An infinitely long line of charge has linear charge density 5.00 10-12 C/m. A proton (mass 1.67 10-27 kg, charge +1.60 10-19 C) is 18.0 cm from the line and moving directly toward the line at 1.20 103 m/s. How close does the proton get to the line of charge?

Incomplete question as we have not told which quantity to find.So the complete question is here

A solenoid used to produce magnetic fields for research purposes is 2.2 mm long, with an inner radius of 25 cmcm and 1300 turns of wire. When running, the solenoid produced a field of 1.5 TT in the center.Given this, how large a current does it carry?

Answer:

[tex]I=2.021A[/tex]

Explanation:

Magnetic field B=1.5 T

Length L=2.2mm =0.0022m

Number of turns N=1300 turns

To find

Current I

Solution

From the magnetic at the center of loop we know that:

[tex]B=uI\frac{N}{L}[/tex]

Substitute the given values

[tex]B=uI\frac{N}{L}\\ as\\u=4\pi *10^{-7} T.A/m\\So\\B=uI\frac{N}{L}\\I=\frac{LB}{Nu}\\ I=\frac{0.0022m(1.5T)}{(1300)(4\pi *10^{-7} T.A/m)}\\I=2.021A[/tex]

The radius R of the turn is 1.984 km.

Explanation:

As the falcon is experiencing a centripetal motion, the acceleration exhibited by the falcon will be centripetal acceleration. The formula for centripetal acceleration is

                 [tex]a=\frac{v^{2} }{R}[/tex]

Here a is the acceleration for centripetal motion, v is the velocity and R is the radius of the circular path.

As the centripetal acceleration is given as 0.6 g, the velocity is given as 108 m/s, then the radius of the path can be determined as

       [tex]0.6 \times 9.8=\frac{(108)^{2}}{R}[/tex]

      [tex]R=\frac{(108)^{2}}{0.6 \times 9.8}=\frac{11664}{5.88}=1983.67\ \mathrm{m}[/tex]

So, the radius of the turn is 1.984 km.

Answer:

Total force = 1257.5N

Explanation:

Acceleration = 3.50 m/s2

Total Mass = 245kg

Force = Mass x acceleration

Force = 245 x 3.50 = 857.5N

Opposing Force = 400N

Total Force = Force of Motorcycle + Opposing force

Total force = 857.5N + 400N

Total force = 1257.5N

Answer:

The first eagle hear a frequency of 4.23kHz and the second eagle hear a frequency of 3.56kHz

Explanation:

Given that

both eagle are flying towards one another

speed of the first eagle v1 = 15m/s

speed of the second eagle v2 = 20m/s

frequency emitted by the first eagle f1= 3200Hz

frequency emitted by the second eagle f2 = 3800Hz

speed of sound v = 330m/s

[tex]F_1 = (\frac{v + v_2}{v - v_1} )f_1\\F_1 = (\frac{330 + 20}{330 - 15} )(3200)\\= 3.56 \times 10^3Hz\\= 3.56kHz\\[/tex]

the second part

[tex]F_1 = (\frac{v + v_2}{v - v_1} )f_1\\F_1 = (\frac{330 + 15}{330 - 20} )(3800)\\= 4.23 \times 10^3Hz\\= 4.23kHz\\[/tex]

The first eagle hear a frequency of 4.23kHz and the second eagle hear a frequency of 3.56kHz

The situation can be modeled with a differential equation taking into account the inflow and outflow rates of carbon dioxide. By resolving this equation, we obtain a function representing the CO2 quantity over time. This can be easily converted into percentage by dividing by the room's volume and multiplying by 100.

This problem can be solved using a mathematical model called a differential equation. The percentage of carbon dioxide in the room changes over time due to the input of fresher air and the removal of mixed air.

Let's denote the quantity (not the percentage, the actual quantity) of carbon dioxide in the room at time t by Q(t). Initially, we have Q(0) = 0.0025 * 180 = 0.45 m³.

