ANSWER TRUE OR FALSE: longer days in the summer help to make summer warmer

Answer:

A) They have the same kinetic energies, but different momenta.

Explanation:

Before answering, let's remind that:

- Kinetic energy is a scalar quantity, which is given by:

[tex]K=\frac{1}{2}mv^2[/tex]

where m is the mass of the object and v is the speed.

- Momentum is a vector quantity, whose magnitude is given by:

[tex]p=mv[/tex]

where m is the mass of the object and v is the velocity, and whose direction is the same as the velocity.

By looking at the two definitions, we can say that:

- the two cars have same kinetic energy, because they have same mass and same speed

- The two cars have different momenta, because they do not have same velocity (in fact, their directions are different, since one is heading east and the other one is heading north)

The identical cars traveling at the same speed will have the same kinetic energies, but different momenta because momentum is a vector quantity dependent on direction.

The correct answer would be A) They have the same kinetic energies, but different momenta.

The two identical cars traveling at the same speed will have identical kinetic energies since kinetic energy depends only on mass and speed. The kinetic energy (KE) of an object can be calculated using the formula KE=1/2mv², where m is the mass and v is the speed of the object. Therefore, since the cars are identical and moving at the same speed, their kinetic energies will be the same.

However, their momenta will be different because momentum is a vector quantity, meaning direction matters. The formula for momentum is p=mv, where m is mass and v is velocity (speed in a given direction). Since one car is going east and the other is going north, their momenta are in different directions, hence, their momenta are different.

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Given in the question,

mass of foul ball = 0.140 kg

initial speed with which ball was hit with the bat = 30 m/s

final speed  = 40 m/s

According to the scenario the whole scene is making a right angle triangle

So, to the solve the question we will use pythagorus theorem

Here,

Hypotenuse= Magnitude of impulse

Base = 1st change of momentum

height = 2nd change of momentum

1st impulse (1st change of momentum)

p = m(1)v(1) = (0.14 kg)(40.0 m/s) = 5.6 kg m / s = 5.6 N s

2nd impulse (2nd change of momentum)

p = m(2)v(2) = (0.14 kg)(30.0 m/s) = 4.2 kg m / s = 4.2 N s

Magnitude of impulse (hypotenuse of triangle)

impulse² = (5.6)² + (4.2)²

impulse² = 31.36 + 17.64

impulse² = 49

impulse² = √49

impulse = 7.0 N s

The magnitude of the impulse delivered to the baseball by applying the impulse-momentum theorem is calculated to be 9.8 kg.m/s.

The magnitude of the impulse delivered to the baseball can be found by applying the impulse-momentum theorem. The theorem asserts that the change in momentum of an object equals the impulse imposed on it. In the context of this question, the momentum change is the final momentum minus the initial one (m*(vf) - m*(vi)). This equals 0.140 Kg * 30.0 m/s - (-0.140 Kg * 40.0 m/s). Calculating this we get 9.8 kg.m/s as the magnitude of the impulse delivered to the baseball.

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Answer:

[tex]3.2\cdot 10^{-8} N[/tex]

Explanation:

The inital electrostatic force between the two spheres is given by:

[tex]F=k\frac{q_1 q_2}{r^2}[/tex]

where

[tex]F=8\cdot 10^{-9} N[/tex] is the initial force

k is the Coulomb's constant

q1 and q2 are the charges on the two spheres

r is the distance between the two spheres

The problem tells us that the two spheres are moved from a distance of r=20 cm to a distance of r'=10 cm. So we have

[tex]r'=\frac{r}{2}[/tex]

Therefore, the new electrostatic force will be

[tex]F'=k\frac{q_1 q_2}{(r')^2}=k\frac{q_1 q_2}{(r/2)^2}=4k\frac{q_1 q_2}{r^2}=4F[/tex]

So the force has increased by a factor 4. By using [tex]F=8\cdot 10^{-9} N[/tex], we find

[tex]F'=4(8\cdot 10^{-9} N)=3.2\cdot 10^{-8} N[/tex]

The force of attraction between the soheres when they are 10cm apart is 3.2 * 10^-8 N

