Answer:
Cross bridge in a sarcomere of a fast fiber produce higher amounts of force as compared to a cross bridge in a sarcomere of a slow fiber
Explanation:
When a muscle contracts, a cross bridge is formed between actin and myosin. The sarcomere shortens when a muscle contracts by reforming cross bridge. In general a muscle fiber is of three types – a) slow, b) Fast and c) intermediate.
The sarcomere of fast fiber generates high force but for a short period of time. On the other hand, sarcomere of slow fiber generate lower amounts of force but this force lasts for a longer period of time. Due to this difference, fast fibers are the predominant fibers in the body
About 12 to 24 hours after the last meal, a person's blood sugar level normally varies from 60 to 90 mg per 100 ml of blood, although it may rise to 130 mg per 100 ml after meals high in carbohydrates. That the blood sugar level is maintained within a fairly narrow range, despite uneven intake of sugar, is due to the bodily process called_______________.
The process that helps to maintain the blood sugar level within a fairly narrow range is ; Homeostasis
The insulin and glucagon hormones help in the maintenance of the sugar levels in the human body( Homeostasis ).The function of glucagon is to increase the blood sugar levels, while the insulin decreases high level of blood sugar levels.
Homeostasis is the process of maintaining stable living conditions of an organism by the organism in response to both internal and external changes. As seen in the question the blood sugar level is maintained within a fairly narrow range by both Insulin and glucagon hormones.
Hence we can conclude that The process that helps to maintain the blood sugar level within a fairly narrow range is ; Homeostasis .
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The process maintaining blood sugar level within a narrow range is homeostasis. It's primarily controlled by insulin, which reduces blood glucose by promoting its utilization, and glucagon, which increases blood glucose by stimulating glycogen breakdown during fasting or the postabsorptive state.
Explanation:The bodily process that maintains blood sugar level within a fairly narrow range, despite uneven intake of sugar, is called homeostasis. This process is primarily controlled by two hormones, insulin and glucagon. Blood glucose levels tend to rise after a meal, and especially high-carbohydrate meals which would trigger the release of insulin from the beta cells of the pancreas. Insulin facilitates the uptake of glucose by the body cells and its utilization for energy production, thereby lowering blood glucose level.
On the other hand, during periods of fasting or the postabsorptive state, when glucose levels drop, glucagon is released from the alpha cells of the pancreas. Glucagon stimulates the breakdown of stored glycogen in the liver into glucose and its release into the blood, thus increasing blood glucose level. This process of regulation ensures that blood glucose is maintained within the optimal range for the body's function.
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This human karyotype is unusual because chromosome set
a. 5 has chromosomes of different shapes
b. 10 is missing genetic material
c. 14 has enlarged centromeres
d. 21 has an extra chromosome
Answer:
The correct option is d) 21 has an extra chromosome
Explanation:
The complete array of chromosomes that an individual possesses is known as the karyotype of the individual. Humans have 46 chromosomes which make up 23 pairs.
In the karyotype shown in the picture, the 21st pair has an extra chromosome. Such a condition is known as Down's Syndrome. In such a person, the mental ability of the person is influenced and he usually suffers from mental disabilities. The facial features of such a person also are different.
This human karyotype is unusual because chromosome set 21 has an extra chromosome (option d).
A karyotype is a graphic representation of the individual's collection of chromosomes.In diploid organisms (e.g., humans), each cell receives two homo-logous chromosomes, one from each parent.Human somatic (body) cells contain 46 chromosomes, which are organized into two sets of 22 homo-logous chromosomes and two sex chromosomes (either XX or XY).In conclusion, this human karyotype is unusual because chromosome set 21 has an extra chromosome (option d).
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when blood glucose levels are high The pancreas releases insulin. a.The liver releases insulin. b.The pancreas releases glucose. c.The liver releases glucagon. d.The pancreas releases glucagon.
The options were not well-ordered, it should be options A to E.
Answer: The correct answer is that the pancreas releases insulin.
Explanation:
Whenever the blood glucose level is high, the pancreas responds by releases insulin, a hormone secreted by its beta cells, and responsible for the regulation of blood sugar level by
- signalling cells of the muscle and liver to store excess blood glucose as GLYCOGEN until energy need arises.
Unlike insulin, when blood glucose levels is low, Glucagon is released also by pancreas to stimulates glycogen breakdown to raise glucose levels
Which of these statements is correct?
