Car drag racing takes place over a distance of a 1 4 mile (402 m) from a standing start. If a car (mass 1500 kg) would be propelled forward with a pulling force equal to that of gravity, what would be the change in kinetic energy and the terminal speed of the car (in mph) at the end of the race be?

Answer:

4.8063m

Explanation:

Horzontal range is given by the formula;

R=(u²sin2θ)/g

u=7m/s,  θ=53°, g=9.8m/s

[tex]R=\frac{7^{2}sin2*53 }{9.8}[/tex]

[tex]R=\frac{7^{2}sin106 }{9.8}[/tex]

[tex]R=\frac{49*sin2*53 }{9.8}[/tex]

[tex]R=\frac{47.102 }{9.8}[/tex]

R=4.8063m

A rock thrown at an angle of 53 degrees with an initial speed of 7.0 m/s from a 50-m-height cliff will hit the ground approximately 8.3 meters away from the base of the cliff.

The problem regards the range of a projectile which is given by the formula R = (v²/g) * sin(2*Theta), where v is the initial velocity, g is the acceleration due to gravity, and Theta is the launch angle. Given the initial velocity v = 7.0 m/s, launch angle Theta = 53 degrees, and g = 9.8 m/s², it's a matter of substituting these values into the range formula: R = ((7.0 m/s)² / 9.8 m/s²) * sin(2 * 53 degrees).

After performing the calculations, you obtain that the rock will hit ground approximately 8.3 meters away from the base of the cliff.

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Answer:increased

Explanation:

It is given that elevator speed is increasing while moving upward i.e.its acceleration is increasing .

This causes the apparent to be increased if measured using weighing machine.

considering upward direction to be positive

N-mg=ma

N=m(g+a)

where N=Normal reaction=Apparent weight

a=acceleration of Elevator

thus you feel as if your weight is increased.

When an elevator accelerates upwards, your weight feels heavier due to the additional force pushing you into the floor.

Acceleration is the rate of change of an object's velocity with respect to time. It is a vector quantity, measured in meters per second squared in the International System of Units (SI). Acceleration can be positive (speeding up), negative (slowing down), or zero (constant velocity), and it plays a crucial role in describing the dynamics of motion.

When an elevator starts moving upwards with increasing speed, your weight will feel heavier compared to when the elevator is at rest. This increase in weight is due to the upward acceleration experienced by both you and the elevator. The force of gravity acting on your body remains the same, but now there is an additional force pushing you against the floor of the elevator, resulting in the feeling of increased weight.

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Answer:

Explanation:

Given

Diameter [tex]d=40\ m[/tex]

radius [tex]r=20\ m[/tex]

From diagram, at top point

If Normal force is equal to Gravitational force

[tex]N=mg[/tex]

where N=normal reaction

m=mass of car

Normal reaction will provide centripetal force

[tex]N=\frac{mv^2}{r}[/tex]

thus

[tex]\frac{mv^2}{r}=mg[/tex]

[tex]v=\sqrt{2gr}[/tex]

[tex]v=\sqrt{2\times 9.8\times 20}[/tex]

[tex]v=19.79\ m/s[/tex]              

The speed of a roller coaster car at the top of a 40-m-diameter loop, when the normal force equals the gravity, is 20 m/s.

The question asks for the speed of a roller coaster car at the top of the loop. In this scenario, it is said that the normal force equals the magnitude of the gravitational force. The normal force is the force exerted by a surface to support the weight of an object resting on it. When the roller coaster car is at the top of the loop, the gravitational force (Fg) and normal force (Fn) are acting in the same direction and their sum provides the necessary centripetal force (Fc) for the car to continue its circular motion.

Therefore, we have Fn + Fg = Fc, but as it's mentioned Fn = Fg, so it will be 2Fn = mv²/r. Here, Fn=mg so we can replace it to the equation which is 2mg = mv²/r. Because 'm' (mass) is on both sides of the equation, we can eliminate it, which leaves 2g = v²/r. Rearranging the equation to solve for 'v' (velocity) gives v = square root of (2gr). Given that g (gravity) = 9.8 m/s² and r (radius) = 20 m (half of the 40 m diameter), we solve the equation: v = square root of (2 * 9.8 m/s² * 20 m) = 20 m/s.

