Draw a structure for an alcohol that exhibits a molecular ion at M+ = 74 and that produces fragments at m/z = 59, m/z = 56 and m/z = 45.

Answer:

Hi

A conjugate acid is a chemical compound formed by the reception of a proton by a base; therefore, it is a base with an added hydrogen ion. On the other hand, a conjugate base is what remains after an acid has donated its proton during a chemical reaction, so it can be said that a conjugate base is a species modified by extracting a proton from an acid.

In pyrrole, the electron pair can be relocated to the ring and its availability is very small. In addition, the concept of aromaticity comes into play.

In the attached file are the schemas of the conjugate bases.

Explanation:

To find the minimum number of fuel canisters needed to heat the water to boiling point, calculate the heat required to heat the water and compare it to the heat released from burning one canister of propane.

To find the minimum number of fuel canisters needed to heat the water to boiling point each day, we can calculate the heat required to heat 5.0kg of water from 25°C to its boiling point and compare it to the heat released from burning one canister of propane.

The heat required to heat the water is given by the equation Q = mCΔT, where m is the mass of the water, C is the specific heat capacity of water, and ΔT is the temperature change. The specific heat capacity of water is approximately 4.184 J/g°C.

We can use the equation Q = nΔH, where n is the number of moles of fuel burned and ΔH is the heat of combustion, to calculate the heat released from burning one canister of propane. The heat of combustion of propane is given as -2219.2 kJ/mol.

By equating the two equations and solving for n, we can find the number of moles of fuel burned by one canister of propane. Then, we can use the molar mass of propane (44.1 g/mol) to find the mass of propane burned by one canister. Finally, by dividing the total mass of water to be heated by the mass of propane burned by one canister, we can find the minimum number of fuel canisters needed.

By following these calculations, the minimum number of fuel canisters required to heat the water to boiling point each day will be: {number of canisters}.

Answer: (1). pH = 1.70

(2). pH = 2.3

(3). pH = 3.3

(4). pH = 4.3

(5). pH = 8.41

(6). pH = 10.22

Explanation:

we assume that the formula representation of acid is H₂A

the titration curve has reasonably sharp breaks at both equivalence points, corresponding to the reactions;

H₂A + OH⁻ → HA⁻ + H₂O

HA⁻ + OH⁻ → A²⁻ + H₂O

the volume of NaOH (V₀) at the first equivalent point is,

V₀ = (20.0 mL)(0.100M) / 0.100M = 20.0mL

where volume of NaOH at 1/2 equivalent point is,

V₀/2 = 10.0mL

also Volume of NaOH at the second equivalence (2V₀) point is 40.0mL

the volume of NaOH at 1/2 second equivalent point is,

V₀ + V₀/2 = 30.0mL

Volume of NaOH after second equivalence exceeds 40mL

therefore, at 0 mL NaOH addition;

where the extent of ionization is assumed to be x, we have

                        H₂A   ⇆     HA⁻   +   H⁺

where initial:   0.1 M       -            -

          change:   -x         +x           +x

          Equili:      0.1-x      x             x

Kаl = [HA⁻][H⁺] / [H₂A]

10⁻²³ = (x)(x) / (0.1-x)

x = 0.020

[H⁺] = 0.020 M

pH = -log [H⁺]

pH = -log(0.020)

pH = 1.70

(2). at 10 mL NaOH addition

[H₂A]ini = 0.10 M * 20.0 mL = 2 mmol

[OH⁻] = 0.1 M * 10 mL = 1 mmol

after reaction:

[H₂A] = 1 mmol

[H⁻] = 1 mmol

pH = pKa₁ + log [HA⁻] / [[HA⁻]

pH = 2.3 + log 1mmol / 1mmol

pH = 2.3

(3). pH at the first equivalence point is,

pH = 1/2 (pKa₁ + pKa₂)

pH = 1/2(2.3 + 4.3) = 3.3

pH = 3.3

(4). pH at the second 1/2 equivalence point is

pH = pKa₂ = 4.3

pH = 4.3

(5). pH at the second equivalence point;

all H₂A is converted into A²⁻

[A²⁻] = initial moles of H₂A / total volume = (20.0 mL)(0.10 M) / (20.0 + 40.0) mL = 0.033 M

at equilibrium:

