid and acetaminophen and a binder after the binder is removed and you mix the two other components with the sodium bicarbonate the solution the acetylsalicylic acid dissolved but the acetaminophen did not meaning you could separate it from the other.

Explanation:

The electronegativity difference in C-C and C-H atoms is quite low. This means smaller the electron cloud. This further means larger bond length that is electron's are further from the nucleus.  hence,  higher potential energy of C-C and C-H bonds.

On the contrary, C-O and H-O have large difference in electronegativity( O is high electronegative element) . This means smaller bond length. Electron's near the nucleus. Thus, lower potential energy of bonds.

Answer:

The final concentration of NaI is 0.4M

Explanation:

Step 1: Data given

Initial volume of a 0.2 M NaI solution

To form a 1.0 L solution

The molar mass of NaI is 150 g/mol

Step 2: Calculate the moles of NaI

Moles NaI = 0.2M * 2.0 L = 0.4 moles

Step 3: Calculate the final concentration

Concentration = moles / volume

Concentration = 0.4 moles / 1.0L

Concentration = 0.4M

The final concentration of NaI is 0.4M

Answer:

B. frost wedging Hope i helped!

Explanation:

Answer:

B

Explanation:

Answer:

B. An ionized atom has a number of protons that is unequal to the number of electrons.

Explanation:

For a neutral atom , the number of proton and electron is equal. An ionized atom has either loss or gain electron, thereby making the number of proton and electron unequal. The answer B is true because an ionized atom has either loss or gain electron to make the number of electron and proton unequal.

Option A is incorrect because a cations holds a positive charge when it loss one or more electron not when it gains one or more electron(s). Anions possess negative charge for gaining electron(s).

Option C is not true because ions can also carry negative charges and they are called anions.

Option D is false because losing one or more electron will turn an atom to a cations.

Answer: Option (A) is the correct answer.

Explanation:

It is known that the relation between force and electric field is as follows.

                           F = qE .......... (1)

where,      F = force

                q = charge

                E = electric field

Also, we know that,   F = ma ...... (2)

Hence, equating equation (1) and (2) as follows.

                   qE = ma

or,                q = [tex]\frac{ma}{E}[/tex]  

Therefore, putting the given values into the above formula as follows.

                     q = [tex]\frac{ma}{E}[/tex]  

                        = [tex]\frac{441 g \times 13.0 m/s^{2}}{5.0 N/C}[/tex]

                        = 1.1466 C        

                        = 1.15 C (approx)

Therefore, we can conclude that the charge carried by given charge is 1.15 C.

Answer : The correct option is, (A) [tex]AlCl_3[/tex]

Explanation :

Van't Hoff factor : It is defined as the ratio of the experimental value of the colligative property to the calculated value of the colligative property.

We can determine the van't Hoff factor by the association and dissociation of the compound.

(A) [tex]AlCl_3[/tex]

It is an electrolyte that dissociates to give aluminum ion and chloride ion.

The dissociation of [tex]AlCl_3[/tex] will be,

[tex]AlCl_3\rightarrow Al^{3+}+3Cl^{-}[/tex]

So, Van't Hoff factor = Number of solute particles = [tex]Al^{3+}+3Cl^{-}[/tex] = 1 + 3 = 4

(B) [tex]KI[/tex]

It is an electrolyte that dissociates to give potassium ion and iodide ion.

The dissociation of [tex]KI[/tex] will be,

[tex]KI\rightarrow K^{+}+I^{-}[/tex]

So, Van't Hoff factor = Number of solute particles = [tex]K^{+}+I^{-}[/tex] = 1 + 1 = 2

(C) [tex]CaCl_2[/tex]

It is an electrolyte that dissociates to give calcium ion and chloride ion.

The dissociation of [tex]CaCl_2[/tex] will be,

[tex]CaCl_2\rightarrow Ca^{2+}+2Cl^{-}[/tex]

So, Van't Hoff factor = Number of solute particles = [tex]Ca^{2+}+2Cl^{-}[/tex] = 1 + 2 = 3

(D) [tex]MgSO_4[/tex]

It is an electrolyte that dissociates to give magnesium ion and sulfate ion.

The dissociation of [tex]MgSO_4[/tex] will be,

[tex]MgSO_4\rightarrow Mg^{2+}+SO_4^{2-}[/tex]

So, Van't Hoff factor = Number of solute particles = [tex]Mg^{2+}+SO_4^{2-}[/tex] = 1 + 1 = 2

(E) Non-electrolyte

The dissociation non-electrolyte is not possible. So, the Van't Hoff factor will always be, 1.

Hence, the highest van't Hoff factor of solute is, [tex]AlCl_3[/tex]

Van't Hoff factor: It is defined as the ratio of the experimental value of the colligative property to the calculated value of the colligative property.

