Dee is on a swing in the playground. the chains are 2.5 m long, and the tension in each chain is 450 n when dee is 55 cm above the lowest point of her swing. tension is a vector directed along the chain, measured in newtons, abbreviated n. what are the horizontal and vertical components of the tension at this point in the swing

Answers

Answer 1
Refer to the diagram shown below.

From the geometry, obtain
x = 2.5 - 0.55 = 1.95 m
cos θ = 1.95/2.5 = 0.78
θ = cos⁻¹ 0.78 = 38.74°

From the free body diagram, the tension in the chain is 450 N.
F is the centripetal force,
W is Dee's weight.

The components of the tension are
Horizontal component = 450 sin(38.74°) = 281.6 N, acting left.
Vertical component = 450 cos(38.74°) = 351.0 N, acting upward.

Answers:
Horizontal: 281.6, acting left.
Vertical: 351.0 N, acting upward.
Dee Is On A Swing In The Playground. The Chains Are 2.5 M Long, And The Tension In Each Chain Is 450
Answer 2

The horizontal and vertical components of the tension at the given point in the swing are  281.6 N and 351 N respectively.

Given data:

The length of chain is, L = 2.5 m.

The magnitude of tension on each chain is, T = 450 N.

Distance above the lowest point is, d = 55 cm = 0.55 m.

In problem, first we need to obtain the angle of inclination made by string horizontally.

So, the angle inclined by the string with horizontal is given as,

[tex]cos \theta =\dfrac{L-d}{L}\\\\cos \theta =\dfrac{2.5-0.55}{2.5}\\\\\theta = cos^{-1}(\dfrac{1.95}{2.5})\\\\\theta=38.74^{\circ}[/tex]

Now, the horizontal component of tension force acting on the string is,

[tex]T_{H}=T \times cos \theta\\T_{H}=450 \times cos 38.74\\T_{H}=281.6 \;\rm N[/tex]

And, the vertical component of tension force acting on the string is,

[tex]T_{V}=T \times sin \theta\\T_{V}=450 \times sin 38.74\\T_{V}=351 \;\rm N[/tex]

Thus, the horizontal and vertical components of the tension at this point in the swing are 281.6 N and 351 N respectively.

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Related Questions

A mass m = 17 kg is pulled along a horizontal floor with no friction for a distance d =5.8 m. then the mass is pulled up an incline that makes an angle θ = 35° with the horizontal and has a coefficient of kinetic friction μk = 0.39. the entire time the massless rope used to pull the block is pulled parallel to the incline at an angle of θ = 35° (thus on the incline it is parallel to the surface) and has a tension t =88 n. 1) what is the work done by tension before the block goes up the incline? (on the horizontal surface.) 418.1 j submit 2) what is the speed of the block right before it begins to travel up the incline? 7.01 m/s submit 3) what is the work done by friction after the block has traveled a distance x = 3 m up the incline? (where x is measured along the incline.) -159.67 j submit 4) what is the work done by gravity after the block has traveled a distance x = 3 m up the incline? (where x is measured along the incline.) -286.67 j submit 5) how far up the incline does the block travel before coming to rest? (measured along the incline.)

Answers

Final answer:

The student's problems require applying the concepts of work and energy to determine the effects of tension, friction, and gravity on a block moving on a surface and up an incline.

Explanation:

The student's question pertains to the work done by various forces on a block which is initially pulled along a horizontal surface and then up an incline. To solve problems like these, we rely on concepts from physics including work, energy, and the effects of forces on motion.

Work done by Tension on a Horizontal Surface

On a horizontal surface with no friction, the work done by tension is given by Work = force × distance. Since the force of tension is parallel to the displacement, the work done is simply the product of tension (T) and the distance (d).

Speed Before Incline

The speed of the block before it goes up the incline can be found using the work-energy principle. The work done on the block is equal to the change in its kinetic energy.

Work Done by Friction and Gravity on an Incline

When the block is pulled up an incline with friction, both the force of friction and gravity do work against the direction of motion. The work done by friction is the product of frictional force, distance, and the cosine of the angle between the force and the displacement (which is 180 degrees, so cos(180°) = -1).