Therefore, the roller coaster's speed at the top of a 40-m-diameter loop is 20 m/s.

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Final answer:

The gravitational acceleration on planet X is approximately 34.4 m/s².

Explanation:

The gravitational acceleration on planet X can be determined using the equation:

g = (G * M) / r^2

Where:
g is the gravitational acceleration
G is the gravitational constant (approximately 6.674 × 10^-11 N m^2/kg^2)
M is the mass of the planet
r is the radius of the planet

Since the diameter of planet X is 3 times the diameter of Earth, its radius would be 1.5 times that of Earth. The mass of planet X is 30 times the mass of Earth.

Let's assume the radius of Earth (rE) is 6371 km and the mass of Earth (ME) is 5.972 x 10^24 kg.

Using these values, the radius of planet X (rX) would be 1.5 * rE = 9556.5 km, and the mass of planet X (MX) would be 30 * ME = 1.7916 x 10^26 kg.

Now, we can plug these values into the equation to calculate the gravitational acceleration on planet X:

gX = (G * MX) / rX^2

gX = (6.674 x 10^-11 N m^2/kg^2 * 1.7916 x 10^26 kg) / (9556.5 km)^2

Converting km to meters and solving for gX gives us approximately 34.4 m/s².

Answer:

Decreases fundamentally for getting positive charge and increases in case of obtaining a negative charge.

Explanation:

As we know that the basic elemental unit of charge is an electron. All the charges are fundamentally quantized in multiples of an electron charge.

So, whenever a neutral object is charged, it either looses electron to  get a positive charge or gains electron to be negatively charged and precisely electron has some mass so there is change in the mass of the object at microscopic level when it gets charged.

Answer:

The answer is h/4

Explanation:

When Peter collides with Fred, the collision is inelastic & they both proceed with a velocity of V/2.

let m represent the masses for Peter & Fred

v represent the initial velocity of Peter

V represent final velocity of both of them

mv + 3m × 0 = (m+m)V

V = v/2

Using the expression; H = v² / 2g .............Eqn 1

Upon substitution of V/2 into Eqn 1 above,

H = (V/2)² / 2g

H = (V²/4) ÷ 2g

Therefore height will be h/4

Final answer:

In a semi-circular halfpipe scenario, Peter starting from rest at a height h and colliding with Fred will result in an inelastic collision, where they would not reach the initial height h due to the combined mass and shared kinetic energy post-collision.

Explanation:

The question you are asking regards a physical scenario involving conservation of energy and momentum in a skateboarding situation. When Peter, starting from rest at a height h, collides with Fred, who is at the bottom, the collision will exchange energy and momentum between the two. Assuming they have the same mass and the collision is perfectly inelastic (they stick together), they will move together with a combined mass of 2m (where m is the individual mass of Peter or Fred) and reach a new height that is less than h.

Based on the conservation of energy, because there are no external forces doing work (ignoring friction and air resistance), the potential energy at the initial height h will be equal to the kinetic energy at the bottom of the halfpipe. In an inelastic collision where the two objects stick together, they move with a common velocity after the collision. Since the kinetic energy after the collision must be shared by both masses, the combined system must have less kinetic energy per unit mass than Peter did alone before the collision, therefore, they won't reach the original height h.

Answer:

Direction

Explanation:

The arrival of seismic waves namely P and S wave are essential as it helps in the determination of the distance from the recording seismic station. In order to cover all the possibilities that are related to an earthquake, seismologists draw a circle around the station but this does not help in obtaining the proper information. By the use of two seismic stations, it can draw two circles that intersect at two points, which again does not help in determining the exact epicenter location. So, at least three seismic stations are needed, by which the triangulation method can be implemented, and as the three circles drawn from the three seismic stations intersect at one common point, it represents the exact location of the earthquake epicenter, and the exact direction also is obtained from this.

