Approximately how many times greater is 9.75×106 than 1.25×102 ? 7.8 7800 78,000 780,000

Since ∠E and ∠F are vertical angles, they are congruent, meaning that m∠E = m∠F

Plugging in the equations that were originally given, we can form the equation 9x + 12 = 3x + 24

Subtract both sides of the equation by 3x

6x + 12 = 24

Subtract 12 from both sides

6x = 12

Divide both sides by 6

x = 2

This should be your answer. Have an awesome day! :)

Answer:

Landon makes $10.5 per hour at babysitting and $7.75 per hour at water park.

Step-by-step explanation:

Let the amount made per hour in dollars for babysitting be = x

Let the amount made per hour in dollars at water park be = y

As per the condition, the equations form:

[tex]3x+10y=109[/tex]     .......(1)

[tex]8x+12y=177[/tex]     ......(2)

Multiplying (1) by 8 and (2) by 3, and subtracting (2) from (1), we get

[tex]44y=341[/tex]

=> y = 7.75

And [tex]3x+10(7.75)=109[/tex]

=> [tex]3x+77.5=109[/tex]

=> [tex]3x=109-77.5[/tex]

=> [tex]3x=31.5[/tex]

x = 10.5

Therefore, Landon makes $10.5 per hour at babysitting and $7.75 per hour at water park.

Probability measures to determine the possibility of an event. In this case, the events are cars with no 4 wheels and cars with third row seats.

The probability that a randomly selected car with no 4-wheel drive has third row seats is 0.3

Let:

[tex]A \to[/tex] A car with no 4-wheel drive

[tex]B \to[/tex] A car that has third row seats

The probability that a randomly selected car with no 4-wheel drive has third row seats is represented as:

[tex]P(B|A)= \frac{n(A\ n\ B)}{n(A)}[/tex]

From the 2-way table, we have the following parameters:

[tex]n(A\ n\ B) = 12[/tex]

[tex]n(A) = 40[/tex]

So, the probability is:

[tex]P(B|A)= \frac{n(A\ n\ B)}{n(A)}[/tex]

[tex]P(B|A)= \frac{12}{40}[/tex]

[tex]P(B|A)= 0.3[/tex]

Hence, the probability that a randomly selected car with no 4-wheel drive has third row seats is 0.3

Read more about probability at:

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Final answer:

The direct variation equation relating Lee's pay (x) to the hours worked (y) is y = 7.60x. Lee's pay for working 25 hours in a week is $190.

Explanation:

Let's define the direct variation equation:

y = kx

We can substitute the information given in the question:
When x = 6.5, y = 49.40
49.40 = 6.5k
k = 49.40 / 6.5
k = 7.60

Therefore, the direct variation equation relating Lee's pay (x) to the hours worked (y) is y = 7.60x.

To find Lee's pay if she works 25 hours, we can substitute x = 25 into the equation:
y = 7.60(25)
y = 190

Lee's pay for working 25 hours in a week is $190.

Answer:

You bring home $14.25 with you.

Step-by-step explanation:

First we add the money spent in movie tickets and snacks.

Your ticket = $7.25

Brother's ticket = $4.25

Sister's ticket = $4.25

Soda and popcorn = $20.00

Total = 7.25 + 4.25 + 4.25 + 20.00 = $35.75

Your parents gave you = $50.00

You spent = $35.75

Balance = 50.00 - 35.75 = $14.25

You bring home $14.25 with you.

The volume of the cone is one-third of the volume of the cylinder which is equal to the product of area of the base and the height. The equation is,

    V = (1/3)(pi)(r^2)h         

Dividing both sides of the equation by (1/3)(pi)(h) will give us,

  3V/(pi)(h) = r^2

Taking the square-root of both sides,

  r = sqrt(3V/(pi)(h))

Answer:

[tex]r = \sqrt{\displaystyle\frac{3V}{h\pi}}[/tex]

Step-by-step explanation:

We are given the following information in the question.

Using the formula for volume of cone, we have to express r in terms of V, h and pi.

Formula:

[tex]\text{Volume of cone, V} = \displaystyle\frac{1}{3}\pi r^2 h\\\\\text{where r is the radius of cone, h is the height of radius}[/tex]

Now, we have to evaluate r, the radius of cone.

Rearranging the terms, we have,

Working:

[tex]V = \displaystyle\frac{1}{3}\pi r^2 h\\\\r^2 = \frac{3\times V}{\pi\times h}\\\\r^2 = \frac{3V}{h\pi}\\\\r = \sqrt{\frac{3V}{h\pi}}[/tex].