Distance Traveled Up the Incline Before Rest

To find how far up the incline the block travels before coming to rest, we need to equate the work done against friction and gravity with the initial kinetic energy of the block. This will require solving for distance in the work-energy equation.

astronauts in orbit feel weightless because...

Answers

You feel gravity when you feel things pressing together. Like your foot pressing against the floor, or your heart pressing against the inside of your chest. If everything around you is falling just like you are, then you never feel any things pressing together, and that feels like there's no weight.

what occurs when a swimmer pushes through the water to swim?

Answers

The water is pushed back by the swimmers hand allowing the swimmer to push their self forward with the use of kicking 

A car, initially at rest, travels 20 m in 4 s along a straight line with constant acceleration. the acceleration of the car is:

Answers

We are asked to find the acceleration of the car:
Formula: s = 1/2 a t^2 

20 = 1/2 a (4)^2 

a = 40 / 16
a = 5 / 2 m/s^2 
= 2.5 m/s^2

The acceleration of the car is 2.5 m/s^2

Final answer:

To find the car's constant acceleration, we use the formula s = ½at², substituted with the given values to calculate the acceleration, which is found to be 2.5 m/s².

Explanation:

The question involves finding the constant acceleration of a car that starts from rest and travels 20 m in 4 s along a straight line. To find the acceleration, we can use the formula for motion under uniform acceleration, s = ut + ½at², where s is the distance covered, u is the initial velocity, t is the time, and a is the acceleration. Given that the car starts from rest, u is 0, which simplifies the formula to s = ½at².

Rearranging the formula to solve for acceleration (a), we get a = 2s/t². Plugging in the values, a = 2*20/4² = 2.5 m/s². Therefore, the acceleration of the car is 2.5 m/s².

How many times larger is the elephant's momentum than the momentum of a 0.033-kg tranquilizer dart fired at a speed of 350 m/s?

Answers

Elephants Momentum Sp= EM Sp=(5400 kg (Average weight of an Asian Elephant))(4.5 m/s ( Average walking speed) ) = 24300 kg m/s Momentum of Dart: D=MD MD=(0.033 kg)(350 m/s) = 11.55 kg m/s Elephant has more momentum

suppose the same amount of heat is applied to two bars. they have the same mass, but experience different changes in temperature. are the specific heat capacities the same for the two bars? explain.

Answers

If both bars are made of a good conductor, then their specific heat capacities must be different. If both are metals, specific heat capacities of different metals can vary by quite a bit, eg, both are in kJ/kgK, Potassium is 0.13, and Lithium is very high at 3.57 - both of these are quite good conductors.

If one of the bars is a good conductor and the other is a good insulator, then, after the surface application of heat, the temperatures at the surfaces are almost bound to be different. This is because the heat will be rapidly conducted into the body of the conducting bar, soon achieving a constant temperature throughout the bar. Whereas, with the insulator, the heat will tend to stay where it's put, heating the bar considerably over that area. As the heat slowly conducts into the bar, it will also start to cool from its surface, because it's so hot, and even if it has the same heat capacity as the other bar, which might be possible, it will eventually reach a lower, steady temperature throughout.

What would most likely happen if the power lines in a petroleum power plant were broken

Answers

Customers would not get electricity. If the transmission lines [heavy power] leaving the plant broke [zap], it's just fix the transmission lines. But if the generators or main switch gear were lost, so the plant itself has no power, it can get ugly. 

Options:

The petroleum would not burn. Steam would not be produced. Customers would not receive electricity. Energy would not be converted.

Answer:

Option-(3):Customers would not receive electricity.

Explanation:

Power lines breakage:

The power lines are required to supply power or electricity to the households and the different consumers i.e industries. If the lines are broken then there will be no more power or electricity supply to the consumers.

What distance does the car cover in the first 4.0 seconds of its motion?

Answers

The car's velocity to be 2.4 m/s, and the distance covered in the first 4 seconds to be 4.8 meters.

From the given parameters and the provided graph, we're tasked with determining the velocity of a car and the distance it covers within a specific time interval. The total distance traveled by the car (S) is 12 meters, and the total time taken is 8 seconds. To find the velocity (V), we use the formula for the area of a trapezium.

