A light-year is the distance light travels in one year, at a speed = 2.998 x 10^8 m/s.

(a) How many meters are there in 1.00 light years?
(b) An AU is the average distance from the Sun to the Earth, 1.50 x 10^8 How many AU are there in 1.00 light-year?
(c) What is the speed of light in AU/h? ...?

Answers

Answer 1
Final answer:

A light-year, being the distance light travels in a year, is about 9.461 x 10^15 meters. 1.00 light-years equals 63,240 astronomical units (AU). And the speed of light is around 7.214 AU/hr.

Explanation:

In astronomy, a light-year and an astronomical unit (AU) are common units of measurement.

(a) A light-year is defined as the distance that light can travel in a year. The speed of light = 2.998 x 10^8 m/s and a year has approximately 3.1536 x 10^7 seconds. Therefore, to get the distance, we multiply the speed of light by the number of seconds in a year which equals 9.461 x 10^15 meters. (b) An AU is defined as the average distance from the Sun to the Earth, about 1.50 x 10^8 meters. To convert light years to AU, we divide the distance of one light year in meters by the distance of one AU in meters, which gives about 63,240 AU in 1.00 light-year. (c) To calculate the speed of light in AU/h, we assume the value of one AU as 1 and then calculate the speed of light in distance covered per hour. Since light travels at about 63,240 AU in one year, a year has approximately 8760 hours so we get approximately 7.214 AU/h.

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Answer 2
Final answer:

One light-year equals approximately 9.461 x 10^15 meters. There are about 63,000 AUs in one light-year. The speed of light is roughly 7.2 AU/h.

Explanation:

A light-year is the distance light travels in one year. To find out how many meters there are in 1.00 light-year:

The speed of light, c, is 2.998 x 10^8 meters per second (m/s).There are 60 seconds in a minute, 60 minutes in an hour, 24 hours in a day, and approximately 365.25 days in a year. So, one year has 60 x 60 x 24 x 365.25 = 31,557,600 seconds.Multiplying the speed of light by the number of seconds in a year gives the distance for one light-year in meters: 2.998 x 10^8 m/s x 31,557,600 s/year ≈ 9.461 x 10^15 meters.

To calculate how many Astronomical Units (AU) are there in 1.00 light-year:

1 AU is the average distance from the Sun to the Earth, which is about 1.50 x 10^11 meters.To find out how many AUs are in one light-year, you divide the number of meters in one light-year by the number of meters in one AU: 9.461 x 10^15 meters / 1.50 x 10^11 meters/AU ≈ 63,000 AU.

To find the speed of light in AU/h:

First, convert the speed of light to km/s, which is about 3 x 10^5 km/s.Since 1 AU is equal to 1.50 x 10^8 km, the speed of light in AU/s is 3 x 10^5 km/s / 1.50 x 10^8 km/AU = 2 x 10^-3 AU/s.There are 3600 seconds in an hour, so the speed of light in AU/h is 2 x 10^-3 AU/s x 3600 s/h = 7.2 AU/h.

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Related Questions

An airplane heads northeast at an airspeed of 700 km/hr, but there is a wind blowing from the west at 60 km/hr. In what direction does the plane end up flying? What is its speed relative to the ground?

Answers

Final answer:

The plane ends up flying northeast. To find its speed relative to the ground, use vector addition to calculate the resultant velocity as 694 km/hr.

Explanation:

Direction: The plane ends up flying northeast.

Speed Relative to the Ground: To find the speed relative to the ground, we need to calculate the resultant velocity. The plane's velocity relative to the air is northeast at an angle, while the wind blows from the west. Using vector addition, we determine the speed relative to the ground to be 694 km/hr.

Vector Addition: Vector addition is essential to determine the resultant velocity of the plane with respect to the ground, taking into account both the airspeed and the wind speed.


What are some indicators that a chemical reaction is occurring? Check all that apply.



the formation of bubbles


a change in size


a change in color


the formation of a liquid


the formation of a precipitate

Answers

The formation of bubbles, a change in color, and the formation of a precipitate (1, 3, & 5) are all indicators that a chemical reaction is occurring.

