Answer:
C. software
Explanation:
software, is a collection of data or computer instructions that tell the computer how to work. This is in contrast to physical hardware, from which the system is built and actually performs the work.
Answer:gbji
Explanation:
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Stefan's Law says:
A) that doubling the star's temperature would also double its peak wavelength.
B) the energy radiated by a blackbody is proportional to T3.
C) that if the Sun's temperature were doubled, it would give off 16X more energy.
D) the hotter a star's surface, the bluer it looks to us.
E) E =mc2.
Answer:
The Sun's temperature were doubled, it would give off 16X more energy.
Explanation:
The Stefan's law gives the relationship between total energy radiated per unit surface area of a black body and the temperature. It is given by :
[tex]j\propto T^4[/tex]
[tex]j=\sigma T^4[/tex]
[tex]\sigma[/tex] is the constant of proportionality called the Stefan–Boltzmann constant
T is temperature
So, the correct statement regarding Stefan's Law is that if the Sun's temperature were doubled, it would give off 16 X more energy. Hence, the correct option is (C).
Final answer:
Stefan's Law, or the Stefan-Boltzmann law, indicates the power output of a black body like the Sun would increase by a factor of 16 (C) if its temperature were to double, due to the relationship where energy flux is proportional to the fourth power of temperature. Hence, (C) is the correct option.
Explanation:
The correct answer to the statement 'Stefan's Law says' is that if the Sun's temperature were doubled, it would give off 16X more energy.
This relationship is known as the Stefan-Boltzmann law and states that the total energy flux (energy radiated per square meter) from a black body, such as a star, is proportional to the fourth power of its absolute temperature, as expressed in the formula [tex]F = \sigma\T4[/tex] (with sigma being the Stefan-Boltzmann constant).
Therefore, if the temperature of the Sun were to double from its current temperature (approximately 5800 K to 11600 K), its power output, or radiated energy, would increase by a factor of 24 or 16.
A 12-volt automotive circuit has a current of 3 amps. Technician A says the electric power in this circuit is 36 watts. Technician B says the electric power in this circuit is 4 watts. Who is right?
Answer:
Technician A is right.
Explanation:
Given that,
Voltage of circuit, V = 12 volt
Current in the circuit, I = 3 A
Technician A says the electric power in this circuit is 36 watts. Technician B says the electric power in this circuit is 4 watts. We need to say that which technician is correct.
The power of any circuit is given by :
[tex]P=V\times I[/tex]
[tex]P=12\ V\times 3\ A[/tex]
P = 36 watts
So, technician A is right. Hence, this is the required solution.
The power in an electric circuit is calculated by multiplying the voltage by the current. Therefore, in a 12-volt circuit with a current of 3 amps, the power would be 36 watts. This confirms the statement made by Technician A, making him correct.
Explanation:In the context of electric circuits, the power is determined by multiplying the voltage across the circuit by the current flowing through it. This relationship is captured in the formula P = IV, where P represents power, I represents current, and V represents voltage.
In this particular case, given a 12-volt circuit with a current of 3 amps, the calculation becomes P=12V * 3A. Accordingly, the power in this circuit would be 36 watts, validating Technician A's statement. Therefore, in this instance, Technician A is correct and Technician B is incorrect.
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A 1.00 cm diameter plastic sphere, used in a static electricity demonstration, has a charge of 22.6 pC uniformly distributed on its surface. What is the potential at its surface (or just barely above it)?
Answer:
Electric potential, V = 40.68 volts
Explanation:
Given that,
Charge on the sphere, [tex]q=22.6\ pC=22.6\times 10^{-12}\ C[/tex]
Diameter of the plastic sphere, d = 1 cm
Radius, r = 0.5 cm
We need to find the electric potential at its surface. The potential at a surface is given by :
[tex]V=\dfrac{kq}{r}[/tex]
[tex]V=\dfrac{9\times 10^9\times 22.6\times 10^{-12}}{0.5\times 10^{-2}}[/tex]
V = 40.68 volts
So, the electric potential at its surface is 40.68 volts. Hence, this is the required solution.
Why is designing a successful service operation often more difficult than a successful design of a tangible product?
A. Strong element of customer involvement
B. Lack of computer-aided design
C. Tangible products are more personalized
D. More challenging inventory considerations
Answer:
A. Strong element of customer involvement
Explanation:
A service operation involves managing and performing the activities that are necessary to deliver services at a good level of quality to customers. Service operation tends to be more difficult than a successful design of a tangible product because the process involves high customer contact because customers are consumers of the product but in the case of the services, they are also part of its production and this is more difficult to control. According to this, the answer is that a successful service operation is more difficult because it has a strong element of customer involvement.
