Fernanda looked at a sample of paint under a microscope. At right is the sketch she made of what she saw. Label A points to the solid particles of pigment that give the paint its color. The solid particles are the . Label B represents the liquid surrounding the solid particles. This liquid is called the for this mixture. This paint does not settle over time, so it is an example of a .

Answer : The concentration of silver ion is, [tex]3.8\times 10^{-3}M[/tex]

Explanation :

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.

As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.

The given equilibrium reaction is,

[tex]Ag_2S(s)\rightleftharpoons 2Ag^+(aq)+S^{2-}(aq)[/tex]

The expression of [tex]K[/tex] will be,

[tex]K_{eq}=[Ag^+]^2[S^{2-}][/tex]

[tex]2.4\times 10^{-4}=(2.5\times 110^{-1})^2[S^{2-}][/tex]

[tex][S^{2-}]=3.8\times 10^{-3}M[/tex]

Therefore, the concentration of silver ion is, [tex]3.8\times 10^{-3}M[/tex]

3.84 x 10⁻³ M

Given:

Question:

What is [S²⁻] at equilibrium?

The Process:

For the reaction [tex]\boxed{ \ Ag_2S_{(s)} \rightleftharpoons 2Ag^+_{(aq)} + S^{2-}_{(aq)} \ }[/tex], we can observe that the substances on the right-hand side have a solution phase (aq) that is allowed into the equilibrium constant K.

Remember, pure solids (s) and liquids (l) are disregarded and kept at 1.

Therefore, from the initial formula [tex]\boxed{ \ K = \frac{ [Ag^+]^2.[S^{2-}] }{[Ag_2S]} \ }[/tex] we get the final result [tex]\boxed{ \ K = [Ag^+]^2.[S^{2-}] \ }[/tex].

Let us find out [S²⁻] at equilibrium.

[tex]\boxed{ \ K_{eq} = [Ag^+]^2.[S^{2-}] \ }[/tex]

[tex]\boxed{ \ 2.4 \times 10^{-4} = [2.5 \times 10^{-1}]^2.[S^{2-}] \ }[/tex]

[tex]\boxed{ \ 2.4 \times 10^{-4} = 6.25 \times 10^{-2} \cdot [S^{2-}] \ }[/tex]

[tex]\boxed{ \ [S^{2-}] = \frac{2.4 \times 10^{-4}}{6.25 \times 10^{-2}} \ }[/tex]

Thus we get [S²⁻] at equilibrium equal to [tex]\boxed{ \ [S^{2-}] = 3.84 \times 10^{-3} \ M \ }[/tex]

- - - - - - - - - -

Notes:  

Hi there nice to meet u thank you

A. solutions and colloids

Answer: 21.9

Explanation:

I got it right

Answer:

a. 0.31 g

Explanation:

So, 70 days represent (70 days/ 14 days = 5.0 half-lives).

10 g → (first half-life = 14 days) 5 g → (second half-life = 28 days) 1.5 g → (third half-life = 42 days) 1.25 g → (fourth half-life = 56 days) 0.625 g → (fifth half-life = 70 days) 0.3125 g.

So, the right choice is: a. 0.31 g.

Answer:

0.31 g

Explanation:

proved the answer right below

Do you mean people become part of a 'circut' when a person becomes part of an electrical current?

Answer:

Circuit

Explanation:

People become part of the circuit

Answer: Option (B) is the correct answer.

Explanation:

Entropy is the measure of randomness present within the molecules of a substance.

When entropy of a reaction has a positive sign then it means there is an increase in the entropy. On the other hand, when entropy of a reaction has a negative sign then it means there is a decrease in entropy.

As, entropy change = entropy of products - entropy of reactants

And, larger is the value of entropy more will be the number of microstates.

When entropy is negative then entropy of products is less than the entropy of reactants.

This also means that products have small number of available energy microstates than reactants.

Thus, we can conclude that a negative change in entropy indicates that the products have a smaller number of available energy microstates than the reactants.

Answer:

A negative charge of entropy indicates that the product has a smaller number of available energy microstates than the reactants.

Explanation:

Entropy can be defined as the thermodynamic property of the system associated with the randomness of the molecules.  The energy of entropy is represented as the mathematical flow for the availability of the reactants and products.

When the entropy has a negative charge, this indicates that there is a decrease in the entropy of the system.

A positive charge of entropy indicates the increase in the energy of the system. This indicates that there is a greater number of available microstates for the product.

