(a) On the coil: 20 V, on the resistor: 0 V
The sum of the potential difference across the coil and the potential difference across the resistor is equal to the voltage provided by the battery, V = 20 V:
[tex]V = V_R + V_L[/tex]
The potential difference across the inductance is given by
[tex]V_L(t) = V e^{-\frac{t}{\tau}}[/tex] (1)
where
[tex]\tau = \frac{L}{R}=\frac{0.005 H}{6.00 \Omega}=8.33\cdot 10^{-4} s[/tex] is the time constant of the circuit
At time t=0,
[tex]V_L(0) = V e^0 = V = 20 V[/tex]
So, all the potential difference is across the coil, therefore the potential difference across the resistor will be zero:
[tex]V_R = V-V_L = 20 V-20 V=0[/tex]
(b) On the coil: 0 V, on the resistor: 20 V
Here we are analyzing the situation several seconds later, which means that we are analyzing the situation for
[tex]t >> \tau[/tex]
Since [tex]\tau[/tex] is at the order of less than milliseconds.
Using eq.(1), we see that for [tex]t >> \tau[/tex], the exponential becomes zero, and therefore the potential difference across the coil is zero:
[tex]V_L = 0[/tex]
Therefore, the potential difference across the resistor will be
[tex]V_R = V-V_L = 20 V- 0 = 20 V[/tex]
(c) Yes
The two voltages will be equal when:
[tex]V_L = V_R [/tex] (2)
Reminding also that the sum of the two voltages must be equal to the voltage of the battery:
[tex]V=V_L +V_R[/tex]
And rewriting this equation,
[tex]V_R = V-V_L[/tex]
Substituting into (2) we find
[tex]V_L = V-V_L\\2V_L = V\\V_L=\frac{V}{2}=10 V[/tex]
So, the two voltages will be equal when they are both equal to 10 V.
(d) at [tex]t=5.77\cdot 10^{-4}s[/tex]
We said that the two voltages will be equal when
[tex]V_L=\frac{V}{2}[/tex]
Using eq.(1), and this last equation, this means
[tex]V e^{-\frac{t}{\tau}} = \frac{V}{2}[/tex]
And solving the equation for t, we find the time t at which the two voltages are equal:
[tex]e^{-\frac{t}{\tau}}=\frac{1}{2}\\-\frac{t}{\tau}=ln(1/2)\\t=-\tau ln(0.5)=-(8.33\cdot 10^{-4} s)ln(0.5)=5.77\cdot 10^{-4}s[/tex]
(e-a) -19.2 V on the coil, 19.2 V on the resistor
Here we have that the current in the circuit is
[tex]I_0 = 3.20 A[/tex]
The problem says this current is stable: this means that we are in a situation in which [tex]t>>\tau[/tex], so the coil has no longer influence on the circuit, which is operating as it is a normal circuit with only one resistor. Therefore, we can find the potential difference across the resistor using Ohm's law
[tex]V=I_0 R = (3.20 A)(6.0 \Omega)=19.2 V[/tex]
Then the battery is removed from the circuit: this means that the coil will discharge through the resistor.
The voltage on the coil is given by
[tex]V_L(t) = -V e^{-\frac{t}{\tau}}[/tex] (1)
which means that it is maximum at the moment when the battery is disconnected, when t=0:
[tex]V_L(0)=.V[/tex]
And V this time is the voltage across the resistor, 19.2 V (because the coil is now connected to the resistor, not to the battery). So, the voltage across the coil will be -19.2 V, and the voltage across the resistor will be the same in magnitude, 19.2 V (since the coil and the resistor are connected to the same points in the circuit): however, the signs of the potential difference will be opposite.
(e-b) 0 V on both
After several seconds,
[tex]t>>\tau[/tex]
If we use this approximation into the formula
[tex]V_L(t) = -V e^{-\frac{t}{\tau}}[/tex] (1)
We find that
[tex]V_L = 0[/tex]
And since now the resistor is directly connected to the coil, the voltage in the resistor will be the same as the coil, so 0 V. This means that the coil has completely discharged, and current is no longer flowing through the circuit.
When a battery is connected to a coil and a resistor, initially all the battery voltage is across the coil. After some time, the voltage across the coil reduces to zero and that across the resistor becomes equal to the battery voltage. The voltages are equal during the magnetization process of the coil. When the battery is replaced with a short circuit, the entire voltage falls across the coil initially and then reduces to zero.
Explanation:At the instant the battery is connected to the 5.00mH coil and 6.00Ω resistor (t=0), the potential difference across the resistor will be zero and the entire battery voltage will be across the coil as it opposes the sudden change in current. Therefore, at t=0, the voltage across the resistor is 0V and the voltage across the coil is 20.0V.
After several seconds, the current in the circuit will have achieved a steady state as the coil has become fully magnetized and now behaves as a wire. Therefore, the voltage drop across the resistor will become 20.0V (due to Ohm's law I=V/R, V=IR), and that across the coil will be 0V.
The two voltages are equal when the coil is half-way through its magnetization process. This is when the current in the circuit is building up.
When the circuit is modified with a short circuit after a current of 3.20A has been established, the entire potential difference falls across the coil immediately afterwards. Several seconds later, the coil loses its magnetic field since no more current flows through the circuit, thus no voltage exists either across the coil or the resistor.
Learn more about Electric Circuits here:https://brainly.com/question/29761561
#SPJ3
Project Seafarer was an ambitious program to construct an enormous antenna, buried underground on a site about 10000 km2 in area. Its purpose was to transmit signals to submarines while they were deeply submerged. If the effective wavelength were 1.8 × 104 Earth radii, what would be the (a) frequency and (b) period of the radiation emitted? Ordinarily, electromagnetic radiations do not penetrate very far into conductors such as seawater. Take the Earth's radius to be 6370 km. (a) Number Enter your answer for part (a) in accordance to the question statementEntry field with incorrect answer Units Choose the answer for part (a) from the menu in accordance to the question statementEntry field with correct answer
(a) 0.0026 Hz
The relationship between frequency and wavelength for an electromagnetic wave is
[tex]f=\frac{c}{\lambda}[/tex] (1)
where
[tex]c=3.0\cdot 10^8 m/s[/tex] is the speed of light
f is the frequency
[tex]\lambda[/tex] is the wavelength
For the wave in the problem, the wavelength is [tex]1.8\cdot 10^4[/tex] Earth radii. The Earth radius is
[tex]R=6370 km = 6.37\cdot 10^6 m[/tex]
so the wavelength would be
[tex]\lambda = (1.8\cdot 10^4 )(6.37\cdot 10^6 m)=1.14\cdot 10^{11}m[/tex]
So by using eq.(1) we find the frequency:
[tex]f=\frac{3\cdot 10^8 m/s}{1.14\cdot 10^{11}m}=0.0026 Hz[/tex]
(b) 384.6 s
The period of a wave is given by:
[tex]T=\frac{1}{f}[/tex]
where
T is the period
f is the frequency
For the wave in the problem,
f = 0.0026 Hz
so the period is
[tex]T=\frac{1}{0.0026 Hz}=384.6 s[/tex]
To find the frequency and period of the radiation emitted by Project Seafarer, use the formula: Frequency = Speed of Light / Wavelength and Period = 1 / Frequency. Convert the effective wavelength given to kilometers and then use the formulas to calculate the frequency and period.
