Separate a mixture of sand, salt, and iron filings by first using a magnet to remove the iron filings. Then, add water to dissolve the salt, and decant the salty water, leaving the sand behind. Finally, allow the water to evaporate to retrieve the salt.
Explanation:To separate a mixture of sand, salt, and iron filings, you would first use a magnet to remove the iron filings from the mixture. This is possible because iron is a magnetic material and will be attracted to the magnet, which allows it to be separated from the non-magnetic substances (sand and salt).
Run a magnet over the mixture. Hold the magnet close but not directly in the substance, to attract only the iron filings.Next, to separate the sand and salt, add water to the mixture. Salt is soluble in water, which means it will dissolve in the water, but the sand will not.Stir the mixture to allow the salt to dissolve completely. Allow it to sit for a period to let the sand settle at the bottom.Then, decant (pour off) the salty water into another container, being careful to leave the sand behind.Finally, to retrieve the salt from the water, you can simply allow the water to evaporate, leaving the salt behind.Learn more about Separate mixture here:https://brainly.com/question/35865688
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How many moles of ammonium nitrate are necessary to form 0.692 moles water?
The ka value for acetic acid, ch3cooh(aq), is 1.8× 10–5. calculate the ph of a 1.60 m acetic acid solution.
To calculate the pH of a 1.60 M acetic acid solution, use the ionization constant (Ka) of acetic acid, set up an ICE table, and solve for x to find the concentration of the hydronium ion (H3O+). Then, calculate the pH using the equation pH = -log[H3O+]. The pH of the acetic acid solution is approximately 1.5873.
Explanation:To calculate the pH of a 1.60 M acetic acid solution, we can use the ionization constant (Ka) of acetic acid and the relationship between the concentration of the acid, its conjugate base, and the pH. The Ka value for acetic acid is 1.8×10-5. Since acetic acid is a weak acid, we can assume that the concentration of the hydronium ion (H3O+) is equal to the concentration of the acid that has ionized.
Using the equation Ka = [H3O+][C2H3O2]/[HC2H3O2], we can set up an ICE table to calculate the concentration of the hydronium ion:
Initial concentration: [H3O+] = unknown, [C2H3O2] = 0, [HC2H3O2] = 1.60 MChange in concentration: [H3O+] = -x, [C2H3O2] = x, [HC2H3O2] = -xEquilibrium concentration: [H3O+] = 1.60 - x, [C2H3O2] = x, [HC2H3O2] = 1.60 - xSubstituting these values into the Ka expression, we get 1.8×10-5 = (1.60 - x)(x)/(1.60 - x). Solving for x gives us x ≈ 0.0127 M. Since [H3O+] = 1.60 - x, the pH of the solution is approximately 1.60 - 0.0127 = 1.5873.
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The pH of a 1.60 M acetic acid solution can be calculated using the equilibrium constant expression and initial concentration. The pH is equal to -log[H3O+]. The pH of this particular solution is 2.37.
Explanation:The pH of a 1.60 M acetic acid solution can be calculated using the equation:
pH = -log[H3O+]
First, we need to find the concentration of the hydronium ion, [H3O+]. To do this, we use the equilibrium constant expression for acetic acid, which is Ka = [H3O+][CH3CO2-] / [CH3COOH]. With a given Ka value of 1.8 × 10-5 and a concentration of acetic acid of 1.60 M, we can plug in these values to find the concentration of [H3O+], which is then used to calculate the pH.
Therefore, the pH of a 1.60 M acetic acid solution is 2.37.
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Explain how the law of conservation of mass necessitates our balancing all chemical equations.
How much water should be added to 30 l of a 40 acid solution to reduce it to a 30 solution?
To solve this we use the equation,
M1V1 = M2V2
where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.
M1V1 = M2V2
40% x 30 L = 30% x V2
V2 = 40 L
Therefore, you will need to have 30 mL of the 40% acid solution and 10 mL of distilled water. In mixing the two liquids, you should remember that the order of mixing would be acid to water. So, you use a 40 mL volumetric flask . Put small amount of distilled water and add the 30 mL of HCl solution. Lastly, dilute with distilled water up to the mark.
How many oxygen atoms are there in 7.00 g of sodium dichromate, na2cr2o7?
