Can someone please help me with these 2 questions
1) A car takes 76 metres to stop once a driver has noticed a hazard. If the thinking distance of the driver was 14m and the speed of the car was 8m/s. how long did it take the brakes to slow the car down to a stop?

2) A lorry travels 28m when stopping from a speed of 4m/s. If its braking distance was 18m, what was the driver's reaction time?​

The change in momentum is equal to 1.3928 kg.m/s².

The kinetic energy of the ball as it strikes the surface = 2.94 Joules

Given:

Mass of the ball = 100 g = 100 × 10⁻³ kg = m = 0.1 kg

Height from which ball falls = h = 3 m

Height to which the ball rebounds = h' = 2 m

g= acceleration due to gravity = g = 9.8 m/s²

1. A ball dropped from a height of 3 m, hits the horizontal surface and bounces back. This will cause a change in momentum.

The velocity of the ball before hitting the surface and after hitting the surface is different; causing a change in momentum (Δp).

Since momentum (p) = mass (m) × velocity (v) : [tex]p=m\times v[/tex]

Δp = [tex]m\times V_\ after[/tex] [tex]-\ m\times V_\ before[/tex] = [tex]m\times (V_\ after[/tex] [tex]\ -\ V_\ before[/tex] [tex])[/tex] ...........................(1)

Velocity (v) is given by [tex]v = \sqrt{2gh}[/tex]

[tex]V_\ before[/tex] = [tex]\sqrt{2\times g\times h} = \sqrt{2\times 9.8\times 3} = \sqrt{58.8} = 7.668\ m/s^2[/tex]

[tex]V_\ after[/tex] = [tex]\sqrt{2\times g\times h'} = \sqrt{2\times 9.8\times 2} = \sqrt{39.2} = 6.2609\ m/s^2[/tex]

[tex]V_\ before[/tex] is a decreasing quantity (Ball dropped from 3 m) until it becomes equal to [tex]V_\ after[/tex] and hence is a negative vector (negative in sign and opposite in direction to [tex]V_\ after[/tex].)

[tex]V_\ before[/tex] = (-7.668 m/s²)

From (1), for m = 0.1 kg, Δp becomes;

Δp = [tex]m\times (V_\ after[/tex][tex]\ -\ V_\ before[/tex][tex])[/tex] =  [tex]0.1( 6.2609 - ( - 7.668)) = 0.1\times 13.9289 = 1.3928\ kg.m/s[/tex]

2. As a ball falls to the surface, its gravitational potential energy is transformed into kinetic energy. This kinetic energy keeps on increasing with increase in momentum until it strikes the surface.

K.E of ball just before it strikes the surface from 3 m height = [tex]K.E = mgh[/tex]

[tex]K.E = 0.1\times 9.8\times 3 = 2.94\ J[/tex]

Answer:

The primary reason that power is transmitted at high voltages is to increase efficiency. As electricity is transmitted over long distances, there are inherent energy losses along the way. ... The higher the voltage, the lower the current. The lower the current, the lower the resistance losses in the conductors.

Explanation:

There will be zero radioactive atoms left

Explanation:

The amount of radioactive atoms left of a radioactive sample after a certain time t is given by the equation

[tex]N(t) = N_0 (\frac{1}{2})^{-\frac{t}{\tau}}[/tex]

where

N(t) is the number of radioactive atoms left after time t

[tex]N_0[/tex] is the initial number of radioactive atoms

[tex]\tau[/tex] is the half-life of the sample

In this problem we have:

[tex]N_0 = 800[/tex] (initial number of radioactive atoms)

[tex]t=14 \tau[/tex] (we want to evaluate the number of atoms left after 14 half-lives)

Substituting, we find:

[tex]N(14\tau) = (800)(\frac{1}{2})^{-\frac{14\tau}{\tau}}=0.049[/tex]

This means that there will be zero atoms left, since atoms can't be split in fractional parts.

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Answer:

Humid air is lighter so it has lower pressure

Explanation:B.) humid air is lighter, so it has lower pressure

Explanation:

Humidity is related to air pressure in that, a humid air is lighter and it has very low pressure.

Air is heavier than water vapor.

   The main component of humid air is water vapor.

   Water vapor is mostly water in its gaseous form

   We know that for a single mole of water, the mass is 18g

   Air is a mixture of gases with Nitrogen gas dominating.

