Answer:
Step-by-step explanation:
The values of x are given as
0, 1, 2, 3
The corresponding values of y are given as
0,5 10,15
Let k represent constant of proportionality
Therefore,
When x = 0, y = 0
When x = 1, y = 5
y/x = k
k = 5/1 = 5
When x = 2, y = 10
y/x = k
k = 10/2 = 5
When x = 3, y = 15
y/x = k
k = 15/3 = 5
Therefore, the constant of proportionality is 5
The equation to represent the table is
y = 5x
Determine whether the distribution is a discrete probability distribution. x âP(x) 0 0.21 1 0.28 2 0.02 3 0.28 4 0.21 Is the distribution a discrete probabilityâ distribution? Why? Choose the correct answer below. A. No comma because the total probability is not equal to 1. B. No comma because some of the probabilities have values greater than 1 or less than 0. C. Yes comma because the distribution is symmetric. D. Yes comma because the probabilities sum to 1 and are all between 0 and 1 comma inclusive.
Answer:
D. Yes, because the probabilities sum to 1 and are all between 0 and 1, inclusive.
Step-by-step explanation:
0.21 + 0.28 + 0.02 + 0.28 + 0.21 = 1
All individual data are between 0 and 1. Data added up = 1
The true statement is (d) Yes, because the probabilities sum to 1 and are all between 0 and 1, inclusive.
For a distribution to be a discrete probability distribution, the following must be true
[tex]\sum P(x) =1[/tex]
So, we have:
[tex]\sum P(x) = 0.21 + 0.28 + 0.02 + 0.28 + 0.21[/tex]
Evaluate the sum
[tex]\sum P(x) =1[/tex]
The above statement shows that the distribution is a discrete probability distribution
Hence, the true statement is (d) Yes, because the probabilities sum to 1 and are all between 0 and 1, inclusive.
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Let the distribution of X be Binomial(150,0.8). The next 4 questions correspond to this information. The answer may be rounded up to 3 decimal places of the actual value:
Answer:
Step-by-step explanation:
Hello!
Missing Questions:
1) The probabylity of P(121 < X ≤ 129) is:
You can rewrite it as:
P(X ≤ 129) - P(X < 121)
Now the expression " P(X < 121)" does not include 121 so to calculate this interval you have to substract the cummulative probability to the previoous value of the variable " P(X ≤ 120)"
Then the interval is
P(X ≤ 129) - P(X ≤ 120)= 0.978 - 0.533= 0.445
2) The approximation to normal (without correction of continuity) of P(121 < X ≤ 129) is:
To use the normal approximation you have to calculate the mean and variance of the variable.
E(X)= np= 150*0.8= 120
V(X)= np(1-p)= 150*0.8*0.2= 24
Now you can standardize the given interval:
P(X ≤ 129) - P(X < 121)= P(Z ≤ (129-120)/√24) - P(Z < (121-120)/√24)
P(Z ≤ 1.84) - P(Z < 0.20) = 0.967 - 0.579= 0.388
3) The approximation to normal (with correction of continuity) of P(121 < X ≤ 129) is:
P(121 < X ≤ 129)
Applying the correction of continuity:
For X ≤ n + 0.5
For X > n + 0.5
P(121.5 < X ≤ 129.5) = P(X ≤ 129.5) - P(X < 121.5)
P(Z ≤ (129.5-120)/√24) - P(Z < (121.5-120)/√24)
P(Z ≤ 1.94) - P(Z < 0.31) = 0.974 - 0.622= 0.352
4) The approximation of poisson of P(121 < X ≤ 129) is:
First define the rate of successes of the distribution λ= np= 150*0.8= 120
Then you look at the individual cummulative probabilities using the tables of the distribution:
P(X ≤ 129; λ= 120)= 0.808
P(X < 121; λ= 120)= P(X ≤ 120; λ= 120)= 0.524
P(121 < X ≤ 129) = P(120 ≤ X ≤ 129)= P(X ≤ 129) - ≤ 129)= 0.808 - 0.524= 0.284
I hope it helps!
Tim claims that a coin is coming up tails less than half of the time. In 110 tosses, the coin comes up tails 47 times. Using P-value, test Tim's claim. Use a 0.10 significance level and determine conclusion.
Answer:
[tex]z=\frac{0.427 -0.5}{\sqrt{\frac{0.5(1-0.5)}{110}}}=-1.531[/tex]
[tex]p_v =P(z<-1.531)=0.0629[/tex]
If we compare the p value obtained and using the significance level given [tex]\alpha=0.1[/tex] we have that [tex]p_v<\alpha[/tex] so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 10% of significance the proportion of tails is significantly less than 0.5.
Step-by-step explanation:
1) Data given and notation
n=110 represent the random sample taken
X=47 represent the number of tails obtained
[tex]\hat p=\frac{47}{110}=0.427[/tex] estimated proportion of tails
[tex]p_o=0.5[/tex] is the value that we want to test
[tex]\alpha=0.1[/tex] represent the significance level
Confidence=90% or 0.90
z would represent the statistic (variable of interest)
[tex]p_v[/tex] represent the p value (variable of interest)
2) Concepts and formulas to use
We need to conduct a hypothesis in order to test the claim that the proportion of tails is lower than 0.5:
Null hypothesis:[tex]p\geq 0.5[/tex]
Alternative hypothesis:[tex]p < 0.5[/tex]
When we conduct a proportion test we need to use the z statistic, and the is given by:
[tex]z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}[/tex] (1)
The One-Sample Proportion Test is used to assess whether a population proportion [tex]\hat p[/tex] is significantly different from a hypothesized value [tex]p_o[/tex].
3) Calculate the statistic
Since we have all the info requires we can replace in formula (1) like this:
[tex]z=\frac{0.427 -0.5}{\sqrt{\frac{0.5(1-0.5)}{110}}}=-1.531[/tex]
4) Statistical decision
It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.
