Answer:
It will have a certain kinetic energy at the beginning, but it will be lost by resistant work done by friction. Thus, itsmotion wil be uniformly decelerating.
Explanation:
1.
A poorly tuned Yugo can accelerate from rest to a speed of 28 m/s in
20 s.
a) What is the average acceleration of the car?
b) What distance does it travel in this time?
Explanation:
Average acceleration is defined as the rate of change of velocity to the rate of change of period. Change of velocity refers to the difference between final velocity and initial velocity. The unit of acceleration is meter/sec/sec (or) m s^2.
Avg Acceleration=(Final velocity - Initial velocity) /(Final time - Initial time)
a. To find the average acceleration of the car, (initial velocity and initial time is 0, the final velocity is 28 m/s, final time = 20 s)
Avg acceleration of the car = (28 - 0) / (20 - 0)
= 28 / 20 = 1.4 m / s^2.
b. The distance traveled is given by the product of speed and time
Distance traveled = Speed * Time
The Distance traveled by the car = 28 * 20 = 560 m.
By applying basic physics formulas, the car's average acceleration can be determined as 1.4 m/s², and the distance it travels in 20 seconds is 280 meters.
Explanation:To answer this question, you'll need to apply basic physics formulas. Let's go step by step:
a) What is the average acceleration of the car?
Acceleration is defined as the rate of change of velocity per unit of time. The formula is Acceleration = (Final speed - Initial speed) / Time. Here, the initial speed is 0 (because the car is starting from rest), final speed is 28 m/s and time is 20 s.
So, Acceleration = (28 m/s - 0) / 20 s = 1.4 m/s². That's your answer for part a.
b) What distance does it travel in this time?
The distance traveled by the car can be found using the formula of linear motion: Distance = Initial speed x Time + 0.5 x Acceleration x Time². Since the car starts from rest, the initial speed is zero, and this component of the formula will be zero.
So, Distance = 0 + 0.5 x 1.4 m/s² x (20 s)² = 280 m. So, the car travels 280 meters in that time.
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A car accelerates uniformly from rest and reaches a speed of 33.5 m/s in 11.9 s. The diameter of a tire is 37.5 cm.
Find the number of revolutions the tire makes during this motion, assuming no slip- ping.
The number of revolutions the tire makes during this motion is 169.265 revolution.
Explanation:
Given:
Car’s initial velocity, u = 0
Car’s final velocity, v = 33.5 m/s
Time required t = 11.9 s
Hence, car’s acceleration ‘a’ can be given by the first equation of motion as
[tex]v=u+(a \times t)[/tex]
[tex]33.5=0+(a \times 11.9)[/tex]
[tex]11.9 \times a=33.5[/tex]
[tex]a=\frac{33.5}{11.9}=2.815 \mathrm{m} / \mathrm{s}^{2}[/tex]
The distance covered by the car during this time is given by the second equation of motion
[tex]s=(u \times t)+\left(\frac{1}{2} \times a \times t^{2}\right)[/tex]
[tex]s=0+\left(0.5 \times 2.815 \times 11.9^{2}\right)[/tex]
[tex]s=0.5 \times 2.815 \times 141.61=199.31 m[/tex]
Now as in each revolution a wheel rolling without slipping covers a distance equal to its periphery ([tex]2 \pi R[/tex]), if the total numbers of revolution of each tire be n, then we have
[tex]s=n \times 2 \pi R[/tex]
Given diameter, d = 37.5 cm = 0.375 m
Radius of the wheel, R = [tex]\frac{d}{2}=\frac{0.375}{2}=0.1875 \mathrm{m}[/tex]
Total numbers of revolution,
[tex]n=\frac{s}{2 \pi R}=\frac{199.31}{2 \times 3.14 \times 0.1875}=\frac{199.31}{1.1775}=169.265 \text { revolution }[/tex]
The car's tires make approximately 917 revolutions during the motion.
Explanation:To find the number of revolutions the tire makes during this motion, we need to first find the distance the car travels. We can use the formula s =[tex]ut + 1/2at^2[/tex]the distance, u is the initial velocity, a is the acceleration, and t is the time. In this case, the initial velocity is 0 m/s, the acceleration is the same as the car's acceleration, and the time is 11.9 s. Plugging in these values, we get:
s = 0(11.9) + 1[tex]/2(33.5)(11.9)^2[/tex]
The distance traveled is equal to the circumference of the tire multiplied by the number of revolutions. The circumference of the tire is equal to π times the diameter. Plugging in the values, we get:
2π(0.375) = 2.35619 m
Let's assume the number of revolutions is N. Therefore, the distance traveled can also be calculated as N times the circumference. Setting up the equation, we have:
N(2.35619) = 2156.29
Solving for N, we get:
N = 2156.29 / 2.35619 = 916.67
Therefore, the tire makes approximately 917 revolutions during this motion.