With a negative charge, there is a decrease i.e. the available energy microstates are smaller for the product stating the product has lesser energy as compared to the reactants.

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4.5 x 10^25 molecules of SO2

Answer:

c. triple bond

Explanation:

The shortest and strongest covalent bond is the triple bond. It involves the sharing of three pairs of electrons between two atoms, making it stronger and shorter than single and double bonds. An ionic bond is a different kind of bonding involving the transfer of electrons.

In terms of covalent bonds, the triple bond is both the shortest and the strongest. Covalent bonds are a category of chemical bonding where two atoms share one or more electron pairs. Single bonds are longer and weaker since they involve the sharing of only one pair of electrons. Double bonds involve two pairs and are shorter and stronger. Triple bonds, such as those found in a nitrogen molecule (N2), are the shortest and strongest since they involve the sharing of three pairs of electrons. The ionic bond is not a type of covalent bond, it's a completely different kind of bonding which involves the transfer of electrons from one atom to another, not sharing.

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Answer:

Energy was released when the sodium and hydroxide ions formed new bonds with the water.

Explanation:

Answer:

The lattice enthalpy of sodium hydroxide is less than the sum of hydration enthalpies of hydroxide ions and sodium ions.

Explanation:

Lattice enthalpy is defined as heat energy required to break 1 mole of crystal lattice.

Hydration enthalpy is defined as amount energy released when 1 mole of ions undergo hydration (surrounding of water molecules).It is always negative.

Enthalpy of solution = Lattice enthalpy + hydration enthalpy

Reaction between sodium hydroxide and water is an example of an exothermic reaction. During this process sodium hydroxide dissociates into sodium ions and hydroxide ions into the water.

The rise in temperature is due to hydration enthalpy of hydroxide ions and sodium ions is greater than that of the lattice enthalpy of the sodium hydroxide. This is the reason behind the warmth of the sodium hydroxide solution.

Answer:

[tex]\boxed{\text{3. All of these}}[/tex]

Explanation:

The tarnish on silverware is silver sulfide.

You can remove the tarnish by resting the silverware on a piece of aluminium foil in a pot of boiling water with a small amount of salt.

The reaction is an example of an electrochemical cell.

The half-cell reactions are

3×[Ag₂S(s) + 2e⁻ ⟶ 2Ag(s) + S²⁻(aq)]

2×[Al(s) ⟶ Al³⁺(aq) + 3e⁻]

  2Al³⁺(aq) + 3S²⁻(aq) ⟶ Al₂S₃(s)          

  3Ag₂S(s) + 2Al(s) ⟶ 6Ag(s) + Al₂S₃(s)

The aluminium ions react with the sulfide ions to form aluminium sulfide.

The aluminum atoms lose three electrons each, so they are oxidized.

The silver atoms gain one electron each, so they are reduced.

Thus, the answer is [tex]\boxed{\textbf{3. All of these}}[/tex].

Final answer:

To find the number of grams in 3 moles of A2, we can use the formula: grams = moles * molar mass. In this case, the number of grams would be 6X grams.

Explanation:

To determine the number of grams in 3 moles of A2, we need to know the molar mass of A2. Assuming A is a diatomic gas, its molar mass would be the sum of the atomic masses of the two atoms in its formula. Let's say the atomic mass of A is X and the atomic mass of B is Y. Since A2 has two atoms of A, the molar mass of A2 would be 2X. Therefore, to find the number of grams in 3 moles of A2, we can use the formula: grams = moles * molar mass. In this case, the number of grams would be 3 * 2X = 6X grams. Hence, the correct option is c.) 6.

The correct answer is c.) 6. in 3 moles of A2 (with an assumed atomic mass of 3 units for element A), there are 18 grams.

To determine the number of grams in 3 moles of A2, we first need to find the molar mass of A2. The molar mass of a substance is the mass in grams of one mole of that substance. Since A2 represents a diatomic molecule (two atoms of A), we'll calculate the molar mass by adding the atomic masses of two atoms of element A.

Looking at the periodic table, suppose the atomic mass of element A is X units. As A2 consists of two atoms of A, the molar mass of A2 is 2 * X units.

Without specific atomic masses provided, let's assume a hypothetical atomic mass of 3 units for element A. Therefore, the molar mass of A2 would be 2 * 3 = 6 units.

