Engineers have determined that the maximum safe speed around a
particular non-banked curve is 20 m/s. If the coefficient of friction
between the tires and the road is 0.703, what is the radius of the curve?

4) none of these matter. with no air resistance, they all hit the ground at the same time.​

Explanation:

The motion of the objects is a free fall motion, since the only force acting on them is gravity. Therefore, it is a uniformly accelerated motion with constant acceleration [tex]g[/tex] (acceleration of gravity) towards the ground, and so we can find the time of flight by using the suvat equation:

[tex]s=ut+\frac{1}{2}at^2[/tex]

where

s is the vertical displacement (equal to height of the tower)

u = 0 is the initial velocity

t is the time

[tex]a=g[/tex] is the acceleration

Re-arranging the equation.

[tex]t=\sqrt{\frac{2s}{g}}[/tex]

As we can see, the time of flight depends only on the height of the tower (s) and the acceleration due to gravity (g): therefore, the three objects reach the ground at the  same time.

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Answer: two

Explanation:

Answer:

Its 2

Explanation:

This compound has a central Sulfur atom surrounded by 4 Oxygens in a covalent bonds, with an overall charge of negative 2 and 2 Sodium atoms with a charge of positive one. Thus making the answer 2.

Weather forecaster can predict hurricanes through two methods:

Explanation:

Prediction of Hurricanes

With the help of elementary statistics, meteorologists can predict the intensity of hurricanes coming in specific regions with the approximate wind speeds. The possible trajectory of hurricanes can be drawn as a cone which is updated by estimating the error in the prediction.

Based on the past events of hurricanes and the current climate conditions, a statistical regression equation is formed. There are many many models such as NHC90 and BAM that help meteorologists to predict the intensity of waves and eventually the probability of hurricanes coming in specific regions.

Answer:

Elements belonging to the same periodic group reflects similar chemical properties because of the same number of valence electrons residing in their outermost orbits that reflect the same energy level.

Explanation:

Elements of a periodic group reflecting similar properties

We often observe that a specific group of elements reflect common characteristics towards other elements. This is because these elements have their valence electrons in the same energy levels.

This is the prime factor according to which elements are kept in a specific group in the periodic table. All elements in the group have the same number of valence electrons. These elements may have different number of electrons over all. Elements belonging to the same group shows the same chemical properties such as bonding with other elements, reacting to other substances etc.

Elements in the same group on the periodic table have similar properties because they have the same number and distribution of valence electrons. This affects how they behave chemically, as represented by the similarities within groups such as the alkali metals and the halogens.

Elements in a group on the periodic table exhibit similar properties due to their similar electron configuration. That is, they all have the same number and distribution of electrons in their valence shells. This shared trait influences how these elements behave chemically. For instance, in Group 1 (the alkali metals), elements like lithium and sodium each have only one valence electron, which makes them highly reactive. Similarly, elements in Group 17 (the halogens) like fluorine and chlorine each have seven valence electrons, making them also very reactive, but in a different way than Group 1 elements. The nature of these group similarities underpins the principle of the periodic table and helps predict how different elements are likely to react.

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The work done against gravity is 100 J

Explanation:

The work done against gravity in order to lift an object is equal to the change in gravitational potential energy of the object:

[tex]W=mg\Delta h[/tex]

where

m is the mass of the object

g is the acceleration of gravity

[tex]\Delta h[/tex] is the change in height of the object

For the object in this problem, we have:

m = 5 kg

[tex]g=10 m/s^2[/tex]

[tex]\Delta h = 2 m[/tex]

Substituting into the equation,

[tex]W=(5)(10)(2)=100 J[/tex]

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Answer:

m=ρV

V=LxWxD

V=4x10x2=80

m=2*80=160 grams

Explanation:

Mass is equal to density multiply by volume of object. Volume of rectangle pice can be calculated by multiplying all sides.

Final answer:

The mass of the metal piece is calculated by first obtaining the volume, which is 80 cm³, and then using the density to find the mass, resulting in a mass of 160 g.

Explanation:

Metals are components or with brilliant, hard, moldable, blending, pliable properties. Name of metal (material) types are - Gold, Silver, Aluminum, Copper, Iron, and so on. They are utilized to create devices as they might be strong and effectively formed.