A. Scientific ideas are subjected to repeated testing.
B. Science can be used to prove or disprove the idea that deities or spirits cause earthquakes and other natural disasters.
C. Science does not require observations that other people can confirm.
D. Only discovery science can lead to important conclusions about nature.
Final answer:
The correct statement is that scientific ideas are subjected to repeated testing (A). Science focuses on the natural world and relies on observations that other researchers can confirm. Discovery and hypothesis-driven scientific approaches are both valuable for making conclusions about nature.
Explanation:
The correct statement among the options provided is A. Scientific ideas are subjected to repeated testing. This is a fundamental aspect of the scientific method, which involves formulating hypotheses and then conducting experiments and making observations to test these hypotheses. The results are then analyzed, and conclusions are drawn, which may either support or refute the hypotheses. This process can lead to revisions or further testing, contributing to a more accurate understanding of the natural world.
The protein building instructions must be sent out to the cytoplasm. A copy of the instructions is made in the form of ________. This process is called ______________________.
Answer:
1. RNA
2. Transcription
Explanation:
DNA stores the instructions required for the synthesis of proteins. However, the sequence of DNA does not directly serve as a template for protein synthesis. Rather, the template DNA strand is copied into the RNA. The process is called transcription.
The RNA in eukaryotes undergo modifications such as removal of introns and the addition of specific sequences at its 3' and 5' end. This mature mRNA that joins ribosomes for protein synthesis. The nucleotide sequence of mRNA is read in the form of triplets and each triplet code for a specific amino acid.
Maria loves to dance. She has noticed that whenever she dances, she has more energy the next day. Maria has noticed a __________ correlation.
Answer:
Maria noticed a positive correlation
Explanation:
Correlation is used to measure the extend to which two or more variables are related.
It can be positive where one variable increases when the other increases.
Negative where the increase of one aspect decrease the other variable.
Lastly, no correlation means there is no relationship between the two variables hence a change in one will not affect the other.
In the case of maria, there is a positive correlation between having more energy the next day and her dancing.
Which of the following hormones is released by the anterior pituitary as a part of that positive feedback loop between it and the ovary?
The anterior pituitary releases LH and FSH as part of the positive feedback loop with the ovary, triggered by high levels of estrogen leading to ovulation.
Explanation:The hormone released by the anterior pituitary as a part of the positive feedback loop between it and the ovary is LH (Luteinizing Hormone) and FSH (Follicle Stimulating Hormone). This occurs when the dominant follicle in the ovary secretes a large amount of estrogen, which in normal cases would exert a negative feedback. However, when estrogen levels are extremely high, they instead trigger a positive feedback loop, causing the anterior pituitary to release significant amounts of LH and FSH into the bloodstream. This event predominantly happens during the ovulation phase of the menstrual cycle, signaling one of the key steps that lead to ovulation.
Luteinizing hormone (LH) is released by the anterior pituitary in the positive feedback loop between it and the ovary.
Let's break down the options:
A) Progesterone: Progesterone is not released by the anterior pituitary; it is primarily produced by the corpus luteum in the ovary.
B) Luteinizing hormone (LH): LH is indeed released by the anterior pituitary and plays a crucial role in the positive feedback loop between the anterior pituitary and the ovary during the menstrual cycle.
C) Gonadotropin releasing hormone (GnRH): GnRH is released by the hypothalamus, not the anterior pituitary. It stimulates the release of LH and follicle-stimulating hormone (FSH) from the anterior pituitary.
D) Estrogen: Estrogen is primarily produced by the developing follicles in the ovary, not the anterior pituitary.
E) Gonadotropin: This term refers to hormones that stimulate the gonads (ovaries and testes), such as LH and FSH. "Gonadotropin" alone does not specify a particular hormone released by the anterior pituitary.
Therefore, the correct answer is: B) Luteinizing hormone
Luteinizing hormone (LH) is released by the anterior pituitary as part of the positive feedback loop between it and the ovary during the menstrual cycle.
The complete question is here:
Which of the following hormones is released by the anterior pituitary as a part of that positive feedback loop between it and the ovary?
A) Progesterone
B) Luteinizing hormone
C) Gonadotropin releasing hormone
D) Estrogen
E) Gonadotropin
Which of the following disciplines did Darwin draw information from in order to found the field of evolutionary biology and develop his theorya. demography
b. systematics
c. paleontology
d. taxonomy
e. geology
Answer:
b) Systematics
Explanation:
Darwin presented the theory of evolution and explained that the process of evolution occured because of natural selection which further explains that offsprings are produced from organisms and these organisms are able to survive in their environment.
