ED decides to include more fruit in his diet he goes to the grocery store over the weekend and buys six apples six oranges six avocados the total cost is 19.50 write 3 Equations

Answers

Answer 1

Answer:

x = (19.5 - 6y - 6z) /6

y = (19.5 - 6x - 6z) /6

z = (19.5 - 6x - 6y) /6

Step-by-step explanation:

Let the Apples be X

           Oranges be Y

           Avocados be Z

Total cost of the Fruits = 19.5

So the equation would be as follows:

6x + 6y + 6z = 19.5

for Apples, equation would be:  

6x= 19.5 - 6y - 6z

x = (19.5 - 6y - 6z) /6

For Oranges, the equation would be:

6y= 19.5 - 6x - 6z

y = (19.5 - 6x - 6z) /6

For Avocados, the equation would be:

6z= 19.5 - 6x - 6y

z = (19.5 - 6x - 6y) /6

Answer 2

Answer:

simple answer

Step-by-step explanation:

Let x be the cost of one apple, y the cost of one orange, and z the cost of one avocado.

The first weekend, Ed buys 6 of each fruit and pays $19.50: 6x+6y+6z=19.5

The second weekend, Ed buys 12 apples, 2 oranges, and 1 avocado and pays $9.50: 12x+2y+z=9.5

The third weekend, Ed buys 2 apples, 4 oranges, and 5 avocados and pays $14: 2x+4y+5z=14.


Related Questions

Which is a solution to (x - 3)(x + 9) = -27?
х=-9 x = -3
х = 0
х = 6

Answers

Answer:

x=0

Step-by-step explanation:

x^2+6x-27=-27

x^2+6x=0

x(x+6)

x=0, x=-6

The solution to (x - 3)(x + 9) = -27 is x=6, the correct option is D.

What is a quadratic equation?

A quadratic equation is the second-order degree algebraic expression in a variable. the standard form of this expression is  ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.

We are given that;

(x - 3)(x + 9) = -27

Now,

If we plug in x = 6 into the equation,

we get: (6 - 3)(6 + 9) = -27.

Simplifying, we get: (3)(15) = -27.

Multiplying, we get: 45 = -27. This is true, so x = 6 is a solution.

The other values of x do not satisfy the equation.

For example, if we plug in x = -9, we get: (-9 - 3)(-9 + 9) = -27. Simplifying, we get: (-12)(0) = -27.

Multiplying, we get: 0 = -27. This is false, so x = -9 is not a solution

Therefore, by quadratic equations the answer will be x = 6.

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Dose anyone know number 7.

Answers

Answer: B

Step-by-step explanation: The Answer is B. 30 Sides.

The number of sides of the regular polygon each interior angle measuring 168° is 30. Thus, the correct option is B.

What is a polygon?

A polygon is a planar figure characterised by a limited number of straight-line segments joined to create a closed polygonal chain in geometry. A polygon is defined as a bounded planar region, a bounding circuit, or both.

The measure of interior angles of a regular polygon is given by the formula,

[tex]\text{Measure of an interior angle} = \dfrac{(n-2) \times 180^o}{n}[/tex]

where n is the number of sides in the polygon.

Since it is given that measure of an interior angle of the polygon is 168°. Therefore, the number of sides will be,

[tex]168 = \dfrac{(n-2) \times 180^o}{n}[/tex]

168n = 180n - 360

180n - 168n = 360

12n  = 360

n = 30

Hence, The number of sides of the regular polygon each interior angle measuring 168° is 30.

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I am confused by this question. Can someone help​

Answers

square root both sides, divide by v both sides, divide by 2 both sides, divide pCd both sides

tanisha office is on the 9 floor of an office building . She parks her car in the underground parking garage 4 floors below ground level how many floors are between tanisha office and her car?

Answers

Answer: 13

Step-by-step explanation: If there are 9 floors from where Tanisha's office is to the ground, but then also 4 more floors to her car, that would simply be 9+4. There are 13 floors between Tanisha's office and her car.

On Saturn year equals 29.5 earth years. If you were three years old on Saturn how old would you be on earth

Answers

Answer 88.5 I think I don’t know if it’s right

Step-by-step explanation:

Multiply it by 3

Final answer:

If you were three years old on Saturn, which has a year length equivalent to 29.5 Earth years, you'd be 88.5 years old on Earth.