Answer:

technician A.

Explanation:

Commonly,  air pressure rating of standard shop air compressor's is between the range of 100 psi and 150 psi. And over the years since, the plant pressure creep's up , the level of pressure increases from 100 psi to at max 150 psi but not more than that. Therefore, in the given question technician A is correct and technician B is incorrect.

The altitude of a geosynchronous orbit is [tex]3.59\cdot 10^7 m[/tex]

Explanation:

A geostationary (or geosynchronous) orbit is the orbit of a satellite that stays over the same spot on the equator of the rotating Earth.

This means that the period of a geostationary satellite is equal to the period of rotation of the Earth, which is 24 hours:

[tex]T=24 h \cdot 3600 s/h = 86400 s[/tex]

We can find the altitude of the orbit in the following way. First, we notice that the orbital speed of the satellite is given by

[tex]v=\frac{2\pi r}{T}[/tex]

where r is the radius of the orbit.

Then we also notice that the gravitational force between the satellite and the Earth is equal to the centripetal force, so we can write:

[tex]\frac{GMm}{r^2}=m\frac{v^2}{r}[/tex]

where

G is the gravitational constant

M is the mass of the Earth

m is the mass of the satellite

Re-arranging the equation,

[tex]\frac{GM}{r}=v^2[/tex]

And substituting the expression for the velocity,

[tex]\frac{GM}{r}=(\frac{2\pi r}{T})^2=\frac{4\pi^2 r^2}{T^2}[/tex]

Solving for r,

[tex]r=\sqrt[3]{\frac{GMT^2}{4\pi^2}}[/tex]

And substituting:

[tex]G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}\\M=5.98\cdot 10^{24} kg\\T=86400 s[/tex]

we find:

[tex]r=\sqrt[3]{\frac{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})(86400)^2}{4\pi^2}}=4.225\cdot 10^7 m[/tex]

And since the radius of the Earth is

[tex]R=6.37\cdot 10^6 m[/tex]

The altitude of the satellite is

[tex]h=r-R=4.225\cdot 10^7 - 6.37\cdot 10^6 = 3.59\cdot 10^7 m[/tex]

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A satellite in a synchronous orbit stays over a certain spot on the equator as the Earth rotates beneath it. The altitude of a synchronous orbit can be calculated using the formula: altitude = (radius of the Earth) + (height of the geostationary orbit), which gives an altitude of approximately 42,157 kilometers.

In order for a satellite to stay over a certain spot on the equator of Earth, it needs to be in a synchronous orbit. A synchronous orbit is an orbit in which the satellite's orbital period matches the rotation period of the Earth. This means that the satellite stays above the same spot on the equator as the Earth rotates beneath it.

The altitude of a synchronous orbit can be determined using the formula:

altitude = (radius of the Earth) + (height of the geostationary orbit)

The radius of the Earth is approximately 6,371 kilometers, and the height of the geostationary orbit is approximately 35,786 kilometers. So the altitude of a synchronous orbit is:

altitude = 6,371 km + 35,786 km = 42,157 km

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Final answer:

All of the options mentioned are obstacles to creating computer-based models for tracking a hurricane. Hurricanes form over water, making them difficult to observe accurately, most sources of data about hurricanes are anecdotal and unreliable, and forecasters need to consider a large number of variables that affect the path of the storm.

Explanation:

All of the above options are obstacles to creating computer-based models for tracking a hurricane.

Hurricanes form over water, making them difficult to observe accurately. Most sources of data about hurricanes are anecdotal and unreliable, which poses a challenge for accurate modeling. Additionally, forecasters need to consider a large number of variables that affect the path of the storm, such as wind speed, atmospheric pressure, and temperature.

