Compared to a blue star in the same local cluster, the surface temperature of a red star is a) greater. b) the same. c) lower. d) not consistently any of these

Answer:

The distance between the charges is 9.5 cm

(c) is correct option

Explanation:

Given that,

Charge [tex]q= 10^{-6}\ C[/tex]

Force F = 1 N

We need to calculate the distance between the charges

Using Coulomb's formula

[tex]F = \dfrac{kq_{1}q_{2}}{r^2}[/tex]

Where, q = charge

r = distance

F = force

Put the value into the formula

[tex]1=\dfrac{9.0\times10^{9}\times(-10^{-6})^2}{r^2}[/tex]

[tex]r=\sqrt{9\times10^{9}\times(-10^{-6})^2}[/tex]

[tex]r=0.095\ m[/tex]

[tex]r= 9.5\ cm[/tex]

Hence, The distance between the charges is 9.5 cm

Answer:

1.637687 x 10¹³ m²

Explanation:

Land area of Russia has been given in the question as

A = land area of Russia = 16,376,870  km²

we know that

1 km = 1000 m

hence

A = land area of Russia = 16,376,870  (1000 m)² = 16,376,870,000,000 m²

A = 16,376,870,000,000 m²

To represent the area in exponent form, we shift the decimal place from right to left until we have one decimal place.

So we get

A = 1.637687 x 10¹³ m²

Answer:

B. The algebraic sum of the two electric potentials is determined at a distance r/2 from each of the charges, making sure to include the signs of the charges.

Explanation:

Total electric potential is the sum of all the electric potential. And because electric potential is a scalar quantity you have to account for the signs.

Answer:

Magnetic field, [tex]B=2.55\times 10^{-14}\ T[/tex]

Explanation:

It is given that,

Speed of proton, [tex]v=4\times 10^6\ m/s[/tex]

Mass of the proton, [tex]m=1.67\times 10^{-27}\ kg[/tex]

Charge on proton, [tex]q=1.6\times 10^{-19}\ C[/tex]

We need to find the magnetic field strength required to just balance the weight of the proton and keep it moving horizontally.

The Lorentz force is given by :

[tex]F=q(v\times B)=qvB\ sin90[/tex].............(1)

The weight of proton,

[tex]W=mg[/tex]..............(2)

From equation (1) and (2), we get :

[tex]mg=qvB[/tex]

[tex]B=\dfrac{mg}{qv}[/tex]

[tex]B=\dfrac{1.67\times 10^{-27}\ kg\times 9.8\ m/s^2}{1.6\times 10^{-19}\ C\times 4\times 10^6\ m/s}[/tex]

[tex]B=2.55\times 10^{-14}\ T[/tex]

Hence, this is the required solution.

Final answer:

The magnetic field strength required to balance the weight of a proton and keep it moving horizontally is 3.07 x 10^-4 Tesla, calculated by setting the magnetic force (qvB) equal to the gravitational force (mg) and solving for B with given values for q, v, m, and g.

Explanation:

To calculate the magnetic field strength required to balance the weight of a proton and keep it moving horizontally, we can use the relationship between the magnetic force and the gravitational force acting on the proton. The magnetic force that will balance the weight of the proton is given by FB = qvB sin(θ), where q is the charge of the proton, v is its velocity, B is the magnetic field strength, and θ is the angle between the velocity and the magnetic field. Because the proton is moving at a right angle to the magnetic field, sin(θ) will be 1.

The weight of the proton (gravitational force) is given by W = mg, where m is the mass of the proton and g is the acceleration due to gravity. Setting the magnetic force equal to the weight gives us:

FB = W
qvB = mg
B = mg/qv

Substituting the given values for mass m = 1.67 x 10-27 kg, charge q = 1.60 x 10-19 C, speed v = 4.00 x 106 m/s, and the acceleration due to gravity g = 9.81 m/s2, we can find the magnetic field strength:

B = (1.67 x 10-27 kg * 9.81 m/s2) / (1.60 x 10-19 C * 4.00 x 106 m/s)
B = 3.07 x 10-4 T

The magnetic field strength required is 3.07 x 10-4 Tesla.

