The enthalpy of combustion of C6H14 can be calculated using the enthalpies of formation of the products and reactants as per Hess's law, resulting in an approximate value of -4163 kJ/mol.
Explanation:To calculate the enthalpy of combustion, ΔH°comb, for C6H14, we first need to write and balance the combustion reaction for C6H14. The balanced chemical equation for the combustion of C6H14 in oxygen is:
C6H14 (l) + 19/2 O2 (g) -> 6 CO2 (g) + 7 H2O (l)
Going by Hess's law, the enthalpy change of the whole process will be equivalent to the sum of the enthalpy changes of each step. The enthalpies of formation of CO2 and H2O are -393.5 kJ/mol and -285.8 kJ/mol respectively, while the enthalpy of formation of C6H14 is -200.0 kJ/mol from literature. Using the balanced equation, we can calculate the ΔH°comb:
ΔHC°comb = ΣΔHf° (products) - ΣΔHf° (reactants)
So,
ΔHC°comb = [(6×-393.5) + (7×-285.8)] - [-200.0]
2hich gives the enthalpy of combustion of C6H14 to be approximately -4163 kJ/mol, to four significant figures.
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The Earth's mantle is
Q 3.6: calculate the number of po43- ions present in 23.7 g of ca3(po4)2.
23.7 g of Ca₃(PO₄)₎₂ contains 9.20 x 10^22 ions of PO₄³⁻
23.7 g of Ca₃(PO₄)₎₂ contains 0.1528 moles of PO₄³⁻ which is equivalent to 9.20 x 10^22 ions of PO₄³⁻
Further Explanation:An AtomAn atom is the smallest particle of an element that can take part in a chemical reaction. For example, sodium atom, Na. A MoleculeA molecule is a substance that is made up of one or more atoms. The atoms in a molecule may be similar or different making a compound. A compound A compound is a substances that contains two or more different atoms that are bonded together. When the atoms are similar the substance is known as a molecule, therefore not all molecules are compounds.Ca₃(PO₄)₎₂ is an example of a compound that contains three calcium ions and two Phosphate ions.Therefore;
Ca₃(PO₄)₎₂ ionizes to give out 3 Ca²⁺ ions and 2 PO₄³⁻ ions
Ca₃(PO₄)₎₂ → 3Ca²⁺ + 2PO₄³⁻
Required to determine the number of ions of PO₄³⁻ ions
Step 1: Moles of Ca₃(PO₄)₎₂Number of moles = Mass /Molar mass
Molar mass of Ca₃(PO₄)₎₂ = 310.1767 g/mol
Thus;
Moles = 23.7 g/310.1767 g/mol
= 0.0764 moles
Step 3: Moles of PO₄³⁻ ions1 mole of Ca₃(PO₄)₎₂ ionizes to give 2 moles PO₄³⁻ ions
Therefore;
0.0764 moles will produce;
= 0.0764 moles x 2
= 0.0152 moles PO₄³⁻ ions
Step 3: Number of PO₄³⁻ ions1 mole of PO₄³⁻ ions contains 6.022 x 10^23 ions
Therefore;
0.01528 moles PO₄³⁻ ions contains;
= 0.01528 x 6.022 x 10^23 ions
= 9.20 x 10^22 ions
Keywords: Atoms, ions, Moles, molar mass
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Subject: Chemistry
Topic: Moles
Sub-topic: Avogadro's constant
Predict the products in the reaction between magnesium and hydrochloric acid. If you were conducting this reaction in the lab, what would be your clue that this was a chemical reaction? If silver replaced magnesium as one of the reactants, what would you expect to happen?
Which element in the periodic table has the greatest electronegativity?
Both protons and neutrons are located inside the nucleus of an atom. Changing the number of neutrons in the nucleus would form different isotopes of the same element. Which of these BEST describes the outcome of decreasing the number of protons in the nucleus?
What physical property difference enabled you to Seperate salt from water?
Which group of drugs includes legal painkillers like OxyContin?
A.Stimulants
B.Hallucinogens
C.Depressants
D.Narcotics
Answer:
Narcotics
Explanation:
gradpoint
In a three-step calculation, would you round your answer after the first, second, or third step?
In a popular song from 1970, the musical group Crosby, Stills, and Nash use the line, "We are stardust." Why is this statement true?
