An electric range burner weighing 683.0 grams is turned off after reaching a temperature of 477.6°C, and is allowed to cool down to 23.2°C.

Calculate the specific heat of the burner if all the heat evolved from the burner is used to heat 552.0 grams of water from 23.2°C to 80.3°C.

Answer:

A and D are true , while B and F statements are false.

Explanation:

A) True.  Since the standard gibbs free energy is

ΔG = ΔG⁰ + RT*ln Q

where Q= [P1]ᵃ.../([R1]ᵇ...) , representing the ratio of the product of concentration of chemical reaction products P and the product of concentration of chemical reaction reactants R

when the system reaches equilibrium ΔG=0 and Q=Keq

0 = ΔG⁰ + RT*ln Q → ΔG⁰ = (-RT*ln Keq)

therefore the first equation also can be expressed as

ΔG = RT*ln (Q/Keq)

thus the standard gibbs free energy can be determined using Keq

B) False. ΔG⁰ represents the change of free energy under standard conditions . Nevertheless , it will give us a clue about the ΔG around the standard conditions .For example if ΔG⁰>>0 then is likely that ΔG>0 ( from the first equation) if the temperature or concentration changes are not very distant from the standard conditions

C) False. From the equation presented

ΔG⁰ = (-RT*ln Keq)

ΔG⁰>0 if Keq<1 and ΔG⁰<0 if Keq>1

for example, for a reversible reaction  ΔG⁰ will be <0 for forward or reverse reaction and the ΔG⁰ will be >0 for the other one ( reverse or forward reaction)

D) True. Standard conditions refer to

T= 298 K

pH= 7

P= 1 atm

C= 1 M for all reactants

Water = 55.6 M

Answer:

a. 406.3mL

b. 5519.6g

Explanation:Please see attachment for explanation

Complete Question:

A chemist prepares a solution of iron chloride by measuring out 0.10 g of FeCl2 into a 50. mL volumetric flask and filling to the mark with distilled water. Calculate the molarity of anions in the chemist's solution.

Answer:

[Fe+] = 0.0156 M

[Cl-] = 0.0316 M

Explanation:

The molar mass of iron chloride is 126.75 g/mol, thus, the number of moles presented in 0.10 g of it is:

n = mass/molar mass

n = 0.10/126.75

n = 7.89x10⁻⁴ mol

In a solution, it will dissociate to form:

FeCl2 -> Fe+  + 2Cl-

So, the stoichiometry is 1:1:2, and the number of moles of the ions formed are:

nFe+ = 7.89x10⁻⁴ mol

nCl- = 2*7.89x10⁻⁴  = 1.58x10⁻³ mol

The molarity is the number of moles divided by the solution volume, in L (50.0 mL = 0.05 L):

[Fe+] = 7.89x10⁻⁴/0.05 = 0.0156 M

[Cl-] = 1.58x10⁻³/0.05 = 0.0316 M

Answer: The final pressure of carbon dioxide is 15.4 atm

Explanation:

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

Given mass of carbonic acid = 78.2 g

Molar mass of carbonic acid = 62 g/mol

Putting values in above equation, we get:

[tex]\text{Moles of carbonic acid}=\frac{78.2g}{62g/mol}=1.26mol[/tex]

For the given chemical reaction:

[tex]H_2CO_3(aq.)\rightarrow H_2O(l)+CO_2(g)[/tex]

By Stoichiometry of the reaction:

1 mole of carbonic acid produces 1 mole of carbon dioxide

So, 1.26 moles of carbonic acid will produce = [tex]\frac{1}{1}\times 1.26=1.26mol[/tex] of carbon dioxide

To calculate the pressure, we use the equation given by ideal gas, which follows:

[tex]PV=nRT[/tex]

where,

P = pressure of the carbon dioxide = ?

