Assume that you have taken out an amortized loan for $10,000 to buy a new car. The yearly interest rate is 18% and you have agreed to pay off the loan in 4 years. What is your monthly payment?

The equation will be like this: y=ax+c. a is the slope and c is where the line crosses the (vertical) y axis - AKA the y-intercept.

As for the slope, it can be found like [(8-3)/(2-1)]. That gives 5. Another way to see it is to notice that between (1,3) and (2,8), the line moved up 5 points and went to the right only 1.

And for the y-intercept, make the equation y = 5x + c. Solve for c by filling x and y with information from any of the two points. Let's choose (1,3). Plugging in gives the equation 3=5(1)+c. C equals -2.

So, the final equation is:

y = 5x - 2

Answer:

y - 3 = 5(x - 1)

Step-by-step explanation:

Slope:  as we move from (1, 3) to (2, 8), x increases by 1 and y increases by 5.  Hence, the slope of this line is m = rise / run = 5/1, or just m = 5.

In point-slope form, the pertinent equation is

y - 3 = 5(x - 1)

Answer:

$ 2.737

Step-by-step explanation:

The amount of tax is 6% of the purchase price

Solution

[tex]\frac{6}{100} *45.62=2.7372[/tex]

Amount of tax will be $2.737

The amount of tax is 6% of the purchase price

Solution

\frac{6}{100} *45.62=2.7372

Amount of tax will be $2.737

First you are going to multiply the number by the percent. 9,895 x 20= 197,900.

Now divide the answer by 100. 197,900 / 100= 1,979.

This means the car salesman should make 1,979 from the car sale.

Remember, multiply the number by the percent, then divide that answer by 100.

I hope this helps! :)

Answer:

the first one is graph c and the second, graph b.

Step-by-step explanation:

They are both linear inequalities, so for both, you have to solve for x first. For the first one, since x is basically multiplied to 2 (2x), you have to divide both sides to get x by itself, and you get x>25. The graph has to have an opened circle, and the arrow should go to the right because all the numbers greater than 25 can be x. For the second one, you have to subtract 6 to both sides to get x by itself which then leaves you with ×<26. This one should also be an opened circle, and is going to the left, because all the numbers less than 26 can be x.

Answer:

first box c second box b

Step-by-step explanation:

Answer:

x³ - 4x² - 16x + 24

Step-by-step explanation:

Each term in the second factor is multiplied by each term in the first factor, that is

x(x² + 2x - 4) - 6(x² + 2x - 4) ← distribute both parenthesis

= x³ + 2x² - 4x - 6x² - 12x + 24 ← collect like terms

= x³ - 4x² - 16x + 24

A. x³ - 2x² - 16x + 24

To multiply 2 polynomials, apply the distributive property by using each term in 1 polynomial to multiply every in the other polynomial.

(x – 6)(x² + 2x – 4)

x(x² + 2x – 4) -6(x² + 2x – 4)

x³ + 2x² - 4x - 6x² - 12x + 24

Combine like terms

x³ - 2x² - 16x + 24

(x – 6)(x² + 2x – 4) equals: A. x³ - 2x² - 16x + 24

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Answer:

1.59

Step-by-step explanation:

log (2x-3)= log (3-x) -2

log (2x-3)/(3-x) =-2

If we remove log,

2x-3/(3-x) = e^-2

2x-3= 3e^-2 -xe^-2

2x+ xe^-2 = 3e^-2+3

x(2+e^-2) = 3( e^-2+1)

If you use calculator you will get answer nearly equal to 1.59.

