(c) The driver of a car traveling at a speed of 17 m/s slams on the brakes and comes to a stop in 3 s. If we assume that the speed changed at a constant rate (constant net force), what was the average speed during this 3 s interval?

Answer:

e = 16.67 km/L

Explanation:

given,

fuel efficiency = 39.2 mi/gal

we need to convert fuel efficiency in Km/l

1 Km = 0.621 mile

1 gal = 3.786 L

now, efficiency

[tex]e = 39.2 \dfrac{mi}{gal}\times \dfrac{1\ km}{0.621\ mile}\times\dfrac{1\ gal}{3.786\ L}[/tex]

e = 16.67 km/L

hence, the efficiency of the car in km/L is equal to 16.67 km/L

Answer:

force of friction

Explanation:

the force of friction in an inclined place is less than that in lever, also a lever works on the principle that it reduces the amount of force required to to work while an inclined plane works by decreasing the amount of force required to do the work.

Answer:

a. its constitution and mixed government.

Explanation:

Polybius tell us about the Roman mixed constitution as a fundamental in the Roman victory and the Carthaginian defeat in the Punic war, conceiving the mixed constitution as the best, since this constitution was at its peak, which implies that among the elements of the constitution, the aristocratic component was the dominant one.

Answer:

0.4rad/s²

Explanation:

Angular acceleration is the time rate of change of angular velocity . In SI units, it is measured in radians per second squared (rad/s²)

w1 = 4rad/s, w2 =2rad/s, t = 5sec, r = 0.30m

a = ∆w/t

a = (w2 - w1)/t

a = (2 - 4)/5 = -2/5 =

a = - 0.4rad/s²

The -ve sign indicates a deceleration in the motion

Good luck

The car's speed at the top of the loop is approximately 0.41 m/s.

At the top of the loop-the-loop, the normal force equals the magnitude of the gravitational force, which means the net force acting on the roller coaster car is zero.

This condition occurs when the car is just about to lose contact with the track due to insufficient normal force.

Using the centripetal force formula, [tex]\( F_{\text{net}} = \frac{mv^2}{r} \)[/tex], where \( m \) is the mass of the car, v is its speed, and \( r \) is the radius of the loop.

At the top of the loop, the net force is zero, so we equate the gravitational force and the centripetal force:

[tex]\[ mg = \frac{mv^2}{r} \][/tex]

Solving for v, we get:

[tex]\[ v = \sqrt{gr} \][/tex]

Substituting the given radius [tex]\( r = \frac{33 \, \text{mm}}{2} = 0.0165 \, \text{m} \)[/tex] and the acceleration due to gravity [tex]\( g = 9.8 \, \text{m/s}^2 \)[/tex], we find:

[tex]\[ v = \sqrt{(9.8 \, \text{m/s}^2)(0.0165 \, \text{m})} \approx 0.41 \, \text{m/s} \][/tex]

Therefore, the car's speed at the top of the loop is approximately 0.41 m/s.

Answer:

The maximum no. of electrons- [tex]2.25\times 10^{22}[/tex]

Solution:

As per the question:

Maximum rate of transfer of charge, I = 1.0 C/s

Time, t = 1.0 h = 3600 s

Rate of transfer of charge is current, I

Also,

[tex]I = \frac{Q}{t}[/tex]

Q = ne

where

n = no. of electrons

Q = charge in coulomb

I = current

Thus

Q = It

Thus the charge flow in 1. 0 h:

[tex]Q = 1.0\times 3600 = 3600\ C[/tex]

Maximum number of electrons, n is given by:

[tex]n = \frac{Q}{e}[/tex]

where

e = charge on an electron = [tex]1.6\times 10^{- 19}\ C[/tex]

Thus

[tex]n = \frac{3600}{1.6\times 10^{- 19}} = 2.25\times 10^{22}[/tex]

To calculate the viscosity of the oil, you need to utilize the concept of shear stress in fluid dynamics. You take the known values of torque, cylinder length, and rotational speed and substitute them into the rearranged shear stress formula. Ensure you convert length from millimeters to meters to maintain SI unit consistency.