   A mole of nitrogen gas has a mass of 28g.

   We can see that air that is humid i.e contains more water vapor is lighter and it has a lower pressure.

The displacement of the book is 5 meters

Explanation:

The work done by a force when moving an object is given by:

[tex]W=Fd cos \theta[/tex]

where :

F is the magnitude of the force

d is the displacement

[tex]\theta[/tex] is the angle between the direction of the force and the displacement

In this problem, we have:

W = 500 J is the work done by Maria

F = 100 N is the force applied by Maria

[tex]\theta=0^{\circ}[/tex], assuming the direction of the force is parallel to the displacement

So we can rearrange the equation to solve for d, the displacement:

[tex]d=\frac{W}{F cos \theta}=\frac{500}{(100)(cos 0)}=5 m[/tex]

So, the book was moved 5 meters.

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the effect of pressure on surface tension can be attributed in part to absorption of gas at the surface of the liquid and in part to an intrinsic decrease in density of the liquid in the neighborhood of the surface.

In the case of liquids , Owing to contact forces between the edge of the surface and the vessel, the surface acquires a curvature, and if the liquid rises up at the edges where it meets the vessel, the pressure will be less in the liquid than in the air, for points just below and just above the surface. The vessel exerts an upward force on the liquid. This is simply a matter of looking at the directions of forces acting, knowing that the surface is under tension.

Answer:

Two objects are identical except that on is hotter than the other. Thus, when an equal force acts on them the hotter one will move faster or will get displaced more or stop slower than the other one. This is because the hotter object has comparatively more mobile particles than the other

Hope this helps!

Final answer:

Identical forces exerted on two objects with different temperatures will affect them equally according to Newton's third law, but their responses, such as stress and expansion, may differ due to properties like thermal expansion coefficients. Also, at thermal equilibrium, the final temperature is closer to the object with greater heat capacity. The hotter star of two identical stars will be significantly brighter.

Explanation:

Response to the Student's Question

When two objects are identical except for temperature and they are exposed to identical forces, the forces they experience will be the same due to Newton's third law. However, the effect of the force may differ if their temperatures lead to different physical properties like thermal expansion. If object A has a higher thermal expansion coefficient than object B and both are heated identically, A will likely feel greater stress because it will expand more, which could create internal strain if constrained. For the question about the heat capacities, when two objects—one hot, one cold—are brought into contact, the final temperature at thermal equilibrium will be closer to the object with the higher heat capacity, in this case, the colder object. Therefore, it will not be exactly halfway between the two initial temperatures.

In the context of stars, brightness is related to temperature. The star with a temperature of 8700 K will be brighter than the star at 2900 K due to Wien's Law and the Stefan-Boltzmann Law, which relate temperature to luminosity and energy output. The hotter star is, therefore, significantly brighter.

Explanation:

Factors affecting surface tension includes;

There are three factors that affect surface tension.

Temperature- the surface tension of a liquid decreases with increase in temperature.

Soluble impurities - the presence of soluble impurities may increase or decrease the surface tension.

Insoluble impurities- insoluble impurities decrease the surface tension.

400 N

The weight of the man is evenly distributed on each scale

The man's total weight of 800-N, when distributed equally over two bathroom scales, will result in each scale reading 400-N.

The man's total weight is 800-N and he is standing on two scales, with his weight distributed evenly. This means each scale will bear half of the total weight. Therefore, the reading on each scale will be 800-N divided by 2. That calculation yields a result of 400-N per scale. So each bathroom scale will show a weight of 400-N, assuming the weight distribution remains equals.

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Answer:

food chain

Explanation:

The given flow chart or diagram represents a food chain . A food chain is the flow of energy from lower level organism to higher level organism.

In ecology, the food chain is the flow of substance and energy from one organism to another in the form of food. Due to the fact that most species consume more than one kind of animal or plant, food chains locally entangle to form a food web.

The main source of food are plants since they use photosynthesis to turn solar energy into food.A flesh-eating animal consumes a plant-eating species in a predator chain. A smaller organism in a parasite chain takes a portion of a larger host and may also become a parasite on itself.

Here, the phytoplanktons are eaten by shrimps and they are in turen eaten by salmon which is edible to humans. Hence, the diagram represents a food chain.