[tex]\boxed{1.1255 \times {{10}^{23}}{\text{ atoms}}}[/tex] of oxygen are present in 7.00 g of sodium dichromate.
Further Explanation:
Given information:
Mass of sodium dichromate: 7.00 g
To calculate:
Number of oxygen atoms in 7.00 g of sodium dichromate
Steps to proceed:
I. First of all, moles of sodium dichromate that are present in 7.00 g of sodium dichromate are to be calculated. This is done with the help of equation (1) as mentioned below.
The formula to calculate moles of sodium dichromate [tex]\left( {{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{r}}_{\text{2}}}{{\text{O}}_{\text{7}}}} \right)[/tex] is as follows:
[tex]{\text{Moles of N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{r}}_{\text{2}}}{{\text{O}}_{\text{7}}} = \dfrac{{{\text{Mass of N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{r}}_{\text{2}}}{{\text{O}}_{\text{7}}}}}{{{\text{Molar mass of N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{r}}_{\text{2}}}{{\text{O}}_{\text{7}}}}}[/tex] …… (1)
The mass of [tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{r}}_{\text{2}}}{{\text{O}}_{\text{7}}}[/tex] is 7.00 g.
The molar mass of [tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{r}}_{\text{2}}}{{\text{O}}_{\text{7}}}[/tex] is 261.97 g/mol.
Substitute these values in equation (1).
[tex]\begin{aligned}{\text{Moles of N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{r}}_{\text{2}}}{{\text{O}}_{\text{7}}} &= \frac{{{\text{7}}{\text{.00 g}}}}{{{\text{261}}{\text{.97 g/mol}}}} \\ &= 0.0267{\text{ mol}} \\ \end{aligned}[/tex]
II.Moles of oxygen that are present in 0.267 moles of sodium dichromate are to be calculated.
According to the chemical formula of sodium dichromate, it is evident that one mole of sodium dichromate contains two moles of sodium, two moles of chromium and seven moles of oxygen in it. Since one mole of sodium dichromate consists of seven moles of oxygen, moles of oxygen present in 0.267 moles of sodium dichromate can be calculated as follows:
[tex]\begin{aligned}{\text{Moles of oxygen}} &= \left( {0.0267{\text{ mol N}}{{\text{a}}_2}{\text{C}}{{\text{r}}_4}{{\text{O}}_7}} \right)\left( {\frac{{7{\text{ mol O}}}}{{{\text{1 mol N}}{{\text{a}}_2}{\text{C}}{{\text{r}}_4}{{\text{O}}_7}}}} \right) \\&= 0.1869{\text{ mol O}} \\\end{aligned}[/tex]
III. Number of oxygen atoms that are present in 0.1869 moles of oxygen is to be calculated. This is done with the help of Avogadro’s law which states that one mole of a substance contains [tex]6.022 \times {10^{23}}{\text{ particles}}[/tex] . Such particles can be atoms, molecules, or formula units.
Since one mole of oxygen contains [tex]6.022 \times {10^{23}}{\text{ atoms}}[/tex], atoms of oxygen present in 0.1869 moles of oxygen can be evaluated as follows:
[tex]\begin{aligned}{\text{Number of oxygen atoms}} &= \left( {0.1869{\text{ mol}}} \right)\left( {\frac{{6.022 \times {{10}^{23}}{\text{ atoms}}}}{{{\text{1 mol}}}}} \right) \\&= 1.1255 \times {10^{23}}{\text{ atoms}} \\\end{aligned}[/tex]
Hence, [tex]1.1255 \times {10^{23}}{\text{ atoms}}[/tex] of oxygen are present in 7.00 g of sodium dichromate.
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How many moles of Cl are present in 8 moles of [tex]{\text{CC}}{{\text{l}}_4}[/tex]? https://brainly.com/question/3064603 Calculate the moles of ions in HCl solution: https://brainly.com/question/5950133
Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Mole concept
Keywords: sodium dichromate, oxygen, mass, molar mass, 7.00 g, 1.1255*10^23 atoms, Avogadro’s law, one mole, atoms, molecules, particles.
What is the approximate molar mass of a molecular solute if 300 g of the solute in 1000 g of water causes the solution to have a boiling point of 101°C? (Kb = 0.512°C/m; Kf = 1.86°C/m; molar mass of water = 18 g)
Answer: The molar mass of solute is 156 g/mol
Explanation:
Elevation in boiling point is defined as the difference in the boiling point of solution and boiling point of pure solution.
