Answer:
4+5=9 amu
Explanation:
Together, the number of protons and the number of neutrons determine an element's mass number: mass number = protons + neutrons.
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A car in a movie moving at 20 m/s flies off a cliff that is 74.3m tall. How long is the car in the air for and how far does the car travel before it hits the ground below?
The time the car, moving at 20 m/s, is in the air after flying off a 74.3m cliff is approximately 3.88 seconds. Within that time, it travels about 77.6 meters horizontally before hitting the ground.
Explanation:Using the concepts of gravity and projectile motion, the time the car, moving at 20 m/s, is in the air after flying off a 74.3m cliff is approximately 3.88 seconds.
To find the time the car is in the air, we use the formula for time in free fall, t = sqrt(2h/g), where h is the height the car falls, and g is the acceleration due to gravity. So, t = sqrt((2 * 74.3m) / 9.8m/s²), roughly giving t = 3.88 seconds.
To find the horizontal distance the car travels before hitting the ground, we use the formula x = vt, where v is the initial horizontal velocity and t is the time of flight. So, x = 20 m/s * 3.88 s, roughly equals 77.6 meters.
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What kind of front involves three air masses of different temperatures?
An occluded front involves three air masses of different temperatures: two cold air separated by a warm air .
What is occluded front?Due to different densities, when big amounts of warm and cold air collide, they do not mix. They instead create a front that is typically hundreds of miles long. When a warm air mass is sandwiched between two cold air masses, an occluded front forms. As the cool air masses collide in the centre, the warm air mass rises. As the warm air mass is "cut off" from the earth and forced upward, the temperature decreases. Such fronts have the potential to produce violent winds and copious rain.
Typically, mature low pressure zones are where occluded fronts form.
Early occlusion of an extratropical cyclone in the Northern Hemisphere
Occlusion comes in two flavours, warm and cold:
In a cold occlusion, the cool air mass in front of the warm front is pushed aside by the cold air mass that is overtaking it because it is colder.In a warm occlusion, the warm air is lifted by the warm front's overtaking cold air mass, which is warmer than the cool air ahead of the warm front.Learn more about occluded front here:
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Refer to Explorations in Literature for a complete version of this story. How does Lizabeth interact with Miss Lottie in "Marigolds"?
A) Lizabeth is intrigued by Miss Lottie and her marigolds, so she enjoys going by Miss Lottie's house to see her garden.
B) Lizabeth thinks Miss Lottie and her marigolds are strange, and her frustration with her own life drives Lizabeth to destroy the woman's flowers.
C) Lizabeth knows that Miss Lottie doesn't like to be bothered, but she encourages the other children to tease the woman.
D) Lizabeth is afraid of Miss Lottie because she thinks the old woman is a witch, so she avoids her house.
The answer is: B) Lizabeth thinks Miss Lottie and her marigolds are strange, and her frustration with her own life drives Lizabeth to destroy the woman's flowers.
Lizbeth was depicted as an immature character that hates her condiiton and the place where she lived in. When she saw Miss Lottie taking care of the marigold flower, she could not understand why these poor woman had enough passion to take care of the wild flowers despite the horrid situations that she had and not miserable like her. This led her to destroy the flowers.
Assume that on a physics diagram, you saw a croquet ball moving along the grass and above it was an arrow labeled "3.5 m/s" that indicated BOTH the speed and direction of the ball. This is an arrow is a(n) _____.
Force arrow
Acceleration arrow
Speed arrow
Vector
Answer:
a vector.
Explanation:
The arrow labeled '3.5 m/s' in the given scenario, which denotes both the speed and direction of a croquet ball, is called a vector. A vector, in physics, represents a quantity showcasing both magnitude (in this case, velocity measured as '3.5 m/s') and direction.
Explanation:In the context of the question, the arrow labeled '3.5 m/s' that is indicating both the speed and the direction of the croquet ball is known as a vector. In physics, a vector is a quantity that possesses both magnitude (size or quantity) and direction. In this case, the '3.5 m/s' is the magnitude of the vector (the speed of the ball), and the direction the arrow is pointing indicates the direction the ball is moving. This is as opposed to a scalar quantity, which only has magnitude.
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Earth has an abundant amount of iron, but also has many elements heavier than iron. Form a hypothesis
The earth has many elements heavier than iron due to the hypothesis that the explosions of sun have become more massive to man kind over a period of time, thus creating heavier elements found on Earth.