The significance level provided [tex]\alpha=0.1[/tex]. The next step would be calculate the p value for this test.
Since is a left tailed test the p value would be:
[tex]p_v =P(z<-1.531)=0.0629[/tex]
If we compare the p value obtained and using the significance level given [tex]\alpha=0.1[/tex] we have that [tex]p_v<\alpha[/tex] so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 10% of significance the proportion of tails is significantly less than 0.5.
These data represent the volumes in cubic yards of the largest dams in the united states and in South America. Construct a boxplot of the data for each region and compare the distribution.
United States South America
125,628 311,539
92,000 274,026
78,008 105,944
77,700 102,014
66,500 56,242
62,850 46,563
52,435
50,000
By organizing the data and determining the minimum, maximum, median, and quartiles for the volumes of the largest dams in the United States and South America, we can construct boxplots to compare the distribution of the data in each region Create a text based boxplot
United States:
+---------+---------+---------+---------+---------+
| Minimum | Q1 | Median | Q3 | Maximum |
+---------+---------+---------+---------+---------+
|-----|-----|-----|-----|-----|
50,000 77,700 77,854 108,814 125,628
South America:
+---------+---------+---------+---------+---------+
| Minimum | Q1 | Median | Q3 | Maximum |
+---------+---------+---------+---------+---------+
|-----|-----|-----|-----|-----|
46,563 51,403 103,979 292,783 311,539
To construct a boxplot for the volumes of the largest dams in the United States and South America, we will first need to organize the data in ascending order. Then we can determine the minimum, maximum, median, and quartiles. The boxplot will allow us to compare the distribution of the data for each region.
United States volumes (in cubic yards) in ascending order:
50,000
52,435
62,850
66,500
77,700
78,008
92,000
125,628
South America volumes (in cubic yards) in ascending order:
46,563
56,242
102,014
105,944
274,026
311,539
Now, we can find the minimum, maximum, median, and quartiles for each dataset:
United States:
- Minimum: 50,000
- Maximum: 125,628
- Median: The middle value is the average of the two middle values, (77,700 + 78,008) / 2 = 77,854
- First Quartile (Q1): The median of the lower half of the dataset, (52,435 + 62,850) / 2 = 57,642.5
- Third Quartile (Q3): The median of the upper half of the dataset, (92,000 + 125,628) / 2 = 108,814
South America:
- Minimum: 46,563
- Maximum: 311,539
- Median: The middle value is the average of the two middle values, (102,014 + 105,944) / 2 = 103,979
- First Quartile (Q1): The median of the lower half of the dataset, (46,563 + 56,242) / 2 = 51,402.5
- Third Quartile (Q3): The median of the upper half of the dataset, (274,026 + 311,539) / 2 = 292,782.5
With this information, we can construct boxplots for each region. The boxplots will visually represent the minimum, first quartile, median, third quartile, and maximum values for each dataset.
We flip a fair coin five times. For every heads you pay me $1 and for every tails I pay you $1. Let X denote the my net winning at the end of the flips. Find the possible values and the probability mass function of X.
The possible values of net winnings in this coin flipping game range from -5 to 5 dollars. The individual probabilities of these outcomes can be calculated using a binomial probability distribution. The game is symmetric because of the fairness of the coin, resulting in the probability of winning and losing $5 being equal.
Explanation:In this coin flipping game
, we have five independent trials (flips) each having two possible outcomes (heads or tails). This implies
a binomial distribution
is expected. In each trial, 'success' can be defined as getting heads, and 'failure' as getting tails. Number of successes (X) can range from 0 to 5, that is your net winnings can be from -5 to 5 dollars.
The Probability Mass Function (PMF) of X can be calculated using the binomial distribution formula, which is: P(X=k) = (5 choose k) * (0.5)^k * (0.5)^(5-k), where k represents number of 'successes' (heads), (5 choose k) is the number of combinations of getting k successful outcomes in 5 trials, and (0.5) is the probability of getting heads or tails.
PMF will give you the probability of each possible outcome (from -5 to 5 dollars), which in this specific scenario is symmetric due to the coin being fair. So for instance, winning $5 and losing $5 both have a probability of (0.5)^5 = 0.03125.
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I need help with letter B, please!
The general question on the photo says: a company is hiring a truck driver to deliver the company's product. Truck driver A charges an initial fee of $50 plus $7 per mile. Truck driver B charges an initial fee of $175 plus $2 per mile
Question B: Solve the system of linear equations by graphing. Interpret your solution.
I will give 25 points if someone gets the answer correct right away!
So if you want to fit the y-intercepts or "b", on the y-axis you should go by 25's [0, 25, 50, 75, 100...]
If the x-axis does not have to follow the same pattern (25's), you should go by 5's [0, 5, 10, 15, 20...]
y = 7x + 50
y = 2x + 175
First I would plot the y-intercepts for each equation, then plot a few points with x = 5, 10, 15 Then draw a straight line.
The point where the two lines meet/cross paths is your solution. It should be (25, 225) The x-axis is the number of miles, and the y-axis is the total cost. So Truck driver A and B would arrive/be at the same place/meet in 25 miles at the same cost of $225
Suppose that in a certain metric geometry satisfying Axioms D-1-D-3, points A, B, C, and D are collinear and AB = AC = 3,BC = 6,BD = 2,and AD = 1. If the Ruler Postulate is also valid, find CD
Answer:
We calculate that is CD=4.
Step-by-step explanation:
From Exercise we have that
AB=AC=3
BC=6
BD=2
AD=1.
From Axioms D-1 and D-3, we have
D-1: ∀ A, B∈ S, there is a unique AB ∈ R
D-3: ∀ A, B∈ S, AB=BA.