The question can be solved using the principles of fluid dynamics, specifically the concept of viscous drag in a medium. In this case, the medium is oil and the object moving through it is a cylinder. The viscosity of the oil can be calculated using the formula for shear stress (τ), given as τ = η (du/dy), where η represents viscosity, du represents the difference in velocity, and dy represents the distance between layers of fluid. As we're given torque (τ) in Newton-metres (Nm), cylinder length (L) in millimeters, and rotational speed in rad/s (radians per second), we can derive η (viscosity) using the rearranged formula: η = τ /(du/dy).

In this case, du is equivalent to the speed of the cylinder let's represent this as 'u', dy is equivalent to the length of the cylinder 'L', hence du/dy becomes u/L. Substitute these values into the rearranged formula and solve to get the viscosity. It's critical to convert the length from millimeters to meters before performing the calculation to maintain consistency in the SI units.

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Answer:

h= 32059.37 m

Explanation:

Assuming the missing in formation as

A certain lead-acid storage battery has a mass of 33 kg . Starting from a fully charged state, it can supply 6 A for 20 hours with a terminal voltage of 24 V before it is totally discharged.

Now, Applying energy conservation ( Electrical to potential)

Electrical Energy E= I×V×t

I = correct , V= voltage , t= time of flow of current

E = 6×24×20×60×60.

E= 10368 KJ

Now this energy is used to lift the battery with 100% efficiency

Hence,

electrical energy E= potential energy P

P= mgh

m=mass of the battery , g= the acceleration due to gravity is 9.8 m/s^2

h= height

mgh = 10368 kJ

33×9.8×h= 10368×1000

h = 10368×1000/(33×9.8)

h= 32059.37 m

Answer:

Force, [tex]F=7.04\times 10^{-5}\ N[/tex]

Explanation:

Given that,

Distance between 1.70 A from the plutonium nucleus, [tex]d=1.7\times 10^{-10}\ m[/tex]

The number of electron in plutonium is 94.

To find,

The magnitude of the force on an electron.

Solution,

Total charge in the plutonium nucleus is, [tex]q=94\times 1.6\times 10^{-19}=1.504\times 10^{-17}\ C[/tex]. The electric force between charges is given by :

[tex]F=\dfrac{kq^2}{d^2}[/tex]

[tex]F=\dfrac{9\times 10^9\times (1.504\times 10^{-17})^2}{(1.7\times 10^{-10})^2}[/tex]

[tex]F=7.04\times 10^{-5}\ N[/tex]

So, the magnitude of the force on an electron is [tex]7.04\times 10^{-5}\ N[/tex]. Hence, this is the required solution.

Answer:

The average diameter of a single alveolus is 0.0222 cm.

Explanation:

Volume of the lung ,V= 1.9 L

[tex]1 L = 1000 cm^3[/tex]

[tex]1.9 L=1.9\times 1000 cm^3=1900 cm^3[/tex]

Number of alveoli in a human lung = [tex]330\times 10^6[/tex]

Volume of single alveoli =v

[tex]v\times 330\times 10^6=V[/tex]

[tex]v=\frac{1900 cm^3}{330\times 10^6}[/tex]

[tex]v=5.7575\times 10^{-6} cm^3[/tex]

The alveoli are spherical.

Radius of an alveolus = r

Volume of the sphere = [tex]\frac{4}{3}\pi r^3[/tex]

[tex]v=\frac{4}{3}\pi r^3[/tex]

[tex]5.7575\times 10^{-6} cm^3=\frac{4}{3}\times 3.14\times r^3[/tex]

[tex]r=0.0111 cm[/tex]

Diameter of the alveolus =d

d = 2r = 2 × 0.0111 cm = 0.0222 cm

The average diameter of a single alveolus is 0.0222 cm.

The question seeks to find the average diameter of a single alveolus in the human lung, using information about the total volume of the lung and the number of alveoli. By using the formula for the volume of a sphere, one can calculate the volume of a single alveolus and derive its radius and thereby its diameter.