To find the mass of a piece of metal with given dimensions and density, first calculate its volume and then apply the formula for mass. The volume of a rectangular piece of metal is found by multiplying its length, width, and height.

Volume = Length x Width x Height = 4 cm x 10 cm x 2 cm = 80 cm³.

Once the volume is known, the mass can be calculated using the given density:

Mass = Density x Volume = 2 g/cm³ x 80 cm³ = 160 g.

Therefore, the mass of the metal piece is 160 grams.

Answer:

The force of Earth's gravity is 327954 N

Explanation:

Given:

Mass of the space craft = 1350 kg

Mass of the earth = 6*10^ 24

Distance = 1.28 * 10 ^ 6

To Find:

The  force of Earth's gravity = ?

Solution:

The force of attraction between a planet and an object kept in space is given by the expression

[tex]F =\frac{GMm}{R^2}[/tex]

where

M is the mass of the earth

m is the mass of the space craft

R is the distance between the earth and the space craft and

G is the gravitational constant

On substituting the values

[tex]F =\frac{(6.67 \times 10^{-11})(6\times10^ {24})(1350)}{(1.28\times 10^6)^2}[/tex]

[tex]F =\frac{(54027\times 10^{13})}{(1.28\times 10^6)^2}[/tex]

[tex]F =\frac{(54027\times 10^{13})}{(1.6384\times 10^{12})}[/tex]

F = 327954 N

Answer:

Explanation:The container weighs 352.8

Answer:

Gravity is considered a theory because it is supported by extensive experimental evidence and has successfully predicted the behavior of objects in the universe.

Hope this helps you mate

Answer:

kinetic energy

Explanation:

before energy is put in motion its being stored as potential energy then becomes kinetic once its released

Kinetic energy is the energy of motion possessed by an object.

The energy of motion is known as kinetic energy. It is the energy possessed by an object due to its motion. Kinetic energy can be calculated using the formula:

Kinetic Energy = 1/2 * mass * velocity2

For example, a moving car has kinetic energy because it is in motion.

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Answer:

[tex]0.5mv^{2}[/tex]

Explanation:

Kinetic energy, [tex]KE= 0.5mv^{2}[/tex]

while potential energy, PE= mgh where m is the mass, v is the velocity of the ball, g is acceleration due to gravity and h is the height.

The question requires kinetic energy hence we use the [tex]KE= 0.5mv^{2}[/tex]

Since the figures are not given, we maintain that [tex]KE= 0.5mv^{2}[/tex]

The kinetic energy of a ball just before it hits the ground is its motion energy due to gravitational potential energy conversion. It can be computed using the kinetic energy formula and the ball's mass and velocity. The energy dissipates and converts during the bounce, depending on the coefficient of restitution.

Kinetic Energy Before Colliding with the Ground

The kinetic energy of a ball just before it hits the ground is the energy it has due to its motion. This energy is obtained from the conversion of gravitational potential energy into kinetic energy as the ball falls. Assuming no non-conservative forces are acting on the ball, such as air resistance, the kinetic energy can be calculated using the equation KE = 1/2 mv₂, where m is the mass of the ball and v is its velocity just before impact. The velocity can be found using kinematic equations or the conservation of energy principle. Since its initial potential energy is converted entirely into kinetic energy at the moment before collision, if the height from which the ball was dropped is known and the mass of the ball is given, one can accurately calculate its velocity and consequently its kinetic energy just before the impact.

Conversion and Dissipation of Energy During Bounce

Once the ball collides with the ground, its kinetic energy is temporarily transferred into other forms, including elastic potential energy and thermal energy due to deformation. The coefficient of restitution, represented as e, determines what fraction of the kinetic energy is retained after the collision. Hence, the kinetic energy of the ball just after it bounces up will be a fraction e2 of its initial kinetic energy before the collision. As the ball ascends, this kinetic energy is once again converted back into potential energy.

Answer: 2N in Daniel's direction.

Explanation:

Since, both of them are playing a game of tug and war, the resultant(net) force consists of opposing forces.