Answer:
C
Explanation:
C) All elements, including those in our body, that are heavier than hydrogen are produced by fusion at the center of stars. Explosions of these stars then lead to the creation of planets and organisms.
Fission occurs at the star's core to create all elements heavier than hydrogen, including those found in human body. The subsequent explosions of these stars and it dust result in the formation of planets and life.
What are stars?Stars are massive objects in the universe with shining light and are grouped to any galaxy by the force of gravitation. Sun is a star who provide energy for us.
There are many more elements in each star which are formed through fusion such as hydrogen and helium in sun. Stars are thus the source of nuclear fusion.
Each stars have a definite life time and after that it will die by explosion and this result in a huge dust particles which are then contributing to the formation of other planets and gaseous atmosphere.
By fission takes place in the starts other elements are generated to form a stable atmosphere and that's why the musical group says that everything including them are from stardust and the statement is true.
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The compound zinc sulfate is a strong electrolyte. write the reaction when solid zinc sulfate is put into water:
Final answer:
Solid zinc sulfate dissolves in water by dissociating into zinc ions (Zn²⁺) and sulfate ions (SO₄²⁻), making it a strong electrolyte. This shows the nature of ionic compounds dissociating in solutions.
Explanation:
The question asks about the reaction when solid zinc sulfate is dissolved in water, incorrectly referencing reactions of zinc with hydrochloric acid and copper(II) sulfate. However, for zinc sulfate in water, the correct dissociation reaction is:
ZnSO₄(s) → Zn²⁺(aq) + SO₄²⁻(aq)
This equation shows that solid zinc sulfate dissociates into zinc ions (Zn²⁺) and sulfate ions (SO₄²⁻) when it is put into water, making it a strong electrolyte. It highlights the process by which ionic compounds like zinc sulfate split into their respective ions in a solution, thereby enhancing the solution's ability to conduct electricity.
Which substance can be decomposed by chemical means?
a.cobalt
b.krypton
c.methane
d.zirconium?
The substance that can be decomposed by chemical means is [tex]\boxed{{\text{c}}{\text{. methane}}}[/tex].
Further Explanation:
The pure form of matter is called substance whereas the combination of atoms and molecules is known as mixture.
Substance is further divided into two types:
1. Element
It is a type of pure substance and is the simplest form that cannot be broken down by any chemical means. Copper, iron, and cobalt are some of the examples of elements.
2. Compound
It is composed of two or more different elements that are held together by chemical bonds. These can be broken down into their respective constituents. Their properties are quite different from those of their constituent elements. NaCl, [tex]{\text{C}}{{\text{O}}_{\text{2}}}[/tex] and [tex]{{\text{H}}_{\text{2}}}{\text{O}}[/tex] are examples of compounds.
a. Cobalt is an element so it is the simplest form in which it can exist. Therefore it cannot be broken down or decomposed by chemical methods.
b. Krypton is an element so it is the simplest form in which it can exist. Therefore it cannot be broken down or decomposed by chemical methods.
c. Methane is formed from one carbon and four hydrogen atoms so it is a compound. Since compounds can be decomposed chemically, methane is also decomposed by chemical means.
d. Zirconium is an element so it is the simplest form in which it can exist. Therefore it cannot be broken down or decomposed by chemical methods.
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Answer details:
Grade: High School
Subject: Chemistry
Chapter: Elements, compounds, and mixtures
Keywords: substance, methane, cobalt, zirconium, krypton, element, compound, chemical means, decomposed, broken down, simplest form.
Dissolving a rock in acid is the equivalent of
Answer:
it is equivalent to the erosion of the rocks.
Explanation:
It can be said that the process of dissolving a rock is equivalent to the erosion process because erosion is the wear and tear on the rocks that is produced by the action of wind and water in their different forms. This wear is produced by the dragging of the particles from the rocks, produced by the impact of the particles that are moved in the medium against the rocks. When dissolving a rock in an acid, for example lemon or acetic acid, these acids react with the stone dissolving it, allowing the stone to break.
Pairs of valence electrons that are not involved in covalent bonding are known as
A student-made sample of sodium carbonate weighing 0.169g that generates 37.6 mL of CO2 gas when treated with sulfuric acid. The atmospheric pressure in the lab is 731.8 mm Hg and the temp. is 21.3-degree Celsius.