Explanation:To find the frequency and period of the radiation emitted by the Project Seafarer antenna, we need to use the formula:
Frequency = Speed of Light / Wavelength
Period = 1 / Frequency
The effective wavelength given in the question is 1.8 × 104 Earth radii. We can convert this to kilometers by multiplying it by the Earth's radius of 6370 km. So the wavelength is 1.8 × 104 * 6370 = 1.1486 × 108 km.
Now we can calculate the frequency using the formula: Frequency = 3 × 108 m/s / 1.1486 × 108 km.
Finally, we can calculate the period by taking the reciprocal of the frequency.
Learn more about Frequency and period of electromagnetic radiation here:https://brainly.com/question/10429732
#SPJ3
Use Snell's Law to solve the following:
Answer:
1.171
Explanation:
if n₁sinΘ₁=n₂sinΘ₂, then n₂=n₁sinΘ₁ / sinΘ₂;
[tex]n_2=\frac{1.5*sin45}{sin65}=\frac{1.5*0.707}{0.906} =1.1705[/tex]
A tennis player tosses a tennis ball straight up and then catches it after 1.77 s at the same height as the point of release. (a) What is the acceleration of the ball while it is in flight? magnitude m/s2 direction (b) What is the velocity of the ball when it reaches its maximum height? magnitude m/s direction (c) Find the initial velocity of the ball. m/s upward (d) Find the maximum height it reaches. m'
(a) 9.8 m/s^2, downward
There is only one force acting on the ball while it is in flight: the force of gravity, which is
F = mg
where
m is the mass of the ball
g is the gravitational acceleration
According to Newton's second law, the force acting on the ball is equal to the product between the mass of the ball and its acceleration, so
F = mg = ma
which means
a = g
So, the acceleration of the ball during the whole flight is equal to the acceleration of gravity:
g = -9.8 m/s^2
where the negative sign means the direction is downward.
(b) v = 0
Any object thrown upward reaches its maximum height when its velocity is zero:
v = 0
In fact, at that moment, the object's velocity is turning from upward to downward: that means that at that instant, the velocity must be zero.
(c) 8.72 m/s, upward
The initial velocity of the ball can be found by using the equation:
v = u + at
Where
v = 0 is the velocity at the maximum height
u is the initial velocity
a = g = -9.8 m/s^2 is the acceleration
t is the time at which the ball reaches the maximum height: this is half of the time it takes for the ball to reach again the starting point of the motion, so
[tex]t=\frac{1.77 s}{2}=0.89 s[/tex]
So we can now solve the equation for u, and we find:
[tex]u=v-at=0-(-9.8 m/s^2)(0.89 s)=8.72 m/s[/tex]
(d) 3.88 m
The maximum height reached by the ball can be found by using the equation:
[tex]v^2 - u^2 = 2ad[/tex]
where
v = 0 is the velocity at the maximum height
u = 8.72 m/s is the initial velocity
a = g = -9.8 m/s^2 is the gravitational acceleration
d is the maximum height reached
Solving the equation for d, we find
[tex]d=\frac{v^2-u^2}{2a}=\frac{0^2-(8.72 m/s)^2}{2(-9.8 m/s^2)}=3.88 m[/tex]
Bob is driving the getaway car after the big bank robbery. He's going 50 m/s when his headlights suddenly reveal a nail strip that the cops have placed across the road 120 m in front of him. If Bob can stop in time, he can throw the car into reverse and escape. But if he crosses the nail strip, all his tires will go flat and he will be caught. Bob's reaction time before he can hit the brakes is 0.7 s,and his car's maximum deceleration is 10 m/s2.Does Bob stop before or after the nail strip and by what distance?Express your answer with the appropriate units. Enter positive value if Bob stops after the nail strip and negative value if he stops before it.
Answer:
-40 m
Explanation:
First, we find the position that Bob reaches before he reacts.
x = x₀ + v₀ t + ½ at²
x = 0 m + (50 m/s) (0.7 s) + ½ (0 m/s²) (0.7 s)²
x = 35 m
Then, we find his position when he stops after deceleration.
v² = v₀² + 2a(x - x₀)
(0 m/s)² = (50 m/s)² + 2(-10 m/s²)(x - 35 m)
x = 160 m
His position relative to the nail strip is:
120 m - 160 m = -40 m
So Bob stops after the nail strip by 40 m.
Bob will stop after the nail strip by a distance of 40 m.
Explanation:Using the given information, we can calculate whether Bob stops before or after the nail strip and by what distance.
First, we need to calculate the distance covered during Bob's reaction time. He is traveling at 50 m/s, and his reaction time is 0.7 s, so the distance covered is:
Distance = (Speed)(Time) = (50 m/s)(0.7 s) = 35 m
Next, we can calculate the distance it takes for Bob to stop the car. Bob's car has a maximum deceleration of 10 m/s2, so the distance covered during braking is:
Distance = (Initial Velocity^2) / (2 * Deceleration) = (50 m/s)ˆ2 / (2 * 10 m/s^2) = 125 m
Therefore, the total stopping distance is the sum of the distance covered during the reaction time and the distance covered during braking:
Total Stopping Distance = 35 m + 125 m = 160 m
Since the nail strip is 120 m in front of him, Bob will stop after the nail strip by a distance of 40 m.
Learn more about Stopping distance here:https://brainly.com/question/4726243
#SPJ2
The speed of electromagnetic waves (which include visible light, radio, and x rays) in vacuum is 3.0 x 108 m/s. Wavelengths of visible light waves range from about 400 nm in the violet to about 700 nm in the red. What are the (a) minimum and (b) maximum frequencies of these waves? The range of frequencies for shortwave radio (for example, FM radio and VHF television) is 1.5 to 300 MHz. What are the (c) minimum and (d) maximum wavelengths of these waves? X ray wavelengths range from about 5.0 nm to about 1.0 x 10-2 nm. What are the (e) minimum and (f) maximum frequencies of x rays?
(a) [tex]4.29\cdot 10^{14}Hz[/tex]
The frequency of an electromagnetic wave is given by
[tex]f=\frac{c}{\lambda}[/tex]
where
c is the speed of light
[tex]\lambda[/tex] is the wavelength
We notice from the formula that the frequency is inversely proportional to the wavelength, so the minimum frequency corresponds to the maximum wavelength, and viceversa
The maximum value of the wavelength of the visible light waves is
[tex]\lambda_{max} = 700 nm = 7.0\cdot 10^{-7} m[/tex] (red light)
so the minimum frequency of visible light is
[tex]f_{min} = \frac{c}{\lambda_{max}}=\frac{3.0\cdot 10^8 m/s}{7.00\cdot 10^{-7}m}=4.29\cdot 10^{14}Hz[/tex]
(b) [tex]7.50\cdot 10^{14}Hz[/tex]
The maximum frequency corresponds to the minimum wavelength;
The minimum wavelength is
[tex]\lambda_{min} = 400 nm = 4.0\cdot 10^{-7} m[/tex] (violet light)
so the maximum frequency of visible light is
[tex]f_{max} = \frac{c}{\lambda_{min}}=\frac{3.0\cdot 10^8 m/s}{4.00\cdot 10^{-7}m}=7.50\cdot 10^{14}Hz[/tex]
(c) 1 m
The wavelength of an electromagnetic wave is given by
[tex]\lambda=\frac{c}{f}[/tex]
as before, we notice that the minimum wavelength corresponds to the maximum frequency, and viceversa.