Indicators that a chemical reaction is occurring -

the formation of bubblesa change in colorthe formation of a precipitate

Chemical reactions involve the chemical interaction of two or more chemical substances, resulting in a new substance being formed, and are usually irreversible.

The signs of chemical reactions include gas formation, energy release in the form of light or flame, heat absorption, precipitate formation, and color change.

Gas bubbles appear after a chemical reaction has occurred and the mixture becomes saturated with gas.A solid, known as a precipitate, that forms after two solutions are mixed is also a sign of a chemical change. Each chemical compound has a characteristic color. When the compound changes during a chemical reaction, the color may change as well.

Thus, Indicators that a chemical reaction is occurring -

the formation of bubblesa change in colorthe formation of a precipitate

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A cyclist maintains a constant velocity of
4 m/s headed away from point A. At some
initial time, the cyclist is 253m from point A.
What will be his displacement from his
starting position after 64 s?
Answer in units of m

What will be his position from point A after
that time?
Answer in units of m

Answers

The answer is 509 m.

Let point B be 253 m from point A. Let point C be 64 s away from point B.
Let d1 be the displacements from point A to point B and d2 and be the displacements from point B to point C
Step 1. Calculate the displacement from the point B after 64 s.
Step 2. Calculate the displacement from the point A by summing up two distances (d1 and d2).

Step 1.
v = d2/t
v = 4 m/s
d2 = ?
t = 64s
____
4 = d2/64
d2 = 64 * 4 = 256 m


Step 2:
d = d1 + d2
d1 = 253 m
d2 = 256 m
d = 253 + 256 = 509m

Final answer:

The cyclist's displacement from the starting position after 64 seconds is 256 meters. Their position from point A after that time is 509 meters.

Explanation:

If a cyclist maintains a constant velocity of 4 m/s headed away from point A, their displacement after any given time can be calculated using the formula Δx = vt, where Δx is the displacement, v is the velocity, and t is the time. For a time of 64 seconds, the displacement would be Δx = (4 m/s) × (64 s) = 256 meters.

Since the cyclist starts 253 meters away from point A, the new position (total distance from point A) after 64 seconds can be found by adding the initial distance to the displacement. This gives us a total distance = 253 m + 256 m = 509 meters from point A.

The velocity v of the flow of blood at a distance "r" from the central axis of an artery of radius "R" is: v = k(R^2^ - r^2^) where k is the constant of proportionality. Find the average rate of flow of blood along a radius of the artery. (use 0 and R as the limits of integration) ...?

Answers

As the  The average rate of flow is given by 
(1/(R - 0)) * ∫(r = 0 to R) k(R^2 − r^2) dr 
So what we do is that we proceed like this:
= (k/R) * ∫(r = 0 to R) (R^2 − r^2) dr 
= (k/R) * (R^2 r − r^3/3) {for r = 0 to R} 
= (k/R) * (R^2 * R − R^3/3) - 0 
= (k/R) * (2R^3/3) 
= (2k/3) R^2. 
I hope this can help you for good

Final answer:

The average rate of flow of blood along the radius of an artery is found by integrating the velocity equation v = k(R² - r²) from 0 to R, which results in an average velocity formula of (2/3)kR after integration and simplification.

Explanation:

The question asks to find the average rate of flow of blood along a radius of the artery using the given velocity equation v = k(R² - r²) and integrating between the limits 0 and R. To find the average velocity, we integrate the given equation across the artery's radius and then divide by the radius R to calculate the average.

The integration process involves calculating the integral of k(R² - r²) with respect to r, over the interval from 0 to R, which gives us kR²r - (kr³)/3 evaluated between 0 and R. Substituting the limits and simplifying, the result is (2/3)kR². To find the average velocity, we divide this by R, resulting in an average velocity of (2/3)kR.

What is the speed of a wave with a wavelength of 3 m and a frequency of .1Hz?

Answers

We know,
Speed = Frequency * Wavelength 
Speed = 3 * 0.1 m/s   [hertz = 1/sec.]
So, your final answer is 0.3 m/s

Hope this helps!!

The correct answer to the question is 0.3 m/s i.e the speed of the wave is 0.3 m/s.