A. What is the partial pressure of CO2 gas generated from the sample in mm Hg? In atm?
B. How many moles of CO2 gas are produced?
C. How many moles of pure Na2CO3 were there in the sample?
D. How much was pure Na2CO3 there in the sample, in grams?
E. What was the percent of pure Na2CO3 in the sample?
First let us consider the CO₂ formed in the reaction where the variables are:
>Pressure, P = (731.8/760) atm
>Volume, V = 37.6 mL = 0.0376 L
>Gas constant, R = 0.0821 atm L / (mol K)
>Temperature, T = (273.2 + 21.3) K = 294.5 K
From the ideal gas law : PV = nRT
Then, n = PV/(RT)
number of moles CO₂ formed, n = (731.8/760) × 0.0376 / (0.0821 × 294.5) mol = 0.001497 mol
The complete balanced chemical equation for the reaction is:
Na₂CO₃ + H₂SO₄ → Na₂SO₄ + H₂O + CO₂
We see that the mole ratio is Na₂CO₃ : CO₂ = 1 : 1
Hence, the number of moles of Na₂CO₃ which reacted
=> n = 0.001497 mol
Calculating for molar mass of Na₂CO₃
=> (23.0×2 + 12.0 + 16.0×2) g/mol = 106.0 g/mol
Therefore, mass of Na₂CO₃ reacted
=> (0.001497 mol) × (106.0 g/mol) = 0.159 g
So the percent purity of Na₂CO₃ in the sample is
=> (0.159/0.169) × 100% = 94.1%
Summary of answers:
a. 731.8 mm Hg; 0.963 atm
b. 0.001497 mol
c. 0.001497 mol
d. 0.159 g
e. 94.1%
The CO₂ gas's partial pressure is found using atmospheric pressure, with conversion to atm. Moles of CO₂ and Na₂CO₃ are calculated using the ideal gas law and stoichiometry. The percent purity of Na₂CO₃ is determined by comparing pure Na₂CO₃ mass to the original sample mass.
Explanation:Gas Produced from Sodium Carbonate ReactionTo determine the partial pressure of CO₂ gas produced, we use the ideal gas law, corrected for non-standard conditions and vapor pressure of water (which is negligible here). Given the atmospheric pressure, we take that as the total pressure, assuming CO₂ is the only gas collected. The conversion to atm from mm Hg is done using the conversion factor: 1 atm = 760 mm Hg.
To find the number of moles of CO₂, we will use the ideal gas equation (PV=nRT) with the provided volume, temperature, and pressure. For the temperature, we'll convert from Celsius to Kelvin by adding 273.15.
To determine the moles of Na₂CO₃, we use the stoichiometry of the reaction between sodium carbonate and sulfuric acid, knowing that it produces sodium sulfate, water, and CO₂. The molar mass of Na₂CO₃ is needed to find the mass of the pure sodium carbonate in the sample.
Finally, the percent purity of Na₂CO₃ in the original sample is calculated using the mass of pure Na₂CO₃ obtained and the original mass of the sample.
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What type of reaction does one reactant form two or more products?
How does an enzyme increase the rate of the chemical reaction it catalyzes? how does an enzyme increase the rate of the chemical reaction it catalyzes? an enzyme's active site binds only the reactants, and not the products of a reaction, pushing the equilibrium for the reaction far to the right. an enzyme reduces the free-energy change (δg) of the reaction it catalyzes. an enzyme reduces the free energy of activation (ea) of the reaction it catalyzes?
Enzymes speed up chemical reactions by decreasing the energy needed for the reaction to occur and by providing a specific location (the active site) where the reaction can take place more easily.
Explanation:Enzymes are proteins that act as biological catalysts, meaning they speed up chemical reactions that take place within the cells of organisms. They do this by reducing the energy of activation (Ea) necessary for the reaction to take place. The energy of activation is the minimum amount of energy that reactants must have to undergo a chemical reaction. By reducing the Ea, an enzyme essentially 'lowers the bar' for the reaction to happen, allowing it to proceed faster.
