Based on its degree, what kind of polynomial is this? h(x)=-x^2+2x-5

The standard notation 0.0002 cm becomes 2 × 10^-4 and 0.02 cm becomes 2 × 10^-2, both in scientific notation.

The standard notation for 0.0002 centimeters is 2 × 10^-4 in scientific notation. Meanwhile, the standard notation for 0.02 centimeters is 2 × 10^-2 in scientific notation.

You arrive at these translations by recognizing that the number 0.0002 means you've moved the decimal point four units to the right from 2 (thus raising 10, the base, to -4), and 0.02 represents moving the decimal point two units to the right from 2 (thus raising 10 to the -2).

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Answer:

C. < 1,6 > (x)

Step-by-step explanation:

We know that,

Translation is the transformation that shifts the image in any direction.

The general form of horizontal translation of f(x) to f(x±k) and vertical translation of f(x) to f(x)±k where k is any constant.

Now, as the given function 'X' is translated 1 unit to the left i.e. translated horizontally by 1 unit i.e. X+1.

Also, the function is translated 6 units up i.e. translated vertically by 6 units i.e. X+6.

Hence, the solution is < 1,6 >(x).

Answer:

The explicit formula of the geometric sequence is:

                   [tex]a_n=4\times 5^{n-1}[/tex]

Step-by-step explanation:

The explicit formula is the expression where the nth term is given in terms of the first term of the sequence.

We know that the explicit formula for a geometric sequence is given by:

       [tex]a_n=(a_1)^{r-1}[/tex]

Here we are given:

The second and fifth terms as: 20 and 2500 respectively.

i.e.

[tex]a_2=20[/tex] and  [tex]a_5=2500[/tex]

i.e.

[tex]ar=20\ and\ ar^4=2500[/tex]

Hence,

[tex]\dfrac{ar}{ar^4}=\dfrac{20}{2500}\\\\\\\dfrac{1}{r^3}=\dfrac{1}{125}\\\\\\(\dfrac{1}{r})^3=(\dfrac{1}{5})^3\\\\\\\dfrac{1}{r}=\dfrac{1}{5}\\\\\\r=5[/tex]

Also,

we have:

[tex]ar=20\\\\i.e.\\\\a\times 5=20\\\\i.e.\ a=4[/tex]

Hence, the explicit formula is given by:

         [tex]a_n=4\times 5^{n-1}[/tex]

Part A

months = m

 since birds decrease by 7%, there will be 93% left. 93% = 0.93
birds: 975 x 0.93^m
trees: 350 - 7m

Part B
birds: 975 x 0.93^12 = 408
trees: 350-7(12) = 266

Part C

350 - 7m = 0.93^m(975)

We have intersection points at approximately 22.21 and 44.4781. round off to whole numbers, we have 22 and 44 months.

sqrt(32) = 5.66

 so it is in section B

Answer:

section B.

YOUR WELCOME

Answer:

u didn't provide a chart but the dependent variable is the y axis, or the vertical line

Step-by-step explanation:

It's always the y axis (the vertical line)

I believe the problem ask for s which is the standard deviation. We must recall that the formula for z statistic is stated as:

z = (x – x over bar) / s

Where,

z = z statistic = 2.5

x = sample value or sample score = 102

x over bar = the sample mean or sample average  = 100

s = standard deviation = unknown

Rewriting the equation in terms of s:

s = (x – x over bar) / z

Substituting the given values into the equation:

s = (102 – 100) / 2.5

s = 0.8  

Therefore the standard deviation s is 0.8

Answer: The correct answer is "Test scores will increase because the graph shows a negative association."

Step-by-step explanation: Negative association is decreasing and positive is increasing but in this case we flip it to get our answer.

The impact of time spent surfing the internet on students' test scores depends on whether the association represented on the scatter plot is positive or negative. In a positive association, scores increase with increased internet time, while in a negative association, scores decrease.

Based on the question, it seems there is a relationship between the time spent surfing the Internet and students' test scores which is represented by a scatter plot. The association between these variables can be either positive, negative, or no association. A positive association means as the hours of surfing the internet increase, the test scores also increase. A negative association implies that as the hours of surfing the internet increase, the test scores decrease.

However, the question didn't provide the information about whether the scatter plot shows a positive or a negative association between these two variables, which is crucial to determine what happens to the test scores as internet surfing time increases.

