An animal shelter spends $4.50 per day to care for each cat and $8.00 per day to care for each dog. Savannah noticed that the shelter spent $123.00 caring for cats and dogs on Tuesday. Savannah found a record showing that there were a total of 25 cats and dogs on Tuesday. How many cats were at the shelter on Tuesday​

Answer:

The Inequality that shows number of hours Tabitha will need to work to have enough money to buy the tablet is [tex]75+8.5x\geq 306.34[/tex].

Tabitha needs to work at least 28 hours to buy the tablet.

Step-by-step explanation:

Amount earn per hour = $8.50

Amount already saved = $75

Cost of tablet = $289

Sales tax = 6%

We to write and solve the inequality number of hours Tabitha will need to work to have enough money to buy the tablet.

Solution:

Let the number of hours she need to work be 'x'.

First we will find the total amount required to buy tablet.

Amount of sales tax = [tex]\frac{6}{100}\times289 = \$17.34[/tex]

Now Total cost to buy tablet will be equal to sum of Cost of tablet and Amount of sales tax.

framing in equation form we get;

Total cost to buy tablet = [tex]289+17.34 = \$306.34[/tex]

Now we can say that;

Amount already saved plus Amount earn per hour multiplied by Amount earn per hour should be greater than or equal to Total cost to buy tablet.

framing in equation form we get;

[tex]75+8.5x\geq 306.34[/tex]

hence The Inequality that shows number of hours Tabitha will need to work to have enough money to buy the tablet is [tex]75+8.5x\geq 306.34[/tex].

On solving the above Inequality we get;

First we will subtract both side by 75 we get;

[tex]75+8.5x-75\geq 306.34-75\\\\8.5x\geq 231.34[/tex]

Dividing both side by 8.5 we get;

[tex]\frac{8.5x}{8.5}\geq \frac{231.34}{8.5}\\\\x\geq 27.21[/tex]

Hence Tabitha needs to work at least 28 hours to buy the tablet.

Answer:

The co - ordinates of another end point is

(x,y) = (3, 12)

Step-by-step explanation:

step :-

mid point formula:-

Let [tex](x_{1} ,y_{1} ) and (x_{2} ,y_{2} )[/tex] be any two end points

Mid point of two given points are

[tex](\frac{x_{1}+x_{2} }{2} , \frac{y_{1}+y_{2} }{2} )[/tex]

let (x,y ) be the another end point

given one end point is (5,-6)

now by using mid-point formula , we get

[tex](\frac{x+5}{2} , \frac{y-6}{2} )[/tex]  this is equating to given mid-point is M(4,3)

now [tex](\frac{x+5}{2} , \frac{y-6}{2} )=(4,3)[/tex]

simplify , we get

[tex]\frac{x+5}{2} =4 and \frac{y-6}{2} =3[/tex]

cross multiplication and simplify

[tex]x+5 = 8 and y-6=6[/tex]

x = 3 and y = 12

The another point is (x,y) = (3,12)

Answer:

4y+14m+1

Step-by-step explanation:

Remove the brackets

-3y-5+5m+7y+6+9m

Rearrange the terms

7y-3y+5m+9m+6-5

Adding like terms

4y+14m+1

Answer:

Step-by-step explanation:

it seems to me that if he wants the same rate of acceleration as the first trip, then he would need the same amount of soil as the first trip.

Therefore, he should reduce the amount of soil by one half and apply the same force. <====

Because the first time it was half full.....and since the second trip was all the way full, if he reduced it by one half, it would contain the same amount as the first trip....so he can then get the same rate of acceleration.

Answer:

A.

Step-by-step explanation:

According to Newton's second law of motion, an object with a larger mass requires more force to accelerate it at a certain rate than an object with less mass. This means that an object with a larger mass requires more force to accelerate.

To move the wheelbarrow at the same rate of acceleration for the second trip, the amount of soil must be the same as in the first trip. Since the gardener first filled only one-half of the wheelbarrow with soil, the gardener must reduce the amount of soil by one-half and apply the same amount of force.

