Find the surface area of x^2+y^2+z^2=9 that lies above the cone z= sqrt(x^@+y^2)

Answers

Answer 1
The cone equation gives

[tex]z=\sqrt{x^2+y^2}\implies z^2=x^2+y^2[/tex]

which means that the intersection of the cone and sphere occurs at

[tex]x^2+y^2+(x^2+y^2)=9\implies x^2+y^2=\dfrac92[/tex]

i.e. along the vertical cylinder of radius [tex]\dfrac3{\sqrt2}[/tex] when [tex]z=\dfrac3{\sqrt2}[/tex].

We can parameterize the spherical cap in spherical coordinates by

[tex]\mathbf r(\theta,\varphi)=\langle3\cos\theta\sin\varphi,3\sin\theta\sin\varphi,3\cos\varphi\right\rangle[/tex]

where [tex]0\le\theta\le2\pi[/tex] and [tex]0\le\varphi\le\dfrac\pi4[/tex], which follows from the fact that the radius of the sphere is 3 and the height at which the sphere and cone intersect is [tex]\dfrac3{\sqrt2}[/tex]. So the angle between the vertical line through the origin and any line through the origin normal to the sphere along the cone's surface is

[tex]\varphi=\cos^{-1}\left(\dfrac{\frac3{\sqrt2}}3\right)=\cos^{-1}\left(\dfrac1{\sqrt2}\right)=\dfrac\pi4[/tex]

Now the surface area of the cap is given by the surface integral,

[tex]\displaystyle\iint_{\text{cap}}\mathrm dS=\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}\|\mathbf r_u\times\mathbf r_v\|\,\mathrm dv\,\mathrm du[/tex]
[tex]=\displaystyle\int_{u=0}^{u=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}9\sin v\,\mathrm dv\,\mathrm du[/tex]
[tex]=-18\pi\cos v\bigg|_{v=0}^{v=\pi/4}[/tex]
[tex]=18\pi\left(1-\dfrac1{\sqrt2}\right)[/tex]
[tex]=9(2-\sqrt2)\pi[/tex]

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Not in words

Answers

1) [tex]6 = 1 - 2n + 5 [/tex]
      Reorganize the problem: [tex]6 - 1 - 2 (n) + 5 = ? [/tex]
              [tex]2(n) = 0 [/tex]
              ÷ [tex]2[/tex]  ÷ 2 
                      [tex]0 [/tex] ÷ 2 = 0, right? ; [tex]2 [/tex] ÷ [tex]2 [/tex] [tex] = 1 [/tex], right ?   [tex]0 [/tex] ÷[tex]1 = 0 [/tex]
                                 [tex]n = 0 [/tex]  

2) [tex]-5 (1 - 5x) + 5 (-8x - 2) = -4 [/tex]
          [tex]-15(x) - 11 [/tex]
                  +11    +11 
                  ---        ----
                  -4         22 
                × -1       ×-1
               -------      ------
                   4             -22 
              ÷ 15            ÷15
 [tex]x = \frac{11}{15} [/tex]

If I am missing something, please let me know so  I can finish it off 

But, good luck on your assignment! 

There are 50 competitors in the men’s ski jumping. 30 move on to the qualifying round. How many different ways can the qualifying round be selected?

Answers

Final answer:

To calculate the number of different ways 30 qualifiers can be selected from 50 competitors in a ski jumping event, use the combination formula C(n, k) = n! / (k!(n - k)!), where in this case n=50 and k=30.

Explanation:

The question here is focused on finding the number of different combinations in which the qualifying round can be selected from a group of competitors in a sport event, specifically men’s ski jumping. This falls under the category known as combinatorics, which is a part of mathematics that deals with counting, both in a concrete and abstract way, as well as finding certain properties of finite structures.

The total number of different ways 30 competitors can be chosen from a group of 50 can be found using the combination formula, which is expressed as C(n, k) = n! / (k!(n - k)!), where "n" is the total number of competitors, "k" is the number of competitors to choose, "n!" signifies the factorial of "n", and "(n - k)!" is the factorial of the difference between "n" and "k".