Now, to find the grams in 3 moles of A2, we use the formula:

[tex]\[ \text{Grams} = \text{Number of Moles} \times \text{Molar Mass} \][/tex]

Plugging in the values, we get:

[tex]\[ \text{Grams} = 3 \, \text{moles} \times 6 \, \text{units/mol} = 18 \, \text{units} \][/tex]

Thus, in 3 moles of A2 (with an assumed atomic mass of 3 units for element A), there are 18 grams.

This calculation relies on the assumed atomic mass for element A. However, the specific atomic masses for the elements A and B in the diatomic gases are essential for accurate calculations. The given question lacks this information, so the assumption of the atomic mass was necessary for computation.

Th answer is A. Hormones are chemical receptors and the x structure is taking it to the nucleus

Answer:

f.ADP

Explanation:

Answer: F. ADP

Explanation:

The level of ADP is the most important factor in the determination of the rate of Oxidative Phosphorylation.

The rate of oxygen utilization by the Mitochondria is increased when ADP is added and usually returns to its initial level when the added ADP has being converted to ATP.

Answer:

The correct answer is C) B is a base. I just did it.

Explanation:

Answer:

Based on Boyle's law, which of the following statements is true for an ideal gas at a constant temperature and mole amount?

A) Pressure is directly proportional to volume.

B) Pressure is inversely proportional to volume. CORRECT ANSWER!!!

C) The number of collisions is independent of pressure.

D) The number of collisions decreases with increase in pressure.

B is the CORRECT answer!!!

Based on Boyle's law, pressure is inversely proportional to volume is true for an ideal gas at a constant temperature and mole amount.

Boyle’s law is a gas law which states that the pressure exerted by a gas (of a given mass, kept at a constant temperature) is inversely proportional to the volume occupied by it. In other words, the pressure and volume of a gas are inversely proportional to each other as long as the temperature and the quantity of gas are kept constant.

Boyle’s law is a connection between pressure and volume. It asserts that under constant temperature, the pressure of a specific quantity of gas is inversely proportional to its volume. It is possible to prove the law empirically. The paper discusses a syringe-based experimental approach for verifying the law.

The mathematical equation for Boyle's law is, where P denotes the pressure of the system, V denotes the volume of the gas, k is a constant value representative of the temperature and volume of the system.

The correct answer is option B.

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Answer: 1.07 V

Explanation: [tex]E^0_{[Zn^{2+}/Zn}=-0.76V[/tex]

[tex]E^0_{[Cu^{2+}/Cu]}=+0.34V[/tex]

The metal with negative reduction potential will easily lose electrons and thus is oxidized and the one with positive reduction potential will easily gain electrons and thus is reduced.

[tex]Zn+Cu^{2+}\rightarrow Zn^{2+}+Cu[/tex]

[tex]E^o_{cell}[/tex] = standard electrode potential =[tex]E^0_{cathode}- E^0_{anode}=0.34-(-0.76)=1.1V[/tex]

Using Nernst equation:

[tex]E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Zn^{2+}]}{[Cu^{2+}]}[/tex]

where,

n = number of electrons in oxidation-reduction reaction = 2

[tex]E_{cell}=1.10-\frac{0.0592}{2}\log \frac{[0.1]}{[0.01]}[/tex]

[tex]E_{cell}=1.07V[/tex]

A. Polyatomic Ion

Why? Nitrogen and Hydrogen are covalently bonded, and there are 4 Nitrogen atoms (fitting the prefix “poly”, meaning “many”).

[tex]NH^{+ 4}[/tex] is a A. Polyatomic ion

When two atoms combine with each other through a covalent bond it leads to the formation of charged species called as polyatomic ions.  

The ammonium cation is a decidedly accused polyatomic particle of the synthetic recipe [tex]NH^{+ 4}[/tex]. It is shaped by the protonation of ammonia.  Ammonium is additionally a general name for decidedly charged or protonated substituted amines and quaternary ammonium cations [tex](NH^{+ 4})[/tex], where at least one hydrogen molecules are supplanted by natural gatherings.

Answer:

Explanation:

The boiling point is defined as the tempearature at which the vapor pressure of a substance equals the atmospheric pressure.

The vapor pressure is the pressure exerted by the vapor particles above the liquid in a sealed container.

In order to a liquid boil, the particles must have enough kinetic energy to escape from the tliquid to the gas (vapor) phase. With that we can approach the choices:

a. Increasing the air pressure above the lquid.

Incorrect choice.

