at the beginning of a lesson, a piece of chalk is 4.875 inches long. at the end of the lesson, it is 3.125 inches long. writ the two amounts in expanded form using fractiones.

Answers

Answer 1
Each digit of each amount is written in expanded form depending on the position of the digit.

Let's see number 4.875.

Digit 4 is in the place of the units so it is 4 * 1

8 is in the place of the tenths, so it is 8/10 = 8 * 1/10

7 is in the place of the hundreths, so it is 7/100 = 7 * 1 /100

5 is in the place of the thousanths, so it is 5/1000 = 5 * 1 / 1000

So, the number 4.875 written in expanded form using fractions is:

4*1 + 8 * 1/10 + 7 * 1/100 + 5 * 1/100.

Now, see the next amount, 3.125, which using the same procedure leads to:

3 *1 + 1 * 1/10 + 2 * 1/100 + 5 * 1/ 1000

Related Questions

Find the value of x in 4000(1.5x) = 25,000. show all work

Answers

4000(1.5)x = 25,000
25000/4000 = 1.5x
6.25 = 1.5x
25/6 = x
4000(1.5x)=25000  divide both sides by 4000

1.5x=6.25  divide both sides by 1.5

x=25/6

x=4 1/6

But that is pretty simplistic, I suspect that you actually meant this was an exponential function of the form:

4000(1.5^x)=25000  divide both sides by 4000

1.5^x=6.25  take the natural log of both sides

xln(1.5)=ln(6.25)  divide both sides by ln(1.5)

x=ln(6.25)/ln(1.5)

x≈4.52  (to nearest hundredth)

Quadrilateral ABCD is similar to quadrilateral EFGH. The lengths of the three longest sides in quadrilateral ABCD are 60 feet, 40 feet, and 30 feet long. If the two shortest sides of quadrilateral EFGH are 6 feet long and 12 feet long, how long is the 4th side on quadrilateral ABCD?

Answers

Final answer:

The length of the fourth side on quadrilateral ABCD is 120 feet.

Explanation:

Given that quadrilateral ABCD is similar to quadrilateral EFGH, we can use the property of similar figures to find the length of the fourth side on quadrilateral ABCD.

If the two shortest sides of quadrilateral EFGH are 6 feet and 12 feet long, we can set up a proportion using the corresponding sides of the two quadrilaterals.

Let x be the length of the fourth side on quadrilateral ABCD.

Using the property of similar figures, we have:

(60/6) = (x/12)

Cross multiplying, we get:

6x = 720

Dividing both sides by 6, we find:

x = 120

Therefore, the length of the fourth side on quadrilateral ABCD is 120 feet.

An earthquake with a rating of 3.2 is not usually felt. What is the value of x when the Richter scale rating is 3.2? Round your answer to the nearest hundredth.

Answers

10^3.2=1584.893≈1584.89

Write an equation for the function. Tells what each variable you use represents. A plant's height is 1.6 times its age in months.

Answers

Y=1.6x+b (B can be anything or you won't need to add it into the equation)
This is function can be defined as a linear equation, in the standard form of y = mx + b. X is the independent variable, y is the dependent variable, m is the slope (rate of change/growth), and b is the constant (starting point).

Since the growth rate of height for the plant is 1.6 times the independent variable and there is no starting point (so assume 0), our equation should look like this:

y = 1.6x

The plant's height is y and its age in months is x.

Hope my answer helped clear things up a bit.

What is the sum of the arithmetic series? ∑[i=1,15,Fn=5i-1]

Answers

[tex]\bf \sum\limits_{i=1}^{15}\ 5i-1\implies 5\sum\limits_{i=1}^{15}\ i-\sum\limits_{i=1}^{15}\ 1\implies 5\left[ \cfrac{15(15+1)}{2} \right]-(15\cdot 1) \\\\\\ 5\cdot (15\cdot 8)-15\implies 585[/tex]

5 times the difference of 29 and a number is 215. Which equation below can be used to find the unknown number?

Answers

Is it multiple choice? If not I would say 215=5(x)-29

Answer:

The required equation is [tex]5(29-n)=215[/tex]

Step-by-step explanation:

Given : 5 times the difference of 29 and a number is 215.

To find :  Which equation can be used to find the unknown number?

Solution :

Let the number be 'n'.

The difference of 29 and a number i.e. [tex]29-n[/tex]

5 times the difference of 29 and a number i.e. [tex]5(29-n)[/tex]

5 times the difference of 29 and a number is 215 i.e. [tex]5(29-n)=215[/tex]

Therefore, the required equation is [tex]5(29-n)=215[/tex]

Which figure has the correct lines of symmetry drawn in?

Answers

The figure which has the correct lines of symmetry drawn is figure D.

What is line of symmetry?

A line of symmetry refers to the line that divides a shape or an object into two equal and symmetrical parts.