In this situation, to find the number of different ways to select the 30 qualifiers from 50 competitors, we plug the values into the formula to calculate C(50, 30).

Final answer:

To find the number of different ways the qualifying round can be selected, you need to use combinations. The formula for combinations is C(n, r) = n! / (r!(n-r)!), where n is the total number of competitors and r is the number of competitors moving on to the qualifying round.

Explanation:

To find the number of different ways the qualifying round can be selected, we need to use combinations. The formula for combinations is C(n, r) = n! / (r!(n-r)!), where n is the total number of competitors and r is the number of competitors moving on to the qualifying round.

In this case, n = 50 and r = 30. Plugging these values into the formula, we get C(50, 30) = 50! / (30!(50-30)!). Simplifying this expression, we find that C(50, 30) = 211915132760.

Therefore, there are 211,915,132,760 different ways the qualifying round can be selected.

Which expression is equivalent to 3(8 + 7)?

Answers

Final answer:

The expression 3(8 + 7) is equivalent to 45. The calculation follows the distributive property rule in mathematics, whereby we first simplify the expression inside the parentheses before multiplication.

Explanation:

The mathematical expression of 3(8 + 7) is based on the principle of distribution in mathematics. This principle can be interpreted as 'spread' or 'distribute' and applies when you multiply a number by addends within parentheses.

For the given expression 3(8 + 7), do the operation inside the parentheses first. So 8 + 7 equals 15. Now the expression becomes 3(15).

To find the solution, just multiply 3 by 15, which equals 45. So, 3(8 + 7) is equivalent to 45.

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Find the area of the shaded segment. Round your answer to the nearest square centimeter. Will make brainliest answer if correct :)

Answers

First find the area of the circle using A=pi*r^2
pi*36
Then divide this by 4 because the shaded region is 1/4 of the circle
(36*pi)/4=9*pi
Final answer: B

How many different triangles can be formed from four rods with lengths of 1 meter, 3 meters, 5 meters, and 7 meters?

Answers

Since there is no angle restriction in this case, therefore the one rule that is applicable to this is that in forming a triangle, the sum of the lengths of the two smaller sides (A + B) should be larger than the length of the biggest side (C):

Triangle length rule: Side A + Side B > Side C

We can see that no matter how we combine the rods, the only combination of rods that satisfies this rule is:

 Triangle formed by rods 3 meters, 5 meters, and 7 meters

 

Therefore, there is only 1 triangle that can be formed from these four rods.

How can you use integers to represent the velocity and the speed of an object?

Answers

1)The SPEED of an object tells us how fast this object is moving, bit it doesn't indicate the direction of :
Speed = distance/time

2) The VELOVITY of an object tells us how fast this object is moving and in which direction it's moving ( If UP, then it's positive. If DOWN, then it's negative. Same logic for moving right (+) or left (opposite to right, then -) 
Velocity = distance/time

In short te absolute value of Velocity = Value of speed:

| Velocity | = Speed 

For his long long distance phone service Chris pays a $6 monthly fee plus 8 cents per minute. Last month, Chris's long distance bill was $11.52. For how many minutes was Chris billed

Answers

total bill would be X=6.00 +0.08m

where m = minutes

X = total bill

so 11.52 = 6.00+0.08m

subtract 6 from each side

5.52 = 0.08m

 now divide both sides by 0.08

5.52/0.08 = 69

 he was billed for 69 minutes.

20 points PLEASE HELP WITH THIS QUESTION,, I WILL RANK HIGHEST TOO
Directions: Three families have purchased a large lot in the country and have built new homes on it. They plan to install a satellite dish on their lot. Locate the point on their lot that is equidistant (equal distance) from their 3 homes. Find the best location of the satellite dish. .