Firstly, using the area of a trapezium formula, where S = 1/2 (a + b) * V, with a and b representing the parallel sides of the trapezium formed by the graph:

Given that a = 2 and b = 8, we substitute these values into the formula:

12 = 1/2(2 + 8) * V

24 = 10V

V = 24/10

V = 2.4 m/s

Thus, the velocity of the car is calculated to be 2.4 m/s.

Next, within the first 4 seconds, the shape of the distance covered by the car forms a triangle on the graph. Utilizing the formula for the area of a triangle, which is 1/2 * base * height, where the base is the time (4s) and the height is the speed (V = 2.4 m/s):

S = 1/2 * 4 * 2.4

S = 4.8 m

Hence, the distance covered by the car within the first 4 seconds of its motion is 4.8 meters.

In summary, by calculating the velocity using the area of a trapezium and determining the distance covered within a specific time interval using the area of a triangle, we find the car's velocity to be 2.4 m/s, and the distance covered in the first 4 seconds to be 4.8 meters.

The question probable may be;

A car in stop-and-go traffic starts at rest, moves forward 12 m in 8.0 s, then comes to rest again. The velocity-versus-time plot for this car is given in the figure. What distance does the car cover in the first 4.0 seconds of its motion?

in rutherford's gold foil experiment what kind of particles in dense atomic nuclei caused some alpha particles to bounce straight back from the gold foil

Answers

In Rutherford's gold foil experiment, Nuclei in the gold atom caused some of the alpha particles to bounce straight back from the gold foil Alpha particles are positively charged as is the nucleus of atoms therefor repelling each other. Because the large spacing of the nucleus in the gold atoms only a small amount of alpha particles will collide directly with the nucleus, therefor only a small amount of alpha particles will be reflected back.

Answer: POSITIVE

Explanation:

Because angular momentum is conserved, an ice-skater who throws her arms out will

Answers

This is an example of conservation of angular momentum.

The ice skater will rotate more slowly because her arms would be considered the outside torque that is impacting her constant angular momentum.

So, an ice-skater who throws her arms out will rotate more slowly.

Final answer:

An ice-skater who pulls her arms in will spin faster due to the conservation of angular momentum, as a reduction in her moment of inertia results in an increased rotation speed to keep the angular momentum unchanged.

Explanation:

Because angular momentum is conserved, an ice-skater who throws her arms out will experience a change in their rotation speed when altering their body's configuration. When a figure skater on ice extends her arms while spinning, she has a certain angular momentum, which depends on her rotation speed and the distribution of her mass—or her moment of inertia. With arms extended, her moment of inertia is greater. If she pulls her arms in, she reduces her moment of inertia, but because no external torque is acting on her, her angular momentum must stay constant. To maintain the same angular momentum with a smaller moment of inertia, her rotation speed—or angular velocity—must increase. Therefore, when an ice skater pulls in her arms, she spins faster; this is a classic demonstration of the conservation of angular momentum.

The formula for angular momentum (l) is defined as l = mvR, where m is the mass, v is the linear speed, and R is the radius of the orbit or the distance from the axis of rotation. When the skater pulls her arms inward, 'R' decreases, and since mass ('m') remains unchanged, the speed ('v') must increase for the angular momentum to stay conserved. This result in an increased rate of spin, which is also seen as an increase in rotational kinetic energy due to the work done by the skater to pull her arms closer to her body.

A 2-ft-thick block constructed of wood (sg = 0.6) is submerged in oil (sg = 0.8), and has a 2-ft-thick aluminum (specific weight = 168 lb/ft3) plate attached to the bottom as indicated in fig. p2.146. (a) determine completely the force required to hold the block in the position shown. (b) loca

Answers

Final answer:

The behavior (rising or falling) of a wooden block in oil based on buoyancy and calculating the wood's density, which is found to be 600 kg/m³ based on its specific gravity.

Explanation:

Applying Archimedes' principle, which states that the buoyant force on a submerged object is equal to the weight of the fluid displaced by the object, can solve this problem. Since the block is submerged in oil with a specific gravity (sg) of 0.8, and has an attached aluminum plate, the overall density and buoyancy of the system are affected, leading to a complex calculation that incorporates the densities of the wood, aluminum, and oil.

