Answer:
Heat losses by convection, Qconv = 90W
Heat losses by radiation, Qrad = 5.814W
Explanation:
Heat transfer is defined as the transfer of heat from the heat surface to the object that needs to be heated. There are three types which are:
1. Radiation
2. Conduction
3. Convection
Convection is defined as the transfer of heat through the actual movement of the molecules.
Qconv = hA(Temp.final - Temp.surr)
Where h = 6.4KW/m2K
A, area of a square = L2
= (0.25)2
= 0.0625m2
Temp.final = 250°C
Temp.surr = 25°C
Q = 64 * 0.0625 * (250 - 25)
= 90W
Radiation is a heat transfer method that does not rely upon the contact between the initial heat source and the object to be heated, it can be called thermal radiation.
Qrad = E*S*(Temp.final4 - Temp.surr4)
Where E = emissivity of the surface
S = boltzmann constant
= 5.6703 x 10-8 W/m2K4
Qrad = 5.6703 x 10-8 * 0.42 * 0.0625 * ((250)4 - (25)4)
= 5.814 W
The time rate of change of the hotplate's temperature is 0.0062 K/s. The magnitude of the heat losses by convection and radiation is 64.23 W.
Explanation:The question is asking for the time rate of change of the plate temperature when it is at 250°C and the magnitude of the heat losses by convection and by radiation.
First, transform the initial plate temperature from Celsius to Kelvin, so 250°C = 523.15 K.
The air temperature is also given in Celsius, which is 25°C = 298.15 K.
Next, we calculate the heat loss due to convection using the formula Q_conv = h * A * (T_plate - T_air), where h is the convection coefficient, A is the surface area of the plate, and T_plate and T_air are the temperatures of the plate and the air, respectively.
Substituting the given values, we get: Q_conv = 6.4 W/m^2.k * 0.25 m * 0.25 m * (523.15 K - 298.15 K) = 1.80 W.
The heat loss due to radiation can be calculated using the Stefan-Boltzmann law: Q_rad = ε * σ * A * (T_plate^4 - T_surrounding^4), where ε is the emissivity, σ is the Stefan-Boltzmann constant (5.67 * 10^-8 W/m^2.K^4), and T_surrounding is the surrounding temperature.
Again plugging in the given values, we get the heat loss due to radiation as Q_rad = 0.42 * 5.67 * 10^-8 W/m^2.K^4 * 0.25 m * 0.25 m * (523.15 K^4 - 298.15 K^4) = 62.43 W.
So, the total heat loss Q = Q_conv + Q_rad = 1.80 W + 62.43 W = 64.23 W.
To find the time rate of change of the temperature, we use the formula: dT/dt = Q / (m*C), where dT/dt is the time rate of change of the plate temperature, m is the mass, and C is the specific heat. Substituting the values, we get: dT/dt = 64.23 W / (3.75 kg * 2770 J/kg.K) = 0.0062 K/s.
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Water needs to be turned into steam in a high altitude lab where the atmospheric pressure is 84.6 KPa. Computte the heat energy (in calories) required to evaporate 900g of water at 15 degree C under these conditions.
Answer:
558.1918 kilocalories = 558191.8 calories
Explanation:
Data provided in the question:
Atmospheric pressure = 84.6 KPa
Mass of water, m = 900 g = 0.90 kg
Temperature = 15°C
Now,
Temperature at 84.6 KPa = 94.77°C
Therefore,
Heat energy required = m(CΔT + L)
here,
C is the specific heat of the water = 4.2 KJ/kg.°C
L = Latent heat of water = 2260 KJ/kg
Thus,
Heat energy required = 0.90[ 4.2 × (94.77 - 15) + 2260 ]
= 2335.53 KJ
also,
1 KJ = 0.239 Kilocalories
Therefore,
2335.53 KJ = 0.239 × 2335.53 Kilocalories
= 558.1918 kilocalories = 558191.8 calories
What is a coarse-grained rock composed of intermediate plagioclase feldspar and pyroxene? a. graniteb. gabbro c. andesited. peridotitee. diorite
Answer:
B.gabbro
Explanation:
Gabbro is a coarse-grained, dark-colored igneous
rock . It is usually black or dark green in color and composed mainly of the minerals plagioclase and augite. It is the most abundant rock in the deep oceanic crust. Gabbro is used in construction.