V = Volume of the container = 2.00 L

T = Temperature of the container = 298 K

R = Gas constant = [tex]0.0821\text{ L. atm }mol^{-1}K^{-1}[/tex]

n = number of moles of carbon dioxide = 1.26 moles

Putting values in above equation, we get:

[tex]P\times 2.00L=1.26mol\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 298K\\\\P=\frac{1.26\times 0.0821\times 298}{2.00}=15.4atm[/tex]

Hence, the final pressure of carbon dioxide is 15.4 atm

The question is incomplete, here is the complete question:

Calculate the volume in liters of a 0.13 M potassium dichromate solution that contains 200. g of potassium dichromate . Round your answer to 2 significant digits.

Answer: The volume of solution is 5.2 L

Explanation:

To calculate the volume of solution, we use the equation used to calculate the molarity of solution:

[tex]\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}[/tex]

We are given:

Molarity of solution = 0.13 M

Given mass of potassium dichromate = 200. g

Molar mass of potassium dichromate = 294.15 g/mol

Putting values in above equation, we get:

[tex]0.13M=\frac{200}{294.15\times \text{Volume of solution}}\\\\\text{Volume of solution}=\frac{200}{294.15\times 0.13}=5.23L[/tex]

Hence, the volume of solution is 5.2 L

The volume of a potassium dichromate solution containing 1.8 moles cannot be calculated without the molarity of the solution. Once molarity is known, use V = n / M and convert to liters, considering significant figures for accuracy.

To calculate the volume of a potassium dichromate solution that contains 1.8 moles of potassium dichromate, we must first determine the molarity (M) of the solution, which is not provided in the question. Assuming we have this information, the formula to find the volume (V) when the number of moles (n) and molarity (M) are known is:V = n / M

Without a given molarity, we cannot proceed with this calculation. If molarity is provided, we'd convert it to liters. Since the molarity and actual number of grams of potassium dichromate were not provided in your question, we cannot complete this calculation precisely. However, the reference provided for preparing a different solution with KBrO3 and the details about significant figures indicate that calculations should be made using suitable glassware for precision and rounding off to the correct number of significant digits.

Answer:

0.026%

Explanation:

The Helium-4 is the isotope of the helium that has a mass equal to 4. The element has 2 electrons, so, the total radius of the electrons is 2*2.8 = 5.6 fm = 0.0056 pm.

So, the total radius of the particles is 0.0056 + 0.0026 = 0.0082 pm.

The percentage of the space that the particles occupy is the radius of them divided by the radius of the atom:

% = 0.0082/31 *100%

% = 0.026%

* 1 fentometer (fm) = 0.001 picometer (pm)

Answer:

Moles of Br₂ = 0.236 (First option)

Explanation:

Bromine gas is a diatomic molecule. Its formula is Br₂.

Moles = Mass / Molar mass

Moles = 37.7 g / 159.8 g/mol

Moles of Br₂ = 0.236

Answer:Iodide has weaker ion-dipole interactions with water than bromide.

Explanation:

The electronegativity difference between sodium and iodine in sodium iodide is about 1.73. This shows that the compound is not composed of purely ionic bonds. Electro negativity decreases down the group hence iodine is far less electronegative than bromine and is thus ineffective in forming strong dipole interactions with water hence the higher entropy due to much less association of ions in solution.

The entropy change for NaI is greater than that for NaBr because iodide ions have weaker ion-dipole interactions with water, leading to a more disordered system and higher entropy upon dissolution.

The entropy change is greater for the dissolution of NaI compared to NaBr because Iodide has weaker ion-dipole interactions with water than bromide. This is attributable to the larger size and more diffuse electron cloud of the iodide ion, which makes its interactions with water molecules less specific and weaker compared to the smaller bromide ion. Due to these weaker interactions, when NaI dissolves, there is a greater increase in disorder or entropy within the system as the iodide ions are less constrained by water molecules relative to bromide ions. Since entropy is a measure of disorder or the number of available microstates for a system, the dissolution of NaI leads to a higher increase in entropy.

Answer: The mass in grams for a 9.50 carat diamond is 1.9.