Explanation:

The subject of your question is focused on the comparison of time passage on different planets--in this case, how years on Saturn compare to years on Earth. In terms of the Solar system, a year on any planet is determined by how long it takes to orbit the Sun. Given that one Saturn year equals 29.5 Earth years, if you were three years old on Saturn, you'd be 88.5 years old on Earth (Because 29.5 * 3 = 88.5).

This is calculated simply by multiplying the number of Saturn years by the equivalent in Earth years. This concept can be applied to other planets as well, as each has its own specific length of year based on its orbit around the Sun.

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A pet toy manufacturer is designing a plastic ball for dogs that will float in water. In order for the ball to float it must have a density that is less than 1 gram per milliliter (the density of water). The approved design has a mass of 115 grams and a density of 0.600 g/mL. Use the density formula d = m v to determine the radius of the ball to the nearest hundredth of a centimeter. Volume of a sphere = 4 3 π r 3

Answers

Answer:

3.576 cm

Step-by-step explanation:

radius of ball, r=?

Given:

Density, p = 0.600g/mL

mass, m= 115g

finding volume, v of ball by using formula p=m/v

v= m/p

= 115/0.600

=191.666 mL^3

=191.666 cm^3

Now using formula v= (4/3)πr^3 to find radius, r of the ball

r^3= 3v/4π

   = 3(191.666)/4π

   =45.75 cm

r   =3.5767 cm !

Solve for x

12=x^2+6x

Answers

Answer:

[tex]\large\boxed{x=-3\pm\sqrt{21}}[/tex]

Step-by-step explanation:

[tex]x^2+6x=12\\\\x^2+2(x)(3)=12\qquad\text{add}\ 3^2\ \text{to both sides}\\\\x^2+2(x)(3)+3^2=12+3^2\qquad\text{use}\ (a+b)^2=a^2+2ab+b^2\\\\(x+3)^2=12+9\\\\(x+3)^2=21\iff x+3\pm\sqrt{21}\qquad\text{subtract 3 from both sides}\\\\x=-3\pm\sqrt{21}[/tex]

G=4ca-3ba for a Asap

Answers

Answer:

a = [tex]\frac{G}{4c-3b}[/tex]

Step-by-step explanation:

Given

G = 4ca - 3ba ← factor out a from each term on the right side

G = a(4c - 3b) ← divide both sides by (4c - 3b)

a = [tex]\frac{G}{4c-3b}[/tex]

given [tex]f(x)= 4x^2 + 6x and g(x) = 2x^2 +13x+15 \\[/tex], find (f/x) (x)

Answers

Answer:  [tex](f/g)(x)=\frac{2x}{x+5}[/tex]

Step-by-step explanation:

Given the function f(x):

[tex]f(x)=4x^2+6x[/tex]

And the function g(x):

[tex]g(x)=2x^2+13x+15[/tex]

To find [tex](f/g)(x)[/tex] you need to divide the function f(x) by the function g(x).

Therefore, knowing this, you get:

[tex](f/g)(x)=\frac{4x^2+6x}{2x^2+13x+15}[/tex]

You can simplify the numerator by factoring out 2x:

[tex](f/g)(x)=\frac{2x(2x+3)}{2x^2+13x+15}[/tex]

 You have to simplify the denominator:

 Rewrite the term 13x as a sum of two terms whose product be 30:  

[tex](f/g)(x)=\frac{2x(2x+3)}{2x^2+(10+ 3)x+15}[/tex]

Apply Distributive property:

[tex](f/g)(x)=\frac{2x(2x+3)}{2x^2+10x+ 3x+15}[/tex]

Make two groups of two terms:

[tex](f/g)(x)=\frac{2x(2x+3)}{(2x^2+10x)+ (3x+15)}[/tex]

Factor out 2x from the first group and 3 from the second group:

[tex](f/g)(x)=\frac{2x(2x+3)}{(2x(x+5))+ 3(x+5)}[/tex]

Factor out (x+5):

[tex](f/g)(x)=\frac{2x(2x+3)}{(2x+3)(x+5)}[/tex]

Simplifying, you get:

[tex](f/g)(x)=\frac{2x}{x+5}[/tex]

ANSWER

[tex]( \frac{f}{g} )(x) = \frac{2x }{x + 5}[/tex]

where

[tex]x \ne - \frac{3}{2} \: or \: x = - 5[/tex]

EXPLANATION

The given functions are:

[tex]f(x) = 4 {x}^{2} + 6x[/tex]

and

[tex]g(x) =2 {x}^{2} + 13x + 15[/tex]