As systematics is the branch of biology, which basically deals with evolutionary relationships of the organisms .Thus the darwin theory of evolution will be considered in the field of systematics.
Hence the option B) Systematics is the right option.
Darwin's theory of evolution was largely based on concepts and data derived from the fields of demography, paleontology, and geology.
Explanation:Charles Darwin, the founder of evolutionary biology, drew upon multiple academic disciplines to develop his groundbreaking theories. Particularly, he relied heavily upon concepts and data from demography, paleontology, and geology.
Demography provided him with insights into population dynamics, which formed the foundation of natural selection. Paleontology offered archaeological evidence of evolution over time through fossil records, proving the concept of 'descent with modification'. Geology made him understand that Earth's surface itself evolves, changing over very long timescales, which gave him a sense of the vast span of geological time during which evolution could occur.
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Summarize the aerobic phases of cellular respiration?
Answer:
1. Kreb's cycle breakdown the acetyl CoA into CO2 and H2O. The energy released is stored in the reducing powers (NADH and FADH2).
2. The electron transport chain oxidized the reducing powers into their oxidized forms. During this electron transport, the proton concentration gradient is produced across the inner mitochondrial membrane that drives ATP synthesis.
Explanation:
Kreb's cycle and electron transport chain (ETC) are the aerobic phases of cellular respiration. The carbon skeleton glucose enters Kreb's cycle in the form of acetyl CoA and is completely oxidized into CO2 and H2O. For one molecule of glucose, Kreb's cycle produces four molecules of CO2, 6 NADH, and 2 FADH2. In addition, two ATP are also formed by substrate-level phosphorylation.
The NADH and FADH2 enter ETC and are oxidized by giving their electrons to the molecular oxygen. Here, some of the energy of electrons is used to pump the protons from the matrix to intermembrane space. The resultant proton concentration gradient drives ATP synthesis. NADH produces the proton gradient enough to drive around 3 ATPs while FADH2 supports the formation of around 2 ATPs by oxidative phosphorylation.
The study of biological processes by comparing different species is known as
a. the comparative approach.
b. translational approach.
c. Gorzalka approach.
d. between-subjects approach.
Answer:
The correct answer is a. the comparative approach.
Explanation:
In the comparative method, we do the comparison between two different values, groups, cultures, etc. In a comparative approach, the similarities and differences are checked between two things to draw a conclusion.
Comparative study helps in finding out the relationship between two subjects. It can be used for hypothesis testing and theory building. Comparative study is and can be used in every field. So the study of biological processes by comparing different species is known as comparative study.
A football quarterback can simultaneously make calculations of receiver distances, player movements, and gravitational forces. This best illustrates the activity of multiple ________.a. endocrine glandsb. endorphin agonists
c. neural networks
d. endorphin antagonists
e. thresholds
Answer: Neural networks
Explanation:
The brain woks by combination of the networks. There are different types of neurons that combines together to function.
The network of neurons that are combined together in such a way to process the data.
It has the ability to process data in such a way that multiple function can be performed together like decision making, receiver distance, et cetera.
_________ is the preferred term to use when referring to the direction of a person’s sexual or romantic attraction.
Answer:
Sexual orientation
Explanation:
The sexual orientation is a term that defines the enduring pattern of sexual or romantic attraction of a person towards the opposite sex , same sex, more than one gender or towards both the sex. These are categorized as heterosexuality, homosexuality, bisexuality. The another category includes asexuality that includes lack or no sexual attraction.
The gender and gender identity is different from the sexual orientation. The combination of certain factors like environment, hormones, biological and emotional are responsible for sexual orientation. Most of the individuals are aware about their sexual orientation during adolescence.
After crossing true-breeding yellow and green pea plants, Mendel allowed the yellow F1 plants to self. As a result of this F1 self-cross, he observed 5920 yellow peas and 2103 green pea plants. Determine whether or not these data are consistent with his law of equal segregation.
Answer:
The data are not consistent with law of equal segregation.
