Answer:
The equation is balanced
Explanation:
Before a equation can be said to be balanced the number of mole at the reaction side must be equal to number mole at the product side
Let's start with Zn at the reactant side 4 moles of Zn reacts and 4 moles of Zn was obtained from the product side which makes it balanced
Let's take HNO3
For H,10 moles react and 10 moles was obtained in the product side
For N,10 moles react and 8 moles was obtained initially and 2 moles was obtained as well which makes it 10 moles and it makes it balanced
For O,30 moles react and after calculating the total amount of O at the product side it was observed to be 30 which indicates that the equation is balanced...
The equation is absolutely well balanced
What is true of diffusion
The true statement about diffusion is b. Molecules will move from high to low concentration until equilibrium is reached.
Molecules diffuse passively, moving from high-concentration regions to low-concentration regions without the requirement for external energy input.This motion continues until the system reaches equilibrium, at which point the concentration of molecules is uniform throughout. It's vital to remember that diffusion, which is caused by the random movement of particles, does not require a transport protein.
Option b, which highlights the movement of molecules from high to low concentration until a condition of equilibrium is reached, therefore appropriately captures a feature of diffusion.
complete question;
Which of the following is true of diffusion?
a. It requires energy.
b. Molecules will move from high to low concentration until equilibrium is reached.
c. It is a transport mechanism that requires a transport protein.
d. All of the above.
The measurement 0.41006 gram, rounded to three significant figures, is expressed as
Answer:
0.410
Explanation:
Rounding 0.41006 gram to three significant figures results in 0.410 g.
To express the measurement 0.41006 gram rounded to three significant figures. When rounding to significant figures, we look at the digits from the left and count the first non-zero digit and the following digits up to the desired number of figures.
Here, the first three significant figures are 4, 1, and 0 (since this zero comes after a non-zero digit and before another non-zero digit, it counts as significant). Therefore, rounding 0.41006 to three significant figures gives us 0.410 g.
How do chemists express the rates of chemical reactions
Answer:
They expressed it as rate of change in concentration of reactants or products in a chemical reaction
The rate of a chemical reaction can be expressed in the terms of the increase in the concentration of product or decrease in the concentration of reactants with time.
What is the rate of the chemical reaction?The rate of reaction can be defined as the speed at which the products are formed from the reactants in the reaction. The rate of the chemical reaction offers information on how much the time reaction will be completed.
The rate of reaction can be defined as the speed of a reaction at which reactants are transformed into products. Some reactions are instantaneous, while some reactions take time to reach the final equilibrium.
A catalyst can be defined as a substance that enhances the rate of the reaction without going under any change in the reaction.
Rates of reaction are expressed as the concentration of reactant used or the concentration of product produced per unit of time. The units of rates are mol per liter or mol/L.
Learn more about the rate of reaction, here:
brainly.com/question/13571877
#SPJ2
how is a mole like a dozen?
Answer:
Answer in explanation.
Explanation:
The mole is a unit for counting 6.02 1023 representative particles. The dozen is used to count 12 items.
The mole is a unit for counting 6.02 1023 representative particles.
The dozen is used to count 12 items
If you have 100 grams of a radioactive isotope with a half life of 10 years how much of the isotope will you have left after 20 years
Hey there!
A half-life means after a certain amount of time, half of that substance will be gone/changed after that time.
There are two half lives in 20 years because 20 ÷ 10 = 2.
So, we divide the 100g sample in half 2 times.
100 ÷ 2 = 50
50 ÷ 2 = 25
There will be 25g of the radioactive sample remaining after two half lives.
Hope this helps!
How can you increase the electrical output of a generator?
Decrease the speed of the spinning magnet.
Increase the turns of the wire.
O Decrease the turns of the wire.
Decrease the speed of the spinning solenoid.
O Decrease the size of the magnet.
Answer:
Increase the turns of the wire
Explanation:
By increasing the number of turns the wire has made, you are increase the inductive power of the coil in the generator, thereby giving rise to the output of the generator.