The problem is essentially asking to find the average diameter of a single alveolus, given we know the total volume of the lung and the number of alveoli. Using the formula for the volume of a sphere, V=4/3πr³, where V is the volume and r is the radius, we can find the volume of a single alveolus by dividing the total volume of the lungs (1.9 liters, which equals to 1.9 x 10^9 cubic millimeters) by the number of alveoli (approximately 330 million). We can then calculate the radius by rearranging the sphere volume formula to r = ((3*V)/4π)^1/3. The diameter would be double the radius.

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Answer:

  t = 1.099 s

Explanation:

given,

constant speed = 2.51 m/s

height of balloon above ground = 3.16 m

time elapsed before it hit the ground = ?

Applying equation of motion to the compass

[tex]y = u t + \dfrac{1}{2}at^2[/tex]

[tex]-3.16 = 2.51 t + \dfrac{1}{2}\times (-9.8)t^2[/tex]

[tex]4.9 t^2 - 2.51 t - 3.16 = 0[/tex]

using quadratic formula to solve the equation

[tex]t = \dfrac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]

[tex]t = \dfrac{-(-2.51)\pm \sqrt{2.51^2-4(4.9)(-3.16)}}{2\times 4.9}[/tex]

  t = 1.099 s, -0.586 s

hence, the time elapses before the compass hit the ground is equal to 1.099 s.

The extension in the rubber band for the restoring force of 3 newtons is 1.5 cm.

The force according to Hooke's law is given as:

[tex]F=kx[/tex]

Here F is the restoring force, k is the proportionality constant and x is the stretch or compression.

Given:

Restoring force, [tex]F= 2\ N[/tex]

Stretch in the band, [tex]x=1\ cm[/tex]

The value of the k is computed as:

[tex]F=kx\\2=k \times 1cm\\k= 2\ N/cm[/tex]

The stretch in the band for a restoring force of 3 N is computed as:

[tex]F=kx\\x=\frac{F}{k}\\x= \fract{3}{2}\\x = 1.5 cm[/tex]

Therefore, the extension in the rubber band for the restoring force of 3 newtons is 1.5 cm.

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According to Hooke's Law, a force of 3 newtons will stretch the rubber band 1.5 centimeters.

To answer this question, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position. In this case, we are given that when a rubber band is stretched 1 cm beyond its natural length, it exerts a restoring force of 2 newtons. This means that the force constant of the rubber band is 2 newtons per centimeter (N/cm).

To find out how far a force of 3 newtons will stretch the rubber band, we can use the formula for Hooke's Law: F = kx, where F is the force, k is the force constant, and x is the displacement. Rearranging the formula, we have x = F/k. Plugging in the values, we get:

x = 3 N / (2 N/cm) = 1.5 cm

Therefore, a force of 3 newtons will stretch the rubber band 1.5 centimeters.

With negligible air resistance and low speed, the only significant net force on a 0.7 kg ball is gravity, affecting the ball's y component of momentum. The x component remains constant, and z component changes are not discussed without additional forces.

When a ball of mass 0.7 kg flies through the air at low speed with air resistance negligible, the net force acting on the ball while it is in motion is primarily due to gravity, which will be impacting the y component of the ball's momentum. The x component of the ball's momentum remains unchanged because no horizontal force is applied, while the y component changes due to gravity, and the z component would only change if there were forces acting in a direction out of the horizontal plane, which are not mentioned in the scenario. As for the Earth-ball system, momentum is conserved in the vertical direction because the system experiences no net external vertical force.

The total amount of energy per hour is [tex]2.039\cdot 10^{16} kJ[/tex]

Explanation:

In this problem we are told that the amount of energy reaching a square meter in the United States per hour is

[tex]E_1 = 2073 kJ[/tex]

The total surface area of the United States is

[tex]A=9.834\cdot 10^6 km^2[/tex]

And converting into squared metres,

[tex]A=9.834\cdot 10^6 \cdot 10^6 = 9.834\cdot 10^{12} m^2[/tex]

Therefore, the total energy reaching the entire United States per hour is given by:

[tex]E=AE_1 = (9.834\cdot 10^{12})(2073)=2.039\cdot 10^{16} kJ[/tex]

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The potential difference between the terminals of an ordinary AA or AAA battery is usually 1.5 volts. Voltage is the work required to move a charge, while current is the charge flow rate. Batteries can provide considerable energy for their size, analogous to lifting a significant mass against gravity.