CALCULATION:

As per the question, the wavelength of the wave is given as [tex]\lambda=\ 3\ m.[/tex]

The frequency of the wave f = 0.1 Hz.

We are asked to calculate the speed [ V ] of the wave .

The relation among speed, frequency and wavelength of a  wave is given as -

                            speed = frequency × wavelength

                           ⇒ V =  f × [tex]\lambda[/tex]

                                   = 3m × 0.1 Hz

                                   = 0.3 m/s.                        [ans]

Hence, the speed of the wave will be 0.3 m/s.

Julie drives 100 mi to Grandmother's house. On the way to Grandmother's, Julie drives half the distance at 33.0 and half the distance at 80.0 . On her return trip, she drives half the time at 33.0 and half the time at 80.0 . What is Julie's average speed on the way to Grandmother's house? What is her average speed on the return trip? ...?

Answers

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Average Speed = Total distance/ Total Time 
total distance is 100mi 
total time is (50mi / 33) + (50mi / 80) 
total time is = 1.52 + 0.625 = 2.145 
so average speed going to grandmothers house is 100mi / 2.145 hrs = 46.62 mph 

on her return trip 
x = V1 x t/2 + V2x t/2 
100 = 33t/2 + 80t/2 
100 = 113t/2 
t = 100x2/113 = 1.7699hrs 
average speed = 100mi/1.7699hrs = 56.60mph

Which of the following is distance divided by the change in time?


displacement

acceleration

speed


velocity

Answers

Answer:

the correct answer is speed, velocity scored incorrectly on my quiz

Explanation:

Which of the following best illustrates the role that gravity played in the formation of our solar system?
A. Gravity allowed the nebula to expand and move outward.
B. Gravity caused the nebula to cool enough for planets to form.
C. Gravity removed excess gas and dust from the cores of the planets.
D. Gravity pulled particles of dust and gas together to form planets.

Answers

D. Gravity forced dust and gas together to form the planets and our earth

Answer:

Option D

Explanation:

Gravity is a force of attraction by virtue of mass of a body. It is an attractive force. It is due to gravity that the planets and hence, the solar system was formed. Starting from the nebula, the gravity caused the nebula to contract and form start. From rest of the material, the dust and gas were pulled in together due to gravity to form planet. The gravity of the Sun holds the planets in their respective orbits.

Thus, option D is correct.

what is Initial temperature and final temperature equations??
...?

Answers

One that can help you is:
ΔT=TFinal−TInitial
That is of course adding both tmepratures. There is one more that is a lil bit more complex 
Tf=Ti−ΔHrxn∗nrxn/(Cp,water∗mwater)
This one is taking into account that yu can find temperature and that there could be a change with a chemical reaction. Hope this helps

Which of the following describes how an atom becomes negatively charged?
A. electrons are gained when free floating electrons attach to the atom
B. protons are gained when free floating electrons attach to the atom
C. electrons are transferred to the atom from other atoms through direct contact
D. protons are transferred from other atoms through direct contact ...?

Answers

An atom becomes negatively charged when electrons are transferred to the atom from other atoms through direct contact. For example, when rubbing wool on paper, the wool becomes negatively charged.

Answer:

C. electrons are transferred to the atom from other atoms through direct contact

Explanation:

When an atom is negatively charged then it means that the number of electrons in the atom is in excess in number as compare it to the number of protons

This is possible when an atom will transfer its electron to other atom. Here the transfer of electrons will produce negative or positive charge because electrons are loosely bounded while protons are strongly bounded inside the nucleus.

So here correct answer is given as

C. electrons are transferred to the atom from other atoms through direct contact

A 60.0- kg dancer leaps 0.32 m high. With what momentum does he reach the ground

Answers

151 

answer below 

cheers 

The momentum of the dancer is equal to 151 Kg.m/s.

What is momentum?

The momentum of a body can be defined as the function of the mass of the body and its velocity. Momentum (p) can be determined as the kinetic energy of the body and is the multiplication of velocity (v) and mass (m).

The mathematical equation to calculate the momentum of the body is equal to:

p = m×v

The momentum can be described as the conserved quantity and will be zero if the velocity of an object is equal to zero.