In a physics experiment, two equal-mass carts roll towards each other on a level, low-friction track. One cart rolls rightward at 2 m/s and the other cart rolls leftward at 1 m/s. After the carts collide, they couple (attach together) and roll together with a speed of __________. Ignore resistive forces.a. 0.5 m/s
b. 0.33 m/s
c. 0.67 m/s
d. 1.0 m/s
e. none of these
Answer:
The correct answer is option a.
Explanation:
Conservation of momentum :
[tex]m_1u_1+m_2u_2=m_1v_1+m_1v_2[/tex]
Where :
[tex]m_1, m_2[/tex] = masses of object collided
[tex]u_1,u_2[/tex] = initial velocity before collision
[tex]v_1,v_2[/tex] = final velocity after collision
We have :
Two equal-mass carts roll towards each other.
[tex]m_1=m_2=M[/tex]
Initial velocity of [tex]m_1=u_1=2 m/s[/tex]
Initial velocity of [tex]m_2=u_2=-1 m/s[/tex] (opposite direction)
Final velocity of [tex]m_1=v_1=v[/tex] (same direction )
Final velocity of [tex]m_2=v_2=v[/tex] (same direction)
[tex]M\times 2 m/s+M(-1 m/s)=Mv+Mv[/tex]
[tex]1 m/s=2v[/tex]
v = 0.5 m/s
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The speed of the carts after their collision is 0.5 m/s.
Using the principle of conservation of momentum, the combined carts will have a speed of 0.5 m/s after their collision. This is because their total momentum prior to the collision is conserved during the collision and is equal to their total momentum post the collision.
Explanation:This is a question about the principle of conservation of linear momentum in physics. Before the collision, the total momentum of the system (two carts) is the sum of their individual momenta. Since they have equal mass, we can write the total momentum as momentum of cart 1 + momentum of cart 2 = total momentum, or (mass x velocity of cart 1) + (mass x -velocity of cart 2) = total momentum. Since one cart is moving rightward and the other is moving leftward, we take the velocity of the leftward moving cart, cart 2, as negative. Thus, we have (mass x 2 m/s) - (mass x 1 m/s) = total momentum, hence the total momentum comes out to be mass x 1 m/s.
After the collision, the two carts couple and move with a common speed which we denoted as V. According to the conservation of linear momentum law, the total momentum before collision must be equal to the total momentum after the collision, which gives us mass x 1 m/s = 2 x mass x V (since the total mass after the collision becomes 2 times the mass of one cart), solving this gives V = 0.5 m/s.
Therefore, the combined carts will have a speed of 0.5 m/s after the collision. So, the answer to your question is a. 0.5 m/s.
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Put the items below in correct sequence for using wind to generate electricity.
1 - A generator converts mechanical energy into electrical energy.
2 - Wind turns the wind turbine blade.
3 - A gear box transfers mechanical energy to a generator.
4 - Electricity is transferred to the grid.
Answer:
2- 3 - 1- 4
Explanation:
Extracting energy from the wind is known as wind energy. Wind energy is are a renewable source of energy.
Energy can be extracted from the wind by following different steps.
1) Wind will turn the wind turbine blade.
2) Then the mechanical energy from the wind turbine blade is transferred to the generator.
3) The generator will convert mechanical energy into electrical energy.
4) the electrical energy produced is then transferred to the grid.
Hence, the sequence of Power generation is
2- 3 - 1- 4
What percent is the air density at the summit of Mount Everest relative to the air density at sea level?
Answer:
43.76%
Explanation:
The air density at the sea level ρ_s = 1.25 kg/m^3.
also, air density at the top of the mountain where ρ_t = 0.547 kg/m^3.
taking temp as --50° C and pressure as 1/3 of P_atm.
therefore, t percent is the air density at the summit of Mount Everest relative to the air density at sea level
= [tex]\frac{\rho_t}{\rho_s}\times100[/tex]
=[tex]\frac{0.547}{1.25}\times100[/tex]
=43.76 %
What is the new pressure of 150 ml of a gas that is compressed to 50 ml when the original pressure was 3.0 atm and the temperature is held constant?
Answer: 9.0 atm
Explanation:
To calculate the new pressure, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.
The equation given by this law is:
[tex]P_1V_1=P_2V_2[/tex]
where,
[tex]P_1\text{ and }V_1[/tex] are initial pressure and volume.
[tex]P_2\text{ and }V_2[/tex] are final pressure and volume.