Explanation:
According to law of segregation, the ratio of yellow peas to green peas at F2 should be 3:1.
yellow green
Observed frequencies 5920 2103
Expected frequency [tex]\frac{3}{4}*8023[/tex] = 6017.25 [tex]\frac{1}{4} * 8023[/tex] = 2005.75
Using Chi square([tex]X^2[/tex]):
[tex]X^2[/tex] yellow = [tex]\frac{(observed frequency - expected frequency)^2}{expected frequency}[/tex]
= [tex]\frac{(5920 - 6017.25)^2}{6017.25}[/tex]
= 1.57
[tex]X^2[/tex] green = [tex]\frac{(2103 - 2005.75 )^2}{2005.75 }[/tex]
= 4.72
[tex]X^2[/tex] total = 1.57 + 4.72 = 6.29
Degree of freedom = 2 - 1 = 1
[tex]X^2[/tex] tabulated (α = 0.05) = 3.841
The calculated Chi square value is more than the tabulated Chi square value, hence, the conclusion is that the data are not consistent with law of segregation.
Title II of the Sarbanes-Oxley Act prohibits registered public accounting firms from providing certain nonaudit services. These services include all of the following except:
Answer:
A.
tax preparation services.
Assuming chimps and gorillas are humans' closest relatives, removing humans from the great ape clade and placing them in a different clade has the effect of making the phylogenetic tree of the great apes _______.
A) polyphyletic
B) into a new order
C) monophyletic
D) paraphyletic
Answer:
c
Explanation:
Cytoplasm A) A process in which electrons are transferred from one compound to another with a release of energy occurring in the production of ATP A Electron transport chain B) An organic molecule that occurs as an intermediate in many metabolic processes C Fermentation C) The chemical breakdown of a substance B Pyruvate D) The gel-like material within a living cell
Answer:
D) The gel-like material within a living cell
Answer:D) The gel-like material within a living cell
Explanation: Cytoplasm are materials within the cell erxcept the nucleus. Its a gel like material and also known as cytosol. It is made up of water,enzymes,salt etc.
The passage of nutrients and other substances into the walls of the gastrointestinal tract and then into the bloodstream is called _________.a. digestion.b. molecular.c. function.d. absorption.e. metabolism.
Answer:
d. absorption
Explanation:
all the process is an act of absorbing
A 60-year-old man complains of chest pain. He is conscious and alert and denies shortness of breath. Which of the following questions would be the MOST appropriate to ask him?
Answer: "Do you have any heart problems or take any medications?"
Explanation:
The most suitable question to ask a 60-year-old man with chest pain is whether he was exerting himself when the pain began, as this helps discern if the pain is angina related to physical activity, a common symptom of coronary heart disease. Option A is correct.
When assessing a 60-year-old man complaining of chest pain who is conscious, alert, and denies shortness of breath, the most appropriate question to ask would be "Were you exerting yourself when the chest pain began?" This question helps determine if the chest pain, described as angina, is related to physical activity, which is a typical characteristic of ischemic chest pain due to coronary artery disease.
It's essential to identify if the pain is stable angina, which usually occurs with exertion and is relieved by rest, or whether it indicates a more emergent condition such as an acute myocardial infarction. Additional critical questions would involve inquiring about pain radiation to the arms, as angina pain can often spread to the arms, neck, jaw, back, or feel like indigestion. Given that any chest pain could potentially be a sign of a serious condition, thorough and immediate assessment by a medical professional is crucial.
Hence, A. is the correct option.
The complete question is:
A 60-year-old man complains of chest pain. He is conscious and alert and denies shortness of breath. Which of the following questions would be the MOST appropriate to ask him?
Select one:
A "Were you exerting yourself when the chest pain began?"
B "Do you have any heart problems or take any medications?"
C "Does the pain in your chest feel like a stabbing sensation?"
D "Does the pain in your chest move to either of your arms?"
All of the following are correct about the typical American diet except that it is _________.a. low in calcium. b. low in vitamin D. c. high in sodium. d. high in fiber.
Answer:
a
Explanation:
Final answer:
The typical American diet is high in sodium and low in fiber, vitamin D, and calcium, and lacks an emphasis on nutrient-dense foods. It is not high in fiber, contrary to one of the options provided.
Explanation:
The typical American diet is often criticized for its nutritional imbalances. Among the concerns is that the diet is generally high in sodium and low in essential nutrients such as dietary fiber, vitamin D, and calcium. Moreover, the diet tends to be heavy in calories from solid fats, added sugars, and refined grains, which can displace more nutrient-dense food options. In contrast, a healthier eating pattern would emphasize the consumption of vegetables, fruits, whole grains, and dairy products that are fortified or in their low-fat or fat-free forms to provide these essential nutrients while controlling calorie and sodium intake.