Answers

1. Use the homes to draw a triangle so that each home is one of the vertices.
2. The find the circumcenter of the triangle by drawing a line that is perpendicular to each side and that bisects the side.

The circumcenter is equidistant from each of the vertices of a triangle.

The best location for the satellite coordinates is

(Ax + Bx + Cx) / 3, (Ay + By + Cy) / 3).

We have,

From the figure given,

Assume that the coordinates of the three families are:

Sanchez = (a, b)

Perez = (c, d)

Reyes = (e, f)

The point equidistant from all three families' coordinates can be calculated using the formula.

Midpoint = ((m + o) / 2, (n + p) / 2)

Where (m, n) and (o, p) are the coordinates.

Midpoint between Sanchez and Perez:

Midpoint(SP) = A = ((a + c) / 2, (b + d) / 2)

Midpoint between Perez and Reyes:

Midpoint(PR) = B = = ((c + e) / 2, (d + f) / 2)

Midpoint between Sanchez and Reyes:

Midpoint(SR) = C = ((a + e) / 2, (b + f) / 2)

Equidistant Point

= (Ax + Bx + Cx) / 3, (Ay + By + Cy) / 3)

Where "Ax" represents the x-coordinate of the midpoint between Sanchez and Perez, Bx" represents the x-coordinate of the midpoint between Perez and Reyes, and Cx" represents the x-coordinate of the midpoint between Sanchez and Reyes. Similarly, Ay, By, and Cy" represent the y-coordinates of the respective midpoints.

Thus,

The best location for the satellite coordinates is

(Ax + Bx + Cx) / 3, (Ay + By + Cy) / 3).

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Mr. Wu is going to stock the concession stand for the Little League playoffs. He knows he will need at least twice as many hamburger buns as hotdog buns. Hamburger buns cost $0.45 each, and hotdog buns cost $0.40 each. He cannot spend more than $60 on buns. If x = the number of hamburger buns and y = the number of hotdog buns, which system of inequalities could be used to determine how many of each kind of bun Mr. Wu should purchase for the stand?

Answers

x = burger buns and y = hot dog buns

0.45x + 0.40y < = 60
x > = 2y

The system of inequalities to determine the number of hamburger and hotdog buns Mr. Wu should purchase is x \\geq 2y for the quantity requirement, and 0.45x + 0.40y \\leq 60 for the budget constraint.

To determine how many hamburger buns (x) and hotdog buns (y) Mr. Wu can purchase for the concession stand, we need to set up a system of inequalities based on the given conditions. Since he needs at least twice as many hamburger buns as hotdog buns, we can express this requirement as an inequality: x \\geq 2y. Additionally, considering the cost of hamburger buns is $0.45 each and hotdog buns are $0.40 each, the total spending should not exceed $60. This gives us a budget constraint inequality: 0.45x + 0.40y \\leq 60. Therefore, the system of inequalities that can be used to determine the number of each kind of bun Mr. Wu should purchase is:

x \\geq 2y0.45x + 0.40y \\leq 60

What must be the contact area between a suction cup (completely evacuated) and a ceiling if the cup is to support the weight of an 80.0-kg student?

Answers

Contact area must be 0.00775 m2, which is the area of a circle with 10 cm in diameter. 
Are you surprised that such a small cup is, in theory, enough to hold your weight? But it all comes from the equation of pressure: 
P = F / S 
P= Pressure, in Pascal, [P] 
F = Force, in Newton [N] 
S = Surface, in squared meters [S] 

Pressure (atmospheric) is 101325 Pascal, and the required force (as per your question) is 80Kg = 785 N. Solving for S, you get 0.00775 m2. 

You should have seen these suction cups used by glass workers, where a couple of cups are enough to lift a big piece of glass. This depends on how good the cups are and how smooth the surface of the ceiling or glass is. The idea is to have no pressure inside the cup. If you have some air inside the cup then atmospheric pressure might not be enough to hold 80Kg, as calculated.
Final answer:

The question asks for the required contact area between a suction cup and a ceiling to support an 80.0 kg person. Using principles of physics pressure calculations, a suction cup with a minimum contact area of 7.74 cm² would be needed.