The maximum frequency of shortwave radio waves is
[tex]f_{max}=300 MHz = 3.0\cdot 10^8 Hz[/tex]
so the minimum wavelength of these waves is
[tex]\lambda_{min} = \frac{c}{f_{max}}=\frac{3.0\cdot 10^8 m/s}{3.0\cdot 10^8 Hz}=1 m[/tex]
(d) 200 m
The minimum frequency of shortwave radio waves is
[tex]f_{min}=1.5 MHz = 1.5\cdot 10^6 Hz[/tex]
so the maximum wavelength of these waves is
[tex]\lambda_{max} = \frac{c}{f_{min}}=\frac{3.0\cdot 10^8 m/s}{1.5\cdot 10^6 Hz}=200 m[/tex]
(e) [tex]6.0\cdot 10^{16}Hz[/tex]
As in part (a) and (b), we can find the frequency of the X-rays by using the formula
[tex]f=\frac{c}{\lambda}[/tex]
The maximum wavelength of the x-rays is
[tex]\lambda_{max} = 5.0 nm = 5.0\cdot 10^{-9} m[/tex]
so the minimum frequency is
[tex]f_{min} = \frac{c}{\lambda_{max}}=\frac{3.0\cdot 10^8 m/s}{5.0\cdot 10^{-9}m}=6.0\cdot 10^{16}Hz[/tex]
(f) [tex]3.0\cdot 10^{19}Hz[/tex]
The maximum frequency corresponds to the minimum wavelength;
The minimum wavelength is
[tex]\lambda_{min} = 1.0\cdot 10^{-2} nm = 1.0\cdot 10^{-11} m[/tex]
so the maximum frequency of the x-rays is
[tex]f_{max} = \frac{c}{\lambda_{min}}=\frac{3.0\cdot 10^8 m/s}{1.0\cdot 10^{-11}m}=3.0\cdot 10^{19}Hz[/tex]
Final answer:
The frequency of electromagnetic waves varies inversely with the wavelength. For visible light, the frequencies range between 4.29 x 10⁹⁴ Hz and 7.5 x 10⁹⁴ Hz; for shortwave radio, the wavelengths range from 1 to 200 meters; for x-rays, the frequencies vary between 6 x 10⁹⁶ Hz and 3 x 10⁹⁹ Hz.
Explanation:
Calculating Frequency and Wavelength of Electromagnetic Waves
To calculate the frequency (ν) and wavelength (λ) of electromagnetic waves, we use the relation c = λν, where c is the speed of light in a vacuum (approximately 3.0 x 10⁸ m/s).
(a) The minimum frequency of visible light (700 nm) is obtained by c/λ, yielding approximately 4.29 x 10¹⁴ Hz.
(b) The maximum frequency for visible light (400 nm) is reached with c/λ, giving around 7.5 x 10¹⁴ Hz.
(c) The minimum wavelength for shortwave radio at 300 MHz is found by c/ν, resulting in 1 meter (m).
(d) The maximum wavelength at 1.5 MHz of shortwave radio is calculated with c/ν, equating to 200 meters (m).
(e) The minimum frequency of x-rays (1.0 x 10⁻² nm) is computed using c/λ, and is approximately 3 x 10¹⁹ Hz.
(f) The maximum frequency for x-rays (5.0 nm) is also obtained with c/λ, yielding around 6 x 10¹⁶ Hz.
What is EMF?
When are we exposed to EMF?
Does EMF increase or decrease with distance?
What are the primary differences in direct current and alternating current?
Answer:
Electricity is the voltage produced by any electrical energy source such as battery or dynamo. EMF increase with distance.
The direct current is fixed but the alternating current is constantly changing
The wavelength of a wave on a string is 1.2 meters. If the speed of the wave is 60 meters/second, what is its frequency? A. 0.20 hertz B. 2.0 hertz C. 50 hertz D. 10 hertz E. 15 hertz
Answer:
50 Hz
Explanation:
The frequency of a wave is given by
[tex]f=\frac{v}{\lambda}[/tex]
where
v is the speed of the wave
[tex]\lambda[/tex] is the wavelength
In this problem,
v = 60 m/s
[tex]\lambda=1.2 m[/tex]
So the frequency is
[tex]f=\frac{60 m/s}{1.2 m}=50 Hz[/tex]
Answer:
50 hertz
Explanation:
A team of astronauts is on a mission to land on and explore a large asteroid. In addition to collecting samples and performing experiments, one of their tasks is to demonstrate the concept of the escape speed by throwing rocks straight up at various initial speeds. With what minimum initial speed ????esc will the rocks need to be thrown in order for them never to "fall" back to the asteroid? Assume that the asteroid is approximately spherical, with an average density ????=4.49×106 g/m3 and volume ????=3.32×1012 m3 . Recall that the universal gravitational constant is ????=6.67×10−11 N·m2/kg2 .
Answer:
463.4 m/s
Explanation:
The escape velocity on the surface of a planet/asteroid is given by
[tex]v=\sqrt{\frac{2GM}{R}}[/tex] (1)
where
G is the gravitational constant
M is the mass of the planet/asteroid
R is the radius of the planet/asteroid
For the asteroid in this problem, we know
[tex]\rho=4.49\cdot 10^6 g/m^3[/tex] is the density
[tex]V=3.32\cdot 10^{12} m^3[/tex] is the volume
So we can find its mass:
[tex]M=\frac{\rho}{V}=(4.49\cdot 10^6 g/m^3)(3.32\cdot 10^{12}m^3)=1.49\cdot 10^{19} kg[/tex]
Also, the asteroid is approximately spherical, so its volume is given by
[tex]V=\frac{4}{3}\pi R^3[/tex]
where R is the radius. Solving the formula for R, we find its radius:
[tex]R=\sqrt[3]{\frac{3V}{4\pi}}=\sqrt[3]{\frac{3(3.32\cdot 10^{12}m^3)}{4\pi}}=9256 m[/tex]
So now we can use eq.(1) to find the escape velocity:
[tex]v=\sqrt{\frac{2(6.67\cdot 10^{-11})(1.49\cdot 10^{19}kg)}{9256 m}}=463.4 m/s[/tex]
The difference between the mass of the nucleus and the mass of the nucleons it contains is converted into ? that holds the nucleus together
Photoelectric energy
Binding energy
Answer:
Binding energy
Explanation:
The energy required to bind the nucleus is called binding energy.
Binding energy is equal to the product of mass defect and square of velocity of light.
Mass defect is the difference of mass of neucleons and the mass of atom.