The correct answer is A) [tex]ALCL_3[/tex]

The van't hoff factor is decided by the number of ions present in the compound.

In option A there are 4 ions that are [tex]AL^3+ and \ CL^-[/tex].

According to the concept, the ions for other options are  4, 1, 3, and, 1 respectively.

The correct option is A.

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Answer:

Empathetic listening

Answer:

Option (A)

Explanation:

Thus, all these three processes are mainly implemented in order to reduce soil erosion, which usually takes place due to agents like wind and water.

Hence, the correct answer is option (A).

Answer:

a

Explanation:

Answer:

correct answer is a) primary air pollutants

Explanation:

solution

primary air pollutants material are that material which release pose health risk in the unmodified form and they emitted directly from identifiable source not react so they are primary air pollutant

and some major material released directly into the atmosphere as unmodified are given below

they all are primary air pollutants

so correct answer is is a) primary air pollutants

Answer:

16.933g approximately 17.0 grams

Explanation:

From the simple promotions and given the same compound ascorbic acid (vitamin C)

In the laboratory synthesised ascorbic acid

Mass of carbon = 30.0g

Mas of Oxygen = 40.0g

That is the mass of Oxygen per unit mass of Carbon

Per gram of Carbon we have

(30.0g Carbon)÷30 combines with (40.0g of Oxygen)÷30

That is 4/3g of Oxygen per gram of Carbon

Hence the mass of Oxygen compound that combines with 12.7g of Carbonin natural occurring ascorbic acid (vitamin C) is = 4/3×12.7 = 16.933g approximately 17.0g

The amount of oxygen in the second sample, calculated using the concept of stoichiometry and the ratio of carbon to oxygen in the first sample, is approximately 16.9 grams.

This question involves the concept of stoichiometry in Chemistry. Given the masses of carbon and oxygen in the laboratory synthetized sample, we can determine the ratio of carbon to oxygen. This is 30.0g Carbon / 40.0g Oxygen = 0.75. We assume this ratio is the same in any sample of ascorbic acid regardless of its source, because the makeup of a pure substance is always the same. Therefore, to find the amount of oxygen in the lemon-sourced sample, we can use this ratio: 12.7g Carbon / x g Oxygen = 0.75. Solving for x gives us the mass of oxygen, which is approximately 16.9g.

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Answer: The mass of nitrogen gas that must be reacted is 1.4 grams

Explanation:

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]      .....(1)

Given mass of ammonia = 1.7 g

Molar mass of ammonia = 17 g/mol

Putting values in equation 1, we get:

[tex]\text{Moles of ammonia}=\frac{1.7g}{17g/mol}=0.1mol[/tex]

The chemical equation for the production of ammonia follows:

[tex]N_2+3H_2\rightarrow 2NH_3[/tex]

By Stoichiometry of the reaction:

2 moles of ammonia is produced by 1 mole of nitrogen gas

So, 0.1 moles of ammonia will be produced from [tex]\frac{1}{2}\times 0.1=0.05mol[/tex] of nitrogen gas

Now, calculating the mass of nitrogen gas from equation 1, we get:

Molar mass of nitrogen gas = 28 g/mol

Moles of nitrogen gas = 0.05 moles

Putting values in equation 1, we get:

[tex]0.05mol=\frac{\text{Mass of nitrogen gas}}{28g/mol}\\\\\text{Mass of nitrogen gas}=(0.05mol\times 28g/mol)=1.4g[/tex]

Hence, the mass of nitrogen gas that must be reacted is 1.4 grams

Obligate anaerobes survive without oxygen by using anaerobic respiration or fermentation as their energy-producing processes. They lack normal cellular defenses against oxidative stress, which makes oxygen lethal to them. For example, Clostridium perfringens bacteria are obligate anaerobes that cannot survive in the presence of oxygen and use molecules other than oxygen as terminal electron acceptors.

Obligate anaerobes are organisms that cannot live in an environment where there is oxygen. They survive without oxygen by using anaerobic respiration or fermentation as their energy-producing processes. These organisms lack normal cellular defenses against oxidative stress, which makes oxygen lethal to them. For example, Clostridium perfringens bacteria are obligate anaerobes that cannot survive in the presence of oxygen and use molecules other than oxygen as terminal electron acceptors.

Answer:

5.04 kJ

Explanation:

We are given the enthalpy of fusion of methanol as 3.16 kJ per mol of methanol. Thus, what we need is to determine is the number of mol in 25.4 g of methanol and multiply by this enthalpy.

mol methanol = mass / MW CH₃OH = 25.6 mol / 16.04 g/mol = 1.60 mol

ΔH = 1.60 mol x 3.16 kJ/mol = 5.04 kJ

Answer:

The assumptions  we make when we infer the mass of a galaxy cluster from observations of the spectra of its constituent galaxies is thermal hydrostatic equilibrium

Explanation:

In galaxy cluster observation, thermal X-ray emission from the hot intracluster gas measures directly the gas density and temperature distributions within the cluster. This hot gas is confined by and expected to trace the underlying three-dimensional gravitational potential. Under the assumption of thermal hydrostatic equilibrium, these gas properties may be used to infer the cluster total mass distribution.