ANSWER BOTH ASAP AND I WILL GIVE BRAINLYEST!!!!
Answer:
For the first one it is C
Explanation:
Answer:
answer is: constant , direct solar radiation as the ocean influences weather and climate by storing solar radiation, distributing heat and moisture around the globe, and driving weather systems.
The Coriolis effect is the apparent curvature of global winds, ocean currents, and everything else that moves freely across the Earth's surface. The curvature is due to the rotation of the Earth on its axis. The effect was discovered by the nineteenth century French engineer Gaspard C.
what is ecology and what is ecosystem
Answer:
Ecosystem :
Any living organism interacting with its physical environment by any means is known as Ecosystem.
Ecology :
Ecology is the study of the ecosystem. In this field of biology, we study how an organism interact with its physical environment and how the environment respond.
1. Define a Family.
2. What is a period?
3. What is the symbol for the following elements?
a. Magnesium __________
b. Potassium ___________
c. Iron ________________
d. Copper _____________
e. Aluminum __________
4. What are the names of the following elements?
a. C ________________
b. Cl _______________
c. Au ______________
d. Sr _______________
5. What period are the following element in?
a. He ______________
b. Ge ______________
c. Rb ______________
d. I ________________
6. What group are the following elements?
a. Sulfur ______________
b. Ca _________________
c. Iodine ______________
d. Fe _________________
7. Give me an atom with the following characteristics.
a. Halogen __________________
b. Alkali metal _______________
c. Nobel gas _________________
d. Transition metal _____________
e. Nonmetal __________________
Answer:
a family is a group consisting of 2 parents and their children living together in a union.or all desendants of a common ancestor
2. A period is a name given to the horizontal row of the periodic table.
3.
a.mg
b.k
c.Fe
d.cu
e.Al
4.
a.Carbon
b.Chlorine
c.Gold
d.strontium
5.
a.period 1
b.period 4
c.period 5
d.period 5
6.
a.group 6
b.group 2
c.group 7
d.group 8 belong ti 1st transitional elements.
7.
a.F
b.Na
c.Ar
d.V
e.I
This answer provides definitions for chemical families (groups) and periods, symbol and name identification for a number of elements, their period and group placements within the Periodic Table, and examples of atoms of different types.
Explanation:1. In chemistry, a Family is a column of elements in the Periodic Table. They are also known as Groups and share similar chemical behavior.
2. A period in the Periodic Table is a horizontal row of elements. Each new row (or Period) signifies a new energy level in the atom's electrons.
3. The symbols for the elements are:
a. Magnesium - Mg
b. Potassium - K
c. Iron - Fe
d. Copper - Cu
e. Aluminum - Al
4. The names of the elements:
a. C - Carbon
b. Cl - Chlorine
c. Au - Gold
d. Sr - Strontium
5. The periods for the elements:
a. He (Helium) - Period 1
b. Ge (Germanium) - Period 4
c. Rb (Rubidium) - Period 5
d. I (Iodine) - Period 5
6. The groups for the elements:
a. Sulfur - Group 16
b. Ca (Calcium) - Group 2
c. Iodine - Group 17
d. Fe (Iron) - Group 8 (In the transition metals)
7. Examples of atoms based on characteristics:
a. Halogen - Fluorine(F)
b. Alkali metal - Sodium(Na)
c. Noble gas - Neon(Ne)
d. Transition metal - Iron(Fe)
e. Nonmetal - Oxygen(O)
https://brainly.com/question/35461104
#SPJ2
Compared to size of earth, the atmosphere is very
Answer:
thin
Explanation:
Answer:
very thin
Explanation:
the atmosphere is actually very thin compared to the size of the earth.
How does a molecule differ from an atom?
Answer:
Atom are single neutral particles.Molecule are neutral particles made of two or more atom bonded together.
over the course of two years the top layer of soil at a Michigan farm is blown away
For each of the situations below, state whether it describes erosion, weathering, or possibly both.