Explanation:

The subject of your question is physics given it requires an understanding of pressure, force, and area relationships. To keep the suction cup adhered, the pressure difference between the lower (inside) of the suction cup and the outside (room pressure) must be large enough to support the weight of the person. This principle makes use of a simple physics equation: Pressure = Force/Area.

To support an 80.0-kg person, the force exerted due to weight would be mass multiplied by gravity or 80.0 kg * 9.8 m/s² = 784 N. The atmospheric pressure is about 101,325 Pascal (Pa) or N/m². Rearranging the equation for Pressure will give us the needed area: Area = Force/Pressure. So, the necessary contact area would be 784 N / 101325 Pa ≈ 0.00774 m² or 7.74 cm².

This means, that in ideal conditions and neglecting factors such as surface roughness, a suction cup with a contact area of at least 7.74 cm² would be needed to support an 80.0-kg person.

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Identify the domain of the exponential function shown in the following graph: (2 points) Exponential graph starting at point 0, 30000 and approaching the x axis as it moves left to right. Select one: a. all real numbers b. x ≥ 0 c. 0 ≤ x ≤ 30,000 d. 7 ≤ x ≤ 30,000

Answers

b. x>=0
You don't say it terminates but goes to infinity, therefore all values of x>=0 is the domain

Answer: b. [tex]x\geq 0[/tex] , where x is the positive real numbers.

Step-by-step explanation:

We Know that, The Set of all Possible values of independent variable is called Domain of the function.

Since, Exponential graph starting at point (0, 30000),

Thus, the initial value of value of independent variable is 0.

Also,  The given exponential function is approaching the x axis as it moves left to right.

Therefore, The Domain must contain the all positive real numbers.

Thus, the Domain of the given function is [tex]x\geq 0[/tex] , where x is the positive real numbers.

Therefore, Option b is correct.

for 2 hours, Lia drove at the speed of 60 mph ,and for the next 3 hours,at the speed of 50mph.What was Lia's average speed during this trip

Answers

[tex]\bf \begin{array}{ccllll} hours&speed\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 1&60\\ 2&60\\ 3&50\\ 4&50\\ 5&50 \end{array}\qquad \textit{average speed}\implies \cfrac{60+60+50+50+50}{5}[/tex]

The matrix a is 13 by 91. give the smallest possible dimension for nul

a.

Answers

Use the rank-nullity theorem. It says that the rank of a matrix [tex]\mathbf A[/tex], [tex]\mathrm{rank}(\mathbf A)[/tex], has the following relationship with its nullity [tex]\mathrm{null}(\mathbf A)[/tex] and its number of columns [tex]n[/tex]:

[tex]\mathrm{rank}(\mathbf A)+\mathrm{null}(\mathbf A)=n[/tex]

We're given that [tex]\mathbf A[/tex] is [tex]13\times91[/tex], i.e. has [tex]n=91[/tex] columns. The largest rank that a [tex]m\times n[/tex] matrix can have is [tex]\min\{m,n\}[/tex]; in this case, that would be 13.

So if we take [tex]\mathbf A[/tex] to be of rank 13, i.e. we maximize its rank, we must simultaneously be minimizing its nullity, so that the smallest possible value for [tex]\mathrm{null}(\mathbf A)[/tex] is given by

[tex]13+\mathrm{null}(\mathbf A)=91\implies\mathrm{null}(\mathbf A)=91-13=78[/tex]

Final answer:

The smallest possible dimension for the null space of a 13 by 91 matrix is 78. This is determined using the Rank-Nullity Theorem, taking into account that the rank of a matrix cannot exceed the number of its rows.

Explanation:

The question pertains to the dimension of the null space (also known as the nullity) of a matrix 'a.' The dimensions of matrix 'a' are 13 by 91, which means it has 13 rows and 91 columns. The null space of a matrix 'a' is the set of all vectors that, when multiplied by 'a,' give the zero vector. The dimension of the null space is referred to as the nullity of 'a.'