The reactants in the reaction that an enzyme catalyzes, also known as the substrate, bind to a specific part of the enzyme called the active site. The enzyme and substrate fit together in a manner often compared to a 'lock and key'. Once the substrate is bound to the active site, the enzyme can facilitate the reaction, converting substrate to product and then releasing the product.
To summarize, enzymes increase the rate of chemical reactions by reducing the energy of activation and by providing a suitable environment for the reaction to occur at the enzyme's active site.
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Choose the correct order of electron structures from largest to smallest.
A. principal energy level, sublevel, orbital, electron
B. orbital, sublevel, principal energy level, electron
C. electron, orbital, sublevel, principal energy level
D. principal energy level, sublevel, electron, orbital
Answer:
Principal energy level, sublevel, orbital, electron. A table relating these classifications is attached.
Butane is used as a fuel in camping gas stoves.100 cm3 of butane is burned in excess oxygen .calculate the volume of carbon dioxide produced at r.t.p
The given for the problem:
100 cm^3 butane
Get first the molecular formula of butane and it is C4H10
To solution for the problem is:
2 C4H10 + 13 O2 = 8 CO2 + 10 H2O
n = V/22.4
n (C4H10) = 0.1/22.4 = 0.0047 mol
n (CO2) = 4 · n (C4H10) = 4 · 0.0047 = 0.018 mol
Burning 100 cm³ of butane in excess oxygen at STP produces 0.4 liters of carbon dioxide, as calculated through the stoichiometry of the balanced combustion reaction of butane.
When butane (C₄H₁₀) is burned in excess oxygen, the combustion reaction can be represented by the balanced equation:
2 C₄H₁₀(g) + 13 O₂(g) → 8 CO₂(g) + 10 H₂O(g)
The balanced equation shows that 2 moles of butane produce 8 moles of carbon dioxide (CO₂). At standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 L. Therefore, for every 2 moles (2 × 22.4 L) of butane, 8 moles (8 × 22.4 L) of CO₂ are produced. If we burn 100 cm³ (which is equivalent to 0.1 L) of butane, we need to determine how many moles this quantity represents and then calculate the corresponding volume of CO₂ produced.
First, we calculate the moles of butane:
0.1 L butane × (1 mole butane / 22.4 L) = 0.00446 moles butane
Using the stoichiometry of the reaction, the moles of CO₂ produced are 4 times the moles of butane:
0.00446 moles butane × (4 moles CO₂ / 1 mole butane) = 0.01784 moles CO₂
Now, we convert the moles of CO₂ to volume at STP:
0.01784 moles CO₂ × (22.4 L / 1 mole CO₂) = 0.4 L CO₂
Therefore, 100 cm³ of butane will produce 0.4 liters of carbon dioxide at STP when burned in excess oxygen.
The electron configuration for an atom is 1 s 2 2 s 2 2 p 2 . How many electrons does the atom have?
A. 6
B. 2
C. 5
D. 4
Answer:
D) 4
Explanation:
An element of Group II loses two electrons in the process of a chemical combination. What is its ionic charge?
Explanation:
An element that gains one electron will tend to acquire a negative charge whereas an element that tend to lose an electron will acquire a positive charge.
Similarly, an element losing two electrons will acquire a 2+ charge.
For example, calcium is a group II element and has 2 valence electrons. Therefore, to attain stability it loses two electrons and thus changes into [tex]Ca^{2+}[/tex] ion.
Hence, we can conclude that an element of Group II loses two electrons in the process of a chemical combination then its ionic charge will be +2.
The line spectrum of lithium has a red line at 670.8 nm. Calculate the energy of a photon with this wavelength.