Explanation:

Given :

The mass of gemstones and pearls is usually expressed in units called carats.

we have to find mass in grams for 9.50 carat diamond.

1 carat = 200 mg

Thus 9.50 carat=[tex]\frac{200}{1}\times 9.50=1900mg[/tex]

Also [tex]1 mg =10^{-3}g[/tex]

Thus  [tex]1900mg =\frac{10^{-3}}{1}\times 1900=1.9g[/tex]

Thus the mass in grams for a 9.50 carat diamond is 1.9

Answer:

The neutral organic product of the reaction is the 2-methoxy-2-methylpropane, shown in the attached figure.

Explanation:

By reacting an alkene (2-methylprop-1-ene) with an alcohol (methanol) in the presence of an acid it forms an ester (2-methoxy-2-methylpropane) through Markovnikov’s rule. First, a protonation of the alkene occurs where a tertiary carbocation is formed, then the nucleophile (methanol) attacks the previously formed carbocation, and finally ocurr the deprotonation of the hydrogen bound to the oxygen, thus forming the ester, in our case the neutral organic product 2-methoxy-2-methylpropane.

Without information about the reactants and reaction conditions, it is impossible to predict the neutral organic product of a reaction.

The question refers to a reaction and asks for the prediction of the neutral organic product. However, the reaction and reactants are not provided, so it is impossible to provide a specific answer. In organic chemistry, reactions can involve different reactants and conditions, leading to various possible products.

To predict the neutral organic product of a reaction, it is necessary to know the reactants and the specific reaction conditions.

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Answer:

Speed, [tex]v=\sqrt{\dfrac{2qV}{m}}[/tex]

Explanation:

The device which is used to accelerate charged particles to higher energies is called a cyclotron. It is based on the principle that the particle when placed in a magnetic field will possess a magnetic force. Just because of this Lorentz force it moves in a circular path.  

Let m, q and V are the mass, charge and potential difference at which the particle is accelerated.

The work done by the particles is equal to the kinetic energy stored in it such that,

[tex]qV=\dfrac{1}{2}mv^2[/tex]

v is the speed with which the particles enter the cyclotron

So,

[tex]v=\sqrt{\dfrac{2qV}{m}}[/tex]

So, the speed with which the particles enter the cyclotron is [tex]v=\sqrt{\dfrac{2qV}{m}}[/tex]. Hence, this is the required solution.

The speed of particles entering a cyclotron, given a potential difference V, particle mass m, and particle charge q, can be calculated using the formula v = sqrt((2qV) / m). This is based on the conversion of electrical potential energy to kinetic energy in the system.

In a cyclotron, the electrical potential energy of the particles is converted into kinetic energy. This follows the conservation of energy principle, and this transformation is described by the equation for kinetic energy, K.E. = 1/2 mv². In this case, the kinetic energy is equivalent to the energy gained from the electrical potential difference, qV (where q is the charge of the particle and V is the potential difference).

So, the equation becomes qV = 1/2 mv². Solving for the final speed v, we find that v = sqrt((2qV) / m). This equation allows us to calculate the speed at which particles enter the cyclotron, directly determined by the potential difference, particle charge (q), and particle mass (m).

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Answer:

500 years

Explanation:

The original carbon-14 was 100%, and after 100 years, it decays 1.202%. So after 100 years it goes to 98.798%, after more 100 years (200 years), it will be 97.596% (98.798 - 1.202), thus, after n 100 years "package", the percenatge will be:

100% - actual% = n*1.202

n = (100% - actual%)/1.202

n = (100% - 94%)/1.202

n = 4.992

So, the number of years is n*100 = 4.992*100 = 499.2 ≅ 500 years.

Answer:Iodine:

Electron configuration:

[Kr]4d10 5s2 5p5

1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p5

Explanation:

Iodine is an element in group 17. It has only on umpired electron in the 5p orbital it combines with fluorine which also has one unpaired electron in its outermost orbital to form different complex interhalogen compounds by covalent bonding. These interhalogen compounds exhibit various shapes and properties.

