Echo is creating a garden that is 36 feet wide and can fit one row of shrubs. Each shrub is 4.5 feet wide. Each shrub costs $15.32. She plants the maximum number of shrubs for the garden.


What is the total cost for Echo’s shrubs?

Answer:

[tex]3\sqrt{2} \sqrt{x}[/tex]

Answer: 1,360

Step-by-step explanation:

20 * 20 = 400

20 * 12 = 240

240 * 4 = 960

960 + 400 = 1,360

Answer:

1.26 liters.

Step-by-step explanation:

Given that, a hummingbird feeder holds [tex]\frac{2}{3}[/tex] of a cup of hummingbird solution.

Again, a bottle of solution will fill the feeder 8 times.

Therefore, a bottle of solution will measure [tex](\frac{2}{3}\times 8) = \frac{16}{3} = 5.33[/tex] cups of hummingbird solution.

Now, one cup is equivalent to 0.236588 liters.

So, 5.33 cups is equal to (0.236588 × 5.33) = 1.26 liters. (Answer)

Answer:

Step-by-step explanation:

3x - 6 + 2x + 108 + 88 = 360     Gather like terms

5x + 108 + 88 - 6 = 360

5x = 190                                      Divide by 5

x = 190/5

x = 38  

Answer:

Susan had $41.

Step-by-step explanation:

The amount of money they have is enough for $99 spending. The answer can be found by testing two numbers and seeing whether the amounts need to be increased or decreased to make the distance between them 17, with a sum of 99.

40 and 57: distance of 17, but not enough for $99. $41 and $58 equal 99, with a distance of 17 between them. Jenny, with $17 more, has 58. Susan has 41.

Only if they are each the same distance away from zero, but on opposite sides of the number line.

Hope this help! :)

Answer:If you add a negative and a positive you do the the integers step by changing the add operation to a subtraction.

Step-by-step explanation:-4+3

integers property     -4 - 3 = 1

negative plus a positive is a positive.

Answer:

Plane B is closer.

The distance for Plane A is 7.9 km.

The distance for Plane B is 7.4 km.

Step-by-step explanation:

To find the distance to the tower, altitude must be converted to kilometers. Each 1000 ft is 0.3048 km, so the heights of the planes are ...

-- Plane A: (20 thousand ft)*(0.3048 km/thousand ft) = 6.096 km

-- Plane B: (8 thousand ft)*(0.3048 km/thousand ft) = 2.4384 km

The Pythagorean theorem can be used to find the distance from each plane to the tower:

-- distance = √((ground distance)² + (height)²)

-- Plane A distance = √(5² +6.096²) ≈ √62.16 ≈ 7.9 . . . km

-- Plane B distance = √(7² +2.4384²) ≈ √54.95 ≈ 7.4 . . . km

The distance for Plane B is shorter, so Plane B is closer to the tower.

Answer:

[tex]\lim _{x\to \infty \:}\left(\frac{\sqrt{9x^2+x+1}-\sqrt{4x^2+2x+1}}{x+1}\right)=1[/tex]

Step-by-step explanation:

Considering the expression

[tex]\lim _{x\to \infty \:}\frac{\sqrt{9x^2+x+1}-\sqrt{4x^2+2x+1}}{x+1}[/tex]

Steps to solve

[tex]\lim _{x\to \infty \:}\frac{\sqrt{9x^2+x+1}-\sqrt{4x^2+2x+1}}{x+1}[/tex]

[tex]\mathrm{Divide\:by\:highest\:denominator\:power:}\:\frac{\sqrt{9+\frac{1}{x}+\frac{1}{x^2}}-\sqrt{4+\frac{2}{x}+\frac{1}{x^2}}}{1+\frac{1}{x}}[/tex]

[tex]\lim _{x\to \infty \:}\left(\frac{\sqrt{9+\frac{1}{x}+\frac{1}{x^2}}-\sqrt{4+\frac{2}{x}+\frac{1}{x^2}}}{1+\frac{1}{x}}\right)[/tex]

[tex]\lim _{x\to a}\left[\frac{f\left(x\right)}{g\left(x\right)}\right]=\frac{\lim _{x\to a}f\left(x\right)}{\lim _{x\to a}g\left(x\right)},\:\quad \lim _{x\to a}g\left(x\right)\ne 0[/tex]