To find the smallest possible dimension of the null space, we consider the Rank-Nullity Theorem, which states that for any matrix 'A' of size m by n, the rank of 'A' plus the nullity of 'A' is equal to n, the number of columns in 'A.' The maximum rank a matrix can have is limited by the smaller of the number of rows or columns, so for matrix 'a' with dimensions 13 by 91, the maximum rank is 13 since there are only 13 rows.

Using the Rank-Nullity Theorem, we can say:

Rank(a) + Nullity(a) = 91MaxRank(a) = 13 (Since there are only 13 rows)MaxRank(a) + Nullity(a) = 9113 + Nullity(a) = 91Nullity(a) = 91 - 13Nullity(a) = 78

Therefore, the smallest possible dimension for the null space of matrix 'a' is 78.

A plane flew for 4 hours heading south and for 6 hours heading east. If the total distance traveled was 3,370 miles, and the plane traveled 45 miles per hour faster heading south, at what speed was the plane traveling east?

Answers

We know the total distance and individual times, so we can sum and equate total distance.

Let
E=speed heading east
E+45=speed heading south
then
4(E+45)+6E=3370 miles
Solve for E:
4E+180+6E=3370
10E=3370-180=3190 mph
E=319 mph.

The plane was traveling at 319 miles per hour heading east. This was determined by setting up equations for the distances covered in both directions, considering the speed difference, and solving for the eastward speed.

To find the speed at which the plane was traveling east, we need to set up two equations based on the given information.

Let's denote the speed of the plane heading east  [tex]v_e[/tex] and the speed of the plane heading south [tex]v_s[/tex]. According to the problem, [tex]v_s[/tex] = [tex]v_e[/tex] + 45 mph. We also know that the plane flew south for 4 hours and east for 6 hours, covering a total distance of 3,370 miles.

To represent the sum of distances covered in both directions, we use the equation:

4[tex]v_s[/tex] + 6[tex]v_e[/tex] = 3,370

Substituting [tex]v_s[/tex] with [tex]v_e[/tex] + 45 in the equation yields:

4([tex]v_e[/tex] + 45) + 6[tex]v_e[/tex] = 3,370

By simplifying and solving for [tex]v_e[/tex], we find the speed of the plane traveling east. Let's solve it step by step:

4[tex]v_e[/tex] + 180 + 6[tex]v_e[/tex] = 3,370

10[tex]v_e[/tex] + 180 = 3,370

10[tex]v_e[/tex] = 3,190

[tex]v_e[/tex] = 319 mph

Therefore, the plane was traveling at 319 miles per hour heading east.

If a boatman rows his boat 35km up stream and 55km downstream in 12 hours and he can row 30km upstream and 44 km downstream in 10hr , then the speed of the stream and that of the boat in still water

Answers

To solve this problem, let us assume linear motion so that we can use the equation:

t = d / v

where t is time, d is distance and v is velocity

 

First let us assign some variables, let us say that the velocity upstream is Vu while Velocity downstream is Vd, so that:

35 / Vu + 55 / Vd = 12                     ---> 1

30 / Vu + 44 / Vd = 10                     ---> 2

 

We rewrite equation 1 in terms of Vu:

(35 / Vu + 55 / Vd = 12) Vu

35 + 55 Vu / Vd = 12 Vu

12 Vu – 55 Vu / Vd = 35

Vu (12 – 55 / Vd) = 35

Vu = 35 / (12 – 55 / Vd)                  ---> 3

 

Also rewriting equation 2 to in terms of Vu:

Vu = 30 / (10 – 44 / Vd)                  ---> 4

 

Equating 3 and 4:

35 / (12 – 55 / Vd) = 30 / (10 – 44 / Vd)   

35 (10 – 44 / Vd) = 30 (12 – 55 / Vd)

Multiply both sides by Vd:

350 Vd – 1540 = 360 Vd – 1650

10 Vd = 110

Vd = 11 km / h

Using equation 3 to solve for Vu:

Vu = 35 / (12 – 55 / 11)

Vu = 5 km / h

 

Answers:

Vu = 5 km / h = velocity upstream

Vd = 11 km / h = velocity downstream

 

Reducing the original price of an item is often called

Answers

Should be markdown, but if you have other options let me know and I'll tell you which it is.  But if markdown is one of your choices, or if this is fill-in, it's markdown.