The figure given is a five sided shape referred to as a pentagon.

A pentagon has five lines of symmetry.

Therefore, the correct line of symmetry is 5 lines drawn from each angle respectively.

Read more on line of symmetry:

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You have a 20-foot ladder that you are using as you paint your house. You place the ladder so that it forms an angle of 30 at the point of contact between the ladder and the ground. How high will the top of the ladder be above the ground

Answers

First draw out the picture it will help.  Then you can see that you want the opposite segment of the angle, which leads you to use a sine.  So you have 20sin30 or 20(1/2) or 10ft.

Answer:

The Ladder is 10 ft high.

Step-by-step explanation

According to the question we have a 20 ft ladder inclined against a wall at a 30° angle, and are asked to find how high the top of the ladder is from the ground. I have added a visual representation to help you better understand the situation. As you can see we need to solve for x. Since we are given one angle and the hypotenuse we can solve for x using the SIN operator.

[tex]sin(a) = \frac{opposite}{hypotenuse}[/tex]

Since we have the angle (a) and the hypotenuse we can just plug the information into the sin equation and solve for the opposite (x).

[tex]sin(30) = \frac{x}{20ft}[/tex]

[tex]sin(30)*20ft = x[/tex]

[tex]0.5*20ft = x[/tex]

[tex]10ft = x[/tex]

So now we can see that the height of the top of the ladder to the ground is 10 ft

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

What is the value of -2 (7-15) over 4

Answers

The answer to the question is: 4

How many inches are in a foot?

Answers

there are 12 inches in a foot
There are 12 inches in a foot.

A teacher has 3 hours to grade all the papers submitted by the 35 students in her class. She gets through the first 5 papers in 30 minutes. How much faster does she have to work to grade the remaining papers in the allotted time?

Answers

At first, she was grading papers at 10 papers per hour. To meet her time limit, she would have to begin grading them at 12 papers per hour, or 20% faster than her previous rate
so, she has 3hrs to grade all papers, for 35 students.. alrite.

the first 5, she does them in 30minutes.. what's the speed rate? well, 5/30 or 1/6

now, she has still 2 hours and a half, or 150 minutes, to do the remaining 30 papers... she has to work at a rate of 30/150 then... which is 1/5 simplified.

now if we take 1/6 as the 100%, what is 1/5 in percentage then?

[tex]\bf \begin{array}{ccllll} rate&\%\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ \frac{1}{6}&100\\\\ \frac{1}{5}&x \end{array}\implies \cfrac{\frac{1}{6}}{\frac{1}{5}}=\cfrac{100}{x}\implies \cfrac{1}{6}\cdot \cfrac{5}{1}=\cfrac{100}{x}\implies \cfrac{5}{6}=\cfrac{100}{x} \\\\\\ x=\cfrac{6\cdot 100}{5}\implies x=120[/tex]

so 1/5 is 120% in relation to 1/6... meaning the rate of 1/5 she needs to move through, namely 1 paper every 5 minutes, is 20% faster than 1/6.

What is the value of k in the equation below? 5k - 2k = 12? 1 1/5, 1 5/7, 3, 4

Answers

Hi there!

5k - 2k = 12
Solve for K
3k = 12
Divide both sides by 3
3k/3 = 12/3
k = 4
The correct answer is : 4


I hope that helps!
Brainliest answer :)

Answer:4

Step-by-step explanation:

simplify the expression below. show your work. -(-7y+12)

Answers

[tex]-(-7y+12) = 7y -12[/tex]

What is the distance between (–6, 2) and (8, 10) on a coordinate grid?

Answers

Distance Formula: d = √(x₂ - x₁)² + (y₂ - y₁)²

(-6 , 2) and (8 , 10)
 x₁   y₁         x₂    y₂

d = √(8 - (-6))² + (10 - 2)²
d = √(8+6)² + (10 - 2)²
d = √(14)² + (8)²
d = √(196) + (64)
d = √ 260
d = 2√65

I think this is right, but I am not sure.

Answer:

D. √260

Step-by-step explanation:

Use the distance formula then input the points (–6, 2) and (8, 10) into it to get √(-6 −2)^2 + (2 −10)^2. Finaly simplify/solve and you get √260.

Can someone please help me solve this triangle problem, picture is shown.

Answers

(4t + 4t + 4t)  (addition form)

3(4t) (multiplication form)

these are two forms you can use to get your answer

answer: 12t


hope this helps
perimeter = 4t + 4t + 4t

and

perimeter = 4t * 3

find two consecutive even integers such that the smaller added to five times the larger give you a sum of 46.