Answer:
Erosion
Explanation:
The blowing away of the top layer of the soil at a Michigan farm is best described as scenario that shows wind erosion.
Erosion is the removal of the top layer of the earth on which plant grows. In short is the washing away of soil by stream or blowing away by wind.
When soil is blow away, it is a pure case of erosion. The process of erosion usually follows weathering or sometime occurs together with it.
Weathering is the physical disintegration and chemical decomposition of rocks to form sediments and soils.
Often times, the process of weathering and erosion occurs together. It is loose weathering products that are carried away during erosion.
In the soil layer at Michigan, the process of erosion by wind is current taking place by ablation.
Over the course of two years, there has been change in the concentration the top layer of soil at a Michigan farm due to natural forces, leading to potential agricultural challenges.
Erosion of the topsoil layer at a Michigan farm over two years can have detrimental effects on agricultural productivity and the environment. Topsoil is crucial for plant growth as it contains essential nutrients and organic matter. When it is blown away, as in this scenario, farmers face difficulties in cultivating crops as the soil becomes less fertile and less capable of retaining moisture. This can result in reduced crop yields and increased vulnerability to drought conditions.
Furthermore, the erosion of topsoil can lead to environmental issues such as water pollution, as sediment runoff can contaminate nearby water bodies. Soil conservation practices, such as planting cover crops and implementing erosion control measures, are essential to mitigate these negative consequences and maintain the long-term sustainability of the Michigan farm's agricultural activities.
Learn more about concentration here: https://brainly.com/question/35383336
#SPJ3
If K3PO4= 0.250M, how many grams of K3PO4 are in 750.0ml of solution? Remember that M is the same as mol/L. Answer: 39.8g
please show work!
Answer:
See below
Explanation:
Molarity = moles/Volume in Liters = (grams/formula wt)/Vol in Liters
=> Grams of solute = Molarity x Vol in Liters x formula wt
= (0.250M)(0.750L)(212.3g/mol)
= 39.8 grams
Final answer:
To find the mass of K3PO4 in a 0.250 M solution with a volume of 750.0 mL, calculate the number of moles and then multiply by the molar mass, resulting in 39.8 grams.
Explanation:
To calculate the mass of K3PO4 in a 0.250 M solution with a volume of 750.0 mL, we need to follow these steps:
Convert the volume from mL to L: 750.0 mL is 0.750 L.Calculate the number of moles of K3PO4 using the molarity and volume of the solution: 0.250 M imes 0.750 L = 0.1875 moles.Find the molar mass of K3PO4 by adding the atomic masses of 3 potassium (K) atoms, 1 phosphorus (P) atom, and 4 oxygen (O) atoms. Using periodic table values: Molar mass of K3PO4 = (3 imes 39.10) + 30.97 + (4 imes 16.00) = 212.27 g/mol.Multiply the number of moles by the molar mass to get the mass in grams: 0.1875 moles imes 212.27 g/mol = 39.8 grams.Therefore, there are 39.8 grams of K3PO4 in 750.0 mL of a 0.250 M solution.
Decide whether you agree or disagree with the statement, "New theories in science are
accepted quickly as soon as supporting evidence is reported." Justify your reasoning.
Answer:
Time is relative - and science is still arguing about singlet versus doublet Carbenes; they fought over whether Oxygen was “real”, and refused to believe in Radium until one by one they SAW that drop glow! (And affect photographic film).
Explatnation:
Which of the following describes an example of the atmosphere acting as a system?
its lavered structure
global wind patterns
Answer:
its lavered structure
Explanation:
Final answer:
The atmosphere acts as a system in how it manifests global wind patterns which are influenced by atmospheric pressure gradients, the rotation of the Earth, and thermal energy. The Coriolis effect and thermal activity generate geographically significant wind patterns like the trade winds. Global warming may induce alterations in these patterns.