The block will rise if its combined density (wood and aluminum) is less than that of the surrounding oil. Since wood has a lower specific gravity than oil, it tends to float, but the attached aluminum plate, with a specific weight of 168 lb/ft³, increases the system's density. Whether it rises or falls will depend on the overall density compared to the oil's density.

The density of the wood can be derived from its specific gravity. The specific gravity is the ratio of the density of the wood to the density of water (1000 kg/m³). Therefore, a specific gravity of 0.6 indicates the wood's density is 600 kg/m³.

Which is the best example of translational motion?

A. a soccer ball passed between two players.

B.a powered up rocket on the launch pad.

C.an ice skater spinning in place.

D.water molecules in a glass of water.

Answers

The correct answer would be A. a soccer ball passed between two players. Hope I helped God bless you and your family

The best example of translation motion is a soccer ball passed between two players.

What is translation motion?

Motion in which a moving body's points travel uniformly in one direction. We can observe that there is no change in the object's orientation if it is moving in a translatory manner. Motion that is translated is sometimes referred to as translational motion.

A body is considered to be in linear motion when it moves in a straight line (or rectilinear motion). A body is considered to be in translational motion when all of its points move the same distance in the same period of time.

Given that in question that to find best example of translational motion which is basically the change in the position of the body under observation.

The best example of the translational motion is a soccer ball passed between two players.

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Which of the following statements is true? 1 mL = 1 g 1 g = 1 oz 1 mL = 1 cm3 1 g = 1 cm

Answers

The first one.    1mL=1g

What is the frequency of radiation whose wavelength is 0.84 nm ? express the frequency in inverse seconds to three significant digits?

Answers

The relationship between the frequency and wavelength of and electromagnetic wave is c(speed of light) = f(frequency) * lambda(wavelength). c = 3 x 10^8 m/s and, in this case, the wavelength is .84 nm or 8.4 x 10^-10. Plugging in to the equation above we see the frequency of the wave is 3.57 x 10^17 s^-1 or Hz.

which of the following would decrease current flow in a circuit made of originally from 1.5 volt battery a loop of wire and a switch

Answers

There are no "following" to choose from.

The current in the circuit will decrease if you make the battery voltage less than 1.5v, or make the wire in the loop longer, or open the switch.

What is the mass of a 14.0 cm3 cube of fresh water (density 1.00 g/cm3)?

Answers

density=mass/vol ,,mass =density ×vol=1*14

This is when minerals break on specific planes.

Answers

The answer is Cleavage.
Crystals often contain planes of atoms along which the bonding between the atoms is weaker than along other planes. In such a case, if the mineral is struck with a hard object, it will tend to break along these planes. This property of breakingalong specific planes is termed cleavage.

A proton travels through uniform magnetic and electric fields. the magnetic field is in the negative x direction and has a magnitude of 2.04 mt. at one instant the velocity of the proton is in the positive y direction and has a magnitude of 1930 m/s. at that instant, what is the magnitude of the net force acting on the proton if the electric field is (a) in the positive z direction and has a magnitude of 4.70 v/m, (b) in the negative z direction and has a magnitude of 4.70 v/m, and (c) in the positive x direction and has a magnitude of 4.70 v/m?

Answers

a. the net force magnitude in case (a) is  [tex]7.53 * 10^-^1^8 N[/tex].

b.   the net force magnitude in case (b) is also [tex]7.53 * 10^-^1^8 N[/tex].

c.   the net force magnitude in case (c) is approximately [tex]6.40 * 10^-^1^5 N.[/tex]

a. Electric force:

Force = q * E

= ([tex]1.602 * 10^-^1^9[/tex] C) * (4.70 V/m)

= [tex]7.53 * 10^-^1^8[/tex] N (pointing in the positive x direction)

b. Magnetic force:

The magnetic force will now create a force in the negative y direction with magnitude:

Force = q * v * B, where v is the proton velocity and B is the magnetic field

Force = [tex](1.602 * 10^-^1^9 C) * (1930 m/s) * (2.04 x 10^-^3 T) \\= 6.40 * 10^-^1^5 N[/tex]

c. Net force:

Net force = electric force + magnetic force (vector sum)

Net force magnitude = √(([tex]7.53 *10^-^1^8 N)^2 + (6.40 * 10^-^1^5 N)^2)[/tex]

Net force magnitude ≈  [tex]6.40 * 10^-^1^5[/tex] N

Teams A and B are in a tug-of-war challenge. Team A wins the challenge. What can be said about Team A?