We use the Axioms D-1 and D-3, and we get that
AC=CA=3
AD=1
because are the points is collinear, we get
CA+AD=CD
3+1=CD
CD=4
We calculate that is CD=4.
Final answer:
To find the length of segment CD, we assume points on a collinear path as A-D-B-C, and subtract the length of BD from BC, resulting in CD = 4 units.
Explanation:
The student has asked for the length of segment CD when given a set of collinear points A, B, C, and D, with various distances between them. Since we have point B between points A and C, and points A and D, and knowing AB, AC, BC, and BD, we can determine the length of AD by subtracting from AC the length of BC, since AB equals AC. Therefore, AD = AC - BC = 3 - 6 = -3, which does not make sense geometrically since lengths cannot be negative. This might imply a typo or a misinterpretation of the points' arrangement. If assuming points in a line segment: A-D-B-C, CD can be found by subtracting BD from BC, CD = BC - BD = 6 - 2 = 4.
Suppose a normally distributed set of data has a mean of 102 and a standard deviation of 20. Use the 68-95-99.7 Rule to determine to determine the percent of scores in the data set expected to be below a score of 151. Give your answer as a percent and includeas many decimal places as the 68-95-99.7 rule dictates. (For example, enter 99.7 instead of 0.997.)
Answer:
0.71%
Step-by-step explanation:
Given that a normally distributed set of data has a mean of 102 and a standard deviation of 20.
Let X be the random variable
Then X is N(102, 20)
We can convert this into standard Z score by
[tex]z=\frac{x-102}{20}[/tex]
We are to find the probability and after wards percentage of scores in the data set expected to be below a score of 151.
First let us find out probability using std normal table
P(X<151) = [tex]P(Z<\frac{151-102}{20} \\=P(Z<2.45)\\=0.5-0.4929\\\\=0.0071[/tex]
We can convert this into percent as muliplying by 100
percent of scores in the data set expected to be below a score of 151.
=0.71%
Substitute yequalse Superscript rx into the given differential equation to determine all values of the constant r for which yequalse Superscript rx is a solution of the equation. y double prime plus 4 y prime minus 12 y equals 0
Answer:
y(x)=C_1·e^{2x} + C_2·e^{-6x}
Step-by-step explanation:
From Exercise we have the differential equation
y''+4y'-12=0.
This is a characteristic differential equation and we are solved as follows:
y''+4y'-12=0
m²+4m-12=0
m_{1,2}=\frac{-4±\sqrt{16+48}}{2}
m_{1,2}=\frac{-4±\sqrt{64}}{2}
m_{1,2}=\frac{-4±8}{2}
m_1=2
m_2=-6
The general solution of this differential equation is in the form
y(x)=C_1·e^{m_1 ·x} + C_2·e^{m_2 ·x}
Therefore, we get
y(x)=C_1·e^{2x} + C_2·e^{-6x}
The correct values of the constant [tex]\( r \)[/tex] for which [tex]\( y = e^{rx} \)[/tex] is a solution of the differential equation [tex]\( y'' + 4y' - 12y = 0 \)[/tex] are [tex]\( r = 2 \)[/tex] and [tex]\( r = -6 \).[/tex]
To find the values of [tex]\( r \)[/tex], we substitute [tex]\( y = e^{rx} \)[/tex] into the differential equation. First, we find the first and second derivatives of [tex]\( y \)[/tex]:
[tex]\[ y' = \frac{d}{dx}(e^{rx}) = re^{rx} \][/tex]
[tex]\[ y'' = \frac{d}{dx}(re^{rx}) = r^2e^{rx} \][/tex]
Now, we substitute [tex]\( y \)[/tex], [tex]\( y' \)[/tex], and [tex]\( y'' \)[/tex] into the differential equation:
[tex]\[ y'' + 4y' - 12y = 0 \][/tex]
[tex]\[ r^2e^{rx} + 4re^{rx} - 12e^{rx} = 0 \][/tex]
Since [tex]\( e^{rx} \)[/tex] is never zero, we can divide through by [tex]\( e^{rx} \)[/tex] to get the characteristic equation:
[tex]\[ r^2 + 4r - 12 = 0 \][/tex]
Now, we solve this quadratic equation for [tex]\( r \)[/tex]:
[tex]\[ r^2 + 6r - 2r - 12 = 0 \][/tex]
[tex]\[ r(r + 6) - 2(r + 6) = 0 \][/tex]
[tex]\[ (r - 2)(r + 6) = 0 \][/tex]
Setting each factor equal to zero gives us the possible values for [tex]\( r \)[/tex]:
[tex]\[ r - 2 = 0 \quad \Rightarrow \quad r = 2 \][/tex]
[tex]\[ r + 6 = 0 \quad \Rightarrow \quad r = -6 \][/tex]
Therefore, the values of [tex]\( r \)[/tex] for which [tex]\( y = e^{rx} \)[/tex] is a solution of the given differential equation are [tex]\( r = 2 \)[/tex] and [tex]\( r = -6 \).[/tex]
In finding the areas under the normal curve, if we wish to determine the area between A and B, and both A and B are greater than the mean (with A further away from the mean than B)
a)We find the area between the mean and A and subtract the area between the mean and B
b)We find the area between the mean and A and add the area between the mean and B
c)We find the area between the mean and A and subtract it from .50
d)We find the area between the mean and A and add it to .50
Answer:
a.
Step-by-step explanation:
A and B both are greater than mean and so A and B lies on the right side of mean. Further it is stated that A is more away from the mean than B. It means that A is greater than B. So, in order to find the area between A and B we have to subtract the area of mean to B from area of mean to A. It can be explain in the notations as
P(B<X<A)=P((B-μ)/σ<z<(A-μ)/σ)
P(B<X<A)=P(z<(A-μ)/σ)-P(z<(B-μ)/σ)
Hence, we find the area from mean to A and subtract the area from mean to B.