The potential difference between the terminals of an ordinary AA or AAA battery is the electromotive force (emf) when the battery is not part of a complete circuit, and is typically about 1.5 volts (V). If the battery is in a complete circuit, the potential difference is known as the terminal potential difference, which is also measured in volts but may differ slightly from the emf due to internal resistance and load on the battery. Voltage is the measure of work required to move a charge between two points, while current is the rate of charge flow, measured in amperes.

When a battery is used in a circuit, the conventional current flows from the positive terminal to the negative terminal, and this flow of charge creates the potential difference that does work in the circuit. An ammeter, which must be connected in series, is used to measure current. The common AA battery not only has a voltage of 1.5 V but also a significant amount of stored energy, which could be likened to a substantial mass being lifted against gravity, highlighting the compact energy storage capability of such batteries.

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Answer:

A. F=107.6nN

B. Repulsive

Explanation:

According to coulombs law, the force between two charges is express as

F=(Kq1q2) /r^2

If the charges are of similar charge the force will be repulsive and if they are dislike charges, force will be attractive.

Note the constant K has a value 9*10^9

Hence for a charge q1=7.10nC=7.10*10^-9, q2=4.42*10^-9 and the distance r=1.62m

If we substitute values we have

F=[(9×10^9) ×(7.10×10^-9) ×(4.42×10^-9)] /(1.62^2)

F=(282.4×10^-9)/2.6244

F=107.6×10^-9N

F=107.6nN

B. Since the charges are both positive, the force is repulsive

The magnitude of the electric force between the two particles is approximately 0.012 N, according to Coulomb's Law. The force could be either attractive or repulsive, depending on whether the charges are the same or opposite, respectively.

The subject of this question is Physics, specifically about Coulomb’s Law, which deals with the electric force between two charges.

(a) According to Coulomb’s Law, the electric force (F) between two charges is directly proportional to the product of their charges (q1 and q2) and inversely proportional to the square of the distance (d) between them. This is mathematically represented as F = k*q1*q2/d^2, where k is Coulomb's constant (8.988 x 10^9 Nm^2/C^2). Substituting in the given values, we find F = (8.988 * 10^9 Nm^2/C^2) * (7.10 * 10^-9 C) * (4.42 * 10^-9 C) / (1.62 m)^2, resulting in an electric force of approximately 0.012 N.

(b) Whether the force is attractive or repulsive depends on the nature of the charges. Same charges repel each other, while opposite charges attract each other. As the charges are not specified, we cannot definitively answer this part of the question.

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Answer:

28343.3 kgm/s

177145.625 N

Explanation:

u = Initial velocity = 19 m/s

v = Final velocity = -3.3 m/s (opposite direction)

m = Mass of car = 1271 kg

t = Time taken = 0.16 s

Impulse is given by

[tex]J=m(v-u)\\\Rightarrow J=1271(-3.3-19)\\\Rightarrow J=-28343.3\ kgm/s[/tex]

The magnitude of the impulse due to the collision is 28343.3 kgm/s

Force given by

[tex]F=\dfrac{J}{t}\\\Rightarrow F=\dfrac{-28343.3}{0.16}\\\Rightarrow F=-177145.625\ N[/tex]

The magnitude of the average force exerted on the automobile is 177145.625 N

Final answer:

The magnitude of the impulse during the collision is 28345.3 kg·m/s, and the magnitude of the average force exerted on the automobile is 177158 N.

Explanation:

In the crash test scenario described, the impulse experienced by the automobile can be determined by using the change in momentum due to the collision. Momentum (p) is the product of mass (m) and velocity (v), and impulse is the change in momentum which can be calculated using the initial (vi) and final velocities (vf) of the car:

Impulse = Change in momentum
= m × (vf - vi)

For the automobile:

Impulse = 1271 kg × (-3.3 m/s - 19 m/s)
= 1271 kg × (-22.3 m/s)
= -28345.3 kg·m/s (to one decimal placing)

The magnitude of the impulse is the absolute value:
28345.3 kg·m/s.