The correct electron configuration for the element with one unpaired 5p electron that forms a covalent compound with fluorine is [Kr] 5s^2 4d^10 5p^3.

To determine the electron configuration of the element in question, we need to consider the following points:

1. The element forms a covalent compound with fluorine, which means it is likely to be a non-metal or metalloid, as these elements commonly form covalent bonds.

2. The element has one unpaired electron in the 5p subshell. This indicates that the 5p subshell is not completely filled, but it has at least one electron in it.

3. The noble gas before this element in the periodic table is krypton (Kr), which has a stable electron configuration ending in [Kr] 4s^2 4p^6.

4. The next electron added after krypton would go into the 5s subshell, followed by the 4d and then the 5p subshells, according to the Aufbau principle.

5. Since we are looking for an element with one unpaired 5p electron, we need to fill the 5s and 4d subshells completely and then partially fill the 5p subshell.

6. The 5s subshell can hold 2 electrons, and the 4d subshell can hold 10 electrons. The 5p subshell can hold 6 electrons, but we only need to add 3 electrons to it to have one unpaired electron (5p^3).

7. Therefore, the electron configuration would be [Kr] 5s^2 4d^10 5p^3, which shows a complete filling of the 5s and 4d subshells and three electrons in the 5p subshell, leaving one unpaired electron in the 5p orbital.

8. This configuration corresponds to the element iodine (I), which is known to form covalent compounds with fluorine, such as IF, IF_3, IF_5, and IF_7.

In summary, the element with one unpaired 5p electron that forms a covalent compound with fluorine is iodine, and its expected ground-state electron configuration is [Kr] 5s^2 4d^10 5p^3.

Answer: 5.8

Explanation:

the formula:

d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2\,}d=

(x

2

​

−x

1

​

)

2

+(y

2

​

−y

1

​

)

2

​

Answer: The density of the given sample of hydrogen gas is 0.061 g/L

Explanation:

Assuming ideal gas behavior, the equation follows:

PV = nRT

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

Rearranging the above equation:

[tex]P=\frac{m}{M}\frac{RT}{V}[/tex]

We know that:

[tex]\text{Density}=\frac{\text{Mass}}{\text{Volume}}[/tex]

Rearranging the above equation:

[tex]P=\frac{dRT}{M}[/tex]     ......(1)

We are given:

P = pressure of the gas = 0.799 atm

d = density of hydrogen gas = ?

R = Gas constant = [tex]0.0821\text{ L . atm }mol^{-1}K^{-1}[/tex]

T = temperature of the gas = [tex]47^oC=[47+273]K=320K[/tex]

M = molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1, we get:

[tex]0.799atm=\frac{d\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 320K}{2g/mol}\\\\d=\frac{0.799\times 2}{0.0821\times 320}=0.061g/L[/tex]

Hence, the density of the given sample of hydrogen gas is 0.061 g/L

Answer:

Moles of [tex]ScCl_3[/tex] = 6 moles

Explanation:

The reaction of [tex]Sc[/tex] and [tex]Cl_2[/tex] to make [tex]ScCl_3[/tex] is:

[tex]2Sc+3Cl_2[/tex]⇒[tex]2ScCl_3[/tex]

The above reaction shows that 2 moles of Sc  can react with 3 moles of [tex]Cl_2[/tex] to form [tex]ScCl_3.[/tex]

Mole Ratio= 2:3

For 10 moles of Sc we need:

Moles of [tex]Cl_2[/tex] = [tex]Moles of Sc *\frac{3 moles of Cl_2}{2 Moles of Sc}[/tex]

Moles of [tex]Cl_2[/tex] = [tex]10 *\frac{3 moles of Cl_2}{2 Moles of Sc}[/tex]

Moles of [tex]Cl_2[/tex] =15 moles

So 15 moles of [tex]Cl_2[/tex] are required to react with 10 moles of [tex]Sc[/tex] but we have 9 moles of [tex]Cl_2[/tex] , it means [tex]Cl_2[/tex] is limiting reactant.