Answer:
Binding Energy
Explanation:
Coders play an important role in
Answer:
it is a.health record documentation
Explanation:hope this helps
Answer: Reimbursement and research
Explanation: I got it right on the PF exam
Explain how energy allows a paper clip to be attracted to a magnet
I really don’t know maybe energy from the poles just attaches and the soil comes and energy lifts the matter of soil and the magnet follows and lifts and goes up to the soil and the poles attach the magnet to the soil and the energy lifts the magnet and the soil follows and it is attracted to the magnet
The North Pole of the bar magnet lines up magnetic domains in the paper clip, in such a fashion that the domain’s South Pole are on the closer side. In the same way, the South Pole induces North Pole in the paper clip. This causes the attraction
List the main types of electromagnetic waves in order of increasing frequency. radio waves, microwaves, infrared, visible light, ultraviolet light, X-rays, gamma rays microwaves, radio waves, infrared, visible light, ultraviolet light, X-rays, gamma rays radio waves, microwaves, infrared, ultraviolet light, visible light, X-rays, gamma rays radio waves, microwaves, visible light, infrared, ultraviolet light, X-rays, gamma rays radio waves, microwaves, infrared, visible light, ultraviolet light, gamma rays, X-rays
Answer:
radio waves, microwaves, infrared, visible light, ultraviolet light, X-rays, gamma rays
Explanation:
Electromagnetic waves are oscillations of electric and magnetic fields in a direction perpendicular to the direction of motion of the wave (transverse waves). They are classified into 7 different types, according to their frequencies.
From lowest to highest frequency, we have:
Radio waves [tex]<10^9 Hz[/tex]
Microwaves [tex]10^9 Hz - 4\cdot 10^{13}Hz[/tex]
Infrared [tex]4\cdot 10^{13} - 4\cdot 10^{14} Hz[/tex]
Visible light [tex]4\cdot 10^{14} - 8\cdot 10^{14}Hz[/tex]
Ultraviolet [tex]8\cdot 10^{14} - 2.4\cdot 10^{16} Hz[/tex]
X-rays [tex]2.4\cdot 10^{16} -5 \cdot 10^{19}Hz[/tex]
Gamma rays [tex]>5\cdot 10^{19} Hz[/tex]
The index of refraction for violet light in silica flint glass is 1.66, and that for red light is 1.62. What is the angular spread (in degrees) of visible light passing through a prism of apex angle 60.0° if the angle of incidence is 54.0°? See figure below. A triangular prism is shown. A ray of visible light moves up and to the right and is incident on the left edge of the prism. Inside the prism a rainbow of colors spreads out from the incident ray and in order from top to bottom they are red, orange, yellow, green, blue and violet. Once the rainbow leaves the prism, it continues to move down and to the right but all the colors are at slopes which are steeper than they were within the material. The rainbow is then projected onto a screen. The angular spread between the red and violet colors is indicated. A dashed line extends from the incident ray on the left to the right and the angle that this line makes with the red light ray is labeled Deviation of red light. ° (b) What If? What is the maximum angular spread (in degrees) for white light passing through this prism?
Answer:
4.2°
Explanation:
Snell’s law gives:-
n₁ sin θ₁ = n₂ sin θ₂
Given, θ₁ = 54.0°
For the refraction of violet light ( n = 1.66 ) from air to glass:
( 1.00 ) sin 54.0° = ( 1.66 ) sin θ₂₁
sin θ₂₁ = ( 1.00 / 1.66 ) sin 54.0° = 29.2
For the refraction of violet light from glass to air …
n₂ sin θ₂ = n₃ sin θ₃₁
θ₂ = 60 -29.2 = 30.8
n₂ = 1.66
n₃ = 1
sin θ₃₁ = ( n₂ / n₃ ) sin θ₂ = n₂ sin θ₂₂ = ( 1.66 ) sin 30.8°
θ₃₁ = sin ⁻ ¹ [ ( 1.66 ) sin 30.8° ] = 58.2°
For the refraction of red light ( n = 1.62 ) from air to glass
( 1.000 ) sin 54° = ( 1.62 ) sin θ₂
sin θ₂ = ( 1.000 / 1.62 ) sin 54°
θ₂ = sin ⁻ ¹ [ ( 1.000 / 1.62 ) sin 54° ] = 29.95986° = 30.0°
For the refraction of red light from glass to air
n₂ sin θ₂ = n₃ sin θ₃₂
n₂ = 1.62 , θ₂ = 30° , n₃ = 1.000 …
sin θ₃₂ = ( n₂ / n₃ ) sin θ₂ = n₂ sin θ₂ = ( 1.62 ) sin 30°
θ₃₂ = sin ⁻ ¹ [ ( 1.62 ) sin 30° ] = 54°
Angular spread = γ = θ₃₁ - θ₃₂ = 4.2°
The angular spread in degrees of visible light passing through a prism of ap ex angle 60.0° if the angle of incidence is 54.0° is; 4.1°
What is the angular spread?For incoming rays, sin sin θ₂ = (sin θ₁)/n
Thus;
(θ₂)_violet = sin⁻¹ ((sin 54)/1.66)
(θ₂)_violet = 29.17°
(θ₂)_red = sin⁻¹ ((sin 54)/1.62)
(θ₂)_red = 29.96°
For the outgoing ray;
(90 - θ₂) + (90 - θ₃) + 60° = 180°
Also, θ₃ = 60 - θ₂ and sin θ₄ = n sin θ₃
(θ₄)_violet = sin⁻¹ (1.66 * sin 30.83))
(θ₄)_violet = 58.29°
θ₄)_red = sin⁻¹ (1.62 * sin 30.04))
(θ₄)_red = 54.19°
The angular dispersion is the difference and so;
Angular dispersion = (θ₄)_violet - (θ₄)_red
Angular dispersion = 58.29° - 54.19°
Angular Dispersion = 4.1°
Read more about angular dispersion at; https://brainly.com/question/13972198
An electron, traveling at a speed of 5.90 × 10 6 5.90×106 m/s, strikes the target of an X-ray tube. Upon impact, the electron decelerates to three-quarters of its original speed, with an X-ray photon being emitted in the process. What is the wavelength of the photon?
Answer:
[tex]2.84\cdot 10^{-8} m[/tex]
Explanation:
Due to the law of conservation of energy, the energy of the emitted X-ray photon is equal to the energy lost by the electron.
The initial kinetic energy of the electron is:
[tex]K_i = \frac{1}{2}mv_i^2 = \frac{1}{2}(9.11\cdot 10^{-31}kg)(5.90\cdot 10^6 m/s)^2=1.59\cdot 10^{-17}J[/tex]
The electrons decelerates to 3/4 of its speed, so the new speed is
[tex]v_f = \frac{3}{4}v_i = \frac{3}{4}(5.90\cdot 10^6 m/s)=4.425\cdot 10^6 m/s[/tex]
So the final kinetic energy is
[tex]K_f = \frac{1}{2}mv_f^2=\frac{1}{2}(9.11 \cdot 10^{-31} kg)(4.425\cdot 10^6 m/s)^2=8.9\cdot 10^{-18} J[/tex]
So, the energy lost by the electron, which is equal to the energy of the emitted photon, is
[tex]E=K_i - K_f =1.59\cdot 10^{-17} J-8.9\cdot 10^{-18} J=7\cdot 10^{-18} J[/tex]
The wavelength of the photon is related to its energy by
[tex]\lambda=\frac{hc}{E}[/tex]
where h is the Planck constant and c the speed of light. Substituting E, we find
[tex]\lambda=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{7\cdot 10^{-18} J}=2.84\cdot 10^{-8} m[/tex]
To determine the wavelength of the photon emitted when an electron decelerates in an X-ray tube, we can use Planck's equation and the information given about the electron's speed.