Answer:

Gravitational potential energy = 524.85 kJ

Explanation:

Refer the figure.

Gravitational potential energy = mgh

Mass, m = 75 kg

Acceleration due to gravity, g = 9.81 m/s²

We have

        [tex]sin14.6=\frac{h}{2830}\\\\h=713.36m[/tex]

Gravitational potential energy = 75 x 9.81 x 713.36 = 524854.62 J = 524.85 kJ

Answer:

0.25 m/s

Explanation:

This problem can be solved by using the law of conservation of momentum - the total momentum of the squid-water system must be conserved.

Initially, the squid and the water are at rest, so the total momentum is zero:

[tex]p_i = 0[/tex]

After the squid ejects the water, the total momentum is

[tex]p_f = m_s v_s + m_w v_w[/tex]

where

[tex]m_s = 1.60 kg[/tex] is the mass of the squid

[tex]v_s[/tex] is the velocity of the squid

[tex]m_2 = 0.115 kg[/tex] is the mass of the water

[tex]v_w = 3.50 m/s[/tex] is the velocity of the water

Due to the conservation of momentum,

[tex]p_i = p_f[/tex]

so

[tex]0=m_s v_s + m_w v_w[/tex]

so we can find the final velocity of the squid:

[tex]v_s = -\frac{m_w v_w}{m_s}=-\frac{(0.115 kg)(3.50 m/s)}{1.60 kg}=-0.25 m/s[/tex]

and the negative sign means the direction is opposite to that of the water.

By applying the conservation of momentum, the squid would achieve a speed of about 0.80 m/s in the opposite direction to that of the ejected water.

This problem is related to the principle of conservation of momentum. According to this principle, the total momentum before and after the ejection of the water should be the same, because no external force is acting on this system of the squid and the water it ejects.

The initial momentum of the system is 0, because the squid is initially stationary. When the squid ejects water, it gets a momentum in the opposite direction. Hence,

0 = momentum of squid + momentum of water

or, 0 = (mass of squid × speed of squid) + (mass of ejected water × speed of ejected water),

Solving this equation for the speed of the squid gives:

speed of squid = - (mass of ejected water × speed of ejected water) / mass of squid

Substituting the given values into this equation:

speed of squid = - (0.115 kg × 3.50 m/s) / 1.60 kg ≈ -0.80 m/s.

The negative sign indicates that the squid moves in the opposite direction to that of the ejected water.

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The tension in the rod as the stone moves through the bottom of the circle is 80 N, which is found by applying the principles of conservation of energy and circular motion.

The problem involves the concept of centripetal force and the principle of conservation of energy. When the stone is at the bottom of the circular path, the centripetal force necessary to keep it moving in a circle is provided by the tension, T in the rod and the weight of the stone. The tension can be calculated using the formula for the centripetal force, which is F = m * g + m * v²/r where m is the mass of the stone (2 kg), g is the acceleration due to gravity (approximate 10 m/s²), v is the velocity of the stone and r is the radius of of the circle.

Since the energy at the top of the circle (potential energy) is equal to the energy at the bottom of the circle (kinetic energy + potential energy), and we know that potential energy = m * g * h and kinetic energy = 1/2 * m * v², we can solve for v² = 2 * g * h. Hence, substituting v² in the previous formula, we get T = m * g + m * (2 * g * h)/r. Considering that h=r=1.2m, this simplifies to T = 4 * m * g , which, when evaluated equals 80N. Therefore, the correct answer is (d) 80 N.

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Answer:

Yes

Explanation:

The velocity measured by Jennifer and Johnny is

[tex]v_m = 34.87 m/s[/tex]

The actual velocity is

[tex]v=34.15 m/s[/tex]

We can calculate the % error of the students measurement as follows:

[tex]Err = \frac{v_m - v}{v}\cdot 100 = \frac{34.87 m/s-34.15 m/s}{34.15 m/s}\cdot 100 =0.021 \cdot 100 = 2.1 \%[/tex]

Which is lower than the 2.5% maximum error required, so the two students will pass the test.