Earth is approximately a sphere of radius 6.37 × 106 m. What are (a) its circumference, (b) its surface area, and (c) its volume?
Answer:
(a) 4.00×10^7 m
(b) 5.10×10^14 m^2
(c) 1.083×10^21 m^3
Step-by-step explanation:
Put the given value of radius into the various formulas and do the arithmetic. Your scientific calculator can show you the results in scientific notation.
C = 2πr = 2π·6.37×10^6 m ≈ 4.00×10^7 m* . . . circumference
A = 4πr^2 = 4π(6.37×10^6 m)^2 ≈ 5.10×10^14 m^2 . . . area
V = (4/3)πr^3 = (4/3)π(6.37×10^6 m)^3 ≈ 1.083×10^21 m^3 . . . volume
_____
* An early definition of the meter was 10^-7 times the distance from the North Pole to the Equator as measured through Paris, France.
A concrete column has a diameter of 350mm and a length of 2m. If the density (mass/volume) of concrete is 2.45 Mg/m3 determine the weight of the column in pounds. 1 pound = 4.4482 N
Answer:
The weight of concrete column is 1039 Newton.
Step-by-step explanation:
We are given the following in the question:
Diameter of column = 350 mm = 0.35 m
[tex]\text{Radius} = \dfrac{\text{Diameter}}{2} = \dfrac{0.35}{2} = 0.175 ~m[/tex]
Length of column = 2 m
Density of column = 2.45 Mg per meter cube
Volume of column =
[tex]\text{Volume of cylinder}\\= \pi r^2h\\\text{where r is the radius and h is the height}\\V = \dfrac{22}{7}\times (0.175)^2\times 2\\\\V = 0.1925\text{ cubic meter}[/tex]
Mass of column =
[tex]\text{Volume of column}\times \text{Density of cone}\\= 2.45\times 0.1925\\=0.4716~ Mg\\=0.4716\times 10^3~Kg\\= 471.6~Kg[/tex]
Weight of column =
[tex]\text{Mass}\times g\\= 471.6\times 9.8\\= 4621.68~ N[/tex]
Weight in pounds =
[tex]1 \text{ pound} = 4.4482 ~N\\\\\Rightarrow \dfrac{4621.68}{4.4482} = 1039\text{ pounds}[/tex]
The weight of concrete column is 1039 Newton.
Final answer:
To determine the weight of the concrete column in pounds, calculate its mass using the density formula and then convert it using the conversion factor. The weight of the column is approximately 1.882π lb.
Explanation:
To determine the weight of the concrete column in pounds, we need to calculate its mass and then convert it to pounds using the conversion factor. First, let's find the volume of the column by using the formula for the volume of a cylinder: V = πr^2h, where r is the radius and h is the height.
The radius is half the diameter, so r = 350mm / 2 = 175mm = 0.175m. The height is given as 2m. Thus, the volume is: V = π(0.175m)^2 * 2m = 0.1925π m³.
Next, we can calculate the mass of the concrete using the density formula: mass = density * volume. Plugging in the given density of concrete (2.45 Mg/m³) and the calculated volume, we get: mass = 2.45 Mg/m³ * 0.1925π m³ = 0.425π Mg.
To convert the mass to pounds, we need to multiply by the conversion factor of 4.4482 N / 1 lb. Using this conversion factor, the weight of the concrete column is: weight = 0.425π Mg * 4.4482 N / 1 lb = 1.882π lb.
A population of 30 deer are introduced into a wildlife sanctuary. It is estimated that the sanctuary can sustain up to 400 deer. Absent constraints, the population would grow by 40% per year.
Estimate the population after one year p1 =
Estimate the population after two years p2=
The population after one year would be 42 deer.
And, the population after two years would be 59 deer.
Used the concept of compound interest where the amount A after t years, starting from an initial value P and growing at a rate r is:
[tex]A = P(1+r)^t[/tex]
Given that,
A population of 30 deer is introduced into a wildlife sanctuary.
Hence, After one year we have;
P₁ = 30 (1 + 0.40)¹
= 42
After two years;
P₂ = 30 (1 + 0.40)²
= 59
Thus, the population after one year = 42 deer.
And, the population after two years = 59 deer.
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Solve for the vector x + 2a - b in terms of the vectors a and b. (If needed, use BOLD vector form on calcPad Vector menu.) x + 2a - b = 5(x + a) - 2(3a - b) x =
Answer:
x+2a-b=5x+5a-2*3a+2*b
x+2a-b=5x+5a-6a+2b
x+2a-b=5x-a+2b
5x-x=2a-b+a-2b
4x=3a-3b
4 x=3(a-b)
x=3/4(a-b)
The answer of the vector x in the form of a and b is 3/4(a-b).
What is vector ?"A vector is an object that has both a magnitude and a direction. Geometrically, we can picture a vector as a directed line segment, whose length is the magnitude of the vector and with an arrow indicating the direction. The direction of the vector is from its tail to its head."
Here,
[tex]x + 2a - b = 5(x + a) - 2(3a - b) x[/tex]
[tex]x+2a-b=5x+5a-6a+2b\\\\x+2a-b=5x-a+2b\\\\5x-x=2a-b+a-2b\\\\4x=3a-3b\\\\4 x=3(a-b)\\\\x=3/4(a-b)\\[/tex]
Hence the vector x = 3/4(a-b)
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A single card is drawn from a standard deck. Find the probability of the following event. Drawing a jack or a face card
Answer:
16/52 or 4/13 when reduced.
Step-by-step explanation:
4/52 is for the Jack card since there are 4 jack cards out of a total of 52 cards.
