Can someone help me please i need help with this question

Answer:

[tex]\large\boxed{B.\ 4x^2-41x+105}[/tex]

Step-by-step explanation:

[tex]f(x)=4x-\sqrt{x}\\\\g(x)=(x-5)^2\\\\f(g(x))\to\text{put}\ x=(x-5)^2\ \text{to}\ f(x):\\\\f(g(x))=f\bigg((x-5)^2\bigg)=4(x-5)^2-\sqrt{(x-5)^2}\\\\\text{use}\\(a-b)^2=a^2-2ab+b^2\\\sqrt{x^2}=|x|\\\\f(g(x)=4(x^2-2(x)(5)+5^2)-|x-5|\\\\x>5,\ \text{therefore}\ x-5>0\to|x-5|=x-5\\\\f(g(x))=4(x^2-10x+25)-(x-5)\\\\\text{use the distributive property:}\ a(b+c)=ab+ac\\\\f(g(x))=(4)(x^2)+(4)(-10x)+(4)(25)-x-(-5)\\\\f(g(x))=4x^2-40x+100-x+5\\\\\text{combine like terms}\\\\f(g(x))=4x^2+(-40x-x)+(100+5)\\\\f(g(x))=4x^2-41x+105[/tex]

Answer: Option B

[tex]f(g(x)) = 4x^2 -41x + 105[/tex]

Step-by-step explanation:

We have 2 functions

[tex]f(x) = 4x -\sqrt{x}[/tex]

[tex]g(x) = (x-5)^2[/tex]

We must find [tex]f(g(x))[/tex]

To find this composite function enter the function g(x) within the function f(x) as follows

[tex]f(g(x)) = 4(g(x)) -\sqrt{(g(x))}[/tex]

[tex]f(g(x)) = 4(x-5)^2 -\sqrt{(x-5)^2}[/tex]

By definition [tex]\sqrt{a^2} = |a|[/tex]

So

[tex]f(g(x)) = 4(x-5)^2 -|x-5|[/tex]

Since x is greater than 5 then the expression [tex](x-5)> 0[/tex].

Therefore we can eliminate the absolute value bars

[tex]f(g(x)) = 4(x-5)^2 -(x-5)[/tex]

[tex]f(g(x)) = 4(x^2 -10x + 25) -(x-5)[/tex]

[tex]f(g(x)) = 4x^2 -40x + 100 -x+5[/tex]

[tex]f(g(x)) = 4x^2 -41x + 105[/tex]

Comparing the periods of the given cosine functions indicates that functions A) and C) both have the greatest period of π, which is longer than the period of function B), π/2.

To compare the periods of the given functions, let's first understand what the general form of a cosine function tells us about its period.

The general form is y = A cos(Bx + C), where A is the amplitude, B affects the period, and C is the phase shift.

The period of such a function is given by 2π / |B|.

For function A) y = 3cos(2x+1), B = 2, thus its period is π.

For function B) y=5cos(4x +8), B = 4, yielding a period of π/2.

Lastly, for function C) y=cos(2x+4) (4.3), assuming the (4.3) is an unrelated notation and focusing on the given cos component with B = 2, its period is also π.

The function with the greatest period among A, B, and C is thus A) and C), both having the same period of π, which is greater than the period of B).

Answer:

Step-by-step explanation:

[tex]30\cdot\dfrac{1}{6}=\dfrac{30}{6}=5[/tex]

20^2+21^2=29^2 can be used to determine if the triangle is a right triangle

Answer:

Step-by-step explanation:

The two smaller line lengths are squared separately and added. The square of the third line is noted. If squares of the two small ones equal the square of the largest one, you are working with a right angle triangle.

The one that puts into a formula what is stated above is B. D is close, but the longest line must be by itself.

you can get 12 quarters

Answer:

No Solutions

Step-by-step explanation:

-5x+10x+3=5x+6

5x+3=5x+6

5x=5x+3, which isn't true

ANSWER

The equation has no solution.

EXPLANATION

The given equation is

-5x+10x+3=5x+6

Group similar terms

-5x-5x+10x=6-3

-10x+10x=6-3

0=3

This statement is not true.

Hence the equation has no solution.

Answer:

[tex]f(x)=log_ex[/tex]

Step-by-step explanation:

By definition, we can write ln instead of log. WHEN??

Whenever the base of the logarithm is the number "e".

Hence, when we have:

[tex]Log_e[/tex]

We can write it in shortcut as:

[tex]Log_e=ln[/tex]

Hence, ln x can also be written as [tex]Log_ex[/tex]

Fourth answer choice is right.