Given, the mass of the dancer, m = 60 Kg

The height from the ground, h = 0.32 m

The initial velocity of the dancer, u = 0

v² - u² = 2gh

v² - 0 = 2 × 9.8 ×0.32

v² = 6.272

v = 2.53 m/s

The momentum of the dancer does he reach the ground:

p = 60 × 2.53

p = 151 Kg.m/s

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The radius of a cylinder is 5" and the lateral area is 70 PI sq. in. Find the length of the altitude.

? inches ...?

Answers

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

Lateral Area = AL = 70*π 

Perimeter of Circle = PC = 2*π*R (R = Radius) 

Length of Altitude = L = AL / PC = 70*π / 2*π*R = 7 inches

A 3858 N piano is to be pushed up a(n) 3.49 m frictionless plank that makes an angle of 31.6 ◦ with the horizontal. Calculate the work done in sliding the piano up the plank at a slow constant rate. Answer in units of J.

Answers

the work done will be equal to the potential energy of the piano at the final position

P.E=m.g.h

.consider the plank the hypotenuse of the right triangle formed with the ground
.let x be the angle with the ground=31.6°
.h be the side opposite to the angle x (h is the final height of the piano)
.let L be the length of the plank

sinx=opposite side / hypotenuse
= h/L

then h=L.sinx=3.49×sin31.6°=0.638m

weight w=m.g
m=w/g=3858/10=385.8kg

Consider Gravity g=10m/s2

then P.E.=m.g.h=385.8kg×10×0.638=2461.404J

then Work W=P.E.=2451.404J

Answer:

7055.13 J

Explanation:

Step 1: identify the given parameters

Applied force on the piano = 3858NLength of plank = 3.49mangle between the plank and horizontal surface = 31.6⁰

Note: frictional force between the piano and horizontal surface is zero since the plank is frictionless.

Step 2: work done in sliding the piano up the plank = applied force X distance moved by the piano.

The distance moved by the piano is equal to the height above ground when the piano reach top of the plank.

make a sketch of right angle trianglelength of the plank is the hypotenuse sideangle between the hypotenuse and the horizontal is 31.6⁰height of the triangle is the height above ground , let it be the unknown  

Height of the triangle = 3.49m X sine31.6⁰

Height of the triangle = 1.8287m

Recall, height of the triangle is the height above ground which is equal to the distance moved by the piano

work done in sliding the piano up the plank = applied force X distance moved by the piano.

work done in sliding the piano up the plank = 3858N X 1.8287M

                                                                           = 7055.13 J

Suppose all of the apples have a mass of 0.10 kg and one of the apples in the bowl (C) is 1.0 meter off the ground. If the apple (C) falls from the table, what is the maximum kinetic energy it can gain?

Answers

The answer is 0.981 J

E = m · g · h
E - energy
m - mass
g - gravitational acceleration
h - height

We know:
E = ?
m = 0.10 kg
g = 9.81 m/s²
h = 1 m

E = 0.10 kg * 9.81 m/s² * 1 m = 0.981 J

Because cosmologists can't go out into space and test all of their theories, they must depend on the cosmological principle. This principle assumes that _____.
the universe stays at a steady state
any physical laws are the same for the entire universe
the universe is going to eventually collapse
the universe is cooling down

Answers

This principle assumes that any physical laws are the same for the entire universe.

It can also be said that physical laws are the same for everybody at any place in universe.

B.) Any physical laws are the same for the entire universe.

A push or pull that gives energy to an ob-
ject, causing that object to start moving, stop
moving, or change its motion is
1. friction.
2. pressure.
3. inertia.
4. a force. ...?

Answers

The answer is a force
The best and most correct answer among the choices provided by your question is the fourth choice or letter D.

A force is a push or pull that gives energy to an object, causing that object to start moving, stop moving, or change its motion.

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Audio frequency range of a human ear is 20Hz - 20000 Hz. Express the range in terms of time period ? Answer needed urgently. Pl. help. Thanks ! S.Ramya ...?

Answers

Using the term c in this case is a little confusing. It is more generic to use a general velocity, v. That way, in this case, we know to use the speed of sound. 

wavelength*frequency=v 

wavelength_20Hz = (345 m/s)/(1/20s) 

wavelength_20kHz = (345 m/s)/(1/20000s)


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Where do plants get energy to live and grow?