We want to find ,

[tex]( \frac{f}{g} )(x) = \frac{f(x)}{g(x)} [/tex]

[tex]( \frac{f}{g} )(x) = \frac{4 {x}^{2} + 6x }{2 {x}^{2} + 13x + 15} [/tex]

[tex]( \frac{f}{g} )(x) = \frac{2x(2x + 3) }{2{x}^{2} + 10x +3x + 15} [/tex]

[tex]( \frac{f}{g} )(x) = \frac{2x(2x + 3) }{2{x}(x + 5) +3(x + 5)} [/tex]

[tex]( \frac{f}{g} )(x) = \frac{2x(2x + 3) }{(2x + 3)(x + 5)} [/tex]

We cancel out the common factors to get:

[tex]( \frac{f}{g} )(x) = \frac{2x }{x + 5} [/tex]

where

[tex]x \ne - \frac{3}{2} \: or \: x = - 5[/tex]

in a city, 35% of the bus riders with a monthly pass are students. in a random sample of 50 bus riders with monthly passes, 23 are students.

what is ρ and ρ with ^

Answers

Answer:

ρ = 35% or 0.35

ρ with ^ = [tex]\frac{23}{50}=0.46[/tex] or equivalently 46%

Step-by-step explanation:

ρ represents the population proportion of the bus riders, with a monthly pass, who are students.

The population proportion is simply the percentage of the entire population with a particular characteristic. We have been informed that in a city, 35% of the bus riders with a monthly pass are students. This means that 35% of the whole population of bus riders with a monthly pass are students. Therefore, our ρ is simply 35% or 0.35.

ρ with ^ represents the sample proportion of the bus riders, with a monthly pass, who are students. This is a statistic or an estimator as it is normally used to estimate the value of ρ, the population proportion. It is calculated using the formula;

ρ with ^ = [tex]\frac{x}{n}[/tex]

where n represents the size of the sample and x the number of individuals in the sample with a certain desired characteristic. We have been informed that;

in a random sample of 50 bus riders with monthly passes, 23 are students.

Using the above formula and the values given we have;

ρ with ^ = [tex]\frac{23}{50}=0.46[/tex] or equivalently 46%

Answer: The correct answer is: ρ=0.35, ρˆ=0.46

Step-by-step explanation:

I hope this helps! :)

(-3,-2) and (x,6); m=2

Answers

Answer:

x=1

Step-by-step explanation:

We can find the slope given two points by

m = (y2-y1)/(x2-x1)

2 = (6--2)/(x--3)

2 = (6+2)/(x+3)

2 = 8/(x+3)

Multiply each side by x+3

2(x+3) = 8/(x+3) * (x+3)

2(x+3) = 8

Divide each side by 2

2/2 (x+3) = 8/2

x+3 = 4

Subtract 3 from each side

x+3-3=4-3

x =1

Solve for x: 3(x+1)=-2(x-1)-4

Answers

Answer:

X= -1

You're welcome! Love ya!! <3

Answer:

The correct answer is x = -1

Step-by-step explanation:

It is given an expression with variable x

3(x + 1) = -2(x - 1) - 4

To solve the given expression

3(x + 1) = -2(x - 1) - 4

3x + 3 = -2x + 2 - 4   ( open the bracket)

3x + 2x = 2 - 4 -3

5x = -5

x = -5/5 = -1

Therefore the value of x = -1

The correct answer is x = -1

(2x^3)^2 x 6x^2

(2m^0 x 5m)^2 x 5m^2

Answers

Answer:

[tex]\large\boxed{(2x^3)^2\times6x^2=24x^8}[/tex]

Step-by-step explanation:

[tex](2x^3)^2\times6x^2\qquad\text{use}\ (ab)^n=a^nb^n\ \text{and}\ (a^n)^m=a^{nm}\\\\=2^2(x^3)^2\times6x^2=4x^6\times6x^2=(4\times6)(x^6x^2)\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=24x^{6+2}=24x^8[/tex]

PLEASE HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

The line plot shows the weights of pumpkins available at a farm stand. The pumpkins cost $0.30 per pound. A baker purchases all of the pumpkins to make pies. If she uses a $100 bill to pay for the pumpkins, how much change will she receive?

Answers

If she uses a $100 bill to pay for the pumpkins, then the amount of change that she receives will be $ 32.5.

What is subtraction?