This is the force pulling bodies together given by  

the force of attration, F = ( G q1 q2 ) / d^2

G refera to constant of attraction

q1 and q2 is the charges of the objects

d is the distance between the objects

G q1 q2 are all constant with respect to this question

let K = G * q1 * q2

F = k / d^2

for d = 20 cm = 0.2 m

F20 = k / 0.2^2

8*10^-9 = k / 0.2^2

K = 8*10^-9 *0.2^2

K = 3.2*10^-10

for d = 10 cm = 0.1 m

F10 = K / d^2

= (3.2*10^-10) * 0.1^2

= 3.2*10^-8 N

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In Burglar alarm, LDR acts an AND gate.

Answer: C

Explanation

The LDR is light dependent resistor. The principle used in the working of LDR is that the resistance is inversely proportional to the intensity of light falling on the diode.

In burglar alarm, LDR diode is combined with an IC 555.

Normally an LED source is made to be incident on the LDR diode with same intensity such that the resistance will be maintained constant.

As the LDR is connected with IC, the voltage will be high when light is falling on the diode.

The IC will give only two output states that is high and low. This confirms that LDR in burglar alarm act as AND gate.

As the thief enters and crosses the LED light, the intensity of the light falling on the diode will decrease leading to decrease in the voltage which will cause the alarm to beep.

In a Burglar alarm, LDR acts as an AND gate. Option C is correct. This is further explained below.

Generally, an alarm is simply defined as a danger signal, generally in the form of loud noise or flashing light: If there's a problem, pull the safety cord to sound the alarm.

In conclusion, LDR serves as an AND gate in a security alarm.

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You can increase the capacitance of a capacitor by decreasing the plate spacing (A) or by increasing the area of the plates (D).

'A' and 'D' both do the job, so the correct choice is (E) .

Capacitance is the effect of a capacitor. We can increase the capacitance of the capacitor by decreasing the plate spacing and by increasing the area of the plates.

The capacitance is the effect of a capacitor, while a capacitor is a device that stores the electrical energy into it. The energy stored in a capacitor can be calculated by the formula,

[tex]U = \dfrac{1 \times Q^2}{2 \times C} = \dfrac{1 \times Q}{2 \times V} = \dfrac{1}{2}CV^2[/tex]

The following things affect the capacitance of a capacitor:

Thus, We can increase the capacitance of the capacitor by decreasing the plate spacing and by increasing the area of the plates.

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Answer:

6.14 m

Explanation:

The motion of the object is divided into three parts:

- Part 1: the object moves with speed

v = +0.9 m/s (the positive sign means positive x-direction)

for t = 3.6 s

Therefore, the distance covered is

[tex]d_1 =vt=(0.9 m/s)(3.6 s)=3.24 m[/tex]

- Part 2: the object stops for 4.7 s, so during this time the distance travelled by the object is zero.

- Part 3: the object moves with speed

v = -1 m/s (negative sign means negative x-direction)

for a time of

t = 2.9 s

We are only concerned in the distance travelled, so we can ignore the negative sign, and the distance covered in this part is

[tex]d_3 = vt=(1 m/s)(2.9 s)=2.90 m[/tex]

So, the total distance covered is

[tex]d=d_1+d_2+d_3=3.24 m+0 +2.90 m=6.14 m[/tex]

Curve of space time

Newton believed that time and space are absolute, while Einstein believed that the speed of light is absolute.

Answer:

[tex]1.88\cdot 10^{-5} A[/tex]

Explanation:

The capacitance of a parallel plate capacitor is given by:

[tex]C=\frac{\epsilon_0 A}{d}[/tex] (1)

where

[tex]\epsilon_0[/tex] is the vacuum permittivity

A is the area of the plates

d is the separation between the plates

The charge stored on the capacitor is given by

[tex]Q=CV[/tex] (2)

where C is the capacitance and V is the voltage across the capacitor.