Explanation:
Global Wind Patterns as an Atmospheric System
The earth's atmosphere behaves as a dynamic system, particularly evident through global wind patterns. These patterns are driven by complexities such as atmospheric pressure gradients, the rotation of the Earth, and thermal energy from the Sun. The resulting movement of air in response to these factors is what we call 'wind.'
For instance, in the northern hemisphere, air moves into a low-pressure region and is deflected to the right due to the Coriolis force, creating counterclockwise circulation. On the other hand, air moving away from high-pressure areas is deflected in a rightward motion as well, but this results in a clockwise circulation. The combination of rising and sinking air due to thermal activity and the Coriolis effect generates trade winds, which are essential in the global transfer of heat and moisture, impacting global climate and weather systems.
Additionally, global warming could significantly alter these atmospheric circulation patterns, potentially leading to changes in weather systems, like the distribution of precipitation and the intensity and frequency of storms.
which term best describes the physical properties of a rainbow
Answer: meteorological phenomenon
Explanation: Hello, there! A rainbow is a meteorological phenomenon that is caused by reflection, refraction and dispersion of light in water droplets resulting in a spectrum of light appearing in the sky. It takes the form of a multicoloured circular arc. Rainbows caused by sunlight always appear in the section of sky directly opposite the sun.
I hoped i help and im here for any more questions you might have! thankyou!
Two boxes are filled with air. The molecules that make up the air in Box A
have more kinetic energy than those in Box B. What can you say about these
boxes?
Answer:
box a is warmer than box b, so the molecules are moving around a lot more
using the soubility curve what is the solubilityof nh4cl in 10 mL of water at a temperature of 60 degrees Celsius
Answer:
Please, see attached two figures:
The first figure shows the solutility curves for several soluts in water, which is needed to answer the question.The second figure shows the reading of the solutiblity of NH₄Cl at a temperature of 60°C.Answer: 5.5gExplanation:
The red arrow on the second attachement shows how you must go vertically from the temperature of 60ºC on the horizontal axis, up to intersecting curve for the solubility of NH₄Cl.
From there, you must move horizontally to the left (green arrow) to reach the vertical axis and read the solubility: the reading is about in the middle of the marks for 50 and 60 grams of solute per 100 grams of water: that is 55 grams of grams of solute per 100 grams of water.
Assuming density 1.0 g/mol for water, 10 mL of water is:
[tex]10mL\times 1.0g/mL=10g[/tex]
Thus, the solutibily is:
[tex]10gWater\times 55gNH_4Cl/100gWater=5.5gNH_4Cl[/tex]
How many protons are in a hydrogen Atom
Answer:
1
Explanation:
Its periodic number is 1.
Answer:
There are 1 plus that is the periodic number
Jayne's science teacher mixed a clear liquid with a blue liquid in a beaker. After a few minutes there was a white solid at the bottom of the beaker. What is most likely true about the white solid?
A.
It is a new substance with different properties.
B.
It is an organic compound.
C.
It will dissolve in water to form a blue solution.
Which of the following statements is most likely true about the solubilities of CF4 and CCl2F2 in water? CF4 is soluble in water; CCl2F2 is not. Both CF4 and CCl2F2 are insoluble in water. CF4 is insoluble in water; CCl2F2 is soluble in water. Both CF4 and CCl2F2 are soluble in water.
Answer:
Explanation:
CF4 is insoluble in water; CCl2F2 is soluble in water
According to the concept of solubility,CF₄ is insoluble in water; CCl₂F₂ is soluble in water.
What is solubility?Solubility is defined as the ability of a substance which is basically solute to form a solution with another substance. There is an extent to which a substance is soluble in a particular solvent. This is generally measured as the concentration of a solute present in a saturated solution.
The solubility mainly depends on the composition of solute and solvent ,its pH and presence of other dissolved substance. It is also dependent on temperature and pressure which is maintained.Concept of solubility is not valid for chemical reactions which are irreversible. The dependency of solubility on various factors is due to interactions between the particles, molecule or ions.