Net force= 12N-10N = 2N

And the net force is in Daniel's direction because Daniel exerted greater force.

In the tug-of-war scenario between John and Daniel, the net force is 2 N in Daniel's direction, as his force is 12 N compared to John's 10 N. The forces are unbalanced with the larger force determining the direction of the net force.

When John and Daniel play tug-of-war, John exerts a force of 10 N while Daniel exerts a slightly higher force of 12 N. To find the net force, we consider the direction of the forces as well. Since they are exerting forces in opposite directions, the net force is the difference between the two forces. Therefore, the net force is 12 N (Daniel's force) - 10 N (John's force) = 2 N in the direction of the larger force, which is Daniel's direction.

Understanding tug-of-war forces is an interesting way to conceptualize the principles of balanced and unbalanced forces. In this case, the forces are unbalanced because one player is exerting more force than the other, causing the net force to shift in one direction.

Final answer:

The average velocity of the airplane is calculated using the formula: velocity equals displacement divided by time. For a displacement of 500 km northwest over 1.2 hours, the average velocity is 416.67 km/h northwest.

Explanation:

Calculating Average Velocity

To calculate the average velocity of an airplane that has a displacement of 500 km northwest in 1.2 hours, we need to use the formula for average velocity, which is the displacement divided by the time taken. Since the displacement is given as a northwest direction, we are dealing with vector quantities, meaning that both magnitude and direction are important. However, for average velocity, we are concerned with the magnitude of this vector quantity.

The formula to calculate average velocity, v, is:

v =[tex]rac{d}{t}[/tex]

In this problem:

Displacement (d) = 500 km northwest

Time (t) = 1.2 hours

To find the average velocity, we divide the displacement by the time:

v =   rac{500}{1.2}   = 416.67 km/h northwest

The airplane's average velocity is 416.67 km/h in the northwest direction.

Explanation:

When an object falls freely, it falls due to the influence of gravity and this free falling object is called as acceleration of gravity. The free falling object has an acceleration value of about 9.8 m / s^2 downward on Earth.

The Acceleration of Gravity is denoted by a symbol g.

Solution:  

Initial speed = 8.0 m / s.

a. To calculate the time taken, (initial velocity is 8.0 m/s and the final velocity        is 0)

                                     T = Velocity / gravity

Time taken to reach highest point t = 8 / 9.8 = 0.816 s.

b. To calculate the height, (initial velocity is 8.0 m/s and the final velocity is   0)

                                    h = square of velocity / (2 * g)

The maximum height the ball reaches h = (8 * 8) / (2 * 9.8)

                                                                    = 64 / 19.6 = 3.26 m.

The average speed is 0.517 m/s

The average velocity is 0.12 m/s west

Explanation:

When dividing the total distance covered by object by time, we get the value for average speed.

[tex]\text { speed }=\frac{\text {distance}}{\text {time}}[/tex]

Calculate the distance without consideration of motion’s direction. So, the distance walks 144 m first, and then another 89 m, so the total distance covered is

d = 144 + 89 = 233 meters

Given t = 7.5 minutes. Convert minute into seconds,  

[tex]7.5 \times 60=450 \text { seconds }[/tex]

So, the average speed can be calculates as below,

[tex]\text { speed }=\frac{233}{450}=0.517 \mathrm{m} / \mathrm{s}[/tex]

When dividing the object’s displacement by time taken, we can calculate average velocity.

[tex]\text {velocity}=\frac{\text {displacement}}{\text {time}}[/tex]

In given case, the students walks 144 m west first, and then 89 m east. The displacement is the distance in a straight line between the initial and final position: therefore, in this case, the displacement is

d = 144 (west) - 89 (east) = 55 m (west)

The time taken is t = 450 s

So, the average velocity is

[tex]\text {velocity}=\frac{55}{450}=0.12 \mathrm{m} / \mathrm{s}[/tex]

And the direction is west (the same as the displacement).