Answers

Answer:

Team A exert more force on ground.

Explanation:

In Tug of war since both teams are pulling two ends of a string or rope so here the net force on the string along with two teams would be zero

So in order to win the game each team has to exert force on the ground.

When team exert more force on the ground then due to the reaction force of ground on the team in opposite direction will help the team to pull the rope towards them

So here if Team A wins the game then the force exerted by that team on the ground must be more due to which the reaction force by ground on the team is of larger magnitude and hence they wins the game

In a tug-of-war, Team A's victory means they exerted a larger force than Team B, creating a net force that caused the movement of the rope towards their side.

In a tug-of-war challenge, if Team A wins, it can be said that Team A exerted a larger force on the rope than Team B. This is because the winning team in a tug-of-war is the one that pulls the rope towards their side over the center line, overcoming the opposing team's efforts. Force in physics is a measure of the interaction between two objects, and in this case, the interacting objects are the two teams exerting forces on the rope. The team that wins is the one that manages to exert a net force that is greater than that of the opposing team, resulting in the movement of the rope towards the winning team's side.

A baseball (m=145g) traveling 40 m/s moves a fielder's glove backward 27 cm when the ball is caught. part a what was the average force exerted by the ball on the glove? express your answer to two significant figures and include the appropriate units.

Answers

Final answer:

The average force exerted by the ball on the glove is approximately 857 N.

Explanation:

To calculate the average force exerted by the ball on the glove, we can use the equation:

F = m × Δv / Δt

where F is the average force, m is the mass of the ball, Δv is the change in velocity, and Δt is the time taken.

In this case, the mass of the ball is given as 145g, which is equal to 0.145 kg. The change in velocity of the ball is given as 40 m/s, since it travels from an initial speed of 40 m/s to a final speed of 0 m/s when caught. The time taken is calculated by converting the distance the glove moves to meters (27 cm = 0.27 m) and dividing it by the final speed of the ball. Therefore, Δt = 0.27 m / 40 m/s = 0.00675 s.

Now we can substitute the given values into the formula to find the average force:

F = (0.145 kg × 40 m/s) / 0.00675 s ≈ 857 N

Therefore, the average force exerted by the ball on the glove is approximately 857 N.

A skydiver is descending with a constant velocity. Consider air resistance. Diagram the forces acting upon the skydiver

Answers

The forces acting on the skydiver is downward force due to his own weight,  and drag force acting upwards due to air resistance.

At a constant speed, the upward acceleration of the skydiver is zero. The downward acceleration is equal to acceleration due to gravity. The upward force is equal to downward force.

The sketch of the forces acting on the skydiver is presented below using simple diagram;

                                 ↑ N

                                 Ф

                                  ↓ W

Thus, the forces acting forces acting on the skydiver is downward force due to his own weight,  and drag force acting upwards due to air resistance.

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If the magnitude of the electric field at a distance of 7.8 cm from the center is 30500 n/c , what is the magnitude of the electric field at 22.3 cm from the center? answer in units of n/c.

Answers

3730 N/C The intensity of the electric field follows the inverse square law. Since everything except the distance is remaining constant, then the force will vary with the inverse square of the ratio of the change. So first, lets calculate the ratio of the change in distance. 22.3 / 7.8 = 2.858974359 And since we actually want the square of the distance... 2.858974359^2 = 8.173734385 And since the distance increased, that means the force will decrease. So we get 30500 / 8.173734385 = 3731.464538 Rounding to 3 significant figures gives 3730 N/C.

To find the electric field at [tex]22.3 cm[/tex]  from the center, use the given electric field at [tex]7.8 cm[/tex]  to first calculate the charge, then reapply the electric field formula at the new distance. The result is approximately [tex]3684.2 N/C[/tex].

