"Electromagnetic radiation travels or propagates through space in the form of a wave but can interact with matter as a particle of energy called a photon. This dual nature is referred to as":____________

Answer:

1.86 s

Explanation:

Given the expression

h(t) = -16t²+ 64...................... Equation 1

Where h = height of the object, t = time it will take the object to hit the ground.

Given: h = 64 foot.

We have to concert from foot to meters

If 1 foot =  0.3048 meters

Then, 64 foot = 0.3048×64 = 19.51 meters.

We substitute the value of h into equation

119.51 = -16t²+64

-16t² = 199.51-64

-16t² = 55.51

t² = 55.51/-16

t² = 3.469

t = √3.469

t = 1.86 s.

Hence it will take the object 1.86 s to hit the ground.

Impulse delivered

or

Change in momentum.

Final answer:

The area under the net external force vs time graph is equal to impulse or change in momentum, representing the impulse-momentum theorem.

Explanation:

The area under the curve of the net external force vs time graph is equal to impulse or change in momentum. This relationship arises from Newton's second law of motion, which states that the force acting on an object is equal to the rate of change of its momentum. In graphical terms, when force is plotted on the y-axis and time on the x-axis, the area under the curve represents the impulse, which is the product of the force and the time interval over which it acts. This impulse is equivalent to the change in momentum of the object according to the impulse-momentum theorem.

Answer: 2000 v/m, from B to A.

Explanation: if point A is at the origin (x=0m) and point B is at the point x= 0.150m, the distance between both points (d) = 0.150 - 0 = 0.150m

Point A is at a 200v potential and point B is at a potential of 500v.

Difference in potential produces a voltage (v) = 500 - 200 = 300v.

The relationship between voltage, electric field intensity and distance is given by the formulae below

v=Ed

Where v = voltage = 300v, electric field =?, d = 0.150m

300 = E×0.150

E = 300/0.150

E = 2000 v/m.

Since point B is at higher potential than A, it implies that if there is an electron in this field, it will move from B to A thus making the direction of field be from B to A.

The electric field's magnitude is 2000v/m and its direction is from B to A along the negative x-axis.

The electric field (E) in a region of space is defined as the electric force per unit charge. The electric field direction is taken to be the direction of the force it would exert on a positive test charge. The electric potential at a point in the field is the work done in bringing unit positive charge from infinity to that point. In your case, the electric potential difference, ΔV between point A and point B is: ΔV = Vb - Va = 500v - 200v = 300v. The separation between A and B, Δx is 0.150m. The magnitude of the electric field E can be calculated by the equation E = - ΔV / Δx = - 300v / 0.150m = - 2000v/m. The negative sign indicates that the field direction is from B to A along the negative x-axis.

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Answer:

half filled bucket requires more force to stop

Explanation:

When spinning a bucket half filled it is clear that is has greater mass of water than the quarter filled bucket.

While revolving any mass tied about a fixed point we have a centripetal force acting on the bucket which makes it take the circular path during the motion.

This is centripetal force is given as:

[tex]F_c=m.\frac{v^2}{r}[/tex]

where:

[tex]m=[/tex] mass of the revolving body

[tex]v=[/tex] tangential velocity

[tex]r=[/tex] radius of revolution

The revolving mass has to be brought to rest in this case the momentum of the heavier mass will be greater and from the Newton's second law of motion we have the the rate of change in momentum directly proportional to the force applied.

Mathematically:

[tex]F=\frac{d}{dt}(m.v)[/tex]

here the mass is constant so,

[tex]F=m.\frac{d}{dt} v[/tex]

Therefore if the length of the rope, and the speed of revolution is same in both the case then the half filled bucket whose mass is greater than the quarter filled bucket will require more force to stop the circular motion of the bucket.