The equation used to calculate elevation in boiling point follows:
[tex]\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of pure solution}[/tex]
[tex]\Delta T_b[/tex] = ? °C
Boiling point of pure water = 100°C
Boiling point of solution = 101°C
Putting values in above equation, we get:
[tex]\Delta T_b=(101-100)^oC=1^oC[/tex]
To calculate the elevation in boiling point, we use the equation:
[tex]\Delta T_b=iK_bm[/tex]
Or,
[tex]\Delta T_b=i\times K_b\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}[/tex]
where,
[tex]\Delta T_b[/tex] = 1°C
i = Vant hoff factor = 1 (For non-electrolytes)
[tex]K_b[/tex] = molal boiling point elevation constant = 0.52°C/m.g
[tex]m_{solute}[/tex] = Given mass of solute = 300 g
[tex]M_{solute}[/tex] = Molar mass of solute = ?
[tex]W_{solvent}[/tex] = Mass of solvent (water) = 1000 g
Putting values in above equation, we get:
[tex]1^oC=1\times 0.52^oC/m\times \frac{300\times 1000}{M_{solute}\times 1000}\\\\M_{solute}=156g/mol[/tex]
Hence, the molar mass of solute is 156 g/mol
A considerable amount of heat is required for the decomposition of aluminum oxide. 2 al2o3(s) â 4 al(s) + 3 o2(g) δh = 3352 kj (a) what is the heat change for the formation of 1 mol of aluminum oxide from its elements?
The heat change for the formation of 1 mol of aluminum oxide from its elements is 1676 kJ.
Explanation:The heat change for the formation of 1 mol of aluminum oxide from its elements can be calculated using the information provided in the question. We know from the given thermochemical equation that the decomposition of 2 mol of aluminum oxide releases 3352 kJ of heat. Therefore, we can set up a proportion to find the heat change for the formation of 1 mol of aluminum oxide:
3352 kJ / 2 mol = x kJ / 1 mol
Solving for x gives us the heat change for the formation of 1 mol of aluminum oxide, which is 1676 kJ.
What would be the volume in liters of an ideal gas, if a 0.425 mole sample of the gas had a temperature of 900 degrees celsius at a pressure of 3.00 atmospheres? (the ideal gas constant is 0.0821 l•atm/mol•k.)?
How many milliliters of calcium, with a density of 1.55 g/mL, are needed to produce 85.8 grams of calcium fluoride in the single replacement reaction below? Show all steps of your calculation as well as the final answer.
Unbalanced equation: Ca + HF yields CaF2 + H2
Answer: 55.35ml
Explanation:
[tex]Ca+2HF\rightarrow CaF_2+H_2[/tex]
To calculate the given moles, we use the formula:
[tex]Moles=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
[tex]Moles=\frac{85.8g}{78g/mol}=1.1moles[/tex]
By stoichiometry of the reaction,
1 mole of [tex]CaF_2[/tex] is produced by 1 mole of Ca
1.1 moles of [tex]CaF_2[/tex] are produced by=[tex]\frac{1}{1}\times 1.1=1.1 moles[/tex] of Ca.
Mass of [tex]CaF_2=\text{no of moles}\times \text{Molar mass}[/tex]
Mass of [tex]CaF_2=1.1\times {78}=85.8g[/tex]
[tex]Volume=\frac{Mass}{Density}[/tex]
[tex]Volume=\frac{85.8g}{1.55g/ml}=55.35ml[/tex]
What is the molar concentration of potassium ions in a 0.250 m k2so4 solution?
Answer : The molar concentration of [tex]K^+[/tex] ion is, 0.5 M
Explanation :
The dissociation reaction of [tex]K_2SO_4[/tex] is,
[tex]K_2SO_4(aq)\rightarrow 2K^+(aq)+SO_4^{2-}(aq)[/tex]
By the stoichiometry we can say that, 1 mole of [tex]K_2SO_4[/tex] dissociates into 2 mole of [tex]K^+[/tex] ions and 1 mole of [tex]SO_4^{2-}[/tex] ions.
As we are given the concentration of [tex]K_2SO_4[/tex] is, 0.250 M.