Carbon dioxide flows into the room at a rate of 0.0005 * 2 = 0.001 m³/min and flows out at the rate proportional to the total quantity present, which is (Q(t) / 180) * 2 = (Q(t) / 90) m³/min. Therefore the situation can be modelled by the differential equation dQ/dt = 0.001 - Q(t) / 90. Here, 0.001 represents the rate on inflow of carbon dioxide, and Q(t) / 90 represents the rate of outflow.

By solving this differential equation, we can obtain the function Q(t) which gives the quantity of carbon dioxide in the room at each moment, and the percentage of carbon dioxide can be obtained by dividing Q(t) by the volume of the room and multiplying by 100 to get a percentage, i.e., p(t) = Q(t)/180 * 100.

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The percentage of carbon dioxide in the room over time can be calculated using differential equations. The resulting function is[tex]p(t) = 0.005 * e^{(t/90)} + 0.02 * e^{(-t/90)}[/tex]. This takes into account both the inflow of fresh air and the mixture exiting the room.

To determine the percentage p of carbon dioxide in the room as a function of time t (in minutes), we need to use principles from differential equations to model the mixing process.

Initially, the volume of the room is 180 m³ containing 0.25% carbon dioxide. Fresh air with 0.05% carbon dioxide flows into the room at 2 m³/min.

Let's denote the amount of carbon dioxide in the room at time t by C(t), measured in cubic meters. The concentration of carbon dioxide p(t) is given by:

The rate of change of the carbon dioxide in the room can be written as:

The inflow of carbon dioxide is:

The outflow of carbon dioxide depends on the concentration in the room:

Thus, the differential equation becomes:

This simplifies to:

[tex]or, dC/dt = 0.001 - (C/90)[/tex]

To solve this, we use an integrating factor. The integrating factor is:

Multiplying both sides by the integrating factor:

This simplifies to:

Integrate both sides:

Hence,

To find K, use the initial condition C(0):

Initial amount of CO2:

Thus,

Therefore, [tex]K = 0.36[/tex].

The solution is:

The percentage of CO2 is:

This simplifies to:

Hence:

[tex]p(t) = 0.005 * e^{(t/90)} + 0.02 * e^{(-t/90)}[/tex]

Answer: B) Light

Explanation: light waves are Electromagnetic waves. Visible light is one of the many types of electromagnetic waves. The others are mechanical waves.

Answer:

In 3 hours, the cars will be 297 miles apart.

Explanation:

Speed=Distance/Time

Distance= Speed X Time

Speed of 1st Car=44 miles/hr

Distance=44 X Time taken = 44t

Speed of 2nd Car=55 miles/hr

Distance=55 X Time taken = 55t

Total Distance Covered by both Cars = 44t + 55t = 99t

The cars are 297 miles apart, therefore:

99t = 297

t = 3 hours

It means that in 3 hours, the distance between the cars is 297 miles.

Answer:

Time spent on the greenway road  = 4.5 hours

Time spent on the 2 lane road = 1.5 hours

Explanation:

The distance of the trip  is 360 miles and the initial speed of the car is 62 miles/hr and after the road became 2 lane highway the car slowed to 54 miles/hr.

Let us divide the trip into two

Greenway

speed = distance/time

speed = 62 mph

time = a

distance = speed × time

distance = 62a

2 lane highway

speed = distance/time

speed = 54 mph

time = b

distance = speed × time

distance = 54b

Total distance

62a + 54b = 360......................(i)

Total time

a + b = 6..............................(ii)

a = 6-b

insert a in equation (i)

62(6-b) + 54b = 360

372  - 62b + 54b = 360

-8b = 360-372

-8b = - 12

b = 12/8

b = 1.5

from equation (ii)

a + 1.5 = 6

a = 6 - 1.5

a = 4.5

Answer:

Explanation:

Torque on smaller wheel

= F x r

50 x .30

= 15 Nm

Torque on larger wheel

= F x .5

For equilibrium

F x .5 = 15

F = 15 / .5

= 30 N

Answer:

b. slow-moving streams.

Explanation:

In Fluid Mechanics, the Reynolds numbers indicates the existence of turbulence in fluid streams. Low Reynolds numbers are related with laminar flow. The Reynolds formula is:

[tex]Re = \frac{\rho_{water} \cdot L_{c}}{\mu_{water}} \cdot v[/tex]

The Reynolds number is directly proportional to fluid speed. Hence, slow-moving streams are a sound example of laminar flow. The correct answer is B.