Answer:  so there is potiental enrgy need to stop spinning the bucket

Explanation:The Force of and bucket outcome is determed by the force of that i uesd to

Answer:

8.64 seconds

Explanation:

According to the question

[tex]10^{10}\ years=1\ day[/tex]

[tex]1\ year=\dfrac{1}{10^{10}}\ day[/tex]

Humans have lived for [tex]10^6[/tex] years

In one universe day

[tex]10^6\ years=10^6\times \dfrac{1}{10^{10}}=10^{-4}\ day[/tex]

In seconds

[tex]10^{-4}\times 24\times 60\times 60=8.64\ seconds[/tex]

In one universe day humans have lived for 8.64 seconds

Humans have been around for 8.64 'universe seconds'.

The question asks for a conversion of human existence into 'universe seconds' given that humans have been around for approximately 106 years and the universe is approximately 10^10 years old. To answer this, one must conceptualise a 'universe day' as representing the entire 10^10 years of the universe's existence and break it down into 'universe seconds' in the same way that a normal day is broken down into normal seconds.

A regular day has 86,400 seconds (24 hours × 60 minutes per hour × 60 seconds per minute). As humans have existed for 10^6 years in the context of the universe's 10^10 years, we can calculate the fraction of the universe's existence that humans have been present for:

Human existence fraction = (Human years) / (Universe years) = 10^6 / 10^10 = 1 / 10^4

Now, we multiply this fraction by the total number of seconds in a day to find the equivalent 'universe seconds' of human existence:

Universe seconds of human existence = 1 / 10^4 × 86,400

Universe seconds of human existence = 8.64

Therefore, humans have existed for 8.64 'universe seconds' when defining the age of the universe as 1 'universe day'.

Answer:

The question is incomplete or some details are missing. The last part of the question says ; What is the total distance, side to side, that the top of the building moves during such an oscillation? Express your answer to two significant figures and include the appropriate units.

Total distance (x) = 0.3972m

Explanation:

The detailed steps is as shown in the attachment

Answer: a) 12.9 m b) 0.40 rad/s² c) 335.4 J d) 1349.06 J

Explanation:

a)

Distance traveled= R∅

where ∅= [tex]\frac{(2\pi )^2 }{(2.8)^2}[/tex] / 2*α

To find α we have

Sum of torque= Iα

F x r x number of children = m*r²/2 * α

26 x [tex]\frac{4.1}{2}[/tex] * 4 = (255) * (4.10/2)² /2 *α

Solving we get,

α= [tex]\frac{213.2}{535.82}[/tex]

α= 0.40

So,

∅= [tex]\frac{(2\pi )^2 }{(2.8)^2}[/tex] / 2*α

Becomes

∅= 6.29

Now,

Distance traveled= 4.1/2 * 6.29

Distance traveled= 12.9 m

b)

Angular acceleration= 0.40

c)

Work done= F x distance traveled

Work done= 26 x 12.9

Work done= 335.4 J

d)

Kinetic energy= [tex]\frac{1}{2}* I * (\frac{2\pi }{2.8})^2[/tex]

Putting values we get,

Kinetic energy= 267.91 * 5.03

Kinetic energy= 1349.06 J

The merry-go-round problem involves calculating the distance each child runs, the angular acceleration, the work done by each child, and the kinetic energy of the system, using principles of rotational dynamics and energy.

We are given a merry-go-round scenario with children exerting force to set it in motion. Let's break down the problem step by step.

(a) Distance run by each child:

(b) Angular acceleration:

(c) Work done by each child:

(d) Kinetic energy of the merry-go-round:

Frequency division multiplexing operates by dividing the signal into different frequencies

Explanation:

The technique that is used in the networking is the Frequency Division Multiplexing. using this technique, the existing bandwidths can be partitioned into different frequency bandwidths. These are not interrupting with each other. Each bandwidth can be used for carrying signals individually.

Using this technique many users can share a particular communication medium and they will not be interrupted with each other's communication.Hence this technique can also be termed as Frequency Division Multiple Access.