[tex]\mathrm{With\:the\:exception\:of\:indeterminate\:form}[/tex]

[tex]\frac{\lim _{x\to \infty \:}\left(\sqrt{9+\frac{1}{x}+\frac{1}{x^2}}-\sqrt{4+\frac{2}{x}+\frac{1}{x^2}}\right)}{\lim _{x\to \infty \:}\left(1+\frac{1}{x}\right)}.....[1][/tex]

As

[tex]\lim _{x\to \infty \:}\left(\sqrt{9+\frac{1}{x}+\frac{1}{x^2}}-\sqrt{4+\frac{2}{x}+\frac{1}{x^2}}\right)=1[/tex]

Solving

[tex]\lim _{x\to \infty \:}\left(\sqrt{9+\frac{1}{x}+\frac{1}{x^2}}-\sqrt{4+\frac{2}{x}+\frac{1}{x^2}}\right)....[A][/tex]

[tex]\lim _{x\to a}\left[f\left(x\right)\pm g\left(x\right)\right]=\lim _{x\to a}f\left(x\right)\pm \lim _{x\to a}g\left(x\right)[/tex]

[tex]\mathrm{With\:the\:exception\:of\:indeterminate\:form}[/tex]

[tex]\lim _{x\to \infty \:}\left(\sqrt{9+\frac{1}{x}+\frac{1}{x^2}}\right)-\lim _{x\to \infty \:}\left(\sqrt{4+\frac{2}{x}+\frac{1}{x^2}}\right)[/tex]

Also

[tex]\lim _{x\to \infty \:}\left(\sqrt{9+\frac{1}{x}+\frac{1}{x^2}}\right)=3[/tex]

Solving

[tex]\lim _{x\to \infty \:}\left(\sqrt{9+\frac{1}{x}+\frac{1}{x^2}}\right)......[B][/tex]

[tex]\lim _{x\to a}\left[f\left(x\right)\right]^b=\left[\lim _{x\to a}f\left(x\right)\right]^b[/tex]

[tex]\mathrm{With\:the\:exception\:of\:indeterminate\:form}[/tex]

[tex]\sqrt{\lim _{x\to \infty \:}\left(9+\lim _{x\to \infty \:}\left(\frac{1}{x}+\lim _{x\to \infty \:}\left(\frac{1}{x^2}\right)\right)\right)}[/tex]

[tex]\lim _{x\to \infty \:}\left(9\right)=9[/tex]

[tex]\lim _{x\to \infty \:}\left(\frac{1}{x}\right)=0[/tex]

[tex]\lim _{x\to \infty \:}\left(\frac{1}{x^2}\right)=0[/tex]

So, Equation [B] becomes

⇒ [tex]\sqrt{9+0+0}[/tex]

⇒ [tex]3[/tex]

Similarly, we can find

[tex]\lim _{x\to \infty \:}\left(\sqrt{4+\frac{2}{x}+\frac{1}{x^2}}\right)=2[/tex]

So, Equation [A] becomes

⇒ [tex]3-2[/tex]

⇒ 1

Also

[tex]\lim _{x\to \infty \:}\left(1+\frac{1}{x}\right)=1[/tex]

Thus, equation becomes

[tex]\frac{\lim _{x\to \infty \:}\left(\sqrt{9+\frac{1}{x}+\frac{1}{x^2}}-\sqrt{4+\frac{2}{x}+\frac{1}{x^2}}\right)}{\lim _{x\to \infty \:}\left(1+\frac{1}{x}\right)}=\frac{1}{1}=1[/tex]

Therefore,

[tex]\lim _{x\to \infty \:}\left(\frac{\sqrt{9x^2+x+1}-\sqrt{4x^2+2x+1}}{x+1}\right)=1[/tex]

Keywords: limit

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I will have "x" represent the unknown number, or you could use a "?", doesn't matter.

