Determine if the sequence is algebraic or geometric, and find the common difference or ratio.


x 1 2 3 4
f(x) 5 −5 −15 −25

A.Algebraic, common difference = −10
B.Algebraic, common difference = −1
C.Geometric, common ratio = −10
D.Geometric, common ration = −1

Answer:

  C.  f^-1(x) = 1/5x

Step-by-step explanation:

You know that f^-1(f(x)) = x, so you can try the answers.

____

You can also solve for f^-1(x). It will be "y" when ...

  f(y) = x

  5y = x

  y = 1/5x . . . . . divide by 5

Answer:

vertex s is -2,-2

Step-by-step explanation:

and with the rectangle is q to p is 4cm coz one box is 1 cm and r to q is 3cm so you multiply them and the answer is 12cm

We know that, Final Amount in Compound Interest is given by :

[tex]\bigstar\;\;\boxed{\mathsf{Amount = Principal\left(1 + \dfrac{Rate\;of\;interest}{100}\right)^{Number\;of\;Years}}}[/tex]

Given :

●  Principal = $5000

●  Rate of interest = 1.25

●  Number of Years = 10

Substituting the values in the Formula, We get :

[tex]\implies \mathsf{Amount = 5000\left(1 + \dfrac{1.25}{100}\right)^{10}}[/tex]

[tex]\implies \mathsf{Amount = 5000\left(1 + \dfrac{0.25}{20}\right)^{10}}[/tex]

[tex]\implies \mathsf{Amount = 5000\left(1 + \dfrac{0.05}{4}\right)^{10}}[/tex]

[tex]\implies \mathsf{Amount = 5000\left(\dfrac{4.05}{4}\right)^{10}}[/tex]

[tex]\implies \mathsf{Amount = 5000\times (1.0125)^{10}}[/tex]

[tex]\implies \mathsf{Amount = 5661.354}[/tex]

Answer : $5661.354 money will be in the account 10 years later

Answer: $5,661.35

Step-by-step explanation:

I used the exponential growth formula to get my answer.

Answer:

The correct answer is option A.  23 in

Step-by-step explanation:

It us given that, the length of a rectangle is 5 more than 3 times its width. The perimeter of the rectangle is 58 in.

To find the length of rectangle

Let 'x' be the width of rectangle.

Length = 3x + 5

Perimeter of rectangle = 2(length + width)

58 = 2(3x + 5 + x)

58 = 2(4x + 5)

29 = 4x + 5

4x = 29 - 5

4x = 24

x = 24/4 = 6

Therefore length of rectangle = 3x + 5

 = 3*6 + 5 = 23 in

The correct answer is option A.  23 in

Answer:

x=ysq2-2

Step-by-step explanation:

because you get the x alone and subtract the variable

Answer:

Graph A

Step-by-step explanation:

because the function given is y= (x+3)(x+3) the vertex is (-3,0)

Answer:

14 cups

Step-by-step explanation:

3 pizzas needed

1 pizza means 2 cups of flour

So for 3 pizzas he will need 6 cups of flour

If he has 20 cups of flour and he uses 6, how much is left?

20-6=14

Answer:

14 cups of flour

Step-by-step explanation:

The three pizzas will require 6 cups of flour.

3 x 2 = 6 cups of flour needed to make 3 pizzas.

20 - 6 = 14 cups left

Answer:

10y

Step-by-step explanation:

9y + y = 10y

Answer:

[tex]10y[/tex]

Step-by-step explanation:

[tex]9y + y = y(9 + 1) = y(1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1) = y \times 10 = 10y[/tex]

To find the cost of one bag of windflower bulbs and one package of crocus bulbs, we can use the substitution method. By setting up a system of equations and solving for the variables, we find that the cost of one bag of windflower bulbs is $45 and the cost of one package of crocus bulbs is $7.50.

To find the cost of one bag of windflower bulbs and one package of crocus bulbs, we can set up a system of equations. Let's use the substitution method.

Let x represent the cost of one bag of windflower bulbs and let y represent the cost of one package of crocus bulbs.

We can set up two equations:

2x + 5y = 105

9x + 5y = 164.50

From the first equation, we can rewrite it as: 2x = 105 - 5y. We can substitute this expression for 2x in the second equation:

9(105 - 5y) + 5y = 164.50

Solving for y, we get y = 7.50. Substituting this value back into the first equation, we can solve for x: 2x + 5(7.50) = 105. Solving for x, we get x = 45.

Therefore, the cost of one bag of windflower bulbs is $45 and the cost of one package of crocus bulbs is $7.50.

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Follow below steps:

Mark and Julio are selling flower bulbs for a school fundraiser. To find the cost of one bag of windflower bulbs and one package of crocus bulbs, we set up two equations based on the information given, and then solve them using the substitution method.