Answer:

Price reduction.

Step-by-step explanation:

The act of reducing the selling price of products in order to attract costumers is called Price Reduction. This comprehends a marketing strategy.

Jean-pierre consumes only apples and bananas. he prefers more apples to less, but he gets tired of bananas. if he consumes fewer than 28 bananas per week, he thinks that one banana is a perfect substitute for one apple. but you would have to pay him one apple for each banana beyond 28 that he consumes. the indifference curve that passes through the consumption bundle with 31 apples and 40 bananas also pass through the bundle with x apples and 23 bananas, where x equals:

Answers

Bundle (31 , 40) has 40 bananas.
So 40 - 28 = 12 bananas
These 12 banana give the consumer negative utility which will be balance one for one apple.
So we have to need 12 apple to balance it.
So the final utility of apples and banana is 28 + (31 - 12) = 28 + 19 = 43
In second bundle (X , 23) has 23 bananas. We need to get the same utility 43.
Which we will get from 43 - 23 = 20 apples.
So X equal to 23.

The Perimeter of a rectangle is 66 feet and the width is 7 feet. What's the length in feet?

Please explain how to solve this problem-a)26;b)52;c)40;d)20

Answers

To solve for the length of a perimeter, use
L = P/2﹣w
L = 66/2 - 7
L = 33 - 7
L = 26

The length is 26

A manufacturer knows that their items have a normally distributed lifespan, with a mean of 2.4 years, and standard deviation of 0.7 years. the 8% of items with the shortest lifespan will last less than how many years? give your answer to one decimal place.

Answers

To solve this problem, we make use of the z statistic. We are to look for the bottom 8% who has the shortest lifespan, this is equivalent to a proportion of P = 0.08. Using the standard distribution tables for z, the value of z corresponding to this P value is:

z = -1.4

 

Now given the z and standard deviation s and the mean u, we can calculate for the number of years of the shortest lifespan:

x = z s + u

x = -1.4 (0.7) + 2.4

x = -0.98 + 2.4

x = 1.42 years

 

Therefore the life span is less than about 1.42 years

find the sum
5^71+5^72+5^73=?

Answers

OK: 1312901068244165525555899876053445041179656982421875
What is the purpose??

4^2(2^3-3)^1+8(2-1)^10

Answers

Hello Brainly User.

You must use PEMDAS 
4^2(2^3-3)^1+8(2-1)^10
4^2(5)^1+8(1)^10
16(5)+8(1) 
80+8
88

Feel free to contact me with your questions. I am more than happy to help. :)

ABCD is a parallelogram. If m

Answers

angle C would be 65. based on the theorem, to get angle C you will need to subtract 65 from 115.

Answer:

65

Step-by-step explanation:

A teacher has 3 hours to grade all the papers submitted by the 35 students in her class. She gets through the first 5 papers in 30 minutes. How much faster does she have to work to grade the remaining papers in the allotted time/4347395/f56da09a?utm_source=registration

Answers

The current grading rate is
(30 minute)/(5 papers) = 6 minutes/paper.

She has 3 hours (or 180 minutes) to grade 35 papers.
She now has 180 - 30 = 150 minutes left, and she has  35- 5 = 30 papers left.

The remaining grading rate is
(150 minutes)/(30 papers) = 5 minutes/paper

Therefore she must work at 1 minute/paper faster to complete grading 35 papers in 3 hours.