Final answer:

Jennifer and Johnny's measurement has a percentage error of approximately 2.11%, which is less than the maximum allowed error of 2.5%. Therefore, they will pass their final project.

Explanation:

To determine if Jennifer and Johnny passed their final project, we need to calculate the percentage error of their measured velocity. The percentage error is calculated using the formula:

Percentage Error = |(Actual Value - Experimental Value) / Actual Value| × 100%

First, let's find the absolute difference between the actual velocity (34.15 m/s) and the measured velocity (34.87 m/s):

|34.15 m/s - 34.87 m/s| = |(-0.72 m/s)| = 0.72 m/s

Now, we calculate the percentage error:

Percentage Error = (0.72 m/s / 34.15 m/s) × 100% ≈ 2.11%

Since the percentage error they obtained (2.11%) is less than the maximum allowed error of 2.5%, Jennifer and Johnny will pass their final project.

you use the formula F=ma to get the answer

Answer:

Instantaneous speed of contact point will be ZERO

Explanation:

As we know that disc is rolling without slipping on horizontal surface

So here the speed of center of the disc is given as

v = 5 m/s

now at the contact point the tangential speed will be in reverse direction

[tex]v_t = R\omega[/tex]

now we know that net contact speed with respect to its lower surface must be zero

[tex]v_{net} = v - v_t = 0[/tex]

so net velocity of contact point with respect to its lower surface must be ZERO here

The instantaneous speed of the point of a disc that is rolling without slipping and makes contact with the surface is zero. This is because that point is momentarily at rest relative to the surface at that instant.

The instantaneous speed of the point of the disc that makes contact with the surface is zero. This is because for a disc rolling without slipping on a surface, the point of contact at any instant is momentarily at rest relative to the surface. This can be understood by imagining the point of contact as the 'pivot' or point about which the disc rotates while rolling. As the disc rolls, the pivot point changes, but whichever point is in contact with the surface at a given instant is not moving relative to the surface. Hence, the instantaneous speed of that point is zero.

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To calculate the deflection at point C of the beam, we can use the deflection equation for beams under a uniformly distributed load and a point load.

To calculate the deflection at point C of the beam, we will use the formula for deflection under a uniformly distributed load and a point load. The deflection equation for beams is given by

δ = (5wL⁴ - PL³) / (384EI)

where δ is the deflection, w is the uniformly distributed load, L is the span length, P is the point load, E is the modulus of elasticity, and I is the moment of inertia of the beam. Substituting the given values into the equation, we can calculate the deflection at point C.

Answer:

Electrical energy consumed, E = 1.95 × 10⁻⁵ kWh  

Explanation:

It is given that,

Power rating on the light bulb, P = 75 W

We need to find the electrical energy consumed by the bulb in 1 second of time i.e in 0.00026 hours.

[tex]P=\dfrac{energy\ consumed}{time}[/tex]

Energy consumed, E = P × t

E = 75 W × 0.00026 h

E = 0.0195 W-h

Energy consumed is calculated in kilo watt hour. Since, 1 watt = 0.001 kW

So, E = 1.95 × 10⁻⁵ kWh  

Hence, this is the required solution.

Answer:

a scientist examines the results and answers the lab question- last choice

Answer:

D. a scientist examines the results and answers the lab question

Answer:

28.2 m/s

Explanation:

The range of a projectile launched from the ground is given by:

[tex]d=\frac{v^2}{g}sin 2\theta[/tex]

where

v is the initial speed

g = 9.8 m/s^2 is the acceleration of gravity

[tex]\theta[/tex] is the angle at which the projectile is thrown

In this problem we have

d = 81.1 m is the range

[tex]\theta=45^{\circ}[/tex] is the angle

Solving for v, we find the speed of the projectile:

[tex]v=\sqrt{\frac{dg}{sin 2 \theta}}=\sqrt{\frac{(81.1 m)(9.8 m/s^2)}{sin (2\cdot 45^{\circ})}}=28.2 m/s[/tex]

Answer:

79.5 m

Explanation:

Let t be the time taken to hit the surface of water and x be the horizontal distance traveled.

use II equation of motion in Y axis direction

h = uy t + 1/2 g t^2

- 60 = - 100 Sin 35 x t - 1/2 x 9.8 x t^2

-60 = - 57.35 t - 4.9 t^2

4.9 t^2 + 57.35 t - 60 = 0

[tex]t = \frac{-57.35\pm \sqrt{57.35^{2} + 4 \times 4.9 \times 60}}{2\times 4.9}[/tex]

By solving we get

t = 0.97 second

The horizontal distance traveled is

x = ux t

x = 100 Cos 35 x 0.97

x = 79.5 m

Final answer:

To find how far from the cliff a projectile hits the water, one must use projectile motion principles to calculate the time of flight based on vertical movement and then determine the horizontal distance traveled during this time.

Explanation:

The question involves calculating how far from the foot of a vertical cliff a projectile hits the water when it is shot from an elevation with a given initial speed and angle. To solve this, we need to use the concepts of projectile motion, specifically focusing on the horizontal distance traveled by a projectile. The key equations involve splitting the initial velocity into its horizontal and vertical components, calculating the time of flight based on the vertical motion, and then using this time to find the horizontal distance traveled.

Given the projectile has a speed of 100 m/s and is fired at an angle of 35.0° below the horizontal from a height of 60.0 m, the calculation involves several steps:

Determine the initial horizontal and vertical velocity components.

Calculate the time of flight using the vertical motion equations.

Finally, compute the horizontal distance traveled using the time of flight.

Due to the complexity and the need for specific formulae and calculations, a detailed step-by-step solution would be necessary to find the exact distance.

Answer:

1.34 seconds

Explanation:

h(t) = 57t - 16t²

Velocity is the derivative of position with respect to time:

v(t) = dh/dt

v(t) = 57 - 32t

When v = 14.25:

14.25 = 57 - 32t

32t = 42.75

t = 1.34

Explanation:

It is given that,

Initial velocity of the bird, u = 13 m/s

Final speed of the bird, v = 10.5 m/s

Time taken, t = 4.20 s

(a) Acceleration of the bird is given by :

[tex]a=\dfrac{v-u}{t}[/tex]

[tex]a=\dfrac{10.5\ m/s-13\ m/s}{4.20\ s}[/tex]

[tex]a=-0.59\ m/s^2[/tex]

So, The direction of acceleration is opposite to the direction of motion.

(b) We need to find the bird’s velocity after an additional 1.50 s has elapsed i.e. t = 4.2 + 1.5 = 5.7 s. Let v' is the new final velocity.

It can be calculated using first equation of motion as :

[tex]a=\dfrac{v'-u}{t}[/tex]

v' = u + at

[tex]v'=(-0.59)\times 5.7+13[/tex]

v' = 9.64 m/s

Hence, this is the required solution.

Answer:

The current in any one of the resistors is 1 A.

Explanation:

It is given that, four 20 ohm resistors are connected in parallel. In parallel combination of resistors, the voltage across each and every resistor is same while the current divides. The equivalent resistance of all resistors is given by :

[tex]\dfrac{1}{R_{eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+\dfrac{1}{R_3}+\dfrac{1}{R_4}[/tex]

[tex]\dfrac{1}{R_{eq}}=\dfrac{1}{20\ \Omega}+\dfrac{1}{20\ \Omega}+\dfrac{1}{20\ \Omega}+\dfrac{1}{20\ \Omega}[/tex]

[tex]R_{eq}=5\ \Omega[/tex]

Current flowing in the entire circuit can be calculated using Ohm's law as :

Current, [tex]I=\dfrac{V}{R_{eq}}[/tex]

[tex]I=\dfrac{20\ V}{5\ \Omega}[/tex]

I = 4 A

Since, in parallel combination current divides. So, current flowing in all four resistor divides and is 1 A. Hence, this is the required solution.