Learn more about solubility,here:
https://brainly.com/question/8591226
#SPJ2
A 8.46 L sample oxygen gas at 267K and 1.23 atm is heated to 295K. If the volume changes to 6.98L, what is the new pressure?
Answer:
The new pressure is 1,65 atm
Explanation:
We use the gas formula, which results from the combination of the Boyle, Charles and Gay-Lussac laws. According to which at a constant mass, temperature, pressure and volume vary, keeping constant PV / T.
(P1xV1)/T1= (P2xV2)/T2
(1,23atmx 8,46L)/267 K = (P2 x 6,98L)/ 295K
0,039 atmx L/K = (P2 x 6,98L)/ 295K
P2=(0,039 atmx L/K)x 295K/6,98L =1,65 atm
50g of an unknown metal at 100.0 degrees celsius is placed into 150g of water at 20.0 degrees Celsius and the final temperature of the metal and water is 23.3 degrees Celsius. What is the specific heat of the metal?
The specific heat of the unknown metal is approximately 0.36 J/g°C.
First, let's identify the variables given in the problem:
- Mass of the unknown metal (m1) = 50g
- Initial temperature of the metal (T1) = 100.0°C
- Mass of water (m2) = 150g
- Initial temperature of water (T2) = 20.0°C
- Final temperature of the metal and water ([tex]T_f[/tex]) = 23.3°C
To find the specific heat of the metal, we can use the formula:
[tex]\[ q = m \times c \times ΔT \][/tex]
Where:
- ( q ) is the heat absorbed or released
- ( m ) is the mass of the substance (either the metal or water in this case)
- ( c ) is the specific heat capacity of the substance
- ( ΔT ) is the change in temperature
First, we'll find the heat absorbed by the metal using the above formula:
[tex]\[ q_{\text{metal}} = m_{\text{metal}} \times c_{\text{metal}} \times ΔT_{\text{metal}} \]\[ q_{\text{metal}} = 50g \times c_{\text{metal}} \times (T_f - T_1) \]\[ q_{\text{metal}} = 50g \times c_{\text{metal}} \times (23.3°C - 100.0°C) \]\[ q_{\text{metal}} = 50g \times c_{\text{metal}} \times (-76.7°C) \][/tex]
Next, we'll find the heat released by the water as it cools down:
[tex]\[ q_{\text{water}} = m_{\text{water}} \times c_{\text{water}} \times ΔT_{\text{water}} \]\[ q_{\text{water}} = 150g \times 4.18 J/g°C \times (T_f - T_2) \]\[ q_{\text{water}} = 150g \times 4.18 J/g°C \times (23.3°C - 20.0°C) \]\[ q_{\text{water}} = 150g \times 4.18 J/g°C \times 3.3°C \][/tex]
Since the heat lost by the metal equals the heat gained by the water (assuming no heat is lost to the surroundings):
[tex]\[ q_{\text{metal}} = q_{\text{water}} \]\[ 50g \times c_{\text{metal}} \times (-76.7°C) = 150g \times 4.18 J/g°C \times 3.3°C \][/tex]
Now, solve for [tex]\( c_{\text{metal}} \):[/tex]
[tex]\[ c_{\text{metal}} = \frac{150g \times 4.18 J/g°C \times 3.3°C}{50g \times (-76.7°C)} \]\[ c_{\text{metal}} = \frac{2085.3 J}{-3835 J} \]\[ c_{\text{metal}} ≈ 0.36 J/g°C \][/tex]
So, the specific heat of the unknown metal is approximately 0.36 J/g°C.
Complete Question:
50g of an unknown metal at 100.0 degrees celsius is placed into 150g of water at 20.0 degrees Celsius and the final temperature of the metal and water is 23.3 degrees Celsius. What is the specific heat of the metal?
The specific heat of the metal is approximately [tex]\( 0.527 \, \text{J/g}^\circ \text{C} \)[/tex].