[tex]Moles of ScCl_3=Given\ Moles\ of\ Cl_2 *\frac{2\ Moles\ o\ fScCl_3}{3\ Moles\ of\ Cl_2}[/tex]

[tex]Moles\ of\ ScCl_3=9 *\frac{2\ Moles\ of\ ScCl_3}{3\ Moles\ of\ Cl_2}[/tex]

Moles of ScCl_3= 6 moles

Answer:

6.00 moles of ScCl3 will be produced.

Explanation:

Step 1: Data given

Moles of Sc = 10.00 moles

Moles of Cl2 = 9.00 moles

Molar mass of Sc = 44.96 g/mol

Molar mass of Cl2 = 70.9 g/mol

Step 2: The balanced equation

2Sc + 3Cl2 → 2ScCl3

Step 3: Calculate the limiting reactant

For 2 moles Sc we need 3 moles Cl2 to produce 2 moles ScCl3

Cl2 is the limiting reactant. It will completely be consumed (9.00 moles)

Sc is the limiting reactant. There will react 2/3 * 9.00 = 6.00 moles

There will remain 10.00 - 6.00 =4.00 moles Sc

Step 4: Calculate moles ScCl3

For 3 moles Cl2 we'll have 2 moles ScCl3

For 9.00 moles we'll have 6.00 moles of ScCl3

6.00 moles of ScCl3 will be produced.

Answer:

a. Dipole-dipole bonding

Explanation:

SO2 has dipole-dipole bonding. This is because of the difference in the electronegativities  of Sulphur and oxygen. Moreover, the lone pair of electrons on S gives it bent shape with a net dipole  unlike CO2 which has a linear shape.( This why CO2 does not have any dipole moment).

So, the correct answer is a.

Answer:

the pressure P= 40.03 bar

Explanation:

The Van der Waals equation states that

P= R*T/(V-b) - a/V²

where

T= absolute temperature = 295 K

V= molar volume = 0.590 L/mol

R= ideal gas constant = 0.082 atm*L/mol*K

a= van der Waals parameter = 1.355 bar⋅dm⁶/mol² * (0.987 atm/bar) * (1 L²/dm⁶) = 1.337 atm ⋅L²/mol²

b= van der Waals parameter = 0.032 dm³/mol *(1 L/dm³) = 0.032 L/mol

then replacing values

P= R*T/(V-b) - a/V² = 0.082 atm*L/mol*K*295 K/( 0.590 L/mol-0.032 L/mol) -  1.337 atm ⋅L²/mol²/(0.590 L/mol)² = 39.51 atm

P= 39.51 atm / (0.987 atm/bar) = 40.03 bar

Final answer:

To calculate the pressure exerted by Ar using the van der Waals equation of state, substitute the given values for Ar, and solve for the pressure. The equation is P = [RT/(V-b)] - (a/V^2).

Explanation:

To calculate the pressure exerted by Ar using the van der Waals equation of state, we can use the equation:

P = [RT/(V-b)] - (a/V^2)

Where P is the pressure, R is the gas constant, T is the temperature, V is the molar volume, a is the van der Waals constant for the gas, and b is another van der Waals constant for the gas.

Substituting the given values for Ar, we have:

a = 1.355 bar.dm^6.mol^(-2)

b = 0.0320 dm^3.mol^(-1)

V = 0.590 L.mol^(-1)

T = 295 K

Next, we can substitute these values into the equation to calculate the pressure exerted by Ar.

Answer:

Check explanation

Explanation:

During the Electron Transport System occur in the mitochondrial membrane, oxygen in this reaction is been reduced to water and ATPs are being produced.

The quinone form or the oxidized form of Flavin Adenine Dinucleotide(FAD) is the FADH2. While Nicotinamide adenine dinucleotide is the acronym for NADH. NADH is a good donating substance/agent.