To calculate the average force exerted on the automobile, we use the fact that impulse also equals the average force (Favg) multiplied by the time of impact (t):

Impulse = Favg × t

Thus, the average force can be found by dividing the impulse by the collision time.

Favg = Impulse / t
= 28345.3 kg·m/s / 0.16 s
= 177158.1 N (to one decimal placing)

The magnitude of the average force is the absolute value: 177158 N.

Answer:

It is directed downward. Its relative magnitude is a= qp*E/mp = 0.96*10⁸*E m/s².

Explanation:

Assuming  gravitational force to be negligible, the only force acting on the proton once within the vacuum chamber, is the one due to the electric field.

As the proton is a positive charge, the electric force on it due to the field has the same direction than the field, as the direction of the field by convention, is the one that would take a positive test charge.

According to electric field definition, and to Newton's 2nd Law, we can find the acceleration of the proton as follows:

F = m*a = q*E ⇒ a= q*E / m = 1.6*10⁻¹⁹ C * E (N/C) / 1.67*10⁻²⁷ kg

⇒ a = 0.96* 10⁸ * E m/s²

A proton shot horizontally into a vacuum chamber with a uniform electric field directed downward will experience an upward acceleration.

A proton shot horizontally into a vacuum chamber with a uniform electric field directed downward will experience an acceleration due to the force exerted by the electric field. Since the electric field is directed downward, the proton will experience an upward acceleration.

The magnitude of the proton's acceleration can be calculated using the equation:

a = qE/m

where a is the acceleration, q is the charge of the proton, E is the magnitude of the electric field, and m is the mass of the proton.

The direction of the acceleration will be opposite to the direction of the electric field, which in this case is upward.

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Answer:

(a) [tex]E=2.42eV[/tex]

(b) [tex]E=1.45*10^{-5}eV[/tex]

(c) [tex]E=1.66*10^{-7}eV[/tex]

Explanation:

The Planck-Einstein relation allows us to know the energy (E) of a photon, knowing its frequency (f). According to this relation, the energy of the photon is defined as:

[tex]E=hf[/tex]

Here h is the Planck constant.

(a)

[tex]E=(4.14*10^{-15}eV\cdot s)(585*10^{12}Hz)\\E=2.42eV[/tex]

(b)

[tex]E=(4.14*10^{-15}eV\cdot s)(3.50*10^{9}Hz)\\E=1.45*10^{-5}eV[/tex]

(c)

[tex]E=(4.14*10^{-15}eV\cdot s)(40.0*10^{6}Hz)\\E=1.66*10^{-7}eV[/tex]

Answer:

0.06

Explanation:

The thickness of a human hair is about 60 micrometers. When converted to millimeters, this measures to 0.06 millimeters.

The thickness of a human hair is about 60 micrometers (um). To convert this to millimeters (mm), you need to understand that 1 millimeter is equal to 1000 micrometers. Therefore, you can convert 60 um to mm by dividing 60 by 1000.

This gives an answer of 0.06 mm. So, the thickness of a human hair is 0.06 millimeters.

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Answer:

10.84406 Nm/rad

0.068625 kgm²

2.00066 rad/s

0.49983 s

Explanation:

F = Force = 4.29 N

R = Radius = [tex]\dfrac{30}{2}=15\ cm[/tex]

[tex]\theta[/tex] = Angle = [tex]3.4\ ^{\circ}[/tex]

m = Mass of disk = 6.1 kg

Torsional constant is given by

[tex]J=\dfrac{\tau}{\theta}\\\Rightarrow J=\dfrac{FR}{\theta}\\\Rightarrow J=\dfrac{4.29\times 0.15}{3.4\times \dfrac{\pi}{180}}\\\Rightarrow J=10.84406\ Nm/rad[/tex]

The torsion constant is 10.84406 Nm/rad

Moment of inertia is given by

[tex]I=\dfrac{1}{2}mr^2\\\Rightarrow I=\dfrac{1}{2}6.1\times 0.15^2\\\Rightarrow I=0.068625\ kgm^2[/tex]