                   A²⁻ + H²O    ⇆   HA⁺ OH⁻

          0.033 - x

from the Kb₁ expression,

Kb₁ = [OH⁻][HA⁻] / [A²]

Kw/Ka₂ = x²/(0.0333 - x)

10⁻¹⁴/10⁻⁴³ = x²/(0.0333 - x)

x = 2.57 * 10⁻⁶

[OH⁻] = 2.57 * 10⁻⁶M

pH = -log Kw/[OH⁻] = 8.41

pH = 8.41

(6). pH after second equivalence point;

assuming the volume of NaOH is 40.10 mL

after second equivalence point OH⁻ in excess

[OH⁻] = 0.10 M * 0.10 mL / (20 + 40.10) mL = 1.66 * 10⁻⁴ M

pH = 0=-log Kw/[OH⁻] = 10.22

pH = 10.22

The correct formula unit equation for the reaction of potassium sulfate and barium chloride forming potassium chloride and barium sulfate in water is: K2SO4 (aq) + BaCl2 (aq) → 2 KCl (aq) + BaSO4 (s). This is because both potassium sulfate and barium chloride are soluble in water, but barium sulfate is not.

The correct formula unit equation for the reaction of potassium sulfate and barium chloride forming potassium chloride and barium sulfate in water is: K2SO4 (aq) + BaCl2 (aq) → 2 KCl (aq) + BaSO4 (s).

This can be justified as when potassium sulfate (K2SO4) and barium chloride (BaCl2) are dissolved in water they dissociate into their respective ions, making them aqueous. The formation of potassium chloride (KCl) acknowledges that potassium ions and chloride ions can be attracted to each other in the water solution, so this is also aqueous. However, barium sulfate (BaSO4) is known to be insoluble in water, and hence, precipitates as a solid (s). Hence, option 2 is correct.

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Answer:

In the arrangement of particles within any atom, the outermost sort of particle is always the electron.

Explanation:

An atom consist of electron, protons and neutrons. Protons and neutrons are present with in nucleus while the electrons are present out side the nucleus.

All these three subatomic particles construct an atom. A neutral atom have equal number of proton and electron. In other words we can say that negative and positive charges are equal in magnitude and cancel the each other.

The electron is subatomic particle that revolve around outside the nucleus and has negligible mass. It has a negative charge.

Symbol= e-

Mass= 9.10938356×10-31 Kg

It was discovered by j. j. Thomson in 1897 during the study of cathode ray properties.

While neutron and proton are present inside the nucleus. Proton has positive charge while neutron is electrically neutral. Proton is discovered by Rutherford while neutron is discovered by James Chadwick in 1932.

Symbol of proton= P+  

Symbol of neutron= n0  

Mass of proton=1.672623×10-27 Kg

Mass of neutron=1.674929×10-27 Kg

In any atom, the outermost type of particle is the electron, specifically the valence electrons in the outermost shell. These electrons play a significant role in chemical reactions and bonding properties of the element. The organization of the Periodic Table reflects patterns in valence electron configurations that correspond to chemical behaviors.

In the arrangement of particles within any atom, the outermost sort of particle is always the electron. Electrons are the smallest of the three types of sub-atomic particles, carrying a negative charge and occupying the space outside the atomic nucleus. Inside the nucleus, much larger particles—protons and neutrons—are found, with protons having a positive charge and neutrons being electrically neutral.

The outermost electrons are of particular importance because they are the valence electrons. These are the electrons that reside in the outermost shell, or valence shell, of an atom in its uncombined state, and they play critical roles in determining the chemical properties of an element as well as its ability to form bonds with other atoms. The electron configuration of an atom is notably important because atoms with the same outer electron configurations tend to show similar chemical behavior, as demonstrated in the organization of the Periodic Table.

The number of valence electrons in the outermost shell can define an element's chemical reactivity and the types of bonds it can form. The arrangement of electrons in atoms means that the electrons with the highest energy levels, which are the valence electrons, are more likely to interact in chemical reactions than the core electrons which are closer to the nucleus and have lower energy levels.

Answer:

pH = 1.98

Explanation:

Given a general acid dissociation:

HA + H₂O  ⇆  H₃O⁺   + A⁻    

The pH is -log[ H₃O⁺ ]

Therefore we need to determine [ H₃O⁺ ] to answer this question, and we should use the data of % dissociation of the acid.