The problem involves calculating the electric field at a different distance from a point charge. We can use the formula for the electric field due to a point charge, which is given by:

[tex]E = \frac{k \cdot |q|}{r^2}[/tex]

Here,

E is the electric field, k is Coulomb's constant ([tex]8.99 \times 10^9 \, \text{N} \cdot \text{m}^2/\text{C}^2[/tex]), q is the charge, r is the distance from the charge.

The magnitude of the electric field at [tex]7.8 cm (0.078 m)\\ \\[/tex] is [tex]30500 N/C[/tex] . First, we calculate the charge q.

Rearrange the formula to find [tex]q: \quad q = \frac{E \cdot r^2}{k}[/tex]

Substitute the known values:[tex]q = 30500 \, \text{N/C} \times (0.078 \, \text{m})^2 / (8.99 \times 10^9 \, \text{N} \cdot \text{m}^2/\text{C}^2)[/tex]

Simplify:[tex]q \approx 2.04 \times 10^{-11} \, \text{C}[/tex]

Now, we use this charge to find the electric field at [tex]22.3 cm (0.223 m)[/tex]:

Substitute the values back into the electric field formula:[tex]E = \frac{k \cdot q}{r^2}[/tex]

[tex]E = \frac{(8.99 \times 10^9 \, \text{N} \cdot \text{m}^2/\text{C}^2) \times (2.04 \times 10^{-11} \, \text{C})}{(0.223 \, \text{m})^2}[/tex]

Calculate the electric field: [tex]E \approx 3684.2 \, \text{N/C}[/tex]

Therefore, the magnitude of the electric field at [tex]22.3 cm[/tex]  from the center is [tex]3684.2 N/C[/tex].

What is the current widely accepted theory about global climate change and what are some predictions associated with it?

Answers

The theory concerning global climate change is that carbon and oxygen are combining to form co2 causing global climate change. Predictions are that they will be positive and negative effects, positive effects are they produce more crops and cold related deaths. Some negatives are damage to crops, rising of sea level, spread of disease and other things.

The widely accepted theory about global climate change is :

The formation of CO₂ by carbon and oxygen

Formation of CO₂

The formation of CO₂ by the mixture of carbon and oxygen is a widely accepted theory because of its effect on global climate change. the predictions regarding this theory includes some positives and negatives.

some of the positive predictions is :

Improved growth of  crops because plants absorb C0₂ during photosynthesis

some negative predictions include

Rising sea levelsspread of carbon related diseases

Hence we can conclude that The widely accepted theory about global climate change is The formation of CO₂ by carbon and oxygen.

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which of the following statements is false about the distances between planets earth and the sun

Answers

the distance from the sun to Neptune is about the same as the distance from Neptune to the next closest star, Proxima Centauri

Answer;

The distance from the sun to Neptune is about the same as the distance from Neptune to the next closest star, Proxima Centauri

Explanation;

When a planet like earth is closer to the sun the heat of the sunlight warms the surface of the planet hence,a planet like Neptune is far away from sun, the sunlight can't reach the planet and it's surface becomes cold so,the distance of the sun and planet is the main factor effecting the temperature.

A tennis player receives a shot with the ball (0.0600 kg) traveling horizontally at 22.0 m/s and returns the shot with the ball traveling horizontally at 35.5 m/s in the opposite direction. (assume the initial direction of the ball is in the −x direction.) (a) what is the impulse delivered to the ball by the tennis racket?

Answers

I need an answer choice

What occurs when a ball Falls from a balcony?
A. The earth moves toward the ball.
B. Neither the ball nor the earth actually move.
C. The earth moves away from the ball.
D. The ball moves but not the earth

Answers

almost positive the answer is D

Which of the following BEST explains why stability is an important skill for athletes?
A.
Without good stability, athletes cannot participate in sports.
B.
Without good stability, athletes are too clumsy to perform well.
C.
Good stability helps athletes improve their speed.
D.
Good stability helps athletes deal with their injuries.

Answers

Answer;

B. Without good stability, athletes are too clumsy to perform well.

Explanation;

Stability refers to the resistance to both linear and angular acceleration, or resistance to disruption of equilibrium.