So, the molar concentration of [tex]K^+[/tex] ion = [tex]2\times 0.250=0.5M[/tex]
The molar concentration of [tex]SO_4^{2-}[/tex] ion = 0.250 M
Therefore, the molar concentration of [tex]K^+[/tex] ion is, 0.5 M
Which is the correct formula for the compound made when aqueous solutions containing a dissolved magnesium compound and a dissolved chloride compound are mixed?
Answer:
The correct formula for the compound made when aqueous solutions containing a dissolved Magnesium and Chloride are mixed is Magnesium chloride [tex]MgCl_2[/tex]
Explanation:
If we suppose the existence of two components in aqueous solutions containing Magnesium and Chloride. For example: Hydrochloric acid - HCl and Magnesium hydroxide - [tex]Mg(OH)_2[/tex].
The global reaction would be:
HCl + [tex]Mg(OH)_2[/tex] --> [tex]MgCl_2[/tex] + [tex]H_2 O[/tex]
It means, Hydrochloric acid is neutralized with Magnesium hydroxide to produce Magnesium chloride and Water.
Besides of that, we can analyze the aqueos solution of every componenent:
For Hydrochloric acid:
HCl + [tex]H_2 O[/tex] --> [tex]H_3O^+[/tex] + [tex]Cl^-[/tex]
For Magnesium hydroxide
[tex]Mg(OH)_2[/tex] + [tex]H_2 O[/tex] --> [tex]H_2O-(OH)^-[/tex] + [tex]Mg^+2[/tex]
Finally, the ionic compounds will form the salt:
[tex]Mg^+2[/tex] + [tex]Cl^-[/tex] -> [tex]MgCl_2[/tex]
A sample of cacl2⋅2h2o/k2c2o4⋅h2o solid salt mixture is dissolved in ~150 ml de-ionized h2o. the oven dried precipitate has a mass of 0.333 g. the limiting reactant in the salt mixture is k2c2o4⋅h2o. cacl2⋅2h2o(aq) + k2c2o4⋅h2o(aq) à cac2o4⋅h2o(s) + 2kcl(aq) + 2h2o(l) starting material (sm) product molar mass (mm) g/mol: cacl2⋅2h2o = 147.02 k2c2o4⋅h2o = 184.24 cac2o4 = 128.10 determine mass of k2c2o4⋅h2o(aq) in salt mixture in grams. answer to 3 places after the decimal and include unit, g
Answer: The mass of [tex]K_2C_2O_4.H_2O[/tex] in the salt mixture is 0.424 grams.
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] .....(1)
For [tex]CaC_2O_4.H_2O[/tex] :Given mass of [tex]CaC_2O_4.H_2O[/tex] = 0.333 g
Molar mass of [tex]CaC_2O_4.H_2O[/tex] = 146.12 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of}CaC_2O_4.H_2O=\frac{0.333g}{146.12g/mol}=0.0023mol[/tex]
The given chemical equation follows:
[tex]CaCl_2.2H_2O(aq.)+K_2C_2O_4.H_2O(aq.)\rightarrow CaC_2O_4.H_2O(s)+2KCl(aq.)+2H_2O(l)[/tex]
By Stoichiometry of the reaction:
1 mole of [tex]CaC_2O_4.H_2O[/tex] is produced by 1 mole of [tex]K_2C_2O_4.H_2O[/tex]
So, 0.0023 moles of [tex]CaC_2O_4.H_2O[/tex] will be produced by = [tex]\frac{1}{1}\times 0.0023=0.0023mol[/tex] of [tex]K_2C_2O_4.H_2O[/tex]
Now, calculating the mass of [tex]K_2C_2O_4.H_2O[/tex] by using equation 1, we get:
Molar mass of [tex]K_2C_2O_4.H_2O[/tex] = 184.24 g/mol
Moles of [tex]K_2C_2O_4.H_2O[/tex] = 0.0023 moles
Putting values in equation 1, we get:
[tex]0.0023mol=\frac{\text{Mass of }K_2C_2O_4.H_2O}{184.24g/mol}\\\\\text{Mass of }K_2C_2O_4.H_2O=(0.0023mol\times 184.24g/mol)=0.424g[/tex]
Hence, the mass of [tex]K_2C_2O_4.H_2O[/tex] in the salt mixture is 0.424 grams.