Let x be the cost of one bag of windflower bulbs and y be the cost of one package of crocus bulbs. According to Mark's sales, the equation is:

2x + 5y = 105 ...(1)

According to Julio's sales, the equation is:

9x + 5y = 164.50 ...(2)

To use the substitution method, we first isolate y in equation (1):

y = (105 - 2x) / 5 ...(3)

Next, we substitute equation (3) into equation (2):

9x + 5((105 - 2x) / 5) = 164.50

9x + 105 - 2x = 164.50

7x = 59.50

x = 8.50

Now that we have the value for x, we can use it to find y by substituting x back into equation (3):

y = (105 - 2(8.50)) / 5

y = (105 - 17) / 5

y = 88 / 5

y = 17.60

Therefore, the cost of one bag of windflower bulbs is $8.50 and the cost of one package of crocus bulbs is $17.60.

The range for this situation represents all possible values of the cost of filling the gas tank in dollars.

The range for this situation represents the set of all possible outputs of the function, which in this case is the cost of filling the gas tank.

Since the equation given is p(g) = 3.5g, the range would be all possible values of p, the cost of filling the gas tank.

The range would depend on the values of g, the amount of gas in gallons, that you input into the equation.

For example, if you fill the tank with 1 gallon of gas, the cost would be p(1) = 3.5 * 1 = $3.50.

If you fill the tank with 3 gallons of gas, the cost would be p(3) = 3.5 * 3 = $10.50.

Therefore, the range for this situation would be all values of p, the cost, that can be obtained by inputting different values of g, the amount of gas in gallons, into the equation p(g) = 3.5g.

The range for this situation is from $0 (empty tank) to $42 (full tank). The cost can be any value in this range depending on the number of gallons pumped into the tank.

In this context, the function [tex]\( p(g) = 3.5g \)[/tex] represents the cost  p  of filling the gas tank with  g  gallons of gas. The range of the function is the set of all possible values for the cost.

Since the cost is directly proportional to the number of gallons, we can evaluate the function for the minimum and maximum values of  g . The minimum value of  g  is 0 gallons (empty tank), and the maximum value is 12 gallons (full tank).

1. For g = 0 , [tex]\( p(0) = 3.5 \times 0 = 0 \)[/tex]. So, the minimum cost is $0.

2. For  g = 12 , [tex]\( p(12) = 3.5 \times 12 = 42 \)[/tex]. So, the maximum cost is $42.

Therefore, the range for this situation is from $0 (empty tank) to $42 (full tank). The cost can be any value in this range depending on the number of gallons pumped into the tank.

Answer:

The maximum height of the marshmallow is 49 feet.

Step-by-step explanation:

The vertex form of a parabola is

[tex]y=a(x-h)^2+k[/tex]           .... (1)

Where, (h,k) is vertex of the parabola is a is constant.

The given function is

[tex]h=-16(t-14)^2+49[/tex]              ..... (2)

Where, h is height of the marshmallow (in feet) and t is the time (in seconds) after he throws the marshmallow.

From equation (1) and (2), we get

[tex]a=-16,h=14,k=49[/tex]

The value of a is -16, which is less than 0. So, the given function is a downward parabola.

The vertex of a downward parabola is the point of maxima.

The value of h is 14 and the value of k is 49. So, the vertex of the parabola is (14,49). It means the maximum height of the marshmallow is 49 feet in 14 seconds.

Therefore the maximum height of the marshmallow is 49 feet.

Answer:

1/4,9

Step-by-step explanation:

might be wrong tbh

The expression  [tex]\rm m^{2.5}[/tex] in radical form is [tex]\rm \sqrt[2.5]{m}[/tex] .

If n is a positive integer greater than 1 and n is a real number, then

[tex]\rm \sqrt[n]{a}[/tex] = aⁿ

Here the index is represented by n, the radicand is represented by a , and the sign is called the radical.

Left side of the equation is called the radical form

Right side of the equation is called exponent form.

The given exponent form is

[tex]\rm m^{2.5}[/tex]

In radical form this will be written as

[tex]\rm \sqrt[2.5]{m}[/tex]

Therefore the expression [tex]\rm m^{2.5}[/tex] in radical form is [tex]\rm \sqrt[2.5]{m}[/tex] .

To know more about Radical form

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Latest time he can leave to be home by a quarter before 5 is 4:13

Step-by-step explanation:

Given Max's trip home takes 32 minutes. we have to find the time at which he can leave to be home by a quarter before 5.

quarter before 5 means 4:45

Max's takes 32 min to come to home so he has to leave 32 minutes before the given time.