It simply implies subtracting something from an entity, group, location, etc. Subtracting from a collection or a list of ways is known as subtraction.

The line plot shows the weights of pumpkins available at a farm stand. The pumpkins cost $0.30 per pound. A baker purchases all of the pumpkins to make pies.

Then the weight of all the pumpkins will be

→ 6 x 3 + 8 x 5 + 9 + 10 x 7 + 12 x 4 + 13 x 2 + 14

→ 225 pounds

Then the amount of money of 225 pounds will be

→ 225 x 0.3

→ $ 67.5

If she uses a $100 bill to pay for the pumpkins, then the amount of change that she receives will be

→ $ 100 - $67.5

→ $ 32.5

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Select the two values of x that are roots or this equation x^2-5x+2=0

Answers

Answer:

(5/2, +-(square root 17)/ 2)

Step-by-step explanation:

1. find a,b, and c of the quadratic

2. use the quadratic formula to solve

The two values of roots of the equation is 4.56 , 0.44 .

What is an Equation ?

An equation is a statement where two algebraic expressions are equated by an equal sign.

The equation given is

x² - 5x +2 = 0

the roots of the equation is given by

[tex]\rm \dfrac{ -b \pm \sqrt { b^2 - 4ac}}{2a}[/tex]

[tex]\rm \dfrac{ 5 \pm \sqrt { 25 - 4 * 1 * 2}}{2 *1}[/tex]

x = [tex]\rm \dfrac{ 5 \pm \sqrt { 17}}{2}[/tex]

Therefore the two values of roots of the equation is 4.56 , 0.44 .

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Abe Cassidy wants to deposit the following into his savings account: 32 one-dollar bills, 4 five-dollar bills, 32 quarters, 25 dimes, 82 pennies, a check for $43.56, and a check for $122.90. He wants to receive a $50.00 bill in cash. How much will he deposit?

136.22

10.44

$229.78

$179.78

Answers

Answer:

179.78

Step-by-step explanation:

Let's count how much Abe has exactly:

32 one-dollar bills: $32

4 five-dollar bills: $20

32 quarters: $8

25 dimes : $2.50

82 pennies :  $0.82

First check: $43.56

Second check: $122.90

Total = $229.78

And he wants a $50 bill... so he'll deposit $179.78 ($229.78 - $50).

Final answer:

Abe Cassidy will deposit $179.78 into his savings account.

Explanation:

Let's calculate how much Abe Cassidy will deposit into his savings account, considering he wants to receive a $50.00 bill in cash. To do this, we need to add up all the various types of money he has and then subtract the $50 he wishes to keep in cash.

32 one-dollar bills = $324 five-dollar bills = $2032 quarters = $8 (since 4 quarters = $1)25 dimes = $2.50 (since 10 dimes = $1)82 pennies = $0.82 (since 100 pennies = $1)1 check for $43.561 check for $122.90

Adding all these amounts gives us a total of $229.78 before removing the $50 he wants in cash.

To find the amount he will deposit, we subtract the $50 from the total amount:

$229.78 - $50 = $179.78

Hence, Abe Cassidy will deposit $179.78 into his savings account.

i am a number. i am half of the square root of 100. i am __________

Answers

Answer:

i believe it is five

Step-by-step explanation:

Answer:

The answer is 5

Step-by-step explanation:

the square root of 100=10 10/2=5

Can I get brainliest

In DEF, DE = 15, and m angle F=32 Find EF to the nearest tenth.

Answers

the answer would be 24.0.

The volume of a cylinder is 441pi. If the cylinder has a height of 9, what is the radius?

Answers

Answer: 7

Step-by-step explanation:

volume of a cylinder = πr²h

441π = π *r²* 9

divide both sides by 9π

49 = r²

r =√49 = 7

Answer:

49

Step-by-step explanation:

Please help me asap! Could you please explain how you got the answer

Complete the two-way frequency table below, which shows the relationship between students who enroll in advanced Algebra and Physics in a particular high school. From a sample of 30 students, it is found that 19 are taking Algebra, 12 are taking Physics, and 4 are enrolled in both. How many students are enrolled in either Algebra or Physics?


Algebra Not in Algebra Total

Physics 4 --------- ----------------------------12

Not in Physics

Total 19---------------------------------------30


A.) 27

B.) 23

C.) 3

D.) 4

Answers

Answer:

B) 23

Step-by-step explanation:

Table:            Algebra | No algebra | Total

Physics        |      4           Step 1: 8      12

No physics  |Step 2: 15

Total            |      19                              30

We look for the number of people who are in algebra and no physics or physics and no algebra.