Answer: The energy of the photon having the given wavelength is [tex]2.96\times 10^{-19}J[/tex]
Explanation:
We are given:
Wavelength of microwave = [tex]670.8nm=670.8\times 10^{-9}m[/tex] (Conversion factor: [tex]1m=10^9nm[/tex] )
To calculate the energy of one photon, we use Planck's equation, which is:
[tex]E=\frac{hc}{\lambda}[/tex]
where,
h = Planck's constant = [tex]6.625\times 10^{-34}J.s[/tex]
c = speed of light = [tex]3\times 10^8m/s[/tex]
[tex]\lambda[/tex] = wavelength = [tex]670.8\times 10^{-9}m[/tex]
Putting values in above equation, we get:
[tex]E=\frac{6.625\times 10^{-34}J.s\times 3\times 10^8m/s}{670.8\times 10^{-9}m}\\\\E=2.96\times 10^{-19}J[/tex]
Hence, the energy of the photon having the given wavelength is [tex]2.96\times 10^{-19}J[/tex]
References t6-3 hess's law for the reaction: agi(s) + br2(g) → agbr(s) + i2(s), δh° = –54.0 kj δhf° for agbr(s) = –100.4 kj/mol δhf° for br2(g) = +30.9 kj/mol the value of δhf° for agi(s) is:
By applying Hess's law, we can calculate the unknown standard enthalpy of formation for AgI(s) using the given standard enthalpy of reaction, and the standard enthalpies of formation for the other reactants and products.
Explanation:In order to determine the value of ΔHf° for AgI(s), we need to use Hess's law which states that the total enthalpy change in a chemical reaction is independent of the pathway over which the reaction takes place. The formula is as follows: ΔHrxn = Σ ΔHf°(products) - Σ ΔHf°(reactants).
Given: ΔHrxn = -54.0 kJ, ΔHf° for AgBr(s) = -100.4 kJ/mol, and ΔHf° for Br2(g) = +30.9 kJ/mol. Making AgI(s) the subject of the formula, we find ΔHf° for AgI(s) = Σ ΔHf°(products) - ΔHrxn, which upon substituting the values gives us the answer.
This method which employs Hess's law, enthalpy of formation, and the known quantities to provide the unknown standard enthalpy of formation for AgI(s) is representative of typical approaches in thermochemistry.
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The enthalpy of formation for AgI(s) is calculated using Hess's Law with the known enthalpies of formation for AgBr(s) and Br₂(g). Applying the enthalpy change for the reaction, the ΔH°f for AgI(s) is found to be -15.5 kJ/mol.
To determine the enthalpy of formation (ΔH°f") of AgI(s) for the reaction AgI(s) + Br₂(g) → AgBr(s) + I₂(s) using Hess's Law:
First, use the given enthalpy change of the reaction, which is -54.0 kJ.We know ΔH°f for AgBr(s) is -100.4 kJ/mol and ΔH°f for Br₂(g) is 30.9 kJ/mol. The enthalpy of formation for elements in their standard state (like I₂(s)) is zero.Apply Hess's Law: ΔH° = (ΔH°f of products) - (ΔH°f of reactants). Inserting the known values:-54.0 kJ = (-100.4 kJ/mol) - (ΔH°f of AgI(s) + 30.9 kJ/mol)Rearrange to solve for ΔH°f of AgI(s):ΔH°f of AgI(s) = -100.4 kJ + 30.9 kJ + 54.0 kJΔH°f of AgI(s) = -15.5 kJ/molalthough the story of Beowulf is set in Scandinavia what language was it written in
Answer:
Although the story of Beowulf is set in Scandinavia what language was it written in Old English.
Explanation:
Beowulf is a very old piece of literary genre. It is one of the earliest European epic written in vernacular language. It is an epic poem written in old English. The setting of the story has been set in Scandinavia. Beowulf is the hero of the poem. He is the protagonist of the story who survives the attacks of the monster named Grendel.
Answer:
OLD ENGLISH
Explanation:
what language "Beowulf" was written in originally. The first manuscript was written in the language of the Saxons, "Old English," also known as "Anglo-Saxon." Since then, the epic poem has been estimated to have been translated into 65 languages
Coal is plentiful and inexpensive; therefore many countries use it despite its environmental impacts. True or False
(5.3 x 10^4 ) + (1.3 x 10^4 )
i have to express it into scientific notation and than find the significant figure.
What elements on the periodic table are most likely to form molecular compounds?
What mass, in g, of agcl is formed from the reaction of 75.0 ml of a 0.078 m agc2h3o2 solution with 55.0 ml of 0.109 m mgcl2 solution? 2 agc2h3o2(aq) + mgcl2(aq) â 2 agcl(s) + mg(c2h3o2)2(aq)?
Answer:
The mass we will get from AgCl is 0.839g
Explanation:
Hello!
Let's solve this!