If the air pressure above the liquids is increased, then the liquid particles will need more energy to escape, which means that this change has a considerable effect on increasing the boiling point.

b. Adding alcohol to the water.

Incorrect choice.

The alcohol  added to the water is a solute. Some of the particles of the alcohol added will ocuppy part of the surface of liquid, reducing the number of particles of water that can escape from the liquid phase to the gas state. This reduces the vapor pressure and cause that the boiling point increase. Then, adding alcohol to the water does has an effect on the boiling point (the boiling point will increase).

c. Adding sodium chloride to the water.

Incorrect choice.

As in the case of adding alcohol, sodium chloride is a solute. Thus, the same analysis drives the condlusion that adding sodium chloride to the water does has an effect on the boiling point (the boiling point will increase).

d. Increasing the amount of water.

Correct choice.

The boiling point is a specific property of the substance: it does not depend on the amount of substance. Then, increasing the amount of water will not affect the boiling point.

Answer: i would personly say it would be atomos in matter because that mostly how human cells work

Final answer:

When 540 g of cyclopentane are burned, approximately 8434.2 kJ of energy is released.

Explanation:

In order to determine the quantity of energy released when 540 g of cyclopentane is burned, we can use the information given in the examples. For example, when 3.12 g of glucose is burned, it releases 48.7 kJ of heat. We can use this information to calculate the heat released per gram of glucose, and then apply it to cyclopentane.

First, we calculate the heat released per gram of glucose:

Heat released per gram of glucose = 48.7 kJ / 3.12 g = 15.63 kJ/g

Now, we can use this value to calculate the heat released when 540 g of cyclopentane is burned:

Heat released = 15.63 kJ/g × 540 g = 8434.2 kJ

Therefore, when 540 g of cyclopentane is burned, approximately 8434.2 kJ of energy is released.

Answer: The correct answer is D. 273 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit.

Explanation:

Conversion of degree Celsius to Kelvin :

K=^oC+273

Conversion of degree Celsius to degrees Fahrenheit :

^oF=(\frac{9}{5}\times ^oC)+32

By using these two conversion factors, we get the three temperature readings all mean the same thing.

For option A :

K=^oC+273=100+273=373K

^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 100)+32=212^oF

For option B :

K=^oC+273=100+273=373K

^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 100)+32=212^oF

For option C :

K=^oC+273=0+273=273K

^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 0)+32=32^oF

For option D :

K=^oC+273=0+273=273K

^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 0)+32=32^oF

From the given options, only option (D) is correct.

Hence, the correct option is, (D) 273 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit

Hope this helps!

Temperature is a degree of measure of heat and coldness. Temperature readings that are the same are 273 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit.

Temperature tells about the hotness and the cold degree measure of any substance or object. It can be measured by Kelvin, Celsius or Fahrenheit scale.

Convert degree Celsius to kelvin as:

[tex]\begin{aligned}\rm K &= \rm ^{\circ} C+273\\\\&= 0 + 273 \\\\&= 273 \;\rm kelvin\end{aligned}[/tex]

Convert degree Celsius to Fahrenheit as:

[tex]\begin{aligned}^{\circ} \rm F & = \rm (\dfrac{9}{5}\times ^{\circ} C)+32\\\\&= 0 + 32\\\\&= 32 \;\rm Fahrenheit \end{aligned}[/tex]

Therefore, option D. 273 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit is the temperature reading that means the same.

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Answer:

Ester Linkages

Explanation:

In a fat molecule, the fatty acids are attached to each of the three carbons of the glycerol molecule with an ester bond through the oxygen atom.

You're welcome

The bond that joins glycerol to fatty acids in lipids like triglycerides and phospholipids is the ester linkage.

The type of bond that joins glycerol to fatty acids in fat molecules and phospholipids is the ester linkage. Glycerol, which is a triol, bonds with three fatty acids, each through an ester bond, during a dehydration synthesis reaction. This reaction forms a triglyceride, which is a type of lipid essential for storing energy and providing insulation. In triglycerides, the fatty acids are attached to glycerol's three carbons through an oxygen atom, forming a strong ester bond. In the case of phospholipids, which are the major constituents of cell membranes, two fatty acid chains and a phosphate group form ester linkages with the glycerol backbone.

Answer:

[tex]\boxed{\text{10.81 u}}[/tex]

Explanation:

The atomic mass of B is the weighted average of the atomic masses of its isotopes.