Answer:

The turbine blades capture the kinetic energy of the water The mechanical energy of the turbine rotates the generator parts. The generator produces the electrical energy that is then transferred via power lines

Explanation:

Hydroelectric Plant

It's widely used to transform potential gravitational energy of the water located at a higher height into electrical energy. A dam is constructed in the potential location of the power plant, so all the water is directed to the turbines at a lower level from the face of the water. This water enters a set of pipes that send the stream to the turbines, whose blades are moved by the water, capturing its kinetic energy. The turbine now has enough mechanical energy to have the generation system moving and transform mechanical into electrical energy. That electric energy is finally sent to the consuming centers through power lines.

Thus, the correct sequence is:

The turbine blades capture the kinetic energy of the water The mechanical energy of the turbine rotates the generator parts. The generator produces the electrical energy that is then transferred via power lines

Answer:The turbine blades capture the kinetic energy of the water

The mechanical energy of the turbine rotates the generator parts

The generator produces electrical energy

Electrical energy is transferred via power lines

Explanation:

bc I just took the k12 test

The reasons for solar power not being best option for some areas of country are mentioned below.

Explanation:

1. The semiconductors used are expensive and need clean environment.

2. Hard to build, install and maintain.

3. Not all areas recieve enough sunlight to make use of solar panels efficiently.

4. Not all areas have sufficient space for installation.

5. Some areas may use cheaper alterantives to generate power.

6. Not helpful on a rainy or foggy day so weather conditions of the area are a major factor.

Answer:

B. galaxies

Explanation:

Galaxies are clusters of stars, gas and dark matter. They are classified based on the shape they form. There are three main categories: Spiral, elliptical, and irregular. As their named suggests, that is what they look like.

Barred spiral galaxies are a subcategory of spiral galaxies. The nucleus of the galaxy (Center) a bar material is formed and arms branch out from the ends of it.

Some galaxies on the other hand, do not fit the main categories.

Attached is a picture of the common and uncommon categories of galaxies.

Answer:

thermal energy

Friction does negative work and removes some of the energy the person expends and converts it to thermal energy. The net work equals the sum of the work done by each individual force. The forces acting on the package are gravity, the normal force, the force of friction, and the applied force.

Explanation:

Answer:

Explanation:

Thermal energy due to heat coming in from rubbing like rubbing your hand and it feel warm

Answer:

The Saffir-Simpson Hurricane Wind Scale is a 1 to 5 rating based on a hurricane's sustained wind speed. This scale estimates potential property damage. Hurricanes reaching Category 3 and higher are considered major hurricanes because of their potential for significant loss of life and damage. Category 1 and 2 storms are still dangerous, however, and require preventative measures. In the western North Pacific, the term "super typhoon" is used for tropical cyclones with sustained winds exceeding 150 mph. Note that all winds are using the U.S. 1-minute average.

Category One Hurricane

     Winds 74-95 mph (64-82 kt or 119-153 km/hr). Very dangerous winds will produce some damage: Well-constructed frame homes could have damage to roof, shingles, vinyl siding and gutters. Large branches of trees will snap and shallowly rooted trees may be toppled. Extensive damage to power lines and poles likely will result in power outages that could last a few to several days. Irene of 1999, Katrina of 2005, and several others were Category One hurricanes at landfall in South Florida.

Category Two Hurricane

     Winds 96-110 mph (83-95 kt or 154-177 km/hr). Extremely dangerous winds will cause extensive damage: Well-constructed frame homes could sustain major roof and siding damage. Many shallowly rooted trees will be snapped or uprooted and block numerous roads. Near-total power loss is expected with outages that could last from several days to weeks. Frances of 2004 was a Category Two when it hit just north of Palm Beach County, along with at least 10 other hurricanes which have struck South Florida since 1894.

Category Three Hurricane

    Winds 111-129 mph (96-112 kt or 178-208 km/hr). Devastating damage will occur: Well-built framed homes may incur major damage or removal of roof decking and gable ends. Many trees will be snapped or uprooted, blocking numerous roads. Electricity and water will be unavailable for several days to weeks after the storm passes. Unnamed hurricanes of 1909, 1910, 1929, 1933, 1945, and 1949 were all Category 3 storms when they struck South Florida, as were King of 1950, Betsy of 1965, Jeanne of 2004, and Irma of 2017.