12/52 is for the face cards since there are 12 face cards out of a total of 52 cards.
Since the problem says OR, this means one or the other, so you will be adding those two fractions together. If the problem said AND, this would mean that you have to multiply since both would have to occur.
The probability of selecting a heart or a face card from a standard deck of cards is 22/52.
To calculate the probability of selecting a heart or a face card from a standard deck of cards, we must consider the total number of heart cards and face cards in the deck, mindful not to double-count any cards that are both. A standard deck has 52 cards, 12 of which are face cards (3 face cards per suit, and there are 4 suits in total). Besides these 12 face cards, there are 13 heart cards, but since three of them are face cards, which we have already counted, we subtract those, leaving us with 10 additional heart cards. Thus, the total number of favorable outcomes is 12 (face cards) + 10 (non-face-card hearts) = 22.
The probability of drawing a heart or face card is then 22 favorable outcomes divided by 52 possible outcomes, which simplifies to 11/26 or about 42.31%.
To understand if this outcome is more or less likely than selecting a heart suit face card, we consider that there are only 3 face cards in the hearts suit. Hence, the probability of drawing a heart suit face card is 3/52 or about 5.77%. Clearly, drawing a heart or a face card is more likely than drawing a heart suit face card alone, as 42.31% > 5.77%.
In the rolling of two fair dice calculate the following: P(Sum of the two dice is 7) = ______
Answer:
P(Sum of the two dice is 7) = 6/36
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
In this problem, we have that:
A fair dice can have any value between 1 and 6 with equal probability. There are two fair dices, so we have the following possible outcomes.
Possible outcomes
(first rolling, second rolling)
(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)
(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)
(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)
(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)
(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)
(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)
There are 36 possible outcomes.
Desired outcomes
Sum is 7, so
(1,6), (6,1), (5,2), (2,5), (3,4), (4,3).
There are 6 desired outcomes, that is, the number of outcomes in which the sum of the two dice is 7.
Answer
P(Sum of the two dice is 7) = 6/36
Final answer:
The probability of getting a sum of 7 while rolling two fair dice is 1/6.
Explanation:
In the rolling of two fair dice, the probability of getting a sum of 7 is:
There are 6 ways to get a sum of 7: (1,6), (2,5), (3,4), (4,3), (5,2), and (6,1).
There are a total of 36 possible outcomes when rolling two dice, each with a probability of 1/36.
Therefore, the probability of rolling a sum of 7 is 6/36 or 1/6.
Find an equation of the sphere with points P such that the distance from P to A(−3, 4, 4) is twice the distance from P to B(6, 3, −1). Find its center and radius. center (x, y, z) = radius
Answer:
Therefore, we conclude that the center of sphere at point
(27/3, -8/3, -8/3) with a radius 6.89.
Step-by-step explanation:
We have the formula for distance, we get
\sqrt{(x+3)^2+(y-4)^2+(z-4)^2} =2· \sqrt{(x-6)^2+(y-3)^2+(z+1)^2}
(x+3)^2+(y-4)^2+(z-4)^2=4·[(x-6)^2+(y-3)^2+(z+1)^2]
x²+6x+9+y²-8y+16+z²-8z+16=4x²-48x+4y²-24y+4z²+8z+184
3x²+3y²+3z²-54x+16y+16z=-143
(x²-54x/3)+(y²+16y/3)+(z²+16z/3)=-143/3
(x²-54x/3+729/9)+(y²+16y/3+64/9)+(z²+16z/3+64/9)=-143/3+729/9+2·64/9
(x-27/3)²+(y+8/3)²+(z+8/3)²=428/9
We calculate a radius \sqrt{428/9} =6.89
Therefore, we conclude that the center of sphere at point
(27/3, -8/3, -8/3) with a radius 6.89.
To find the equation of the sphere in question, use the property that the distance from P to A is twice the distance from P to B, and solve the resulting equation to find the sphere's center and radius.
Explanation:To find an equation of a sphere where the distance from a generic point P to the point A(−3, 4, 4) is twice the distance from P to the point B(6, 3, −1), we use the geometric properties of spheres and distances in three-dimensional space. The distance from a point P to another point Q in 3D space, with coordinates P(x1, y1, z1) and Q(x2, y2, z2), can be found using the distance formula d = √((x2 − x1)² + (y2 − y1)² + (z2 − z1)²).
Let's denote the coordinates of P as (x, y, z). To satisfy the given condition, we have to solve the equation (x + 3)² + (y − 4)² + (z − 4)² = 4[(x − 6)² + (y − 3)² + (z + 1)²]. This equation is derived from setting the distance from P to A as twice the distance from P to B and then squaring both sides to eliminate the square root.
Solving this equation will give us the center and radius of the sphere.
Make a substitution to express the integrand as a rational function and then evaluate the integral. (Remember to use absolute values where appropriate. Use C for the constant of integration.) x + 25 x dx
Answer:
∫(x+25x)dx=13x²
Step-by-step explanation:
From Exercise, we want calculate integral for x + 25 x dx.
But this not required a substitution to express the integrand as a rational function. We can calculte integral, and we get
∫(x+25x)dx= ∫x dx+25∫x dx=x²/2+ \frac{25}{2} · x^2=\frac{26}{2}·x^2=13x²
Therefore, we get that is
∫(x+25x)dx=13x².
Suppose that a fungal disease originates in the middle of an orchard, initially affecting only one tree. The disease spreads out radially at a constant speed of 45 feet per day.
(a) What area will be affected after 2 days?
(b) What area will be affected after 4 days?
(c) What area will be affected after 8 days?
(d) Write a formula for the affected area as a function of time, measured in days. Use t as your variable for time, in days.