We are given:
[tex]P_1=3.0atm\\V_1=150mL\\P_2=?mmHg\\V_2=50mL[/tex]
Putting values in above equation, we get:
[tex]3.0\times 150mL=P_2\times 50mL\\\\P_2=9.0atm[/tex]
Thus new pressure of 150 ml of a gas that is compressed to 50 ml is 9.0 atm
_____________ is an excessive current relative to normal operating current, but one that is confined to the normal conductive path provided by the conductors, circuit components, and loads of the distribution system. A(n) _________ is a current that flows outside the normal conducting path. One generally accepted definition of _______is when a phase or ungrounded conductor comes in contact with, or arcing current flows between, another phase conductor, neutral, or ground.
Answer:
Overload current, short-circuit current and short circuit
Explanation:
Overload current is an excessive current relative to normal operating current, but one that is confined to the normal conductive path provided by the conductors, circuit components, and loads of the distribution system.
A short-circuit current is a current that flows outside the normal conducting path.
One generally accepted definition of short circuit is when a phase or ungrounded conductor comes in contact with, or arcing current flows between, another phase conductor, neutral, or ground.
Four equal masses m are so small they can be treated as points, and they are equally spaced along a long, stiff wire of neglible mass. The distance between any two adjacent masses is l. What is the rotational inertia I_cm of this system about its center of mass?
1) 1/2 ml^2
2) 3 ml^2
3) ml^2
4) 2 ml^2
5) 4 ml^2
6) 7 ml^2
7) 5 ml^2
8) 6 ml^2
Answer: 5m/L^2
Explanation:
Inertial I = mr^2 where r = distance from axis of rotation, while m is the mass of the object.
I = 2[m(1L/2)^2] + 2[m(3L/2)^2] = 2m×. 25/L^2+ 3m×2. 25/L^2= 0. 5m/l^2 +4. 5m/l^2
= 5m/l^2.
A metal alloy rod is submerged 22 cm below the surface of a fresh water pool by steel cables tied 10cm from each end. It has a length of 110 cm, a mass of 2 kg and a uniform square cross sectional area of 7 cm2. Because its density is not uniform its center of mass is located 49 from the left end.
1.) What is the force of tension in the left cable?
2.) What is the force of tension in the right cable?
Answer:
force of tension in the left cable = 7.66N
force of tension in the right cable = 5.074N
Explanation:
The detailed step and calculation is as shown in the attachment.
Suppose an object starts out electrically neutral. Through some process, 11 electrons are removed from the object. What is the electric charge of the object afterward? ANSWER
1. Unselected It has a net charge somewhere between the charge of 11 electrons and 11 protons, but we can’t tell exactly how much.
2. Unselected The stated situation isn’t possible.
3. Unselected It has the same net charge as 11 protons.
4. Unselected It has the same net charge as 11 electrons.
Answer:
3. It has the same net charge as 11 protons.
Explanation:
An electrically neutral object contains the same number of protons and electrons. Therefore, if 11 electrons are removed from it, there will be 11 more protons compared to the number of electrons in the object. Thus, the object It has the same net charge as 11 protons.
Atoms are electrically neutral, but removing electrons results in a charged object with a net charge equivalent to the number of protons present.
Atoms are electrically neutral, meaning that the overall electric charge is zero because the number of protons (positive charge) equals the number of electrons (negative charge). When an atom loses electrons, it becomes positively charged, and when it gains electrons, it becomes negatively charged. In this case, removing 11 electrons from a neutrally charged object will result in a net charge equivalent to having the same net charge as 11 protons.
A hill that has a 28.1% grade is one that rises 28.1 m vertically for every 100.0 ml of distance in the horizontal direction. At what angle is such a hill inclined above the horizontal?
Answer:
[tex]\theta=15.70^\circ[/tex]
Explanation:
A right triangle is formed, in which the vertical elevation is the opposite cathetus and the horizontal distance is the adjacent cathetus, since we know these two values, we can calculate the angle of inclination using the definition of tangent:
[tex]tan\theta=\frac{opp}{adj}\\\theta=arctan(\frac{opp}{adj})\\\theta=arctan(\frac{28.1m}{100m})\\\theta=15.70^\circ[/tex]
When we look at an object that is 1,000 light-years away we see it _________.
a. as it is right now, but it appears 1,000 times dimmer
b. as it was 1,000 light-years ago
c. as it was 1,000 years ago
d. looking just the same as our ancestors would have seen it 1,000 years ago
Answer:
c. as it was 1,000 years ago
Explanation:
since the object is one thousand light years away, it means what ever light is comes from the object (is reflected off the object) would take 1,000 years to get to us, meaning we would be seeing the object as it was 1,000 years ago.