Heavy elements found on earthHeavy elements such iron are formed by nuclear fusion reaction. Example include the heavy element of iron.
Source of these heavy elements are:
geogenic, industrial, agricultural, pharmaceutical,domestic effluents, and atmospheric sources.Many elements that are heavier than iron has been formed over the years due to the sun explosions.
The formation of these heavy elements occurs due to the process called neutron capture, where neutrons penetrate an atomic nucleus in explosions of the sun.
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A satellite makes 16 orbits around the earth in one day. What is the period of it orbit?
An old truck compresses a spring scale at the junkyard by 25 cm. The spring constant for the industrial scale at the junkyard is 39,200 N/m.
What is the force applied to the scale by the car?
_____N
Answer:
Force, F = 9800 N
Explanation:
It is given that,
The spring constant for the industrial scale at the junkyard is, k = 39,200 N/m
The compression in the spring, x = 25 cm = 0.25 m
To find,
The force applied to the scale by the car.
Solution,
The Hooke's law gives the relation between the force and the compression in the spring. Its expression is given by :
[tex]F=-kx[/tex]
[tex]F=39200\times 0.25[/tex]
F = 9800 N
So, the force applied to the scale by the car is 9800 N.
Two carts, a and b, are connected by a rope 39 ft long that passes over a pulley p. the point q is on the floor h = 12 ft directly beneath p and between the carts. cart a is being pulled away from q at a speed of 3 ft/s. how fast is cart b moving toward q at the instant when cart a is 5 ft from q? (round your answer to two decimal places.)
To find the speed at which cart B is moving toward point q, we can set up a proportion using the distances and speeds of the two carts connected by a rope. By substituting the known values into the equation, we can solve for the speed of cart B.
Explanation:To find the speed at which cart B is moving toward point q, we can use the concept of relative motion. Since there is a rope connecting the carts, their speeds are related. We can set up a proportion using the distances and speeds:
(Distance traveled by cart A) / (Speed of cart A) = (Distance traveled by cart B) / (Speed of cart B)
Since we know that cart A is being pulled away from q at a speed of 3 ft/s and is 5 ft from q, we can substitute these values into the equation and solve for the speed of cart B:
(5 ft) / (3 ft/s) = (Distance traveled by cart B) / (Speed of cart B)
From here, we can solve for the speed of cart B.
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how can two tectonic plates move relative to each other
Bernoulli's principle describes the property of a(n) _________.
Final answer:
Bernoulli's principle describes the relationship between pressure and velocity in fluids and is applicable in various fluid flow situations.
Explanation:
Bernoulli's principle describes the property of a fluid where there is an inverse relationship between the pressure and velocity of the fluid. According to Bernoulli's equation, for an incompressible, frictionless fluid, the sum of pressure, kinetic energy, and potential energy per unit volume is constant. This principle is applicable in various situations involving fluid flow, such as in the analysis of fluid devices and systems.
Bernoulli's principle serves as a fundamental concept in fluid dynamics, providing insights into the interplay between pressure and velocity within a flowing fluid. Its application extends to understanding phenomena like lift in aviation, the operation of carburetors, and the behavior of blood flow in arteries. By recognizing the conservation of energy in fluid motion, Bernoulli's principle contributes to the analysis and design of fluid-based systems across diverse fields.
You have landed on an unknown planet, newtonia, and want to know what objects will weigh there. you find that when a certain tool is pushed on a frictionless horizontal surface by a 12.7 n force, it moves 16.1 m in the first 2.50 s , starting from rest. you next observe that if you release this tool from rest at 10.3 m above the ground, it takes 2.88 s to reach the ground.
Final answer:
The question involves applying Newton's laws of motion and universal gravitation in a physics context to determine the gravitational acceleration and accordingly the weight of objects on an unknown planet.
Explanation:
The situation described involves calculating forces and understanding the principles of motion and gravity on an unknown planet, which falls under the subject of physics. Specifically, it looks at the application of Newton's laws of motion and universal gravitation.
Using the given information from the question, we can deduce certain characteristics of the planet's gravitational field. The force exerted, in combination with the mass of the tool and distance traveled, allows us to calculate acceleration using Newton's second law of motion, F = ma. Additionally, the time taken for the object to fall a certain distance on this planet will enable us to determine the planet's gravitational acceleration, which can be compared to Earth's acceleration due to gravity of approximately 9.80 m/s².