Percent dissociation is

% dissociation = [ H₃O⁺ ] / [ HA ]₀ x 100

where [ HA ]₀  is the original acid concentration, so we can calculate [ H₃O⁺ ] , and then the pH.

12 =  [ H₃O⁺ ] /0.089 M ⇒  [ H₃O⁺ ]  = (12 x 0.089 /100) M

                                                          = 1.07 x 10⁻² M

and pH = - log ( 1.07 x 10⁻² ) = 1.98

To determine the pH of a 0.089M solution of an acid that is 12% dissociated, we first calculate the hydronium ion concentration and then use the formula for pH. After calculation, the pH is found to be 2.97.

To calculate the pH of the solution where the acid is 12% dissociated, we first need to determine the concentration of hydronium ions ([H+]) in the solution.

Given a 0.089M solution of an acid that is 12% dissociated, the concentration of dissociated hydronium ions is:

This concentration has three significant figures. Using the formula for pH which is:

The pH is then calculated as:

pH = -log(0.01068) = 2.97

The result is in the acidic pH range, and it has been rounded to two decimal places to match the number of significant figures from the initial concentration given.

Answer:

4. Oxygen

Explanation:

A

Individual lipid molecules are free to diffuse laterally in the surface of the bilayer is a general feature of the lipid bilayer in all biological membranes

Explanation:

The inside of the bilipid layer of the cell membrane of cells is made of fatty acid chains and cholesterol which are nonpolar molecules. they are sandwiched between the polar (glycerol) ends of the  chains because they are hydrophobic and cannot interact with the ‘watery’ extracellular fluids.  Non-polar molecules like lipids can easily diffuse laterally, within this lipid layers of the membrane because non-polar molecules interact well with other nonpolar molecules.

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Answer: the empirical formula is C3H4O3

Explanation:Please see attachment for explanation

Answer:

The answer to your question is  C₃H₄O₃

Explanation:

Data

CxHyOz

mass of sample = 0.150 g

mass of CO₂ = 0.225 g

mass of H₂O = 0.0614 g

Reaction

                     CxHyOz + O₂   ⇒   CO₂   + H₂O

Process

1.- Calculate the moles of C

                            44 g of CO₂ ----------------- 12 g of C

                            0.225 g    ---------------- x

                            x = (0.225 x 12) / 44

                            x = 0.0614 g of C

                            12 g of C -------------------- 1 mol

                           0.0614 g of C --------------- x

                                 x = 0.0051 moles of Carbon

2.- Calculate the moles of hydrogen

                            18 g of H₂O ------------------ 2 g of H

                             0.0614 g --------------- x

                             x = 0.0068 g of H

                             1 g of H ----------------------- 1 mol of H

                            0.0068 g --------------------- x

                             x = 0.0068 moles of H

3.- Calculate the mass of Oxygen

    Mass of oxygen = 0.150 - 0.0614 - 0.0068

                               = 0.0818 g

                       16 g of O -------------------  1 mol

                      0.0818 g -------------------- x

                         x = (0.0818 x 1) / 16

                         x = 0.0051 moles of O

4.- Divide by the lowest number of moles

Carbon       0.0051 / 0.0051  = 1

Hydrogen   0.0068 / 0.0051 = 1.33

Oxygen       0.0051 / 0.0051 = 1

Multiply these numbers by 3

Carbon 3

Hydrogen = 4

Oxygen = 3

5.- Write the empirical formula

                                      C₃H₄O₃

Answer:

Explanation:Isobaric is a thermodynamic process in which the pressure of the system is zero. It is a process where there is no work done in the system. Therefore the temperature of the system according to the ideal gas law will vary linearly with pressure and inversely with volume.

Answer: 2.02mL

Explanation:

Density = 2.82 g/mL

Mass = 5.71 g

Volume =?

Density = Mass /volume

2.82 = 5.71 / Volume

Volume = 5.71 / 2.82

Volume = 2.02mL

Answer:

20.1 g

Explanation:

The solubility indicates how much of the solute the solvent can dissolve. A solution is saturated when the solvent dissolved the maximum that it can do, so, if more solute is added, it will precipitate. The solubility varies with the temperature. Generally, it increases when the temperature increases.