The moment of inertia is 0.068625 kgm²

Frequency is given by

[tex]f=\dfrac{1}{2\pi}\sqrt{\dfrac{J}{I}}\\\Rightarrow f=\dfrac{1}{2\pi}\sqrt{\dfrac{10.84406}{0.068625}}\\\Rightarrow f=2.00066\ rad/s[/tex]

The frequency is 2.00066 rad/s

Time period is given by

[tex]T=\dfrac{1}{f}\\\Rightarrow T=\dfrac{1}{2.00066}\\\Rightarrow T=0.49983\ s[/tex]

The time period is 0.49983 s

Answer:

2.24×10⁻⁸ C

Explanation:

From coulomb's law,

F = kq1q2/r² ............................ Equation 1

Where F = Repulsive force between the two charges, q1 = charge on the first sphere, q2 = charge on the second sphere, r = distance between the sphere, k = proportionality constant.

Note: q1 = q2 = q,

Then, we can rewrite equation 1 as,

F = kq²/r²

making q the subject of the equation

q = √(Fr²/k)................................. Equation 2

Given: F = 21 mN = 0.021 N, r = 15 mm = 0.015 m

Constant: k = 9.0×10⁹ Nm²/C²

Substituting these values into equation 2

q = √(0.021×0.015²/9.0×10⁹)

q = √(5×10⁻¹⁶)

q = 2.24×10⁻⁸ C.

Hence the charge on each sphere = 2.24×10⁻⁸ C

The magnitude of the charge on each sphere is [tex]2.29*10^{-8}C[/tex]

The force between two charges is given by coulombs law,

                  [tex]F=k\frac{Q_{1}*Q_{2}}{r^{2} }[/tex]

Where r is distance between charges.

And k is constant,  [tex]k=9*10^{9} Nm^{2}/C^{2}[/tex]

Given that, [tex]Q_{1}=Q_{2},r=15mm=15*10^{-3}m,F=21mN=21*10^{-3}N[/tex]

Substitute above values in above formula.

       [tex]21*10^{-3}=9*10^{9}*\frac{Q^{2} }{(15*10^{-3} )^{2} } \\\\Q^{2}=\frac{21*10^{-3}*225*10^{-6} }{9*10^{9} } \\\\Q^{2}=5.25*10^{-16} \\\\Q=\sqrt{5.25*10^{-16}} =2.29*10^{-8}C[/tex]

Hence, the magnitude of the charge on each sphere is [tex]2.29*10^{-8}C[/tex]

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Answer:

r = 3721.04 m          

Explanation:

Given that,

Weight of human, F = 650 N

Charge on two humans, [tex]q_1=q_2=1\ C[/tex]

We need to find the distance between charges if the electric attraction between them to equal their 650 N weight. It is given by :

[tex]F=\dfrac{kq^2}{r^2}[/tex]

[tex]r=\sqrt{\dfrac{kq^2}{F}}[/tex]

[tex]r=\sqrt{\dfrac{9\times 10^9\times 1^2}{650}}[/tex]

r = 3721.04 m

So, the distance between charges is 3721.04 m if the electric attraction between them to equal their 650 N weight. Hence, this is the required solution.

Answer:

a) No

b) the rock must have a minimum initial speed of 6.79m/s for it to reach the top of the building.

Explanation:

Given:

Height of the wall = 3.95m

Initial height = 1.60m

Initial speed = 5.00m/s

distance between the initial height and wall top = 3.95 - 1.60 = 2.35m

Using the formula;

v^2 = u^2 + 2as ....1

Where v = final velocity, u = initial velocity, a = acceleration, s = distance travelled

From equation 1

s = (v^2 - u^2)/2a ...2

Since the rock t moving up,

the acceleration = -g = -9.8m/s2

s = maximum height travelled

v = 0 (at maximum height velocity is zero)

Substituting into equation 2

s = (0 - 5^2)/(2×-9.8) = 1.28m

Therefore, the maximum height is 1.28 from his initial height Which is less than the 2.35m of the wall from his initial height. So the rock will not reach the top of the wall

b) Using equation 1:

u^2 = v^2 - 2as

v = 0

a = -9.8m/s

s = 2.35m. (distance between the initial height and wall top)

u^2 = 0 - 2(-9.8 × 2.35)

u^2 = 46.06

u = √46.06

u = 6.79m/s

Therefore, the rock must have a minimum initial speed of 6.79m/s

Answer:

The energy is [tex]9.4\times10^{-21}\ J[/tex]

(a) is correct option

Explanation:

Given that,

Energy = 4480 j

Weight of nitrogen = 20 g

Boil temperature = 77 K

Pressure = 1 atm

We need to calculate the internal energy

Using first law of thermodynamics

[tex]Q=\Delta U+W[/tex]

[tex]Q=\Delta U+nRT[/tex]

Put the value into the formula

[tex] 4480=\Delta U+\dfrac{20}{28}\times8.314\times77[/tex]

[tex]\Delta U=4480-\dfrac{20}{28}\times8.314\times77[/tex]

[tex]\Delta U=4022.73\ J[/tex]

We need to calculate the number of molecules in 20 g N₂

Using formula of number of molecules

[tex]N=n\times \text{Avogadro number}[/tex]

Put the value into the formula

[tex]N=\dfrac{20}{28}\times6.02\times10^{23}[/tex]

[tex]N=4.3\times10^{23}[/tex]

We need to calculate the energy

Using formula of energy

[tex]E=\dfrac{\Delta U}{N}[/tex]

Put the value into the formula

[tex]E=\dfrac{4022.73}{4.3\times10^{23}}[/tex]

[tex]E=9.4\times10^{-21}\ J[/tex]

Hence, The energy is [tex]9.4\times10^{-21}\ J[/tex]

The binding energy of a nitrogen molecule in the liquid is calculated using the formula for latent heat and Avogadro's number. Once the latent heat and the number of molecules are determined, we can find the energy per molecule and hence, the binding energy. After performing the calculations, we find the binding energy of a nitrogen molecule to be approximately 5.2 x 10^-21 J.

To calculate the binding energy of a nitrogen molecule in the liquid, we can use the formula for latent heat. This is given by:

Q = mL, where,

Q = Heat energy applied (color change or state change)

m = mass

L = Latent heat

After calculating the latent heat, we can determine the number of moles of nitrogen gas formed and subsequently the number of molecules using Avogadro's number. Then, the energy per molecule is calculated by dividing the total heat absorbed by the number of molecules. Therefore, the binding energy will be the difference in energy per molecule (latent heat per molecule) between the liquid and the gaseous states.

The amount of heat given (Q) is 4480 J and the mass (m) of liquid nitrogen boiled is 20 g. The molar mass (M) of nitrogen (N2) is approximately 28 g/mol. Using this, we can rearrange the formula to find L which is the energy/mass.

Substituting the values, we get L = Q/m = 4480J / 20g = 224 J/g

The number of moles of N2(n) = m/M = 20g / 28 g/mol ~ 0.714 mol

The number of N2 molecules(N) = n x Avogadro's number = 0.714 mol x 6.022 x 10^23 mol^-1 ~ 4.3 x 10^23

Therefore, the binding energy of a nitrogen molecule (E) = L/N = 224J/g / 4.3 x 10^23 = ~5.2 x 10^-21 J.

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Answer:

The flea will move high to a height of 0.05 meters.

Explanation:

Given that,

Acceleration of the flea, [tex]a=1000\ m/s^2[/tex]

Distance, d = 0.5 mm = 0.0005 m

Let u and v are the initial and final velocity of the flea. Using equation of motion as :

[tex]v^2-u^2=2ad[/tex]

[tex]v^2-u^2=2\times 1000\times 0.0005[/tex]

[tex]v^2-u^2=1[/tex]..........(1)

Using conservation of energy, we get :

[tex]\dfrac{1}{2}mu^2=\dfrac{1}{2}mv^2+mgh[/tex]

[tex]\dfrac{1}{2}u^2=\dfrac{1}{2}v^2+(-g)h[/tex]

[tex]\dfrac{1}{2}u^2=\dfrac{1}{2}v^2-gh[/tex]

[tex]\dfrac{1}{2g}(u^2-v^2)=-h[/tex]

[tex]h=\dfrac{1}{2g}[/tex]

[tex]h=\dfrac{1}{2\times 9.8}[/tex]

h = 0.05 meters

So, the flea will move high to a height of 0.05 meters. Hence, this is the required solution.