The displacement current in the capacitor is given by

[tex]J=\frac{Q}{t}[/tex] (3)

where t is the time elapsed

Substituting (1) and (2) into (3), we find an expression for the displacement current:

[tex]J=\frac{CV}{t}=\frac{\epsilon_0 A}{d} \frac{V}{t}[/tex]

where we have

[tex]A=\pi (\frac{d}{2})^2=\pi (\frac{0.056 m}{2})^2=2.46\cdot 10^{-3} m^2[/tex]

[tex]d = 0.58 mm = 5.8\cdot 10^{-4} m[/tex]

[tex]\frac{V}{t}=500,000 V/s[/tex]

Substituting into the equation, we find

[tex]J=\frac{(8.85\cdot 10^{-12} F/m)(2.46\cdot 10^{-3} m^2)}{5.8\cdot 10^{-4}m}(500,000 V/s)=1.88\cdot 10^{-5} A[/tex]

The displacement current in the parallel-plate capacitor is approximately 0.024 A.

The displacement current in the capacitor can be calculated using the formula I = ε₀A(dV/dt), where ε₀ is the permittivity of free space, A is the area of the plates, and dV/dt is the rate of change of potential difference.

Given that the diameter of the capacitor is 5.6 cm, we can calculate the radius (r) by dividing the diameter by 2. The area (A) of the plates is then πr².

Plugging in the given values and solving for I, we get:

I = (8.85×10⁻¹² F/m)(π(0.028 m)²)(500,000 V/s)

I ≈ 0.024 A

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Answer:

Alpha particle

Explanation:

Initially, the particle moves in a straight line. This means that the electric force and the magnetic force are equal:

[tex]qE=qvB[/tex]

where q is the charge, E is the electric field, v is the speed and B is the magnetic field.

In this problem,

E = 1.5 kV/m = 1500 V/m

B = 0.034 T

Solving the equation for v we find the speed of the particle

[tex]v=\frac{E}{B}=\frac{1500 V/m}{0.034 T}=4.41\cdot 10^4 m/s[/tex]

Now the electric field is turned off, so the particle starts moving in a circular motion, where the magnetic force acts as centripetal force:

[tex]qvB=m\frac{v^2}{r}[/tex]

where

r = 2.7 cm = 0.027 m is the radius of the circular path

Solving the problem for q/m, we find charge-to-mass ratio of the particle

[tex]\frac{q}{m}=\frac{v}{Br}=\frac{4.41\cdot 10^4 m/s}{(0.034 T)(0.027 m)}=4.8\cdot 10^7 C/kg[/tex]

And this corresponds to the q/m ratio of an alpha particle, which has:

[tex]q=2e=3.2\cdot 10^{-19}C\\m=4a.m.u.=6.64\cdot 10^{-27} kg[/tex]

The mass of the particle depends on the type of particle, and the radius of

the path of the particle depend on its mass.

The particle might be an alpha particle.

Reasons:

The given parameters are;

Electric potential of the field, E = 1.5 kV/m

Magnetic field strength, B = 0.034 T

Radius of the circular path, r = 2.7 cm

Required:

Finding the type of particle in the question

Solution:

When moving in a straight line, we have;

B·q·v = F = q·E

Therefore;

E = B·v

When the particle moves in a circular path, we have;

[tex]q\cdot E = B \cdot q \cdot v = \mathbf{\dfrac{m \cdot v^2}{r}}[/tex]

Therefore;

[tex]v = \dfrac{B \cdot q \cdot r }{m}[/tex]

Which gives;

[tex]E = \dfrac{B \cdot q \cdot r }{m} \times B = \dfrac{B^2 \cdot q \cdot r }{m}[/tex]

[tex]\mathrm{The \ mass \ of \ the \ particle, \, m} = \mathbf{\dfrac{B^2 \cdot q \cdot r }{E}}[/tex]

q = n × e

Therefore;

[tex]m = \mathbf{\dfrac{B^2 \cdot n \cdot e \cdot r }{E}}[/tex]

Where;

n = The number of electron charge

Which gives the mass in kilograms as follows;

[tex]m = \dfrac{0.034^2 \times n\times 1.6 \times 10^{-19} \times 0.027 }{1500} = \mathbf{3.32928 \times 10^{-27} \times n}[/tex]

The particle is larger than a subatomic particle

Therefore;

[tex]\dfrac{m}{n} = 3.32928 \times 10^{-27}[/tex]

For an alpha particle, we have;

m ≈ 6.645 × 10⁻²⁷ kg

n = 2

n = 2

Therefore;

[tex]\dfrac{6.645 \times 10^{-27}}{2} \approx \mathbf{3.3225 \times 10^{-27}} \approx 3.32928 \times 10^{-27}[/tex]

Therefore, the particle might be an alpha particle.