Answers

from the sun, i think thats what it is. 

Answer:

Sun light and water

Which of the following best defines mass?
A. The amount of matter in a substance.
B. The amount of water that a substance displaces.
C. The way a sample of matter fills a container.
D. How much space a sample of matter takes up.
Which of the following best defines mass?
A. The amount of matter in a substance.
B. The amount of water that a substance displaces.
C. The way a sample of matter fills a container.
D. How much space a sample of matter takes up.

Answers

Answer:

option (A)

Explanation:

The amount of matter contained in the matter is called its mass.

Mass is a scalar quantity and it always remains constant.

The SI unit of mass is kg.

Hat is required for a rocket to lift off into space?
a. thrust that is greater than earth���s gravity
b. mass that is greater than earth���s
c. very little air resistance
d. more velocity than friction

Answers

Most likely answer is A

A rocket needs thrust greater than Earth's gravity to lift off into space, overcoming air resistance and gravitational pull. Hence, option a is the correct condition for achieving lift-off.

For a rocket to lift off into space, it requires a thrust that is greater than the Earth's gravity. This thrust is provided by the acceleration of the rocket as it ejects high-speed gas through its exhaust nozzles. The opposing forces, such as air resistance and gravitational pull, need to be overcome by this thrust for the rocket to ascend. In the ideal case, without air resistance and neglecting gravity, we could focus solely on the thrust force. However, in reality, rockets must achieve a final velocity great enough to break free from Earth's gravitational influence, which involves reducing the rocket's mass apart from fuel, and producing enough thrust to counteract both gravity and atmospheric drag.

In summary, option a, thrust that is greater than Earth's gravity, is the required condition for a rocket to lift off. Although air resistance and friction are factors that influence the efficiency of the rocket's ascent, achieving a thrust greater than Earth's gravitational pull is the primary necessity.

A car starts from xi = 12m at ti = 0 and moves with the velocity graph shown in figure below. What is the objects position and t=3s and t=4s? Picture in comments below

Answers

Final answer:

To find the position of the car at t = 3 s and t = 4 s, we need to find the area under the velocity graph up to those time points.

Explanation:

The position of an object at a given time can be determined from the velocity graph. To find the object's position at t = 3 s and t = 4 s, we need to find the area under the velocity graph up to those time points. In the figure, we can see that the displacement at t = 3 s is approximately 5 m and the displacement at t = 4 s is approximately 8 m.

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What two organelles should be labeled that WOULD NOT be found in an animal cell?

Answers

chloroplasts and vacuoles 

how does the volume occupied by a cubic centimeter compare with the volume occupied by a millimeter

Answers

One cubic centimeter and one milliliter are equal volumes.

a particle moves along a straight line OX. at a time t(in seconds) the distance X(in metres) from the particle O is given by x=40+12t-t3. how long would the particle travel before coming to rest ...?

Answers

You should consider when the velocity is zero

first i would take the derivative of the equation motion, leaving you with :
x = 12 - 3t^2

next, set the velocity to zero and solve t, which will give you 
√4 = t = +/- 2

Hope this helps

Answer:

16m

Explanation:

Elements used to make semiconductors for computers include germanium and

Answers

Elements used to make semiconductors for computers include germanium and "Silicon"

They mixed, when we need to make semi-conductors by the process of "Doping"

Hope this helps!

according to newton's first law of motion what is required to make an object slow down

Answers

Final answer:

According to Newton's first law of motion, an object at rest will remain at rest and an object in motion will continue moving at a constant velocity unless acted upon by an external force. To make an object slow down, an external force in the opposite direction of its motion, such as friction, is required.

Explanation:

According to Newton's first law of motion, an object will continue moving at a constant velocity unless acted upon by an external force. To make an object slow down, an external force in the opposite direction of its motion is required. This force is called friction. Friction can be caused by various factors, such as air resistance or contact with a surface.

Learn more about Newton's first law of motion

___________ charges a neutral body by touching it with a charged body.

Answers

the correct answer would be cells

The process that charges a neutral body by touching it with a charged body is known as charging by contact.