Answer:
a) 25446.90 ft²
b) 101787.60 ft²
c) 407150.41 ft²
d) 2025πt²
Step-by-step explanation:
Data provided in the question:
Rate of spread radially = 45 feet per day
a) Radius of spread after 2 days
= 45 × 2
= 90 feet
Therefore,
Area affected = πr²
= π(90)²
= 25446.90 ft²
b) Radius of spread after 2 days
= 45 × 4
= 180 feet
Therefore,
Area affected = πr²
= π(180)²
= 101787.60 ft²
c) Radius of spread after 2 days
= 45 × 8
= 360 feet
Therefore,
Area affected = πr²
= π(360)²
= 407150.41 ft²
a) Radius of spread after t days
= 45 × t ft
Therefore,
Area affected = πr²
= π(45t)²
= 2025πt²
The area affected by the fungal disease, which spreads radially at a constant speed, can be calculated by using the formula for the area of a circle, where the radius is the product of the spread speed and time. After 2, 4, and 8 days, the areas affected are 25,446 square feet, 101,784 square feet, and 407,150 square feet, respectively.
Explanation:The given scenario represents a real-world application of the mathematical concept involving growth in a circular pattern where the growth happens at a constant rate. Here, the representation of the disease spread through the farm is in form of a circle increasing in radius over time. To calculate the area affected on any given day (t), we apply the formula for the area of a circle (πr^2) where the radius is the rate of spread multiplied by the number of days.
(a) After 2 days, the radius of the spread will be 2*45 = 90 feet. So, the area affected will be π(90)^2 = 25,446 square feet.(b) After 4 days, the radius is 4*45 = 180 feet. Hence, the affected area in this case will be π(180)^2 = 101,784 square feet.(c) After 8 days, the radius is 8*45 = 360 feet. Therefore, the affected area will be π(360)^2 = 407,150 square feet.(d) The general formula relating the disease spread (the affected area) with the time will be: A = π[(45*t)]^2.Learn more about Circular Growth here:https://brainly.com/question/31924921
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Refer to the accompanying TI-83/84 Plus calculator display of a 95% confidence interval. The sample display results from using a simple random sample of the amounts of tar (in milligrams) in cigarettes that are all king size, nonfiltered, nonmenthol, and non-light. Express the confidence interval in the format of x overbarplus or minusE. ZInterval (21.182,23.958) x overbarequals22.57 nequals25 The confidence interval is nothingplus or minus nothing.
Answer:
[22.57 ± 2.776]
Step-by-step explanation:
Hello!
You have the 95% Confidence Z-interval (21.182;23.958), the mean X[bar]= 22.57 and the sample size n=25.
The formula for the Z interval is
[X[bar] ± [tex]Z_{1-\alpha /2} *( \frac{Sigma}{\sqrt{n} } )[/tex]]
The value of Z comes from tha standard normal table:
[tex]Z_{1-\alpha /2} = Z_{0.975}= 1.96[/tex]
The semiamplitude (d) or margin of error (E) of the interval is:
E or d= (Upperbond- Lowerbond)/2 = (23.958-21.182)/2 = 2.776
[X[bar] ± E]
[22.57 ± 2.776]
I hope it helps!
Use inductive reasoning to predict the next line in the pattern. Then perform the arithmetic to determine whether your conjecture is correct. 8(5) = 10(5 - 1) 8(5) + 8(25) = 10(25 - 1) 8(5) + 8(25) + 8(125) = 10(125 - 1) 8(5) + 8(25) + 8(125) + 8(625) = 10(625 - 1)
Answer:
8(5) + 8(25) + 8(125) + 8(625) +8(3125)= 10(3125 - 1)=31240
Hence proved Conjecture is correct
L.H.S=R.H.S
Step-by-step explanation:
Consider the pattern:
8(5)=10(5-1)=40
8(5) + 8(25) = 10(25 - 1) =240
8(5) + 8(25) + 8(125) = 10(125 - 1) =1240
8(5) + 8(25) + 8(125) + 8(625) = 10(625 - 1)=6240
According to inductive reasoning next term of pattern will become:
8(5) + 8(25) + 8(125) + 8(625) +8(3125)= 10(3125 - 1)=31240
Checking whether conjecture is correct or not:
Consider L.H.S:
8(5) + 8(25) + 8(125) + 8(625) +8(3125)
40+200+1000+5000+25000
31240
R.H.S:
31240
Hence proved Conjecture is correct
L.H.S=R.H.S
A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 439.0 gram setting. It is believed that the machine is underfilling the bags. A 47 bag sample had a mean of 433.0 grams. A level of significance of 0.05 will be used. Determine the decision rule. Assume the standard deviation is known to be 21.0. Enter the decision rule.
The decision rule in hypothesis testing is the criteria used to decide whether to accept or reject the null hypothesis. Given our level of significance and sample data, we reject the null hypothesis if the Z score (calculated as -1.92) is less than the critical value (-1.645). Hence, our decision rule is: if Z is less than -1.645, reject the null hypothesis.
Explanation:The decision rule in hypothesis testing is the criteria that determines what the decision should be. In this case, the null hypothesis (H0) is that the mean weight of the chocolate chip bags is 439.0 grams, and the alternative hypothesis (H1) is that the mean weight is less than 439.0 grams because the machine is believed to be underfilling the bags.
Given a level of significance of 0.05 and a standard deviation of 21.0, we can calculate the z-score of the sample mean. Z = (Sample Mean - Population Mean) / (Standard Deviation / sqrt(Sample Size)), thus Z = (433.0 - 439.0) / (21.0 / sqrt(47)) = -1.92.
For a one-tailed test at a 0.05 level of significance, the critical value from the Z table is -1.645. The rule is to reject the null hypothesis if the calculated Z score is less than the critical value.
So the decision rule is: if Z is less than -1.645, reject the null hypothesis. In this case, as -1.92 is less than -1.645, we reject the null hypothesis. Hence, based on the sample, it can be said that the machine is underfilling the bags.