So, if the solubility is 40.3 g/L, and the volume is 500 mL = 0.5 L, the mass of the solute is:

40.3 g/L = m/V

40.3 g/L = m/0.5L

m = 40.3 g/L * 0.5L

m = 20.1 g

The solubility value indicates how much of compound X can be dissolved in water at 20°C. Considering we need a 500 mL solution, we require half the solubility of X in grams. Therefore, to calculate the required mass of X, we multiply solubility by volume, yielding a result of 20.15 g.

To calculate the mass of compound X required to prepare a saturated solution of 500 mL, we first need to understand the solubility value provided. The solubility of X is given as 40.3 g/L at 20°C, meaning that 1 L of water can dissolve 40.3 g of X at this temperature.

Since we need only 500 mL (or 0.5 L) of the solution, we will require half of the solubility value in grams of X. Therefore, by simple multiplication, we get:

X mass = Solubility * Volume

= 40.3 g/L * 0.5 L = 20.15 g

So, 20.15 g of compound X is needed for a saturated solution of 500 mL at 20°C.

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Answer:Maintaining resting potential and returning to resting potential after the hyperpolarization phase of an action potential

Explanation:TOXINS are chemical substances which are known to be POISONOUS produced with living organisms that causes harm to other organisms, examples include Venom from snakes which when a person is bitten by a Snake it will possibly lead to death if not adequate treated.

HYPERPOLARIZATION is a term that explains the change in membrane potential due to toxin,it make the membrane more electronegative. When the toxin has hyped the level of Sodium-Potassium level returning to a rest state will be most affected.

Answer:

D is the true statement.

Explanation:

Recall that during a phase change the temperature remains constant until all the material has changed its phase. The energy put into the system is utilized to make the phase change, and afterward the temperature of the vliquid will start to increase.

In this case we have a mixture of liquid water and ice at  0ºC  ( assume standard pressure) which is the temperature in which liquid water and ice coexist. The ice will  melt until consumed at constant T = 0ºC, and then the temperature of the liquid water will start to increase at a uniform rate since we are heating at a constant rate.

Now we are in position to answer this question.

A- False the temperature does not increase as the ice melts.

B- False for the reasons given above.

C- False the temperature does not increase slowly as the ice melts, but remains constant.

D-True the temperature of the mixture does not change until all the ice has melted, and then the temperature of liquid water will start to increase uniformly.

Heat applied to a water-ice mixture initially goes into breaking the hydrogen bonds in ice (latent heat of fusion), without causing a temperature increase. Only after all the ice has melted, the added heat increases the water temperature.

The correct option is D: The temperature of the mixture does not change at all until all the ice has melted, at which point it increases at a constant rate. This is because the energy from the heat being applied is first used to break the hydrogen bonds in ice, a process known as latent heat of fusion, which does not involve an increase in temperature. Only after all the ice has melted will the added heat then lead to an increase in the temperature of the water.

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Complete Question:

If heat is added to ice and liquid water in a closed container and after the addition of the heat, ice and liquid water remain, (A) the vapor pressure of the water will decrease. (B) the temperature will increase somewhat. (C) the temperature will decrease somewhat. (D) the vapor pressure of the water will remain constant.

Answer:

A

Explanation:

When heat is added to a system, the internal energy of the molecules increases, and they become more agitated, because of that the temperature intends to increase. But when exists a liquid-vapor equilibrium this increase of temperature may be balanced by the vapor pressure.

The vapor pressure is the pressure that the vapor does when it is in equilibrium with the liquid. So, as higher is it, as easy it will be to the liquid to evaporate. When the temperature increases more liquid will evaporate, because the molecules are more agitated, and so the vapor pressure must increase.

But, if the ice and liquid remain, it indicates that no liquid was evaporated, so, the pressure decreased, to avoid the effect of the temperature, which will remain constant.

Answer:

2H2S + 3O2 → 2SO2 + 2H2O

Explanation:

Step 1: Data given

Hydrogen sulfide = H2S

Oxygen = O2

sulfur dioxide = SO2

water = H2O

Step 2: The unbalanced equation

H2S + O2 → SO2 + H2O

Step 3: Balancing the equation

H2S + O2 → SO2 + H2O

On the left side we have 2x O (in O2) and on the right side we have 3x O (2x in SO2 and 1x in H2O). To balance the amount of O, we have to multiply O2 (on the left side) by 3 and SO2 and H2O on the right side by 3.