Final answer:
The mass of K2C2O4·H2O in the salt mixture is calculated using the molar mass and the moles of the precipitate formed in the reaction, resulting in a mass of 0.479 g.
Explanation:
To determine the mass of K2C2O4·H2O in the salt mixture, we start by identifying that the precipitate formed, CaC2O4·H2O, has a molar mass of 128.10 g/mol and a measured mass of 0.333 g. Using this information, the number of moles of CaC2O4·H2O can be calculated as moles = mass / molar mass = 0.333 g / 128.10 g/mol.
This results in 2.60 x 10-3 moles of CaC2O4·H2O. Since the reaction shows that K2C2O4·H2O and CaCl2·2H2O react in a 1:1 mole ratio to form the precipitate, the same number of moles is used for K2C2O4·H2O. The mass of K2C2O4·H2O can be found by multiplying the number of moles by its molar mass (2.60 x 10-3 moles x 184.24 g/mol).
The resulting mass of K2C2O4·H2O in the salt mixture is 0.479 g, to three decimal places.
If the half-life of a radioisotope is 20,000 years, then a sample in which three-quarters of that radioisotope has decayed is ___________ years old
A mixture of pure agcl and pure agbr is found to contain 60.94% ag by mass. what are the mass percents of cl and br in the mixture?
Final answer:
To calculate the mass percentages of Cl and Br in a mixture of AgCl and AgBr with 60.94% Ag by mass, we need additional data to determine the individual masses of Cl and Br. Without it, we cannot provide precise percentages.
Explanation:
The question is about calculating the mass percents of chlorine (Cl) and bromine (Br) in a mixture of silver chloride (AgCl) and silver bromide (AgBr) that contains 60.94% silver (Ag) by mass. The molar mass of silver (Ag) is 107.87 g/mol, for AgCl it is 143.32 g/mol (107.87 g/mol + 35.45 g/mol for Cl), and for AgBr it is 187.77 g/mol (107.87 g/mol + 79.90 g/mol for Br).
To find the mass percentages of Cl and Br in the mixture, we will first assume we have 100 grams of the mixture. Given the percent of silver, we can calculate the mass of silver in the mixture, which should be 60.94 grams. The remaining mass will be the combined mass of Cl and Br. However, without additional information such as the mass or molar ratios of AgCl to AgBr, we cannot precisely divide the remaining mass between Cl and Br. If such data were available, the mass percentages of Cl and Br could be found by calculating their individual masses and dividing by the total mass of the mixture, then multiplying by 100.
What is the balanced equation when aluminum reacts with copper (ii) sulfate in a single displacement reaction?
The balanced equation is :
2Al + 3CuSO4 -> 3Cu + Al2(SO4)3.
What happens in a single displacement reaction?A single-displacement reaction takes place while an element replaces any other element in a compound. A metallic handiest replaces steel, and a nonmetal only replaces a nonmetal. only a greater reactive element can update the opposite element within the compound with which it reacts.
A single substitute response, now and again known as a single displacement response, is a reaction in which one element is substituted for another detail in a compound. The starting materials are continually natural elements, which include pure zinc steel or hydrogen fuel, plus an aqueous compound.
To determine whether or not a given single replacement will occur, you have to use an “activity series” table. If the metal or the halogen is above the detail it will replace based totally on the hobby series, a single displacement response will occur. Examples of displacement reactions are The reaction among iron and copper sulphate to present iron sulphate as a product. here, iron displaces copper due to the fact iron is extra reactive than copper. The response between zinc and iron sulphate to offer zinc sulphate as a product.
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What state of change do atoms or molecules become more ordered?
Earth's climate has been stable throughout its history. True False
For the weak acid ch3cooh (acetic acid) that is titrated with a strong base (naoh), what species (ions/molecules) are present in the solution at the stoichiometric point?
At the stoichiometric point of the titration of acetic acid with a strong base, the species present in the solution are acetate ions (CH3COO-) and water (H2O).
Explanation:During the titration of acetic acid (CH3COOH) with a strong base (NaOH), at the stoichiometric point all of the acetic acid will have reacted with the sodium hydroxide. This means that the species present in the solution at the stoichiometric point are the acetate ions (CH3COO-) and water (H2O). The balanced chemical equation for the reaction is:
CH3COOH(aq) + NaOH(aq) → CH3COONa(aq) + H2O(l)
Given an initial cyclopropane concentration of 0.00560 m, calculate the concentration of cyclopropane that remains after 1.50 hours.