6.
What is the speed of a rocket that travels 9000 meters in 12.12 seconds?
Answer:
742.57 m/s
Explanation:
Given:
Distance travels by a rocket = 9000 metres
Time taken by rocket = 12.12 seconds
Questioned asked:
Speed of rocket = ?
Solution:
By applying formula, speed = distance traveled divided by time taken
[tex]speed = \frac{distance}{time} \\ = \frac{9000}{12.12} \\ = 742.57m/s[/tex]
Therefore, the speed of a rocket that travels 9000 meters in 12.12 seconds is 742.57 meters per seconds.
The landform pictured above has been growing taller from one year to the next. The picture shows
A.
a sand dune that has been formed by erosion
B.
a sand dune that has been formed by deposition.
C. a mountain that has been formed by crustal uplift.
D.
a mountain that has been formed by plate folding.
Answer:
a sand dune that has been formed by deposition.
Explanation:
The landform pictured above has been growing taller from one year to the next year. The picture shows a sand dune that has been formed by deposition. Thus, the correct option is B.
What are Sand dunes?When the desert winds blow in a particular direction, they carry a lot of sand all around with them. When the wind stops blowing, this sand falls on the land and gets deposited. These deposits look like the little hills or mounds, which are called as the sand dunes.
Sand dunes are usually temporary structures as the next gust of wind can shift them to another place from the actual location where they formed.
Sand dunes are mostly associated with deserts, can be found in the region of deserts.
Therefore, the correct option is B.
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Find the statement about Fusion that is false. Group of answer choices
A) Fusion releases less energy than fission.
B) Fusion is extremely difficult to contain and maintain here on earth.
C) Fusion occurs when low mass nuclei, such as hydrogen collide and combine to form nuclei with greater masses.
D) fusion most commonly combines heavy isotopes of hydrogen into helium.
E) Fusion could be the world's answer to clean unlimited amounts of energy.
A) Fusion releases less energy than fission.
Explanation:
Nuclear fusion is a process in which nuclei of light elements combine together into heavier elements; in the process, the mass of the final nucleus is less than the total mass of the initial nuclei, therefore energy is released during the reaction.
Nuclear fusion is able to liberate a huge amount of energy, according to the famous Einstein's equation:
[tex]E=mc^2[/tex]
where
E is the energy released
m is the mass converted into energy in the process
c is the speed of light
Let's now analyze the statements given:
A) Fusion releases less energy than fission. --> FALSE. In fact, fusion releases much more energy than fission.
B) Fusion is extremely difficult to contain and maintain here on earth. --> TRUE. In order for fusion to occur, the initial nuclei must overcome the electrostatic repulsion between them in order to come very close to each other, within the range of action of the strong force; for this to happen, the temperature and the pressure must be enormous, and this makes fusion difficult to occur on Earth.
C) Fusion occurs when low mass nuclei, such as hydrogen collide and combine to form nuclei with greater masses. --> TRUE
D) fusion most commonly combines heavy isotopes of hydrogen into helium. --> TRUE, this is the most common reaction that occurs within the core of the stars
E) Fusion could be the world's answer to clean unlimited amounts of energy. --> TRUE: energy from fusion is a clean source of energy (there is no radioactive waste) and virtually unlimited, since it can be produced starting from hydrogen.
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You are at an office party, a holiday party, or a gathering of friends at the home of a neighbor and you are engaged in conversation with a friend in a discussion. More people are talking behind you, but you are not paying attention to their conversation. Suddenly, you hear your name mentioned by one of the individuals engaged in the conversation behind you. You become unable to concentrate on the discussion, because you are too busy trying to hear what the other people are saying about you. You know you were not deliberately eavesdropping on this conversation, but you know that you heard your name. Is it possible that you were unconsciously eavesdropping?
The correct answer is; Yes, you can be unconsciously eavesdropping.