How far do you jog each morning? You prefer to jog in different locations each day and do not have a pedometer to measure your distance. Create an application to determine the distance jogged given the average number of strides ran during the fist minute, average number ran during the last minute, and the total minutes jogging. Design a modularized solution (with methods) to display the distance traveled. Pedometers measure the distance you run. However, you can also do a good estimate of the distance if you know your foot stride, how many strides you complete per minute, and the number of minutes you job. Foot stride is the distance covered by one average step length. Since everyone has a different foot size, strides differ. Manny people average 3 feet per setup when jogging. For this application, assume the foot stride is 2.5 feet. There are 5,280 feet in a mile. To establish how many strides per minutes, allow the user to input the number of strides made during the first minute jogging and the number of strides made string the last minutes of jogging. Use the average of those values to represent the strides per minute. Allow the user to input the total time spent jogging in hours and minutes. Write code that will display to distance traveled in miles.
Answer:
The program is given below with appropriate comments for better understanding
Explanation:
#Program
# foot stride = 2.5 feet
# 1 mile = 5280 feet
no_stride_first_min = int(input('Enter the number strides made durng the first minute of jogging: '))
no_stride_last_min = int(input('Enter the number strides made durng the last minute of jogging: '))
avg_stride_one_min = (no_stride_first_min + no_stride_last_min)/2 # calculates the average stride per minute
jogging_duration = float(input('Enter the total time spent jogging in hours and minute: '))
jogging_duration_hours = int(jogging_duration) # gets the hour
jogging_duration_min = jogging_duration - int(jogging_duration) # gets the minute
tot_jogging_duration_min = jogging_duration_hours*60 + jogging_duration_min # calculates total time in minutes
dist_feet = (avg_stride_one_min*2.5)*tot_jogging_duration_min # calculates the total distance in feet
dist_miles = dist_feet/5280 # calculates the total distance in mile
print('Distance traveled in miles = {0:.2f} miles'.format(dist_miles))
Given an array of primitive integers named grades, fill in the blank to complete the following code that calculates the average of all the grades: double average = 0; average + grades[ average (= grades.length; Use proper spacing per the course style guide. Do not include additional spaces at the beginning or end.
Answer:
C++ snippet is given below with appropriate comments and explanation
Explanation:
Code snippet:
double average=0;//declaring variable
//using for loop
for(int i=0;i<grades.length;i++)
{
average+=grades[i];//add each grade to average
}
average/=grades.length;//find average
Explanation :
Above code snippet need a for loop to add each grade from the array to the variable average,
average/=grades.length; this will compute average.
During an actual run with the calorimeter, there are two important criteria which must be satisfied by a correctly positioned thermometer. What are these two criteria?
Answer:
1. the bulb of the thermometer must be in the center of the lower calorimeter, about one inch from the bottom.
2.thermometer must face you to read
Explanation:
During an actual run with the calorimeter, there are two important criteria which must be satisfied by a correctly positioned thermometer. These two criteria include;
1. the bulb of the thermometer must be in the center of the lower calorimeter, about one inch from the bottom.
2. thermometer must face you to read
The thermometer must be fully immersed without touching the calorimeter’s sides or bottom and positioned to minimize heat exchange with the external environment to ensure accurate temperature readings.
When using a calorimeter, it is crucial to ensure that the thermometer is correctly positioned to obtain accurate measurements. The two important criteria for correctly positioning the thermometer in a calorimeter are:
1. Thermal Equilibrium:
- The thermometer must be fully immersed in the substance being measured (typically a liquid) without touching the sides or the bottom of the calorimeter. This ensures that the thermometer accurately reflects the temperature of the substance rather than the container.
- The immersion should be deep enough so that the thermometer's bulb is surrounded by the substance, allowing it to reach thermal equilibrium with the substance. This helps in obtaining a consistent and accurate temperature reading.
2. Minimize Heat Exchange with the Environment:
- The thermometer should be positioned in a way that minimizes heat exchange with the external environment. The calorimeter is designed to be an insulated system, so the thermometer should not introduce significant thermal disturbance.
- The top of the calorimeter should be closed or covered as much as possible to prevent heat loss or gain from the surroundings, which could affect the temperature reading. The thermometer should pass through a small hole or a sealed opening to maintain the insulation integrity of the calorimeter.
By adhering to these criteria, the thermometer can provide precise and reliable temperature measurements, which are essential for accurate calorimetric calculations.
What is the weakest link in the security of an IT infrastructure? What are some of the strategies for reducing the risks?