We can solve this problem by assuming that the decay of cyclopropane follows a 1st order rate of reaction. So that the equation for decay follows the expression:
A = Ao e^(- k t)
Where,
A = amount remaining at
time t = unknown (what to solve for)
Ao = amount at time zero = 0.00560
M
k = rate constant
t = time = 1.50 hours or 5400 s
The rate constant should be given in the problem which I think you forgot to include. For the sake of calculation, I will assume a rate constant which I found in other sources:
k = 5.29× 10^–4 s–1 (plug in the correct k value)
Plugging in the values in the 1st equation:
A = 0.00560 M * e^(-5.29 × 10^–4 s–1 * 5400 s )
A = 3.218 × 10^–4 M (simplify as necessary)
To calculate the concentration of cyclopropane that remains after 1.50 hours, we need to use the first-order integrated rate law equation. Without the rate constant, we cannot calculate the exact concentration, but we can determine that it will be less than 0.200 mol/L.
To calculate the concentration of cyclopropane that remains after 1.50 hours, we need to use the first-order integrated rate law. The rate constant for the reaction is not given, so we cannot calculate it. However, we can use the given information that at 10.0 minutes (0.1667 hours) the concentration of cyclopropane is 0.200 mol/L and find the concentration at 1.50 hours using the integrated rate law equation:
[tex][C] = [C]0 * e^(-kt)[/tex]
where [C] is the concentration at time t, [C]0 is the initial concentration, k is the rate constant, and t is the time.
Given [C]0 = 0.200 mol/L, t = 1.50 hours, and [C] = ?
Let's solve the integrated rate law equation:
Plug in the known values:
[tex][C] = 0.200 * e^(-k*1.50)[/tex]
Since the rate constant is not given, we cannot calculate the exact concentration. However, we can still make a general qualitative statement that the concentration will be less than 0.200 mol/L.
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Why doesn't oil dissolve in water? oil molecules are non–polar. oil molecules carry a net negative charge. oil molecules carry a net positive charge?
Sodium hydrogen carbonate nahco3 , also known as sodium bicarbonate or "baking soda", can be used to relieve acid indigestion. acid indigestion is the burning sensation you get in your stomach when it contains too much hydrochloric acid hcl , which the stomach secretes to help digest food. drinking a glass of water containing dissolved nahco3 neutralizes excess hcl through this reaction: hcl (aq) nahco3 (aq) â nacl (aq) h2o (l) co2 (g) the co2 gas produced is what makes you burp after drinking the solution. suppose the fluid in the stomach of a man suffering from indigestion can be considered to be 250.ml of a 0.076 m hcl solution. what mass of nahco3 would he need to ingest to neutralize this much hcl
Answer:
1.596 g
Explanation:
The neutralization reaction is:
NaHCO₃ + HCl → NaCl + H₂O + CO₂
The number of moles of the acid in stomach is the volume (250.0 mL = 0.250 L) multiplied by the molar concentration (0.076 M):
n = 0.250 * 0.076 = 0.019 mol of HCl
By the stoichiometry of the reaction, 1 mol of NaHCO₃ is needed to neutralize 1 mol of HCl, so it'll be necessary 0.019 mol of sodium bicarbonate.
The molar mass of NaHCO₃ is 84 g/mol, thus the mass of it is:
m = number of moles * molar mass
m = 0.019 * 84
m = 1.596 g
The compound ch3 - ch2 - sh is in the organic family known as
The compound CH3-CH2-SH belongs to the organic family known as Thiols. Thiols are structurally similar to alcohols but the oxygen atom in alcohols is replaced by sulfur in thiols. Both thiols and alcohols belong to a larger class called the Hydrocarbon Derivatives.
Explanation:The compound you mentioned, CH3-CH2-SH, falls into the organic family categorized as 'Thiols'. Thiols are similar to alcohols in structure, but they have a sulfur atom rather than an oxygen atom. They are identified by the -SH or sulfhydryl functional group. Like the hydroxyl group in an alcohol, this sulfhydryl group gives a thiol its properties.