For the metal:
[tex]\[ q_{\text{metal}} = m_{\text{metal}} \cdot c_{\text{metal}} \cdot \Delta T_{\text{metal}} \][/tex]
where[tex]\( q_{\text{metal}} \)[/tex] is the heat lost by the metal, \( m_{\text{metal}} \) is the mass of the metal, [tex]\( c_{\text{metal}} \)[/tex] is the specific heat capacity of the metal, and \( \Delta T_{\text{metal}} \) is the change in temperature of the metal.
For the water:
[tex]\[ q_{\text{water}} = m_{\text{water}} \cdot c_{\text{water}} \cdot \Delta T_{\text{water}} \][/tex]
where [tex]\( q_{\text{water}} \)[/tex] is the heat gained by the water, [tex]\( m_{\text{water}} \)[/tex] is the mass of the water, [tex]\( c_{\text{water}} \)[/tex] is the specific heat capacity of water (which is approximately [tex]\( 4.184 \, \text{J/g}^\circ \text{C} \))[/tex], and [tex]\( \Delta T_{\text{water}} \)[/tex] is the change in temperature of the water.
Since the heat lost by the metal is equal to the heat gained by the water, we have:
[tex]\[ q_{\text{metal}} = -q_{\text{water}} \][/tex]
Substituting the expressions for [tex]\( q_{\text{metal}} \)[/tex] and [tex]\( q_{\text{water}} \)[/tex] into this equation gives us:
[tex]\[ m_{\text{metal}} \cdot c_{\text{metal}} \cdot \Delta T_{\text{metal}} = -m_{\text{water}} \cdot c_{\text{water}} \cdot \Delta T_{\text{water}} \][/tex]
Now we can plug in the known values:
[tex]\[ 50 \, \text{g} \cdot c_{\text{metal}} \cdot (23.3^\circ \text{C} - 100.0^\circ \text{C}) = -150 \, \text{g} \cdot 4.184 \, \text{J/g}^\circ \text{C} \cdot (23.3^\circ \text{C} - 20.0^\circ \text{C}) \][/tex]
Solving for [tex]\( c_{\text{metal}} \)[/tex]:
[tex]\[ 50 \cdot c_{\text{metal}} \cdot (-76.7) = -150 \cdot 4.184 \cdot 3.3 \] \[ c_{\text{metal}} = \frac{-150 \cdot 4.184 \cdot 3.3}{50 \cdot (-76.7)} \] \[ c_{\text{metal}} = \frac{-2020.2}{-3835} \] \[ c_{\text{metal}} \approx 0.527 \, \text{J/g}^\circ \text{C} \][/tex]
The answer is: 0.527 \,[tex]\text{J/g}^\circ \text{C}[/tex]"
If 10.00 g of iron metal is burned in the presence of excess of O2 how many grams of Fe2O3 will form
14.292 grams of Fe2O3 is formed when 10 gram of iron metal is burned.
Explanation:
The balanced equation for the reaction is to be known so that number of moles taking part can be known.
The balanced chemical equation is
4Fe + 3[tex]O_{2}[/tex]⇒ 2 [tex]Fe{2}[/tex][tex]O{3}[/tex]
From the given weight of iron to be used for the production of [tex]Fe{2}[/tex][tex]O{3}[/tex], number of moles of Fe taking part in the reaction can be known by the formula:
Number of moles= mass ÷ Atomic mass of one mole of the element.
(Atomic weight of Fe is 55.845 gm/mole)
Putting the values in equation
Number of moles = 10 gm ÷ 55.845 gm/mole
= 0.179 moles
Applying the stoichiometry concept
4 moles of Fe gives 2 Moles of Fe2O3
0.179 moles will produce x moles of Fe2O3
So, 2÷ 4 = x ÷ 0.179
2/4 = x/ 0.179
2 × 0.179 = 4x
2 × 0.179 / 4 = x
x = 0.0895 moles
So from 10 grams of iron metal 0.0895 moles of Fe2O3 is formed.