Frequency Division Multiplexing operates by dividing a signal into different frequencies to enable multiple transmissions at the same time. This method is used in FM radio and television broadcasts, as well as cell phone conversations and computer data transmissions.

Frequency Division Multiplexing (FDM) operates by dividing the signal into different frequencies. This can be seen in how FM (Frequency Modulation) radio signals are used. In FM radio transmission, the information is carried by varying the frequency of the carrier wave and keeping its amplitude constant. This forms different channels on which multiple signals can be transmitted simultaneously without interfering with each other.

Another example is how television broadcasts. Since a vast amount of visual and audio information needs to be carried, each channel requires a larger range of frequencies, these fall under VHF and UHF (high to ultra-high frequencies).

Cell phone conversations and computer data are also transmitted using a similar approach by converting the signal into a sequence of binary ones and zeros. This binary sequence can be transmitted via different frequencies, allowing multiple data transmissions to take place at the same time.

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The object's weight on the other planet is determined by the force of gravity on that planet, which depends on the planet's mass and radius. The object's weight can be found by plugging these values into the formula for gravitational force, once the actual mass of the object is obtained by dividing its weight on Earth by the Earth's gravitational acceleration.

To find the weight of the object on the other planet, we need to calculate the gravitational pull on that planet. The force of gravity is given by the formula F = G * (m1 * m2) / r^2, where G is the gravitational constant, m1 and m2 are the masses of the objects, and r is the distance between the centers of the two objects (which in this case is the radius of the planet).

On Earth, the object weighs 100 lbs. This is its mass times the gravity of Earth, which is roughly 9.8 m/s^2. So we can find the mass of the object by dividing the weight (100 lbs) by the acceleration due to gravity (9.8 m/s^2).

The planet in question is stated to have 3 times the Earth's radius and 5 times its mass. So we substitute these values into the formula along with the mass of the object we calculated, and solve for F, the force, which will be the weight of the object on the other planet.

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Answer: perpendicular to it oscillations.

Explanation: A transverse wave is a wave whose oscillations is perpendicular to the direction of the wave.

By perpendicular, we mean that the wave is oscillating on the vertical axis (y) of a Cartesian plane and the vibration is along the horizontal axis (x) of the plane.

Examples of transverse waves includes wave in a string, water wave and light.

Let us take a wave in a string for example, you tie one end of a string to a fixed point and the other end is free with you holding it.

If you move the rope vertically ( that's up and down) you will notice a kind of wave traveling away from you ( horizontally) to the fixed point.

Since the oscillations is perpendicular to the direction of wave, it is a transverse wave

In a transverse wave, the vibrations move in a direction perpendicular to the direction of wave travel. This distinguishes them from other types of waves. An example is the movement of water waves.

In a transverse wave, the vibrations or disturbances move in a direction perpendicular (at right angles) to the direction of the wave's travel. This is the key characteristic that separates transverse waves from other types of waves. A common example of transverse waves would be waves in a body of water where the water particles move up and down causing the wave to move forward.

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4. KE increases by a factor of 16 is the answer

Explanation:

Kinetic energy  = (1/2)mv² = 0.5 mv²

where  

m  = mass, and  v = velocity.

So at 15 mph,  

K E =  0.5 m  (15) ² = 112.5 m

And at 60 mph,  

K E = 0.5 m (60)² = 1800 m

m  is the mass, and not meters.

So, 1800  m/112. 5 m = 16

16 times the Kinetic Energy.