Answer:

The Solar Nebula theory

Explanation:

The solar nebula theory describes the origin and formation of the solar system. It explains how the solar system originated from a gaseous cloud, that was comprised of interstellar dust particles and gases. From this giant cloud, the sun formed at the center, and the rest of the planets were formed by the process of condensation. These planets gradually started to rotate and revolve around the sun and were controlled within an elliptical or circular path due to the presence of a strong gravitational force of attraction.

This solar system was constructed in a spiral arm of the huge milky way galaxy.

This solar nebula theory was the ancient accepted theory for the formation of the solar system.

The scientific theory for the origin of our solar system is the nebular hypothesis, which states that the Sun and the planets formed from the collapse of a giant cloud of gas and dust called a nebula.

The scientific theory for the origin of our solar system, involving the condensation and collapse of interstellar material in a spiral arm of the Milky Way galaxy, is the nebular hypothesis. According to this hypothesis, the Sun and the planets of our solar system formed about 4.6 billion years ago from the collapse of a giant cloud of gas and dust, called a nebula. The material in the nebula gradually came together due to gravity, forming a spinning disk. Within this disk, smaller clumps of matter called planetesimals started to form, which eventually coalesced to form the planets and moons.

Answer:

1. Lower Barometric Pressure

2. Aerobic exercise

3. Basal Metabolic Rate Increase

4. improvements in some short duration sea-level performances

5. Vomiting,   insomnia , dyspnea,   nausea, and headache

Explanation:

1. Lower Barometric Pressure

-Hypobaric environment of the particular altitude

-Low atmospheric pressure or Hypobaria

Reduced atmospheric pressure

- Reduced PO2  air breathed in

Reduced PO2 

-Caps pulmonary oxygen diffusion from the lungs

-Restricts O2 transport to the tissues

Low PO2 content in the air

-Also known as hypoxia

Hypoxia

-Low O2

Associated Low PO2 in the blood

-Hypoxemia

2. what types of exercise are detrimentally influenced by exposure to high altitude and why

aerobic exercise

The oxygen requirements of aerobic exercise leads to increased heart rate and , resulting tiredness within a short period of time

3. When someone ascends to an altitude of over 1500 m, describe the physiological adjustments that occur within the first 24 h

-  Basal Metabolic Rate Increase

-  Arterial PO2 Reduction

- Progressive Decrease In Blood plasma volume 

- Blood pH increases

- Decreases in Pressure Gradient   

- Drop in Alveolar PO2  

- Increases in Ventilation 

4. Describe the theoretical advantage of living high and training low

The logic  in this system is that acclimatising the body to altitude by living there, and maintaining  training intensity  by training at sea level provides the harnessing of the gains of altitude exposure and avoiding some of the negative effects of altitude exposure. There are improvements in some short duration sea-level performances by keeping to the above technique. 

5. Vomiting,   insomnia , dyspnea,   nausea, and headache

Consider the ascent rate, the altitude intended to be ascended, and the experience of the individual with the altitude to reduce the likelihood for symptoms to manifest. 

At high altitudes, low oxygen levels can lead to acute mountain sickness and limit sustained aerobic exercise. Physiological adjustments such as increased breathing rate (hyperpnea) and red blood cell production occur within the first 24 hours, and 'living high, training low' offers competitive advantages by leveraging acclimatization benefits. Acute high altitude exposure risks can be mitigated through gradual ascent, hydration, and avoiding strenuous activity.

Conditions at high altitudes can significantly impede physical activity due to the low partial pressure of oxygen, which leads to low blood and tissue levels of oxygen. Acute mountain sickness (AMS) is a potential consequence of such exposure, marked by symptoms like headaches, disorientation, and nausea. These can become more severe during physical exertion, underlining the importance of acclimatization.

Exercise types that involve sustained aerobic performance, like endurance running or cycling, are especially detrimentally influenced at high altitudes. The availability of oxygen is crucial for aerobic respiration, and with less oxygen available, performance can drop significantly.

Within the first 24 hours of ascending to over 1,500 m, physiological adjustments occur, including an increase in breathing rate (hyperpnea) and depth to compensate for lower oxygen levels, a phenomenon also known as hyperventilation. Over days to weeks, the body starts to produce more red blood cells, improving the oxygen-carrying capacity of the blood.