Students in Mr. Jackson's class built two containers designed to keep Ice pops cold for a
penod of time. Both containers had the same dimensions, but were constructed from
diferent materials. They put one Ice pop in each container, kept the surrounding
temperature constant, and measured how long it took for each ice pop to melt. The table
shows their results.
Container Time it took the Ice Pop to Melt (min)
1-25
2-32
Which container was most likely made with a material that had a low specific heat?
A. Container 1 because it took the shortest amount of time for the ice pop to melt, and
materials with low specific heat are poor Insulators
B. Container 1 because it took the shortest amount of time for the Ice pop to melt, and
materials with low specific heat are good Insulators
C. Container 2 because it took the longest amount of time for the Ice pop to melt, and
materials with low specific heat are poor insulators
D. Container 2 because it took the longest amount of time for the ice pop to melt, and
materials with low specific heat are good insulators
The ice in first container melts fastly because the container is made of material with low specific heat capacity. The material is a poor insulator.
What is specific heat capacity ?The heat energy required to raise the temperature of a substance by one degree Celsius per one gram of that substance is called its specific heat capacity. It is an intensive property.
Less the specific heat, heat energy required by the material is less to increase the temperature. If a substance is having higher specific heat it requires more heat energy and it is a poor conductor.
To melt a substance heat energy is required to absorb by the substances to weaken the intermolecular forces. If the ice in container melts easily than the ice in other container, the material of the first container is made with material of less specific heat.
The material with less specific heat is a thermal conductor. Therefore, option A is correct.
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Since you've determined that the power supply is a 700W dual rail, what does that make the maximum output power?
700 makes the maximum output power.
Explanation:
In physics, power is the rate of doing work or of transferring heat, i.e. the amount of energy transferred or converted per unit time. The output power of a motor is the product of the torque that the motor generates and the angular velocity of its output shaft.
A joule is equal to one Newton-meter, which is the amount of work needed to move a 1 Newton force a distance of 1 meter. When you divide work by time, you get power, measured in units of joules per second. This is also called a Watt. 1 Watt = 1 Joule Sec. This is the formula to calculate output power.
The maximum output power of a 700W dual rail power supply is 700W. 'Dual rail' refers to how the power is distributed, it does not increase the total output.
Explanation:Having determined that the power supply is a 700W dual rail, this refers to the maximum amount of power that the power supply can output. The power supply's maximum output power is its total capacity, which in this case is 700W. It's important to remember that 'dual rail' refers to the way the power is distributed and doesn't increase the overall power. Simply put, a dual rail power supply divides its power between two ‘rails’ or circuits, but the maximum output power remains 700W.
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Two identical small metal spheres are separated by 1.00 × 105 m and exert an 18.9-N repulsive force on each other. A wire is connected between the spheres and then removed. The spheres now repel each other, exerting a 22.5-N force. Assume both charges are positive.
1. Determine the total charge of this system.
q =______ (units)
2. Determine the charges of the spheres before the connection.
q1, q2 = ______ C
Answer:
(a). The total charge of this system is 10 C.
(b). The charges of the spheres before the connection is 5 C and 4.2 C.
Explanation:
Given that,
Distance [tex]r= 1.00\times10^{5}\ m[/tex]
Force = 22.5 N
The two spheres are connected for a moment by a wire. After this, charge is re-distributed equally, and each sphere now has a charge
We need to calculate the charge
Using formula of electric force
[tex]F=\dfrac{kq_{1}q_{2}}{r^2}[/tex]
Here, charge is equal
Put the value into the formula
[tex]22.5=\dfrac{9\times10^{9}\times q^2}{(1.00\times10^{5})}[/tex]
[tex]q^2=\dfrac{22.5\times(1.00\times10^{5})^2}{9\times10^{9}}[/tex]
[tex]q=\sqrt{\dfrac{22.5\times(1.00\times10^{5})^2}{9\times10^{9}}}[/tex]
[tex]q=5\ C[/tex]
(a). We need to calculate the total charge of this system
We have the charge of each sphere after re-distribution.
We know that the charge is distributed equally.
Therefore, the total charge of the system is
[tex]q+Q=2q=2\times5=10\ C[/tex]
(b). We need to calculate the charge of the spheres before the connection
Using formula of electric force
[tex]F=\dfrac{kq_{1}q_{2}}{r^2}[/tex]
Put the value into the formula
[tex]18.9=\dfrac{9\times10^{9}\times q_{1}\times q_{2}}{(1.00\times10^{5})}[/tex]
[tex]q_{2}=\dfrac{18.9\times(1.00\times10^{5})^2}{9\times10^{9}\times5}[/tex]
[tex]q_{2}=4.2\ C[/tex]
Hence, (a). The total charge of this system is 10 C.