Answer:

Explanation:

a )

Force on 5 nC due to -3 nC

= 9 x 10⁹x 5 x 3 x 10⁻¹⁸ / ( 5 x 10⁻²)²

= 5.4 x 10⁻⁵ N

X component = 5.4 x 10⁻⁵ cosθ

= -5.4 x 10⁻⁵ x 3/5

= -3.24 x 10⁻⁵ N

y component

= -5.4 x 10⁻⁵ x 4/5

= -4.32 x  10⁻⁵ N

Force on 5 nC due to 2 nC

= 9 x 10⁹x 5 x 2 x 10⁻¹⁸ / ( 3 x 10⁻²)²

= 10 x 10⁻⁵ N

x component = 10 x 10⁻⁵ N

Total x component = (10-3.24)x10⁻⁵ N

= 6.76 x 10⁻⁵ N

y component =   -4.32 x  10⁻⁵ N

magnitude = √( 6.76² + 4.32²) x 10⁻⁵ N

= 8 .02 N

DIRECTION =

Tan θ = -4.32 / 6.76

θ = 32.5

with negative x -direction , south west.

One can find the total forces exerted on the third charge in x and y directions using Coulomb's Law. The total force endured by the third charge is calculated by computing the vector sum of the individual forces. The direction of this force is determined using trigonometric principles.

Using Coulomb’s law, we can determine the forces exerted by each individual charge on the third charge. First, we need to find the distance between each charge and the third charge. We have (x12 = 3 cm, y12 = 4 cm) for the first charge and (x23 = 0 cm, y23 = 0 cm) for the second charge.

Now, the forces in x and y directions can be calculated using the formula: F = k * |q1 * q2| / r², where k is Coulomb's constant, q1 and q2 are the magnitudes of the charges, and r is the distance between the charges.

The components of the total force experienced by the third charge due to the first and the second charge can be calculated by adding the individual forces in both x and y directions. For total force magnitude use this formula: Ftotal = sqrt((Fx)² + (Fy)²).

To find the direction of the total force, you can use this formula: Tan θ = Fy / Fx. The direction of the force will be in the quadrant of the combined forces.

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Answer:

kinetic frictional force opposes the relative motion between the surfaces in contact of the book and the table.

Explanation:

Explanation:

First, we will calculate the electric potential energy of two charges at a distance R as follows.

                   R = 2r

                      = [tex]2 \times 0.1 m[/tex]

                      = 0.2 m

where,    R = separation between center's of both Q's. Hence, the potential energy will be calculated as follows.

                U = [tex]\frac{k \times Q \times Q}{R}[/tex]

                    = [tex]\frac{8.98 \times 10^{9} \times (3 \times 10^{-6} C)^{2}}{0.1}[/tex]

                    = 0.081 J

As, both the charges are coming towards each other with the same energy so there will occur equal sharing of electric potential energy between these two charges.

Therefore, when these charges touch each other then they used to posses maximum kinetic energy, that is, [tex]\frac{U}{2}[/tex].

Hence,   K.E = [tex]\frac{U}{2}[/tex]

                     = [tex]\frac{0.081}{2}[/tex]

                     = 0.0405 J

Now, we will calculate the speed of balls as follows.

                 V = [tex]\sqrt{\sqrt{\frac{2 \times K.E}{m}}[/tex]

                     = [tex]\sqrt{\sqrt{\frac{2 \times 0.0405}{4 kg}}[/tex]

                     = 0.142 m/s

Therefore, we can conclude that final speed of one of the balls is 0.142 m/s.

When a bungee cord is stretched a distance x, it exerts an opposing force given by the formula F = bx2. Integrated over the distance of stretch, this results in a work done of 2 Joules for a stretch distance of 1 meter and force constant b = 6 N/m^2.

The work done in stretching an elastic object like a bungee cord is given by the integral of the force over the distance of stretch. Given the force exerted by the bungee cord is F = bx^2, where b = 6 N/m^2 and the work W is defined as the integral from 0 to x of F dx, the formula to calculate work done becomes W = ∫from 0 to 1 (bx^2) dx. Solving this integral gives W = (b/3)x^3 evaluated from 0 to 1, which simplifies to W = (6/3) (1) = 2 Joules. So, the correct answer is 2 Joules.