Answer:

b d e f

Step-by-step explanation:

Answer:

k(x) = (3g + 5h)(x) ⇒ (1)

k(x) = (5h - 3g)(x) ⇒ (3)

k(x) = (h - g)(x) ⇒ (2)

k(x) = (g + h)(x) ⇒ (4)

k(x) = (5g + 3h)(x) ⇒ (5)

k(x) = (3h - 5g)(x) ⇒ (6)

Step-by-step explanation:

* To solve this problem we will substitute h(x) and g(x) in k(x) in the

  right column to find the corresponding function formula in the

  left column

∵ h(x) = 5 - 3x

∵ g(x) = -3^x + 5

- Lets start with the right column

# k(x) = (3g + 5h)(x)

∵ g(x) = -3^x + 5

∵ 3g(x) = 3[-3^x + 5] = [3 × -3^x + 3 × 5]

- Lets simplify 3 × -3^x

 take the negative out -(3 × 3^x), and use the rule a^n × a^m = a^(n+m)

∴ -3(3 × 3^x) = -(3^x+1)

∴ 3g(x) = -3^x+1 + 15

∵ h(x) = 5 - 3x

∵ 5h(x) = 5[5 - 3x] = [5 × 5 - 5 × 3x] = 25 - 15x

- Now substitute 3g(x) and 5h(x) in k(x)

∵ k(x) = (3g + 5h)(x)

∴ k(x) = -3^x+1 + 15 + 25 - 15x ⇒ simplify

∴ k(x) = 40 - 3^x+1 - 15x

∴ k(x) = 40 - 3^x+1 - 15x ⇒ k(x) = (3g + 5h)(x)

* k(x) = (3g + 5h)(x) ⇒ (1)

# k(x) = (5h - 3g)(x)

∵ 5h(x) = 25 - 15x

∵ 3g(x) = -3^x+1 + 15

∵ k(x) = (5h - 3g)(x)

∴ k(x) = 25 - 15x - (-3^x+1 + 15) = 25 -15x + 3^x+1 - 15 ⇒ simplify

∴ k(x) = 10 + 3^x+1 - 15x

∴ k(x) = 10 + 3^x+1 - 15x ⇒ k(x) = (5h - 3g)(x)

* k(x) = (5h - 3g)(x) ⇒ (3)

# k(x) = (h - g)(x)

∵ h(x) = 5 - 3x

∵ g(x) = -3^x + 5

∵ k(x) = (h - g)(x)

∴ k(x) = 5 - 3x - (-3^x + 5) = 5 - 3x + 3^x - 5 ⇒ simplify

∴ k(x) = 3^x - 3x

∴ k(x)= 3^x - 3x ⇒ k(x) = (h - g)(x)

* k(x) = (h - g)(x) ⇒ (2)

# k(x) = (g + h)(x)

∵ h(x) = 5 - 3x

∵ g(x) = -3^x + 5

∵ k(x) = (g + h)(x)

∴ k(x) = -3^x + 5 + 5 - 3x ⇒ simplify

∴ k(x) = 10 - 3^x - 3x

∴ k(x)= 10 - 3^x - 3x ⇒ k(x) = (g + h)(x)

* k(x) = (g + h)(x) ⇒ (4)

# k(x) = (5g + 3h)(x)

∵ g(x) = -3^x + 5

∵ 5g(x) = 5[-3^x + 5] = [5 × -3^x + 5 × 5] = 5(-3^x) + 25

∴ 5g(x) = -5(3^x) + 25

∵ h(x) = 5 - 3x

∵ 3h(x) = 3[5 - 3x] = [3 × 5 - 3 × 3x] = 15 - 9x

- Now substitute 5g(x) and 3h(x) in k(x)

∵ k(x) = (5g + 3h)(x)

∴ k(x) = -5(3^x) + 25 + 15 - 9x ⇒ simplify

∴ k(x) = 40 - 5(3^x) - 9x

∴ k(x) = 40 - 5(3^x) - 9x ⇒ k(x) = (5g + 3h)(x)

* k(x) = (5g + 3h)(x) ⇒ (5)

# k(x) = (3h - 5g)(x)

∵ 3h(x) = 15 - 9x

∵ 5g(x) = -5(3^x) + 25

∵ k(x) = (3h - 5g)(x)