[tex]8\leq \frac{x}{-4}[/tex]     [8 is less than or equal to (≤) the quotient (÷) of a number and -4, so the number is being divided by -4]

If you need to solve this, you need to isolate/get the variable "x" by itself in the inequality:

[tex]8\leq \frac{x}{-4}[/tex]   Multiply -4 on both sides to get rid of the fraction and get "x" by itself

[tex](-4)8\geq \frac{x}{-4} (-4)[/tex]    When you multiply/divide by a negative number, you flip the sign (< >)

-32 ≥ x          [-32 is greater than or equal to x, or x is less than or equal to -32]

It will take [tex]20\frac{5}{6}[/tex] minutes to fill a 50 gallon tub.

Step-by-step explanation:

Time taken to fill 3 gallons bucket = [tex]1\frac{1}{4}=\frac{5}{4}\ minutes[/tex]

We have to find time required to fill 50 gallons tub.

3 gallons = [tex]\frac{5}{4}\ minutes[/tex]

1 gallon = [tex]\frac{5}{4}*\frac{1}{3}\ minutes[/tex]

1 gallon = [tex]\frac{5}{12}\ minutes[/tex]

To find the time required for 50 gallons;

50 gallons = 50 * Time per gallon

50 gallons = [tex]50*\frac{5}{12}[/tex]

50 gallons = [tex]\frac{250}{12}[/tex] = [tex]\frac{125}{6}[/tex]

50 gallons = [tex]20\frac{5}{6}\ minutes[/tex]

It will take [tex]20\frac{5}{6}[/tex] minutes to fill a 50 gallon tub.

Keywords: fraction, division

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Final answer:

It takes approximately 20.83 minutes to fill a 50 gallon tub if it takes 1 1/4 minutes to fill a 3 gallon bucket, considering a constant rate of filling.

Explanation:

The question asks us to determine how long it will take to fill a 50 gallon tub if it takes 1 1/4 minutes to fill a 3 gallon bucket. To solve this, we can set up a proportion since the rates of gallons per minute will be the same for both the bucket and the tub.

First, let's convert the time from minutes to seconds to match the unit for seconds provided in the example. There are 60 seconds in a minute, so 1 1/4 minutes is equal to 75 seconds.

Now, we know it takes 75 seconds to fill 3 gallons. Let's calculate the number of seconds it takes to fill 1 gallon, and then we will use that rate to find out how many seconds it will take to fill 50 gallons.

We divide 75 seconds by 3 gallons, to get 25 seconds per gallon. Then we multiply this rate by 50 gallons to find the total time needed to fill the tub:

25 seconds/gallon × 50 gallons = 1250 seconds.

Finally, to convert seconds back to minutes, we divide 1250 seconds by 60:

1250 seconds ÷ 60 seconds/minute = 20 5/6 minutes or approximately 20.83 minutes.

So, it takes approximately 20.83 minutes to fill a 50 gallon tub at the given rate.

Answer:

2

Step-by-step explanation:

Answer:

Please, find the image with the diagram of the lines corresponding to this question:

The answers are:

Explanation:

First question:

You must use the fact that the angles DCE and BCD are adjacent angles, because they share the vertex (C) and have a common side (CD).

Thus, as a first fact, the measure of the angle BCE is equal to the sum of the measures of the angles BCD and DCE.

On the other hand, BE is a straight line, thus the measure of angle BCE is 180º.

Hence, you can write:

Second question:

Solve for x:

Substitute m ∠DCE with 120º:

Hence, for m ∠DCE = 120º, x = 60º.

Answer:

42)  122.72 square inches

43) 212.83 additional feet of fabric

Step-by-step explanation:

42)

Diameter = [tex]12\frac{1}{2}[/tex] = 12.5 inches

Radius = (1/2) * Diameter = (1/2) * 12.5 = 6.25 inches

The formula for calculating the area of a circle is π * Radius²

π * Radius²

Substitute radius and pi into formula

3.14159265359 * 6.25²

Solve exponent

3.14159265359 * 39.0625

Multiply

122.7184630309

Round to the nearest hundredth

122.72 square inches

43)  Clarissa needs 500 feet of fabric

She has these pieces

3 pieces of fabric that are each 18 yards long

1 piece of fabric that is [tex]16\frac{1}{2}[/tex] yards long

1 piece of fabric that is [tex]75\frac{2}{3}[/tex] feet long

Convert all yard measurements to feet and all fractions to decimals

(1 yard = 3 feet)

3 pieces of fabric that are each 54 feet long

1 piece of fabric that is 49.5 yards long

1 piece of fabric that is 75.67 feet long

Add all lengths

3(54) + 49.5 + 75.67

162 + 49.5 + 75.67 = 287.17

Subtract from 500 to find missing length

500 - 287.17 = 212.83

212.83 additional feet of fabric

Hope this helps :)

Answer:

55

Step-by-step explanation:

The two shortest sides added up need to be longer then the longest angle so 48 + 55 = 103>73

[tex]\( f(2) = \ln \left( \frac{14}{3} \right) \)[/tex]. You can calculate this value to get a numerical result.