Category Four Hurricane

     Winds 130-156 mph (113-136 kt or 209-251 km/hr). Catastrophic damage will occur: Well-built framed homes can sustain severe damage with loss of most of the roof structure and/or some exterior walls. Most trees will be snapped or uprooted and power poles downed. Fallen trees and power poles will isolate residential areas. Power outages will last weeks to possibly months. Most of the area will be uninhabitable for weeks or months. The 1888, 1900, 1919, 1926 Great Miami, 1928 Lake Okeechobee/Palm Beach, 1947, Donna of 1960 made landfall in South Florida as Category Four hurricanes.

Final answer:

Hurricane A most likely caused the greatest damage as it is categorized as a Category 5 hurricane with wind speeds exceeding 155 mph, known for catastrophic impact.

Explanation:

Based on the data provided, Hurricane A, with an average wind speed of 160 miles per hour, most likely caused the greatest damage. According to the Saffir-Simpson Hurricane Scale, Hurricane A's wind speed places it as a Category 5 hurricane. Category 5 hurricanes have sustained winds of more than 155 miles per hour and are known for catastrophic damage, including destroying buildings, roofs, and structures, as well as uprooting trees and shrubs. As such, the hurricane with the highest wind speeds is usually expected to cause the most severe destruction. This is further supported by the fact that the power of a hurricane scales as the cube of wind velocity, and given that velocities exceed 50 m/s (approximately 110 mph), the intensity and potential for destruction grows significantly with increases in wind speed.

Answer:

Explanation:

Using conservation of momentum

[tex]m_1=59+220=279kg[/tex]

[tex]m_2=2.1kg[/tex]

[tex]U_1=12m/s[/tex]

[tex]U_2=-44m/s[/tex]

[tex]m_1U_1+m_2U_2=(m_1+m_2)V\\\\\frac{278\times 12-2.1\times 44}{279+2.1}=V\\\\V=11.58m/s[/tex]

The velocity of the motorcycle after collision is 11.6 m/s.

Using the principle of conservation of momentum, the total momentum of the system remains constant. Hence, momentum after collision must be equal to momentum before collision.

Thus;

[(55 + 220) Kg * 12 m/s] +  2.1 kg * (-44m/s) = (55 + 220 + 2.1) v

3300 - 92.4 = 277.1v

v = 3300 - 92.4/277.1

v = 11.6 m/s

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Answer:

kenetic energy

When you arent moving something its called potential enegy when its moving it changes into kinetic energy

Answer:

momentum, speed, velocity, and kinetic energy

Explanation:

1) Distance: 9 blocks

2) Displacement: 4.12 blocks at [tex]76^{\circ}[/tex] north of east

Explanation:

1)

Distance is a scalar quantity that represents the total length of the path covered by a body during its motion, regardless of its direction. It can be calculated by simply adding the length of each part of the path.

In this problem, the motion of the person is:

4 blocks north

3 blocks east

2 blocks west

Therefore, the distance covered is just the sum of the length of each path:

distance = 4 + 3 + 2 = 9 blocks

2)

Displacement is a vector quantity connecting the initial position to the final position of the motion of a body. Since it is a vector, it has both a magnitude and a direction.

The magnitude can be computed by calculating the distance in a straight line between the initial and final position of motion.

In this problem, we have:

- The final position along the north-south direction is 4 blocks north

- The final position along the east-west direction is

(3 east) + (2 west) = 1 block east

Therefore, the magnitude of the displacement is given by Pythagorean's theorem:

[tex]displacement = \sqrt{4^2 + 1^2}=4.12[/tex] blocks

and the direction is given by

[tex]\theta=tan^{-1}(\frac{4}{1})=76^{\circ}[/tex] north of east.

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Answer:

15.0 m/s

Explanation:

Take the down direction to be positive.

Given:

Δy = 11.5 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: v

v² = v₀² + 2aΔy

v² = (0 m/s)² + 2 (9.8 m/s²) (11.5 m)

v = 15.0 m/s

Answer:

1. 579 x 10 ^-22N

Explanation:

F = kq1q2/r^2

   = 9.0 x 10^9 x 5.67 x 10^-18 x 3.79 x 10^-18/ (3.5 x 10^-2)^2

    = 1. 579 x 10 ^-22N

The attraction force between two charges is [tex]1.55 \times 10^{-22} \;\rm N[/tex].