Thus, r in form of V, h and pi can be written as:

[tex]r = \sqrt{\displaystyle\frac{3V}{h\pi}}[/tex]

A. how many minutes will it take the machine to use all the dough?

We are given the formula:

d (m) = - 5 m + 320

To find for the value of m when all dough is used, we set d (m) = 0:

0 = - 5  m + 320

m = 320 / 5

m = 64 minutes

B. The domain is time and time can never be negative so it always starts at zero, so at time = 0, the range d (m) is:

d (m) = - 5 (0) + 320

d (m) = 320

The other domain and range is already described in (A.), when all dough is used up.

So the pair of reasonable domain and range is:

(0, 320), (64, 0)

The question involves a mathematical trick to determine the location of a penny based on the parity of a sum and a take-home experiment on the balancing of pennies and torque. Additionally, it touches upon probability in the context of half-life and independent probabilities.

In the trick described, you are presenting a simple mathematical puzzle to determine the location of a penny based on the parity of the sum of two numbers. This is an application of basic arithmetic operations and the concept of even and odd numbers. However, for the take-home experiment involving balancing pennies on a ruler, this is related to physics and moment of force (torque). In this experiment, to balance one penny placed 8 cm away from the pivot, you would need to find a position where the total torque caused by the two or three pennies counterbalances the torque caused by the single penny. This involves understanding the principles of levers and torque.

the half-life coin activity mentioned in the question is an example of using probability to model physical phenomena, specifically radioactive decay. It explores independent probabilities when flipping coins multiple times.

These experiments and demonstrations help to illustrate various scientific and mathematical concepts using coins, which are familiar objects, making them more approachable and relatable to students.

For the given equation 6eˣ-4e⁻ˣ=5 the value obtained after solving the equation will be x =0.29.

It is defined as a function that rapidly increases and the value of the exponential function is always positive. It denotes with exponent y = a^x, where a is a constant and a>1

It is given that,

6eˣ-4e⁻ˣ=5

Multiplying complete equation by eˣ

eˣ(6eˣ-4e⁻ˣ)=5(eˣ)

6(eˣ)(eˣ) - 4(e⁻ˣ)(eˣ) =5(eˣ)

6e²ˣ-4 = 5(eˣ)

6e²ˣ-5eˣ -4 = 0

Suppose y = eˣ

6y² - 5y -4 = 0

After solving the equation we get y = 4/3 and y = -1 / 2.As a result,

eˣ = 4/3  

x = log(4/3)

x = 0.29

Thus, for the given equation 6eˣ-4e⁻ˣ=5 the value obtained after solving the equation will be x =0.29.

Learn more about the exponential function here:

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Answer:

#1) d. ΔJKL is not a right triangle because no two of its sides are perpendicular; #2) -1/3, 3, -7, is, two of these slopes have a product of -1; #3) a. Quadrilateral DEFG is a rhombus because opposite sides are parallel and all four sides have the same length; #4) 1, -1/6, 1, -2/5, is not, only one pair of opposite sides is parallel; #5) c. Quadrilateral PQRS is not a rectangle because it has only one right angle.

Step-by-step explanation:

#1) The slope of any line segment is found using the formula

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

For JK, this gives us (1-1)/(-5-0) = 0/-5 = 0.  For KL this gives us (1--5)/(0-2) = 6/-2 = -3.  For LJ this gives us (-5-1)/(2--5) = -6/7.  None of these slopes are negative reciprocals, so none of the angles are right angles and this is not a right triangle.

#2) The slope of JK is (2-1)/(0-3) = 1/-3 = -1/3.  The slope of KL is (1--5)/(3-1) = 6/2 = 3.  The slope of LJ is (2--5)/(0-1) = 7/-1 = -7.  Two of these slopes have a product of -1, 3 and -1/3.  This means they are negative reciprocals so this has a right angle; this means JKL is a right triangle.

#3) The slope of DE is (5-4)/(-2-2) = 1/-4 = -1/4.  The slope of EF is (4-0)/(2-0) = 4/2 = 2.  The slope of FG is (0-1)/(0--4) = -1/4.  The slope  of GD is (1-5)/(-4--2) = -4/-2 = 2.  Opposite sides have the same slope so they are parallel.

Next we use the distance formula to find the length of each side:

[tex]d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}[/tex]

Using our points, the length of DE is

[tex]\sqrt{(5-4)^2+(-2-2)^2}=\sqrt{1^2+(-4)^2}=\sqrt{1+16}=\sqrt{17}[/tex]

The length of EF is

[tex]d=\sqrt{(4-0)^2+(2-0)^2}=\sqrt{4^2+2^2}=\sqrt{16+4}=\sqrt{20}[/tex]

The length of FG is

[tex]d=\sqrt{(0-1)^2+(0--4)^2}=\sqrt{(-1)^2+(4)^2}=\sqrt{1+16}=\sqrt{17}[/tex]

The length of GD is

[tex]d=\sqrt{(1-5)^2+(-4--2)^2}=\sqrt{(-4)^2+(-2)^2}=\sqrt{16+4}=\sqrt{20}[/tex]

Opposite sides have the same length and are parallel, so this is a parallelogram.