It is important to calculate the acceleration correctly because it impacts subsequent calculations involving force and weight. For instance, with Newton's second law, the net force on a free-falling object without air resistance is simply its weight. This relationship is crucial for determining an object's weight on the unknown planet.
To apply these principles to the scenario, it is essential to use the provided data to determine the gravitational acceleration on the unknown planet. Let's take the second part of the question, which describes an object falling from a given height in a specific amount of time. This would directly give us the gravitational acceleration of the planet, using the formula for the motion of objects under gravity: s = ut + ½at². Once we have the gravitational acceleration, we could then find the weight of objects on the planet using the formula w = mg.
When water has a temperature greater than 100c?
Find the density of a 5 kg solid cylinder. the cylinder is 5 cm tall and has a radius of 2 cm.
A 4-kg ball has a momentum of 12 kg∙m/s. what is the ball's speed?
What is the relationship between mass and momentum? Be specific as you describe the relationship between mass and linear momentum as well as how mass affects the moment of inertia in angular momentum.
What is the wavelength of light emitted when the electron in a hydrogen atom moves from the n=5 state to the n=2 state? give your answer in nm?
A horizontal force of 30 n pulls a block of mass 2.5 kg across a level floor. the coefficient of kinetic friction between the block and the floor is μk = 0.25. if the block begins with a speed of 7.0 m/s and is pulled for a distance of 14 m, what is the final speed of the block?
The final speed is approximately 17.79 m/s. The final speed of the block is determined by calculating the net force and resulting acceleration, then using kinematic equations.
Final Speed of the Block
To determine the final speed of the block, we first need to calculate the net force acting on the block. Given:
Horizontal force (F) = 30 NMass of the block (m) = 2.5 kgInitial speed [tex](v_0) = 7.0 m/s[/tex]Coefficient of kinetic friction [tex](\mu_k) = 0.25[/tex]Distance (d) = 14 mThe force of kinetic friction (Ffriction) is calculated as:
[tex]F_{friction} = \mu_k \times N[/tex]
Where N is the normal force, and on a level floor N = mg:
[tex]N = m \times g = 2.5 kg \times 9.8 m/s^2 = 24.5 N[/tex]
Thus, the force of friction:
[tex]F_{friction} = 0.25 \times 24.5 N = 6.125 N[/tex]
The net force (F_{net}) acting on the block is:
[tex]F_{net} = F - F_{friction} = 30 N - 6.125 N = 23.875 N[/tex]
Using Newton's second law (F = ma) to find acceleration (a):
[tex]a = F_{net} / m = 23.875 N / 2.5 kg = 9.55 m/s^2[/tex]
We use the kinematic equation to find the final speed (v):
[tex]v^2 = v_0^2 + 2ad\\v = \sqrt{((7.0 m/s)^2 + 2 \times 9.55 m/s^2 \times 14 m)} = \sqrt{(49 + 267.4)} = \sqrt{(316.4)} = 17.79 m/s[/tex]
Therefore, the final speed of the block is approximately 17.79 m/s.
Metamorphic rocks may generally be distinguished from igneous rocks because
Use the equation in the sample problem on the previous page to find the area of a rectangle that is 48.5 cm long and 3.77 cm wide. Round your answer to the correct number of significant figures.
The area of a rectangle with dimensions 48.5 cm by 3.77 cm is 182.865 cm², which is rounded to 183 cm² to maintain three significant figures.
To find the area of a rectangle with the dimensions 48.5 cm in length and 3.77 cm in width, we use the formula for the area of a rectangle, which is length x width. Multiplying the length by the width, we get:
48.5 cm x 3.77 cm = 182.865 cm²
When rounding this to the correct number of significant figures, we have to consider that the length and width measurements were given to three and three significant figures, respectively. Therefore, the area should also be reported to three significant figures:
The area rounded to three significant figures is 183 cm².
if a car decelerates at a rate of 5.1 m/s, and its initial speed was 24 m/s. how long will it take the car to stop?
Final answer:
The car will take approximately 4.71 seconds to stop.