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Answer:

The correct answer is

35.01 m/s

Explanation:

To solve the question, we note the given variables thus

Height of platform S = 1.6 m

Distance from the platform the ball landed = 20 m

S = ut + 0.5gt² therefore 1.6 = 0.5 × 9.81 × t² or t = 0.57 s

Distance = 20 m  = velocity × time

Therefore velocity = Distance / time = 20 m/0.57 s = 35 m/s

Answer:

Explanation:

Answer:

qU = Ek = ½mv²

6.00 * 10^-7  * 3000 = ½ * 0.0026 * v²

v² = 0.7222167

v = 0.8498 m/s

Final answer:

After deploying the parachute, a skydiver does experience nonzero acceleration as the increased drag causes rapid deceleration until reaching a new lower terminal velocity.

Explanation:

Immediately after deploying her parachute, a skydiver does indeed have a nonzero acceleration. When a parachute opens, it rapidly increases the area exposed to air resistance, causing a significant increase in drag. As a result, the force of air resistance acting on the skydiver greatly exceeds the force of gravity, which causes a rapid deceleration of the skydiver. The magnitude of this deceleration is determined by the net force acting on the skydiver, which now includes the strong opposing force from the parachute's drag. This deceleration continues until the skydiver reaches a new, much lower terminal velocity with the parachute open.

Answer:

40 seconds

Explanation:

Thrusting speed = V

Where V=at

a= F/m

Therefore V = Ft/m

F = 1200kN = 1200000N

t = 20s

m = 8.0 * 104 kg

V = 1200000 * 20 / 80000

V = 300m/s

Time for the spaceship to coast a distance of 12km

Distance = Vt

t = 12000/300 = 40seconds

The time taken for taking the  spaceship to coast this distance is 40 seconds

Thrusting speed = V

Where

V=at

And,  

[tex]a= F\div m[/tex]

Therefore [tex]V = Ft\div m[/tex]

Now  

F = 1200kN

= 1200000N

t = 20s

[tex]m = 8.0 \times 104 kg[/tex]

Now  

[tex]V = 1200000 \times 20 \div 80000[/tex]

V = 300m/s

Time for the spaceship to coast a distance of 12km

Distance = Vt

[tex]t = 12000\div 300[/tex]

= 40seconds

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Answer:

Case A: - x axis

Case B: - x axis

Case C: no force as the direction of v and B are parallel.

Explanation:

Solution:

- The direction of Force exerted by the magnetic field B with a moving charge q with a velocity of v is given by an expression:

                                     F = q*(v x B)

- Where F: force vector exerted by the field

             v: velocity vector of charged particle q.

             B: magnetic field direction

- The cross product of v with B:

       We will use right hand rule in which our fingers curl from v to B, the direction of the thumb denotes the direction of applied force. Hence,

                                Case A: - x axis

                                Case B: - x axis

                                Case C: no force as the direction of v and B are parallel.

Final answer:

The direction of the magnetic force on a positively charged particle moving through a uniform magnetic field is determined by the right-hand rule 1 (RHR-1). The force is perpendicular to the plane formed by the particle's velocity and the magnetic field. The direction of the force depends on the charge of the particle and is opposite for positive and negative charges.

Explanation:

The direction of the magnetic force on a positively charged particle moving through a uniform magnetic field is determined by the right-hand rule 1 (RHR-1). According to RHR-1, if you point your right thumb in the direction of the particle's velocity (v) and your right fingers in the direction of the magnetic field (B), then your right palm will point in the direction of the magnetic force (F) acting on the particle.

For example, if the particle is moving perpendicular to the magnetic field (B), as shown in the figure, and the particle has a positive charge, then the force (F) will be directed outward from the plane formed by v and B.

It's important to note that the direction of the magnetic force on a negatively charged particle will be in the opposite direction to that on a positively charged particle.

Answer:

The lowest frequency is 45.01 Hz.

The second lowest frequency is 135.03 hz.

The highest frequency is 19993.4 Hz.