Hence, the assumptions  we make when we infer the mass of a galaxy cluster from observations of the spectra of its constituent galaxies is thermal hydrostatic.

The question refers to the method of naming covalent and ionic compounds. Covalent compounds use prefixes for both elements and a suffix for the second, while ionic compounds do not use prefixes and only have a suffix for the second element.

The given question pertains to the rule for naming compounds in chemistry. The two types of compounds referenced in the question are covalent and ionic compounds. In a covalent compound, both the first and second elements have prefixes and the second element has a suffix. An example would be N2O4, which would be named 'Dinitrogen Tetroxide'. However, in ionic compounds, there are no prefixes and only the second element has a suffix. An example would be NaCl, which is named 'Sodium Chloride'.

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Answer: choice B

Explanation: Heat flows from high to low. After you convert the Celsius into kelvin the Zn pellet has 323K and the water has 301K which results the transfer of the heat energy of the pallet to the water. ( you don’t have to convert, but it just make it easier) hope this helped you :)

Answer:

(B) Collisions between the water molecules and the surface of the Zn pellet will result in the transfer of energy, increasing the average kinetic energy of the water molecules.

Explanation:

The question above shows a case of energy transfer and movement of molecules in the generation of heat. Which can be explained as follows:

As you can see, in the question, the solid Zn pellet has a higher temperature than water. There is a physical concept that states that when two bodies of different temperatures come into contact, there is a transfer of energy between them that seeks to equal the temperature of the two bodies. For this reason, when the Zn pellet comes into contact with water, collisions will occur between the water molecules and the surface of the Zn sediment that will result in energy transfer.

However, instead of causing the temperature balance between the water and the Zn tablet, this allows the water to get a higher temperature, because the energy transmitted by zinc increases the kinetic energy of the water molecules. In this case, these tomboys start to move very fast, generating heat.

Answer:

In order to rinse the system of exhaled CO2 and meet the inspiratory flow rate requirements of infants placed on B-CPAP, the flow rate of humidified gas should be set at:

A. 16 to 20 L/minute

B. 6 to10 L/minute

C. at least 15 L/minute

D. 11 to 15 L/minute

B. 6 to10 L/minute

Explanation:

Bubble CPAP is a non-invasive, external ventilation technique used for newborn babies with infant respiratory distress syndrome (IRDS). Continuous positive airway pressure (CPAP) is given to a spontaneously breathing newborn baby to preserve lung volumes during expiration

Answer:

c. strontium is chemically similar to calcium and is incorporated into bone.

Explanation:

Strontium is a chemical element in group two which bears a great similarity with calcium in terms of chemical reactivity, ion size, etc. Hence it can easily replace calcium in the bone, causing a great damage to the individual because of its radioactivity.

Answer:

2.1 M is the molarity of the HCl solution.

Explanation:

[tex]HCl+NaOH\rightarrow H_2O+NaCl[/tex]

Molarity of HCl solution = [tex] M_1=?[/tex]

Volume of HCl solution = [tex]V_1=50.0mL[/tex]

Ionizable hydrogen ions in HCl = [tex]n_1=1[/tex]

Molarity of NaOH solution = [tex] M_2=1.05 M[/tex]

Volume of NaOH solution = [tex]V_2=100.0 mL[/tex]

Ionizable hydroxide ions in NaOH = [tex]n_2=1[/tex]

[tex]n_1M_1V_1=n_2M_2V_2[/tex] (neutralization )

[tex]M_1=\frac{M_2V_2}{V_1}=\frac{1.05M\times 100.0 mL}{50.0 mL}[/tex]

[tex]M_1=2.1 M[/tex]

2.1 M is the molarity of the HCl solution.

Final answer:

The molarity of the HCl solution is determined by calculating the heat absorbed during the reaction, converting this heat to moles of reacted NaOH, and assuming equimolar reaction with HCl. The final molarity of HCl is found to be 2.10 M.

Explanation:

To determine the molarity of the HCl solution, we first need to calculate the heat absorbed by the solution during the neutralization reaction using the specific heat capacity, mass, and change in temperature of the solution.

Calculate the Heat Absorbed by the Solution

Firstly, the total volume of the solution is the sum of the volumes of HCl and NaOH, which is 50.0 mL + 100.0 mL = 150.0 mL. The density of the solution is given as 1.02 g/mL, so the mass of the solution is 150.0 mL × 1.02 g/mL = 153.0 g.