For example, the compound CH3-SH, also known as 'Methanethiol', is analogous to the alcohol methanol. Both thiols and alcohols are part of a larger class called the 'Hydrocarbon Derivatives'. As the name suggests, these are derived from hydrocarbons by replacing one or more hydrogen atoms with a functional group, which in this case is either a hydroxyl group (-OH) for alcohols or a sulfhydryl group (-SH) for thiols.
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A solution with a hydrogen ion concentration of 3.25 × 10-2 m is ________ and has a hydroxide concentration of _______
To know the acidity of a solution, we calculate the pH value. The formula for pH is given as:
pH = - log [H+] where H+ must be in Molar
We are given that H+ = 3.25 × 10-2 M
Therefore the pH is:
pH = - log [3.25 × 10-2]
pH = 1.488
Since pH is way below 7, therefore the solution is acidic.
To find for the OH- concentration, we must remember that the product of H+ and OH- is equivalent to 10^-14. Therefore,
[H+]*[OH-] = 10^-14
[OH-] = 10^-14 / [H+]
[OH-] = 10^-14 / 3.25 × 10-2
[OH-] = 3.08 × 10-13 M
Answers:
Acidic
[OH-] = 3.08 × 10-13 M
The hydrogen ion concentration is 3.25 × 10-2 M, indicating an acidic solution with a pH of 1.49. The hydroxide concentration is 3.08 × 10-13 M.
Explanation:In this question, the hydrogen ion concentration is given as 3.25 × 10-2 M. This concentration indicates that the solution is acidic, with a pH value equal to -log[H3O+]. Therefore, pH = -log(3.25 × 10-2) = 1.49.
The hydroxide concentration can be calculated using the formula: [OH-] = Kw/[H3O+]. At 25°C, the value of Kw (the ion-product constant for water) is 1.0 × 10-14. Therefore, [OH-] = 1.0 × 10-14 / 3.25 × 10-2 = 3.08 × 10-13 M.
How many moles of H2O can be formed when 4.5 moles of NH3 react with 3.2 moles of O2?
4NH3 + 5O2 yields 4NO + 6H2O
A)3.8 mol H2O
B) 4.8 mol H2O
C) 6.4 mol H2O
D) 6.8 mol H2O
When dissolved in water, baking soda is basic.the ph of baking soda (sodium bicarbonate) is closest to:?
Final answer:
Baking soda, or sodium bicarbonate, when dissolved in water, has a basic pH close to 9.0, classifying it as a weak base.
Explanation:
When sodium bicarbonate, commonly known as baking soda, is dissolved in water, it exhibits basic properties. The pH of a baking soda solution is closest to 9.0, which means it is a weak base. Water is neutral with a pH of 7.0, whereas a substance with a pH higher than 7.0 is considered alkaline or basic.
The pH scale ranges from 0 to 14, with 7 being neutral. Acids have a pH less than 7, and bases have a pH greater than 7. The pH of a substance is determined by its concentration of hydronium ions. Baking soda has a lower concentration of hydronium ions compared to pure water, thereby making it a base with a pH higher than 7.
In practical applications, baking soda is used to neutralize acids, such as in bee sting treatments or when mixed with acetic acid in vinegar during bread preparation.
1. How many milliliters of a 0.184 M NaNO3 solution contain 0.113 moles of NaNO3?ans:614 mL
Explanation:
The given data is as follows.
Molarity of solution = 0.184 M
Volume of solution = ?
number of moles = 0.113 mol
As molarity is the number of moles present in liter of solvent.
Mathematically, Molarity = [tex]\frac{\text{No. of moles}}{\text{Volume}}[/tex]
Hence, calculate the volume of given solution as follows.
Molarity = [tex]\frac{\text{No. of moles}}{\text{Volume}}[/tex]
0.184 M = [tex]\frac{0.113 mol}{volume}[/tex]
volume = 0.614 L
As 1 L = 1000 mililiter. Hence convert 0.614 L into ml as follows.
[tex]0.614 L \times \frac{1000 ml}{1 L}[/tex]
= 614 ml
Thus, we can conclude that the volume of given solution is 614 ml.
42.5 grams of an unknown substance is heated to 105.0 degrees Celsius and then placed into a calorimeter containing 110.0 grams of water at 24.2 degrees Celsius. If the final temperature reached in the calorimeter is 32.4 degrees Celsius, what is the specific heat of the unknown substance?