The current in a single 20 Ohm resistor connected in parallel to a 20 V emf device is 1 A. This is calculated using Ohm's law (I = V/R).

The question involves calculating the current in a single resistor when four 20 Ohm resistors are combined in parallel and connected to a 20 V emf device. For resistors in parallel, they share the same potential difference, or voltage. In this case, the emf device provides each parallel resistor with a potential difference of 20 V.

By using Ohm's law, which states that the current through a conductor between two points is directly proportional to the voltage across the two points, the current can be calculated. Ohm's law is typically represented by the formula I = V/R, where I is the current, V is the voltage, and R is the resistance. In this scenario, we can calculate the current as I = 20V/20Ohm which equals 1 A.

So, the current that will flow through any one of the 20 Ohm resistors connected in parallel and connected to a 20 V power supply would be 1 A. The correct answer falls outside the options given and is 1 A.

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(a) The impulse delivered to the ball by the racket is 5.24 kg.m/s

(b) The work that the racket does on the ball is -35.1 Joule

Given :

mass of ball = m = 0.06 kg

initial velocity = v₁ = -50.4 m/s

final velocity = v₂ = 37.0 m/s

Unknown :

(a) Impulse = I = ?

(b) Work = W = ?

Solution :

In this question , we could use the formula from Second Law of Newton :

[tex]I = \Delta p[/tex]

[tex]I = p_2 - p_1[/tex]

[tex]I = m \times v_2 - m \times v_1[/tex]

[tex]I = m \times (v_2 - v_1)[/tex]

[tex]I = 0.06 \times (37.0 - (-50.4))[/tex]

[tex]I = 0.06 \times (87.4)[/tex]

[tex]I = 5.244~kg.m/s[/tex]

[tex]\large { \boxed {I \approx 5.24~kg.m/s} }[/tex]

[tex]W = F \times d[/tex]

[tex]W = (\frac{I}{\Delta t})(\frac {v_1 + v_2}{2} \Delta t)[/tex]

[tex]W = \frac{I(v_1 + v_2)}{2}[/tex]

[tex]W = \frac{5.244(-50.4 + 37)}{2}[/tex]

[tex]W = \frac{5.244(-13.4)}{2}[/tex]

[tex]W = -35.1348~Joule[/tex]

[tex]\large { \boxed {W \approx -35.1~Joule}}[/tex]

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Grade: High School

Subject: Physics

Chapter: Dynamics

Keywords: Newton, Law, Impulse, Work

In this physics problem, we calculate the impulse delivered by the racket to the tennis ball and the work done by the racket on the ball.

The impulse delivered to the ball by the racket:

The work done by the racket on the ball:

1) 5 s

The vertical position of the object is given by

[tex]y(t) = h - \frac{1}{2}gt^2 =  400 - 16 t^2[/tex]

where

h=400 ft represents the initial height

g = 32 ft/s^2 is the acceleration of gravity

t is the time

We want to find the time t at which the object reaches the ground, so the time t at which

y(t) = 0

By substituting this into the equation, we find

[tex]0 = 400 - 16t^2\\t=\sqrt{\frac{400}{16}}=5 s[/tex]

2) 160 ft/s

The object is released from rest, so the initial velocity is zero

u = 0

The final vertical velocity can be found by using

[tex]v^2 - u^2 = 2ah[/tex]

where

v is the final velocity

a = 32 ft/s^2 is the acceleration of gravity

h = 400 ft is the vertical distance covered

Solving for v, we find

[tex]v=\sqrt{u^2 +2ay}=\sqrt{2(32 ft/s)(400 ft)}=160 ft/s[/tex]

Final answer:

The object takes approximately 5 seconds to hit the ground and has an impact velocity of 160 feet per second.