1. 12 - 4 = 8

2. 19 - 4 = 15

3. We find the total of those numbers: 15 + 8 = 23

Answer: 27

Step-by-step explanation:

What is 3log2x-(log2(x+4)) written as a single logarithm

Answers

Answer:

[tex]\large\boxed{3\log_2x-\log_2(x+4)=\log_2\dfrac{x^3}{x+4}}[/tex]

Step-by-step explanation:

[tex]3\log_2x-\log_2(x+4)\\\\\text{use}\ \log_ab^n=n\log_ab\ \text{and}\ \log_ab-\log_ac=\log_a\dfrac{b}{c}\\\\=\log_2x^3-\log_2(x+4)=\log_2\dfrac{x^3}{x+4}\\\\\text{Domain:}\\\\x>0\ \wedge\ x+4>0\to x>0\ \wedge\ x>-4\\\\\boxed{x>0}[/tex]

Answer:

c

Step-by-step explanation:

Week 8 trigonometric worksheet!!! PLEASE HELP ME IS A FINAL GRADE FOR SCHOOL!

Answers

Answer:

Part 1) The six trigonometric functions in the procedure

Part 2) The six trigonometric functions in the procedure

Part 3) The six trigonometric functions in the procedure

Part 4) The value of x is [tex]x=7\sqrt{2}\ units[/tex] and the value of y is [tex]y=7\ units[/tex]

Part 5) The value of x is [tex]x=5\ units[/tex] and the value of y is [tex]y=5\sqrt{3}\ units[/tex]

Part 6) The value of x is [tex]x=2\sqrt{3}\ units[/tex] and the value of y is [tex]y=\sqrt{3}\ units[/tex]

Part 7)  [tex]cos(27\°)=0.8910[/tex]

Part 8)  [tex]tan(5\°)=0.0875[/tex]

Part 9)  [tex]sin(48\°)=0.7431[/tex]

Part 10) [tex]cot(81\°)=0.1584[/tex]

Part 11) [tex]csc(23\°)=2.5593[/tex]

Part 12) [tex]sec(66\°)=2.4586[/tex]

Part 13) [tex]cot(13\°)=4.3315[/tex]

Part 14) [tex]sin(32\°)=0.5299[/tex]

Step-by-step explanation:

Note The complete answers in the attached file

Part 1) In the right triangle of the figure find the hypotenuse

Applying Pythagoras theorem

[tex]c^{2} =8^{2}+15^{2}\\c^{2}=289\\c=17\ units[/tex]

1) Find the [tex]sin(\theta)[/tex]

[tex]sin(\theta)=\frac{8}{17}[/tex] ----> opposite side angle [tex]\theta[/tex] divided by the hypotenuse

2) Find the [tex]cos(\theta)[/tex]

[tex]cos(\theta)=\frac{15}{17}[/tex] ----> adjacent side angle [tex]\theta[/tex] divided by the hypotenuse

3) Find the [tex]tan(\theta)[/tex]

[tex]tan(\theta)=\frac{8}{15}[/tex] ----> opposite side angle [tex]\theta[/tex] divided by the adjacent side angle [tex]\theta[/tex]

4) Find the [tex]cot(\theta)[/tex]

[tex]cot(\theta)=\frac{15}{8}[/tex] ----> adjacent side angle [tex]\theta[/tex] divided by the opposite side angle [tex]\theta[/tex]

5) Find the [tex]sec(\theta)[/tex]

[tex]sec(\theta)=\frac{1}{cos(\theta)}[/tex]

[tex]sec(\theta)=\frac{17}{15}[/tex]  ----> hypotenuse divided by the adjacent side angle [tex]\theta[/tex]

6) Find the [tex]csc(\theta)[/tex]

[tex]csc(\theta)=\frac{1}{sin(\theta)}[/tex]

[tex]csc(\theta)=\frac{17}{8}[/tex]  ----> hypotenuse divided by the opposite side angle [tex]\theta[/tex]

Part 2) In the right triangle of the figure find the adjacent side angle [tex]\theta[/tex]

Applying Pythagoras theorem

[tex]5^{2} =2^{2}+a^{2}\\ a^{2}=5^{2}-2^{2}\\a^{2}=21\\a=\sqrt{21}\ units[/tex]  