∴ k(x) = 15 - 9x - [-5(3^x) + 25] = 15 - 9x + 5(3^x) - 25 ⇒ simplify

∴ k(x) = 5(3^x) - 9x - 10

∴ k(x) = 5(3^x) - 9x - 10 ⇒ k(x) = (3h - 5g)(x)

* k(x) = (3h - 5g)(x) ⇒ (6)

[tex]n[/tex] - 4-digit number

[tex]q[/tex] - quotient

[tex]131q+112=n\\132q+98=n\\\\131q+112=132q+98\\q=14\\\\131\cdot14+112=n\\\boxed{n=1946}[/tex]

The four-digit number which has the remainder of 112 when divided by 131 is 1946.

The division is one of the basic arithmetic operations in math in which a larger number is broken down into smaller groups having the same number of items.

Given that, number which has the remainder of 112 when divided by 131.

Let n be the number and q be the quotient.

We know that, Dividend = Divisor × Quotient + Remainder

Now, n=131×q+112 ------(i)

The remainder of 98 when divided by 132.

That is, n=132×q+98 ------(ii)

From equation (i) and (ii), we get

131×q+112=132×q+98

131q+112=132q+98

132q-131q=112-98

q=14

Substitute q=14 in equation (i), we get

n=131×14+112

n=1946

Therefore, the four digit number is 1946.

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The line of reflection between the two pentagons is the y-axis.

We can see this because all of the points in pentagon P'Q'R'S'T' have the same x-coordinate as their corresponding points in pentagon PQRST, but their y-coordinates are negated. For example, point P has coordinates (-4, 6), and its reflected image P' has coordinates (-4, -6).

The y-axis is the only line that passes through all of the midpoints of the segments connecting corresponding points in the two pentagons. Since reflection preserves distance, the line of reflection must be the perpendicular bisector of any segment connecting a point in one pentagon to its reflected image in the other pentagon.

Answer:

38

Step-by-step explanation:

Range is the largest number minus the smallest number

The largest number is 55 and the smallest number is 17

55-17 = 38

Answer:

[tex]\boxed{A=6}\checkmark[/tex]

The answer should have positive sign.

Step-by-step explanation:

First you do is divide by -6 from both sides of an equation.

[tex]\frac{-6(2+a)}{-6}=\frac{-48}{-6}[/tex]

Then, simplify and solve the problem.

[tex]-48/-6=8[/tex]

[tex]2+a=8[/tex]

Next, you switch sides.

[tex]a+2=8[/tex]

You subtract by 2 from both sides of an equation./

[tex]a+2-2=8-2[/tex]

Finally, solve/simplify.

[tex]8-2=6[/tex]

A=6 is the correct answer.

Hope this helps you!

Have a nice day! :)

[tex]|\Omega|=6^4=1296\\|A|=1\cdot1\cdot5\cdot5\cdot\dfrac{4!}{2!2!}=25\cdot6=150\\\\P(A)=\dfrac{150}{1296}\approx11.6\%[/tex]

Answer:

[tex]x=\frac{5}{3}[/tex]

Step-by-step explanation:

Let do algebra and figure out the value of x:

[tex]\frac{4}{x-3}+5=2\\\frac{4}{x-3}=2-5\\\frac{4}{x-3}=-3\\4=-3(x-3)\\4=-3x+9\\3x=9-4\\3x=5\\x=\frac{5}{3}[/tex]

Note: assuming that the problem is [tex]\frac{4}{x-3}+5=2[/tex]

Answer:

The answer is 5/3

Step-by-step explanation:

Answer:

Equation: 7n = 8.61

Solution: n = $1.23

Step-by-step explanation:

7 binders = $8.61

1 binder = $n

The price of one binder is seven times the price of 7 binders.

7n = The price of 7 binders

The price of 7 binders is $8.61

7n = $8.61

Divide both sides of the equation by 7

n = $1.23

Answer:

x=2

Step-by-step explanation:

Answer:

a

Step-by-step explanation:

Answer:

yes

Step-by-step explanation:

You can perform the "line test." If it is a function, there will not be two x's of the same value. In this case, x is 2,6,-1. No number repeats, thus making a function.