It has been observed that FADH2 produce two(2) ATP while NADH produces three(3) ATP. The reason for this observation is that the production of electron in the FADH2 is at the lower enegy level. Because of this it can not transfer its electron to the first complex .

While;

NADH is at the higher energy level and it can directly transfer its electron to the first complex.

FADH2 oxidation yields one less ATP than NADH oxidation in the ETC because it enters at a lower energy Complex II, bypassing Complex I, and thus pumps fewer protons across the mitochondrial membrane, leading to the generation of fewer ATPs.

The observation that FADH2 oxidation yields one less ATP than NADH oxidation by the Electron Transport System (ETC) is explained by their respective entry points and roles in the ETC. Electrons from NADH enter at Complex I, pumping protons through complexes I, III, and IV, thus contributing to a higher proton gradient than electrons from FADH2, which enter at Complex II. Since FADH2 bypasses Complex I, it results in the pumping of fewer protons across the mitochondrial membrane, which subsequently leads to the generation of fewer ATPs during oxidative phosphorylation. Complex II directly receives electrons from the oxidation of FADH2, bypassing the first proton pump of the ETC, and as a result, less ATP is produced.

During the catabolism of glucose, a net total of 36 ATP are produced from glycolysis, the citric acid cycle, and the ETC. This includes the production of three ATPs for every NADH oxidized and two ATPs for every FADH2. The difference in ATP yield is due to the point at which each carrier donates its electrons to the ETC.

Final answer:

The factors to consider when choosing the ideal solvent for crystallization include solubility properties, intermolecular forces, polarity, and solvent properties such as reactivity, cost, toxicity, and boiling point.

Explanation:

When choosing the ideal solvent for the crystallization of a particular compound, several factors should be taken into consideration:

Alumina, corundum, and bauxite contain significant amounts of aluminum oxide. Alumina is a form of aluminum oxide, corundum is a crystalline form that usually contains traces of other elements, and bauxite is the principal ore of aluminum.

The substances which contain significant amounts of aluminum oxide are alumina, corundum, and bauxite.

Alumina, by its nature, is a form of aluminum oxide. Corundum is a crystalline form of aluminum oxide and typically contains traces of iron, titanium, vanadium, and chromium. Bauxite is the principal ore of aluminum and it primarily consists of one or more aluminum hydroxide minerals, which are often structurally composed of aluminum oxide.

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Answer:

(a) Atomic Mass = 35.24

(b) 2.95x10²¹ Cl₂ molecules

Explanation:

In the attached picture you may read your question, written in a different format.

(a) We calculate the atomic weight of the enriched Cl using the abundances and masses of the isotopes:

(b) We use the previously calculated atomic mass and use it as molar mass (35.24 g/mol), alongside Avogadro's number:

Final answer:

Option A is the correct answer .The crystalline solid described is a network covalent solid, which is characterized by a three-dimensional network of covalent bonds, leading to features like exceptional hardness and high melting points.

Explanation:

A crystalline solid with a high melting point and held together with covalent bonds is an example of a network covalent solid. These solids are formed by atoms that are covalently bonded in a large, continuous three-dimensional network. Network covalent solids, which include materials like diamond and silicon dioxide, are known for their hardness, strength, and very high melting points, often requiring the breaking of strong covalent bonds to melt or to break the solid.

Unlike ionic and metallic solids, network covalent solids are poor conductors of electricity, as they are made up of neutral atoms instead of charged ions. These properties make network covalent solids distinct from other types of crystalline solids, which include ionic, molecular, and metallic solids, each characterized by their own unique bonding and structural features.

Answer: unit conversions can be done either simultaneously or separately

Explanation:

Dimensional analysis involves converting units within a singular calculation. It is a technique used frequently in fields like physics and engineering. Conversion factors in terms of desired and given units are used in the process.