Further Explanation:
When this occurs it is called the “The Cocktail Party Phenomenon.” Your mind can focus on one conversation that is being made and drown out all other speech and things going on around you. This makes your brain have auditory attention on one specific conversation.
The sensory hearing in the person listening to the conversation is subconsciously filtering the conversation into its own stream in the brain. This phenomenon can also detect certain words that are important to the person with a large amount of noise in the background.
This occurs in the left hemisphere of the brain in the superior temporal gyrus region.
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Final answer:
The experience you described is related to the cocktail party effect, a part of selective attention that allows us to focus on a conversation even in a noisy environment, while still unconsciously monitoring other auditory channels, including hearing one's own name.
Explanation:
Cocktail Party Phenomenon and Selective Attention
The situation you described typically relates to the cocktail party effect, which is a well-documented phenomenon in psychology. This effect explains how people can focus on a specific conversation in a noisy environment yet still notice when something salient, like their name, is mentioned elsewhere. It's a part of selective attention, allowing us to concentrate on a single source of input while still unconsciously monitoring other channels. The information overload at events such as parties necessitates this filtering mechanism, where our brains process background conversations without our active awareness. When your name is mentioned, it becomes a significant stimulus that captures your attention, indicating that some unconscious eavesdropping may occur as a byproduct of this natural cognitive process.
As mentioned by Broadbent (1958) and Cherry (1953), selective attention is not a complete exclusion of all background noise; it's a delicate balance that allows for focus while still keeping us connected to our surroundings. This phenomenon shows that even when you're engaged in conversation, you're unconsciously monitoring the environment around you, including the speech of others. Your brain is attending to more than you might realize, as it sifts through various sensory inputs to alert you to anything important—like the mention of your name.
021 (part 1 of 2) 10.0 points
A student sits on a rotating stool holding two
4 kg objects. When his arms are extended
horizontally, the objects are 0.7 m from the
axis of rotation, and he rotates with angular
speed of 0.69 rad/sec. The moment of iner-
tia of the student plus the stool is 4 kg mº
and is assumed to be constant. The student
then pulls the objects horizontally to a radius
0.29 m from the rotation axis.
(D.
T
TZ
Calculate the final angular speed of the
student.
Answer in units of rad/s.
022 (part 2 of 2) 10.0 points
Calculate the change in kinetic energy of the
system.
Answer in units of J.
The problem involves using the principles of conservation of angular momentum and kinetic energy to find the student's final angular speed and the change in kinetic energy of the system when the radius at which weights are held is changed.
Explanation:The problem involves calculating the final angular speed of a student who pulls two objects closer while rotating on a stool and then determining the change in kinetic energy of the system. Using the principle of conservation of angular momentum, we can solve for the student's final angular speed after changing the radius at which the objects are held. The kinetic energy change relies on calculating the initial and final kinetic energies and finding their difference.
Without the complete calculations for this scenario, a precise final angular speed and kinetic energy change cannot be provided here. Typically, you would use the formula for angular momentum (L = Iω) where I is the moment of inertia and ω is the angular speed, and the formula for kinetic energy (KE = 0.5 * I * ω²) to solve these problems.
A 3.50 kg block of lead at 14.4°C comes in contact with a block of copper at 88.4°C. They come to equilibrium at 55.9°C. What was the mass of the copper block? (Unit=kg)
Answer:
1.48 kg
Explanation:
The conservation of energy states that energy cannot be created or destroyed but can be converted from one form to another. Hence, in this case, energy lost by the copper should equal to the energy gained by the lead. Hence,
Energy Lost by Copper = Energy Gained by Lead
mcT = mcT (Bolded is for copper, italicised is for lead)
m(387)(88.4 - 55.9) = (3.50)(128)(55.9 - 14.4)
12577.5m = 18592
m = 1.48 kg (3 sf)
(Note: Thermal energy can be calculated using Q = mcT where m is the mass, c is the specific heat capacity and T is the change in temperature)
Answer:
1.48 kg
Explanation:
How much time does it take Mrs. Spencer to travel 240meters at a speed of 80meters per second?
Answer:
3seconds
Explanation:
it will take 3 seconds
The inside surface of the glass inside a vacuum bottle is coated with aluminum to prevent heat loss by ____.
Answer:
radiation
Explanation:
What type of mixture is salad dressing?