The correct answer to the question is that the typical American diet is not high in fiber; it is actually low in fiber. Over the decades, Americans have increased their consumption of foods high in sugar, which are low in fiber, thereby affecting overall health and nutrition adversely.
Skin color is controlled by three pairs of alleles. Someone with very light skin has 6 recessive alleles while someone with very dark skin has 6 dominant alleles. A person who has a skin color midway between lightest and darkest ________.
Answer:
Has three dominant alleles
Explanation:
Skin colour is a polygenetic inheritance and it is controlled by three genes pairs of alleles. The human skin is determined by the amount of melanin it contains. A combination of melanin producing alleles determines the skin color.
In the above question, the person has a skin color that is midway meaning only half of the alleles produced melanin. The total number of alleles is 6 and half of it is 3. So, only 3 alleles were dominant and the remaining three were recessive.
Answer:
The graph demonstrates the quantitative variation for skin pigmentation.
A bar graph has skin pigmentation color on the horizontal axis and Proportion of population on the vertical axis. From lightest to darkest skin colors, the proportions are: 1/64, 6/64, 15/64, 20/64, 15/64, 6/64, 1/64.
Which conclusion is supported by the graph?
More than half of the population has the central skin pigmentation.
The lightest and the darkest skin pigmentations are equally common in the population. **
The central skin pigmentation makes up more of the population than the rest of the skin pigmentation groups combined.
Fewer people have skin pigmentation lighter than the central peak than people who have pigmentation darker than the central peak.
Explanation:
The _____________ muscle is responsible for lowering and raising the testicles in order to keep them at the right temperature for producing sperm.
Answer:
Dartos muscle.
Explanation:
The dartos muscle is responsible for the contraction and relaxation of the scrotum, adjusting the distance of the testicles from the body to maintain the ideal temperature for sperm production.
Explanation:The muscle responsible for lowering and raising the testicles to regulate temperature for optimal sperm production is the dartos muscle. Sperm are produced in a temperature-regulated process that works best when the scrotal temperature is around 2 to 4°C cooler than the core body temperature. The dartos muscle, along with the cremaster muscle, contracts when cold to pull the testicles closer to the body, warming them, and relaxes when warm to allow the testicles to hang farther from the body, cooling them. This action is essential for maintaining the right temperature, which is on average 91 degrees Fahrenheit, as opposed to the normal core body temperature of most males, which averages at about 98 degrees.
Together, these muscles can elevate the testes in cold weather, moving them closer to the body and decreasing the surface area of the scrotum to retain heat. Alternatively, as the environmental temperature increases, the scrotum relaxes, moving the testes farther from the body core and increasing scrotal surface area, which promotes heat loss.
Only one component bone of the right coxal bone articulates with this same bone component on the other side of the body. Which of the following bone components fits this description?a) pubis.b) ischium.c) ilium.
Answer:
The correct answer is - option a.
Explanation:
Pubis or the pubic bone is one component bone of the right and left coxal bone articulate together. This bone makes the pelvis, in the female uretheral sponge covers the pubic bone from front.
The pubic bone is also makes the inferior and anterior obturator foramen. The pelvic bones are joint together to pubic symphyasis.
Thus, the correct answer is - option a.
The pubis bone component of the right coxal bone articulates with its counterpart on the other side of the body at the pubic symphysis.
Explanation:The bone component that fits the description of articulating with the same bone component on the other side of the body is the pubis. The pubis is one of the three components of the coxal bone, also known as the hip bone. It forms the anterior part of the coxal bone and articulates with its counterpart on the other side at the pubic symphysis.
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When a line cook in a restaurant cooks uses raw meat to cook a hamburger that becomes part of the restaurant's Super Burger Special (available only on Saturday nights during football season), the cook is taking part in a
A) transformation process.
B) turning point.
C) conversion process.
D) therblig.
E) metamorphosis.
A
Answer:
The answer is A) transformation process
Explanation:
Transformation Process:
In management, a transformation process is any measure that takes a particular input, transforms it and adds value to it for clients and customers. Transformation processes can be applied to all, commodities, customers and information.
In this particular case, the chef has taken a raw material i.e. the meat, transformed it into a hamburger and added value to it by adding the bun, vegetables, cheese etc.