Explanation:

Given that,

Length = 1.85 m

Range of frequency = 20 hz - 20000 Hz

Temperature = 18.0°C

Suppose, the tube is closed at one end  lowest frequency , second lowest frequency   and highest frequency

We need to calculate the velocity of sound

Using formula of sound velocity

[tex]v=v_{0}+0.61\times T[/tex]

Put the value into the formula

[tex]v=332+0.061\times18[/tex]

[tex]v=333.09\ m/s[/tex]

(a). For closed end,

We need to calculate the lowest  and second lowest frequency

Using formula of frequency

[tyex]f_{n}=(2n+1)\times\dfrac{v}{4l}[/tex]

If n =0

[tex]f_{0}=\dfrac{v}{4l}[/tex]

Put the value into the formula

[tex]f_{0}=\dfrac{333.09}{4\times1.85}[/tex]

[tex]f_{0}=45.01\ Hz[/tex]

If n = 1

[tex]f_{1}=\dfrac{3v}{4l}[/tex]

Put the value into the formula

[tex]f_{1}=\dfrac{3\times333.09}{4\times1.85}[/tex]

[tex]f_{1}=135.03\ Hz[/tex]

Now, The maximum audible range is 20000 Hz.

We need to calculate the value of n

Using formula of frequency

[tex]f_{n}=(2n+1)\dfrac{v}{4l}[/tex]

Put the value into the formula

[tex]20000=(2n+1)\times45.01[/tex]

[tex]20000=2n\times45.01+45.01[/tex]

[tex]n=\dfrac{20000-45.01}{2\times45.01}[/tex]

[tex]n=221.6[/tex]

We need to calculate the maximum frequency

Using formula of frequency

[tex]f_{n}=(2n+1)\dfrac{v}{4l}[/tex]

Put the value into the formula

[tex]f_{221.6}=(2\times221.6+1)\times45.01[/tex]

[tex]f_{221.6}=19993.4\ Hz[/tex]

Hence, The lowest frequency is 45.01 Hz.

The second lowest frequency is 135.03 hz.

The highest frequency is 19993.4 Hz.

Final answer:

To find the resonant frequencies of a 1.85 m long tube, calculate the speed of sound at 18.0°C, and determine the wavelengths for both an open and closed tube. Use these to calculate the fundamental frequencies, which are 92.5 Hz for the open tube and 46.3 Hz for the closed at one end tube, with higher harmonics also possible in the audible range.

Explanation:

The question involves calculating the resonant frequencies of a tube at a certain temperature, which relates to the physics concept of standing waves in air columns. Specifically, a 1.85 m long tube will produce different frequencies based on whether it's closed at one end or open at both ends, due to the formation of nodes and antinodes. At 18.0°C, the speed of sound in air can be calculated using the formula v=331.4 + 0.6T, where T is the temperature in degrees Celsius. This gives 331.4 + 0.6(18.0) = 342.2 m/s for the speed of sound. The wavelength λ for the fundamental frequency (for a tube open at both ends) is 2L, where L is the length of the tube. Thus, λ = 2(1.85 m) = 3.70 m. The frequency can then be calculated using f = v/λ, resulting in approximately 92.5 Hz. For a tube closed at one end, the fundamental frequency has a wavelength of 4L, because only quarter-wavelengths can fit in the tube, making the fundamental frequency approximately 46.3 Hz. Higher harmonics can also be calculated for both cases, but they will depend on the number of nodes and antinodes that can fit within the tube for closed and open situations respectively.

Answer: B. Sensation

Explanation:

Sensation is input about the physical world obtained by our sensory receptors, and perception is the process by which the brain selects, organizes, and interprets these sensations. In other words, senses are the physiological basis of perception. Perception of the same senses may vary from one person to another because each person’s brain interprets stimuli differently based on that individual’s learning, memory, emotions, and expectations.