Explanation:

Time to Hit the Ground and Velocity at Impact

To find out how long it takes the object to hit the ground, we need to solve the equation s(x) = 400 - 16x2 for the moment when the height s(x) is zero (s(x) = 0). Setting the equation to zero, we get 0 = 400 - 16x2, which simplifies to x2 = 25 after dividing both sides by 16. Taking the square root of both sides gives us x ≈ 5 seconds, which is the time the object takes to hit the ground.

For the object's velocity at the moment of impact, we use the formula v = gt, where g is the acceleration due to gravity (32 feet per second squared), and t is the time in seconds. Thus, the velocity at impact is v = 32 * 5 = 160 feet per second.

Answer:

Wavelength, [tex]\lambda=\dfrac{c}{f}[/tex]

Explanation:

In an electromagnetic wave both electric and magnetic field propagate simultaneously. Radio waves, microwaves, gamma rays etc are some of the examples of electromagnetic waves.

If f is the frequency of electromagnetic wave, c is the speed of light, then the relationship between the frequency f, wavelength and the speed is given by :

[tex]\lambda=\dfrac{c}{f}[/tex]

Hence, the correct option that shows the wavelength of electromagnetic wave in free space is(a) " c/f ".

Answer:

[tex]P_1 - P_2 = 2295 pascal[/tex]

Explanation:

As we know by Bernoulli's principle

[tex]P_1 + \frac{1}{2}\rho v_1^2 = P_2 + \frac{1}{2}\rho v_2^2[/tex]

[tex]P_1 - P_2 = \frac{1}{2}\rho v_2^2 - \frac{1}{2} \rho v_1^2[/tex]

here we know that

[tex]\rho = 1000 kg/m^3[/tex]

also we know that

[tex]v_1 = 2.1 m/s[/tex]

[tex]v_2 = 3 m/s[/tex]

now we have

[tex]P_1 - P_2 = \frac{1}{2}(1000)(3.0^2 - 2.1^2)[/tex]

[tex]P_1 - P_2 = 2295 pascal[/tex]

To find the pressure difference between two points in a pipe, we can use Bernoulli's equation. Bernoulli's equation states that the sum of the pressure, kinetic energy, and potential energy per unit volume of a fluid remains constant along a streamline.

To find the pressure difference between two points in a pipe, we can use Bernoulli's equation. Bernoulli's equation states that the sum of the pressure, kinetic energy, and potential energy per unit volume of a fluid remains constant along a streamline. In this case, since the pipe is horizontal and we neglect friction, the potential energy term can be ignored. So we are left with:

P1 + 1/2ρv12 = P2 + 1/2ρv22

Where P1 and P2 are the pressures at the entrance and exit respectively, ρ is the density of the fluid, and v1 and v2 are the velocities at the entrance and exit respectively.

Using the given values, we can calculate the pressure difference.

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(a) [tex]4.14 rad/s^2[/tex]

The relationship beween centripetal acceleration and angular speed is

[tex]a=\omega^2 r[/tex]

where

[tex]\omega[/tex] is the angular speed

r is the radius of the circular path

Here we gave

[tex]a = 9g = 88.2 m/s^2[/tex] is the centripetal acceleration

r = 5.15 m is the radius

Solving for [tex]\omega[/tex], we find:

[tex]\omega = \sqrt{\frac{a}{r}}=\sqrt{\frac{88.2 m/s^2}{5.15 m}}=4.14 rad/s^2[/tex]

(b) 21.3 m/s

The relationship between the linear speed and the angular speed is

[tex]v=\omega r[/tex]

where

v is the linear speed

[tex]\omega[/tex] is the angular speed

r is the radius of the circular path

In this problem we have

[tex]\omega=4.14 rad/s[/tex]

r = 5.15 m

Solving the equation for v, we find

[tex]v=(4.14 rad/s)(5.15 m)=21.3 m/s[/tex]

Explanation:

(a) Centripetal acceleration, [tex]a=9g=88.2\ m/s^2[/tex]

Radius, r = 5.15 m

Let [tex]\omega[/tex] is the angular speed. The relation between the angular speed and angular acceleration is given by :

[tex]a=\omega^2 r[/tex]

[tex]\omega=\sqrt{\dfrac{a}{r}}[/tex]

[tex]\omega=\sqrt{\dfrac{88.2}{5.15}}[/tex]

[tex]\omega=4.13\ rad/s[/tex]

(b) Let v is the linear speed of the person in the centrifuge have at this acceleration. It is given by :

[tex]v=r\times \omega[/tex]

[tex]v=5.15\times 4.13[/tex]

v = 21.26 m/s

Hence, this is the required solution.