The DNA content of a diploid cell in the G1 phase of the cell cycle is measured. If the DNA content is x, then the DNA content at metaphase of meiosis II would be:
Answer:
2x
Explanation:
The G1 phase is a part of the interphase stage of the cell cycle, where the cell undergoes resting and preparation prior to division. Before division can occur, the cell needs to replicate its genetic material (DNA). The cell does this at the S-PHASE, after the First Gap or G1 phase.
The cell duplicates its DNA in order to ensure that each daughter cell receives equal and correct number of chromosomes (DNA). Hence, if the measured DNA at G1 phase was (x), it replicates/doubles I.e x+x or x × 2 = 2x.
Therefore, at the Metaphase phase (division), the DNA content will be 2x before they separate in the anaphase stage.
If the DNA content of a diploid cell is x in the G1 phase, by metaphase of meiosis II the DNA content would be x/2, since meiosis reduces the chromosome number by half to the haploid state.
The question posed relates to the changes in DNA content throughout the cell cycle, particularly from the G1 phase of interphase to metaphase of meiosis II. In the G1 phase, a diploid cell has a DNA content represented by x or 2c, which stands for two sets of chromosomes (2n). When a cell undergoes meiosis, it starts with a doubled DNA content (4c after S phase), but through meiosis I and meiosis II, the DNA content and number of chromosomes are halved. By metaphase of meiosis II, the cell has completed meiosis I and has halved its chromosome number already to 2c (1n, where n represents the number of complete sets of chromosomes).
Therefore, if the DNA content is x (2c) in the G1 phase, at metaphase of meiosis II, the DNA content would be x/2 (the haploid content or 1c), since meiosis reduces the chromosome number by half.
The type of bond that forms to join monomers (such as sugars and amino acids) into polymers (such as starch and proteins) is a(n) __________ bond.
Answer:
Covalent
Explanation:
Covalent bonds are the ones that are formed by the sharing of electrons between the bonded atoms. Polysaccharides are the carbohydrates that have simple sugars bonded together by covalent bonds. Glycosidic linkage joins glucose residues of the starch together. Similarly, peptide bonds join the amino acids together to form proteins. Glycosidic bonds and peptide bonds are formed by sharing of electrons and are covalent bonds.
Monomers such as sugars and amino acids form polymers such as starch and proteins through covalent bonds. In specific terms, sugar monomers are joined via glycosidic bonds and amino acids are joined by peptide bonds - both are types of covalent bonds.
Explanation:The type of bond that forms to join monomers (such as sugars and amino acids) into polymers (such as starch and proteins) is a covalent bond
These covalent bonds form when two atoms share one or more pairs of electrons. In the case of forming complex carbohydrates like starch - mono-saccharides (sugar monomers) are joined together via glycosidic bonds - a type of covalent bond. Similarly, amino acids, the monomers of proteins, are joined by peptide bonds, which are also a specialized type of covalent bond.
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As a part of his workout regimen, a 21-year-old college football player often engages in squats and lateral arm holds. These are examples of what type of exercise?
a) aerobicb) isotonicc) anaerobicd) isometric
Answer:
The correct answer is- isometric exercise
Explanation:
Isometric exercise also called static strength training which requires contraction of a particular muscle group. In isometric exercise, the joints do not move and the length of the muscle does not change noticeably.
Squat and lateral arm hold are the example of isometric exercise. Isometric exercise improves the strength of a particular muscle or group muscle for example squat helps in building leg muscles.
Therefore if a girl is engaged in squats and lateral arm holds then it is an example of isometric exercise.
Final answer:
The college football player's workout regimen, including squats and lateral arm holds, consists of c) anaerobic and d) isometric exercises designed to increase muscle strength, mass, and endurance, without a significant change in muscle length during the isometric holds.
Explanation:
The college football player engaging in squats and lateral arm holds is primarily performing anaerobic and isometric exercises. Squats entail lifting and lowering the body's weight, which is a form of anaerobic exercise that includes periods of physical exertion and high-intensity, strength-training activities. Meanwhile, lateral arm holds involve maintaining an arm position against resistance without movement, which is an isometric exercise where the muscle tension remains constant despite no change in muscle length.
A single-celled organism isolated from a deep-sea, hot thermal vent was found to have a cell wall but lacked a nucleus. This organism is most likely a member of which of the following domains?