The change in temperature (ΔT) is the final temperature minus the initial temperature, so ΔT = 30.2°C - 22.4°C = 7.8°C.

The heat absorbed (q) by the solution is calculated using the formula q = mass × specific heat × ΔT. Substituting the values, we get q = 153.0 g × 0.96 cal/g°C × 7.8°C = 1143.36 cal.

Convert Heat to Kcal and Calculate Moles of NaOH

Since q needs to be in kilocalories to use the heat of neutralization, we convert 1143.36 cal to kcal: 1143.36 cal × (1 kcal / 1000 cal) = 1.14336 kcal.

We know the heat of neutralization for HCl and NaOH is 13.6 kcal/mol. Therefore, the number of moles of NaOH reacted (which equals moles of HCl because they react 1:1) is:
moles of NaOH = 1.14336 kcal / 13.6 kcal/mol = 0.0841 mol.

Calculate Molarity of HCl

Since 100.0 mL of 1.05M NaOH contains 0.105 mol/L × 0.100 L = 0.105 mol NaOH, and we know all HCl has reacted, we can say that the moles of HCl must also be 0.105 mol.

The molarity (M) of HCl is the number of moles of HCl divided by the volume of HCl in liters. M = moles / liters = 0.105 mol / 0.050 L = 2.10 M HCl.

The ΔG°rxn at 25.0 °C for the given reaction is -4.184 KJ/mol, which means the reaction is spontaneous under standard conditions. When actual concentrations are provided, the ΔGrxn at 25.0 °C is -2.81 kJ/mol, indicating that the reaction remains spontaneous.

To calculate the ΔG°rxn at 25.0 °C, we'll be utilizing the formula ΔG° = -RT ln K, where R is the gas constant (8.314 J/mol K), T is the temperature in Kelvin (25.0 °C = 298.15 K), and K is the equilibrium constant Kf (2.5 × 10³ M^-2). The R needs to be converted to kJ from J by dividing it by 1000. Following these conversions, we can substitute these values:

ΔG° = - (8.314 x 10^-3 kJ/mol K) x (298.15 K) x ln (2.5 × 10³ M^-2) = -4.184 KJ/mol

The spontaneity of the reaction is determined by the sign of ΔG. In this case, since ΔG is negative, it indicates that the reaction is indeed spontaneous under standard conditions.

For evaluating ΔGrxn at 25.0 °C when [Ag^+]=0.00850 M, [NH₃]=0.156 M, and [[Ag(NH₃)2]^+]=0.00632 M, we must resort to the equation ΔG = ΔG° + RT ln Q, where Q is the reaction quotient. We substitute the actual concentrations into the equilibrium expression to get Q = {[Ag(NH₃)2]^+} / ([Ag^+] x [NH₃]^2) = 0.00632 / (0.00850 x (0.156)^2) = 2.666. Thus, the ΔGrxn can be calculated as ΔG = -4.184 kJ/mol + 8.314 x 10^-3 kJ/mol K x 298.15K x ln(2.666) = -2.81 kJ/mol.

As ΔGrxn remains negative even with these conditions, the reaction still remains spontaneous.

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Answer: Photons

Explanation: These are packet of light. These subatomic particles have no electrical charge and rest mass. Photons are also considered as field particles in which they are to be carriers of electromagnetic fields.

Answer:

The anion value of 21mEq/L suggest the client will have metabolic acidosis

Explanation:

Anion gap is the interval or difference between measured cations (Sodium and Potassium) with the sum of measured anions (chloride and bicarbonate)

Using the above mentioned data

(166 + 5) - (115 + 35)  =  21mEq/L

Therefore the Anion gap = 21mEq/L

Answer:

NAD+, FAD.

Explanation:

The citric acid cycle is popularly known as the Kreb's cycle. The cycle involve the oxidation of acetyl-CoA to produce energy. The Kreb's cycle is a chemical process that produces produces two carbon dioxide molecules,NADH,FADH2 and one ATP.

When oxygen is depleted, the citric acid cycle stops, apart from oxygen NAD+ and FAD could be added to the system to restore citric acid cycle activity. NAD+ acts as an electron acceptor.

Citric acid cycle/Kreb's cycle is an aerobic process that occurs in the mitochondria and produces thirty-six(36) ATPs.

To restore citric acid cycle activity when oxygen is depleted is to add an electron acceptor.

In the absence of oxygen, the electron transport chain cannot function properly because oxygen acts as the final electron acceptor in the process of oxidative phosphorylation.

When oxygen is not available, electrons accumulate, and the energy-generating process of the mitochondria is inhibited. This results in the cessation of the citric acid cycle due to the lack of NAD+ and FAD, which are required as electron carriers in the cycle.

To restore the activity of the citric acid cycle under anaerobic conditions, one could add an alternative electron acceptor that can be reduced instead of oxygen.