1) Find the [tex]sin(\theta)[/tex]

[tex]sin(\theta)=\frac{2}{5}[/tex] ----> opposite side angle [tex]\theta[/tex] divided by the hypotenuse

2) Find the [tex]cos(\theta)[/tex]

[tex]cos(\theta)=\frac{\sqrt{21}}{5}[/tex] ----> adjacent side angle [tex]\theta[/tex] divided by the hypotenuse

3) Find the [tex]tan(\theta)[/tex]

[tex]tan(\theta)=\frac{2}{\sqrt{21}}[/tex] ----> opposite side angle [tex]\theta[/tex] divided by the adjacent side angle [tex]\theta[/tex]

4) Find the [tex]cot(\theta)[/tex]

[tex]cot(\theta)=\frac{\sqrt{21}}{2}[/tex] ----> adjacent side angle [tex]\theta[/tex] divided by the opposite side angle [tex]\theta[/tex]

5) Find the [tex]sec(\theta)[/tex]

[tex]sec(\theta)=\frac{1}{cos(\theta)}[/tex]

[tex]sec(\theta)=\frac{5}{\sqrt{21}}[/tex]  ----> hypotenuse divided by the adjacent side angle [tex]\theta[/tex]

6) Find the [tex]csc(\theta)[/tex]

[tex]csc(\theta)=\frac{1}{sin(\theta)}[/tex]

[tex]csc(\theta)=\frac{5}{2}[/tex]  ----> hypotenuse divided by the opposite side angle [tex]\theta[/tex]

Part 3) In the right triangle of the figure find the opposite side angle [tex]\theta[/tex]

Applying Pythagoras theorem

[tex]3^{2} =1^{2}+b^{2}\\ b^{2}=3^{2}-1^{2}\\b^{2}=8\\b=\sqrt{8}\ units[/tex]  

1) Find the [tex]sin(\theta)[/tex]

[tex]sin(\theta)=\frac{\sqrt{8}}{3}[/tex] ----> opposite side angle [tex]\theta[/tex] divided by the hypotenuse

2) Find the [tex]cos(\theta)[/tex]

[tex]cos(\theta)=\frac{\sqrt{1}}{3}[/tex] ----> adjacent side angle [tex]\theta[/tex] divided by the hypotenuse

3) Find the [tex]tan(\theta)[/tex]

[tex]tan(\theta)=\frac{\sqrt{8}}{1}[/tex] ----> opposite side angle [tex]\theta[/tex] divided by the adjacent side angle [tex]\theta[/tex]

4) Find the [tex]cot(\theta)[/tex]

[tex]cot(\theta)=\frac{1}{\sqrt{8}}[/tex] ----> adjacent side angle [tex]\theta[/tex] divided by the opposite side angle [tex]\theta[/tex]

5) Find the [tex]sec(\theta)[/tex]

[tex]sec(\theta)=\frac{1}{cos(\theta)}[/tex]

[tex]sec(\theta)=\frac{3}{1}[/tex]  ----> hypotenuse divided by the adjacent side angle [tex]\theta[/tex]

6) Find the [tex]csc(\theta)[/tex]

[tex]csc(\theta)=\frac{1}{sin(\theta)}[/tex]

[tex]csc(\theta)=\frac{3}{\sqrt{8}}[/tex]  ----> hypotenuse divided by the opposite side angle [tex]\theta[/tex]

Part 4) In the right triangle of the figure

a) Find the value of x

 we know that

[tex]sin(45\°)=\frac{7}{x}[/tex]

[tex]x=\frac{7}{sin(45\°)}[/tex]

Remember that

[tex]sin(45\°)=\frac{\sqrt{2}}{2}[/tex]

substitute

[tex]x=\frac{7}{\frac{\sqrt{2}}{2}}[/tex]

[tex]x=\frac{14}{\sqrt{2}}[/tex]

[tex]x=7\sqrt{2}\ units[/tex]

b) Find the value of y

The value of [tex]y=7\ units[/tex] ----> by triangle 45°-90°-45° measures

Note The complete answers in the attached file

The answer to this problem please

Answers

Answer:

834451800

Step-by-step explanation:

C(n,r)=?

 

C(n,r)=C(35,12)

=35!(12!(35−12)!)

=35!12!×23!

=8.344518E+8

= 834451800

Nadia plans to paint her jewelry box. The box is shaped like a rectangular prism with the dimensions
shown. which is closest to the total surface area of the jewelry box?