Now the formula used above will give the weight of Fe2O3
weight = atomic weight × number of moles
= 159.69 grams × 0.0895
= 14.292 grams of Fe2O3 formed.
When 10.00 g of iron metal is burned in the presence of excess O2, 14.30 g of Fe2O3 will form.
Explanation:When iron metal reacts with oxygen in the presence of excess oxygen, it forms iron(III) oxide (Fe2O3). The balanced equation for this reaction is:
4Fe + 3O2 → 2Fe2O3
Using the molar mass of iron, we can calculate the number of moles of iron in 10.00 g:
10.00 g Fe ÷ (55.85 g/mol Fe) = 0.1787 mol Fe
Since the reaction ratio is 4:2, we can calculate the number of moles of Fe2O3 formed:
0.1787 mol Fe × (2 mol Fe2O3 ÷ 4 mol Fe) = 0.0894 mol Fe2O3
Finally, we can convert the number of moles of Fe2O3 to grams:
0.0894 mol Fe2O3 × (159.69 g/mol Fe2O3) = 14.30 g Fe2O3
Learn more about Formation of Fe2O3 here:
https://brainly.com/question/32455941
#SPJ3
Oxidation is common because?
the solubility in mol/dm3 of 20.2g of potassium trioxonitrate(V)dissolved in 100g of water at room temperature is
Answer:
2.00 mol/dm³Explanation:
Potassium trioxonitrate(V) is KNO₃.
1. Find the molar mass of the solute
The molar mass of KNO₃ is 39.098g/mol + 14.007g/mol + 3×15.999g/mol = 101.102g/mol.
2. Convert the mass of solute, 20.02g, into number of moles
number of moles = mass in grams / molar mass number of moles = 20.2g / 101.102g/mol = 0.1998mol3. Assume that the volume of the solution is equal to the volume of water
This is a rough approximation, but it is necessary since you do not have the density of the solution:
density = mass / volume1.00 g/cm³ = 100g / volumevolume = 100g × 1.00g/cm³ = 100cm³Convert 100cm³ to dm³:
100cm³ × 1dm³ / 1,000cm³ = 0.1 dm³4. Calculate the solubility is mol/dm³
0.1998 mol / 0.1dm³ = 1.998mol/dm³ ≈ 2.00mol/dm³It is rounded to three significant digits to match the choices.
Final answer:
The solubility of potassium trioxonitrate(V) in water at room temperature is 2 mol/dm³, calculated by dividing the moles of the dissolved substance by the volume of the solvent in liters.
Explanation:
To calculate the solubility of potassium trioxonitrate(V), which is potassium nitrate (KNO3), we first need to find the molar mass of KNO3 to convert the given mass to moles. Potassium (K) has an atomic mass of approximately 39 g/mol, nitrogen (N) has an atomic mass of approximately 14 g/mol, and oxygen (O) has an atomic mass of approximately 16 g/mol. Therefore, the molar mass of KNO3 is 39 + 14 + (3 × 16) = 101 g/mol. Now, we take the mass of KNO3, 20.2 g, and divide it by its molar mass to find the number of moles:
Number of moles of KNO3 = 20.2 g / 101 g/mol = 0.2 mol
Since the solvent water has a mass of 100 g, and knowing that the density of water is approximately 1 g/cm³, we can assume that the volume of 100 g of water is approximately 100 mL or 0.1 L. Thus, the solubility of KNO3 in mol/dm³ can be calculated as:
Solubility = Number of moles / Volume in L = 0.2 mol / 0.1 L = 2 mol/dm³
Which is an example of radiation?
Your car parked in the sun is hot when you return.
Hot air rises and cool air moves in to take its place.
Heated water begins circulating in a fish tank.
An example of radiation is a car that gets hot when parked in the sun, as it involves the transfer of heat via infrared waves emitted by the sun. Heat transfer by radiation does not require a medium and is significantly influenced by the emitting object's surface area and temperature. Hence, option A is correct.