Explanation:When an electron decelerates, it emits electromagnetic waves known as X-rays. The wavelength of the X-ray photon can be determined using Planck's equation, E = hv, where E is energy, h is Planck's constant, and v is frequency. Given that the electron's velocity decreases to three-quarters of its original speed and the initial speed is 5.90x10^6 m/s, we can calculate the velocity of the electron after deceleration. Using this value, we can then calculate the wavelength of the photon emitted. Therefore, using the provided information, we can find the wavelength of the photon.
Learn more about X-ray wavelengths here:https://brainly.com/question/13699468
#SPJ11
Guiana dolphins are one of the few mammals able to detect electric fields. In a test of sensitivity, a dolphin was exposed to the electric field of charged electrodes. The electric field was measured by detecting the potential difference between two electrodes located 1.0 cm apart along the field lines. The dolphin could reliably detect a field that produced a potential difference of 0.50 mV. What is the corresponding electric field strength?
Answer:
0.05 V/m
Explanation:
For a uniform electric field, electric field strength and potential difference are related by
[tex]E=\frac{\Delta V}{d}[/tex]
where
E is the electric field strength
[tex]\Delta V[/tex] is the potential difference
d is the distance between the two points
Here we have
[tex]\Delta V= 0.50 mV=5\cdot 10^{-4}V[/tex]
[tex]d=1.0 cm=0.01 m[/tex]
So, the electric field strength is
[tex]E=\frac{5\cdot 10^{-4} V}{0.01 m}=0.05 V/m[/tex]
A parallel-plate capacitor initially has air (K= 1) between the plates. We first fullycharge it by a 12 V battery. After the battery is disconnected, we insert a dielectricbetween the plates and it completely fills the space in between. A voltmeter is placedacross the capacitor and it reads 3.6 V now.(a) Assuming that there is no charge loss during the process, what is the dielectricconstant of this material?(b) What’s the fraction of the stored energy changed by inserting the dielectric?(c) What will the voltmeter read if the dielectric is pulled partway out so that it fillsonly half of the space in between the plates?
(a) 3.33
For a capacitor with dielectric disconnected from the battery, the relationship between the voltage across the capacitor without the dielectric (V) and with the dielectric (V) is given by
[tex]V' = \frac{V}{k}[/tex]
where
k is the dielectric constant of the material
In this problem, we have
[tex]V' = 3.6 V[/tex]
[tex]V=12 V[/tex]
So we can re-arrange the formula to find the dielectric constant:
[tex]k=\frac{V}{V'}=\frac{12 V}{3.6 V}=3.33[/tex]
(b) The energy stored reduces by a factor 3.33
The energy stored in a capacitor is
[tex]U=\frac{1}{2}QV[/tex]
where
Q is the charge stored on the capacitor
V is the voltage across the capacitor
Here we can write the initial energy stored in the capacitor (without dielectric) as
[tex]U=\frac{1}{2}QV[/tex]
while after inserting the dielectric is
[tex]U'=\frac{1}{2}QV' = \frac{1}{2}Q\frac{V}{k}[/tex]
since Q, the charge, has not changed (the capacitor is disconnected, so the charge cannot flow away from the capacitor).
So the ratio between the two energies is
[tex]\frac{U'}{U}=\frac{\frac{1}{2}Q\frac{V}{k}}{\frac{1}{2}QV}=\frac{1}{k}[/tex]
which means
[tex]U' = \frac{U}{k}=\frac{U}{3.33}[/tex]
So, the energy stored has decreased by a factor 3.33.
(c) 5.5 V
Pulling the dielectric only partway so that it fills half of the space between the plates is equivalent to a system of 2 capacitors in parallel, each of them with area A/2 (where A is the original area of the plates of the capacitor), of which one of the two is filled with dielectric while the other one is not.
Calling
[tex]C=\frac{\epsilon_0 A}{d}[/tex] the initial capacitance of the capacitor without dielectric
The capacitance of the part of the capacitor of area A/2 without dielectric is
[tex]C_1 = \frac{\epsilon_0 \frac{A}{2}}{d}= \frac{C}{2}[/tex]
while the capacitance of the part of the capacitor with dielectric is
[tex]C_2 = \frac{k \epsilon_0 \frac{A}{2}}{d}= \frac{kC}{2}[/tex]
The two are in parallel, so their total capacitance is
[tex]C' = C_1 + C_2 = \frac{C}{2}+\frac{kC}{2}=(1+k)\frac{C}{2}=(1+3.33)\frac{C}{2}=2.17 C[/tex]
We also have that
[tex]V=\frac{Q}{C}=12 V[/tex] this is the initial voltage
So the final voltage will be
[tex]V' = \frac{Q}{C'}=\frac{Q}{2.17 C}=\frac{1}{2.17}V=\frac{12 V}{2.17}=5.5 V[/tex]
Final answer:
The dielectric constant of the material is 3.3 based on the voltage drop after insertion between the capacitor's plates from 12 V to 3.6 V. The insertion of the dielectric changes the stored energy to 9% of the original. With half the space filled by the dielectric, the voltmeter would read approximately 5.6 V.
Explanation:
The question concerns the concept of capacitors in physics, specifically the effects of inserting a dielectric material between the plates of a parallel-plate capacitor. Assuming that the battery has been disconnected and there is no charge loss during the process, let's address the parts of the question step by step.
(a) Dielectric constant of the material
The dielectric constant (K) of a material can be determined by the ratio of the initial voltage (Vo) to the voltage (V) after the dielectric has been inserted. Given that the initial voltage is 12 V and it drops to 3.6 V, the dielectric constant is K = Vo / V = 12 / 3.6 = 3.3. Therefore, the dielectric constant of this material is 3.3.
(b) Fraction of the stored energy changed
The stored energy in a capacitor is proportional to the square of the voltage across it. When the voltage drops due to the insertion of the dielectric, the energy stored changes by a factor of (V / Vo)2. Hence, the fraction of the energy change is (3.6 / 12)2 = 0.09, or 9% of the original stored energy.
(c) Voltmeter reading with half space filled by the dielectric
When the dielectric only fills half of the space between the plates, the effective dielectric constant becomes a weighted average of the dielectric and air (K=1). Assuming the dielectric constant of the inserted material is 3.3, and it fills half the space, the effective dielectric constant is (3.3 + 1) / 2 = 2.15. Thus, the new voltage is Vnew = Vo / Keff = 12 / 2.15 = 5.58 V. Therefore, the voltmeter will read approximately 5.6 V when the dielectric fills only half of the space between the plates.