The theoretical advantage of living high and training low centers around the physiological benefits of acclimatization, such as increased red blood cell count, while still being able to train at peak capacity at lower altitudes with more oxygen available.

Health risks associated with acute exposure to high altitudes include AMS, cerebral edema, and pulmonary edema. Minimizing these risks involves a gradual ascent to allow for acclimatization, staying hydrated, and avoiding over-exertion.

Answer:

735.56 K

Explanation:

Carnot Engine: A Carnot engine is a an engine that operates on Carnot cycle.

A Carnot cycle: is defined as an ideal reversible closed thermodynamic operation, in which there are four successive and reversible cycles. These operations include isothermal expansion, adiabatic expansion, isothermal compression, and adiabatic compression.

The efficiency of a Carnot engine is given below,

η=(Th-Tc)/Th.................................................... Equation 1

η = 1-(Tc/Th)........................................ Equation 2

Where Th = temperature of the hot reservoir, Tc = temperature of the cold reservoir, η = efficiency of the Carnot engine.

Given: Th = 331 K, η = 0.55

Substitute into equation 2

0.55 = 1-(331/Th)

0.55-1 = -331/Th

-0.45 = -331/Th

331/Th = 0.45

Th = 331/0.45

Th = 735.56 K.

Thus the temperature of the hot reservoir is 735.56 K.

To determine the hot reservoir temperature required for a Carnot engine to operate with a given efficiency, you can use the equation ηc = 1 - Tc/Th, where ηc is the engine's efficiency, Tc is the cold reservoir temperature, and Th is the hot reservoir temperature. Given an engine efficiency of 0.55 and a cold reservoir temperature of 331K, you can rearrange the equation to solve for the hot reservoir temperature.

The efficiency of a Carnot engine is given by the equation ηc = 1 - Tc/Th, where ηc is the engine's efficiency, Tc is the temperature of the cold reservoir, and Th is the temperature of the hot reservoir. Given that the engine's efficiency (ηc) is 0.55 and the cold reservoir temperature (Tc) is 331K, you can rearrange the equation to solve for the hot reservoir temperature (Th):

Th = Tc / (1 - ηc)

Substituting the given values into this equation yields the hot reservoir temperature required for the engine to operate with an efficiency of 0.55.

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The problem is about the conservation of linear momentum in a collision between two basketball players. The combined momentum before the collision equals the combined momentum after the collision. By setting these two equal and solving for the unknown, we find the velocity of the 87.2 kg player after the collision.

In this problem, we are dealing with the conservation of linear momentum. The combined momentum of the two basketball players before the collision should equal the combined momentum after the collision given that no external forces are acting on the system.

Before the collision, the momentum is calculated as the mass of the 1st player times her velocity (87.2 kg x 7.0 m/s in the positive direction) plus the mass of the 2nd player times his velocity (102.0 kg x 5.2 m/s in the negative direction, because he is moving in the opposite direction).

After the collision, the momentum equals the mass of the 2nd player times his velocity (102.0 kg x -2.9 m/s) plus the mass of the 1st player times her final velocity (87.2 kg x v, where v is the velocity we're trying to find).

Setting these two expressions for momentum equal to one another and solving for v, we find the velocity of the 87.2 kg player after the collision.

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The resulting velocity of the 87.2 kg basketball player after the collision is calculated to be approximately 4.3 m/s in the positive direction.

To solve this problem, we use the principle of conservation of momentum. The total momentum before and after the collision must be the same.

The initial velocities and the masses of the players are:

Player 1: mass (m₁) = 87.2 kg, running at velocity (u₁) = 7.0 m/s in the positive direction

Player 2: mass (m₂) = 102.0 kg, running at velocity (u₂) = -5.2 m/s (toward the first player)

Therefore, the initial momentum of the system will be:

m₁ u₁ + m₂ u₂ = 87.2 kg × 7.0 m/s + 102.0 kg × (-5.2 m/s) = 80 kgm/s    -(i)

After the collision:

Player 2 ends up moving with velocity (v₂) = -2.9 m/s (knocked backward)

We have to find the velocity of the Player (1) given as v₁.