H2S + 3O2 → 2SO2 + 2H2O

On the right side we have 4x H and on the left side we have 2x H. To balance the amount of H, we have to multiply H2S by 2.

Now the equation is balanced.

2H2S + 3O2 → 2SO2 + 2H2O

Answer:

[KIO₃] = 0.548 M

Explanation:

Molarity is a sort of concentration which involves moles of solute in 1L of solution.

Volume of solution 5L

Mass of solution: 587 g

Let's convert the mass to moles (mass / molar mass)

587 g / 214 g/mol = 2.74 moles

Molarity is mol/L → 2.74 mol / 5L = 0.548 M

Answer:

0.0016 mol/(L.s)

Explanation:

The rate of a reaction (r) can be calculated by the initial concentration of the reagent, by the expression:

-r = k*[reagent]ⁿ

Where the minus sign represents that the reagent is disappearing, k is the rate constant, which depends on the temperature, and n is the order of the reaction. For the reaction with more than 1 reagent, each reagent will have its order, which is determined by experiments. So, for n = 0:

-r = 0.0016*(1.50)⁰

-r = 0.0016 mol/(L.s)

Final answer:

The rate of a zero-order reaction is equal to the rate constant, which in the case of the hydrogenation of ethylene using a nickel catalyst is 0.0016 mol L.

Explanation:

To determine the rate of reaction for a zero-order reaction, we use the rate law which states that the rate is independent of the concentration of the reactants. Therefore, for a zero-order reaction, the rate of reaction ( ) is equal to the rate constant (k). Given that the rate constant k is 0.0016 mol L for the hydrogenation of ethylene, the rate of the reaction would simply be the same as the rate constant, which is 0.0016 mol L

The question is incomplete, here is the complete question.

A chemist adds 345.0 mL of a 0.0013 mM (MIllimolar) copper(II) fluoride [tex]CuF_2[/tex] solution to a reaction flask.

Calculate the mass in micrograms of copper(II) fluoride the chemist has added to the flask. Be sure your answer has the correct number of significant digits.

Answer : The mass of copper(II) fluoride is, 0.13 mg

Explanation :  Given,

Millimolarity of copper (II) fluoride = 0.0013 mM

This means that 0.0013 millimoles of copper (II) fluoride is present in 1 L of solution

Converting millimoles into moles, we use the conversion factor:

1 moles = 1000 millimoles

So, [tex]0.0013mmol\times \frac{1mol}{1000mmol}=1.3\times 10^{-6}mol[/tex]

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

We are given:

Moles of copper (II) fluoride solution = [tex]1.3\times 10^{-6}mol[/tex]

Molar mass of copper (II) fluoride = 101.5 g/mol

Putting values in above equation, we get:

[tex]1.3\times 10^{-6}mol=\frac{\text{Mass of copper (II) fluoride}}{101.5g/mol}\\\\\text{Mass of copper (II) fluoride}=(1.3\times 10^{-6}mol\times 101.5g/mol)=1.32\times 10^{-4}g[/tex]

Converting this into milligrams, we use the conversion factor:

1 g = 1000 mg

So,

[tex]\Rightarrow 1.32\times 10^{-4}g\times (\frac{1000mg}{1g})=0.13mg[/tex]

Therefore, the mass of copper(II) fluoride is, 0.13 mg

Answer:

the mass of copper(II) fluoride added to the flask is approximately 476,250 micrograms.

Explanation:

To calculate the mass of copper(II) fluoride (CuF2) added to the reaction flask, you need to multiply the volume (in liters) of the solution by its molarity and then convert the result to micrograms.