Developing and enhancing core strength and stability helps athletes to maximize their power output and enhance game day performance. Additionally, Improving core strength and stability can also help athletes reduce their risk of injury.

Stability is an important skill for an athlete because without good stability, athletes are too clumsy to perform well.

Option B is correct

What is stability an for athlete?

Stability is the ability of an athlete retain controls for more than the average distance of a movement, This does not mean an athlete will no be displace but the ability to regain shape is stability

Therefore, without good stability, athletes are too clumsy to perform well.

Option B is correct

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The voltage across the terminals of a 9.0 v battery is 8.5 v when the battery is connected to a 60 ω load. part a what is the battery's internal resistance?

Answers

Final answer:

The internal resistance of the 9.0 V battery is 3.54 Ω.

Explanation:

The internal resistance of the battery can be calculated using Ohm's Law. Ohm's Law states that the voltage (V) across a resistor is equal to the current (I) through the resistor multiplied by the resistance (R). In this case, the voltage across the battery terminals is 8.5 V and the resistance of the load is 60 Ω.

Using Ohm's Law, we can set up the following equation:

8.5 V = I * 60 Ω

Solving for I gives us:

I = 8.5 V / 60 Ω = 0.1417 A

The internal resistance of the battery can then be calculated using the formula:

Internal Resistance = (Emf - Terminal Voltage) / Current

Substituting the given values:

Internal Resistance = (9.0 V - 8.5 V) / 0.1417 A = 3.54 Ω

A high-speed flywheel in a motor is spinning at 500 rpm when a power failure suddenly occurs. the flywheel has mass 40.0 kg and diameter 76.0 cm . the power is off for 35.0 s and during this time the flywheel slows due to friction in its axle bearings. during the time the power is off, the flywheel makes 180 complete revolutions.

Answers

The flywheel is solid cylindrical disc. Moment of inertial = ½ * mass * radius^2 Mass = 40.0 kg Radius = ½ * 76.0 cm = 38 cm = 0.38 meter Moment of inertial = ½ * 41 * 0.36^2 Convert rpm to radians/second The distance of 1 revolution = 1 circumference = 2 * π * r The number of radians/s in 1 revolution = 2 * π 1 minute = 60 seconds 1 revolution per minute = 2 * π radians / 60 seconds = π/30 rad/s Initial angular velocity = 500 * π/30 = 16.667 * π rad/s 170 revolutions = 170 * 2 * π = 340 * π radians The flywheel’s initial angular velocity = 16.667 * π rad/s. It decelerated at the rate of 1.071 rad/s^2 for 48.89 seconds. θ = ωi * t + ½ * α * t^2 θ = 16.667 * π * 48.89 + ½ * -1.071 * 48.89^2 2559.9 - 1280 θ = 1280 radians

Write a paragraph showing the relationship between chemistry and physical based on what you've learned from the periodic table

Answers

Chemistry is the study of the compounds, their combinations and interactions with one another. Physics, on the other hand, is a scientific discipline that deals with the study of matter their motion through space and time. In relation to the periodic table the groupings of the elements are based on how their interact and their properties. 

Final answer:

The periodic table symbolizes the relationship between chemistry and physics by organizing elements based on their atomic numbers and grouping them by shared properties, influencing their chemical reactivity and physical states.

Explanation:

The relationship between chemistry and physics can be explored through the study of the periodic table, a fundamental tool in the chemical sciences. The periodic table not only lists elements by increasing atomic number but also groups them by shared physical and chemical properties. For example, elements that are gases, liquids, or solids at room temperature can be predicted based on their placement in the periodic table. Similarly, an element's chemical reactivity is indicated by its grouping, which suggests its tendency to combine and form chemical bonds. The table, conceptualized by Dmitri Mendeleev, reflects the periodic trends in electron configuration which underpin both the chemical behaviors and physical properties, such as electrical conductivity. Indeed, the understanding of such properties has been instrumental in technical advancements, such as the use of silicon in electronics due to its semiconductor properties. Thus, the periodic table encapsulates the core principles bridging chemistry and physics.

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