Answer:

(a) 5.725 Ω

(b) 1.3 Ω

Explanation:

(a)

E = emf of the battery = 15.0 Volts

V = terminal voltage of the battery = 12.2 Volts

P = Power delivered to external load resistor "R"  = 26.0 W

R = resistance of external load resistor

Power delivered to external load resistor is given as

[tex]P = \frac{V^{2}}{R}[/tex]

26.0 = 12.2²/R

R = 5.725 Ω

(b)

r = internal resistance of the battery

i = current coming from the battery

Power delivered to external load resistor is given as

P = i V

26.0 = i (12.2)

i = 2.13 A

Terminal voltage is given as

V = E - ir

12.2 = 15 - (2.13) r

r = 1.3 Ω

Final answer:

The external load resistor R is calculated to be 5.72 Ohms using the power and terminal voltage, and the internal resistance of the battery is 1.31 Ohms as determined from the emf, terminal voltage, and the current flowing through R.

Explanation:

To solve for external load resistor R and the internal resistance of the battery, we can use the formulas related to electric power and the relation between emf, terminal voltage, and internal resistance.

(a) Value of R:

The power delivered to the resistor (P) is given by:

P = V2 / R

Where V is the terminal voltage and R is the resistance.

Substituting the given values:

26.0 W = (12.2 V)2 / R

Hence, R = (12.2 V)2 / 26.0 W = 5.72 Ω (Ohms)

(b) Internal resistance of the battery:

We know that terminal voltage V is emf - (current * internal resistance).

The current I flowing through R can be calculated using the power:

I = P / V = 26.0 W / 12.2 V = 2.13 A

Now, using the emf (E) of the battery and terminal voltage (V):

E = V + Ir

15.0 V = 12.2 V + (2.13 A × r)

We solve for r, the internal resistance:

r = (15.0 V - 12.2 V) / 2.13 A = 1.31 Ω (Ohms)

Answer:

176.4 m

Explanation:

U = 0, t = 6s, g = 9.8 m/s^2

Use second equation of motion

H = ut + 1/2 gt^2

H = 0 + 0.5 × 9.8 × 6 × 6

H = 176.4 m

It is the displacement from the point of dropping of object.

Answer:

The angular acceleration is [tex]0.209\ rad/s^2[/tex]

Explanation:

Given that,

Angular velocity, [tex]\omega_{i} = 30.0\ rpm[/tex]

Angular velocity, [tex]\omega_{f} = 50.0\ rpm[/tex]

Time t = 10.0 sec

We need to calculate the angular acceleration

Using formula of angular acceleration

[tex]\alpha=\dfrac{\Delta \omega}{\Delta t}[/tex]

[tex]\alpha=\dfrac{\omega_{f}-\omega_{i}}{\Delta t}[/tex]

[tex]\alpha=\dfrac{50.0-30.0}{10.0}[/tex]

Now, we change the angular velocity in rad/s.