Answer:
Heterogeneous Mixture
Explanation:
Heterogeneous by definition is when two different substance are mixed together, but they are not evenly distributed. In this case, the salad dressing is a Heterogeneous Mixture, for the dressing does not mix completely evenly throughout the salad.
~
A clay ball with a mass of 0.50 kg is traveling at 5.7 m/s to the right and hits another clay ball that has a mass of 0.50 kg which is at rest. The two clay balls stick together and move as one. What is the velocity of the two balls?
Answer:
2.9 m/s to the right
Explanation:
Momentum before = momentum after
m₁ u₁ + m₂ u₂ = (m₁ + m₂) v
(0.50 kg) (5.7 m/s) + (0.50 kg) (0 m/s) = (0.50 kg + 0.50 kg) v
v = 2.85 m/s
Rounded to two significant figures, the velocity is 2.9 m/s to the right.
An advantage of parallel circuits is that A. it is the simplest type of circuit to make. B. electrons can only take one path, so the flow of energy is always known. C. if one part of the circuit is not working, the other parts can still work. D. when one part of the circuit breaks, the whole circuit must be replaced.
Answer:
The answer is c
Explanation:
1) Differences between Magnetic Induction and Demagnetization
2) A freely suspended bar magnet always shows north-south direction. Why?
3) A magnet has stronger force of attraction at the poles than in the middle. Why?
Please guys answer those questions in less than 24 hours.
I really need this answer.
1)
Magnetic Induction is the process by which an object is magnetized by an external magnetic field.
Demagnetization is the process of removing magnetism from an object.
Explanation:
Magnetism is the property of a material to exert a notice magnetic force on anything that is electrically or magnetically charged. Ferromagnetic substances like iron can be magnetized permanently by putting them in an external magnetic field. These materials retain their magnetic properties up to a certain temperature, called the Curie point.
Demagnetization is the process of decreasing the magnetic properties of ferromagnetic materials by heating it past the Curie point, applying a strong magnetic field, applying alternating current, or hammering the metal. Demagnetization occurs naturally over time.
Keywords: magnetism, magnetic induction, demagnetization, Curie point, ferromagnetic.
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2)
A freely suspended magnet always show north-south direction because Earth also shows magnetism.
Explanation:
Earth's magnetic field is similar to that of a bar magnet so it also have two poles; the south pole and the north pole. So when a bar magnet is freely suspended, it arranges itself in such a way that its north pole points towards the south pole of Earth and its south pole points towards the north pole of Earth. Because opposite poles attracts each other.
The south pole of earth's magnet is in geographical north because it attracts the north pole of suspended magnet . Similarly , the north pole of earth's magnet is in geographical south because it attracts the south pole of the suspended magnet . Hence, the suspended bar magnet shows north-south direction.
Keywords: north pole, south pole, magnet, Earth, bar magnet.
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3)
A magnet has stronger force of attraction at the poles than in the middle because the magnetic field lines of a bar magnet are closer at the poles while they almost vanish in the middle comparatively.
Explanation:
Magnetic field lines are used to represent the magnetic field around a magnet. Magnetic field lines are continuous, forming closed loops without beginning or end. They go from the north pole to the south pole. The direction of the magnetic force is tangent to the magnetic field line at that point.
The strength of the magnetic force is directly proportional to the density of the magnetic field lines. Hence, the magnetic force is stronger near the poles and weakens in the middle.
Keywords: magnetic field lines, poles, magnetic force.
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What is the reason why feather falls at a slower rate than a Hammer on Earth not on the moon
If you wanted to be an auto mechanic for Toyota, where would you go to school to get that training? How much would you make your first year?
A picture hanging on a wall has what energy.
In a hydraulic system, why is the force exerted on a small piston multiplied when it acts on a larger piston?
The force multiplies because of Pascal's law .
Explanation:
Pascal's law states that " when there is an increase in pressure at any point in a confined fluid, there is an equal increase at every other point in the container". So, in a hydraulic system where it is a confined fluid system, where the dimensions of two sides are very different, due to it there is an increased amount of force.
Find the acceleration of a car that can go from rest to 50 km/h in 13 s
The acceleration of the car is 1.067 m/[tex]s^{2}[/tex].
Explanation:
Acceleration is the measure of change in velocity experienced by any object for a given time period. So it is determined as the ratio of difference in the velocity to the time period.