Given:

Volume of the solution (V) = 0.015 L

Molarity of the solution (M) = 0.500 M

First, calculate the number of moles of copper(II) fluoride using the formula:

Moles (n) = Molarity (M) × Volume (V)

n = 0.500 M × 0.015 L = 0.0075 moles

Now, you need to convert moles to micrograms. One mole of any substance contains Avogadro's number of molecules (6.022 × 10^23). You also need to consider the molar mass of copper(II) fluoride (CuF2), which is the sum of the atomic masses of copper (Cu) and two fluorine (F) atoms:

Molar mass of CuF2 = (1 * Cu) + (2 * F) = 63.5 g/mol (approximately)

Now, calculate the mass in grams:

Mass (g) = Moles (n) × Molar mass (Molar mass of CuF2)

Mass (g) = 0.0075 moles × 63.5 g/mol ≈ 0.47625 g

Now, convert grams to micrograms. There are 1,000,000 micrograms in a gram:

Mass (micrograms) = Mass (g) × 1,000,000

Mass (micrograms) = 0.47625 g × 1,000,000 µg/g = 476,250 µg

So, the mass of copper(II) fluoride added to the flask is approximately 476,250 micrograms.

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Answer:

The energy required to ionize the ground-state hydrogen atom is 2.18 x 10^-18 J or 13.6 eV.

Explanation:

To find the energy required to ionize ground-state hydrogen atom first we calculate the wavelength of photon required for this operation.

It is given by Bohr's Theory as:

1/λ = Rh (1/n1² - 1/n2²)

where,

λ = wavelength of photon

n1 = initial state = 1 (ground-state of hydrogen)

n2 = final state = ∞ (since, electron goes far away from atom after ionization)

Rh = Rhydberg's Constant = 1.097 x 10^7 /m

Therefore,

1/λ = (1.097 x 10^7 /m)(1/1² - 1/∞²)

λ = 9.115 x 10^-8 m = 91.15 nm

Now, for energy (E) we know that:

E = hc/λ

where,

h = Plank's Constant = 6.625 x 10^-34 J.s

c = speed of light = 3 x 10^8 m/s

Therefore,

E = (6.625 x 10^-34 J.s)(3 x 10^8 m/s)/(9.115 x 10^-8 m)

E = 2.18 x 10^-18 J

E = (2.18 x 10^-18 J)(1 eV/1.6 x 10^-19 J)

E = 13.6 eV

The heat of reaction,  ΔH°rxn, for overall reaction in coal gasification for the production of methane, CH₄ is 12.4 kJ

From the question,

We are to determine the heat of reaction for overall reaction for the production of methane in coal gasification

The equation for the reaction of coal gasification is

2C(coal) + 2H₂O → CO₂ + CH₄  

From the question,

We have the following equations of reactions

(1)        C(coal) + H₂O(g) → CO(g) + H₂(g)               ΔH°rxn = 129.7 kJ

(2)       CO(g) + H₂O(g) → CO₂(g) + H₂(g)               ΔH°rxn = -41 kJ

(3)       CO(g) + 3H₂(g) → CH₄(g) + H₂O(g)              ΔH°rxn = -206 kJ

Multiply (1) by 2 to get

(4)       2C(coal) + 2H₂O(g) → 2CO(g) + 2H₂(g)       ΔH°rxn = 259.4 kJ

Now, adding equations (2), (3), and (4), we get

(2)       CO(g) + H₂O(g) → CO₂(g) + H₂(g)               ΔH°rxn = -41 kJ

(3)       CO(g) + 3H₂(g) → CH₄(g) + H₂O(g)              ΔH°rxn = -206 kJ

(4)       2C(coal) + 2H₂O(g) → 2CO(g) + 2H₂(g)       ΔH°rxn = 259.4 kJ

--------------------------------------------------------------------------------------------------

          2C(coal) + 2H₂O(g) → CH₄(g) + CO₂(g)        ΔH°rxn = 12.4 kJ

Hence, the heat of reaction,  ΔH°rxn, for overall reaction in coal gasification for the production of methane, CH₄ is 12.4 kJ

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The heat of reaction, or ΔH°rxn, for the overall methane production reaction sequence is calculated by summing the enthalpy changes of the individual steps. This value comes out as -117.3 kJ per the application of Hess's Law.

In order to calculate the heat of reaction, ΔH°rxn, for overall methane production, we have to use Hess's Law. According to Hess's Law, if a process can be written as the sum of several stepwise processes, the enthalpy change of the total process equals the sum of the enthalpy changes of the various steps. The first reaction has an enthalpy change of 129.7 kJ, the second -41 kJ, and the third -206 kJ.