Answer:
Archaea
Explanation:
Three main domains exist according to classification, two of these domains are characterized to contain organisms that do not have a membrane bound nucleus, in other words, their single circular genetic material (DNA) is not housed by a nucleus. Instead, the naked DNA is found localized to a central region in the cytoplasm called NUCLEOID. These domains are bacteria and archaea domains and they are termed to be PROKARYOTIC.
These domains also lack membrane bound organnelles i.e their few present organnelles are not bounded by lipid layer. Archaea and Bacteria both have cell walls but what makes up the cell wall is different in both organisms. The organism will most likely be an archaea because it portrays its characteristics being that, an archaea is a unicellular prokaryotic organism with a cell wall. It also has the ability to thrive in extremely harsh conditions like the hot thermal vent described in the question.
The single-celled organism described is most likely a member of the Archaea domain due to its lack of a nucleus and the presence of a cell wall. Archaeans are known to thrive in extreme environments.
Explanation:The single-celled organism you described, that has been isolated from a hot thermal vent in the deep sea and possesses a cell wall but lacks a nucleus, is most likely a member of the Archaea domain. The major characteristics of the Archaea include a lack of nucleus or other membrane-bound organelles, presence of unique lipids in their cell membrane, a distinctive cell wall, and their ability to thrive in extreme conditions, like high temperatures.
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Which of the following describes osmosis?
a. Oxygen transfers into red blood cells through small gaps in the cell membrane from the oxygen- rich environment surrounding the cells
b. Large molecules are brought into the cell by wrapping the cell membrane around the molecules to form a vacuole.
c. Water moves across the cell membrane from the side with high osmotic pressure towards the side with low osmotic pressure.
d. Membrane proteins provide a pathway for larger particles to move across the cell membrane and bring the cell and environment closer to equilibrium.
Answer:
The correct option is C.
Explanation:
Osmosis is a good example of passive transport. In this transport across the cell membrane without any input of cellular energy movement of atomic substance occurs.
Osmosis is defined as the movement of water across the selectively permeable cell membrane from the high osmotic pressure potential towards the area of low osmotic pressure potential. Some examples of osmosis are skin soaking up water, plants receiving water, and when exposed to freshwater red blood cells swelling up.
Osmosis, described in option 'c', is the movement of water from a high to a low concentration through a semi-permeable cell membrane. It aims at achieving a equilibrium state, and is present in various biological processes like water absorption in plant cells.
Explanation:The process that best describes osmosis is option 'c'. Osmosis is the movement of water across a semi-permeable cell membrane from an area of high water concentration (or high osmotic pressure) to an area of low water concentration (or low osmotic pressure). This natural process aims to achieve a state of equilibrium, where the water concentration is the same on both sides of the membrane.
To provide an example, plant cells use osmosis to absorb water from the soil. Inside the cell is a solution with various solutes. Compared to the surrounding soil, this solution has lower water concentration or higher osmotic pressure. Therefore, water from the soil enters the plant cell via osmosis, moving from an area of high water concentration to low water concentration.
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Repeated use of a drug or alcohol to the point of periodic or chronic intoxication that is detrimental to the user or society is called ________.
Answer: Drug abuse
Explanation:
Repeated use of a drug or alcohol to the point of periodic or chronic intoxication that is detrimental to the user or society is called drug abuse or substance abuse.
Substance abuse or drug misuse, is use of a drug or substances in overdose amounts that for the purpose of intoxication or mood alteration. Most drugs abused have properties that are sedative, stimulants among many other properties.
Drug misuse have detrimental and adverse effects on both the individual and the society at large
At a conference, the speaker's grand finale was sautéing mealworms (insect larvae) in butter and serving them to the audience. They were crunchy (like popcorn hulls) because their exoskeletons contain the polysaccharide ______________
1.linoleic acid
2.cellulose
3.chitin
4.collagen
5.glycogen
Answer:
3) Chitin
Explanation:
Most insectcs are arthropods which are covered with a hard exoskeleton that helps in their movement and also provide protection to soft tissue. This exoskeleton is made up of protein (sclerotin) and polysaccharide called chitin. Chitin is also found in cell wall of fungi.
Chitin is most abundandant aminopolysaccharide in nature and second most abundant carbohydrate on earth. Chemicaly chitin is known as poly (β-(1-4)-N-acetyl-D-glucosamine. Chitin is flexible, transparent and, as u tasted, crunchy subatance.
Hoping this might help!!!