Hence, latest time he can leave to be home by a quarter before 5 is 4:45-32 = 4:13

Answer:

Max must leave home at 4:58 to get their before half past 5.

Step-by-step explanation:

Answer:

  $2248.75

Step-by-step explanation:

Susan's monthly payment is ...

  total payment = loan payment + insurance payment

  = $2128.00 + (483,000×0.30/100)/12

  = $2128.00 + 1449/12

  = $2128.00 + 120.75

  = $2248.75

Answer:

Step-by-step explanation:

485'228.3

Answer:

Step-by-step explanation:

mono-, bi-, tri- are prefixes meaning 1, 2, and 3, respectively. A 3-term polynomial is a trinomial; a 2-term polynomial is a binomial.

Answer:

C

Step-by-step explanation:

B isn't right. The 0 makes x^2 go away leaving a linear equation.

A is a linear function.

D is a cubic, so the answer is

C which has an x^2 function

First subtract the difference of the two by the total:

440 - 54 = 386

Now divide that by 2:

386 / 2 = 193

193 is the number of Sociology books sold.

Now add 54 to 193 for the total Physics books:

193 + 54 = 247 Physics books were sold.

Volume = (edge)^3

Volume = (3/4)^3

Volume = (27/64) inches^3

Done.

Answer:

c. (6,1)

Step-by-step explanation:

Add both x and both y (11+1)=12 (5+-3)=2 then divide both by 2

(6,1)

Answer:

x=1 if I understood correctly.

Step-by-step explanation:

[tex] \sqrt{x} + 5 + x - 3 = 4[/tex]

[tex] \sqrt{x} + 2 + x = 4[/tex]

[tex] \sqrt{x} + x = 2[/tex]

At this point if you try all the integers, you will find that only 1 is the solution to this equation, because:

[tex] \sqrt{1} + 1 = 2[/tex]

[tex]1 + 1 = 2[/tex]

[tex]2 = 2[/tex]

Hope I helped!

For this case we must solve the following equation:

[tex]\sqrt {x + 5} -3 = 4[/tex]

We add 3 to both sides of the equation:

[tex]\sqrt {x + 5} = 4 + 3\\\sqrt {x + 5} = 7[/tex]

We raise the square to eliminate the root:

[tex]x + 5 = 7 ^ 2\\x + 5 = 49[/tex]

We subtract 5 on both sides of the equation:

[tex]x = 49-5\\x = 44[/tex]

Answer:

[tex]x = 44[/tex]

Answer:

See below in bold.

Step-by-step explanation:

If we add the 2 equations  we eliminate x  and we get 2y =2.

So y = 1.

Substituting y = 1 in the second equation 1 = x - 3.

So x = 4.

A. One solution: (4, 1).

If we drew a graph we would have 2 lines which intersect at the point (4, 1).

Answer:

Step-by-step explanation:

If we add the 2 equations  we eliminate x  and we get 2y =2.So y =1.

Substituting y = 1 in the second equation 1 = x - 3.So x = 4.

A.

One solution: (4, 1).If we drew a graph we would have 2 lines which intersect at the point (4, 1).

For this case we must find the value of the following expression:

[tex](+328.62) - (+ 98.6) =[/tex]

We apply distributive property to the term within the parenthesis taking into account tha:

[tex]- * + = -[/tex]

Rewriting we have:

[tex]+ 328.62-98.6 =[/tex]

Different signs are subtracted and the sign of the major is placed:

[tex]+328.62-98.6 = 230.02[/tex]

Answer:

230.02

Option B

Answer:

  irrational

Step-by-step explanation:

Pi is irrational.

-1 is rational.

Their sum is irrational.

_____

In general, the sum of a rational number and an irrational number is irrational.

The number 'pi' is an irrational number. When we subtract 1 from 'pi', we still obtain an irrational number, therefore 'pi-1' is irrational.

The number pi is a well-known irrational number. An irrational number cannot be expressed as a ratio of two integers, and its decimal expansion never ends or repeats. When we subtract 1 from pi, we get another number. Since we are creating a new number by subtracting an integer from an irrational number, that number remains irrational. Therefore, pi-1 is also an irrational number.