Therefore, the final momentum of the system will be:

m₁ v₁ + m₂ v₂ = 87.2 kg × v₁ + 102.0 kg × (-2.9 m/s) = (87.2 v₁ - 295.8) kgm/s    -(ii)

According to the principle of conservation of momentum, the initial momentum of the system before collision and the final momentum of the system after collision should be the same. So, equations (i) and (ii) must be equal:

80 kgm/s = (87.2 v₁ - 295.8) kgm/s

375.8 kgm/s = 87.2 v₁ kgm/s

or, v₁ = 375.8 kgm/s ÷ 87.2 kg = 4.3 m/s

Final answer:

To find the angular acceleration of a falling pencil, use the equation angular acceleration = gravitational acceleration * sin(theta) / length. Plug in the provided values and solve for angular acceleration. With the given angle and assuming a pencil length, the angular acceleration is 1.07 rad/s^2.

Explanation:

To find the angular acceleration of a falling pencil, we can use the equation:

[angular acceleration = gravitational acceleration * sin(theta) / length].

Given that the angle is 10.0 degrees and the length of the pencil is not provided, we can assume a typical length of a pencil (15 cm). The gravitational acceleration can be taken as 9.8 m/s^2. Plugging in these values into the formula, we get:

[angular acceleration = 9.8 m/s^2 * sin(10.0 degrees) / 0.15 m].

Simplifying the equation, we get angular acceleration = 1.07 rad/s^2.

Answer:

he diameter of the oil slick is 2523 m

Explanation:

given information?

V = 1 L = 1000 cm³ = 0.001 m³

h = 2 x 10⁻¹⁰ m

first we have to find the radius using the following equation

V = πr²h

r = √V/(πh)

  = √(0.001)/(π x 2 x 10⁻¹⁰ )

  = 1261.56 m

now, we can calculate the diameter of the oil slick

d = 2r

  = 2 (1261.56)

  = 2523 m

To estimate the diameter of oil slick, we can calculate the volume of one oil molecule and then divide the total volume of the spilled oil by the volume of one molecule. The diameter of the oil slick would be the diameter of one molecule multiplied by the square root of the number of oil molecules.

To estimate the diameter of the oil slick, we can first calculate the volume of one oil molecule. The volume of a sphere is given by the formula V = (4/3)πr^3, where r is the radius. Given the diameter of the oil molecule is 2 × 10-10 m, the radius would be half of that, which is 10-10 m. Plugging in the values, we get V = (4/3)π(10-10)^3 = 4.19 × 10-29 m3.

The total volume of the spilled oil is given as 1000 cm3, which is equal to 1000 × 10-6 m3. To find the number of oil molecules in the spilled oil, we can divide the total volume of oil by the volume of one molecule: 1000 × 10-6 m3 / 4.19 × 10-29 m3 = 2.39 × 1022.

Since the oil slick is one molecule thick, the diameter of the slick would be the diameter of one oil molecule multiplied by the square root of the number of oil molecules: 2 × 10-10 m × √ (2.39 × 1022) ≈ 4.89 × 106 m.

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The type of material makes up the functional aspect of the transducer that creates the high-frequency sound is Crystals which is a ceramic.

Explanation:

High frequency of sound can be produced in the transducer with the help of materials like ceramic materials.These are non-metallic compounds.  The ceramic materials are those that are brittle in nature. Crystals, glasses are some of the examples of ceramic materials.

Ceramic materials like crystals are used in transducers that makes them functionally fit to produce high frequency sounds. The materials that are given in the options tungsten, iron oxide and silver/chromium alloy are not fit for these type of materials manufacturing. These belongs to metals and metal oxides and alloy types of metals.

