Divide 6,723 ÷ 8.

What is the remainder?

Answer: A. 45 miles per hour

B. 135 miles

Step-by-step explanation:

Given: The distance traveled by a car at a constant rate is proportional to the time spent driving.

In the equation [tex]d=45t[/tex], d represents the distance (in miles) and t represents the time (in hours).

[tex]\Rightarrow\frac{d}{t}=45\text{ miles per hour}[/tex]

⇒ The constant of proportionality=45 miles per hour.

Also, the distance traveled by car in 1 hour=45 miles

⇒ The distance traveled by car in 3 hours=[tex]3\times45=135\text{ miles}[/tex]

∴ A car will travel 135 hours in 3 hours.

Answer:

Yes, we have to regroup. Why because of place value chart, we have to regroup.

Step-by-step explanation:

When we add, we have to add the numbers according to the place value chart.

Tens     ones

4            3

2             8

-----------------

 7            1

When we add ones place, we get 3 + 8 = 11, it is a two digits number, so place ones place (1) and carry over the tens (1) to the tens place.

Already, we have 4 and 2 in the tens place, another 1 tens adds to tens place.

4 + 2 + 1 = 7

Hope this will helpful.

Thank you.

Mr. Evans can ship approximately 70 freezers in the container.

To determine how many freezers can be shipped in the container, we first need to calculate the total weight of the ovens and then subtract it from the maximum weight the container can hold.

Given:

- Maximum weight the container can hold = 42,000 pounds

- Number of ovens = 90

- Weight of each freezer = 600 pounds

First, we need to calculate the total weight of the ovens:

Total weight of ovens = Number of ovens × Weight of each oven

Total weight of ovens = 90 ovens × 0 pounds = 0 pounds

Now, we subtract the total weight of the ovens from the maximum weight the container can hold to find the remaining weight for the freezers:

Remaining weight for freezers = Maximum weight of container - Total weight of ovens

Remaining weight for freezers = 42,000 pounds - 0 pounds

Remaining weight for freezers = 42,000 pounds

Now, we need to find out how many freezers can be shipped in the container. Since each freezer weighs 600 pounds, we divide the remaining weight for freezers by the weight of each freezer:

Number of freezers = Remaining weight for freezers / Weight of each freezer

Number of freezers = 42,000 pounds / 600 pounds

Number of freezers ≈ 70

So, Mr. Evans can ship approximately 70 freezers in the container.

To find the width of the park, divide the area (25 / 54 square miles) by the length (5 / 9 miles), resulting in a width of

5 / 6 miles.

The question asks to find the width in miles of a rectangular city park whose area is 25 / 54 square miles and whose length is 5 / 9 miles. To find the width, we can divide the area by the length:

Width = Area / Length

Width = (25 / 54) [tex]\div[/tex] (5 / 9)

To divide fractions, we multiply by the reciprocal of the divisor:

Width = (25 / 54) X (9 / 5)

Width = (25 X 9) [tex]\div[/tex] (54 X 5)

Width = (225) [tex]\div[/tex] (270)

Then we reduce the fraction by dividing both the numerator and the denominator by their greatest common divisor, which is 45:

Width = (225 / 45) [tex]\div[/tex] (270 / 45)

Width = 5 / 6

Therefore, the width of the park is 5/6 miles.

Answer:

c)9x11=99

Step-by-step explanation:

The answer is B. Hope this helped

Answer:

13/20

Step-by-step explanation:

1

4

+

2

5

=  

1 × 5

4 × 5

+

2 × 4

5 × 4

=  

5

20

+

8

20

=  

5 + 8

20

=  

13

20

hope this helps

The number of partial products in multiplication is determined by the number of digits in the multiplier.

In multiplication, the number of partial products is determined by the number of digits in the multiplier. In part a, there are three digits in the multiplier, so there are three partial products. Each partial product represents the product of a digit in the multiplier and the multiplicand. In part b, there are only two digits in the multiplier, so there are only two partial products.

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⁷/₁₀ kg

Given:

Question:

How many kilograms of cherries did they buy altogether?

The Process:

Since Linda bought [tex]\frac{1}{10} \ kg[/tex] of cherries less than Tiffany, we subtract [tex]\frac{1}{10} \ kg[/tex] from the [tex]\frac{2}{5} \ kg[/tex] of cherries Tiffany bought.

The least common multiple (LCM) of 5 and 10 is 10.

[tex]\boxed{ \ \frac{2}{5} - \frac{1}{10} = ? \ }[/tex]

[tex]\boxed{ \ = \bigg( \frac{2 \times 2}{5 \times 2} \bigg) - \frac{1}{10} \ }[/tex]

[tex]\boxed{ \ = \bigg( \frac{4}{10} \bigg) - \frac{1}{10} \ }[/tex]

[tex]\boxed{ \ = \bigg( \frac{3}{10} \ }[/tex]

Therefore, Linda bought [tex]\frac{3}{10} \ kg[/tex] of cherries.

Let us find out how many kilograms of cherries did they buy altogether.

[tex]\boxed{ \ Tiffany's cherries + Linda's cherries =? \ }[/tex]

[tex]\boxed{ \ \frac{2}{5} + \frac{3}{10} = ? \ }[/tex]

[tex]\boxed{ \ = \bigg( \frac{2 \times 2}{5 \times 2} \bigg) + \frac{3}{10} \ }[/tex]

[tex]\boxed{ \ = \bigg( \frac{4}{10} \bigg) + \frac{3}{10} \ }[/tex]

[tex]\boxed{\boxed{ \ = \bigg( \frac{7}{10} \ }}[/tex]

Thus, they bought [tex]\frac{7}{10} \ kg[/tex] of cherries altogether.

- - - - - - - - -

Using Diagram

[tex]\boxed{Tiffany's cherries: \frac{2}{5} = \frac{4}{10}}[/tex]

[tex]Tiffany's cherries: \boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}[/tex] or 4 of 10 units.

[tex]\boxed{Linda's cherries = \frac{1}{10}}[/tex] less than Tiffany's, so we subtract 1 from 4 units of Tiffany's, that is [tex]\boxed{\circ}\boxed{\circ}\boxed{\circ}[/tex]

[tex]\boxed{ \ Tiffany's cherries + Linda's cherries =? \ }[/tex]

[tex]\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ} + \boxed{\circ}\boxed{\circ}\boxed{\circ} = \boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}[/tex]

Thus, the number of the two diagrams is 7 out of 10 units or [tex]\frac{7}{10} \ kg[/tex] of cherries.

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