The sensitivity of a given sensory system to the relevant stimuli can be expressed as an absolute threshold. Absolute threshold refers to the minimum amount of stimulus energy that must be present for the stimulus to be detected 50% of the time.

Sometimes, we are more interested in how much difference in stimuli is required to detect a difference between them. This is known as the just noticeable difference (jnd) or difference threshold.

Final answer:

The initial detection of physical stimuli such as odors, light, and sound is known as sensation, which is distinct from perception, the interpretation of these stimuli.

Explanation:

When we initially detect physical stimuli such as odors, light, and sound, the process is referred to as sensation. Sensation occurs when sensory receptors detect sensory stimuli, involving the conversion of physical energy like light or sound waves into a form of energy that the brain can understand, which is electrical stimulation. On the other hand, perception involves the organization, interpretation, and conscious experience of those sensations. It is during the perception process that we can identify specific objects, sounds, or smells and comprehend what they mean or represent in our environment. While absolute threshold refers to the minimum amount of stimulus energy required to be detected about 50% of the time, it is not the initial detection of stimuli itself.

Answer:

(a)  (18m/s/t₁)m/s²

(b) -12.5m/s²

(c) -20mls²

Explanation:

(a) Let t₁ be the initial time

a = v-u/t    

acc = (18m/s/t₁)m/s²

(b) acc = -30m/s/2.4

= -12.5m/s²

(c)The particle was at a speed of 18m/s in the positive x-direction and later after 2.4s ≡Δt, it was at speed of -30m/s in the negative x-direction.

so this imply that the velocity was first v₁ =18m/s and later v₂ = -30m/s.

The average acceleration is then:

Aavg = Δv

             Δt

= v₂-v₁/Δt

= -30-18/2.4 =  -20mls²

Answer: Symbol A

Explanation:

The four symbols described here represent:

- Symbol A shows two dots and a line draw from one not connected to the other.  --> this is an open switch. A switch is component of a circuit that is used to open/close the circuit in order to interrupt/allow the flow of current through the circuit. In this case, the switch is open, since the line does not connect the second dot.

- Symbol B shows two dots and a line draw from one connected to the other.  --> this is the symbol used to represent the switch when it is closed, so it is a closed switch.

- Symbol C shows vertical lines in the pattern long, short, long, and short with a plus and minus symbol on it. --> this symbol represents a battery, which consists of two or more cells and provides the electromotive force that pushes the electrons along the circuit.

Therefore, the correct symbol representing the open switch is

Symbol A

For this case we have that by definition, the switch is a control component that opens or closes a circuit.

It is necessary to emphasize that if the switch is open then the flow of electrons from one point to another is not allowed. Thus, it is said that we are in the presence of an open circuit.

The correct option is symbol A, an open switch is shown graphically in the attached image.

Answer:

Option B

Answer : The velocity of an electron is, [tex]6.1\times 10^{6}m/s[/tex]

Explanation :

According to de-Broglie, the expression for wavelength is,

[tex]\lambda=\frac{h}{p}[/tex]

and,

[tex]p=mv[/tex]

where,  

p = momentum, m = mass, v = velocity

So, the formula will be:

[tex]\lambda=\frac{h}{mv}[/tex]       .............(1)

where,

h = Planck's constant = [tex]6.626\times 10^{-34}Js[/tex]

[tex]\lambda[/tex] = wavelength  = [tex]1.2\times 10^{-10}m[/tex]

m = mass  of electron = [tex]9.11\times 10^{-31}kg[/tex]

v = velocity of electron = ?

Now put all the given values in formula 1, we get:

[tex]1.2\times 10^{-10}m=\frac{6.626\times 10^{-34}Js}{(9.11\times 10^{-31}kg)\times v}[/tex]

[tex]v=6.1\times 10^{6}m/s[/tex]

Thus, the velocity of an electron is, [tex]6.1\times 10^{6}m/s[/tex]

Answer:

348.57 kg

Explanation:

From the law of conservation of momentum,

Total momentum before the small child was picked = Total momentum after the small child was picked

mu + m'u' = V(m+m')................... Equation 1

Where m = mass of the skater, u = initial velocity of the skater, m' = mass of the small child, u' = initial velocity of the small child, V = common velocity after the child was picked.