Show or explain the work needed to solve this problem, and remember that the specific heat capacity of water is 4.18 J/(°C x g).
Answer:The specific heat of the unknown substance is 1.22 J/ °Cg.
Explanation:
Heat absorbed by the water .
Mass of the water = 110.0 g
Change in temperature of water = [tex]\Delta T=32.4^oC-24.2^oC=8.2^oC[/tex]
[tex]Q=mc\Delta T=110.0g\times 4.18 J/^oCg\times 8.2^oC=3,770.36 J[/tex]
Heat lost by substance(Q') = Heat gained by the water(Q)
-Q' = Q
Change in temperature of the substance =
[tex]\Delta T'=(32.4^oC)-105.0^oC=-72.6 ^oC[/tex]
Mass of the substance = m'=42.5 g
Specific heat of substance = c'
[tex]-(m'\times c'\times \Delta T')=3,770.36 J[/tex]
[tex]c'=\frac{3,770.36 J}{42.5 g\times 72.6^oC}=1.22 J/^oCg[/tex]
The specific heat of the unknown substance is 1.22 J/ °Cg.
Which is the next logical step in balancing the given equation?
CS2(l) + Cl2(g) CCl4(l) + S2Cl2(l)
A.) Place the coefficient 2 in front of sulfur dichloride (S2Cl2).
B.)Place the coefficient 3 in front of the chlorine molecule.
C.)Leave the equation alone as it is already balanced.
D.) Place the coefficient 4 in front of carbon disulfide(CS2).
E.)Place the coefficient 2 in front of carbon tetrachloride(CCl4).
CS2(l) +Cl2(g)→CCl4(l) + S2Cl2 (l)
The next logical step in balancing the equation above is place the coefficient 3 in front of the chlorine molecule ( answer B)
Explanation
When coefficient 3 in placed in front of chlorine molecule the balanced equation is as below
CS2 (l) +3Cl2 (g) → CCl4 (l) + S2Cl2 (l)Which best explains why scientific theories grow stronger over time?
A.) As more scientist attempt to find holes in the current theory adjustments are made which make the theory stronger
B.) More students are taught about the theory and so there are more people who will leave the theory to be true
C.) Scientists believe that older theories are stronger than newer theories
D.) New evidence is ignored if it's contradicts to the older more accepted theories
I need the best answers please!
Scientific theories become stronger over time primarily because scientists continuous attempt to challenge and refine them, which leads to improvements and adjustments that further solidify the theory.
The best explanation for why scientific theories grow stronger over time is option A: 'As more scientist attempt to find holes in the current theory adjustments are made which make the theory stronger.' Scientific theories are rigorously tested and often challenged by researchers who seek to uncover any weaknesses or inconsistencies. When such efforts are made, they can lead to refinements and adjustments that subsequently strengthen the theory. This process may involve incorporating new evidence, reinterpreting existing data, or modifying theoretical frameworks to better explain the phenomenon in question.
Scientific theory is not just an educated guess; it is a comprehensive explanation supported by many research studies that collectively provide falsifiable evidence. Throughout history, theories such as the heliocentric model have been revised and strengthened through this process. It is by this meticulous scrutiny, including the elimination of competing hypotheses and the aggregation of reliable evidence, that a scientific theory matures and gains acceptance.
The statement which best explains why scientific theories grow stronger over time is A.) As more scientists attempt to find holes in the current theory, adjustments are made which make the theory stronger.
Scientific theories are dynamic and grow stronger through a process of rigorous testing, criticism, and refinement. When scientists develop a theory, they propose explanations for phenomena observed in the natural world. These theories are not merely guesses; they are grounded in substantial evidence that has been gathered through experimentation and observation. The process of scientific investigation includes trying to refute or find the limitations of current theories. As researchers explore these theories in different contexts and conditions, they either gather more evidence that supports the theory or uncover discrepancies that prompt modifications. This critical assessment and ongoing peer review contribute to the strength and reliability of scientific theories over time. Each time a theory withstands scrutiny or is adjusted to incorporate new data, it becomes more robust and dependable. Scientific theories are considered strong because they have been tested and falsified repeatedly, not because they are simply old or widely taught. It is the accumulation of evidence and the continuous critical analysis by the scientific community that gradually builds the strength of a theory.
Draw a fatty acid chain that is 8 carbons long and is unsaturated