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Answer:

E1 =  2996.667N/C E2 = 11237.5N/C

Explanation:

E1 = kQ1/r^2

  =8.99 x 10^9 x 30 x 10^-9/(30x10^-2)^2

  = 2996.667N/C

E2 = kQ2/r^2

      = 8.99 x 10^9 x 50 x 10^-9/(20x10^-2)^2

      = 11237.5N/C

The direction are towards the point a

The second option G. Docs is a free, cloud-based word processor that allows you to create, edit, and collaborate in real-time with other users.

G. Docs is a web-based application offered by G.o.o.g.l.e within its suite of office tools. It allows users to create, edit, and store documents online, enabling real-time collaboration. Multiple users can simultaneously work on the same document, making it an excellent tool for collaborative projects. G. Docs automatically saves changes, reducing the risk of data loss, and offers seamless integration with G. Drive for easy storage and sharing of documents. The cloud-based nature of G. Docs eliminates the need for specific operating systems, making it accessible from various devices with internet connectivity.

In summary, the correct answer is G. Docs, a versatile cloud-based word processor that promotes efficient collaboration and accessibility across different platforms.

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A) The maximum height is 31.9 m

B) The speed of the ball is 17.7 m/s

Explanation:

A)

We can solve this problem by using the law of conservation of energy. In fact, in abcense of air resistance, the mechanical energy of the ball (sum of potential energy + kinetic energy) must be conserved.

Mathematically:

[tex]U_i +K_i = U_f + K_f[/tex]

where :

[tex]U_i[/tex] is the initial potential energy, at the bottom

[tex]K_i[/tex] is the initial kinetic energy, at the bottom

[tex]U_f[/tex] is the final potential energy, at the top

[tex]K_f[/tex] is the final kinetic energy, at the top

We can rewrite it as

[tex]mgh_i + \frac{1}{2}mu^2 = mgh_f + \frac{1}{2}mv^2[/tex]

where:

m is the mass of the ball

[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity

[tex]h_i = 0[/tex] is the initial height  of the ball

u = 25 m/s is its initial speed

[tex]h_f[/tex] is the maximum height reached by the ball

v = 0 is the final speed (which is zero at the maximum height)

Solving for [tex]h_f[/tex], we find: the maximum height:

[tex]\frac{1}{2}mu^2 = mgh_f\\h_f = \frac{u^2}{2g}=\frac{(25)^2}{2(9.8)}=31.9 m[/tex]

B)

When the ball is halfway up to its maximum height, it means that its height is

[tex]h_f = \frac{31.9}{2}=15.9 m[/tex]

Therefore we can re-apply again the equation of the conservation of energy:

[tex]mgh_i + \frac{1}{2}mu^2 = mgh_f + \frac{1}{2}mv^2[/tex]

where this time v is not zero, but it is the speed of the ball at the height of 15.9 m

Re-arranging the equation and solving for v, we find:

[tex]v=\sqrt{u^2-2gh_f}=\sqrt{25^2-2(9.8)(15.9)}=17.7 m/s[/tex]

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The maximum height the baseball can reach when thrown at an initial speed of 25 m/s is 31.9 meters. When the ball is halfway to this height, its speed is 17.67 m/s.

The subject matter of the question is physics, specifically the concepts of motion, velocity, and gravitational forces.  

Given the initial velocity of the baseball is 25 m/s and the acceleration due to gravity is -9.8 m/s², we can find the maximum height using the equation v² = u² + 2gs, where v is the final velocity, u is the initial velocity, g is acceleration due to gravity, and s is displacement.  

Substituting in the given values gives us 0 = (25 m/s)² + 2*(-9.8 m/s²)*s, so s = (25 m/s)² / (2 * 9.8 m/s²) = 31.9 meters. This is the maximum height the ball reaches.  

When the ball is halfway to its maximum height, it is still subject to the laws of physics, so we cannot simply divide the initial velocity by two. Instead, we can find the velocity at the halfway height (15.95 meters) using the equation v = u + 2gs. Substituting the known values, we get v = sqrt((25 m/s)² + 2*(-9.8 m/s) * (-15.95 m) ) = 17.67 m/s.

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Answer:

It takes 58.8 seconds to swim the length of a olympic-sized pool.

Explanation:

Uniform Velocity Motion

It describes the situation when an object moves in such a way that it travels equal distances at equal times in the same direction. For example, if it travels x=50 m in t=10 seconds and later it travels x=200 m in t=40 seconds, its speed is constant and equal to v=5 m/s. The relation between the variables x,t, and v is

[tex]x=v.t[/tex]

We know a swimmer is traveling at a constant speed of 0.85 m/s. We are required to find how long would it take him to swim the length of an x=50-meter Olympic-sized pool.