Answer:
The weakest link is the people of the organization
The employees should be oriented and educated on the need to be security and safety conscious
Explanation:
Security professional had shown that negligence among the employees for security practices is a serious threat to end point security.
Print a message telling a user to press the letterToQuit key numPresses times to quit. End with newline. Ex: If letterToQuit = 'q' and numPresses = 2, print:
Answer:
Vb.Net
msgbox ("Press "q" twice to quit", msgboxstyle.information)
if char.q = keypress and keypress.count = 2 then
End
End if
Explanation:
Ensure at least ___ distance around fire sprinkler heads, safety showers, eyewash units, and heating and cooling units to ensure proper operation.
90 inches
Explanation:
According to OSHA requirement, the distance around safety showers and eyewash should be between 82-96 inches off the flow. This will allow for maximum diameter of spray.
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for the given sand, the maximum and minimum dry unit weights are 108 lb/ft3 and 92 lb/ft3, respectively. given that Gs=2.65, determine the moist unit weight of the soil when the relative density is 60% and moisture content is 8%.
Answer:
The moist unit weight of compaction = 109.05 lb/ft3
Explanation:
In order to determine the moist unit weight, the dry unit weight has to be evaluated first. If Y is the moist unit weight, then:
Y = Yd (1 + m)
Where:
Yd = dry unit weight
m = moisture content of soil = 8% = 0.08
But the dry unit weight is unknown. In order to calculate the dry unit weight, we will make use of the formula for relative density R;
R = [(Yd — Ydmin) ÷ (Ydmax — Ydmin)] × [Ydmax ÷ Yd]
Where:
R = relative density = 60% = 0.6
Yd = dry unit weight
Ydmin = minimum dry weight = 92 lb/ft3
Ydmax = maximum dry weight = 108 lb/ft3
Therefore R = 0.6 = [(Yd — 92) ÷ (108 — 92)] × [108/Yd]
0.6 = [(Yd — 92)/16] × [108/Yd], or
0.6 = (0.0625Yd — 5.75) × [108/Yd]
0.6Yd = 6.75Yd — 621
6.75Yd — 0.6 Yd = 621
6.15Yd = 621
And Yd = 100.98 lb/ft3 = dry unit weight
But we are asked to find the moist unit weight = Y = Yd (1 + m)
where Yd = dry unit weight and m = moisture content of soil = 8% = 0.08
Therefore, Y = 100.98 (1 + 0.08) = 109.05 lb/ft3.
A student team is to design a human-powered submarine for a design competition. The overall length of the prototype submarine is 4.85 m, and its student designers hope that it can travel fully submerged through water at 0.440 m/s. The water is freshwater (a lake) at T = 15 °C. The design team builds a one-fifth scale model to test in their university’s wind tunnel. A shield surrounds the drag balance strut so that the aerodynamic drag of the strut itself does not influence the measured drag. The air in the wind tunnel is at 25°C and at one standard atmosphere pressure. The students measure the aerodynamic drag on their model submarine in the wind tunnel. They are careful to run the wind tunnel at conditions that ensure similarity with the prototype submarine. Their measured drag force is 5.75 N. "Estimate the drag force" on the prototype submarine at the given conditions.
To estimate the drag force on the prototype submarine, use the principle of dynamic similarity and scale up the measured drag force by a factor of 5.
Explanation:To estimate the drag force on the prototype submarine, we can use the principle of dynamic similarity. The drag force is directly proportional to the density of the fluid, the velocity of the fluid flow, and the reference area of the object. Since the model submarine is one-fifth the size of the prototype, we need to scale up the measured drag force by a factor of 5. Additionally, we need to account for the difference in fluid density between air and water, as well as the viscosity of the fluid.
The drag force on the prototype submarine can be estimated using the equation:
Drag force (prototype) = Drag force (model) x (scale factor)^2 x (fluid density ratio) x (viscosity ratio)
By plugging in the given values and solving the equation, we can estimate the drag force on the prototype submarine.
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A unit cell has a lattice constant a, where a is the length of a single side of the unit cell. Draw a cube and derive the length of the diagonal from one top corner of the unit cell to the bottom far corner (ie. The largest distance between corners in a 3-D cube).
Answer:
The largest distance between corners in a 3-D cube = a root 3
Explanation : The detailed and step by step explanation is given in the attached file below.
A 220-V electric heater has two heating coils that can be switched such that either coil can be used independently or the two can be connected in series or parallel, for a total of four possible configurations. If the warmest setting corresponds to 2,000-W power dissipation and the coolest corresponds to 300 W, find the resistance of each coil.