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Answer:

D = {0 , 1 , 2 , 3 , 4 , 5} and R = {1 , 2 , 4 , 8 , 16 , 32} ⇒ answer D

Step-by-step explanation:

* Lets talk about the domain and the range of a function

- The domain is the input values

- The range is the output values

- f(x) = y,  x is the input then x is the domain of the function and y is the

  output then y is the range of the function

- Example:

# If x = {2 , 3 , 5) and f(x) = 2x

- The input is x to find f(x) substitute the values of x in f(x)

- f(2) = 2(2) = 4 , f(3) = 2(3) = 6 , f(5) = 2(5) = 10

- The output is f(x) = {4 , 6 , 10}

- From all steps above the domain of f(x) is {2 , 3 , 5) and the range

 is {4 , 6 , 10}

* Lets solve the problem

- There are 32 teams participating  in a single-elimination soccer

 tournament

- x is the number of rounds

- f(x) is the number of teams

- only the winning teams from each round progress to the next

 round of the tournament

* Lets look to the graph and find the domain and the range

- The domain the the values of x and the range is the values of f(x)

∵ At x = 0 then f(0) = 32 ⇒ 32 teams inter the 1st round

∵ At x = 1 then f(1) = 16 ⇒ 16 teams inter the 2nd round

∵ At x = 2 then f(2) = 8 ⇒ 8 teams inter the 3rd round

∵ At x = 3 then f(3) = 4 ⇒ 4 teams inter the 4th round

∵ At x = 4 then f(4) = 2 ⇒ 2 teams inter the 5th round

∵ At x = 5 then f(5) = 1 ⇒ 1 team in win

- From all above:

∴ The domain is {0 , 1 , 2 , 3 , 4 , 5} and the range is {1 , 2 , 4 , 8 , 16 , 32}

* D = {0 , 1 , 2 , 3 , 4 , 5} and R = {1 , 2 , 4 , 8 , 16 , 32}

Answer:

  11,184,808

Step-by-step explanation:

The n-th term of a geometric series is ...

  an = a1·r^(n-1)

To fill in the formula, we need a1·r^n, so need to multiply the last term shown by r.

The value of r is 32/8 = 4, and the other terms of interest are a1 = 8, a1·r^(n-1) = 8388608. So, the sum is ...

  [tex]S_n=\dfrac{ra_1r^{n-1}-a_1}{r-1}=\dfrac{4\cdot 8,388,608-8}{4-1}=11,184,808[/tex]

Answer:

Option B) The variable Y will cancel out first.

Step-by-step explanation:

we have

5x-y=-21 ----> equation A

x+y=-3 ----> equation B

Solve by elimination

Adds equation A and equation B

5x-y=-21

x+y=-3

--------------

5x+x=-21-3 ----->variable y will be eliminated first

6x=-24

x=-4

Answer:

Sherina should have added 56 to both sides of the equation.

Step-by-step explanation:

To solve this equation: x-56=230 you need to add 56 to both sides of the equation:

x-56 + 56=230 + 56 → x = 286.

Therefore, Sherina should have added 56 to both sides of the equation.

Answer:

Last option: Sherina should have added 56 to both sides of the equation.

Step-by-step explanation:

To solve the equation [tex]x-56=230[/tex] Sherina needed to solve for the variable "x".

To calculate the value of the variable "x" it is important to remember the Addition property of equality. This states that:

[tex]If\ a=b\ then\ a+c=b+c[/tex]

Therefore, Sherina should have added 56 to both sides of the equation.

The correct procedure is:

[tex]x-56+(56)=230+(56)\\x=286[/tex]

Answer:

23

Step-by-step explanation:

30 + 9 = 39.

39 - 14 = 25.

25 - 2

= 23

Answer:

23

Step-by-step explanation:

Answer:

(d-5)x2

Step-by-step explanation:

you said a number d is subtracted by 5 then doubled so lets make an example. d=6

(6-5)x2

(6-5)=6-5=1

(1)x2=1x2=2

If a number d is decreased by 5 and then doubled, then we can represent that event with an algebraic expression as:

[tex]2\times (d-5)[/tex]

The number d decreased by 5 is written as: [tex]d - 5[/tex]

When we double a thing, we multiply by 2.

Thus we have the algebraic form of given condition as:

[tex]2\times(d-5)[/tex]

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ANSWER

[tex]{(2x - 3)}^{3} = {8x}^{3} - 36 {x}^{2} + 54x - 27[/tex]

EXPLANATION

Using the binomial theorem of Pascal's triangle, the coefficient of the third exponent binomial is :

1,3,3,1

The expansion for

[tex] {(a - b)}^{3} = {a}^{3} - 3 {a}^{2} b + 3a {b}^{2} - {b}^{3} [/tex]

To find the expansion for:

[tex] {(2x - 3)}^{3} [/tex]

We put a=2x and b=3

This implies that,

[tex]{(2x - 3)}^{3} = {(2x)}^{3} - 3 {(2x)}^{2} ( 3) + 3(2x) {(3)}^{2} - {3}^{3} [/tex]

This simplifies to:

[tex]{(2x - 3)}^{3} = {8x}^{3} - 36 {x}^{2} + 54x - 27[/tex]