When computing using dimensional analysis, all unit conversions must be done in a singular calculation. Dimensional analysis is a mathematical method often used in physics and engineering, and it provides a means of converting from one unit to another.

In the process of dimensional analysis, we use conversion factors that are expressed in terms of the desired unit and the given unit.

It is specifically helpful when you want to convert from one system of measurement to another, or when you need to solve a complex problem involving several different units.

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Answer:

NH3 is the limiting reactant. O2 is in excess and there will remain 0.224 grams O2

Explanation:

Step 1: Data given

Mass of NH3 = 2.25 grams

Mass of O2 = 3.38 grams

Volume of N2 = 0.450 L

Temperature = 295 K

Pressure = 1.00 atm

Molar mass NH3 = 17.03 g/mol

Molar mass O2 = 32 g/mol

Molar mass of N2 = 28 g/mol

Molar mass of H2O = 18.02 g/mol

Step 2: The balanced equation

4NH3 + 3O2 → 2N2 + 6H2O

Step 3: Calculate moles NH3

Moles NH3 = mass NH3 / molar mass NH3

Moles NH3 = 2.25 grams / 17.03 g/mol

Moles NH3 = 0.132 moles

Step 4: Calculate moles O2

Moles O2 = mass O2  / molar mass O2

Moles O2 = 3.38 grams / 32 g/mol

Moles O2 = 0.106 moles

Step 5: Calculate limiting reactant

For 4 moles NH3 we need 3 moles O2 to produce 2 moles N2 and 6 moles H2O

NH3 is the limiting reactant. It will completely be consumed (0.132 moles)

O2 is in excess. There will react 3/4 * 0.132 = 0.099 moles O2

There will remain 0.106 -0.099 = 0.007 moles O2

This is 0.007 moles * 32 g/mol = 0.224 grams

NH3 is the limiting reactant. O2 is in excess and there will remain 0.224 grams O2

The question is incomplete, here is the complete question:

An aqueous solution at 25°C has a [tex]H_3O^+[/tex] concentration of [tex]8.8\times 10^{-12}M[/tex] . Calculate the [tex]OH^-[/tex] concentration. Be sure your answer has the correct number of significant digits.

Answer: The hydroxide ion concentration of the solution is [tex]0.1\times 10^{-2}M[/tex]

Explanation:

To calculate the pH of the solution, we use the equation:

[tex]pH=-\log[H_3O^+][/tex]

We are given:

[tex][H_3O^+]=8.8\times 10^{-12}M[/tex]

Putting values in above equation, we get:

[tex]pH=-\log (8.8\times 10^{-12})\\\\pH=11.05[/tex]

To calculate the hydroxide ion concentration, we first calculate pOH of the solution, which is:

pH + pOH = 14

[tex]pOH=14-11.05=2.95[/tex]

To calculate hydroxide ion concentration of the solution, we use the equation:

[tex]pOH=-\log[OH^-][/tex]

We are given:

pOH = 2.95

Putting values in above equation, we get:

[tex]2.95=-\log[OH^-][/tex]

[tex][OH^-]=10^{-2.95}[/tex]

[tex][OH^-]=1.12\times 10^{-3}M=0.1\times 10^{-2}M[/tex]

Hence, the hydroxide ion concentration of the solution is [tex]0.1\times 10^{-2}M[/tex]

Answer:

35.6 g of W, is the theoretical yield

Explanation:

This is the reaction

WO₃  +  3H₂  →   3H₂O  +  W

Let's determine the limiting reactant:

Mass / molar mass = moles

45 g / 231.84 g/mol = 0.194 moles

1.50 g / 2 g/mol = 0.75 moles

Ratio is 1:3. 1 mol of tungsten(VI) oxide needs 3 moles of hydrogen to react.