Answer:
The resistances of both coils are 131.7 Ω and 29.64 Ω.
Explanation:
Since, there are two coils, they can be used independently or in series or parallel. The power is given as:
Power = P = VI
but, from Ohm's Law:
V = IR
I = V/R
therefore,
P = V²/R
R = V²/P
Hence, the resistance (R) and (P) are inversely proportional. Therefore, the maximum value of resistance will give minimum power, that is, 300 W. And the maximum resistance will be in series arrangement, as in series the total resistance gets higher than, any individual resistance.
Therefore,
Rmax = V²/Pmin = R1 + R2
R1 + R2 = (220 V)²/300 W
R1 + R2 = 161.333 Ω ______ en (1)
Similarly, the minimum resistance will give maximum power. And the minimum resistance will occur in parallel combination. Because equivalent resistance of parallel combination is less than any individual resistance.
Therefore,
(R1 R2)/(R1 + R2) = (220 V)²/2000 W
using eqn (1), we get:
(R1 R2) / 161.333 Ω = 24.2 Ω
R1 R2 = 3904.266 Ω²
R1 = 3904.266 Ω²/R2 _____ eqn (2)
Using this value of R1 in eqn (1), we get:
3904.266/R2 +R2 = 161.333
(R2)² - 161.333 R2 +3904.266 = 0
Solving this quadratic eqn we get two values of R2 as:
R2 = 131.7 Ω OR R2 = 29.64 Ω
when ,we substitute these values in eqn (1) to find R1, we get get the same two values as R2, alternatively. This means that the two coils have these resistance, and the order does not matter.
Therefore, the resistance of both coils are found to be 131.7 Ω and 29.64 Ω
Suppose that a bank only permits passwords that are strings from the alphabet = {a, b, c, d, 1, 2, 3, 4} that follow the rules:
The length is at least five characters
It begins with a letter {a, b, c, d}
It ends with two digits {1, 2, 3, 4}
The set of legal passwords forms a regular language L. Construct a regular expression r such that L(r) = L.
Answer:
#Python
import re
password = input("Enter password: ")
p = re.compile('^[ABCDabcd]+.*[^e-zE-Z5-9_]{2,}[1-4][1-4]+$')
match = p.search(password)
if match == None:
print('L(r) != L -> Incorrect password')
else:
print('L(r) = L -> Correct password')
Explanation:
The regular expression needed is:
^[ABCDabcd]+.*[^e-zE-Z5-9_]{2,}[1-4][1-4]+$
To understand why see the step by step of the regex:
^[ABCDabcd]: Here we use ^ to indicate the first character of the class, then we use [] to specify a character class, then we punt ABCDabcd to indicate that the first character has to begin with a letter from a to d and finally we use a + to continue our expression.*[^e-zE-Z5-9_]{2,}: Here we use .* to specify the sequence of characters that comes after the first letter, then we put ^e-zE-Z5-9_ inside brackets, the first character, ^, tell us that the characters coming are forbidden, so the user can not use a number, letter or special character outside of the sequence defined, and finally, we have curly brackets to indicate the length of the expression, where '2,' represents that the length in the middle is at least two characters long[1-4][1-4]+$: With the two brackets in this expression the string must ends with two digits from one to fourth and the $ refers to the end of the expressionNote: if you don't have python you can use an online regex checker like myregextester, note that the string must be at least five characters long because you need one letter at the beginning, at least two characters in the middle and two numbers at the end.
A polymeric extruder is turned on and immediately begins producing a product at a rate of 10 kg/min. An operator realizes 20 minutes later that the production rate is too low, and increases the production rate to an immediate 15 kg/min. An hour later, an emergency causes the outlet valve to rapidly adjust to 1 kg/min. One minute later, the emergency is resolved, and the outlet valve is allowed to rapidly readjust to 10 kg/min. Plot production rate m(t) in kg/min against time t in min. Determine the production rate function m(t) in the time domain, and then determine the Laplace transform of m(t).
Answer:
The plot of the function production rate m(t) (in kg/min) against time t (in min) is attached to this answer.