Answer:

Ensures land is used for its designated purposes hence avoiding misuse of land.

Explanation:

The process of urban planning ensures that different land uses are shown such as commercial, residential, public land, forestry and agricultural and institutional lands. This process helps in designing for essential services such as roads, sewarage and water, gas and electricity. In the process, encroachment is controlled and land utilized as planned. Therefore, land is properly utilized while minimizing environmental pollution, leading to sustainable development.

Answer:

Cover-braking technique

Explanation:

Cover braking involves the technique of taking off the foot from the accelerator and hovering it over the braking pedal. The foot must not be placed on the braking pedal to avoid the wear of brake unnecessarily.

It is done usually when an obstacle is expected in front of the moving car. This provides an edge in the reaction time of application of the brakes hence reducing the stopping time.

Regenerative braking and engine braking are techniques used for a smooth transition from acceleration to braking. These techniques convert kinetic and potential energy into electrical energy or use engine power to slow down the vehicle, respectively.

The technique that provides a smooth transition from acceleration to braking is commonly recognized in physics and engineering called regenerative braking. Regenerative braking is a central component of the operation of hybrid and electric vehicles. It functions by converting a vehicle's kinetic and gravitational potential energy into electrical energy that recharges the vehicle's battery when deceleration is initiated.

Another method is engine braking, usually applied in larger vehicles like trucks to avoid overheating of brakes specially when traveling downhill.

Both methods, whether it is engine braking or regenerative, provide a smooth progression from accelerated motion to a decrease in speed, or braking. This way, they manage the transition smoothly while conserving and efficiently using energy.

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Answer:

The magnitude of average force [tex]F_{avg} =[/tex] [tex]9.125 \times 10^{4} N[/tex]

Explanation:

Given :

Mass of person [tex]m = 73[/tex] Kg

Initial velocity of car  [tex]v_{o} = 20 \frac{m}{s}[/tex]

Average distance [tex]x = 0.16[/tex] m

According to the second law of newton.

 [tex]F_{avg} = m a[/tex]

From the kinematic equations,

 [tex]v^{2}- v_{o} ^{2} = 2ax[/tex]

Where [tex]v_{o} =[/tex] initial velocity, in our case final velocity is zero ([tex]v = 0[/tex])

 [tex]a =- \frac{400}{2 \times 0.16} = -1250 \frac{m}{s^{2} }[/tex]

So average force is given by,

[tex]F _{avg} = 73 \times -1250 = -91250[/tex] N

But magnitude of average force is,

[tex]F_{avg} = 9.125 \times 10^{4}[/tex] N

Answer:

Explanation:

Since momentum is a vector, you, indeed, in two dimension collisions, you can decompose it in two components, the x-direction and the y-direction, such as you do with the force, which is a vector too.

The law of conservation of momentum states that the total momentum before and after the collision are conserved.

Let's assume a collision in one dimension: x-direction.

If object A is moving to the right, its momentum is to the right. If objcet B is at rest its momentum is zero. Then, if when object A collides with object B, the first stops, the second must move to the right with a momentum in the x-direction equal to the momentum that object A initially had.

You can apply the same reasoning if object A is moving in two dimensions, and, a similar one, if object B is not at rest: at the end the momentum in each direction before the collision has to be equal to the momentum in each direction after the collision.

Answer: D all of the above

Explanation:

All of the statements in the options are the character's exhibited by both longitudinal amd transverse waves.

Examples of transverse waves are water waves, light waves, radio waves, and also waves produced in strings and ropes.

Examples of longitudinal waves includes : vibrating turn fork,, drum head etc

Statement A is true for longitudinal waves only, statement C is true for transverse waves only, and statement B is true for both types of waves. These are based on the nature of particle movement in relation to the direction of wave energy flow.

In the given statements, Statement A, 'In longitudinal waves, the particles of the medium move parallel to the direction of the flow of energy', is true solely for longitudinal mechanical waves. This is because, in longitudinal waves, the disturbances (or oscillations) in the medium occur in the same direction as the wave propagation, with notable examples being sound waves in air and water.