To find the particular solution [tex]\( y = f(x) \)[/tex] to the given differential equation [tex]\( \frac{dy}{dx} = \frac{x^2 + 1}{e^y} \)[/tex] with the initial condition [tex]\( f(1) = 0 \)[/tex] and then evaluate [tex]\( f(2) \),[/tex] we can follow these steps:

1. Separate variables:

[tex]\[ e^y dy = (x^2 + 1) dx \][/tex]

2. Integrate both sides:

[tex]\[ \int e^y dy = \int (x^2 + 1) dx \][/tex]

[tex]\[ e^y = \frac{1}{3} x^3 + x + C \][/tex]

3. Apply the initial condition [tex]\( f(1) = 0 \):[/tex]

[tex]\[ e^0 = \frac{1}{3} (1)^3 + 1 + C \][/tex]

[tex]\[ 1 = \frac{1}{3} + 1 + C \][/tex]

[tex]\[ C = \frac{2}{3} \][/tex]

So, the particular solution is:

[tex]\[ e^y = \frac{1}{3} x^3 + x + \frac{2}{3} \][/tex]

4. Solve for  y :

[tex]\[ y = \ln \left( \frac{1}{3} x^3 + x + \frac{2}{3} \right) \][/tex]

Now, we need to find f(2), which means finding the value of y when  x = 2:

[tex]\[ y = \ln \left( \frac{1}{3} (2)^3 + 2 + \frac{2}{3} \right) \][/tex]

[tex]\[ y = \ln \left( \frac{8}{3} + 2 + \frac{2}{3} \right) \][/tex]

[tex]\[ y = \ln \left( \frac{14}{3} \right) \][/tex]

Answer:

The bigger pot is a 9.1-quart pot

Step-by-step explanation:

Initial pot size = 6.5-quart

New pot is 40% bigger than the initial pot size

Bigger pot size = 6.5-quart + (0.4 × 6.5-quart) = 6.5-quart + 2.6-quart = 9.1-quart

Answer:

A because it is increasing

Step-by-step explanation:

Answer:

I would say c

Step-by-step explanation:

you think if you go down a hill what happen is you speed up so you would need to be go down or heading in a negative direction.

Answer:

8:30 PM

Step-by-step explanation:

Let's say that x is minutes since 6:20 PM, and y is position in miles.

Since Jonathan drives at a constant rate, the position vs time graph is linear.  Two points on the line are (0, 75) and (20, 85).  The slope of the line is:

m = Δy / Δx

m = (85 − 75) / (20 − 0)

m = ½

So the equation of the line is:

y = ½ x + 75

We want to find x when y is 140.

140 = ½ x + 75

65 = ½ x

x = 130

So 130 minutes after 6:20 PM is when Jonathan's position will be 140 miles.  130 minutes is 2 hours and 10 minutes.  So the time will be 8:30 PM.

By calculating the speed at which Jonathan was driving and applying that rate to the total distance, it can be concluded that Jonathan would have driven a total of 140 miles by about 8:30 PM.

Jonathan drove 10 miles from 6:20 PM to 6:40 PM, giving a 20-minute duration. We can say the rate of speed he was driving at is 10 miles/20 minutes. We can simplify this rate down to 1 mile/2 minutes to make it easier to work with.
To calculate when he would've driven a total of 140 miles we follow these steps:

Subtract the 75 miles he had already driven from the total of 140 miles we want to find out about, which gives us 65 miles.  

Therefore, Jonathan would've driven a total of 140 miles by about 8:30 PM.