The electric field is defined as the electric force per unit of charge. The direction of the field is taken as the direction of the force it would exert on a positive test load. An electric field is always directed from its positive charge to the negative. Under this condition if the terrestrial electric field is pointing towards the ground, the terminal that is pointing is the negative and that of its surface is the positive. This implies that the sign of the charge of the electric field of the soil will be negative.

Answer:

The answer is zero. The total change in momentum is equal to the sum of the areas within the time interview 0-4s. The area under the graph is Force x time (F being the breadth and time the length)

The sun of the areas is zero.

Explanation:

See the attachment below for the full solution.

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Final answer:

Statement (c) is incorrect because if one object is negatively charged and the other is positively charged, they would attract each other, resulting in a negative potential energy as they come closer, not a positive one.

Explanation:

The question is addressing the concept of electric potential energy between two charged objects. When the electric potential energy of the system is positive as the two objects come close, we can infer that the objects have like charges, either both positive or both negative. This is due to the fact that work needs to be done against the electrical repulsion to bring like charges together, increasing the system's potential energy.

This makes statements (a) Both objects are positively charged and (b) Both objects are negatively charged possibly correct scenarios, as they would lead to a positive potential energy when the objects are brought together. Statement (c) One object is negatively charged and the other one is positively charged would be incorrect in this context, because a positive and a negative charge would attract each other, and the system would do work on the surroundings as they come closer to each other making the potential energy negative. Therefore, the incorrect statement, given that the electric potential energy is positive when they are near each other, is (c).

Answer:

ratio of tangential velocity of satellite b and a will be 0.707

Explanation:

We have given distance of satellite B from satellite A is twice

So [tex]r_b=2r_a[/tex]

Tangential speed of the satellite is given by

[tex]v=\sqrt{\frac{GM}{r}}[/tex], G is gravitational constant. M is mass of satellite and r is distance from the earth

We have to find the ratio of tangential velocities of b and a

From the relation we can see that tangential velocity is inversely proportional to square root of distance from earth

So [tex]\frac{v_b}{v_a}=\sqrt{\frac{r_a}{r_b}}[/tex]

[tex]\frac{v_b}{v_a}=\sqrt{\frac{r_a}{2r_a}}[/tex]

[tex]\frac{v_b}{v_a}=\sqrt{\frac{1}{2}}[/tex]

[tex]\frac{v_b}{v_a}=0.707[/tex]

So ratio of tangential velocity of satellite b and a will be 0.707

The ratio of tangential velocity of satellite B to satellite A is 0.707.

The Tangential velocity is the linear speed of any object moving along a circular path. The tangential speed of the satellite is given below.

[tex]v = \sqrt{\dfrac{Gm}{r}}[/tex]

Where v is the velocity, m is the mass and r is the circular distance. G is the gravitational constant.

Given that mass of both the satellite is the same. Let us consider the mass of both satellites as m. The distance of satellite B from Earth’s center is twice that of satellite A.

Let us consider that the distance of satellite A from the center of the earth is r. The distance of satellite B from the center of the earth is 2r.

The tangential speed of satellite A is,

[tex]v_a = \sqrt{\dfrac {Gm}{r}}[/tex]

The tangential speed of satellite B is,

[tex]v_b = \sqrt{\dfrac {Gm}{2r}}[/tex]

In the ratio form, the tangential speed of both satellites is given below.

[tex]\dfrac {v_b}{v_a} = \dfrac {\sqrt{\dfrac {GM}{2r}} }{\sqrt{\dfrac {Gm}{r}} }[/tex]

[tex]\dfrac {v_b}{v_a} = \sqrt{\dfrac{1}{2}}[/tex]

[tex]\dfrac {v_b}{v_a} = 0.707[/tex]

Hence we can conclude that the ratio of tangential velocity of satellite B to satellite A is 0.707.

To know more about the tangential speed of satellites, follow the link given below.

https://brainly.com/question/21322214.