(b). The charges of the spheres before the connection is 5 C and 4.2 C.
The power rating on a light bulb indicates how much power it would dissipate when it is hooked up to the standard household voltage of 120 V (this rating does not mean that the light bulb always dissipates the same amount of power, assume that the resistance is constant in this case).
A. How much power is dissipated in a light bulb that is normally rated at 75 W, if instead we hook it up to a potential difference of 60 V?
B. How much power is dissipated in a light bulb that is normally rated at 75 W, if instead we hook it up to a potential difference of 120 V?
Answer:
A. P = 18.75 watts
B. P = 75 watts
Explanation:
V = 120 Volts
P = VI
I = P/V = 75/120 = 0.625 Amps
V = IR
R = V/I
R = 120/0.625 = 192 Ω
So the resistance of the bulb is 192 Ω and it does not change as it is given in the question.
A. How much power is dissipated in a light bulb that is normally rated at 75 W, if instead we hook it up to a potential difference of 60 V?
As P = VI and I = V/R
P = V*(V/R)
P = V²/R
P = (60)/192
P = 18.75 watts
As expected, it will dissipate less power (18.75 watts) than rated power due to not having rated voltage of 120 Volts.
I = V/R = 60/192 = 0.3125 Amps
or I = P/V = 18.75/60 = 0.3125 Amps
Since the resistance is being held constant, decreasing voltage will also decrease current as V = IR voltage is directly proportional to the current.
B. How much power is dissipated in a light bulb that is normally rated at 75 W, if instead we hook it up to a potential difference of 120 V?
P = V*(V/R)
P = V²/R
P = 120/192 = 75 watts
I = P/V = 75/120 = 0.625 Amps
As expected, it will dissipate rated power of 75 watts at rated voltage of 120 Volts.
For a light bulb rated at 75 W at 120 V, the power dissipated at 60 V is 18.75 Watts and at 120 V, it would dissipate its rated power of 75 Watts.
Explanation:The power dissipated by a resistor (in this case, a light bulb) can be calculated using the formula P = V² / R, where P is the power, V is the potential difference (or voltage), and R is resistance.
A. With a potential difference of 60 V (half of its normal voltage), we expect the bulb to dissipate a quarter of its normal power. Hence, the power in this case would be (60V)²/R = 75W/4 = 18.75 Watts.
B. The rating on the bulb is 75 W assuming a household voltage of 120 V. So, if we hook it up to a potential difference of 120 V, it should dissipate its normal rated power of 75 Watts.
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What is the best wavelength to use if an astronomer wants to study the composition of planets and stars
Answer: a. gamma rays
Explanation:
Scientists are able to use gamma rays to determine the composition of planets and other celestial bodies.
Special equipment exists that can measure gamma rays emitted by atoms on a planet's surface when it is struck by cosmic rays thus enabling us (humans) to understand more of the universe.
Answer:
Wrong its actually radio waves
Explanation:
To prepare 400 ml of a 40% (w/v) solution of sodium bicarbonate, how many grams of solute are needed?
Answer : The mass of solute needed are, 40 grams.
Explanation :
As we are given that 40 % (w/v) solution of sodium bicarbonate (solute) that means 40 grams of sodium bicarbonate present in 100 mL of solution.
Now we have to calculate the mass of solute needed.
As, 100 mL of solution needs mass of solute = 10 g
So, 400 mL of solution needs mass of solute = [tex]\frac{400mL}{100mL}\times 10g=40g[/tex]
Thus, the mass of solute needed are, 40 grams.
To prepare a 400 ml of 40% (w/v) solution of sodium bicarbonate, multiply the percentage (40%) by the total volume (400 ml) and divide by 100. You will need 160 grams of sodium bicarbonate for this solution.
Explanation:To prepare 400 ml of a 40% (w/v) solution of sodium bicarbonate, you need to understand the meaning of (w/v). It stands for weight/volume, and it means that for every 100 ml of solution, you have the given percentage in grams of the solute. So, for a 40% (w/v) solution, 100 ml of the solution will contain 40 grams of sodium bicarbonate. Therefore, we need to calculate the amount of sodium bicarbonate for 400 ml of solution:
First, determine the total weight of sodium bicarbonate needed for 100 ml: 40 grams (from the definition of 40% w/v).Next, because you need 400 ml, which is four times the amount of 100 ml, you multiply the amount needed for 100 ml by 4.This results in 40 grams x 4 = 160 grams.To prepare a 400 ml of 40% (w/v) sodium bicarbonate solution, you would need 160 grams of sodium bicarbonate.