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A simple machine can make work easier by reduce the amount of energy needed to perform a task, therefore, B. it magnifies the potential energy so that the kinetic energy is greater is the correct answer:)

Low specific heat in the material

This is a question that makes us REALLY want to know what "Which" means.

If you included a list of answer choices with your question, then the correct formula isn't on it.

The formula for converting temperature from degrees Celsius to degrees Fahrenheit is:

°F  =  1.8 · (°C) + 32

Explanation:

The two scales for measuring the temperature of an object are Celsius scale and Fahrenheit scale. Mathematically, it can be written as :

[tex]^{\circ} F=(\dfrac{9}{5}\times ^{\circ}C)+32[/tex]

Where

°F = degree Fahrenheit

°C = degree Celsius

For example, if T = 30°C. It can be converted to °F as :

[tex]^{\circ} F=(\dfrac{9}{5}\times 30)+32[/tex]

[tex]^{\circ} F=86[/tex]

So, 30°C is equal to 86 Fahrenheit. Hence, this is the required solution.

Answer: 0.129 moles of gas were added to the bottle

Explanation:

According to the ideal gas equation:'

[tex]PV=nRT[/tex]

P = Pressure of the gas

V= Volume of the gas

T= Temperature of the gas

R= Gas constant

n=  moles of gas

As Volume , gas constant and temperature are constant

[tex]\frac{P_1}{n_1}=\frac{P_2}{n _2}[/tex]

where,

[tex]P_1[/tex] = initial pressure of gas =730 mm Hg =0.960 atm (760 mmHg = 1 atm)

[tex]P_2[/tex] = final pressure of gas = 1.15 atm

[tex]n_1[/tex] = initial number of moles = 0.650

[tex]n_2[/tex] = final number of moles =  ?

Now put all the given values in the above equation, we get the final moles of gas.

[tex]\frac{0.960}{0.650}=\frac{1.15}{n_2}[/tex]

[tex]n_2=0.779[/tex]

Therefore, the number of moles of gas will be 0.779

Thus moles of gas were added to the bottle are (0.779-0.650) = 0.129

Final answer:

To determine how many moles of gas were added to the gas bottle, we used the Ideal Gas Law relation between pressure and moles, converting pressures to the same units and found approximately 0.129 moles were added.

Explanation:

To determine how many moles of gas were added to the bottle, we can use the Ideal Gas Law: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. Since the volume and temperature of the gas are constant (not mentioned in the problem, so assumed constant), the relationship between pressure and moles of gas is a direct one. This means that by dividing the final pressure by the initial pressure, we should get the ratio of the final moles to the initial moles.

Firstly, we need to make sure pressure units are consistent. We convert the initial pressure from mm Hg to atm: 730 mm Hg × (1 atm / 760 mm Hg) = 0.9605 atm.

Now, we use the ratio of the pressures to find out the number of moles after additional gas was added:

Initial moles (ni) = 0.650 mol at Pi = 0.9605 atm

Final pressure (Pf) = 1.15 atm

Ratio of pressures = Pf / Pi = 1.15 atm / 0.9605 atm

Final moles (nf) = ni × (Pf / Pi)

nf = 0.650 mol × (1.15 / 0.9605)

nf ≈ 0.779 moles

The amount of moles added can be found by subtracting the initial moles from the final moles:

n added = nf - ni

n added = 0.779 mol - 0.650 mol

n added ≈ 0.129 moles

The correct answer is electrically charged.

When an object gains or loses electrons, it becomes electrically charged because it acquires an imbalance of positive and negative charges.

Explanation:

- Atoms are made up of positively charged protons in the nucleus and negatively charged electrons orbiting the nucleus.