The production rate function M(t) is:
[tex]m(t)=[H(t)\cdot10+H(t-20)\cdot5-H(t-80)\cdot14+H(t-81)\cdot9]kg/min[/tex] (1)
The Laplace transform of this function is:
[tex]\displaystyle m(s)=[\frac{10+5e^{-20s}-14e^{-80s}+9e^{-81s}}{s}]kg/min[/tex] (2)
Explanation:
The function of the production rate can be considered as constant functions by parts in the domain of time. To make it a continuous function, we can use the function Heaviside (as seen in equation (1)). To join all the constant functions, we consider at which time the step for each one of them appears and sum each function multiply by the function Heaviside.
For the Laplace transform we use the following rules:
[tex]\mathcal{L}[f(x)+g(x)]=\mathcal{L}[f(x)]+\mathcal{L}[g(x)]=F(s)+G(s)[/tex] (3)
[tex]\mathcal{L}[aH(x-b)]=\displaystyle\frac{ae^{-bs}}{s}[/tex] (4)
The term decision support system is a very specific term that implies the same tool, system, and development approach to most developers.
True/False
Answer:
FALSE: decision support system is an information system that supports business or organizational decision-making activities.
Explanation:
Decision support system is an information system that supports business or organizational decision-making activities. While, a computer program or tool that software developers use to create, debug, maintain, or otherwise support other programs and applications is known as software development tool.
Software development approach maybe Agile, Waterfall, Scrum, Extreme programming, Lean and Feature-Driven Development methodologies.
A multilane highway (two lanes in each direction) is on level terrain. The free-flow speed has been measured at 45 mi/h. The peak-hour directional traffic flow is 1300 vehicles with 6% large trucks and buses and 2% recreational vehicles (f_p = 0.95).If the peak-hour factor is 0.85, determine the highway's level of service.
The level of service of a highway is determined by the volume-to-capacity ratio. Using the provided traffic information, we can calculate the highway's capacity and determine its level of service, which ranges from A to F.
Explanation:The level of service of a highway is determined by the volume-to-capacity ratio (V/C ratio).
Given peak-hour directional traffic flow, vehicle types, peak-hour factor, and free-flow speed, we can calculate the capacity of the highway and determine the level of service.
In this case, we would need to calculate the volume of traffic compared to the highway's capacity to determine the level of service, which can range from A to F.
The natural water content of a Boston Blue Clay soil sample was found to be 14.6% through oven drying. It has been calculated that the maximum density for the clay will be obtained when the water content of the soil reaches 21.2%. Compute how many grams of water must be added to each 500 grams of Boston Blue Clay (in its natural state) in order to increase the water content to 21.2%.
Answer:
41.87 grams of water content must be added to each 500 grams of Boston Blue Clay (in its natural state) in order to increase the water content to 21.2%
Explanation:
The natural water content in Boston Clay is 14.6%. Thus, in 500 grams of Boston clay, the amount of water, naturally present will be:
Natural Water Content = 14.6% of 500 grams
Natural Water Content = 0.146 x 500 grams
Natural Water Content = 73 grams
Thus, the amount of dry clay will be:
Dry Clay = 500 grams - 73 grams
Dry Clay = 427 grams
Now, the required water content is 21.2%, and thus, the remaining 78.8% will be the dry clay. The mass of dry clay is calculated to be 427 grams.
If, we let 'X' be the total mass of clay and water content after the water content is increased to 21.2%. Then;
427 grams = 78.8% of X
427 grams = (0.788)X
X = 427 grams/0.788
X = 541.87 grams
Now, the mass of water content added will be equal to the difference between the total mass of clay before addition of water content and total mass of clay after addition of water content.
Water content added = X - 500 grams
Water Content Added = 541.87 grams - 500 grams
Water Content Added = 41.87 grams
A quack is a data structure combining properties of both stacks and queues. It can be viewed as a list of elements written left to right such that three operations are possible:
Answer:
Three operations possible in a quack is QUACKPUSH, QUACKPOP and QUACKPULL.
Explanation:
A quack is a data structure combining properties of both stacks and queues. It can be viewed as a list of elements written left to right such that three operations are possible, these include:
QUACKPUSH(x): add a new item x to the left end of the list; QUACKPOP(): remove and return the item on the left end of the list; QUACKPULL(): remove the item on the right end of the list.Elements in the quack are stored in stacks. The component stacks can be accessed only through the standard stack functions PUSH and POP.
Provide an argument justifying the following claim: The average (as defined here) of two Java ints i and j is representable as an int, regardless of the lower and upper bounds on the value of an int.
Answer:
public static int average(int j, int k) {
return (int)(( (long)(i) + (long)(j) ) /2 );
}
Explanation:
The above code returns the average of two integer variables
Line 1 of the code declares a method along with 2 variables
Method declared: average of integer data type
Variables: j and k of type integer, respectively
Line 2 calculates the average of the two variables and returns the value of the average.