Statement C, 'In transverse waves, the particles of the medium move perpendicular to the direction of the flow of energy', on the other hand, pertains exclusively to transverse mechanical waves. Transverse waves are characterized by disturbances in the medium that are perpendicular to the direction of the wave propagation, common examples of which are waves seen on stringed instruments and electromagnetic waves, such as visible light.

Statement B, 'Many wave motions in nature are a combination of longitudinal and transverse motion', applies to both longitudinal and transverse mechanical waves. Certain seismic waves generated during earthquakes, for instance, possess both longitudinal and transverse components, demonstrating that waves can indeed display composite behaviors. Thus, in essence, this statement is true for both types of mechanical waves.

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Answer: moon mass = earth mass/96

Explanation:

The moon mass will be 1/96th of the earth mass. There is an attached detailed solution to this.

Answer:

Habitat manipulation

Explanation:

Habitat manipulation, otherwise known as ecological engineering, is a technique of promoting natural enemies within an ecosystem by making thriving conditions more suitable for them.

In this case, thriving conditions for the species (which happens to be predators and hence, natural enemies) were promoted via artificial introduction of food.

Answer:

1 m

Explanation:

P = Patm + ρgh

110,000 Pa = 100,000 Pa + (1020 kg/m³) (9.8 m/s²) h

h = 1 m

At depth of 1 m the sea would the total pressure be 110kpa.

The physical force applied to an object is referred to as pressure. Per unit area, a perpendicular force is delivered to the surface of the objects. F/A is the fundamental formula for pressure (Force per unit area). Pascals are a unit of pressure (Pa). Absolute, atmospheric, differential, and gauge pressures are different types of pressure.

Given that:

Atmospheric pressure at sea level has a value of  p = 100 kPa = 100000 Pa.

The density of sea water is 1020kg/m-3.

Let: at  depth of x m the sea would the total pressure be: P =110 kPa = 110000 Pa.

So, P = p + ρgh

⇒ 110,000 Pa = 100,000 Pa + (1020 kg/m³) (9.8 m/s²) h

⇒ h = 1 m

Hence, at depth of 1 m the sea would the total pressure be 110kpa.

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Answer:

THE ANSWER IS:  Rutherford, Marsden and Geiger discovered the dense atomic nucleus by bombarding a thin gold sheet with the alpha particles emitted by radium

Explanation:

Answer:

it would be longer

Answer:

Distance covered by Tevin before his tire went flat = 24 miles

Explanation:

Let x be the distance covered by Tevin before his tire went flat.

Given:

Tevin drives his bike in the town = 6 mph  

Tevin back to his house = 3 mph

Total taken time by Tevin = 12 hours

We need to find the distance covered by Tevin in 12 hours.

Solution:

Using speed formula    

[tex]Speed =\frac{Distance}{Time}[/tex]

We write the above formula for Time.

[tex]Time=\frac{Distance}{Speed}[/tex]-----------(1)

Time taken by Tevin when biking in town

Substitute speed = 6 mph and distance = x in equation 1.

[tex]Time=\frac{x}{6}[/tex]  ----------(2)

Time taken by Tevin when he is back to his house.

Substitute speed = 3 mph and distance = x in equation 1.

[tex]Time=\frac{x}{3}[/tex]   -------------(3)

Total time taken by Tevin.

Total taken time by Tevin = Time taken when biking in town + Time taken when Tevin back to his house.

Substitute time value from equation 2 and 3 in above equation and total time = 12 hours.

[tex]12=\frac{x}{6}+\frac{x}{3}[/tex]

Now, we solve the above equation for x.

[tex]12=\frac{x+2x}{6}[/tex]

[tex]12\times 6=x+2x[/tex]

[tex]72=3x[/tex]

[tex]x=\frac{72}{3}[/tex]

[tex]x=24\ mi[/tex]

Therefore, distance covered by Tevin in 12 hours is equal to 24 miles.

Answer:

Coefficient of friction between the book and floor is 0.582.