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A statistic refers to:
a fixed unknown number that describes the entire group of interest.
an entire group of interest.
a subset that includes all elements in the group of interest.
a number produced from a subset of the group of interest.
a subset of the entire group of interest.
Answer:
a number produced from a subset of the group of interest.
Step-by-step explanation:
This problems is, basically, about the difference of concepts between a statistic and a parameter.
When something is taken from a sample and estimated to the entire population, it is a statistic. For example, if you survey 200 Central New York residents, an 60% of them say they are Buffalo Bills fans, the 60% is a statistic.
When something is true to the entire population, it is a parameter. If i study the voting preference of all 53 players on the Buffalo Bills active roster, and 83% are Democrats, the 83% is an parameter.
So the correct answer is:
a number produced from a subset of the group of interest.
This subset is the sample, for example, and the group of interest is the population.
Suppose that after computing based on n sample observations , another observation becomes available.
(i) What is the relationship between the mean of the first n observations, the new observation, and the mean of all n+1 observations?
(ii) For the strength observations given below: 22.2 40.4 16.4 73.7 36.6 109.9 30.0 4.4 33.1 66.7 81.5, the mean of the first 10 observations is 43.34. What is the mean of all 11 observations?
Answer:
Mean of the 11th observations = 46.809
Step-by-step explanation:
The step by step explanations is given in the attached file.
What is appled is mean or average which is the total number of observation divided by the sum of the frequencies of each observaton .
find the lateral area for the prism.
L.A. =
Answer:
L.A. = 80 + 16√13
Step-by-step explanation:
the lateral area is the area of the vertical faces.
So, for the given prism = The sum of the area of the vertical rectangles.
= height * perimeter of the right triangle.
The hypotenuse of the right triangle = [tex]\sqrt{6^2+4^2} = \sqrt{36+16} =\sqrt{52} =\sqrt{4*13} =2\sqrt{13}[/tex]
So, the sides of the triangle are 4 , 6 and 2√13
The perimeter of the right triangle = 4 + 6 + 2√13 = 10 + 2√13
Height = 8
The lateral area for the prism = 8 * ( 10 + 2√13 ) = 80 + 16√13
Answer:
The correct answer is 80 + 16√13 feet²
Step-by-step explanation:
Like we can see in the plot, the prism has three rectangular sides, that are its lateral area. For calculating the area, we need to add up the three sides, this way:
Height of the prism (h) = 8 ' or 8 feet
Area of the first side = 8 * 4 = 32 feet²
Area of the third side = 8 * 6 = 48 feet²
Area of the third side = 8 * Hypotenuse of the triangle
Hypotenuse of the triangle² = 4² + 6² = 52
Hypotenuse of the triangle =√52 = √13 * 4 = 2√13 feet
Area of the third side = 8 * 2√13 feet = 16√13 feet²
Area lateral of the prism = 32 + 48 + 16√13 = 80 + 16√13 feet²
(1 point) Let C be the positively oriented square with vertices (0,0)(0,0), (1,0)(1,0), (1,1)(1,1), (0,1)(0,1). Use Green's Theorem to evaluate the line integral ∫C1y2xdx+9x2ydy∫C1y2xdx+9x2ydy.
Answer:
[tex]\displaystyle \oint_C {y^2x \, dx + 9x^2y \, dy} = \boxed{\bold{4}}[/tex]
General Formulas and Concepts:
Calculus
Differentiation
DerivativesDerivative NotationDerivative Property [Multiplied Constant]:
[tex]\displaystyle \bold{(cu)' = cu'}[/tex]
Derivative Rule [Basic Power Rule]:
Integration
IntegralsIntegration Rule [Fundamental Theorem of Calculus 1]:
[tex]\displaystyle \bold{\int\limits^b_a {f(x)} \, dx = F(b) - F(a)}[/tex]
Integration Property [Multiplied Constant]:
[tex]\displaystyle \bold{\int {cf(x)} \, dx = c \int {f(x)} \, dx}[/tex]
Multivariable Calculus
Partial Derivatives
Vector Calculus
Circulation Density:
[tex]\displaystyle \bold{F = M \hat{\i} + N \hat{\j} \rightarrow \frac{\partial N}{\partial x} - \frac{\partial M}{\partial y}}[/tex]
Green's Theorem [Circulation Curl/Tangential Form]:
[tex]\displaystyle \bold{\oint_C {F \cdot T} \, ds = \oint_C {M \, dx + N \, dy} = \iint_R {\bigg( \frac{\partial N}{\partial x} - \frac{\partial M}{\partial y} \bigg)} \, dx \, dy}[/tex]
Step-by-step explanation:
Step 1: Define
Identify given.
[tex]\displaystyle \oint_C {y^2x \, dx + 9x^2y \, dy}[/tex]
[See Graph Attachment] Points (0, 0) → (1, 0) → (1, 1) → (0, 1)
↓
[tex]\displaystyle \text{Region:} \left \{ {{0 \leq x \leq 1} \atop {0 \leq y \leq 1}} \right.[/tex]
Step 2: Integrate Pt. 1
Define vector functions M and N:Step 3: Integrate Pt. 2
We can evaluate the Green's Theorem double integral we found using basic integration techniques listed above:
[tex]\displaystyle \begin{aligned}\oint_C {y^2x \, dx + 9x^2y \, dy} & = \int\limits^1_0 \int\limits^1_0 {16xy} \, dx \, dy \\& = \int\limits^1_0 {8x^2y \bigg| \limits^{x = 1}_{x = 0}} \, dy \\& = \int\limits^1_0 {8y} \, dy \\& = 4y^2 \bigg| \limits^{y = 1}_{y = 0} \\& = \boxed{\bold{4}}\end{aligned}[/tex]
∴ we have evaluated the line integral using Green's Theorem.