This physics problem can be solved using the principles of motion under gravity, we plug our known values into the equation of motion and solve the resulting quadratic equation for time.

This is an example of a physics problem under the theme of motion, specifically vertical motion under gravity. To answer this, you must apply the principles of physics to determine the total time the acrobat will spend in the air from the moment he is shot out of the cannon until the moment he touches the net.

In this situation,l we'll use the equation of motion, Y = Yo + Vot + 0.5gt² , where

Plugging the known values into the equation, we obtain a quadratic equation in terms of t. Solving this quadratic equation will give us two solutions for t, one for the upward journey and one for the downward journey. The acrobat reaches the height of the net along his upward journey from the cannon, so we pick the smaller t as the correct solution (as it occurs first).

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Answer:1520feet

Explanation:

The difference in elevation between the mountain top and the bottom of the trench will be addition of the distance between the sea and mountain top and the distance between the sea level and bottom trench i.e 1100 + 420

= 1520feet

Answer:

The scientific method is the process by which scientists gain confidence in theories by failing to prove them wrong.

Explanation:

Scientific  method is a step by step process of creating and carrying out experiments. These processes to be performed are derived from logical and rational application  of knowledge concerning a particular subject matter. Through these processes, scientists reach a conclusion about the world, these makes them confident in their findings.

The steps involved in scientific method include:

Observation: it is the first step. It enables you organise in your mind how you want the experiment to.

HYPOTHESIS is the result you imagine you'll find.

PREDICTION is how you think about the scientific idea- It solely relies on the hypothesis made.

EXPERIMENT is used to test your hypothesis. It is the tool designed to check if your idea is right or wrong.

CONCLUSION is the final step. It is the result gotten from the experiment. It can approve the hypothesis or reject the hypothesis.

A theory is formed when hypothesis has been tested to be true by many scientists. Hence scientists gain confidence in theories when the scientific method is approved.

 A scientific theory is a well-approved explanation of an aspect of the natural world. The approval is based on thoroughly confirmed hypothesis and experiments carried out by many scientists.

Answer: The person sitting in the middle of the train sees the back of the train enter ing the tunnel before the front end comes out.

Explanation:

Answer:

1. (a)strongly attractive

2 (c) weakly attractive.

Explanation:

Consider three plastic balls (A, B, and C), each carrying a uniformly distributed charge equal to either +Q, -Q or zero, and an uncharged copper ball (D). A positive test charge (T) experiences the forces shown in the figure when brought very near to the individual balls. The test charge T is strongly attracted to A, strongly repelled from B, weakly attracted to C, and strongly attracted to D.

should be the concluding part to this question as presented above

1. What is the nature of the force between balls A and B?

a) strongly attractive.

b) strongly repulsive.

c) weakly attractive.

d) neither attractive nor repulsive.

since there is an attractive force between ball A and the test charge, the charge on ball A must be negative

A = -Q

since ball B is repulsive to the test charged , then B must be positively charged

B = +Q

since A is negative and B is positive , then they will experienced a  strong attraction

option A

2. What is the nature of the force between balls A and C?

a) strongly attractive.

b) strongly repulsive.

c) weakly attractive.

d) neither attractive nor repulsive .

Since C is weakly attracted to the test charge, we can say that Ball C will be weakly attracted to A, because it possess some weka charges

option C

Answer:its c trust me

Explanation:

Answer:

The answer is gemmules.

Explanation:

When the parent freshwater sponge dies in the winter, it releases gemmules, which can survive both freezing and drying. When favorable conditions return in the spring, amoe-boid cells stream out of a tiny opening, called the micropyle, and organize into a sponge.

The net force that accelerates an object on an inclined plane is the parallel component of the weight minus the force of friction.

When an object rests on an inclined plane that makes an angle with the horizontal surface, the weight of the object can be resolved into components that act perpendicular and parallel to the surface of the plane.