Answer:

Function:

(7, -4) (0, 9), (2, -2)

(-6, 5), (-5,6), (8,2)

(2, 3), (6, -5), (-1,3)

Not a Function:

(1, 9), (-3, -2), (1, -4)

(0, 3), (0, 7), (4, 0)

Step-by-step explanation:

I got it right on edge lol

also none of the other answers for this question on here are right

Hello!

Answer:

[tex]\boxed{2y+11x}[/tex]

Step-by-step explanation:

Distributive property: a(b+c)=ab+ac

First, you switch sides. *Group like terms*

[tex]4y-2y+7x+4x[/tex]

Then, you add the similar to elements. You can also add the numbers from left to right.

[tex]4y-2y=2y[/tex]

[tex]2y+7x+4x[/tex]

[tex]7x+4x=11x[/tex]

[tex]\boxed{2y+11x}\checkmark[/tex], is the correct answer.

Hope this helps!

Have a nice day! :)

Answer:

2y + 11x

Step-by-step explanation:

Simplify the expression 4y+7x- 2y+4x​

To simplify any expression, combine the like terms by adding or subtracting

To simplify 4y+7x- 2y+4x​, combine the like terms

combine 4y and -2y, = 2y and

combine 7x and 4x = 11x

2y + 11x

Answer: -2,4

Step-by-step explanation:

Center = (-2,4) are the coordinates of the center of the ellipse .

The major and minor axes' midpoints meet at the center of an ellipse. At their intersection, the axes are perpendicular. The foci are always on the major axis, and the constant sum of the distances between the foci is greater than the sum of the distances from the foci to any point on the ellipse.

The equation of an ellipse is [tex]\frac{\left(x - h\right)^{2}}{a^{2}} + \frac{\left(y - k\right)^{2}}{b^{2}} = 1[/tex]

where (h,k) is the center, b and a are the lengths of the semi-major and the semi-minor axes.

Our ellipse in this form is [tex]\frac{\left(x - \left(-2\right)\right)^{2}}{9} + \frac{\left(y - 4\right)^{2}}{36} = 1[/tex]

Thus, h = -2, k = 4

Center = (-2,4).

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Answer:

Cats: 28; Dogs: 13

Step-by-step explanation:

54-26=28

48-35=13

54+48=102

102-61=41

28+13=41

Answer:

Step-by-step explanation:

To find each answer, we just have to complete the table.

We know that there are 54 cats in total, and 26 belong to 8th grade. So, 7th grade would be 54-26=28.

Also, we know that there are 48 dogs in total, if 35 belong to 8th grade, then 7th grade would be 48-35=13.

Therefore, 7th grade students have 28 cats, 13 dogs, and 41 pets in total. Therefore, the right choice is the second one.

Answer:

They have the same slope but different y-intercepts, so they have no solution.

Step-by-step explanation:

As the slopes are the same (2) but the y-intercepts are different, it means that the straights are parallel. Parallel equations have no solution as the straights don't intercept each other.

Answer: They have the same slope but different y-intercepts, so they have no solution.

The given equations are [tex]y=2x+\frac{1}{4}[/tex] and [tex]y=2x-\frac{1}{4}[/tex].

We compare them with y = mx + b.

So the slope of both of them is m=2.

y-intercept for the first one is = b = 1/4

y-intercept for the second one is = b = -1/4

Hence, the lines are parallel and will never meet and will have no solution.

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Answer:

The answer is C) 57.46cm2

Step-by-step explanation:

To find the area of a trapezoid you add together the parallel lines and times the answer by the height. Then you divide it by 2.

Answer:

The answer is B, 160 cm2

Step-by-step explanation:

To find the area of a trapezoid we have to use the following equation:

A= 0.5*(b1*b2)*h

a= area

b1: base 1

b2: base 2

h: height

Then,

A= 0.5*(14cm+18cm)*10cm = 160 cm2.