- In a neutral atom, the number of protons and electrons are equal, resulting in an overall neutral charge.

- If an atom gains or loses electrons, it disrupts the balance of positive and negative charges, resulting in an electrically charged state.

- If an atom loses electrons, it becomes positively charged because it has more protons than electrons.

- If an atom gains electrons, it becomes negatively charged because it has more electrons than protons.

The other options are incorrect:

B) Electrically neutral: This option is incorrect because gaining or losing electrons causes an object to become electrically charged, not neutral.

C) Magnetically neutral: This option is incorrect because it refers to magnetic properties, not electric charges.

D) Magnetically polarized: This option is incorrect because it refers to magnetic properties, not electric charges.

Therefore, when an object gains or loses electrons, it becomes electrically charged due to the imbalance of positive and negative charges.

Complete question:

When an object gains or loses electrons, it becomes

A) electrically charged.

B) electrically neutral.

C) magnetically neutral.

D) magnetically polarized.

Metals are both good heat conductors and good electrical conductors because of the looseness of outer electrons in metal atoms

_________________________

Unlike nonmetals that are insulators, most metals are both good heat conductors and good electrical conductors. This is because within a solid metal there is one or more outer electrons in each atom that become detached and can move freely through the solid metal, but what about the other electrons?  Well, the y remain bound to the positively charged nuclei, and bound within the material in almost fixed positions. On the other hand, insulators are material having few, very few or no electrons that are allowed to move freely through  the material.

Answer:

looseness of outer electrons in metal atoms

Explanation:

Unlike in insulators the valance electrons in metals are free to roam inside the boundaries of the metal slab. These electrons are called free electrons.

These electrons are free to move because there is no gab between their valance band and conduction band.

Since they are free to move they can transfer charges easily and be a good conductor.

Also heat exchange takes place when one electron collides with another moving electron or a stationary atom.

This is why metals are both good heat conductors and good electrical conductors.

Sound wave requires a physical medium to travel.

       Waves below 20 Hz are called infrasonic waves (infrasound), while         higher frequencies above 20,000 Hz are known as ultrasonic waves (ultrasound).

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Water pipes burst because the water inside them expands is it gets close to freezing, and this causes an increase in pressure inside the pipe. When the pressure gets too high for the pipe to contain, it ruptures.

Water pipes can break in freezing weather when the water inside them expands and creates pressure. Different pipe materials have different coefficients of thermal expansion, affecting their susceptibility to breaking.

When water pipes freeze, the water inside them expands as it turns into ice. This expansion creates pressure on the walls of the pipe, which can cause it to crack or burst. The pressure is typically highest towards the closed faucet or valve, as the ice formation blocks water from flowing out.

The materials used to make the pipes also play a role in their susceptibility to breaking. Different materials have different coefficients of thermal expansion, which determines how much they expand or contract with temperature changes. Some materials, like Pyrex®, have a small coefficient of thermal expansion and are less likely to break.

It's important to note that freezing temperatures alone may not immediately cause the pipes to break. However, if the frozen water remains in the pipe for an extended period and the outside temperature remains cold, the expanding ice can eventually lead to pipe failure.

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Answer:

Visible light

X rays

ultraviolet radiation

gamma rays

microwave radiation

Explanation:

Electromagnetic waves consist of oscillating electric and magnetic fields which vibrate in a direction perpendicular to the direction of motion of the wave (transverse wave). Electromagnetic waves have all same speed in a vacuum ([tex]c=3.0\cdot 10^8 m/s[/tex], known as speed of light) and are classified into 7 different types according to their frequency and wavelength. This classification is called electromagnetic spectrum.

From lowest to highest wavelength, the 7 types are:

Gamma rays

X-rays

Ultraviolet radiation

Visible light

Infrared radiation

Microwaves

Radio waves

Sound waves, on the contrary, do not belong to the electromagnetic spectrum, since they are another type of wave called mechanical waves (which consist of vibrations of the particles in a medium).

When your in the mountains or in a quiet room

Answer:

Explained

Explanation:

The necessary condition for an echo to occur are

1) The distance between the sound source and the object of reflection must be equal to or greater than 17 meters.