Four identical metallic spheres with charges of +8.2 µC, +9.0 µC, −7.8 µC, and −8.8 µC are placed on a piece of paper. The paper is lifted on all corners so that the spheres come into contact with each other simultaneously. The paper is then flattened so that the metallic spheres become separated.
a. What is the resulting charge on each sphere?
b. How many excess or absent electrons (depending on the sign of your answer to part (a)) correspond to the resulting charge on each sphere?
Answer:
a) 0.15 μC b) 9.4*10¹¹ electrons.
Explanation:
As the total charge must be conserved, the total charge on the spheres, after being brought to contact each other, and then separated, must be equal to the total charge present in the spheres prior to be put in contact:
Q = +8.2μC +9.0 μC +(-7.8 μC) + (-8.8 μC) = +0.6 μC
As the spheres are assumed perfect conductors, as they are identical, once in contact each other, the excess charge spreads evenly on each sphere, so the final charge, on each of them, is just the fourth part of the total charge:
Qs = Qt/4 = 0.6 μC / 4 = 0.15 μC.
b) As the charge has a positive sign, this means that each sphere has a defect of electrons.
In order to know how many electrons are absent in each sphere, we can divide the total charge by the charge of one electron, which is the elementary charge e, as follows:
[tex]N =\frac{0.15e-6C}{1.6e-19C} = 9.4e11 electrons[/tex]
The wavelength of visible light is about 5500 times longer than the wavelength of x-rays. If you represent the wavelenth of an x-ray photon by a line 1 inch long, how long a line (in feet) must you draw to represent the wavelength of visible light?
Answer:
458.33 ft
Explanation:
We are given that
Wavelength of of an x- ray photon=1 in
Wavelength of of an x- ray photon==[tex]\frac{1}{12}[/tex]ft
1 in=[tex]\frac{1}{12}[/tex]feet
We have to find the length of line (in feet) drawn by you to represent the wavelength of visible light.
According to question
Wavelength of visible light=[tex]5500\times \frac{1}{12}[/tex] ft
Wavelength of visible light[tex]=\frac{5500}{12}[/tex]ft
Wavelength of visible light=458.33 ft
Hence, the 458.33 ft line must drawn by you to represent the wavelength of visible light.
Answer:
458.33 ft
Explanation:
I had the same question once
A sailboat moves north for a distance of 10.00 km when blown by a wind 30° east of south with a force of 5.00×10^4 N . How much work was done by the wind?
Answer:
-433 MJ of work
Explanation:
Given:
Displacement of the sailboat is, [tex]d=10.00\ km[/tex] towards north
Force applied by the wind is, [tex]F_w=5.00\times 10^4\ N[/tex]
Direction of the force is, [tex]\theta=30(Towards\ East\ of\ South)[/tex]
The vector diagram representing the given scenario is shown below.
We know that, work done by a force is the dot product of force and displacement and is given as:
[tex]W=F\cdot d=Fd\cos x[/tex]
Where, 'x' is the angle between the tails of the vectors 'F' and 'd'.
Now, from the figure below, we can find 'x'.
[tex]x=180-\theta=180-30=150[/tex]
Now, plug in all the given values and solve for 'W'.
[tex]W=(5.00\times 10^4\ N)(10.00\times 10^3\ m)(\cos 150)\\\\W=-433012702\ J =-433\ MJ[/tex]
Therefore, the work done by the wind is nearly 433 MJ. The negative sign implies that the force acts in the direction opposite to the displacement.
Describe the total momentum of billiard balls before and after the cue ball collides with another ball.
Answer:
The Total Momentum before and after collision remains the same.
Explanation:
Note that the balls have the same masses.
A moving cue ball has an initial momentum. After every collision with another stationary ball, the momentum, which is the product of their mass and velocity, of the balls is conserved. This simply means that the total momentum before the collision is the same as the total momentum after the collision.
This also means that the energy must be conserved as well. The balls cannot fling away from each other with more energy than you give them.
Answer:
Total momentum is conserved before and after collusion and it's elastic.
Explanation:
For two colliding balls, the general vector equation for conservation of linear momentum is giving as
Ma*V1a = Ma*V2a + Mb*V2b
Where Ma=mass of que ball = Mb = mass of billiard ball so therefore
V1a= velocity of que ball before impact, V2a = velocity of que ball after impact, V2b = velocity of billiard ball after impact.
So therefore:
V1a = V2a + V2b
Which of the following is a scalar quantity
A. Distance
B. Displacement
C. Velocity
D. Acceleration
Answer :
I think it is A. Distance
Answer:
A. Distance
Explanation:
Velocity, Acceleration, and displacement all require a magnitude and direction to be measured.