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Topic: Multivariable Calculus
Unit: Green's Theorem and Surfaces
Either use technology to find the P-value or use
table to find a range of values for the P-value. The claim is that for the widths (yd) of tornadoes, the mean is μ, < 140 yd. The
sample size is n = 21 and the test statistic is t = -0.024.
Answer:
The first step is calculate the degrees of freedom, on this case:
[tex]df=n-1=21-1=20[/tex]
Since is a one side left tailed test the p value would be:
[tex]p_v =P(t_{(20)}<-0.024)=0.4905[/tex]
And we can use the following excel code to find it: "=T.DIST(-0.024,20,TRUE)"
Step-by-step explanation:
Data given and notation
[tex]\bar X[/tex] represent the mean
[tex]s[/tex] represent the sample standard deviation
[tex]n=21[/tex] sample size
[tex]\mu_o =140[/tex] represent the value that we want to test
[tex]\alpha[/tex] represent the significance level for the hypothesis test.
t=-0.024 would represent the statistic (variable of interest)
[tex]p_v[/tex] represent the p value for the test (variable of interest)
State the null and alternative hypotheses.
We need to conduct a hypothesis in order to check if the mean for the widths of tornadoes is lower than 140 yd, the system of hypothesis would be:
Null hypothesis:[tex]\mu \geq 140[/tex]
Alternative hypothesis:[tex]\mu < 140[/tex]
If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:
[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex] (1)
t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".
Calculate the statistic
The statistic is given by: [tex] t = -0.024[/tex]
P-value
The first step is calculate the degrees of freedom, on this case:
[tex]df=n-1=21-1=20[/tex]
Since is a one side left tailed test the p value would be:
[tex]p_v =P(t_{(20)}<-0.024)=0.4905[/tex]
And we can use the following excel code to find it: "=T.DIST(-0.024,20,TRUE)"
Based on the p value obtained we can conclude that we FAIL to reject the null hypothesis at any significance level selected [tex]\alpah=0.01,0.05,0.1[/tex]
Evaluate each of the following to three significant figures, and express each answer in SI units using an appropriate prefix: (a) [4.86(10 6 )] 2 mm, (b) (348 mm) 3 , (c) (83 700 mN) 2 .
Answer:
a). [tex]4.86\times 10^{-15}[/tex] m
b). [tex]4.21\times 10^{-2}[/tex] m³
c). [tex]7.00\times 10^{3}[/tex] N²
Step-by-step explanation:
In this question we have to convert each option into SI units.
a). [tex]4.86(10^{-6})^{2}[/tex] mm
= [tex]4.86\times (10^{-12})\times (10^{-3} )[/tex] m
= [tex]4.86\times 10^{-15}[/tex] m
b). (348 mm)³
= [tex](348)^{3}\times (10^{-3})^{3}[/tex] m³
= [tex]42144192\times 10^{-9}[/tex] m³
= [tex]4.21\times 10^{-2}[/tex] m³
c). [tex](83700)^{2}\times (10^{-3})^{2}[/tex] N²
= [tex]700569\times 10^{4}\times 10^{-6}[/tex] N²
= [tex]7.00\times 10^{9}\times 10^{-6}N^{2}[/tex]
= [tex]7.00\times 10^{3}[/tex] N²
Bruno listens to podcasts for
two and a half hours a day.
Write an equation where x is
the number of days and y is
the total number of hours.
What is the constant of
proportionality? 25 points brainiest
Answer:the constant of proportionality is 2.5 hours per day.
The equation is y = 2.5x
Step-by-step explanation:
Let x represent the number of days that Bruno listens to podcasts.
Let y represent the total number of hours that Bruno listens to podcasts.
Bruno listens to podcasts for
two and a half hours a day.
Let k represent the constant of proportionality. Therefore,
y = kx
k = y/x
So k = 2.5/1 = 2.5 hours/day
The equation is expressed as
y = 2.5x
Jimmy decides to mow lawns to earn money. The initial cost of his lawnmower is %350. Gasoline and maintenance costs a $6 per lawn. a) Formulate a function C(x) for the total cost of mowing x lawns. b) Jimmy determines that the total-profit function for the lawn mowing business is given by p(x) = 9x - 350. Find a function for the total revenue from mowing x lawns. How much does jimmy charge per lawn? c) How many lawns must jimmy mow before he begins making a profit? a) Formulate a function C(x) for the total cost of mowing x lawns. b) Find a function for the total revenue from mowing x lawns R(x) = How much does Jimmy charge per lawn?
Answer:
Step-by-step explanation:
a) C(x) = 6x+350
b) Function for total revenue, R(x) = 15x & charge per lawn is $15.
c) Jimmy must mow approx 39 lawns before he begins making a profit.
How to formulate a function ?
Consider the initial cost of lawnmower is $350,
Gasoline and maintenance cost are $6 per lawn.
(a) To formulate a function C(x) for the total revenue of mowing x lawn, we use the given values than the function C(x) will be given by
C(x) = 6x+350
How to find the total revenue ?Find the function for the total revenue from moving x lawns.
Recollect: P(x) = R(x)-C(x)
So, R(x) = P(x)+C(x) ..............(1)
Substitute, P(x) = 9x-350 & C(x) = 6x+350 in (1) we get,
R(x) = 9x-350+6x+350
= 15x
So, the total revenue = 15x
∴ Charge per lawn = R(x)/x = 15x/x = $15
How much lawn jimmy needs to mow before make profit ?To find the number of lawn jimmy must mow before begins making a profit, we use P(x) = 0
∴ 9x-350=0
⇒x = 350/9
⇒x ≈ 39
Hence, the solution is x = 39 (approx)
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