Answers

First consecutive integer: n 
Second consecutive integer: n + 2 (next even integer) 
n + 5(n + 2) = 46 
n + 5n + 10 = 46 

6n + 10 = 46 
6n = 36 
n = 6 
n + 2 = 8 
Your answer is 6 and 8

Which expression is equivalent to (7^3)−2
A- 1 over 7 times 7 times 7 times 7 times 7 times 7
B- 7
C- 1 over 7
D-negative 1 over 7 times 7 times 7 times 7 times 7 times 7

Answers

[tex]\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\ a^{-{ n}} \implies \cfrac{1}{a^{ n}} \qquad \qquad \cfrac{1}{a^{ n}}\implies a^{-{ n}} \qquad \qquad a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}} \\\\ -------------------------------\\\\ (7^3)^{-2}\implies 7^{-2\cdot 3}\implies 7^{-6}\implies \cfrac{1}{7^6}\implies \cfrac{1}{7\cdot 7\cdot 7\cdot 7\cdot 7\cdot 7}[/tex]

Steve can complete the 100m dash in 10 seconds while Paul can run it in 12 seconds. How does Steve's time compare to Paul's?

Answers

Steve is faster than Paul by 2 seconds after 100m

A taxi cab charges $0.55 per mile in addition to a $1.75 flat rate fee. Susie has $10 to spend on a taxi cab ride. The taxi driver will not give anyone a ride unless they are going somewhere that is more than 2 miles away. Model Susie’s situation with a system of inequalities.

Answers

The taxi driver doesn't give anyone a ride unless it's 2 miles away, as such you need to add at least $0.55x2 in addition to the $1.75 at the start
1.75+(0.55x2)=2.85
As Susie only has 10 dollars to spend, she can't exceed that. So Susie must spend more than $2.85(minimum from the taxi) and less than $10(her money)
so,
$2.85<Susie<$10

Pediatric asthma survey, n = 50. suppose that asthma affects 1 in 20 children in a population. you take an srs of 50 children from this population. can the normal approximation to the binomial be applied under these conditions? if not, what probability model can be used to describe the sampling variability of the number of asthmatics?

Answers

In this situation, 
n=50, p=1/20, q=(1-p)=19/20, and npq=19/8=2.4

We would like np and npq to be a large number, at least greater than 10.
The normal approximation can always be applied, but the result will be very approximate, depending on the values of np and npq.

Situations are favourable for the normal approximation when p is around 0.5, say between 0.3 and 0.7, and n>30.

"Normal approximation" is using normal probability distribution to approximate the binomial distribution, when n is large (greater than 70) or exceeds the capacity of most hand-held calculators.  The binomial distribution can be used if the following conditions are met:
1. Bernoulli trials, i.e. exactly two possible outcomes.2. Number of trials is known before and constant throughout the experiment, i.e. independent of outcomes.3. All trials are independent of each other.4. Probability of success is known, and remain constant throughout trials.
If all criteria are satisfied, we can model with binomial distribution, where the probability of x successes out of N trials each with probability of success p is given byP(x)=C(N,x)(p^x)(1-p)^(N-x)and,C(N,x) is number of combinations of selecting x objects out of N.
The mean is np, and variance is npq.

For the given situation, np=2.5, npq=2.375, so standard deviation=sqrt(2.375)=1.54.

n=50, p=1/20, q=(1-p)=19/20, and npq=19/eight=2.4

We would like np and npq to be a huge range, at least extra than 10.

The ordinary approximation can usually be carried out, but the result might be very approximate, relying on the values of np and npq.

conditions are favorable for the normal approximation when p is around 0.5, say among 0.3 and 0.7, and n>30.

For the given scenario, np=2.five, npq=2.375, so widespread deviation=sqrt(2.375)=1.54.

underneath what conditions binomial distribution tends to be everyday distribution?

the theory states that any distribution becomes normally allotted whilst the variety of variables is satisfactorily massive. for example, the binomial distribution has a tendency to alternate into the regular distribution with suggest and variance.

Learn more about binomial distribution here: https://brainly.com/question/15246027

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A geometry class has a total of 34 students. The number of males is 14 more than the number of females. How many males and how many females are in the class?

Answers

m=14+f,  m+f=34. Solve for the equations simultaneously.

one way is to substitute teh first into the second to get, 14+2f=34, or 7+f=17, or f=10. Since f is 10 and m+f=34, m=34-10=24.

Good luck!

value for X^2 left for 95% confidence interval when n=18

Answers

Given that n = 18, then the degree of freedom is n - 1 = 17.

