At medina middle school 2% of the students ride bikes to school. If 950 students attend Medina middle school how many students ride a bike to school?

Answer:

20 books NOW WHERE IS MY BRAINLY CROWN

Step-by-step explanation:

Answer:

The answer is D:)

Step-by-step explanation:

Multiplication is a method of finding the product of two or more numbers5367 is the 3 multiple 1,789

Multiplication is a method of finding the product of two or more numbers

We need to find 3 multiple 1,789

Three times of one thousand seven hundred eighty nine.

1789 has four digits and 3 has only one digit.

We have to multiply one digit number with all the four digits

1789

×    3

_________

5367

Hence 5367 is the  3 multiple 1,789.

To learn more on Multiplication click:

https://brainly.com/question/5992872

#SPJ2

with 50 grams of rubber, you can make approximately 8 pencils.

To solve this problem, we need to set up a proportion to find out how many pencils can be made with 50 grams of rubber.

Let's set up the proportion using the given information:

[tex]\[\frac{\text{Grams of rubber}}{\text{Number of pencils}} = \frac{60}{10} = \frac{50}{x}\][/tex]

Where:

- 60 grams of rubber is used to make 10 pencils.

- 50 grams of rubber is the amount we have.

- x is the number of pencils we want to find.

Now, let's solve for x:

[tex]\[\frac{60}{10} = \frac{50}{x}\][/tex]

Cross multiplying:

60x = 500

Dividing both sides by 60:

[tex]\[ x = \frac{500}{60} \][/tex]

x = 8.333

Since you can't make a fraction of a pencil, we need to round down to the nearest whole number because you can't make a fraction of a pencil. Therefore, with 50 grams of rubber, you can make approximately 8 pencils.

The probable question maybe:

A pencil Company used 60 grams of rubber to make 10 pencils how many pencils can be made with 50 grams of rubber?

Sandy's total earnings before taxes for the two weeks will be $769.70, which includes $518 from her hourly wages and $251.70 from her sales commission.

To solve how much Sandy will earn in hourly wages and commission over two weeks of work at a clothing store, where she makes $7 per hour and earns a 15% commission on her sales of $1,678, we first calculate her hourly wages: Sandy worked 74 hours, and at $7 per hour, her earnings from hours worked are 74 hours x $7/hour = $518.

Next, we calculate her commission earnings: 15% of $1,678 in sales is 0.15 x $1,678 = $251.70.

Adding both earnings gives us Sandy's total earnings before taxes, which is $518 + $251.70 = $769.70.

The group of girls can purchase 16 sodas with $20. Because each soda costs $1.25, we find this by dividing the total amount of money ($20) by the cost of each soda ($1.25)

The question is asking how many sodas a group of girls can buy with $20 if each soda costs $1.25. To find this out, you need to divide the total amount of money they have ($20) by the cost of each soda ($1.25). Therefore, $20 divided by $1.25 equals 16, so the girls can buy 16 sodas with $20. Here is a chart to illustrate this:

https://brainly.com/question/34253396

#SPJ2

To find the unit cost of $12 for 4 yd2, divide the total cost by the number of square yards, resulting in a unit cost of $3 per yd2.

To find the unit cost of $12 for 4 yd2, you should divide the total cost by the number of units. In this case, you divide $12 by 4 yd2 to find the cost per square yard. This gives you a unit cost of $3 per yd2.

Here's the step-by-step calculation:

This is a simple division problem that involves unit conversion and understanding fractions. When you perform the division, the units of yd2 remain, indicating the cost is per square yard.

Final answer:

To find the unit cost of $12 for 4 yd2, divide the total cost by the number of square yards, which results in $3 per square yard.

Explanation:

To find the unit cost per square yard when given a total cost for a certain number of square yards, you would divide the total cost by the number of square yards. In this case, the question is asking how to find the unit cost of $12 for 4 yd2.

Using simple division, take the total cost of $12 and divide it by the number of square yards, which is 4. This can be set up as a fraction: $12/4 yd2. When you divide 12 by 4, you get 3. Thus, the unit cost is $3 per yd2.

To understand this better, we can think of the 4 yd2 as a fraction, 4yd2/1, where we have 1 in the denominator. By dividing the total cost by the number of square yards, we are finding the price per single unit of area. Division is the mathematical operation used here, and after dividing, we find that each square yard costs $3.

Final answer:

The football team starts at their own 10 yard line, and after a gain of 15 yards, the ball is on the 25 yard line.

Explanation:

The question is about calculating the new position of a football on the field after a team makes a gain. Initially, the football team starts with the ball on their own 10 yard line. After making a gain of 15 yards in the first play, we can determine the new yard line position by simply adding the gain to the starting position.

Step-by-Step Calculation:

Starting yard line: 10 yards.

Gain made: 15 yards.

Calculate the new yard line position: Starting yard line + Gain made = 10 yards + 15 yards = 25 yards.

Therefore, after the gain, the ball is on the 25-yard line.

The answerto you question is the third one

To write a fraction as a percent, first remember that a percent is a ratio of a number to 100. If we want to write [tex]\frac{1}{8}[/tex] as a percent, we need to find a fraction equivalent to [tex]\frac{1}{8}[/tex] that has a 100 in the denominator. We can do this by setting up a proportion.

[tex]\frac{1}{8}[/tex] = [tex]\frac{n}{100}[/tex]

Now, we can use cross products to find the missing value.

8n = 100

÷8     ÷8   ← divide by 8 on both sides

n = 12.5

Therefore, [tex]\frac{1}{8}[/tex] is equal to [tex]\frac{12.5}{100}[/tex] or 12.5%.

Answer:

Drain A [tex]54\ min[/tex]

Drain B [tex]21.6\ min[/tex]

Step-by-step explanation:

Let

x------> the time in minutes

y-----> the volume of the pool in gallons

we know that

The equation that represent the situation is equal to

[tex]y=mx[/tex]

solve for x

[tex]x=y/m[/tex]

Drain A

[tex]x=y/m[/tex]

In this case we have

[tex]m=2\frac{gal}{min}[/tex]

[tex]y=108\ gal[/tex]

substitute

[tex]x=108/2=54\ min[/tex]

Drain B

[tex]x=y/m[/tex]

In this case we have

[tex]m=5\frac{gal}{min}[/tex]

[tex]y=108\ gal[/tex]

substitute

[tex]x=108/5=21.6\ min[/tex]