Now, to find the overall reaction, we will sum up the enthalpy of all these three reactions. So, ΔH°rxn for the overall reaction would be calculated as 129.7 kJ - 41 kJ - 206 kJ = -117.3 kJ. Hence, the heat of reaction for the given set of reactions for the production of methane will be -117.3 kJ.

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Complete Question

The complete question is show on the first uploaded image

Answer:

This is shown on the second,third , fourth and fifth image

Explanation:

This is shown on the second,third , fourth and fifth image

Answer: The atomic mass of E is 16

Explanation:Please see attachment for explanation

Answer:

The molar mass of E = 15.96 g/mol

Explanation:

Step 1: Data given

The compound Cr2E3 contains 68.47 % Cr and 31.53 % E

The molar mass of Cr = 52 g/mol

⇒ 2*52 = 104 g/mol

The molar mass of Cr2E3 = 2*52 g/mol + 3X

Step 2: Calculate mass of Cr2E3

Cr is 68.47 %

Mass of Cr = 104 grams

Cr2E3 is 100%

Mass of Cr2E3 = 151.89 grams

Molar mass of Cr2E3 = 151.89 g/mol

Step 3: Calculate mass of E

Mass of E3 = mass of Cr2E3 - mass of Cr

Mass of E3 = 151.89 grams - 104 grams

Mass of E3= 47.89 grams

Mass of E = 15.96 grams

The molar mass of E = 15.96 g/mol

Answer:

C21H30O5

Explanation:

Cortisol with molecular formula C21H30O5 is a steroid hormone released by adrenal glands, it is involved in protein synthesis and can also help to control blood sugar level .

Answer:

a, b and d

Explanation:

Proper Solvent choice is very important for effective recrystallization.

Therefore, features of a good solvent are.

a. The solvent should dissolve a moderate quantity of the target substance near its boiling point but only.

b. The solvent should not react with the target substance.

d. The solvent should be easily removed from the purified product.

options c and d are not a property of good solvent.

Answer: The substance that produces fewest particles is [tex]CH_2Cl_2[/tex]

Explanation:

Ionization reaction is defined as the reaction in which an ionic compound dissociates into its ions when dissolved in aqueous solution.

Covalent compounds do not dissociate into ions when dissolved in aqueous solution.

For the given options:

The chemical formula of sodium nitrate is [tex]NaNO_3[/tex]

The ionization reaction for the given compound follows:

[tex]NaNO_3(aq.)\rightarrow Na^+(aq.)+NO_3^-(aq.)[/tex]

This produces in total of 2 ions.

The given compound is a covalent compound and do not dissociate into its ions. It remains as such as a single unit.

The chemical name for the given compound is potassium sulfate.

The ionization reaction for the given compound follows:

[tex]K_2SO_4(aq.)\rightarrow 2K^+(aq.)+SO_4^{2-}(aq.)[/tex]

This produces in total of 3 ions.

The chemical formula of sodium phosphate is [tex]Na_3PO_4[/tex]

The ionization reaction for the given compound follows:

[tex]Na_3PO_4(aq.)\rightarrow 3Na^+(aq.)+PO_4^{3-}(aq.)[/tex]

This produces in total of 4 ions.

Hence, the substance that produces fewest particles is [tex]CH_2Cl_2[/tex]

Answer : A nucleotide is composed of a phosphate group and a nitrogen-containing base.

Explanation :

Nucleotide : It is a building block of nucleic acids or we can say that it is building block of DNA and RNA.

It is composed of three sub-unit molecules which are a nitrogenous base, a five-carbon sugar and one phosphate group.

Nucleotide forms covalent bonds with other nucleotide for the formation of the nucleic acid strand.

Hence, a nucleotide is composed of a phosphate group and a nitrogen-containing base.

A nucleotide is composed of a a. phosphate group, a nitrogen-containing base, and a hydrocarbon glycerol.

A nucleotide is a fundamental building block of nucleic acids, such as DNA and RNA. It consists of three essential components: a phosphate group, a nitrogen-containing base, and a sugar molecule, not a hydrocarbon glycerol. The phosphate group provides a negatively charged backbone, linking individual nucleotides together through phosphodiester bonds, forming the nucleic acid's backbone.