[tex]\omega=20\times\dfrac{2\pi}{60}[/tex]

[tex]\omega=2.09\ rad/s[/tex]

[tex]\alpha=\dfrac{2.09}{10.0}[/tex]

[tex]\alpha=0.209\ rad/s^2[/tex]

Hence, The angular acceleration is [tex]0.209\ rad/s^2[/tex]

Answer:

The rate of angular acceleration is 0.209 rad/s²

Explanation:

the solution is in the attached Word file

Answer:

Density of meteorite = 2.44 g/cm³

Explanation:

Apparent mass = Mass of solid - Mass of water displaced

Mass of water displaced = Mass of solid - Apparent mass

                                         = 15.6 - 9.2 = 6.4 g

Density of water = 1 g/cm³

Volume of water displaced [tex]=1\times 6.4=6.4cm^3[/tex]

Volume of meteorite = Volume of water displaced = 6.4 cm³

[tex]\texttt{Density of meteorite}=\frac{\texttt{Mass of meteorite}}{\texttt{Volume of meteorite}}=\frac{15.6}{6.4}=2.44g/cm^3[/tex]

Density of meteorite = 2.44 g/cm³

This is true. The victim could be too embarrassed and would not want others to know because people could bash her for that.

If a victim of sexual harassment asks a supervisor not report it, the supervisor should respect his or her wishes is False.

If a victim of sexual harassment asks a supervisor not to report it, the supervisor should not automatically respect their wishes. It is essential to prioritize the safety and well-being of the victim and address the issue appropriately.

Sexual harassment is a serious and unlawful matter, and supervisors have a legal and ethical obligation to address and report such incidents following company policies and the law.

Reporting incidents of sexual harassment is crucial for investigating the matter, providing support to the victim, and taking appropriate actions to prevent further harassment and protect the well-being of employees.

Supervisors should follow their organization's policies and procedures for handling harassment complaints and ensure that victims are treated with sensitivity and respect throughout the process. Confidentiality should be maintained to the extent possible, but it should not prevent the necessary actions to address and resolve the issue effectively.

Hence, If a victim of sexual harassment asks a supervisor not report it, the supervisor should respect his or her wishes is False.

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Answer:

-220 rad/s²

Explanation:

ω² = ω₀² + 2α(θ - θ₀)

We're given that ω = 0 rev/min, ω₀ = 3700 rev/min, and θ - θ₀ = 54.0 rev.

Converting to rad/s:

0 rev/min × (2π rad / rev) × (1 min / 60 s) = 0 rad/s

3700 rev/min × (2π rad / rev) × (1 min / 60 s) = 123⅓π rad/s

54.0 rev × (2π rad / rev) = 108π rad

Plugging in:

(0 rad/s)² = (123⅓π rad/s)² + 2α(108π)

α = -221.2 rad/s²

There's 2 significant figures in 3700 rev/min, so we need to round our answer to 2 sig figs.  The angular acceleration is -220 rad/s².

Answer:

B

Explanation:

Use conservation of momentum: Total momentum of the system before is the same as the total momentum after the collision. Since both are moving north, the momentum of both cars is in the same direction, and the total momentum before collision is 1000kg*20m/s + 1500kg*36m/s = 74000kg-m/s.

This is the same amount of momentum after collision, and since they are locked together, their mass is added. The velocity can be found by: 74000kg-m/s ÷ 2500kg = 29.6m/s.

momentum = mass*velocity

The velocity of the two cars combined, immediately after the collision, can be determined by conserving the total momentum before the collision. This velocity is 29.6 m/s north.

This problem is about the conservation of momentum in a collision. Momentum before the collision is the total of the momentum of the two cars combined. We can calculate this using the formula 'momentum = mass x velocity'. For the 1000-kg car it's (1000 kg)x(20 m/s) = 20000 kg.m/s and for the 1500-kg car, it's (1500 kg)x(36 m/s) = 54000 kg.m/s. The total momentum before the collision is 20000 + 54000 = 74000 kg.m/s.

After the collision, the two cars move together, meaning the total mass is now 1000 + 1500 = 2500 kg. The question asks for the velocity (v) of the cars immediately after the collision. As the total momentum must be conserved, we can find this velocity using the formula 'momentum = total mass x velocity'. So, 74000 = (2500 kg) x v. To solve for v, we divide 74000 by 2500. Doing this gives v = 29.6 m/s. Therefore, the velocity of the cars immediately after the collision is 29.6 m/s north.

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