Coulomb's law is used to find out the force of attraction between two charges placed at a certain distance. This law states that, when two point charges are placed at a distance, the force of attraction between them is proportional to the product of both charges and inversely proportional to the square of the distance between them.

[tex]F \propto q_1q_2[/tex] and [tex]F \propto \dfrac{1}{r^2}[/tex]

[tex]F =K \dfrac {q_1q_2}{r^2}[/tex]

Where K is the coulombs constant whose value is 8.988×109 N⋅m2⋅C−2.

Given that charges q1 and q2 are 5.67 x 10-18 C and 3.79 x 10 "C. The distance r is 3.5 x 10 m. The force of attraction is given below.

[tex]F = 8.98\times 10^9 \dfrac {5.67 \times 10^{-18}\times 3.79 \times 10^{-18}}{(3.5\times 10^{-2})^2}[/tex]

[tex]F = 1.55\times 10^{-22} \;\rm N[/tex]

Hence we can conclude that the attraction force between two charges is [tex]1.55 \times 10^{-22} \;\rm N[/tex].

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The sun’s gravitational attraction and the planet’s inertia keeps planets moving is circular orbits.

Explanation:

The planets in the Solar System move around the Sun in a circular orbit. This motion can be explained as a combination of two effects:

1) The gravitational attraction of the Sun. The Sun exerts a force of gravitational attraction on every planet. This force is directed towards the Sun, and its magnitude is

[tex]F=G\frac{Mm}{r^2}[/tex]

where

G is the gravitational constant

M is the mass of the Sun

m is the mass of the planet

r is the distance between the Sun and the planet

This force acts as centripetal force, continuously "pulling" the planet towards the centre of its circular orbit.

2) The inertia of the planet. In fact, according to Newton's first law, an object in motion at constant velocity will continue moving at its velocity, unless acted upon an external unbalanced force. Therefore, the planet tends to continue its motion in a straight line (tangential to the circular orbit), however it turns in a circle due to the presence of the gravitational attraction of the Sun.

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The volume is [tex]153.54 cm^3[/tex]

Explanation:

The volume of the block, assuming it is a parallelepided, is given by

[tex]V=L\cdot W \cdot H[/tex]

where

L is the length

W is the width

H is the height

For the block in this problem, we have

L = 6.21 cm

W = 4.63 cm

H = 5.34 cm

Therefore, the volume is

[tex]V=(6.21)(4.63)(5.34)=153.54 cm^3[/tex]

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In Newton's third law, the action and reaction forces D.)act on different objects

Explanation:

Newton's third law of motion states that:

"When an object A exerts a force on object B (action force), then action B exerts an equal and  opposite force (reaction force) on object A"

It is important to note from the statement above that the action force and the reaction force always act on different objects. Let's take an example: a man pushing a box. We have:

As we can see from this example, the action force is applied on the box, while the reaction force is applied on the man: this means that the two forces do not act on the same object. This implies that whenever we draw the free-body diagram of the forces acting on an object, the action and reaction forces never appear in the same diagram, since they act on different objects.

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Answer:Act on different objects

Explanation:

The work done is [tex]-1.36\cdot 10^5 J[/tex]

Explanation:

According to the work-energy theorem, the work done by external forces on the car is equal to the change in kinetic energy of the car. Therefore, we have:

[tex]W=\Delta K\\W = \frac{1}{2}mv^2-\frac{1}{2}mu^2[/tex]

where

W is the work done by the external forces

m is the mass of the car

v is its final velocity

u is its initial velocity

In this problem, we have:

m = 1165 kg

[tex]u=55 km/h =15.3 m/s[/tex]

v = 0 (the car comes to a stop)

Solving for W, we  find the work done by the frictional forces:

[tex]W=\frac{m(v^2-u^2)}{2}=\frac{(1165)(0-15.3^2)}{2}=-1.36\cdot 10^5 J[/tex]

Where the negative sign indicates that the direction of the force is opposite to the direction of motion of the car.

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