The first of two integers to average is j
The second of two integers to average is k
The last parameter ensures average using (j+k)/2
Universal Containers (UC) has a requirement to expose a web service to their business partners. The web service will be used to allow each business partner to query UC's Salesforce instance to retrieve the status of orders. The business partner should only be allowed access to orders for which the business partner is the fulfillment vendor. The Architect does not want the business partners to utilize the standard APIs and would prefer a custom API be developed. Which three design elements should the Architect consider in order to ensure the data security of the solution?
Answer:
"- Set the Orders object's sharing settings to Private in the Org-Wide Defaults
_Provide each partner with their own Salesforce login set to API Enabled on the profile
-Develop a custom Apex web service using the "With Sharing" keyword"
Explanation:
Universal Containers (UC) has a requirement to expose a web service to their business partners. The web service will be used to allow each business partner to query UC's Salesforce instance to retrieve the status of orders. The business partner should only be allowed access to orders for which the business partner is the fulfillment vendor. The Architect does not want the business partners to utilize the standard APIs and would prefer a custom API be developed. Which three design elements should the Architect consider in order to ensure the data security of the solution?
A. Query the Orders object with Dynamic SOQL based upon the fulfillment ID.
B. Set the Orders object's sharing settings to Private in the Org-Wide Defaults
C. Provide each partner with their own Salesforce login set to API Enabled on the profile.
D. Develop a custom Apex web service with a fulfillment ID input attribute
E. Develop a custom Apex web service using the "With Sharing" keyword.
The above should be a follow up option to the question
The Architect should consider the following design
"- Set the Orders object's sharing settings to Private in the Org-Wide Defaults
_Provide each partner with their own Salesforce login set to API Enabled on the profile
-Develop a custom Apex web service using the "With Sharing" keyword"
There is need for some sharing rule between the architect and the user
List four (or more) issues addressed by Information Assurance that are often not addressed by Information Security.
Answer:
Issues addressed by Information Assurance (AI) that are often not addressed by Information Security:
- Ensures the quality of information
- Ensures reliability of information
- Ensures retrievability of information
- Provides information restoration systems
- Provides an assorted response options for retrieving information
Explanation:
Both, Information Assurance and Information Protection (or Information Security as defined by the NIST), provide preventive measures to uphold information systems´ integrity, confidentiality for protecting personal privacy and proprietary information with authorized restrictions on access and disclosure, and availability, ensuring protection of information systems from unauthorized access, use, disclosure, disruption, modification, or destruction.
Information protection also uses security solutions, like encryption and other technologies. It can be considered as a sub-component of information assurance.
Differentiating both terms can be tricky, as the terms are inherently linked and both aim integrity of information preservation.
In addition to the benefits provided by information protection, information assurance also focuses on data integrity, authenticity, reliability, usability, non-repudiation, confidentiality, availability and timely access to information. It means a broader strategic initiative comprised of a wide range of information protection and management processes.
The rigid bar CDE is attached to a pin support at E and rests on the 30 mm diameter brass cylinder BD. A 22 mm diameter steel rod AC passes through a hole in the bar and is secured by a nut which is snugly fitted when the temperature of the entire assembly is 20oC. The temperature of the brass cylinder is then raised to 50oC while the steel rod remains at 20oC.
Assuming that no stresses were present before the temperature change,
determine the stress in the cylinder.
The stress in the brass cylinder can be calculated using a thermal stress formula that considers the modulus of elasticity, coefficient of linear expansion, and temperature change of the brass. Specific material properties for brass are needed to plug into the formula.
Explanation:The stress in the cylinder can be found by considering that an increase in temperature will cause the brass cylinder BD to expand, while the steel rod AC remains the same length. This will cause an extra stress in the brass cylinder due to the constraints. The stress can be calculated using the formula σ = EαΔT where:
E is the modulus of elasticity for the material, α is the coefficient of linear expansion of the material, and ΔT is the temperature change.In order to use this thermal stress formula, you will need to look up the specific properties for brass in a materials textbook or reliable online resource. Substitute these values into the formula to get the stress in the brass cylinder caused by the temperature change.