2) the time period between hearing the original sound and the echo must not be less than 0.1 second, because human ear is not that sensitive to distinguish between two sounds within a gap of time less than 0.1 second.

Answer:

4.4 kHz

Explanation:

The frequency of the beats is given by the frequency of the original ultrasound, [tex]f=41.2 kHz[/tex], and the frequency of the ultrasound reflected back from the car, [tex]f'[/tex]:

[tex]f_B = f'-f[/tex] (1)

The frequency of the reflected wave can be found by using the Doppler effect formula:

[tex]f'=\frac{v}{v-v_s}f[/tex]

where

v = 340 m/s is the speed of sound

[tex]v_s =33.0 m/s[/tex] is the speed of the car

[tex]f=41.2 kHz[/tex] is the frequency of the original sound

Substituting,

[tex]f'=\frac{340 m/s}{340 m/s-33.0 m/s}(41.2 kHz)=45.6 kHz[/tex]

So, the beat frequency (1) is

[tex]f_B = 45.6 kHz - 41.2 kHz=4.4 kHz[/tex]

The frequency of the beats is about 9.2 kHz

[tex]\texttt{ }[/tex]

Let's recall the Doppler Effect formula as follows:

[tex]\boxed {f' = \frac{v + v_o}{v - v_s} f}[/tex]

f' = observed frequency

f = actual frequency

v = speed of sound waves

v_o = velocity of the observer

v_s = velocity of the source

Let's tackle the problem!

[tex]\texttt{ }[/tex]

Given:

actual frequency = f = 41.2 kHz

velocity of the car = v_c = 33.0 m/s

speed of sound in air = v = 330 m/s

Asked:

frequency of the beats = Δf = ?

Solution:

Firstly , we will calculate the observed frequency by using the formula of Doppler Effect as follows:

[tex]f' = \frac{v + v_c}{v - v_c} \times f[/tex]

[tex]f' = \frac{330 + 33}{330 - 33} \times 41.2[/tex]

[tex]f' = \frac{363}{297} \times 41.2[/tex]

[tex]f' = \frac{11}{9} \times 41.2[/tex]

[tex]f' = 50 \frac{16}{45} \texttt{ kHz}[/tex]

[tex]f' \approx 50.4 \texttt{ kHz}[/tex]

[tex]\texttt{ }[/tex]

Next , we could calculate the frequency of the beats as follows:

[tex]\Delta f = f' - f[/tex]

[tex]\Delta f \approx 50.4 - 41.2[/tex]

[tex]\Delta f \approx 9.2 \texttt{ kHz}[/tex]

[tex]\texttt{ }[/tex]

The frequency of the beats is about 9.2 kHz

[tex]\texttt{ }[/tex]

[tex]\texttt{ }[/tex]

Grade: College

Subject: Physics

Chapter: Sound Waves

Final answer:

In a crystal of salt, the net charge of the electrons is equal to the net charge of the ions, resulting in a zero net charge due to the formation of ionic bonds between oppositely charged ions.

Explanation:

In a crystal of salt, such as sodium chloride (NaCl), the net charge of the electrons compares with the net charge of the ions to ensure overall electrical neutrality. Each sodium ion (Na+) loses one electron becoming positively charged, while each chlorine ion (Cl-) gains an electron becoming negatively charged. There is an equal number of Na+ and Cl- ions, resulting in a balanced, zero net charge within the crystalline structure.

Salt crystals are formed through ionic bonds, which occur when metals like sodium lose electrons to become positively charged, and nonmetals like chlorine gain electrons to achieve a negatively charged state. The opposite charges attract, creating a strong electrostatic force that holds the ions together. Ionic compounds are electrically neutral because of this balance between the positively and negatively charged ions.

Answer:

0.017 m - 17 m

Explanation:

The relationship between wavelength and frequency of a wave is:

[tex]\lambda=\frac{v}{f}[/tex]

where v is the speed of the wave, [tex]\lambda[/tex] the wavelength and f the frequency.