As here the initial velocity is stated as zero, so u = 0. And the final velocity is termed as 50 km/h. Then we have to determine the acceleration in 13 s. So here we have to convert the units as common units. Thus, 50 km/h should be converted to m/s as [tex]\frac{50*1000}{3600}=13.88 m/s[/tex]
So now, the initial velocity u = 0 and final velocity v = 13.88 m/s and the time period is given as t = 13 s.
[tex]Acceleration = \frac{v-u}{t}=\frac{13.88-0}{13}=1.067 m/s^{2}[/tex]
So the acceleration of the car is 1.067 m/[tex]s^{2}[/tex].
A line on a speed-time graph with a steep slope indicates a greater speed
False: a line on a speed-time graph with a steep slope indicates a greater acceleration
Explanation:
In a speed-time graph, we have:
The time represented on the x-axisThe speed represented on the y-axisThis means that the slope of this graph is
[tex]m=\frac{\Delta y}{\Delta x}=\frac{\Delta v}{\Delta t}[/tex]
where
[tex]\Delta v[/tex] is the change in speed
[tex]\Delta t[/tex] is the change in time
However, acceleration is defined as
[tex]a=\frac{\Delta v}{\Delta t}[/tex]
where [tex]\Delta v[/tex] is the change in velocity. If we consider a motion in a straight line, the change in velocity corresponds to the change in speed: therefore, the slope of a speed-time graph corresponds (for a straight line motion) to the acceleration.
Therefore, the steeper the slope, the greater the acceleration of the body.
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A uniform brick of length 18 m is placed
over the edge of a horizontal surface with a
maximum overhang of 9 m attained without
tipping.
K18 m
Now two identical uniform bricks of length
18 m are stacked over the edge of a horizontal
surface.
K18 m
What maximum overhang is possible for
the two bricks (without tipping)?
Answer in units of m.
Answer:
13.5
Explanation:
x= Length
.5 = Center Point
x=0.5(9)= 4.5
So total length over the edge will be given as
Length (L) =9+4.5=13.5
The maximum overhang for two uniform bricks of length 18 m each, when stacked, is 13.5 m. This is determined by considering the center of mass and static equilibrium of the bricks.
Explanation:The question involves the concept of static equilibrium and center of mass in the field of physics. When two uniform bricks of length 18 m are stacked and placed such that they overhang the edge of a surface, the maximum overhang is achieved when the center of mass of the system is still supported by the surface. To find the maximum overhang for two bricks, we can apply the principle of moments. For two stacked bricks, the bottom brick can overhang by half its length, namely 9 m. The top brick can be shifted further out but must keep its center of mass over the bottom brick. The maximal overhang of the second brick is therefore half of what remains from the first brick, which is ½ × 9 m = 4.5 m. Hence, the maximum overhang for the top brick is 4.5 m beyond the end of the bottom brick, which itself overhangs by 9 m. Consequently, the total maximum overhang for two stacked bricks is 13.5 m.
50200 J of heat are removed from
a block of ice, causing its
temperature to drop by 8.00°C.
What is the mass of the ice?
(Unit = kg)
Correct Answer:
3.1375
Explanation:
Use equation [tex]Q=mc[/tex]Δ[tex]T[/tex] to find [tex]m[/tex]
Plug in all variables [tex]-50200=x\cdot 2000\cdot -8[/tex]
Answer: 3.1375
Final answer:
The mass of the ice block is approximately 3.01 kg, calculated using the relation Q = mcΔT with the values given and the specific heat capacity of ice.
Explanation:
To determine the mass of the ice based on the heat removed and the temperature change, we can use the following relation from thermodynamics:
Q = mcΔT
Where:
Q is the heat energy transferred (in Joules)m is the mass of the substance (in kilograms)c is the specific heat capacity (in J/kg°C)ΔT is the change in temperature (in °C)For ice, the specific heat capacity (c) is approximately 2.09 J/g°C or 2090 J/kg°C. Plugging in the values, we have:
50,200 J = m × 2090 J/kg°C × 8°C
Solving for m:
m = 50,200 J / (2090 J/kg°C × 8°C) = ≈ 3.01 kg
Therefore, the mass of the block of ice is approximately 3.01 kg.
A 5 kg book rests on a table. How much force is it exerting on the table?
(Hint: think about acceleration due to gravity.)
Answer:
49N
Explanation:
Basically, think of this problem as asking how much the book weighs, as that is all weight is, how much force you exert on whatever surface you're on.