Answer:

[tex]f(x) = log_e(x)[/tex]

Step-by-step explanation:

[tex]f(x) = ln x[/tex]

For logarithmic function ln(x) the base of ln is 'e'

[tex]f(x) = log_3(x)[/tex]

The base of log is 3 . so it is not equivalent to [tex]f(x) = lnx[/tex]

[tex]f(x) = log_{10}(x)[/tex]

The base of log is 10 . so it is not equivalent to [tex]f(x) = lnx[/tex]

[tex]f(x) = log_b(x)[/tex]

The base of log is b . so it is not equivalent to [tex]f(x) = lnx[/tex]

[tex]f(x) = log_e(x)[/tex]

The base of log is e . so it is equivalent to [tex]f(x) = lnx[/tex]

Answer:

x = 3 + i+√5

x = 3 + i-√5

OR

x= 4 - √6

x= 4 +√6

Step-by-step explanation:

(x - 3)² +6=1​

(x - 3)² + 6 = 1

        -6   -6

sq root > (x - 3)²      = -5

x-3 = i±√5     (i because neg. number)

x = 3 + i±√5

since its ±

two possible answers

x = 3 + i+√5

x = 3 + i-√5

Or

(x - 3)² +6=1​

(x-3)+  √6= √ 1

x-3 = 1 - (±)  √6

x= 4 - (±)  √6

Answers

x= 4 - √6

x= 4 +√6

Answer:

[tex]\large\boxed{\vec{u}\circ\vec{v}=121}[/tex]

Step-by-step explanation:

[tex]\vec{a}=<x_a,\ y_a>,\ \vec{b}=<x_b,\ y_b>\\\\\vec{a}\circ\vec{b}=x_ax_b+y_ay_b\\\\====================================\\\\\vec{u}=<8,\ 7>,\ \vec{v}=<9,\ 7>\\\\\vec{u}\circ\vec{v}=(8)(9)+(7)(7)=72+49=121[/tex]

Answer:

The volume of the pyramid is one third the volume of the rectangular prism

or

The volume of the prism is three times the volume of the pyramid

Step-by-step explanation:

step 1

Find the volume of the rectangular prism

The volume is equal to

[tex]V=Bh[/tex]

where

B is the area of the base

h is the height of the prism

Find the area of the base B

[tex]B=5^{2}=25\ in^{2}[/tex]

substitute

[tex]Vprism=25h\ in^{3}[/tex]

step 2

Find the volume of the square pyramid

The volume is equal to

[tex]V=(1/3)Bh[/tex]

where

B is the area of the base

h is the height of the pyramid

Find the area of the base B

[tex]B=5^{2}=25\ in^{2}[/tex]

substitute

[tex]Vpyramid=(1/3)25h\ in^{3}[/tex]

Remember that

[tex]Vprism=25h\ in^{3}[/tex]

substitute

[tex]Vpyramid=(1/3)Vprism[/tex]

The volume of the pyramid is one third the volume of the rectangular prism

or

[tex]Vprism=3Vpyramid[/tex]

The volume of the prism is three times the volume of the pyramid

Answer:

A) 14 cm^2

Step-by-step explanation:

Given

Rhombus ABCD

let the given length be diagonal 1, a= 8cm

diagonal 2,b= 3.5cm

Area of ABCD=?

Area of rhombus= ab/2

Putting the values in above :

Area of ABCD= 8(3.5)/2

                       =28/2

                       =14 !

Answer:

14cm^2

Step-by-step explanation:

Answer:

x cannot equal -3, and x cannot equal -2

Step-by-step explanation:

Answer:

The excluded values of the rational expression are -3 and -2.

Step-by-step explanation:

If a ration function is defined as [tex]R(x)=\frac{p(x)}{q(x)}[/tex], then the excluded values of the rational function are those values for which q(x)=0.

The given rational expression is

[tex]\frac{x^2+2x-3}{x^2+5x+6}[/tex]

Factories the numerator and denominator.

[tex]\frac{x^2+3x-x-3}{x^2+3x+2x+6}[/tex]

[tex]\frac{x(x+3)-1(x+3)}{x(x+3)+2(x+3)}[/tex]

[tex]\frac{(x+3)(x-1)}{(x+3)(x+2)}[/tex]                .... (1)

Equate the denominator equal to 0.

[tex](x+3)(x+2)=0[/tex]

Using zero product property,

[tex]x+3=0\Rightarrow x=-3[/tex]

[tex]x+2=0\Rightarrow x=-2[/tex]

Therefore the excluded values of the rational expression are -3 and -2.

Cancel out the common factors of equation (1)

[tex]\frac{x - 1}{x + 2}[/tex] for (x≠-3)

It means x=-2 is vertical asymptote and x=-3 is hole.

Answer:

I don't know either

Step-by-step explanation:

the answer would be 4 5/12 pounds

The total weight of the two boxes will be 4 and 5/12 pounds.

Algebra is the study of mathematical symbols, and the rule is the manipulation of those symbols.