The nitrogen-containing base can be adenine (A), thymine (T), cytosine (C), guanine (G) in DNA, or uracil (U) instead of thymine in RNA. The sugar molecule, deoxyribose in DNA and ribose in RNA, forms the structural framework to which the phosphate group and nitrogenous base are attached.

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Answer: 2,5-dimethyl octane.

Explanation:

The basic rules for naming of organic compounds are :

1. First select the longest possible carbon chain.

2. The longest possible carbon chain should include the carbons of double or triple bonds.

3. The naming of alkane is done by adding the suffix -ane, alkene by adding the suffix -ene, alkyne by adding the suffix -yne and carboxylic acid by adding the suffix -oic acid.

4. The numbering is done in such a way that first carbon of double or triple bond gets the lowest number.

5. The carbon atoms of the double or triple bond get the preference over the other substituents present in the parent chain.

6. If two or more similar alkyl groups are present in a compound, the words di-, tri-, tetra- and so on are used to specify the number of times of the alkyl groups in the chain.

Thus the name for straight chain made of 8 carbons with [tex]-CH_3[/tex] groups on the second and fifth carbons will be 2,5-dimethyl octane.

The question is incomplete, here is the complete question:

Consider this reaction occurring at 298 K:

[tex]N_2O(g)+NO_2(g)\rightleftharpoons 3NO(g)[/tex]

If a reaction mixture contains only [tex]N_2O\text{ and }NO_2[/tex] at partial pressures of 1.0 atm each, the reaction will be spontaneous until some NO forms in the mixture.

What maximum partial pressure of NO builds up before the reaction ceases to be spontaneous. Given that: [tex]\Delta G^o_{rxn}=107.8kJ/mol[/tex]

Answer: The maximum partial pressure of NO will be [tex]5.01\times 10^{-7}atm[/tex]

Explanation:

For the given chemical equation:

[tex]N_2O(g)+NO_2(g)\rightleftharpoons 3NO(g)[/tex]

The expression of [tex]K_p[/tex] for above equation follows:

[tex]K_p=\frac{p_{NO}^3}{p_{N_2O}\times p_{NO_2}}[/tex]

When the reaction ceases to be spontaneous, the [tex]\Delta G=0[/tex] (at equilibrium)

Relation between standard Gibbs free energy and equilibrium constant follows:

[tex]\Delta G=\Delta G^o+2.303RT\log K_p[/tex]

where,

[tex]\Delta G^o[/tex] = Standard Gibbs free energy = 107.8 kJ/mol = 107800  J/mol  (Conversion factor: 1 kJ = 1000 J )

R = Gas constant = [tex]8.314J/K mol[/tex]

T = temperature = 298 K

[tex]p_{N_2O}=1.00atm[/tex]

[tex]p_{NO_2}=1.00atm[/tex]

Putting values in above equation, we get:

[tex]0=107800J/mol+(2.303\times 8.314J/Kmol)\times 298K\times \log (\frac{p_{NO}^3}{1.00\times 1.00})[/tex]

[tex]-107800=5705.85\times \log (\frac{p_{NO}^3}{1.00\times 1.00})\\\\-18.893=\log (p_{NO}^3)-\log (1.00)\\\\-18.893=3\log (p_{NO})\\\\\log (p_{NO})=-6.30\\\\p_{NO}=10^{-6.30}=5.01\times 10^{-7}atm[/tex]

Hence, the maximum partial pressure of NO will be [tex]5.01\times 10^{-7}atm[/tex]

Answer:

1) chemical change

2) filtration

Explanation:

A chemical change involves the formation of a new substance. In this case, the pure white solid formed is an entirely new substance, with a different chemical identity from those of the two solutions mixed to form it. The new solid is a precipitate. Precipitates are easily separated by filtration of the reaction mixture. Another name for chemical change is chemical reaction.

1) This is an example of chemical change.

2) The most convenient way to separate the newly formed white solid from the liquid mixture is filtration

A chemical change involves the formation of a new substance. In this case, the pure white solid formed is an entirely new substance, with a different chemical identity from those of the two solutions mixed to form it. The new solid is a precipitate. Precipitates are easily separated by filtration of the reaction mixture. Another name for chemical change is chemical reaction.

The most convenient way  to separate the newly formed white solid from the liquid mixture is filtration since precipitates are formed.

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