A standard mercury thermometer consists of a hollow glasscylinder, the stem, attached to a bulb filled with mercury. As thetemperature of the thermometer changes, the mercury expands (orcontracts) and the height of the mercury column in the stemchanges. Marks are made on the stem to denote the height of themercury column at different temperatures such as the freezing point(0 C ) and the boiling point (100 C ) of water. Othertemperature markings are interpolated between these twopoints.Due to concerns about the toxic properties of mercury,many thermometers are made with other liquids. Consider drainingthe mercury from the above thermometer and replacing it withanother, such as alcohol. Alcohol has a coefficient of volumeexpansion 5.6 times greater than that of mercury. The amount ofalcohol is adjusted such that when placed in ice water, thethermometer accurately records 0 C. No other changes are made tothe thermometer.Part AWhen the alcohol thermometer is placed in 22 C water,what temperature will the thermometer record?less than 22 C22 Cgreater than 22 CPart BWhen the alcohol thermometer is placed in a -12 Csubstance, what temperature will the thermometer record?less than-12 C-12 Cgreater than -12 CPart CIf you want to design a thermometer with the same spacingbetween temperature markings as a mercury thermometer, how must thediameter of the inner hollow cylinder of the stem of the alcoholthermometer compare to that of the mercury thermometer? Assume thatthe bulb has a much larger volume than the stem.5.6 times wider√5.6 times widerthe same diameter but different bulbsize√5.6 times smaller5.6 times smaller
Answer:
this is way too long....
Explanation:
Boxing gloves are padded to lessen the force of a blow. (a) Calculate the force exerted by a boxing glove on an opponent’s face, if the glove and face compress 7.50 cm during a blow in which the 7.00-kg arm and glove are brought to rest from an initial speed of 10.0 m/s. (b) Calculate the force exerted by an identical blow in the days when no gloves were used and the knuckles and face would compress only 2.00 cm. (c) Discuss the magnitude of the force with glove on. Does it seem high enough to cause damage even though it is lower than the force with no glove?
(a) -4667 N
First of all, we can calculate the acceleration of the arm and the glove, using the following equation:
[tex]v^2 - u^2 = 2ad[/tex]
where
v = 0 is the final speed
u = 10 m/s is the initial speed
a is the acceleration
d = 7.50 cm = 0.075 m is the distance through which the arm and the glove move before coming to a stop
Solving for a,
[tex]a=\frac{v^2-u^2}{2d}=\frac{0-(10.0 m/s)^2}{2(0.075 m)}=-666.7 m/s^2[/tex]
And since the know the mass of the arm+glove:
m = 7.00 kg
We can now calculate the force exerted:
[tex]F=ma=(7.00 kg)(-666.7 N)=-4,667 N[/tex]
(b) -17500 N
We can repeat the problem, but this time the stopping distance is different:
d = 2.00 cm = 0.02 m
So the acceleration is
[tex]a=\frac{v^2-u^2}{2d}=\frac{0-(10.0 m/s)^2}{2(0.02 m)}=-2500 m/s^2[/tex]
and so the force is
[tex]F=ma=(7.00 kg)(-2500 m/s^2)=-17,500 N[/tex]
(c) Yes
The force exerted when the glove is used is
F = 4667 N
We see that this force corresponds approximately to the weight of an object of mass m=476 kg, in fact:
[tex]W=mg=(476 kg)(9.81 m/s^2)=4670 N[/tex]
Which is quite a lot. Therefore, the force even when gloves are used seems enough to cause damage.
To calculate the force exerted by a boxing glove on an opponent's face, we can use the equation for impulse.
Explanation:In order to calculate the force exerted by a boxing glove on an opponent's face, we need to use the equation for impulse:
Impulse = change in momentum = force x time
We know the initial speed of the arm and glove (10.0 m/s), the final speed (0 m/s), and the time it takes for the glove and face to compress (which can be calculated using the distance and the initial speed).
By substituting these values into the equation, we can find the average force exerted by the boxing glove on the opponent's face.
Learn more about Calculating force exerted by a boxing glove here:https://brainly.com/question/31182760
#SPJ3
At sunset, red light travels horizontally through the doorway in the western wall of your beach cabin, and you observe the light on the eastern wall. Assume that the light has a wavelength of 700 nm, that the door is 1.0 m wide, and that the distance from the door to the far wall of your cabin in 14 m .Part ADetermine the distance between the central bright fringe and a first-order dark fringe of the interference pattern created by the doorway "slit".
Answer:
[tex]9.8\cdot 10^{-6}m[/tex]
Explanation:
For light passing through a single slit, the position of the nth-minimum from the central bright fringe in the diffraction pattern is given by
[tex]y=\frac{n \lambda D}{d}[/tex]
where
[tex]\lambda[/tex] is the wavelength
D is the distance of the screen from the slit
d is the width of the slit
In this problem, we have
[tex]\lambda=700 nm = 7.00\cdot 10^{-7}m[/tex] is the wavelength of the red light
D = 14 m is the distance of the screen from the doorway
d = 1.0 m is the width of the doorway
Substituting n=1 into the equation, we find the distance between the central bright fringe and the first-order dark fringe (the first minimum):
[tex]y=\frac{(1)(7.00\cdot 10^{-7} m)(14 m)}{1.0 m}=9.8\cdot 10^{-6}m[/tex]
Imagine two parallel, (infinite) planar sheets of perfectly black material, maintained at fixed temperatures TH and TL, respectively, and separated by some finite distance D. Suspended in between and parallel to these sheets are n additional, separate, parallel sheets of material, all with constant reflectivity r. (By separate, we mean that none of the sheets are in actual mechanical contact). When the entire system reaches a steady state, find (a) the net flux density (energy flow per unit time per unit area) of thermal radiation between the original two sheets. (b) How does this compare to the radiation flux that would be present between the two black sheets in the absence of the n intervening sheets? (c) To provide the best insulation, should these intermediate sheets be made of very shiny or very black material, or something in between?
The TIL will support your answer I believe if you just think about of the provide the inslutoin which that mean money is gong fast to the enconmomy
Which of the following is the least reliable source of background information for a scientific project?
general Internet site
government Internet site
library reserve section
scientific journal
Answer:
general internet site
Explanation:
Answer:
General internet site
Explanation:
The following table lists the work functions of a few common metals, measured in electron volts. Metal Φ(eV) Cesium 1.9 Potassium 2.2 Sodium 2.3 Lithium 2.5 Calcium 3.2 Copper 4.5 Silver 4.7 Platinum 5.6 Using these data, answer the following questions about the photoelectric effect. Part A Light with a wavelength of 190 nm is incident on a metal surface. The most energetic electrons emitted from the surface are measured to have 4.0 eV of kinetic energy. Which of the metals in the table is the surface most likely to be made of? View Available Hint(s) Submit Part B Of the eight metals listed in the table, how many will eject electrons when a green laser (λg=510nm) is shined on them? View Available Hint(s) Submit Part C Light with some unknown wavelength is incident on a piece of copper. The most energetic electrons emitted from the copper have 2.7 eV of kinetic energy. If the copper is replaced with a piece of sodium, what will be the maximum possible kinetic energy K of the electrons emitted from this new surface? Enter your answer numerically in electron volts to two significant figures. View Available Hint(s)
A. Lithium
The equation for the photoelectric effect is:
[tex]E=\phi + K[/tex]
where
[tex]E=\frac{hc}{\lambda}[/tex] is the energy of the incident light, with h being the Planck constant, c being the speed of light, and [tex]\lambda[/tex] being the wavelength
[tex]\phi[/tex] is the work function of the metal (the minimum energy needed to extract one photoelectron from the surface of the metal)
K is the maximum kinetic energy of the photoelectron
In this problem, we have
[tex]\lambda=190 nm=1.9\cdot 10^{-7}m[/tex], so the energy of the incident light is
[tex]E=\frac{hc}{\lambda}=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{1.9\cdot 10^{-7} m}=1.05\cdot 10^{-18}J[/tex]
Converting in electronvolts,
[tex]E=\frac{1.05\cdot 10^{-18}J}{1.6\cdot 10^{-19} J/eV}=6.5 eV[/tex]
Since the electrons are emitted from the surface with a maximum kinetic energy of
K = 4.0 eV
The work function of this metal is
[tex]\phi = E-K=6.5 eV-4.0 eV=2.5 eV[/tex]
So, the metal is Lithium.