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Answer:45

Step-by-step explanation:

it is 45

Step-by-step explanation:

Answer:

63

Step-by-step explanation:

Answer:

65

Step-by-step explanation:

75% of 65 = 48

Answer:

[tex]b+g=26[/tex]

[tex]b=g-3[/tex]

Step-by-step explanation:

Let the number of boys be reprented by [tex]b[/tex]

Let the number of girls be represented by [tex]g\\[/tex]

↓ Total number of boys + girls must be 26

[tex]b+g=26[/tex]

↓ Number of boys is 3 less than the number of girls

[tex]b=g-3[/tex]

The system of equations that represents the number of boys and girls are [tex]x+y=26[/tex] and [tex]x = y-3[/tex] and this can be determined by forming the linear equation.

Given :

The following steps can be used in order to determine the system of equations that represents the number of boys and girls:

Step 1 - Let the total number of boys be 'x' and the total number of girls be 'y'.

Step 2 - So, the linear equation that represents the total number of students in Mrs. Augello's math class is:

[tex]x+y=26[/tex]    --- (1)

Step 3 - The linear equation that represents the situation "number of boys is three less than the number of girls" is:

[tex]x = y-3[/tex]   --- (2)

For more information, refer to the link given below:

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Answer:

About

step 1 highlight numbers

step 2 do ctrl+f

step 3 type in 9

ENJOY

1051541451431641621571721571511441234567881234567812345678123678326470547 2999999259923478990124999995689902993413269916749953349999914649932724997 2994567809912568990139956799809929936781467998299634699818991169966144990 2999994569970124995699801323459999012615302799995324993243699019923412993 2994567801993569980299356780239999456725634569974326992644399243992369936 2994567801992689901239967899029939945745315319931253399436998011992349950 2998012345299999388352999991039953991232012479934673289999982640499999415l

Step-by-step explanation:

By substituting x = -2 in each expression, we find that x-2 equals -4, x-1 equals -3, x₀ equals 1, x₁ equals -2, and x₂ equals 4.

To solve this, we need to substitute x = -2 into each expression. Here are the results:

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13d + 25 = 8d

13d - 8d = -25

5d = -25

d = -5

so the answer is (-5)

Answer:

Step-by-step explanation:

13d + 25 = 8d

13d = 8d -25

13d - 8d = -25

5d = -25

d = -5

Answer:

approximately 2,800

Step-by-step explanation:

you would round 691 to 700 then multiply by 4

Answer:

2,800

Step-by-step explanation:

In saying "largest number," I believe the question means that you should round 691 up to 700 (nearest hundreds). Multiple 700 by 4, and you will get 2,800! Hope this helps! :)

MI ≅ MR proved by using ASA postulate of congruence

Step-by-step explanation:

Let us revise the cases of congruence

∵ M is the mid-point of TE

∴ MT = ME

In Δs TMI and EMR

∵ ∠T ≅ ∠E ⇒ given

∵ ∠TMI ≅ EMR ⇒ vertical opposite angles

∵ MT = ME ⇒ proved

∴ Δ TMI ≅ ΔEMR by ASA postulate of congruence

- From congruence, corresponding sides are equal

∴ MI ≅ MR

MI ≅ MR proved by using ASA postulate of congruence

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The question is about a geometry proof related to congruent angles and midpoints, but additional information is needed to provide a specific solution.

The question appears to be a geometry proof involving congruent angles and midpoints. The goal is to prove that two line segments MI and MR are congruent given ∠E ≅ ∠T, and M is the midpoint of TE.

To prove this, one would need to provide more information about the points I and R, such as their positions relative to point E, T, and M.

Without this additional information, it is difficult to give a specific proof. However, typical proof strategies might involve showing that triangles EMI and TMR are congruent by Side-Angle-Side (SAS), Angle-Side-Angle (ASA), or Angle-Angle-Side (AAS) postulates, depending on the position of points I and R.

Answer:

There's no picture. Is it D.√3 / 2

Step-by-step explanation:

Answer:

Therefore Afon can read 0.75 pages per minute.

Step-by-step explanation:

Afon read 22 1/2 pages in 30 minutes

Therefore Afon read 22.5 pages in 30 minutes.

Therefore the number of pages Afon can read in 1 minute

[tex]= \dfrac{22.5}{30} = \dfrac{45}{60} = \dfrac{9}{12} = \dfrac{3}{4} = 0.75 pages[/tex]

Therefore Afon can read 0.75 pages per minute.