Explanation:

Using the velocity formula;

v^2 = 2as

a = v^2/(2s)

a = 1.6^2/(2*0.9)

a = 2.56/1.8

a = 1.42 m/s^2

the force necessary to give the book the acceleration is  

F = ma = 3.5*1.42 (m is mass of the book i.e. 3.5 kg)

F = 4.98 N

The difference in the force is the friction force, which is

Ff = 25 - 4.98 = 20 N

Ff = mgμ

where μ is coefficient of friction and g is acceleration due to gravity that is 9.8 m/s^2

μ = Ff/mg

μ = 20/(3.5*9.81)

μ = 0.582

Coefficient of friction between the book and floor is 0.582.

This question involves the concepts of the equation of motion and Newton's second law of motion.

The coefficient of kinetic friction between the book and the floor is "".

First, we will find the acceleration of the block by using the third equation of motion:

[tex]2as = v_f^2-v_i^2[/tex]

where,

a = acceleration = ?

s = distance covered = 0.9 m

vf = final speed = 1.6 m/s

vi = initial speed = 0 m/s

Therefore

[tex]a=\frac{(1.6\ m/s)^2-(0\ m/s)^2}{2(0.9\ m)}\\\\a=1.42\ m/s^2[/tex]

Hence, from Newton's second law of motion:

[tex]Net\ Force = Frictional\ Force + F\\Net\ Force = \mu mg+ma[/tex]

where,

Net Force = 25 N

μ = coefficient of kinetic friction = ?

m = mass of the book = 3.5 kg

g = acceleration due to gravity = 9.81 m/s²

Therefore,

[tex]25\ N = \mu(3.5\ kg)(9.81\ m/s^2)+(3.5\ kg)(1.42\ m/s^2)\\\\\mu=\frac{25\ N - 4.98\ N}{34.33\ N}\\\\\mu = 0.58[/tex]

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The attached picture shows Newton's Second Law of Motion.

Answer:

Both

A. Low tides are lowest at both full moon and new moon.

B. High tides are highest at both full moon and new moon.

Explanation:

Tides are formed as a consequence of the differentiation of gravity due to the moon across to the Earth sphere.

Since gravity variate with the distance:

[tex]F = G\frac{m1\cdot m2}{r^{2}}[/tex]  (1)

Where m1 and m2 are the masses of the two objects that are interacting and r is the distance Where m1 and m2 are the masses of the two objects that are interacting and r is the distance between them.

For example, see the image below, point A is closer to the moon than point b and at the same time the center of mass of the Earth will feel more attracted to the moon than point B. Therefore, that creates a tidal bulge in point A and point B.

On the other hand, a full moon it gets when Sun, the Earth and the moon are in a line and the moon is reflecting the sunlight.

When the Moon is between the Earth and the Sun it will be illuminated in its back, so it is not possible to see it from the Earth (that is called new moon).

In those two cases mentioned above, the Sun tidal force contributes to the tidal force of the moon over the earth making high tides higher and low tides lower.  

Answer:

Protein molecules

Explanation:

Ribosomes are the cell organelles that are responsible for the synthesis of protein in the cell. Proteins are the fundamental building blocks and help in repair and damage of cell in the body.

Ribosome is a complex which is made up of protein and RNA. Ribosomes can be found floating within the cytoplasm or attached to the endoplasmic reticulum.

Answer:

 = 238N

Explanation:

mass = 0.14g = 14 × 10⁻⁵kg

initial velocity = 218m/s

final velocity = 0

penetration depth (distance) = 14mm = 14 × 10⁻³m

v²(final) = v²(initial) + 2aΔx

0² = (218)² + 2(14 × 10⁻³)a

a = -(218)² /  2(14 × 10⁻³)

a = 16.97 × 10⁵m/s²

F = ma

 = (14 × 10⁻⁵)(16.97 × 10⁵)

 = 237.58N

 ≅ 238N

Explanation:

Below is an attachment containing the solution.

Answer:

59.84 N

Explanation:

The net force is responsible for the upward acceleration of the bowling ball.

The net force acting on a body accelerates the body in the same direction as that in which the resultant is applied.