Answers

Answer:

[tex]132\ in^{2}[/tex] is closest to the total surface area of the box

Step-by-step explanation:

we know that

The surface area of the box is equal to

[tex]SA=2B+PH[/tex]

where

B is the area of the base

P is the perimeter of the base

H is the height of the box

we have

[tex]L=7\frac{3}{4}\ in=\frac{7*4+3}{4}=\frac{31}{4}\ in[/tex]

[tex]W=3\frac{1}{4}\ in=\frac{3*4+1}{4}=\frac{13}{4}\ in[/tex]

[tex]H=3\frac{7}{8}\ in=\frac{3*8+7}{8}=\frac{31}{8}\ in[/tex]

Find the area of the base B

[tex]B=LW[/tex]

[tex]B=(\frac{31}{4})(\frac{13}{4})=\frac{403}{16}\ in^{2}[/tex]

Find the perimeter of the base P

[tex]P=2(L+W)[/tex]

[tex]P=2(\frac{31}{4}+\frac{13}{4}))[/tex]

[tex]P=2(\frac{44}{4})=22\ in[/tex]

Find the surface area

[tex]SA=2(\frac{403}{16})+22(\frac{31}{8})[/tex]

[tex]SA=(\frac{403}{8})+(\frac{682}{8})[/tex]

[tex]SA=\frac{1,085}{8}=135.625\ in^{2}[/tex]

Johnny and his family arrived in Williamsburg Virginia at 1:15 p.m. they drove for 45 minutes after they stopped for lunch their lunch break was 20 minutes they drove for 2 hours and 10 minutes before stopping for lunch what time did they leave home?​

Answers

Answer:

1:15 P.M. - (:45 + :20 + 2:10) =

1:15 P.M. - 2:75 = 13:15 - 3:15 =

10:00 A.M.

Johnny and his family left home at 10:00 A.M.

6(2x + 3) − 4(5x + 2)

Answers

Answer:

-8x+10

Step-by-step explanation:

=(6)(2x)+(6)(3)+(−4)(5x)+(−4)(2)

=12x+18+−20x+−8

Combine Like Terms:

=12x+18+−20x+−8

=(12x+−20x)+(18+−8)

=−8x+10

Answer:

-8x+ + 10

Step-by-step explanation:

Stop deleting my answer scooby Doo, i really need points now

John has a ribbon that was 1 1/2 meters long. He used 2 pieces that were each 1/3 of that length. How much ribbon did John use?

Answers

Answer:

1 meter.

Step-by-step explanation:

1 1/2 * 1/3

= 3/2 * 1/3

= 3/6

= 1/2.

So John used 2*1/2 = 1 meter of the ribbon.

Help please with workings of possible

Answers

Answer:

V = x³ + 10x² cm³

Step-by-step explanation:

The volume (V) of the triangular prism is calculated using the formula

V = area of triangular face × length

Area of triangular face = [tex]\frac{1}{2}[/tex] bh ( b is base and h is height )

here b = 2x and h = x, thus

A = [tex]\frac{1}{2}[/tex] × 2x × x = [tex]\frac{1}{2}[/tex] × 2x² = x²

length = x + 10, hence

V = x²(x + 10) = x³ + 10x²

Solveee 3x^2 - 9 = 0

Answers

Answer:

x = ± [tex]\sqrt{3}[/tex]

Step-by-step explanation:

Given

3x² - 9 = 0 ( add 9 to both sides )

3x² = 9 ( divide both sides by 3 )

x² = 3 ( take the square root of both sides )

x = ± [tex]\sqrt{3}[/tex]

A bowling team participated in a two-day tournament and records the scores for each team member on both days.The scores for both days are represented by the box plots below

Answers

I think it's B hope you got it right

The correct answer is B. The scores on Friday have a greater median and a greater interquartile range than the scores on Saturday.

The box plots represent the bowling scores of a team on Friday and Saturday. Let’s analyze the information from the plots:

Friday Box Plot:

The median (Q2) is higher than the median for Saturday.

The interquartile range (IQR) is larger than the IQR for Saturday.

Saturday Box Plot:

The median (Q2) is lower than the median for Friday.

The interquartile range (IQR) is smaller than the IQR for Friday.

Based on this analysis, we can draw the following conclusion:

B. The scores on Friday have a greater median and a greater interquartile range than the scores on Saturday.

Therefore, the correct answer is B.

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