Answer:

[tex]x=37.5[/tex]

Step-by-step explanation:

We need to find the solution to the following system of equations:

[tex]y = -\frac{4}{5} x[/tex] and [tex]y=-30[/tex]

By plugging the value of 'y' into the first equation we have that:

[tex]-30 = -\frac{4}{5} x[/tex] ⇒ [tex]30=\frac{4}{5} x[/tex]

Solving for 'x' we have:

[tex]x=37.5[/tex]

So, the solution to the system of equation is: (37.5, -30)

Answer:

[tex]\cos (x-y)=\dfrac{1}{2}=0.5[/tex]

Step-by-step explanation:

Use formula:

[tex]\cos (x-y)=\cos x\cos y+\sin x\sin y[/tex]

Since

[tex]\sin x=-\dfrac{1}{2}[/tex]

and angle x is in the fourth quadrant, then cos x is greater than 0 and is equal to

[tex]\cos x=\sqrt{1-\sin ^2x}=\sqrt{1-\left(-\dfrac{1}{2}\right)^2}=\sqrt{1-\dfrac{1}{4}}=\sqrt{\dfrac{3}{4}}=\dfrac{\sqrt{3}}{2}[/tex]

Since

[tex]\cos y=\dfrac{\sqrt{3}}{2}[/tex]

and angle y is in the first quadrant, then sin y is greater than 0 and is equal to

[tex]\sin y=\sqrt{1-\cos ^2y}=\sqrt{1-\left(\dfrac{\sqrt{3}}{2}\right)^2}=\sqrt{1-\dfrac{3}{4}}=\sqrt{\dfrac{1}{4}}=\dfrac{1}{2}[/tex]

Hence,

[tex]\cos (x-y)=\cos x\cos y+\sin x\sin y=\dfrac{\sqrt{3}}{2}\cdot \dfrac{\sqrt{3}}{2}+\left(-\dfrac{1}{2}\right)\cdot \dfrac{1}{2}=\dfrac{3}{4}-\dfrac{1}{4}=\dfrac{1}{2}[/tex]

Answer:

p^4 p^3 P^2

Step-by-step explanation:

Look at the numbers and put them in order from largest to smallest number.

Answer:Answer:

p^4 p^3 P^2

Step-by-step explanation:

Look at the numbers and put them in order from largest to smallest number.

Answer:

x = -4

Step-by-step explanation:

Distribute 2 inside the parentheses

[tex]2\times x = 2x\\ 2\times2=4\\ 2x+4 - 4[/tex]

Combine like terms

[tex]-4x + 2x = -2x + 4 = 12[/tex]

Subtract 4 from both sides

-2x = 8

x = -4

The solution of the linear equation 2(x + 2) – 4x = 12 will be negative 4.

The distribution of weights to the variables involved that establishes the equilibrium in the calculation is referred to as a result.

A relationship between two or more parameters that, when shown on a graph, produces a linear model. The degree of the variable will be one.

The linear equation is given below.

2(x + 2) - 4x = 12

Solve for x in the equation 2(x + 2) - 4x = 12. Then we have

2(x + 2) - 4x = 12

2x + 4 - 4x = 12

-2x = 12 - 4

-2x = 8

x = -8/2

x = -4

The solution of the linear equation 2(x + 2) – 4x = 12 will be negative 4.