Tim mails two boxes of cookies to friends. One box weighs 1 and 3/4 pounds, and the other weighs 2 and 2/3 pounds.

Then the total weight of the two boxes will be

Total weight = 1 + 3/4 + 2 + 2/3

Total weight = 3 + 17/12

Total weight = 3 + 1 + 5/12

Total weight = 4 + 5/12

The total weight of the two boxes will be 4 and 5/12 pounds.

More about the Algebra link is given below.

https://brainly.com/question/953809

#SPJ2

Answer:

[tex]m<FEH=86\°[/tex]

Step-by-step explanation:

we know that

The inscribed angle measures half that of the arc comprising

step 1

Find the measure of arc EF

[tex]m<FHE=\frac{1}{2}(arc\ EF)[/tex]

we have

[tex]m<FHE=45\°[/tex]

substitute

[tex]45\°=\frac{1}{2}(arc\ EF)[/tex]

[tex]arc\ EF=90\°[/tex]

step 2

Find the measure of arc EH

[tex]m<EGH=\frac{1}{2}(arc\ EH)[/tex]

we have

[tex]m<EGH=49\°[/tex]

substitute

[tex]49\°=\frac{1}{2}(arc\ EH)[/tex]

[tex]arc\ EH=98\°[/tex]

step 3

Find the measure of arc FGH

[tex]arc\ FGH=360\°-(arc\ EH+arc\ EF)[/tex]

substitute the values

[tex]arc\ FGH=360\°-(98\°+90\°)[/tex]

[tex]arc\ FGH=172\°[/tex]

step 4

Find the measure of angle FEH

[tex]m<FEH=\frac{1}{2}(arc\ FGH)[/tex]

we have

[tex]arc\ FGH=172\°[/tex]

substitute

[tex]m<FEH=\frac{1}{2}(172\°)=86\°[/tex]

Answer:

C. 1

Step-by-step explanation:

The line containing segment BC has a slope of 1 and a y-intercept of 5 (at point B). Thus, its equation is ...

y = x + 5

For the value of x = -4, the value of y is ...

y = -4 +5 = 1

Point (-4, 1) is on the line containing segment BC.

Answer:

C. 1

Step-by-step explanation:

now divide 76.5 by 8.5

76.5/8.5 = 9 hours

Answer:

B) 3.5  ^_^

Step-by-step explanation:

The answer is -2. X is -2.

Answer:

5 if its a dice.

Step-by-step explanation:

On a dice, 5. The probability of it landing on 6 is 1/6

Answer:

is the last one if not the second option would  be the 2 second

Step-by-step explanation:

Answer:

[tex]x^{\frac{5}{12} }[/tex]

Step-by-step explanation:

In the question given we use the law of exponents;

[tex](a^{b})^{c} = a^{bc}[/tex]

If a base a is raised to a power b and the entire expression raised to a power c, the resulting expression is simply equal to the base a raised to the product of the two exponents b and c, that is bc.

In the case given,

a = x

b = 5/8

c = 2/3

To simplify the expression we simply multiply b and c;

bc = 5/8 * 2/3

     = 5/12

The simplified expression is thus;

[tex]x^{\frac{5}{12} }[/tex]

Answer:

The correct answer is ((x⁵/⁸)²/³) = x⁵/¹²

Step-by-step explanation:

Points to remember:-

Identity

(xᵃ)ᵇ = xᵃᵇ

Here it is given that, ((x⁵/⁸)²/³)

To find the value of ((x⁵/⁸)²/³)

(5/8) * (2/3) =  (5 * 2) /(8 * 3) = 10/24 = 5/12

By using identity (xᵃ)ᵇ = xᵃᵇ we can write,

((x⁵/⁸)²/³) = x⁽⁵/⁸⁾ˣ⁽²/³⁾

= x⁵/¹²    

Therefore the correct answer is ((x⁵/⁸)²/³) = x⁵/¹²

The formula for finding the volume of a rectangular prism (the cargo area of the truck is the shape of a rectangle in 3D; a rectangular prism) is V = (l)(w)(h); where l = length, w = width, and h = height.

First, substitute the known values into the equation:

l = 8.5

w = 6

h = 10.5

V = (8.5)(6)(10.5)

(Note: .5 = 1/2)

Now, all we need to do is simplify:

V = 535.5 ft³ OR 535 1/2 ft³

(Note: ft³ is the condensed form of cubic feet)

You can pick whichever form your test directs you to use. They are both the same value though.

Hope this helps!

The volume of the cargo area of the truck is 519.75 cubic feet.