The speed of sound waves in air at room temperature is

v = 340 m/s

For the lowest frequency, f = 20 Hz, the wavelength is

[tex]\lambda=\frac{340 m/s}{20 Hz}=17 m[/tex]

For the highest frequency, f = 20 kHz = 20,000 Hz, the wavelength is

[tex]\lambda=\frac{340 m/s}{20,000 Hz}=0.017 m[/tex]

On 1930 the astronomer Edwin Hubble classified the galaxies into elliptical, spiral and irregular, being the first two classes the most frequent.  

However, it should be noted that this classification is based only on the visual appearance of the galaxy, and does not take into account other aspects, such as the rate of star formation or the activity of the galactic nucleus.  

The classification is as follows:  

Their main characteristic is that the concentration of stars decreases from the nucleus, which is small and very bright, towards its edges. In addition, they contain a large population of old stars, usually little gas and dust, and some newly formed stars.  

They are symbolized by the letter E and subdivided into eight classes, from E0 with zero eccentricity (spherical) to E7 (called husiform).  

They have the shape of flattened disks containing some old stars and also a large population of young stars, enough gas and dust, and molecular clouds that are the birthplace of the stars.  

They are symbolized with the letter S and depending on the minor or major development that each arm possesses, it is assigned a letter: a, b or c (for example: Sa, Sb, Sc, SBa, SBb, SBc).  

These galaxies, are also divided into two types:  

-Lenticular galaxies  

-Barred spiral galaxies

They are symbolized by the letter I (or IR), although they are usually dwarf or rare and do not have well-defined structure and symmetry.  

They are classified in:  

-Irregular type 1 (Magellanic), which contain large numbers of young stars and interstellar matter.  

-Regular type 2, less frequent and whose content is difficult to identify.  

This type of irregular galaxies are generally located close to larger galaxies, and usually contain large amounts of young stars, gas and cosmic dust.

The net charge in the system is 0. All electrons that were sent to the rod are missing from the fur. Hence, the rod is a (-) while the fur is a (+).

Answer:

In order to satisfied the law of conservation of charge, If the rubber rod becomes negatively charged, then the fur becomes positively charged.

Explanation:

This law states that charge is neither created nor destroyed, it can only be transferred from one system to another. In this case the rubber rod obtains electrons from the fur, in consequence the rod, which was originally neutral becomes negatively charged (the number of electrons on it increase), and the fur which was originally neutral becomes positively charged (the number of electrons on it decrease).

Answer:

0.23 T

Explanation:

The magnetic force exerted on the antiproton must be equal to the centripetal force, since it is a circular motion, therefore we can write:

[tex]qvB = m\frac{v^2}{r}[/tex]

where

[tex]q=1.6\cdot 10^{-19}C[/tex] is the charge of the antiprotons

[tex]v=5.70\cdot 10^7 m/s[/tex] is the speed of the antiprotons

B is the magnitude of the magnetic field

[tex]m=1.67\cdot 10^{-27}kg[/tex] is the antiproton mass

r = 2.60 m is the radius of the orbit

Solving the equation for B, we find the strength of the magnetic field:

[tex]B=\frac{mv}{qr}=\frac{(1.67\cdot 10^{-27} kg)(5.70\cdot 10^7 m/s)}{(1.6\cdot 10^{-19}C)(2.60 m)}=0.23 T[/tex]

To hold antiprotons in a magnetic field, while moving at 5.70 × 10⁷ m/s in a circular path of radius 2.60 m, the strength of the magnetic field required is approximately 0.60 T.

The question deals with the concept of holding antiprotons in a magnetic field, typically a topic in physics related to magnetic force on charged particles. The formula governing this phenomenon is F = qvBsin(θ), where F is the magnetic force, q is the charge, v is the speed, B is the magnetic field strength, and θ is the angle between the velocity and the magnetic field.

Here, sin(θ) is 1 because the field and velocity are perpendicular. The force in this case is a centripetal force because the particle is moving in a circle, so F can be equated to mv²/r. Solving for B, we have B = mv/(qr).