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Answer:

(-10, -8) and (-6, -4)

Step-by-step explanation:

we know that

The diagonals of a rhombus are perpendicular

If two lines are perpendicular, then the product of their slopes is equal to -1

m1*m2=-1

step 1

Find the slope of the given diagonal

we have

(-11, -9) and (-5, -3)

m=(-3+9)/(-5+11)

m=-6/6=-1

Find the slope of the other diagonal

we have

m1=-1

Find m2

m1*m2=-1

(-1)*m2=-1

m2=1

step 2

Verify the slope of each of the endpoints of the other diagonal

The slope of the other diagonal must be equal to 1

so

case a) (-10, -4) and (-6, -8)

m=(-8+4)/(-6+10)

m=-4/4=-1

therefore

The points of case a) cannot be the end-points of the other diagonal

case b) (-8, -3) and (-5, -6)

m=(-6+3)/(-5+8)

m=-3/3=-1

therefore

The points of case b) cannot be the end-points of the other diagonal

case c) (-8, -4) and (-8, -8)

m=(-8+4)/(-8+8)

m=-4/0 -----> undefined

therefore

The points of case c) cannot be the end-points of the other diagonal

case d) (-10, -8) and (-6, -4)

m=(-4+8)/(-6+10)

m=4/4=1

therefore

The points of case d) can be the end-points of the other diagonal

Answer:

A) -sqrt(3)/3

Step-by-step explanation:

If you know your unit circle (attached), 11pi/6 has the value of (sqrt(3)/2,-1/2), where the coords are (cosine, sine).

Tangent is sine/cosine:

(-1/2)/(sqrt(3)/2)

We can convert this to multiplication by miltiplying the reciprocal of sqrt(3)/2:

(-1/2)*(2/sqrt(3))

Multiplied out to:

-2/(2sqrt(3))

We have to rationalize this by multiplying the numerator and denominator by sqrt(3):

-2(sqrt(3))/2sqrt(3)(sqrt(3)

two of the same square roots multiplied together equals the number without the sqrt:

-2(sqrt(3))/2*3

we can factor out 2 from the numerator and denominator:

-sqrt(3)/3

Therefore, the answer is A

Answer:

Since the money appreciates 4.2% each year, then:

2000=1600x(1.042)^n, where n is the number of years

Then:

1.25=1.042^n

ln 1.25=ln 1.042^n=n ln 1.042

n=5.424 years

Cate's $1600 stock investment, growing at 4.2% annually, will take approximately 5.21 years to reach a value of about $2000.

Given that Cate purchases $1600 worth of stock with an estimated increase in value by 4.2% each year, we are looking to find out after how many years the value will be about $2000. To determine this, we can use the formula for exponential growth, P = P_0 (1 + r)^t, where P is the future value, P_0 is the initial value, r is the rate of increase, and t is the time in years.

Cate's initial investment is $1600 (P_0), and we aim for a future value of $2000 (P). The annual growth rate r is 4.2%, or 0.042 when expressed as a decimal. Plugging these values into the formula and solving for t gives us:

So, it will take approximately 5.21 years for Cate's investment to reach a value of about $2000, assuming a steady 4.2% growth rate.

Answer:

The maximum number of hours that can rent the canoe is 2 hours

Step-by-step explanation:

Let

h ----> the number of hours you can rent the canoe

we know that

The inequality that represent this situation is

[tex]14.5+6h\leq 32[/tex]

Solve for h

Subtract 14.5 both sides

[tex]6h\leq 32-14.5[/tex]

[tex]6h\leq 17.5[/tex]

Divide by 6 both sides

[tex]h\leq 17.5/6[/tex]

[tex]h\leq 2.9\ hours[/tex]

The maximum number of hours that can rent the canoe is 2 hours

The equation that represents the number of hours you can rent the canoe is h = ($32.50-$14.50)/$6.

The subject of this question is Mathematics and it appears suitable for a Middle School level. Given the scenario you presented, we will need to create a linear equation to determine the number of hours of canoe rental. In this case, the $14.50 is a fixed cost, like the $31.50 in one of your examples. Additionally, the $6 per hour to use the canoe is a variable cost. To create an equation that represents the amount of hours you can rent the canoe, we first deduct the fixed cost from your total budget. This gives you $32.50 - $14.50 = $18 left to work with. Each hour of canoe use costs $6, so we divide the remaining amount by 6 to find how many hours (h) you can rent the canoe. This gives us the equation, h = ($32.50-$14.50)/$6.

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