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After setting up a system of equations based on the given age relationships and solving for both Grace and Joseph, we deduce that Grace is 20 years old and Joseph is 40 years old currently.

Let's denote Grace's current age as G and Joseph's current age as J. According to the problem, Grace is half of Joseph's age, so we have the first equation:

G = 0.5 * J

In 10 years, Grace will be three-fifths of Joseph's age, giving us the second equation:

G + 10 = (3/5) * (J + 10)

Ten years ago, Grace was one-third of Joseph's age, which gives us the third equation:

G - 10 = (1/3) * (J - 10)

We now have a system of three equations with two variables. We can solve this system to find the current ages of Grace and Joseph. After solving for G and J, we find that Grace is 20 years old and Joseph is 40 years old.

The correct option is a. 625.

The total number of outcomes in 4 spins of the spinner can be found by multiplying the number of outcomes in one spin by itself 4 times, resulting in 625 outcomes.

The sample space for 4 spins of the spinner can be calculated by raising the number of outcomes in one spin to the power of the number of spins.

In this case, as there are 5 outcomes on the spinner, the total number of outcomes in 4 spins would be 5^4 = 625.

Therefore, the correct option is a. 625.

Segment AB has slope 0. Segment DE, with midpoints of AC and BC, also has slope 0. Thus, DE is parallel to AB.

To prove that segment DE is parallel to segment AB, we need to show that the slopes of both segments are equal.

The slope of segment AB, denoted as [tex]\( m_{AB} \)[/tex], can be calculated using the coordinates of points A and B:

[tex]\[ m_{AB} = \frac{{y_B - y_A}}{{x_B - x_A}} \][/tex]

Given that point A is at (0, 0) and point B is at [tex]\((x_2, 0)\)[/tex], the slope [tex]\( m_{AB} \)[/tex] is:

[tex]\[ m_{AB} = \frac{{0 - 0}}{{x_2 - 0}} = 0 \][/tex]

Now, let's find the coordinates of points D and E.

Point D lies on segment AC, so it is at the midpoint of segment AC. Therefore, the coordinates of point D, denoted as [tex]\((x_{D}, y_{D})\)[/tex], are the average of the coordinates of points A and C:

[tex]\[ x_{D} = \frac{{x_1 + 0}}{2} = \frac{{x_1}}{2} \][/tex]

[tex]\[ y_{D} = \frac{{y_1 + 0}}{2} = \frac{{y_1}}{2} \][/tex]

Similarly, point E lies on segment BC, so it is at the midpoint of segment BC. Therefore, the coordinates of point E, denoted as [tex]\((x_{E}, y_{E})\)[/tex], are the average of the coordinates of points B and C:

[tex]\[ x_{E} = \frac{{x_1 + x_2}}{2} \][/tex]

[tex]\[ y_{E} = \frac{{y_1 + 0}}{2} = \frac{{y_1}}{2} \][/tex]

Now, let's calculate the slope of segment DE, denoted as [tex]\( m_{DE} \)[/tex]:

[tex]\[ m_{DE} = \frac{{y_{E} - y_{D}}}{{x_{E} - x_{D}}} \][/tex]

Substituting the coordinates of points D and E:

[tex]\[ m_{DE} = \frac{{\frac{{y_1}}{2} - \frac{{y_1}}{2}}}{{\frac{{x_1 + x_2}}{2} - \frac{{x_1}}{2}}} \][/tex]

[tex]\[ m_{DE} = \frac{0}{{\frac{{x_1 + x_2 - x_1}}{2}}} \][/tex]

[tex]\[ m_{DE} = 0 \][/tex]

Since the slopes of segments AB and DE are both equal to 0, we can conclude that segment DE is parallel to segment AB.

The probability of independent events Q and R both occurring is calculated by multiplying the individual probabilities of each event. Thus in this case, P(Q and R) = (1/8) * (2/5) = 1/20.

The question posed asks for the probability of events Q and R both occurring. Given that Q and R are independent events, the likelihood of both happening is calculated by multiplying the probabilities of each event.

That is, P(Q and R) = P(Q)P(R). From the question, we know that P(Q) is 1/8 and P(R) is 2/5.

Therefore, the probability of both Q and R occurring would be (1/8) * (2/5) = 1/20.

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