Thus, the force due to gravity Fgrav = mg = 5 * 9.8m/s^2 = 49N.
The force will be "49 N". A complete solution is provided below.
According to the question,
Mass of books,
m = 5 kg
We know the value,
g = 9.8 m/s⁻¹
Now,
The force exerting on the table, will be:
→ [tex]F = mg[/tex]
By substituting the given values in the above formula, we get
→ [tex]=5\times 9.8[/tex]
→ [tex]=49 \ N[/tex]
Thus the above answer is correct.
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Which kind of intelligence involves is the ability to hear pitch, tone, and rhythm?
Answer:
musical intelligence
Explanation:
What is the IMA of a lever whose resistance arm is 7cm long if the effort arm is 0.7m long and the load is 8.5N?
The IMA of the lever is 10
Explanation:
The IMA (Ideal Mechanical Advantage) of a simple machine is given by:
[tex]IMA=\frac{d_e}{d_r}[/tex]
where
[tex]d_r[/tex] is the length of the resistance arm
[tex]d_e[/tex] is the length of the effort arm
For the lever in this problem, we have:
[tex]d_r = 7 cm = 0.07 m[/tex] is the length of the resistance arm
[tex]d_e = 0.7 m[/tex] is the length of the effort arm
Substituting into the equation, we find the IMA of the lever:
[tex]IMA=\frac{0.7}{0.07}=10[/tex]
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Use the drop-down menus to complete the statements.
The amount of energy a wave carries corresponds to its
is equal to the number of wavelengths that pass a fixed point in a second.
Frequency is typically expressed in
Answer:
1st blank - amplitude
2nd blank - frequency
3rd blank - hertz
The amount of energy a wave carries corresponds to its amplitude. Frequency is equal to the number of wavelengths that pass a fixed point in a second. Frequency is typically expressed in hertz
Find the current passing through a circuit consisting of a battery and one resistor. The resistance has a retance of 2ohms and the battery hasa voltage of 12 volts
The current passing through a circuit consisting of a battery of 12 V and resistor of 2 ohms is 6 Ampere .
Explanation:
Assume the wires are ideal with zero resistance. The current passing through the circuit will beI = V/R = 12/2 = 6.000 A.
The charged parts of the atom are the
Answer:
Proton and electron
Explanation:
An atom can be broken down into three constituents parts – protons, neutron, and electrons. Each of these parts has an associated charge, with protons carrying a positive charge, electrons having a negative charge, and neutrons possessing no net charge
A football player kicks a 0.94 kg football with a force of 2.4 N.
Calculate the acceleration of the football as the player kicks the ball. Round your answer to the nearest tenth of a m/s2.
The acceleration of the football is
m/s2.
Answer:
The Answer is 2.6m/s(m/s)
Explanation:
Just took the test!
Answer:
2.6 m/s2............................
A 60-kilogram high jumper lands on a mat after her jump. The mat brings her to a stop after 1 second. She
was traveling at 5.0 m/sec when she landed on the mat. Note: The speed of the jumper at the top of her jump.
before she started to fall toward the mat, was 0 m/sec.
a. What is the change in momentum for the jumper?
b. What is the force felt by the jumper upon impact with the mat?
a) Change in momentum: -300 kg m/s
b) Force felt by the jumper: -300 N
Explanation:
a)
The change in momentum of an object is given by
[tex]\Delta p = m(v-u)[/tex]
where
m is the mass of the object
v is the final velocity
u is the initial velocity
For the jumper in this problem, we have
m = 60 kg (mass of the jumper)
v = 0 (final velocity is zero)
u = 5.0 m/s (initial velocity before he hits the mat)
Substituting,
[tex]\Delta p = (60)(0-5.0)=-300 kg m/s[/tex]
Where the negative sign means that the direction of the change in momentum is opposite to the direction of motion.
b)
According to the impulse theorem, the change in momentum of an object is equal to the impulse exerted on it:
[tex]\Delta p = F\Delta t[/tex]
where
F is the force exerted on the object
[tex]\Delta t[/tex] is the time interval
In this problem, we have
[tex]\Delta p = -300 kg m/s[/tex] (change in momentum)
[tex]\Delta t = 1 s[/tex] (duration of the collision)
Solving for F,
[tex]F=\frac{\Delta p}{\Delta t}=\frac{-300}{1}=-300 N[/tex]
Where the negative sign means that the direction of the force is opposite to the direction of motion.
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