Which Earth system spheres are involved in this particular scientific investigation on hydraulic fracturing? Choose one or more: a.biosphere b.atmosphere c.hydrosphere d.cryosphere e.geosphere
Hydraulic fracturing involves several of Earth's system spheres including the geosphere (with drilling into rock formations), the hydrosphere (with extensive use of water), and the biosphere (potential impacts on ecosystems).
Explanation:The scientific investigation on hydraulic fracturing involves several of Earth's systems, specifically the biosphere, the hydrosphere, and the geosphere. The geosphere is involved as hydraulic fracturing involves the extraction of natural gas from deep underground rock formations. The hydrosphere is engaged as large quantities of water are used in the process, potentially affecting water resources. Finally, the biosphere is implicated as there could possibly be impacts on local ecosystems and wildlife from the operation and waste produced from the process.
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A uniform solid disk with a mass of 24.3 kg and a radius of 0.364 m is free to rotate about a frictionless axle. Forces of 90.0 N and 125 N are applied to the disk, as the drawing illustrates. (a) What is the net torque produced by the two forces? (Assume counterclockwise is the positive direction.)(b) What is the angular acceleration of the disk? rad/s2
To find the net torque, we multiply the radius by each force, and then add them taking the direction into account. Then, we divide the net torque by the moment of inertia (which we find by substituting the given mass and radius values into the formula for a uniform solid disk) to find the angular acceleration.
Explanation:To solve this question, we need to calculate the net torque ('t') which is the product of the radius and the force applied perpendicular to it, and then use that value to find the angular acceleration ('a', represented as rad/s2). This involves the physics concept of Newton's second law applied to rotation.
Step 1: Calculate net torque. The applied forces are perpendicular to the radius and friction is negligible, so the torque due to each force is t = rF. The total torque is the sum of the torques due to the two forces applied, taking into account that the 90.0 N force is in the counterclockwise direction and the 125 N force is in the clockwise direction (-125 N). The net torque would therefore be t = r(90 N) - r(125 N) = 0.364m(90 N) - 0.364m(125 N).
Step 2: Calculate angular acceleration. Angular acceleration is the net torque divided by the moment of inertia ('I') of the disk. The moment of inertia for a uniform solid disk is 0.5mr2. We can substitute m = 24.3 kg and r =0.364 m to find I. The angular acceleration is therefore a = t/I.
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The net torque produced by the two forces is 12.74 N·m and the angular acceleration of the disk is 7.90 rad/s². The calculation involved determining the torque from each force and then using the moment of inertia for a solid disk to find the angular acceleration.
(a) Net Torque Calculation
To calculate the net torque, we use the formula:
Torque (τ) = Force (F) x Radius (r) x sin(θ)
Assuming both forces are applied tangentially (θ = 90° or sin(90°) = 1), we have:
Torque from 90.0 N force:
τ₁ = 90.0 N x 0.364 m x 1 = 32.76 N·m (clockwise, so negative)
Torque from 125 N force:
τ₂ = 125 N x 0.364 m x 1 = 45.5 N·m (counterclockwise, so positive)
The net torque is:
Net Torque = τ₂ - τ₁ = 45.5 N·m - 32.76 N·m = 12.74 N·m
(b) Angular Acceleration Calculation
First, we need the moment of inertia (I) for a solid disk, given by:
I = 0.5 x Mass (m) x Radius² (r²)
For this disk:
I = 0.5 x 24.3 kg x (0.364 m)² = 1.612 kg·m²
Next, using the net torque (τ) to find angular acceleration (α):
α = τ / I
Substituting the values:
α = 12.74 N·m / 1.612 kg·m² = 7.90 rad/s²
Conclusion:
The net torque produced by the two forces is 12.74 N·m, and the angular acceleration of the disk is 7.90 rad/s².
Two football players with mass 75kg and 100kg run directly toward each other with speeds of 6 m/s and 8 m/s respectively, If they grab each other as they collide, the combined speed of the two players just after the collision would be:
Answer:
2 m/s
Explanation:
From the law of conservation of momentum,
Total momentum before collision = total momentum after collision
mu+m'u' = V(m+m') .................................Equation 1
Where m = mass of the first player, u = initial speed of the first player, m' = mass of the second player, u' = initial speed of the second player, V = combined speed of both players.
Making V the subject of the equation,
V = (mu+m'u')/(m+m')................ Equation 2
Note: Taking the direction of the first player as positive.
Given: m = 75 kg, m' = 100 kg, u = 6 m/s, u' = -8 m/s (opposite the first player),
Substituting into equation 2
V = [(75×6)+(100×(--8))]/(75+100)
V = (450-800)/175
V = 350/175
V = - 2 m/s.