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CHALLENGE ACTIVITY 2.8.1: Using constants in expressions. The cost to ship a package is a flat fee of 75 cents plus 25 cents per pound. 1. Declare a const named CENTS_PER_POUND and initialize with 25. 2. Get the shipping weight from user input storing the weight into shipWeightPounds. 3. Using FLAT_FEE_CENTS and CENTS_PER_POUND constants, assign shipCostCents with the cost of shipping a package weighing shipWeightPounds.
Answer:
int CENTS_PER_POUND = 25;
shipWeightPounds = scnr.nextInt();
shipCostCents = (shipWeightPounds * CENTS_PER_POUND) + FLAT_FEE_CENTS;
Explanation:
We declare a constant named CENTS_PER_POUND in the first line of ode as the answer.
scnr.nextInt(); is how we get our imput, then we declare it to shipWeightPounds.
and lastly the math, we get the weight and multiply it by how much the money costs per weight, and then lastly add the flat fee bc its mandatory fee.
Full Code:
import java.util.Scanner;
public class ShippingCalculator {
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
int shipWeightPounds;
int shipCostCents = 0;
final int FLAT_FEE_CENTS = 75;
int CENTS_PER_POUND = 25;
shipWeightPounds = scnr.nextInt();
shipCostCents = (shipWeightPounds * CENTS_PER_POUND) + FLAT_FEE_CENTS;
System.out.println("Weight(lb): " + shipWeightPounds);
System.out.println("Flat fee(cents): " + FLAT_FEE_CENTS);
System.out.println("Cents per pound: " + CENTS_PER_POUND);
System.out.println("Shipping cost(cents): " + shipCostCents);
}
}
While there are many ways to solve this problem, one strategy is to calculate the volume of any metal's unit cell given its theoretical density (Equation 3.8) and atomic weight. What is the volume of the zirconium unit cell in cubic meters?
The volume of a zirconium unit cell, using a theoretical density of 6.52 g/cm³ and an atomic weight of 91.22 g/mol, can be found to be approximately 2.3 x 10-29 m³.
Explanation:To calculate the volume of the zirconium unit cell, we need to know the atomic weight, density, and Avogadro's number. Assuming a theoretical density of 6.52 g/cm³, an atomic weight of 91.22 g/mol, and using Avogadro's number (6.022 x 10²³ atoms/mol), we can use the formula: volume = atomic weight / (density * Avogadro's number).
First, convert the density from g/cm³ to kg/m³, 1 g/cm³ = 1000 kg/m³. So, 6.52 g/cm³ = 6520 kg/m³. Then substitute these values into the formula: volume = 91.22 g/mol / (6520 kg/ m³ * 6.022 x 10²³ atoms/mol) = approximately 2.3 x 10-29 m³.
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Write a simple calculator program. Your program should ask for three things two whole numbers and an operator in the form of an expression like: 3 * 2 Use a select case structure to determine what operation needs to be performed on the two numbers. Your program should handle the arithmetic functions Add, Subtract, Multiply, and Divide (Depending on the operator entered).
Answer:
The solution code is written in Java.
Scanner input = new Scanner(System.in); System.out.print("Enter operator: "); String operator = input.nextLine(); System.out.print("Enter first integer: "); int num1 = input.nextInt(); System.out.print("Enter second integer: "); int num2 = input.nextInt(); int result = 0; switch(operator){ case "+": result = num1 + num2; break; case "-": result = num1 - num2; break; case "*": result = num1 * num2; break; case "/": result = num1 / num2; break; default: System.out.println("Invalid operator"); } System.out.println(result);Explanation:
To ask for the user input for two whole numbers and an operator, we can use Java Scanner class object. Since the input operator is a string, we can use nextLine() method to get the operator string (Line 3). We use nextInt() method to get whole number input (Line 5 & 7).
Next we use the switch keyword and pass the operator into the switch structure to determine which case statement should be executed. For example, if the input operator is "*" the statement "result = num1 * num2; " will run and multiply num1 with num2.
If p is a pressure, V a velocity, and a fluid density, what are the dimensions (in the MLT system) of (a) p/, (b) pV, and (c)p/pV2?
Answer:p=ML^-1T^-2
b)PV=MT^-3
c)P/PV^2=T^2L^-2
Explanation:In dimensions,Mass in kg is represented by M
Length is represented by L in meters.
T represent Time in seconds,s.