Explanation:
To find out how long it will take for the car to stop, we can use the equation:
Final velocity = initial velocity + (acceleration × time)
In this case, the final velocity is 0 m/s (since the car stops), the initial velocity is 24 m/s, and the acceleration is -5.1 m/s² (since the car is decelerating).
Plugging in these values, we have:
0 m/s = 24 m/s + (-5.1 m/s² × time)
Simplifying this equation, we get:
-5.1 m/s² × time = -24 m/s
Dividing both sides by -5.1 m/s², we find that:
time = 4.71 seconds
So, it will take approximately 4.71 seconds for the car to stop.
As you move from left to right on the periodic table, what generally happens to the electronegativity? *
A study showed that children who watch more than 5 or more hours of television a day have lower grades than children who watch less. Which of these could be a hidden variable
The answer is D
Children who watch more television may have parents who are home less often to help them with schoolwork
The strength of the electric field 0.5 m from a 6 µC charge is positive N/C. (Use k = 8.99 × 109 N• and round answer to the nearest whole number.)
Answer:
[tex]2.16 \cdot 10^5 N/C[/tex]
Explanation:
The strength of the electric field produced by the single charge is given by
[tex]E=\frac{kq}{r^2}[/tex]
where
[tex]k=8.99\cdot 10^9 N m^2 C^{-2}[/tex] is the Coulomb's constant
[tex]q = 6 \mu C = 6 \cdot 10^{-6} C[/tex] is the charge
[tex]r = 0.5 m[/tex] is the distance from the charge at which we want to calculate the field strength
Substituting the numbers into the equation, we find
[tex]E=\frac{(8.99\cdot 10^9 )(6 \cdot 10^{-6} C)}{(0.5 m)^2}=2.16\cdot 10^5 N/C[/tex]
If you have an effusive personality, then it __________ of you. motor oil will __________ across the gravel if it spills out of the can.
Which kelvin temperature is equivalent to â24°c?
What happens to static and kinetic friction as mass increases?
What is the biggest source of air pollution? power plants agriculture motor vehicles industry
Answer:
Moto vehicles
Explanation:
Does the coefficient of kinetic friction depend on the weight of the block
The coefficient of kinetic friction is independent of an object's weight and depends on the two contact surfaces. Actual frictional force increases with weight due to its dependence on the normal force. Weight influences the tension in a string due to the effect of friction on net force.
Explanation:The coefficient of kinetic friction (μk) is a value that describes how much frictional resistance is encountered by two surfaces sliding past one another. It is independent of the weight of the block and solely depends on the properties of the two contact surfaces. However, the actual frictional force, which is the product of the coefficient of kinetic friction and the normal force, does depend on the weight of the block because the normal force is equal to the weight of the block when the block is on a horizontal surface.
Given the mass (M) of the larger block and the force (F), you are looking to find the tension in the string that connects it to another block. The kinetic friction value affects the calculation of the net force and therefore influences the tension in the string.
What is the input and output of a microwave?
(ii) a woman stands on a bathroom scale in a motionless elevator. when the elevator begins to move, the scale briefly reads only 0.75 of her regular weight. calculate the acceleration of the elevator, and find the direction of acceleration.
Final answer:
To calculate the acceleration of the elevator when a woman's weight reads 0.75 of her regular weight, we use Newton's second law, resulting in an acceleration of -2.45 m/s². This indicates that the elevator is accelerating downwards or decelerating while moving upwards.
Explanation:
If a woman standing on a bathroom scale in an elevator observes that the scale reads only 0.75 of her regular weight, it means that the net force acting on her is reduced because the elevator is accelerating.
To calculate the acceleration of the elevator, we can use Newton's second law of motion and some assumptions about gravitational acceleration (g = 9.8 m/s2).
Let's denote the woman's mass as m, her regular weight as W = mg (where g is the acceleration due to gravity), and the scale reading when the elevator accelerates as 0.75W. When the elevator is accelerating, the apparent weight (scale reading) is W' = 0.75mg.
The net force (Fnet) acting on the woman in the elevator is her apparent weight, W', minus her actual weight, W, leading to Fnet = ma. Therefore:
Fnet = W' - W
ma = 0.75mg - mg
a = 0.75g - g = -0.25g
This gives us a = -0.25(9.8 m/s2) = -2.45 m/s2. The negative sign indicates that the acceleration is directed downwards - meaning that the elevator is accelerating downward or decelerating while going up.