Examples of radiation involve the transfer of heat energy without the need for a medium, such as air, to facilitate the transfer. It occurs through electromagnetic waves, and an example of this is when your car parked in the sun is hot when you return. The sun emits infrared waves that transfer heat to the car's surfaces, warming them even without direct contact. Other forms of heat transfer, like convection and conduction, necessitate the movement of air or physical contact, respectively.
Electromagnetic radiation can come in various forms, including microwaves, infrared radiation, and visible light. The Earth is warmed by the sun through radiation, and even the human body emits thermal radiation. Understanding heat transfer by radiation is essential in many applications, from household heating to climate science. The power of radiation is significantly influenced by the emitting object's surface area and is dramatically affected by its absolute temperature (as per the relationship P × T⁴).
Which of the following would increase the amount to dissolve a solid solute?
By stirring and increasing temperature, there is an increase in dissolving capacity of the solid solute.
Explanation:
If a solute is added to the solution, it doesn't get dissolve easily then we have to increase the temperature, which in turn increases the movement of the solvent (may be water) and the solute particles, thus increases the dissolving power of the solid solute. One more way is by constant stirring, that is by making more contact among the solvent as well as the solute particles there by increasing the solubility of solid solute.
Which structure of the respiratory system connects the pharynx to the trachea?
Answer:
Larynx
Explanation:
It is a cartilaginous structure inferior to the laryngopharynx that connects the pharynx to the trachea and helps regulate the volume of air that enters and leaves the lungs.
The larynx, also known as the voice box, is the structure in the respiratory system that connects the pharynx to the trachea. It serves as a conduit for air and also house the vocal cords, playing a crucial role in speech and vocalization.
Explanation:The structure of the respiratory system that connects the pharynx to the trachea is the larynx. The larynx, also known as the voice box, is a short passageway that connects the pharynx (the region that receives air from the nasal cavities and the mouth) to the trachea (the 'windpipe' that leads to the lungs). The larynx not only serves as a conduit for air, it also houses the vocal cords, and thus, plays a crucial role in speech and vocalization.
Learn more about Respiratory System here:https://brainly.com/question/18289690
#SPJ6
3 The volume of a gas is 50.0 mL at 20.0 K. What will be the new
temperature if the gas is compressed to 10.0 mL under constant pressure?
A 100 K
B 10.0 K
C4.00 K
D 5.00 K
Answer:
C. 4.00 K
Explanation:
We can solve this using Charles's Law of the ideal gas. The law describes that when the pressure is constant, the volume will be directly proportional to the temperature. Note that the temperature here should only use the Kelvin unit. Before compressed, the volume of the gas is 50ml(V1) and the temperature is 20K (T1). After compressed the volume becomes 10ml(V2). The calculation will be:
V1 / T1= V2 / T2
50ml / 20K = 10ml / T2
T2= 10ml/ 50ml * 20K
T2= 4K
Final answer:
The new temperature of the gas, when compressed from 50.0 mL to 10.0 mL under constant pressure, will be 4.00 K, following Charles's Law which relates temperature and volume of a gas under constant pressure.
Explanation:
The question involves the concept of how the volume of a gas changes with temperature, under constant pressure, following Charles's Law. This law states that the volume of a gas is directly proportional to its temperature (in Kelvin) when the pressure is kept constant. Given that the volume of a gas is 50.0 mL at 20.0 K and the volume is compressed to 10.0 mL under constant pressure, we want to find the new temperature. Applying Charles's Law, we set up the proportion (V1/T1) = (V2/T2) where V1 is the initial volume, T1 is the initial temperature, V2 is the final volume, and T2 is the final temperature.
To solve for T2, we rearrange the formula to T2 = (V2/V1) * T1. Substituting the given values, T2 = (10.0 mL / 50.0 mL) * 20.0 K = 4.00 K. Therefore, the new temperature of the gas, when compressed to 10.0 mL under constant pressure, will be 4.00 K.