#4) The slope of AB is (-1-2)/(-4--1) = -3/-3 = 1.  The slope of BC is (2-1)/(-1-5) = 1/-6 = -1/6.  The slope of CD is (1--3)/(5-1) = 4/4 = 1.  The slope of DA is (-3--1)/(1--4) = -2/5.  Only one pair of opposite sides is parallel, so this is not a parallelogram.

#5) The slope of PQ is (2-4)/(-4-3) = -2/-7 = 2/7.  The slope of QR is (4-0)/(3-5) = 4/-2 = -2.  The slope of RS is (0--2)/(5--3) = 2/8 = 1/4.  The slope of SP is (-2-2)/(-3--4) = -4/1 = -4.  Only one pair of sides has slopes that are negative reciprocals; this means this figure only has 1 right angle, so it is not a rectangle.

The answers provided for ΔJKL, ΔJKL as a right triangle, and quadrilateral ABCD are correct. For quadrilateral DEFG, the answer may be correct depending on side lengths, and for quadrilateral PQRS, slopes must be calculated to determine if it's a rectangle.

To determine whether the given shapes are right triangles, rhombuses, rectangles, or parallelograms, we use properties such as the slopes of lines to check for perpendicularity, parallelism, and equal lengths.

For ΔJKL with vertices J(-5, -1), K(0, 1), L(2, -5), you calculated it's not a right triangle because none of the slopes of the sides are negative reciprocals of each other (indicating perpendicular sides). This is correct; no slopes have a product of -1, so answer (d) is correct.

In the second case, ΔJKL with vertices J(0, 2), K(3, 1), L(1, -5) has slopes -1/3, 3, and -7 for sides JK, KL, and JL respectively. Since -1/3 and 3 are negative reciprocals, ΔJKL is a right triangle due to the perpendicular sides JK and KL. So, the filled answers are correct.

Regarding quadrilateral DEFG, you might want to reconsider option (b), as you cannot determine whether it's a rhombus solely based on one pair of opposite sides being parallel. Instead, check if all sides have the same length using the distance formula, and if the opposite sides are parallel by comparing slopes. Since you didn't provide the side lengths, I will only address the slopes here, which you've noted. Answer (b) can be correct if the side lengths are not equal, but if they are, it should be (c).

For quadrilateral ABCD, your assessment of the slopes leads to the conclusion that it is not a parallelogram, which is correct as only one pair of opposite sides (AB and CD having a slope of 1) is parallel. The filled answers are appropriate.

Last, for quadrilateral PQRS, you must calculate the slopes of the sides to determine if the sides are perpendicular to each other by checking if the products of the corresponding slopes are -1. If the slopes of adjacent sides are negative reciprocals of each other, then PQRS has right angles, and it could be a rectangle. Calculate the slopes, and if none are negative reciprocals, then answer (d) is correct stating that PQRS is not a rectangle because it has no right angles.

Answer:

24 unit

Step-by-step explanation:

Given,

The vertices of the triangle ABC are,

A (1,1), B (7,1), and C (1,9),

By the distance formula,

[tex]AB=\sqrt{(7-1)^2+(1-1)^2}=\sqrt{6^2}=6\text{ unit}[/tex]

[tex]BC=\sqrt{(1-7)^2+(9-1)^2}=\sqrt{6^2+8^2}=\sqrt{36+64}=\sqrt{100}=10\text{ unit}[/tex]

[tex]CA=\sqrt{(1-1)^2+(1-9)^2}=\sqrt{8^2}=8\text{ unit}[/tex]

Thus, the perimeter of the triangle ABC = AB + BC + CA = 6 + 10 + 8 = 24 unit

A. Let us say that:

s = number of small containers

m = number of medium containers

From the given data, the total volume of soup is:

total soup = 4 ounces * 6 + 6 ounces * 10 = 84 ounces

So the equation is:

4s + 6m = 84

B. We rewrite the equation explicit to one variable, here we choose s:

4s = 84 – 6m

s = 21 – 1.5m

Then we assign several values for m starting at 0 to get the corresponding value of s then plot the graph. See the graph attached.

C. From the graph, we choose the pair of s and m that are whole numbers. The four possible combinations are:

21 small containers, 0 medium containers

15 small containers, 4 medium containers

9 small containers, 8 medium containers

3 small containers, 12 medium containers