Given that the speed (v) of the antiprotons is 5.70 × 10⁷ m/s and the radius (r) of the circular path is 2.60 m, the mass (m) of a proton (same as an antiproton) is 1.67 × 10⁻²⁷ kg, and the charge (q) equivalent to the basic charge of an electron is 1.60 x 10⁻¹⁹ C, we can substitute these values into the equation:

B = (1.67 × 10⁻²⁷ kg  × 5.70 × 10⁷ m/s) / (1.60 x 10⁻¹⁹ C  × 2.60 m) ≈ 0.60 T (or Tesla)

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A) 1.55

The speed of light in a medium is given by:

[tex]v=\frac{c}{n}[/tex]

where

[tex]c=3\cdot 10^8 m/s[/tex] is the speed of light in a vacuum

n is the refractive index of the material

In this problem, the speed of light in quartz is

[tex]v=1.94\cdot 10^8 m/s[/tex]

So we can re-arrange the previous formula to find n, the index of refraction of quartz:

[tex]n=\frac{c}{v}=\frac{3\cdot 10^8 m/s}{1.94\cdot 10^8 m/s}=1.55[/tex]

B) 550.3 nm

The relationship between the wavelength of the light in air and in quartz is

[tex]\lambda=\frac{\lambda_0}{n}[/tex]

where

[tex]\lambda[/tex] is the wavelenght in quartz

[tex]\lambda_0[/tex] is the wavelength in air

n is the refractive index

For the light in this problem, we have

[tex]\lambda=355 nm\\n=1.55[/tex]

Therefore, we can re-arrange the equation to find [tex]\lambda_0[/tex], the wavelength in air:

[tex]\lambda_0 = n\lambda=(1.55)(355 nm)=550.3 nm[/tex]

Final answer:

The index of refraction of quartz at the given wavelength is approximately 1.55. The wavelength of the same light in air would be approximately 549 nm.

Explanation:

Part A: Index of Refraction of Quartz

The index of refraction (n) is given by the formula n = c/v, where c is the speed of light in a vacuum, and v is the speed of light in the material. Here, we are given the speed of light in a quartz (v_quartz) as 1.94×108 m/s. Using the speed of light in a vacuum (c) as 3.00×108 m/s, we can calculate the index of refraction of quartz as follows:

n_quartz = c / v_quartz
n_quartz = (3.00×108 m/s) / (1.94×108 m/s)
n_quartz = 1.55

Part B: Wavelength in Air

Since the frequency of light remains constant when transitioning between mediums, its wavelength in air (λ_air) can be found using the same frequency. Using the formula λ = v/f, where v_air is the speed of light in air and f is the frequency, we get:

λ_air = c / f
Since c = v_air and n_quartz = c / v_quartz,
we can write
f = v_quartz / λ_quartz

Now, plug the value of f back into the first equation:

λ_air = v_air / (v_quartz / λ_quartz)
λ_air = (3.00×108 m/s) / (1.94×108 m/s) × 355 nm
λ_air ≈ 549 nm

Answer:

deflected toward bottom of the screen

Explanation:

When entering the region with magnetic field, a magnetic force is exerted on the proton. This force is perpendicular to both the direction of the magnetic field and the direction of the velocity of the proton.

The direction of the force can be determined by using the right-hand rule. We have:

- Index finger: direction of the velocity of the proton --> to the right

- Middle finger: direction of the magnetic field --> into the screen

- Thumb: direction of the magnetic force --> toward bottom of the screen

So, the correct answer is

deflected toward bottom of the screen

From the information given about the topic I would say that the molecules will move more quickly.

The molecules will move more slowly

Entropy generation in an ideal Brayton cycle is zero since all processes are reversible and there are no irreversibilities within the system to generate entropy.

The student's question relates to finding the rate of entropy generation for an ideal Brayton cycle using argon as the working fluid. However, the Brayton cycle, as an ideal cycle, does not lead to entropy generation within the system because all processes are reversible. Entropy may change as heat crosses the system boundaries, but this is not the same as entropy generation due to irreversibilities. Calculating entropy changes in an actual Brayton cycle requires knowledge of each process's irreversibilities, which cannot be determined without additional data on the components' efficiencies and the specific entropy values of argon at the given states. Further calculations for ideal processes can be simplified using the assumption of adiabatic and isentropic compression and expansion.