The net force that accelerates an object on an inclined plane is the component of the weight that acts parallel to the plane, minus the force of friction. The force of gravity acting on the object is divided into two components: a force acting perpendicular to the plane (normal force) and a force acting parallel to the plane. The parallel component of the weight causes the object to accelerate down the incline.

If there is friction present on the inclined plane, the force of friction opposes the motion of the object and must be subtracted from the parallel component of the weight. The net force can then be calculated by subtracting the force of friction from the parallel component of the weight.

Answer: decrease; less

Explanation:

Insolation, refers to the amount of solar radiation that is received by earth. If the surface of earth was white, the radiation, will be reflected back into space. This reflective activity of a white surface will in turn cause the temperature of the planet to drop as there would be less energy to be converted to heat.

Answer:

A. Earth would cool down because it would reflect more solar radiation.

Explanation:

was right on edge :)

Answer:

(a) Horizontal component of the launch velocity = 60.7m/s

(b) Vertical component of the launch velocity = 56.0m/s

Explanation:

Initial Kinetic Energy = (IKE)= 1670J, mass (m) = 0.49kg, hmax = 160m

IKE = 1/2mu^2

1670×2/0.48 = u^2

u^2 = 6816.3

u = √6816.3 = 82.6m/s

hmax = u^2sin^2A/2g

160×2×9.8/6816.3 = sin^2A

Sin^2A = 0.46

SinA = √0.46 = 0.6782

A = inverse (sin 0.6782)

A = 42.7° (angle of inclination to the horizontal)

(a) Horizontal component (Ux) = ucosA = 82.6×cos42.7° = 82.6×0.7349 = 60.7m/s

(b) Vertical component (Uy) = usinA = 82.6×sin42.7° = 82.6×0.6782 = 56.0m/s

To find the horizontal and vertical components of the projectile's launch velocity, use the principle of conservation of energy.

To find the horizontal and vertical components of the projectile's launch velocity, we'll use the principle of conservation of energy. The projectile's initial kinetic energy is equal to its potential energy at its maximum displacement.

The projectile's initial kinetic energy is given as 1670 J. At the maximum displacement of 160 m, the potential energy is given as m*g*h, where m is the mass of the projectile (0.49 kg), g is the acceleration due to gravity (9.8 m/s^2), and h is the maximum displacement (160 m).

Using these values, we can solve for the vertical component of the launch velocity using the equation for potential energy: m*g*h = 0.49 kg * 9.8 m/s^2 * 160 m. The horizontal component of the launch velocity remains unchanged throughout the projectile's motion.

Answer:

Preassure plate

Explanation:

The flywheel, clutch disc, pressure plate, throw-out bearing clutch fork, and the pilot bearing are the components of a clutch. It works when the flywheel bolts onto the crankshaft and therefore the pressure plate bolts back into the flywheel.

I hope you find this information useful and interesting! Good luck!

Answer:

b) Particles that are emitted from a strip of metal are electrons.

Explanation:

Which observation provided Albert Einstein the clue that he needed to explain the photoelectric effect?

b) Particles that are emitted from a strip of metal are electrons.

the metal is injected by photon which leads to electron emission called photo-electron.

Answer:

D is the correct answer

Explanation:

Explanation:

Resultant, R of two vectors P and Q is given by,

           [tex]R=\sqrt{P^2+Q^2+2PQcos\theta }[/tex]

Here P = 4.52 N

        Q = 7.33 N

         θ = 90°

Substituting

         [tex]R=\sqrt{4.52^2+7.33^2+2\times 4.52\times 7.33\times cos90 }\\\\R=8.61N[/tex]

Magnitude of their sum, F = 8.61 N

Answer:

3.True. The magnitude of momentum is the same

Explanation:

Let's propose the solution of the problem

The initial moment is

                     p₀ = m v

The final moment

                     [tex]p_{f}[/tex] = m (-v)

                  p₀ = - [tex]p_{f}[/tex]

Now we can review the claims

1. False. We see that the moment module is the same, but its direction changes

2. False. The impulse is a vector

3.True. The magnitude of momentum is the same