The reaction is:
2AgC2H3O2 + MgCl2 ---> 2AgCl + Mg (C2H3O2) 2
The data we have are:
V1 = 75mL * (1L / 1000L) = 0.075L
M1 = 0.078M
V2 = 55mL * (1L / 1000mL) = 0.055L
M2 = 0.109M
The molarity formula is
M = mol / V
We calculate the moles of each compound:
molAgC2H3O2 = 0.075L * 0.078mol / L = 0.00585mol
molMgCl = 0.055L * 0.109M = 0.005995
We calculate the compound that is in excess, and then use the limiting reagent to calculate the amount of product we will obtain.
Since there are two Cl in MgCl2, this means that we have 0.01199 mol to produce the product, but we will only use 0.00585 mol which is the amount we have of AgC2H3O2. So MgCl is the excess reagent.
Then:
AgCl mass = 0.00585mol * (2mol AgCl / 2molAgC2H3O2) * (143.34g AgCl / 1mo AgCl) = 0.839gAgCl
The mass we will get from AgCl is 0.839g
0.839 g of AgCl is formed.
Further explanationGiven a reaction between:
75.0 ml of a 0.078 M AgC₂H₃O₂ solution 55.0 ml of 0.109 M MgCl₂ solutionQuestion:
What mass, in g, of AgCl is formed?
The Process:
Step-1:
Let us find the mole numbers of both reagents:
[tex]\boxed{ \ Concentration \ (M) = \frac{moles \ (n)}{volume \ (V)} \ } \rightarrow \boxed{ \ n = MV \ }[/tex]
AgC₂H₃O₂ → 0.078 x 0.075 = 5.85 mmol
MgCl₂ → 0.109 x 0.055 = 5.995 mmol
Step-2:
The equation for the reaction is
[tex]\boxed{ \ 2 AgC_2H_3O_2_{(aq)} + MgCl_2_{(aq)} \rightarrow 2 AgCl_{(s)} + Mg(C_2H_3O_2)_2_{(aq)} \ }[/tex]
According to the equation, 2 mol of AgC₂H₃O₂ react with 1 mol of AgCl.
Let us check which substances will be a limiting reagent.
AgC₂H₃O₂ → [tex]\boxed{ \ \frac{5.85}{2} = 2.925 \ }[/tex]
MgCl₂ → [tex]\boxed{ \ \frac{5.995}{1} = 5.995 \ }[/tex]
AgC₂H₃O₂ is the limiting reagent because the test results are the smallest.
Step-3:
As AgC₂H₃O₂ is the limiting reagent, the amount of AgCl produced will be determined by the amount of AgC₂H₃O₂. Since the proportion between the mole numbers of AgC₂H₃O₂ and AgCl is one to one, their mole numbers will be equal:
[tex]\boxed{ \ The \ mole \ of AgCl = \frac{1}{1} \times the \ mole \ of \ AgC_2H_3O_2 \ }[/tex]
So the amount of AgCl is 5.85 moles.
Step-4:
Prepare the molar mass of AgCl.
Mr = 108 + 35.5 = 143.5 g/mol
Let us find out how many mass, in g, of AgCl is formed.
[tex]\boxed{ \ mol \ (n) = \frac{mass \ (g)}{molar \ mass \ (Mr)} \ } \rightarrow \boxed{ \ g = n \times Mr \ }[/tex]
Mass = 5.85 mmol x 143.5 g/mol
Mass = 839.475 mg ≈ 0.839 g.
Thus the amount of AgCl is formed is 0.839 g.
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How many moles of S are in 35.4 g of (C3H5)2S?
What element is represented by the electron configuration [ar]4s23d8?
Answer:
Nickel
Explanation:
The element which have the electronic configuration of [Ar]4s²3d⁸ is Nickel
What is electronic configuration?This is the arrangement of electrons in the various energy levels of an atom.
The number of electrons to be filled in the energy levels is equal to the atomic number of the element
How to determine the elementElectronic configuration = [Ar]4s²3d⁸Atomic number of Ar = 18Element =?Atomic number of element = Ar + 2 + 8
Atomic number of element = 18 + 2 + 8
Atomic number of element = 28
From the periodic table, only Nickel has atomic number of 28.
Thus, we can conclude that the element having the electronic configuration of [Ar]4s²3d⁸ is Nickel
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