From the above equation, we solve for t

[tex]\displaystyle t=\frac{x}{v}[/tex]

[tex]\displaystyle t=\frac{50\ m}{0.85\ m/s}[/tex]

[tex]\boxed{t=58.8\ s}[/tex]

It takes near 59 seconds to swim the length of a olympic-sized pool

A swimmer would take about 59 seconds to swim the length of a 50-meter Olympic-sized pool when traveling at a constant speed of 0.85 m/s.

The time it takes to cover a specific distance traveling at a constant speed can be calculated using the equation time = distance / speed.

In this question, the swimmer is traveling at a constant speed of 0.85 meters per second and the distance to be covered is a 50-meter Olympic-sized pool. To solve the problem we will use the equation stated above:

time = 50 m / 0.85 m/s = 58.82 seconds approximately.

So, at a constant speed of 0.85 m/s, it would take a swimmer about 59 seconds to swim the length of a 50-meter pool.

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The centripetal acceleration is 27.692 kg m / s^2.

The mass of the ball is 7.94 kg.

Explanation:

            centripetal force Fc = (mass * square of velocity) / radius

where m represents mass in kg

          v represents  velocity

          r represents radius in a meter.

                                                             = (6 * 6) / 1.3

                                                             = 27.692 kg m / s^2.

 The mass of the ball is found by using the centripetal force formula,

                                                      m = (F * r) / v^2

                                                          =  (220 * 1.3) / 36

                           mass of the ball  m = 7.94 kg.

Answer:

24 m

Explanation:

initial velocity is u = 3.5 m/sec

final velocity is v = 0 m/sec

distance traveled is S = 1.5 m

From kinematic equation [tex]v^{2}-u^{2} = 2as[/tex]

Making acceleration the subject,

[tex]a=\frac {v^{2}-u^{2}}{2s}[/tex]

Acceleration [tex]a = \frac {0^2-3.5^2}{(2*1.5)}= -4.083333333m/s^{2}[/tex]

When the initial velocity is quadrupled= u = 3.5*4 = 14 m/s

V = 0 m/s

[tex]a = -4.083333333m/s^{2}[/tex]

then [tex]S = \frac {v^{2}-u^{2}}{2} = \frac {0^{2}-14^{2}}{2\times -4.083333333} = 24 m[/tex]

It would have more kinetic energy at the start, resulting in greater potential energy at the bottom of the track.

Answer: Option A.

Explanation:

The car at the race track will accelerate at point X. It will have more kinetic energy at the start because the car is at the slope and with time it will result in greater potential energy at the bottom.

As we go down towards the bottom of the track, the kinetic energy will get converted into potential energy because here the body starts coming at rest and is not moving.

Answer:

yall its A

Explanation:

Answer:

765,000 Joule

Explanation:

Principle of Conservation of Energy

The total energy in an isolated system cannot be created or destroyed, but transformed. Moving objects have kinetic energy, objects placed in some height above a reference level have gravitational potential energy. When they change their motion variables, one energy converts into the other, but if the numbers don't fit, we know there was some other type of energy acting into the system. The most common reason for energy 'losses' is the thermal energy, produced when objects move in rough surfaces or take friction from the air.

The 7,500 kg truck is originally traveling at 20 m/s to a certain height we'll set to 0. Thus, its total energy is  

[tex]\displaystyle E_1=\frac{mv^2}{2}[/tex]

[tex]\displaystyle E_1=\frac{7,500\ 20^2}{2}[/tex]

[tex]E_1=1,500,000\ Joule[/tex]

When it comes to a stop, its speed is 0 and its height is 10 m higher than before. It means all the kinetic energy was transformed into other types of energy. The gravitational potential energy is

[tex]U=mgh=(7,500)(9.8)(10)=735,000\ Joule[/tex]

Since this number is not equal to the previous value of the energy, the difference is due to thermal energy dissipated by friction

[tex]E_t=1,500,000\ Joule-735,000\ Joule=765,000\ Joule[/tex]

The initial velocity is [tex]6.7 m/s[/tex]

Explanation:

The motion of the ball is a projectile motion, therefore it consists of two independent motions:  