Note: Assuming the small child was stationary before he was picked, the u' = 0 m/s.

making m' the subject of the equation

m' = (mu-mV)/V........................... Equation 2

Given: m = 80 kg, u = 6 m/s, V = 1.12 m/s.

Substitute into equation 2

m' = [(80×6)-(80×1.12)]/1.12

m' = (480-89.6)/1.12

m' = 390.4/1.12

m' = 348.57 kg.

Thus the mass of the small child = 348.57 kg

Answer:

1keff=1k1+1k2

see further explanation

Explanation:for clarification

Show that the effective force constant of a series combination is given by 1keff=1k1+1k2. (Hint: For a given force, the total distance stretched by the equivalent single spring is the sum of the distances stretched by the springs in combination. Also, each spring must exert the same force. Do you see why?

From Hooke's law , we know that the force exerted on an elastic object is directly proportional to the extension provided that the elastic limit is not exceeded.

Now the spring is in series combination

F[tex]\alpha[/tex]e

F=ke

k=f/e.........*

where k is the force constant or the constant of proportionality

k=f/e

[tex]f_{eff} =f_{1} +f_{2}[/tex]............................1

also for effective force constant

divide all through by extension

1) Total force is

Ft=F1+F2

Ft=k1e1+k2e2

F = k(e1+e2) 2)

Since force on the 2 springs is the same, so

k1e1=k2e2

e1=F/k1 and e2=F/k2,

and e1+e2=F/keq

Substituting e1 and e2, you get

1/keq=1/k1+1/k2

Hint: For a given force, the total distance stretched by the equivalent single spring is the sum of the distances stretched by the springs in combination.

Final answer:

To find the Earth's average density, we divide its mass (5.94×10²⁴ kg) by its volume converted to cubic meters (1.08×10²⁴ m³), resulting in a density of approximately 5.5 kg/m³.

Explanation:

An object's average density is defined as the ratio of its mass to its volume (rho = M/V). To calculate the Earth's average density, we use the given mass of the Earth (5.94×10²⁴ kg) and the given volume of the Earth (1.08×10¹² km³).

It's important to convert the volume from cubic kilometers to cubic meters to ensure consistency in units since density is typically expressed in kilograms per cubic meter (kg/m³). There are 1,000,000,000,000 (1×10¹²) cubic meters in one cubic kilometer, so the volume in cubic meters is 1.08×10¹² km³ × 1×1012 m³/km³ = 1.08×1024 m³.

Now, dividing the mass by the volume in consistent units gives:

Density = Mass / Volume = 5.94×10²⁴ kg / 1.08×10²⁴ m³ = 5.5 kg/m³

Therefore, The average density of Earth is roughly 5.5 kg/m³.

Answer: Acoustic or sound wave

Explanation:

Acoustic wave is a type of wave energy that travels through a medium by adiabatic compression and decompression, they have acoustic velocity which is determined by the type and nature of medium they travel through. They are mechanical and longitudinal waves with characteristic features such as amplitude, period, frequency and wavelength.

Answer:

Tension in the string will be 19.293 N

Explanation:

We have given length of the string r = 42.1 cm = 0.421 m

Mass of the stone m = 1000 gram

We know that 1000 gram = 1 kg

Velocity in the circular path v = 2.85 m/sec

We have to find the tension in the string

Tension in the string will be equal to centripetal force

So tension [tex]T=\frac{mv^2}{r}[/tex], here m is mass, v is velocity and r is length of the string

So tension in the string [tex]T=\frac{1\times 2.85^2}{0.421}=19.293N[/tex]

So tension in the string will be equal to 19.293 N