B. cesium, potassium, sodium
The wavelength of green light is
[tex]\lambda=510 nm=5.1\cdot 10^{-7} m[/tex]
So its energy is
[tex]E=\frac{hc}{\lambda}=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{5.1\cdot 10^{-7} m}=3.9\cdot 10^{-19}J[/tex]
Converting in electronvolts,
[tex]E=\frac{3.9\cdot 10^{-19}J}{1.6\cdot 10^{-19} J/eV}=2.4 eV[/tex]
So, all the metals that have work function smaller than this value will be able to emit photoelectrons, so:
Cesium
Potassium
Sodium
C. 4.9 eV
In this case, we have
- Copper work function: [tex]\phi = 4.5 eV[/tex]
- Maximum kinetic energy of the emitted electrons: K = 2.7 eV
So, the energy of the incident light is
[tex]E=\phi+K=4.5 eV+2.7 eV=7.2 eV[/tex]
Then the copper is replaced with sodium, which has work function of
[tex]\phi = 2.3 eV[/tex]
So, if the same light shine on sodium, then the maximum kinetic energy of the emitted electrons will be
[tex]K=E-\phi = 7.2 eV-2.3 eV=4.9 eV[/tex]
The surface is most likely to be made of Lithium. Four metals (Cesium, Potassium, Sodium, and Lithium) will eject electrons when a green laser is shone on them. The maximum kinetic energy of the electrons emitted from Sodium will be approximately 4.9 eV.
Explanation:Part A: Let's calculate the energy of the incident photon using Planck's equation E = h * c / λ , where h is Planck's constant (6.626 * 10^-34 J.s), c is the speed of light (3 * 10^8 m/s) and λ is the wavelength of the incident light (convert 190 nm to 1.9 * 10^-7 m). The energy of the photon (Ep) is approximately 6.6 eV. The given kinetic energy (Ek) of the most energetic electrons is 4.0 eV. According to the photoelectric effect, Ep = Work Function + Ek. So, the work function of the metal surface (Wf) is Ep - Ek, which gives us a work function of 2.6 eV. The closest value to this in the table is that of Lithium with 2.5 eV, so the surface is likely made of Lithium.
Part B: To find out the number of metals that will eject electrons when a green laser of wavelength 510 nm is shone on them, we first need to convert this wavelength into energy using the same formula as in Part A. The energy hence calculated is approximately 2.4 eV. As per the photoelectric effect, a metal can only eject electrons when its work function is less than or equal to the energy of the incident light. Therefore, only metals with work functions less than or equal to 2.4 eV will eject electrons. Looking at the table, we see that this covers Cesium, Potassium, Sodium, and Lithium. So, 4 metals will eject electrons.
Part C: Given the kinetic energy of electrons emitted from copper is 2.7 eV, and the work function of copper is 4.5 eV. According to the photoelectric effect, the energy of the incident radiation should be the sum of these two, which yields 7.2 eV. Now, if we replace the copper sample with sodium (having a work function of 2.3 eV), then the maximum kinetic energy of the emitted electrons from the sodium sample (Ek) will be the energy of the incident light minus the work function of Sodium i.e., 7.2 eV - 2.3 eV which is approximately 4.9 eV.
Learn more about Photoelectric effect here:https://brainly.com/question/35875610
#SPJ3
The sun is directly over the equator on what day of the year?
Answer:
The Sun Crosses the Equator. on March 19, 20, or 21 every year. The September equinox occurs the moment the Sun crosses the celestial equator, this happens either on September 22, 23, or 24 every year.
Explanation:
The Sun Crosses the Equator. on March 19, 20, or 21 every year. The September equinox occurs the moment the Sun crosses the celestial equator, this happens either on September 22, 23, or 24 every year.
Answer:
The sun is directly above the equator on the equinoxes, the spring equinox being on March 20, and the fall equinox being on September 22.
Explanation:
A plane electromagnetic wave, with wavelength 4.1 m, travels in vacuum in the positive direction of an x axis. The electric field, of amplitude 310 V/m, oscillates parallel to the y axis. What are the (a) frequency, (b) angular frequency, and (c) angular wave number of the wave? (d) What is the amplitude of the magnetic field component? (e) Parallel to which axis does the magnetic field oscillate? (f) What is the time-averaged rate of energy flow associated with this wave? The wave uniformly illuminates a surface of area 1.8 m2. If the surface totally absorbs the wave, what are (g) the rate at which momentum is transferred to the surface and (h) the radiation pressure?
(a) [tex]7.32\cdot 10^7 Hz[/tex]
The frequency of an electromagnetic waves is given by:
[tex]f=\frac{c}{\lambda}[/tex]
where
[tex]c=3.0\cdot 10^8 m/s[/tex] is the speed of light
[tex]\lambda=4.1 m[/tex] is the wavelength of the wave in the problem
Substituting into the equation, we find
[tex]f=\frac{3.0\cdot 10^8 m/s}{4.1 m}=7.32\cdot 10^7 Hz[/tex]
(b) [tex]4.60\cdot 10^8 rad/s[/tex]
The angular frequency of a wave is given by
[tex]\omega = 2\pi f[/tex]
where
f is the frequency
For this wave,
[tex]f=7.32\cdot 10^7 Hz[/tex]
So the angular frequency is
[tex]\omega=2\pi(7.32\cdot 10^7 Hz)=4.60\cdot 10^8 rad/s[/tex]
(c) [tex]1.53 m^{-1}[/tex]
The angular wave number of a wave is given by
[tex]k=\frac{2\pi}{\lambda}[/tex]
where
[tex]\lambda[/tex] is the wavelength of the wave
For this wave, we have
[tex]\lambda=4.1 m[/tex]
so the angular wave number is
[tex]k=\frac{2\pi}{4.1 m}=1.53 m^{-1}[/tex]
(d) [tex]1.03\cdot 10^{-6}T[/tex]
For an electromagnetic wave,
[tex]E=cB[/tex]
where
E is the magnitude of the electric field component
c is the speed of light
B is the magnitude of the magnetic field component
For this wave,
E = 310 V/m
So we can re-arrange the equation to find B:
[tex]B=\frac{E}{c}=\frac{310 V/m}{3\cdot 10^8 m/s}=1.03\cdot 10^{-6}T[/tex]
(e) z-axis
In an electromagnetic wave, the electric field and the magnetic field oscillate perpendicular to each other, and they both oscillate perpendicular to the direction of propagation of the wave. Therefore, we have:
- direction of propagation of the wave --> positive x axis
- direction of oscillation of electric field --> y axis
- direction of oscillation of magnetic field --> perpendicular to both, so it must be z-axis
(f) 127.5 W/m^2
The time-averaged rate of energy flow of an electromagnetic wave is given by:
[tex]I=\frac{E^2}{2\mu_0 c}[/tex]
where we have
E = 310 V/m is the amplitude of the electric field
[tex]\mu_0[/tex] is the vacuum permeability
c is the speed of light
Substituting into the formula,
[tex]I=\frac{(310 V/m)^2}{2(4\pi\cdot 10^{-7} H/m) (3\cdot 10^8 m/s)}=127.5 W/m^2[/tex]
(g) [tex]1.53\cdot 10^{-8} kg m/s[/tex]
For a surface that totally absorbs the wave, the rate at which momentum is transferred to the surface given by
[tex]\frac{dp}{dt}=\frac{<S>A}{c}[/tex]
where the <S> is the magnitude of the Poynting vector, given by
[tex]<S>=\frac{EB}{\mu_0}=\frac{(310 V/m)(1.03\cdot 10^{-6} T)}{4\pi \cdot 10^{-7}H/m}=254.2 W/m^2[/tex]
and where the surface is
A = 1.8 m^2
Substituting, we find
[tex]\frac{dp}{dt}=\frac{(254.2 W/m^2)(1.8 m^2)}{3\cdot 10^8 m/s}=1.53\cdot 10^{-8} kg m/s[/tex]
(h) [tex]8.47\cdot 10^{-7} N/m^2[/tex]
For a surface that totally absorbs the wave, the radiation pressure is given by
[tex]p=\frac{<S>}{c}[/tex]
where we have
[tex]<S>=254.2 W/m^2[/tex]
[tex]c=3\cdot 10^8 m/s[/tex]
Substituting, we find
[tex]p=\frac{254.2 W/m^2}{3\cdot 10^8 m/s}=8.47\cdot 10^{-7} N/m^2[/tex]
What’s The Answer, To The Question In The Photo
Answer:
The correct answer is the third option: The kinetic energy of the water molecules decreases.