Charging by contact is the process where a charged body touches a neutral body, transferring charge to it, unlike charging by induction which involves no direct touch.

This method requires the charged object, such as a positively charged glass rod, to physically touch the neutral object, transferring charge directly.

For instance, when a positively charged rod touches an electroscope, electrons move to neutralize the positive charges, resulting in the electroscope itself gaining a positive charge. Unlike charging by induction, where a charged object is brought near a neutral object without direct contact causing a redistribution of charges within the neutral object, charging by contact involves direct touch.

A steel wire of diameter 1 mm can support a tension of 0.24 kn. suppose you need a cable made of these wires to support a tension of 24 kn. the cable should have diameter of what order of magnitude?

Answers

Final answer:

To support a tension of 24 kN, a cable made from steel wires that originally have a diameter of 1 mm should have a new diameter of 10 mm, which is one order of magnitude larger.

Explanation:

If a steel wire of diameter 1 mm can support a tension of 0.24 kN, to support a tension of 24 kN, we need to determine the required diameter of a cable made of these wires. The tension supported by a wire is directly proportional to the cross-sectional area, which is proportional to the square of the diameter. Therefore, if the tension increases by a factor of 100 (from 0.24 kN to 24 kN), the diameter must increase by a factor of the square root of 100, which is 10.

Hence, the new diameter would be 10 mm, which is a one order of magnitude increase from the original diameter of 1 mm.

Find a vector w with the same direction of u but twice as long as v. u = {0 4 2} v = {2 1 0}.

Answers

Find magnitude of v and then double itFind unit vector of u Multiply the above two

Let's do it step by step:

Magnitude of v and then double itmagnitude||v||=√2^2+1^2+0^2=√5 double it become  =2√5
Find unit vector of u magnitude||u||=√0^2+4^2+2^2=2√5 
so  unit.vector={0,2/√5,1/√5}

Multiply the above two:

when u multiply u get ( 0, 4/5, 2/5)



Final answer:

To find a vector w with the same direction of u but twice as long as v, we can use unit vectors. The magnitude of u is √20 and the magnitude of v is √5. The unit vector parallel to u is (0, 2/√5, 1/√5) and the unit vector parallel to v is (2/√5, 1/√5, 0). Multiplying the unit vector parallel to u by 2 times the magnitude of v gives us the vector w = (4/√5, 2/√5, 0).

Explanation:

To find a vector w with the same direction as u but twice as long as v (u = {0 4 2} v = {2 1 0}), we can use the concept of unit vectors. First, let's calculate the magnitudes of vectors u and v. The magnitude of u is √(0^2 + 4^2 + 2^2) = √20. The magnitude of v is √(2^2 + 1^2 + 0^2) = √5.

To find a unit vector parallel to u and v, we divide each vector by its magnitude. The unit vector parallel to u is (0/√20, 4/√20, 2/√20) = (0, 2/√5, 1/√5). The unit vector parallel to v is (2/√5, 1/√5, 0).

To find a vector w with the same direction as u but twice as long as v, we can multiply the unit vector parallel to u by 2 times the magnitude of v. w = 2(2/√5, 1/√5, 0) = (4/√5, 2/√5, 0).

Weatherstripping prevents heat loss by
a. lessening evaporation.
b. reducing convection and conduction.
c. preventing condensation.
d. increasing radiation. ...?

Answers

Answer: Weatherstripping can refer to either the process or the agent that is used to seal small openings around windows, doors, trunk lids and other areas where a tight seal is desired. Essentially weatherstripping is designed to eliminate a flow or draft from an interior space to an exterior space. Because of this property, weatherstripping is often added to window sashes and doors in order to allow for more efficient heating and cooling of the interior space.

So “B” Is the answer of your question.

Explanation:Weatherstripping can take on several different forms. When it comes to dealing with drafts originating from a small open space between the bottom of a door and the floor, the addition of a small rubber strip along the threshold will often be sufficient to seal the area. The weather stripping will effectively block the airflow between inside and outside, while still allowing the door to be opened and closed with ease. Weatherstripping doors may be accomplished when the door is hung, or added at a later time as the house settles.

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Other Questions
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