Pressure=hpg,h=height or depth In m,a=density=kg/m^3
g=acceleration due to gravity,m/s^2
P=hag=mxkg/m^3 xm/s^2=m^2×kg/m^2×s^2=kgm^-1 s^-2=ML^-1T^-2
B)PV=pressure xvelocity
=ML^-1T^-2×distance/time
ML^-1T^-2×L/T=MT^-3
C)p/pv^2=1/V^2=(time/distance)^2=(T/L)^2=T^2L^-2
A geothermal pump is used to pump brine whose density is 1050 kg/m3 at a rate of 0.3 m3/s from a depth of 200 m. For a pump efficiency of 90 percent, determine the required power input to the pump. Disregard frictional losses in the pipes, and assume the geothermal water at 200 m depth to be exposed to the atmosphere.
Answer:
Input power of the geothermal power will be 686000 J
Explanation:
We have given density of brine [tex]\rho =1050kg/m^3[/tex]
Rate at which brine is pumped [tex]V=0.3m^3/sec[/tex]
So mass of the pumped per second
Mass = volume × density = [tex]1050\times 0.3=315[/tex] kg/sec
Acceleration due to gravity [tex]g=9.8m/sec^2[/tex]
Depth h = 200 m
So work done [tex]W=mgh=315\times 9.8\times 200=617400J[/tex]
Efficiency is given [tex]\eta =0.9[/tex]
We have to fond the input power
So input power [tex]=\frac{617400}{0.9}=686000J[/tex]
So input power of the geothermal power will be 686000 J
BIGMART Supermarket has different ways of awarding discounts to its customers for each purchase they make. An 8 percent discount is given on the total value of the purchase. In addition, a standard loyalty discount is given if customers have a permanent customer ID card. Your program should indicate the amount payable by the customer after the discounts. Identify the inputs that the program requires from these options:
Answer:
d) II and IV . See explanation below.
Explanation:
Assuming the following list of inputs:
I. The discount percentage
II. The total value of the purchase
III. The loyalty-discount amount
IV. The customer ID card number
V. The amount payable after discount
Possible options for the answer:
a) I, II, and III
b) I and III
c) II, IV, and V
d) II and IV
For this case we want to calculate the amount payable by the customer after the discounts.
And for this case is always necessary the value of the purchase so option II is true. The percent of discount is given so then option I is not true since we know this value.
The option III is not required since the discount is based on the info and if the customer have ID card so then this value is not necessary.
For option IV is necessary know the ID card in order to identify if the person have a permanent or non permanent card in order to apply discounts, this information is useful
And for the last option V that's not an input, since represent the output desired.
So then the correct options are II and IV
d) II and IV
Felix has placed some Copper wire (where the official looked up inferred absolute temperature is 234.5 Celsius) 28 gauge wire in a freezer at 15.3 degrees Fahrenheit. He measures the resistance of the COLD wire to be 15.3 ohms. What is the length of the wire in units of feet?
Answer:
2.14 ft
Explanation:
We will use the following equation:
[tex]L = \frac{R_{T} * A}{p_{20C}*(1+\alpha _{20C}*dt ) }[/tex]
Data obtained:
[tex]R_{15.3 F , -9.27 C} = 15.3 ohms\\A_{28-gauge} = 8.2*10^(-8) m^2\\p_{20 C} = 1.723*10^(-6)\\\alpha _{20C} = 0.00393\\ dt = 20 - (-9.27) = 29.28[/tex]
Using the above equation:
[tex]L = \frac{15.3 * 8.2*10^(-8)}{1.723*10^(-6)*(1+0.00393*29.28 ) }\\\\L =0.6530 m = 2.14 ft[/tex]
Explain the conductivity results observed for ionic compounds in the solid state and in aqueous solution.i.Solid ionic compounds don’t have a conductivity because there isn’t any free space. However, in an aqueous solution ionic compounds have free space causing it to be conductive
Answer:
Aqueous solution of ionic compounds conduct electricity while solid ionic compounds don't.
Explanation:
Ionic compound conduct electricity when liquid or in aqueous solution that is resolved in water because the ionic bonds of the compound become weak and the ions are free to move from place to place.
Ionic compounds don't conduct electricity while in solid state because the ionic bonds are to strong and ions cannot move around with lack of space for movement which makes the electric conductivity zero.
Solid ionic compounds don't have any electrical conductivity as they are not free to move. Hence they lack the free space as compared to the molten or aqueous solution where there exist some gaps and pockets.
Since the melting of the ions takes up lots of heat they are in a molten state and such ions can conduct electricity when they are dissolved in water. Hence they can move around freely.The solids ions that dissolve in the water are called electrolytes as compounds such as acids.
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