Let's make rules of three:

1 mol of tungsten(VI) oxide needs 3 moles of H₂

Then 0.194 moles of tungsten(VI) oxide would need (0.194  .3) /1 = 0.582 moles (I have 0.75 moles of H₂, so the H₂ is my excess.. Then, the limiting is the tungsten(VI) oxide)

3 moles of H₂ need 1 mol of WO₃ to react

0.75 moles of H₂ would need (0.75 . 1)/3 = 0.25 moles

It's ok. I do not have enough WO₃.

Finally, the ratio is 1:1 (WO₃ - W), so 0.194 moles of WO₃ will produce the same amount of W.

Let's convert the moles to mass (molar mass  . mol)

0.194 mol . 183.84 g/mol = 35.6 g

Explanation:

According to Lewis, acids are the species which readily accept electrons. Whereas bases are the species which donate electrons to electron deficient or electropositive ions.

Out of the given options, boron of [tex]BBr_{3}[/tex] and carbon of [tex](CH_{3})_{3}C^{+}[/tex] contain sextet of electrons. This means that they have accepted electrons from the combining atoms.

Thus, we can conclude that out of the given options [tex]BBr_{3}[/tex] and [tex](CH_{3})_{3}C^{+}[/tex] compounds can be labeled as Lewis acids.

BBr3 and (CH3)3C+ are the compounds that can be labeled as Lewis acids because they can accept a pair of electrons due to having an incomplete octet and a positively charged center respectively.

In the context of Lewis acid-base theory, a Lewis acid is a compound that can accept a pair of electrons, while a Lewis base is one that can donate a pair of electrons. Considering the options given:

Thus, BBr3 and (CH3)3C+ can be labeled as Lewis acids.

Answer:

B. only one copy of the field in memory

Explanation:

A static method is sort of a description of a class but is not part of the objects that it generates. Crucial: A program may perform a static method without constructing an object first! All other functions (those not static) only occur when they're member of an object. Thus it is necessary to build an object before they could be executed.

Therefore, when an static field is declared static, there will be:

B. only one copy of the field in memory

Answer: The molar mass of the unknown solute is 35.8 g/mol

Explanation:

Depression in freezing point is given by:

[tex]\Delta T_f=i\times K_f\times m[/tex]

[tex]\Delta T_f=T_f^0-T_f=(0-(-2.60))^0C=2.60^0C[/tex] = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

[tex]K_f[/tex] = freezing point constant = [tex]1.86^0C/m[/tex]

m= molality

[tex]\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}[/tex]

Weight of solvent (water)=[tex]density\times volume =1.00g/ml\times 100ml=100g=0.1kg[/tex]      (1kg=1000g)

Molar mass of unknown non electrolyte = M g/mol

Mass of unknown non electrolyte added = 5.00 g

[tex]2.60=1\times 1.86\times \frac{5.00g}{M g/mol\times 0.100kg}[/tex]

[tex]M=35.8g/mol[/tex]

The molar mass of the unknown solute is 35.8 g/mol

The molar mass of the unknown nonelectrolytic solute is found through computing freezing point depression and molality, resulting in a molar mass of approximately 35.71 g/mol.

To solve this problem, we need to first determine the freezing point depression. Normal freezing point of water is 0°C but in this case, it is -2.60°C, hence the depression is 2.60°C. We also use the known value of the molal freezing point depression constant for water (1.86°C/m).

The formula for freezing point depression is ΔTF = KF * m, where m is the molality of the solution. By re-arranging this equation to solve for molality (m), we get m = ΔTF / KF.

Substituting the known values: m = 2.60°C / 1.86°C/m = 1.40 m. Molality means moles of solute per kilogram of solvent. In this case, we have 100 mL of water, or 0.1 kg. Therefore, the number of moles = 1.40 mol/kg * 0.1 kg = 0.14 mol.

To find the molar mass, we know that mass = number of moles * molar mass. Again, rearranging to solve for molar mass, we find that molar mass = mass / number of moles. So, substituting the known values, molar mass = 5.00g / 0.14 mol = approximately 35.71 g/mol.

Therefore, the molar mass of the unknown nonelectrolytic solute is approximately 35.71 g/mol.

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