Consider a composite wall that includes an 8-mm-thick hardboard siding, 40-mm by 170-mm hardwood studs on 0.65-m centers with glass fiber insulation (paper faced, 28 kg/m3 ), and a 12-mm layer of gypsum (vermiculite) wall board. What is the thermal resistance associated with a wall that is 2.5 m high by 6.5 m wide (having 10 studs, each 2.5 m high)?

Answers

Answer 1

Answer:

dimensions and materials information that are provided about composite wall (2.5mx6.5m 10 studs each 2.5m high)

to find:wall thermal resistance=??

properties:

Ka=0.094W/m.K

Kb=0.16W/m.K

Kc=0.17W/m.K

Kd=0.038W/m.K

using isothermal surface assumption:

(La/KaAa)=0.008/0.094(0.65x2.5)

=0.0524K/W

(LB/KbAb)=0.13/0.16(0.04x2.5)

=8.125K/W

(Ld/KdAd)=0.13/0.38(0.6x2.5)

=2.243K/W

core's equivalent resistance is:

Req=(1/Rb+1/Rd)⁻¹

=(1/8.125+1/2.243)⁻¹

=1.758K/W

For total resistance we will find sum of

Rtot=Ra+Req+Rc

=1.854K/W

Whereas 10 studs are used so:

Rtotal=(10x1/Rtot)⁻¹

=0.1854K/W


Related Questions

Select the correct verb form to complete each of the following sentences.Members of the committee ____ issued a mobile phone and one roll of stamps. Neither the CEO nor the CFO _____any recollection of the illegal funds transfer. Mr. Adams and his assistant______ planning to attend the annual technology showcase. The finance committee _______planning their vacations around the annual June meeting.Everything in my home office _____ to stop functioning when I need it the most.

Answers

The correct verb forms to complete the given sentences are:

Members of the committee issued a mobile phone and one roll of stamps.

Neither the CEO nor the CFO has any recollection of the illegal funds transfer.

Mr. Adams and his assistant are planning to attend the annual technology showcase.

The finance committee is planning their vacations around the annual June meeting.

Everything in my home office seems to stop functioning when I need it the most.

In the first sentence, the verb "issued" is correct because it is in the past tense and agrees with the subject of the sentence, "Members of the committee."

In the second sentence, the verb "has" is correct because it is in the present tense and agrees with the subject of the sentence, "Neither the CEO nor the CFO." The verb "has" is also used when the subject is a singular noun that refers to two or more people or things joined by "neither" or "nor."

In the third sentence, the verb "are" is correct because it is in the present tense and agrees with the subject of the sentence, "Mr. Adams and his assistant." The verb "are" is also used when the subject is a plural noun.

In the fourth sentence, the verb "is" is correct because it is in the present tense and agrees with the subject of the sentence, "The finance committee." The verb "is" is also used when the subject is a singular noun that refers to a group of people or things.

In the fifth sentence, the verb "seems" is correct because it is in the present tense and agrees with the subject of the sentence, "Everything in my home office." The verb "seems" is also used to express an opinion or belief.

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For a given set of input values, a NAND gate produces the opposite output as an OR gate with inverted inputs.A. True
B. False

Answers

Answer:

B.

Explanation:

For a given set of input values, A NAND gate produces exactly the same values as an OR gate with inverted inputs.

The truth table  for a NAND gate with 2 inputs is as follows:

0 0    1

0 1     1

1  0    1

1  1    0

The  truth table for an OR gate, is as follows:

0 0    0

0 1     1

1  0    1

1  1     1

If we add two extra columns for inverted inputs, the truth table will be this one:

0 0    1  1       1

0 1     1  0      1

1  0    0  1      1

1  1     0  0     0

which is the same as for the NAND gate, not the opposite, so the statement is false.

This means that the right choice is B.

In the frequency domain, you view a signal whose highest frequency is fH=4.3kHz, and lowest frequency is fL=300Hz. What is the signal’s frequency bandwidth?