- A uniform motion (constant velocity) along the horizontal direction  

- A uniformly accelerated motion, with constant acceleration (acceleration of gravity) in the downward direction  

In this problem, we just need to analyze the horizontal motion: the horizontal velocity is constant, therefore the horizontal distance travelled is given by

[tex]x=v_x t[/tex]

where

[tex]v_x[/tex] is the horizontal velocity

t is the time of flight

Here we have:

t = 0.45 s

x = 3.0 m

And so solving for [tex]v_x[/tex], we find

[tex]v_x = \frac{3.0}{0.45}=6.7 m/s[/tex]

And since the ball was initially projected horizontally, this is also the initial velocity.

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The initial velocity of the ball is 6.67 m/s.

To determine the initial velocity of the ball, we need to use the horizontal motion equation, which states that the horizontal distance traveled equals the product of the initial velocity and the time of flight. In this case, the horizontal distance traveled is 3.0 m and the time of flight is 0.45 s. Rearranging the equation, we find that the initial velocity is equal to the horizontal distance divided by the time of flight.

Initial velocity = horizontal distance / time of flight = 3.0 m / 0.45 s = 6.67 m/s

Therefore, the initial velocity of the ball is 6.67 m/s.

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Answer:

Voltage describes the potential difference between the two ends of a conductor and thus , more the voltage , more will be the flow of current through the conductor ( more no of electrons and faster speed).

Explanation:

Voltage represents the potential difference between two ends of a conductor, and so the greater the voltage, the greater the current flow through the wire.

Ohm's law claims that the voltage across a conductor is directly proportional to the current flowing through it.

Ohm's law claims that the voltage across a conductor is directly proportional to the current flowing through it.

This current-voltage connection may be expressed mathematically as,

The Equation of Ohm's Law

V=IR

Voltage represents the potential difference between two ends of a conductor, and so the greater the voltage, the greater the current flow through the wire.

Hence, Voltage is described as the product of the current and the resistance.

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Answer:

B: it is the instantaneous speed of the bike rider.

Explanation:

keep it going....

Answer:

B It is the instantaneous speed of the bike rider.

Explanation:

I took  the test

Answers:

a)The balloon is 68 m away of the radar station

b) The direction of the balloon is towards the radar station

Explanation:

We can solve this problem with the Doppler shift equation:

[tex]f'=\frac{V+V_{o}}{V-V_{s}} f[/tex]  (1)

Where:

[tex]f=250,000 Hz[/tex] is the actual frequency of the sound wave

[tex]f'=240,000 Hz[/tex] is the "observed" frequency

[tex]V=340 m/s[/tex] is the velocity of sound

[tex]V_{o}=0 m/s[/tex] is the velocity of the observer, which is stationary

[tex]V_{s}[/tex] is the velocity of the source, which is the balloon

Isolating [tex]V_{s}[/tex]:

[tex]V_{s}=\frac{V(f'-f)}{f'}[/tex]  (2)

[tex]V_{s}=\frac{340 m/s(240,000 Hz-250,000 Hz)}{240,000 Hz}[/tex]  (3)

[tex]V_{s}=-14.16 m/s[/tex] (4) This is the velocity of the balloon, note the negative sign indicates the direction of motion of the balloon: It is moving towards the radar station.

Now that we have the velocity of the balloon (hence its speed, the positive value) and the time ([tex]t=4.8 s[/tex]) given as data, we can find the distance:

[tex]d=V_{s}t[/tex] (5)

[tex]d=(14.16 m/s)(4.8 s)[/tex] (6)

Finally:

[tex]d=68 m[/tex] (8) This is the distance of the balloon from the radar station

Answer:

The characteristics of water waves is that it travels through the waver, the particles travel in clockwise circles. The radius of the circles decreases as the depth into the water increases.

Explanation:

The amount of  time the shot-put spent in the air before it hits the ground is 3 sec

given the data in the question;

A person throws a shot-put from height, initial height; s = 5ft

Initial vertical velocity or speed; v = 40 ft/s

Now, it is said that, vertical motion model is;

[tex]h = -16t^2 +vt + s[/tex]

so we substitute in the given values

[tex]h = -16t^2 + (40ft/s * t) + 5ft[/tex] --------------Let this be equation 1

To calculate the amount of  time the shot-put spent in the air before it hits the ground.