Net force = ma

ma = F - mg

In the first case,

F = 71.6 N, a = a m/s²

ma = 71.6 - mg (eqn 1)

In the second case,

F = 82.3 N, a = 1.91a m/s²

m(1.91a) = 82.3 - mg

1.91 ma = 82.3 - mg (eqn 2)

Substitute for ma in (eqn 2)

1.91 (71.6 - mg) = 82.3 - mg

136.756 - 1.91 mg = 82.3 - mg

136.756 - 82.3 = 1.91 mg - mg

0.91 mg = 54.456

mg = 54.456/0.91

mg = 59.84 N

Hence, the weight of the bowling ball = 59.84 N

Hope this Helps!!!

The weight of the bowling ball is 59.84 N

The net force should be held responsible where there is the upward acceleration of the bowling ball. When it should be acted on the body so it should be in a similar direction.

We know that

Net force = ma

So,

ma = F - mg

Now

In the first case,

F = 71.6 N, a = a m/s²

ma = 71.6 - mg (eqn 1)

And,

In the second case,

F = 82.3 N, a = 1.91a m/s²

m(1.91a) = 82.3 - mg

So,

1.91 ma = 82.3 - mg (eqn 2)

Now

1.91 (71.6 - mg) = 82.3 - mg

136.756 - 1.91 mg = 82.3 - mg

136.756 - 82.3 = 1.91 mg - mg

0.91 mg = 54.456

mg = 54.456/0.91

mg = 59.84 N

Hence, the weight of the bowling ball = 59.84 N

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Answer:

k = 1755 N/m

Explanation:

Given:

- The length of the cord L = 23.4 m

- Weight of the student W = 818 N

- The elevation of balloon H = 31.3 m

Find:

Calculate the required force constant of the cord if the student is to stop safely 2.74 m above the river.

Solution:

- We know the potential energy of the student changes by  

                      ΔP.E = m*g*( H - 2.74 )

                      mg*(31.3 - 2.74) = 818*28.56 = 23362.08 J

- When he stops at 2.74 m above ground his KE = 0 so ALL his lost potential energy must be stored in the extended or stretched bungee cord.

- He falls 23.4 m before the bungee cord starts to stretch. That means it doesn't start stretching until he is 31.3 - 23.4 = 7.9 m above the ground.  

- It has to stop  stretching at 2.74 m above the ground so the

                                total stretch = 7.9 - 2.74 = 5.16 m

- Therefore his PE from 31.3 m to 2.74 m is stored in a 5.16 m stretch of the bungee cord.                      

                                ½kx² =  ΔP.E

                                k = 2*ΔP.E / x^2

                                k = 2*23362.08 / 5.16^2

                                k = 1755 N/m

Answer:

1. A Haploid

2. A. Somatic Cell production

3. B. Gametic cell production

4. C. Mitosis produces identical cells to parent cells.

5. B 4:0

6. C Both parent bees are heterozygous Ll

7. D DNA is made up of chromosomes

8. B Each hypothesis was tested and DNA supported the data better

9. D There may be an increase in pest populations that are resistant to control measures.

10. A They are proven to cause cancer.

11. B a form of a gene

Explanation:

Answer was too long, so is attached in a word document

Answer:

(a) increase

Explanation:

On a line graph; we have the x-axis to the positive side and the negative side .In a positive x-axis direction, the force is usually positive, vice versa the negative side as well.

The change in the potential energy of a charge field-system can be given as:

[tex]\delta U= -q(EdsCos \theta)[/tex]

where;

q = positive test charge

E = Electric field

ds = displacement between thee charge positions

θ  = Angle between the electric field and the displacement.

Given that:

Charge of the particle = -q

displacement = (60.0 -20.0)cm = 40.0 cm

θ = 0

Replacing our values in the above equation, we have:

[tex]\delta U = -(-q)(60Cos 0)[/tex]

[tex]\delta U = qEds[/tex]

Since the potential energy of the system is positive, therefor the electric potential energy also increases.

The electric potential energy of a system consisting of a negatively charged particle in a uniform electric field increases when the particle is moved in the same direction as the field.

The electric potential energy of the charge-field system increases as a negatively charged particle is moved in the same direction as the electric field. This is because work is done to overcome the force of the electric field, which opposes the movement of the negatively charged particle. The uniform electric field produces a constant force, and since work is force times distance, the amount of work (and hence energy) increases.

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