From the table of Chi Square [tex](X^2)[/tex]

The value of [tex](X^2)[/tex] to the left for 95% confidence interval given a degree of freedom of 17 is 8.672

Without solving, decide what method you would use to solve each system: graphing, substitution, or elimination. Explain. 4s-3t=8 ; t=-2s-1

Answers

I would use substitution. The value of t in terms of s is already given so you can just plug that into the equation like this.
4s-3(-2s-1)=8

Information about movie ticket sales was printed in a movie magazine. in a sample of of fifty pg-rated movies, 36% had ticket sales in excess of $30,000,000. in a sample of thirty-five r-rated movies, 23% grossed over $30,000,000. suppose that this data is used to test the claim that the proportion of movies with ticket sales in excess of $30,000,000 is the same for pg movies as it is for r-rated movies. what would be the test statistic for this test? z = 1.29 z = 2.07 z = 4.005 z = 2.58

Answers

Let us say that the samples for fifty movies is 1 and samples for thirty five is 2. To solve the test statistic z, we can use the formula:

z = (p1 – p2) / sqrt [p (1 – p) (1 / n1 + 1 / n2)]

Where,

p1 = is the proportion for sample 1 = 0.36

p2 = is the proportion for sample 2 = 0.23

n1 = number of samples = 50

n2 = number of samples = 35

while p can be calculated using the formula:

p = [p1 * n1 / (n1 + n2)] + [p2 * n2 / (n1 + n2)]

p = [0.36 * 50 / (50 + 35)] + [0.23 * 35 / (50 + 35)]

p = 0.211764705 + 0.094705882

p = 0.306470587

Going back for the calculation of z:

z = (0.36 – 0.23) / sqrt [0.306 (1 – 0.306) (1 / 50 + 1 / 35)]

z = 1.279

 

Therefore the nearest answer is:

z = 1.29

The graph of a limacon curve is given. Without using your graphing calculator, determine which equation is correct for the graph.[-5, 5] by [-5, 5] (1 point)

Answers

The general form for this curve is:
[tex]r = Acos \theta + B[/tex]
Now find A,B given 2 points:
[tex]r(0) = 5, r(\pi) = 1[/tex]
[tex]A +B = 5 \\ \\ -A+B = 1[/tex]
Solving this system yields:
[tex]A = 2, B = 3 \\ \\ r = 2cos \theta + 3[/tex]

Answer:

r = 2 - 3 cos θ

Step-by-step explanation:

This is the best I could come up with.

A ship traveled for 4 hours heading east and for 3 hours heading north. If the total distance traveled was 149 miles, and the ship traveled 3 miles per hour faster heading north, at what speed was the ship traveling east?

Answers

just like the previous one

if the ship travelled a total of 149 miles, then let's say it travelled East "d" miles and thus it travelled North the slack of 149 and "d", thus " 149 - d".

now, if the rate travelling East is say "r", then the faster rate going North is " r + 3".

[tex]\bf \begin{array}{lccclll} &distance&rate&time\\ &-----&-----&-----\\ East&d&r&4\\ North&149-d&r+3&3 \end{array} \\\\\\ \begin{cases} \boxed{d}=4r\\ 149-d=(r+3)3\\ ----------\\ 149-\boxed{4r}=3(r+3) \end{cases}[/tex]

solve for "r".

Sidney made $26 more than seven times Casey's weekly salary. If x represents Casey's weekly salary, write an expression for sidney's weekly salary

Answers

7x+26 becase it is 7 times and then you add 26

Find the rectangular coordinates of the point with the polar coordinates. ordered pair negative 5 comma 5 pi divided by 3

Answers

[tex]\bf \begin{array}{rllll} (-5&,&\frac{5\pi }{3})\\ \uparrow &&\uparrow \\ r&&\theta \end{array}\qquad \begin{cases} x=rcos(\theta )\\ y=rsin(\theta )\\ ----------\\ x=(-5)cos\left( \frac{5\pi }{3} \right)\\ \qquad -5\cdot \frac{1}{2}\\ \qquad -\frac{5}{2}\\ y=(-5)sin\left( \frac{5\pi }{3} \right)\\ \qquad -5\cdot -\frac{\sqrt{3}}{2}\\ \qquad \frac{5\sqrt{3}}{2} \end{cases}\implies \left(-\frac{5}{2}\ ,\ \frac{5\sqrt{3}}{2} \right)[/tex]

simplify the expression I-30I

Answers

it would be only 30        

Each figure is filled with unit cubes. Drag 22 figures whose combined volume is equal to 45 unit cubes.

Answers

To solve this problem, what we have to do first is to calculate for the volumes of each figure. Let us start from the figure on the left going to the right. Let us call the figures 1 to 4. Formula for volume is:

V = l * w * h

 

Figure 1:

V1 = 4 * 3 * 1 = 12 unit cubes

 

Figure 2:

V2 = 3 * 2 * 3 = 18 unit cubes

 

Figure 3:

V3 = 2 * 2 * 4 = 16 unit cubes

 

Figure 4:

V4 = 3 * 3 * 3 = 27 unit cubes

 

The two combinations that would result in 45 total unit cubes would be:

V = V2 + V4 = 18 unit cubes + 27 unit cubes = 45 unit cubes

 

So the answers are:

Figure 2 and Figure 4

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