Answers

Answer:

[tex]BW=\Delta f= f_H-f_L=4300Hz-300Hz=4000Hz=4kHz[/tex]

Explanation:

Bandwidth is the difference between the upper and lower frequencies in a continuous set of frequencies. The bandwidth may be determined by use of the following formula:

[tex]BW=f_H-f_L\\\\Where:\\\\f_H=Upper\hspace{3}cutoff\hspace{3}frequency=4.3kHz=4300Hz\\f_L=Lower\hspace{3}cutoff\hspace{3}frequency=300Hz[/tex]

Hence the signal’s frequency bandwidth is:

[tex]BW=4300-300=4000Hz=4kHz[/tex]

The car travels along the circular path such that its speed is increased by at = (0.5et ) m/s2 , where t is in seconds. Determine the magnitudes of its velocity and acceleration after the car has traveled s =18 m starting from rest. Neglect the size of the carDetermine the magnitude of its acceleration after the car has traveled s = 18 m starting from rest

Answers

Answer:

acceleration = 24.23 ms⁻¹

Explanation:

Let's gather the data:

The acceleration of the car is given by a = 0.5 [tex]e^{t}[/tex]

The acceleration is the change in the speed in relation to time. In other words:

[tex]\frac{dv}{dt}[/tex] = a = a = 0.5 [tex]e^{t}[/tex]            ...1

Solving the differential equation yields:

v = 0.5 [tex]e^{t}[/tex] + C₁

Initial conditions : 0 = 0.5 [tex]e^{0}[/tex] + C₁

                             C₁ = -5

at any time t, the velocity is: v= 0.5[tex]e^{t}[/tex]- 5

Solving for distance, s = 0. 5[tex]e^{t}[/tex] - 0.5 t - 0.5

                                    18 = 0.5 [tex]e^{t}[/tex] - 0.5 t - 0.5

                                       t = 3.71 s

Substitute t = 3.71 s

                   v= 0.5[tex]e^{t}[/tex]- 5

                     = 19.85 m/s

a = 0.5 [tex]e^{t}[/tex]             ...1

 = 20.3531

an = [tex]\frac{v^{2} }{p}[/tex]

     = [tex]\frac{(19.853)^{2} }{30}[/tex]

     = 13.1382

Magnitude of acceleration = [tex]\sqrt{ (a)^{2} + (an)^{2} }[/tex]

                                            = [tex]\sqrt{(20.3531)^{2} +(13.1382)^{2} }[/tex]

                                            = 24.23 ms⁻¹ Ans

One the eight safety systems that failed was deemed to be ____________.
Select one:
a. political
b. misinterpreted pressure tests to determine whether the well had been sealed
c. the water temperature
d. the weather temperature

Answers

Answer: B. misinterpreted pressure tests to determine whether the well has been sealed.

Explanation:

Pressure test is a non-destructive test carried out to ensure there is integrity of the pressure shell on an equipment that is new or pressure and piping equipment installed earlier that has undergone some repairs.

After a crew carried out a variety of pressure tests to determine whether the well was sealed or not. The results of these tests were misinterpreted, so they thought the well was under control. This caused oil to spill.


Assume that the conversion of energy into mechanical work (at the wheel) in an internal combustion engine is 20%. Calculate gallons of gasoline required to deliver 30 horsepower at the wheel, for one hour. 1 HP = 746 Watts
1 HP for 1 hour is 0.746 kWh
1 Kwh = 3 412 BTU

Answers

Final answer:

To deliver 30 horsepower at the wheel for one hour with a 20% efficient internal combustion engine, approximately 2.88 gallons of gasoline are required.

Explanation:

The question at hand involves calculating the quantity of gasoline required to deliver 30 horsepower (HP) at the wheel for one hour, given that the energy conversion efficiency of an internal combustion engine is 20%. First, understand that 1 HP is equivalent to 746 Watts, and therefore, 30 HP equals 22,380 Watts or 22.38 Kilowatts. Since 1 HP for 1 hour is 0.746 kWh, 30 HP for 1 hour is 22.38 kWh. Knowing the energy content of gasoline and the engine's efficiency will allow us to calculate the required gallons of gasoline.

Given that a gallon of gasoline releases about 140 MJ (or 38.89 kWh) of energy when burned and considering the 20% efficiency, the useful energy per gallon of gasoline is approximately 7.778 kWh. To find out how many gallons of gasoline are needed to produce 22.38 kWh at 20% efficiency, we divide the total required energy output (22.38 kWh) by the useful energy per gallon (7.778 kWh), resulting in approximately 2.88 gallons of gasoline needed.

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