We multiply the atomic mass of each isotope by a number representing its relative importance (i.e., its percent of the total).

Set up a table for easy calculation:

[tex]\begin{array}{ccccr}\textbf{Atom} & \textbf{Mass/u} &\textbf{Percent} & \textbf{Calculation}& \textbf{Result}\\^{10}\text{B}& 10.01 & 19.91 & 10.01 \times 0.1991 & 1.99\\^{11}\text{B}& 11.01 & 80.09 & 11.01 \times 0.8009 & 8.82 \\& & & \text{TOTAL} = &\textbf{10.81}\\\end{array}[/tex]

The average atomic mass of B is [tex]\boxed{\textbf{10.81 u}}[/tex].

Answer:

10.81u

Explanation:

I just did the test

Answer:

= 25 ppm

Explanation:

Given; a sample size of 2000 g contained 0.050 g DDT

It means, 2000 mL sample contained 50 mg DDT

Therefore in ppm we get;

= 50 mg/ 2 L

= 25 mg/L

= 25 ppm

The concentration of DDT in your sample is calculated by dividing the mass of DDT by the total mass and multiplying by 1,000,000. Using your provided values, the DDT concentration is 25 parts per million (PPM).

In the context of your question, you want to know the concentration of DDT in a sample size of 2000 g which contains 0.050 g of DDT in terms of parts per million (PPM). PPM is a unit typically used to express concentrations of pollutants and other trace contaminants in similar low concentration scenarios.

To calculate the concentration in PPM, the formula is quite straightforward. You divide the mass of the contaminant by the total mass of the sample, then multiply the result by 1,000,000.

Using your values:

(mass of DDT / total mass) * 1,000,000 = (0.050g / 2000g) * 1,000,000 = 25 ppm.

This means that there are 25 parts of DDT per every 1,000,000 parts of the sample.

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More neutrons are produced than are absorbed

Answer:

The right word to fill the blank space is GREATER THAN.

Explanation:

In nature, heat in form of temperature is usually transfer from the region of higher temperature to the region of lower temperature. Thus, for heat to be transfer from one substance to another one, the temperature will flow from the body with the higher temperature to that which has a lower temperature, the substance that is giving out the heat must have a higher temperature.  

Explanation:

When two substances of different temperature are in contact with each other then heat will flow from hot object to cold object until a thermal equilibrium is maintained between them.

Kinetic energy is the energy obtained due to the motion of an object is known as kinetic energy. Total kinetic energy of all the particles present in a system is known as average kinetic energy.

Thus, we can conclude that when two samples of carbon come into contact. Heat will transfer from Sample A to Sample B if the average kinetic energy of Sample A's atoms is greater than the average kinetic energy of Sample B's atoms.

Answer:

D. It reacts with Mg to produce H2.

Answer: Option (D) is the correct answer.

Explanation:

The acetic acid, [tex](CH_{3}COOH)[/tex] present in vinegar reacts wit magnesium and therefore, it releases hydrogen gas and magnesium acetate.

The chemical reaction will be as follows.

       [tex]2CH_{3}COOH + 2Mg \rightarrow 2Mg(CH_{3}COO) + H_{2}[/tex]

An acid is a substance which has pH less than 7 and changes blue litmus red. Acids taste sour as they are acidic in nature and releases hydrogen ions.

Whereas bases have pH greater than 7 and changes red litmus into blue.Bases taste bitter and releases hydroxide ions.

Thus, we can conclude that the statement it reacts with Mg to produce [tex]H_{2}[/tex] best describes the acid found in vinegar (acetic acid).

Answer:

= 6.0 moles

Explanation:

The equation for the reaction is;

2 CH3OH + 3 O2 → 2 CO2 + 4 H2O

We are given 4.0 moles of CH3OH.

From the reaction; 2 moles of CH3OH requires 3 moles of O2,

Therefore; moles of Oxygen will be;

= 4.0 moles × 3/2

= 6.0 moles

Therefore; 6.0 moles of Oxygen gas are required to react completely with 4.0 moles CH3OH.

Answer:

H2O2 - - - - - -> H2O + O2

+1 +2 0

Oxidation O. S.

state of of Oxygen

Oxygen

[tex]2H_{2}O_{2}[/tex]--------->  [tex]2H_{2}O+O_{2}[/tex] is the equation given for the oxidation of peroxide during a redox reaction.

The reaction in which both oxidation and reduction can simultaneously occur to give raise to product is called as redox reaction.

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