Explanation:
Temperature is, in depth, a statistical value; kind of an average of the particles movement in any physical system (such as a glass filled with water). Kinetic energy, for sure, is the energy resulting from movement (technically depending on mass and velocity of a system; in other words, the faster something moves, the greater its kinetic energy.
Since temperature is related to the total average random movement in a system, and so is the kinetic energy (related to movement through velocity), as the thermometer measures less temperature, that would mean that the particles (in this case: water particles) are moving slowly, so that: the slower something moves, the lower its kinetic energy.
In summary: temperature tells about how fast are moving and colliding the particles within a system, and since it is directly proportional to the amount of movement, it can be related (also directly proportional) to the kinectic energy.
A scale used to weigh fish consists of a spring hung from a support. The spring's equilibrium length is 10.0 cm. When a 4.0 kg fish is suspended from the end of the spring, it stretches to a length of 13.4 cm.
(Part A) What is the spring constant k for this spring? Express your answer with the appropriate units.
(Part B) If an 8.0 kg fish is suspended from the spring, what will be the length of the spring? Express your answer with the appropriate units.
A) 1153 N/m
We can find the spring constant by using Hooke's law:
[tex]F=kx[/tex]
where
F is the force applied to the spring
k is the spring constant
x is the displacement of the spring
In this problem, a fish of mass m = 4.0 kg is hanging on the spring, so the force applied is the weight of the fish:
[tex]F=mg=(4.0 kg)(9.8 m/s^2)=39.2 N[/tex]
and the displacement of the spring is:
[tex]x = 13.4 cm - 10.0 cm = 3.4 cm = 0.034 m[/tex]
so, the spring constant is
[tex]k=\frac{F}{x}=\frac{39.2 N}{0.034 m}=1153 N/m[/tex]
B) 16.8 cm
In this case, a fish of mass
m = 8.0 kg
is hanging on the spring. Therefore, the force applied to the spring is
[tex]F=mg=(8.0 kg)(9.8 m/s^2)=78.4 N[/tex]
So we can find the displacement of the spring:
[tex]x=\frac{F}{k}=\frac{78.4 N}{1153 N/m}=0.068 m = 6.8 cm[/tex]
And since the equilibrium length of the spring is
[tex]x_0 = 10.0 cm[/tex]
the new length of the spring will be
[tex]x' = 10.0 cm + 6.8 cm = 16.8 cm[/tex]
The spring constant of the spring is 1,152.94 N/m.
The new length of the spring when 8kg fish is suspended on it is 16.8 cm.
The given parameters;
length of the spring, L₁ = 10.0 cmmass of the fish, m = 4 kgfinal length of the spring, L₂ = 13.4 cmThe extension of the spring is calculated as follows;
x = L₂ - L₁
x = 13.4 cm - 10.0 cm
x = 3.4 cm
The spring constant of the spring is calculated as follows;
F = kx
mg = kx
[tex]k = \frac{mg}{x} \\\\k = \frac{4 \times 9.8}{0.034} \\\\k = 1,152.94 \ N/m[/tex]
The new extension of the spring when 8 kg fish is suspended on it;
[tex]x = \frac{mg}{k} \\\\x = \frac{8 \times 9.8}{1152.94} \\\\ x= 0.068 \ m\\\\x = 6.8 \ cm[/tex]
The new length of the spring = 6.8 cm + 10 cm = 16.8 cm
Learn more here:https://brainly.com/question/4404276
A uniform square crate is released from rest with corner D directly above A and it rotates about A until its corner B impacts the floor and then it rotates about B. The floor is rough enough to prevent slipping and the corner at B does not rebound on impact. Determine, (a) as a function of g and `, the angular velocity of the crate !E2 just before impact. (b) as a function of !E2, the angular velocity of the crate immediately after impact !E3. (c) the fraction of energy lost during the impact. (d) the maximum achieved after the impact. During the impact, assume that the weight force is non-impulsive.
(c) the fraction of energy lost during the impact
Gary needs to move a chair that is 20 pounds at a distance of 5 feet. How much work will he need to produce?
100 ft-lbs
80 ft-lbs
120 ft-lbs
75 ft-lbs
The answer is:
The answer is the first option, 100 ft-lbs.
Why?To calculate the work done by an object over a distance, we need to multiply the applied force by the amount of movement (distance).
So, to calculate the work that Gary needs to do to move the chair, we need to use the following equation:
[tex]Work=Force*Distance[/tex]
We are given,
[tex]Force=20lb\\Distance=5ft[/tex]
[tex]Work=F*D\\Work=(20lb)*(5ft)=100ft-lbs[/tex]
Hence, the answer is the first option, 100 ft-lbs.
Have a nice day!
answer- 100 ft-lbs
Hope I helped
Make the following conversion.
56.32 kL = _____ L
0.056320
0.56320
5,632
56,320
Answer:
The answer would be D 56,320
Explanation:
If a hypothesis is falsifiable, _____.
it is wrong
it might be wrong
it must be possible to prove it wrong
it is correct
Answer:
it must be possible to prove it wrong
Explanation:
Answer:
it must be possible to prove it wrong
Explanation:
Falsibiable is the word used to make the refernce that it is possible to prove something wrong or to prove that somthing is wrong with a statement ot hypothesis, since the hypothsesis is falsifiable it must be possible to prove it wrong, that is the correct answer.