We say:  height; h = 0 i.e when the shot-put touches the ground, the height becomes zero.

so we substitute in h=0 in equation 1

[tex]0 = -16t^2 + (40ft/s * t) + 5ft[/tex]

we rearrange

[tex]16t^2 - 40t - 5 = 0[/tex]

To solve for "t", we use the quadratic equation

[tex]x = \frac{-b\±\sqrt{b^2-4ac} }{2a} \\[/tex]

as [tex]ax^2 +bx-c = 0[/tex], we take each value from its position and substitute into the quadratic equation

so

a = 16

b = -40

c = -5

so substitute

[tex]x = \frac{-(-40)\±\sqrt{(-40)^2 - (4*16*(-5)} }{2*16} \\\\x = \frac{40\±\sqrt{1600+320} }{32}[/tex]

[tex]x = \frac{40\±\sqrt{1920} }{32}\\so\\\\x = \frac{40+\sqrt{1920} }{32} or \frac{40-\sqrt{1920} }{32} \\\\x = 2.62\\or\\ x = -0.12\\[/tex]

we know that, time can not be negative,

Hence x = 2.62 ≈ 3 sec { nearest tenth }

Therefore, the amount of  time the shot-put spent in the air before it hits the ground is 3 sec

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Answer:

Energy cannot be created or destroyed.

Explanation:

Energy cannot be created or destroyed, it can only be altered from one from to another.

Answer:

C. Energy cannot be created or destroyed but it can change form.

Energy can be converted from one form to another. The law of conservation of energy says that energy is neither created nor destroyed. When you consume energy, it is not gone forever. Instead, it is changed from one form of energy to another. So, energy is not manufactured and it doesn't go away after you use it. It is just transformed, or stored.

Explanation:

(a) The net force in the y direction is the sum of the individual forces.  Taking up to be +y:

∑F = Lift − Weight

∑F = 100,000 N − 75,000 N

∑F = 25,000 N

(b) Since the net force is not 0, the forces are unbalanced.

(c) Since the lift is greater than the weight, the plane will rise.

(d) The net force in the x direction is the sum of the individual forces.  Taking forward to be +x:

∑F = Thrust − Drag

∑F = 200,000 N − 23,000 N

∑F = 177,000 N

(e) Since the net force is not 0, the forces are unbalanced.

(f) Since the thrust is greater than the drag, the plane will accelerate.

Answer:

Explanation:

The force is a vector magnitude, it has direction, course and intensity.

Suppose that you have given two forces at a certain angle and that you need to find the resultant force then you apply the Parallelogram of force low.

You represent the two forces in the drawing as vectors and connect their origin to the same point and then construct a parallelogram over them.

The longer diagonal represents the resultant force.

God is with you!!!

The distance travelled in 5 seconds is 125 m

Explanation:

The motion of the skydiver is a free fall motion, since he is acted upon the force of gravity only. Therefore, it is a uniformly accelerated motion, with constant acceleration downward, and we can find the distance he travels by using the following suvat equation:

[tex]s=ut+\frac{1}{2}at^2[/tex]

where

s is the distance travelled

u is the initial velocity

t is the time

a is the acceleration

In this problem, we have:

u = 0 (the skydiver jumps from rest)

[tex]a=g=10 m/s^2[/tex] (acceleration of gravity)

And substituting

t = 5.0 s

we find the distance travelled:

[tex]s=0+\frac{1}{2}(10)(5)^2=125 m[/tex]

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Need more details, what is the slope of the line, etc.

It depends.

In order to answer the question, a person has to know:

-- the velocity (speed and direction) of the ball WHEN it's released

-- whether the ball has any net electric charge

-- whether there's any other net electric charge in the neighborhood

-- the mass of the ball, if any net charges are involved

-- what planet is nearest to the ball

-- the acceleration of gravity on that planet

Each of these details has an influence on the answer.  That is, if one of them changes, then the answer changes.  Now, it hasn't escaped my notice that you neglected to provide ANY of this information, so there's no way to even begin to concoct an answer.

Right now, the question is a lot like me asking you "How much will I weigh 8 seconds after I finish eating the steak ?".

Answer:

352.8 N

Explanation:

= 36

= 9.8

⁄ = ? = = 36 × 9.8 = 352.8

Answer:

360 N

Explanation:

mass = 36 kg

g = 10m/s²

W = mg

W = 36 × 10

W = 360 N