Answer: She should work faster at an increased rate of  1 minute per paper.

the sum of two numbers is 8 if one number is subtracted from the other the result is -4

Answers

a + b = 8
a - b = -4

a = b - 4
(b - 4) + b = 8
2b - 4 = 8
2b = 12
b = 6
a + 6 = 8
a = 2

a = 2
b = 6

2 + 6 = 8
2 - 6 = -4
Use these formulas:

x + y = 8
x - y = -4

Find x. The units are in feet.

Answers

Using similarity properties you know that:

x/12 = (x+6)/18

Now you can solve that equation:

18x = 12(x+6)

18x = 12x + 12*6

18x - 12x = 72

6x = 72

x = 72/6

x= 12

Answer: x is 12 feet

How to factor 4(x+5)^3(x-1)^2-(x+5)^4 • 2 (x-1) by grouping?

Answers

[tex]\bf 4(x+5)^3(x-1)^2-(x+5)^4\cdot 2(x-1) \\\\\\ 4(x+5)^3(x-1)^2-2(x-1)(x+5)^4 \\\\\\ \underline{2}\cdot 2\underline{(x+5)^3}(x-1)\underline{(x-1)}~-~\underline{2}\underline{(x-1)}(x+5)\underline{(x+5)^3}\leftarrow \begin{array}{llll} notice~the\\ common\\ \underline{factors} \end{array} \\\\\\ 2(x+5)^3(x-1)~[~2(x-1)-(x+5)~] \\\\\\ 2(x+5)^3(x-1)~[2x-2-x-5]\implies 2(x+5)^3(x-1)(x-7)[/tex]

Integration of (cosec^2 x-2005)÷cos^2005 x dx is

Answers

we are asked in the problem to evaluate the integral of (cosec^2 x-2005)÷cos^2005 x dx. The function is an example of a complex function with a degree that is greater than one and that uses special rules to integrate the function via the trigonometric functions. For example, we integrate 
2005/cos^2005x dx which is equal to 2005 sec^2005 x since sec is the inverse of cos. The integral of this function when n >3 is equal to I=∫sec(n−2)xdx+∫tanxsec(n−3)x(secxtanx)dx
Then, 
∫tanxsec(n−3)x(secxtanx)dx=tanxsec(n−2)x/(n−2)−1/(n−2)I
we can then integrate the function by substituting n by 3.

On the first term csc^2 2005x / cos^2005 x we can use the trigonometric identity csc^2 x = 1 + cot^2 x to simplify the terms

15 tan^3 x=5 tan x Find all solutions of the equation in the interval [0, 2π). (Enter your answers as a comma-separated list. If there is no solution, enter NO SOLUTION.)

Answers

Final answer:

The solutions to the equation 15 tan^3 x=5 tan x in the interval [0, 2π) are approximately x = 0.6155, x = 3.757, x =2.527, x = 5.669.

Explanation:

The trigonometric equation provided in the question is 15 tan3 x=5 tan x. We can start solving this equation by dividing both sides by tan x, which gives 15 tan2 x = 5. Dividing again by 5, we get tan2 x = 1/3. The solutions to tan2 x = 1/3 are values of x in the interval [0, 2π) where the square of the tangent of x equals 1/3. However, these values cannot be easily computed, thus we use a calculator to approximate the results. We find the solutions to the equation by considering all angles whose tangent is either sqrt(1/3) or -sqrt(1/3). Therefore, the solutions for x in the interval [0, 2π) are approximately x = 0.6155, x = 3.757, x = 2.527, x = 5.669.

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What are the domain and range of f(x)=1/5x

Answers

Domain: -∞<x<∞
Range: -∞<y<∞

(-) stands for negative

If r is the radius of the circle and d is it diameter ,which of the following is an equivalent formula for the circumference c=2pir

Answers

to calculate circumference you can either use

 2 x PI x r

 or

pi x d

Answer:

PI X D

Step-by-step explanation:

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