The volume of the cargo area of the truck can be calculated by multiplying its length, width, and height. Given the dimensions in feet are:

Length = 8 1/2 feet = 8.5 feet = 8 + 1/2 feet

Width = 6 feet

Height = 10 1/2 feet = 10.5 feet = 10 + 1/2 feet

To find the volume, we convert the mixed numbers to improper fractions and then multiply:

Length in fractions = 8 + 1/2 = 17/2 feet

Width in fractions = 6 = 6 * 2/2 = 12/2 feet

Height in fractions = 10 + 1/2 = 21/2 feet

Now, multiply the dimensions to find the volume:

Volume = Length * Width * Height

Volume = (17/2 feet) * (12/2 feet) * (21/2 feet)

Volume = (17 * 12 * 21) / (2 * 2 * 2) cubic feet

Volume = 4158 / 8 cubic feet

Simplifying the fraction, we get:

Volume = 519.75 cubic feet

Answer:

15

Step-by-step explanation:

Since 9 questions is 60% of the exam, you must find 100%. You could find the value of 10% by dividing 60 by 6. You do the same to 9, divide by 6 to get 1.5. Now that you have the value of 10% you can multiply 10% by 10 to get 100. You also do the same to 1.5. Your answer should be 15, if not check your work again. Work hard!!

The total number of questions in the exam is 15 and this can be determined by using the unitary method.

Given :

Priya has completed 9 exam questions. This is 60% of the questions on the exam.

The unitary method can be used in order to determine the total number of questions in the exam.

According to the given data, Priya has completed 9 exam questions which are 60% of the questions on the exam. So, the 100% questions in the exam are:

[tex]= \dfrac{9}{60}\times 100[/tex]

Multiply 9 by 100 in the above expression.

[tex]=\dfrac{900}{60}[/tex]

Divide 900 by 60 in the above expression.

= 15 questions

So, the total number of questions in the exam is 15.

For more information, refer to the link given below:

https://brainly.com/question/21648365

I and II

When a graph has a solid line, solutions lie ON that line, whereas if it was a dotted line, solutions lie only on the shaded side of that line, not the line itself.

Answer:

I am pretty sure the answer is square

265,000

Hope this helps!

Because the number in the ten thousands place is over 4, it’s going to turn the 2 in the hundred thousands place into a 3, making the answer 300,000

Answer:

A.

Step-by-step explanation:

First, let's define the types of numbers.

Real numbers: a value that represents a quantity along a continuous line

ex: 1, 5, -6, 0.125, 45.5258,

Integer: Zero, any positive or negative number

ex: -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5....

Whole numbers: a number without fractions [not negative]

ex: 0, 1, 2, 3, 4, 5.....

Rational numbers: any number that can be expressed as the quotient or fraction

ex: 1, 2, 3, 4, 5

Irrational numbers: any number that can't be expressed at the quotient or fraction

ex: pi, [3.14.... (never ending decimal)]  square root of 2....

Based on this information, the false statment would be A. I believe, because

pi is a real number and it is an irrational number.

I hope this helps!!! :)

Answer:

Part A) The perimeter of the court is [tex]P=139.25\ ft[/tex]

Part B) [tex]5\ cans[/tex]

Step-by-step explanation:

Part A) we know that

The perimeter of the court is equal to the perimeter of the square plus the perimeter of semicircle

[tex]P=4D+\frac{\pi D }{2}[/tex]

we have that

[tex]D=25\ ft[/tex]

substitute

[tex]P=4(25)+\frac{(3.14*25)}{2}[/tex]

[tex]P=139.25\ ft[/tex]

Part B)

Find the area above the foul line (labelled II)

The area of a semicircle is equal to

[tex]A=\frac{\pi r^{2}}{2}[/tex]

we have

[tex]r=25/2=12.5\ ft[/tex]

substitute

[tex]A=\frac{(3.14)(12.5)^{2}}{2}[/tex]

[tex]A=245.31\ ft^{2}[/tex]

Round to the nearest whole number

[tex]A=245\ ft^{2}[/tex]

One can of paint covers 50 square feet of floor

so

Calculate how many cans of blue paint does the school need to purchase

[tex]245/50=4.9\ cans[/tex]

Round up

[tex]5\ cans[/tex]

Answer:

The radius is [tex]r=5\ cm[/tex]

Step-by-step explanation:

we know that

The inscribed angle is half that of the arc it comprises.

so

[tex]m<C =(1/2)[arc\ AB][/tex]

[tex]m<C =90\°[/tex]

substitute

[tex]90\°=(1/2)[arc\ AB][/tex]

[tex]arc\ AB=180\°[/tex]

That means----> The length side AB of the inscribed triangle is a diameter of the circle

Applying Pythagoras Theorem

Calculate the length side AB

[tex]AB^{2}=AC^{2}+BC^{2}[/tex]

[tex]AB^{2}=8^{2}+6^{2}[/tex]

[tex]AB^{2}=100[/tex]

[tex]AB=10\ cm[/tex] -----> is the diameter

Find the radius

[tex]r=10/2=5\ cm[/tex] -----> the radius is half the diameter