Note: The negative signs tells that the combined speed is in the direction of the second player.
Hence the combined speed of the two players = 2 m/s
Final answer:
The question involves using the conservation of momentum to calculate the combined speed of two football players after they collide and cling together. By applying the formula (m1*v1 + m2*v2) / (m1 + m2), the resulting velocity can be obtained, considering the direction of the players' velocities.
Explanation:
The question involves a physical interaction between two football players, which is described by the conservation of momentum, a fundamental concept in physics. When two objects, in this case football players, collide and stick together, the total momentum before the collision equals the total momentum after the collision, provided no external forces act on the system. The formula to find the combined velocity just after the collision is derived from the conservation of momentum principle: (m1*v1 + m2*v2) / (m1 + m2), where m1 and m2 are the masses and v1 and v2 are the velocities of the two players respectively.
Therefore, to find the combined speed of the two players just after the collision, we would use their given masses and initial speeds: (75kg*6m/s + 100kg*-8m/s) / (75kg + 100kg). The negative sign indicates that the second player is running in the opposite direction. After solving, we'd get the resulting velocity, which represents the speed and direction of the two players immediately after the collision.
Here is a simple example. The inhabitants of a small island begin exporting beautiful cloth made from a rare plant that grows only on their island. Seeing how popular the small quantity that they export has been, they steadily raise their prices. A clothing maker from New York, thinking that he can save money by "cutting out the middleman," decides to travel to the small island and buy the cloth himself. Ignorant of the local custom of offering strangers outrageous prices and then negotiating down, the clothing maker accepts (much to everyone's surpise) the initial price of 400 tepizes/m2. The price of this cloth in New York is 120 dollars/yard2.If the clothing maker bought 500 m2 of this fabric, how much money did he lose? Use 1tepiz=0.625dollar and 0.9144m=1yard.
Answer:
He lost $53,240.60
Explanation:
In order to solve this problem, we must start by determining how many dollars he spent for the [tex]500m^{2}[/tex] of cloth. We can determine this by doing the following conversion:
[tex]500m^{2}*\frac{400 tepizes}{m^{2}}*\frac{\$0.625}{1 tepiz}=\$125,000[/tex]
Next, we need to figure out what is the price of the [tex]500m^{2}[/tex] of coth is in New York:
[tex]500m^{2}*\frac{1yd^{2}}{(0.9144m)^{2}}*\frac{\$120}{1 yard^{2}}=\$71,759.40[/tex]
so now we subtract the two amounts so we get:
$125,000-$71,759.40=$53,240.60
The plates of a parallel-plate capacitor have constant charges of +Q and?Q. Do the following quantities increase, decrease, or remain the same as the separation of the plates is increased?
A) the electric field between the plates
B) the potential difference between the plates
C) the capacitance
D) the energy stored in the capacitor
Explanation:
(A) Electric field for the parallel plate capacitor is given by :
[tex]E=\dfrac{\sigma}{2\epsilon_o}[/tex]
It is clear that the electric field does not depend on the separation of the plates.
(B) The relation between the electric field and the electric potential is given by :
[tex]V=Ed[/tex]
d is the separation between plates. So, if the separation of the plates is increased, the potential difference increases.
(C) The capacitance of the parallel plate capacitor is given by :
[tex]C=\dfrac{A\epsilon_o}{d}[/tex]
So, the capacitance decreases when the separation of the plates is increased.
(D) The energy stored in the capacitor is given by :
[tex]E=\dfrac{1}{2}CV^2[/tex]
[tex]E=\dfrac{1}{2}C(Ed)^2[/tex]
So, the energy stored in the capacitor is increased when the separation of the plates is increased.
Answer:
a)constant
b)constant
c)constant
d) constant
Explanation:
a)
The electric field between the plates remain constant. The Electric field between the plates is given as:
[tex]E=\frac{\sigma}{\epsilon}[/tex]
where:
[tex]\sigma=[/tex] surface charge density
[tex]\epsilon=[/tex] permittivity of the material between the plates
b)
The potential difference between the plates is related as:
[tex]V=\frac{Q}{C}[/tex]
and
[tex]E=\frac{V}{d}[/tex]
where:
d = distance between the plates
Therefore the potential difference remains constant when the capacitor plates distance remains constant.
c)
the capacitance:
[tex]C=\frac{Q}{V}[/tex]
When the charge and potential difference is constant then the capacitance also remains constant.
d)
Energy stored in a capacitor:
[tex]U=\frac{1}{2} C.V^2[/tex]
Since capacitance and potential difference are constant therefore potential difference is also constant.