Option "D. y=x−12" and "E. y=1/4x" are the functions whose graphs include the point (16,4)

Step-by-step explanation:

In order to find the functions whose graph includes the point we will put the point in the functions one by one

So,

A. y=2x

Putting x = 16 and y = 4

[tex]4 = 2(16)\\4\neq 32[/tex]

B. y=x^2

Putting x= 16 and y=4

[tex]4 = (16)^2\\4 \neq 256[/tex]

C. y=x+12

Putting x= 16 and y=4

[tex]4 = 16+12\\4 \neq 28[/tex]

D. y=x−12

Putting x= 16 and y=4

[tex]4 = 16-12\\4 = 4[/tex]

E. y=1/4x

Putting x= 16 and y=4

[tex]4 = \frac{1}{4} * 16\\4 = 4[/tex]

Hence,

Option "D. y=x−12" and "E. y=1/4x" are the functions whose graphs include the point (16,4)

Keywords: Functions, graphing

Learn more about functions at:

#learnewithBrainly

Answer:

Step-by-step explanation:

The answers are D and E

Answer:

Nonrigid

Segment lents are not

Step-by-step explanation:

Answer:

answer in picture

Step-by-step explanation:

Answer:

16,055/16 = 1003

The remainder would be 7

Step-by-step explanation:

Answer:

119.5

Step-by-step explanation:

Answer:

Step-by-step explanation:

a - 7 = 3(b + 2)

a - 7 = 3b + 6

a - 7 - 6 = 3b

a - 13 = 3b

(a - 13) / 3 = b <====

Answer:

-13-1/4 b

Step-by-step explanation:

b is on the outside of the fraction not with the four.

-13-\frac{1}{4b}

Answer:

36

Step-by-step explanation:

To obtain the required number, multiply 27 by the inverse of [tex]\frac{3}{4}[/tex]

The inverse of [tex]\frac{3}{4}[/tex] is [tex]\frac{4}{3}[/tex] ( fraction turned upside down ), thus

[tex]\frac{4}{3}[/tex] × 27 ← divide 3 and 27 by 3

= 4 × 9 = 36

Answer:

1. X= 25.9 meters

2.X= 21.3 meters

Step-by-step explanation:

1. Tan 50°= X/21

2. Tan 12°= X/100

Answer:

[tex]5 \sqrt{5} [/tex]

Step-by-step explanation:

We want to find the distance between (-8,-4) and (2,-9).

We use the distance formula:

[tex]d = \sqrt{ {(x_2-x_1)^2} +(y_2-y_1)^2 } [/tex]

We substitute the coordinates to get:

[tex]d = \sqrt{ {(2- - 8)^2} +( - 9 - - 4)^2 } [/tex]

We simplify to obtain:

[tex]d = \sqrt{ {(2 + 8)^2}+( - 9 + 4)^2 } [/tex]

Add the numbers within the parenthesis to get:

[tex]d = \sqrt{ {(10)^2}+( -5)^2 } [/tex]

Find the squares of the numbers under the radical

[tex]d = \sqrt{ {100}+25} [/tex]

[tex]d = \sqrt{125} = 5 \sqrt{5} [/tex]

Answer:

The  length of the rectangle is[tex](4+7y^3)[/tex] and its  width is[tex]3y^2[/tex]

Step-by-step explanation:

Given:

The Area of the rectangle =[tex]12y^2+21y^5[/tex].

Width is the greatest common factor of  [tex]12y^2[/tex] and[tex]21y^5[/tex]

To Find:

The length and width of the rectangle = ?

Solution:

Step 1: Finding the greatest common factor of [tex]12y^2[/tex]and[tex]21y^5[/tex]

[tex]12 y^2[/tex]= 2 x 3 x 3 x y x y

[tex]21y^5[/tex] = 3 x 7 x y x y x y x y x y

Thus the greatest common factor is [tex]3y^2[/tex] which is the width

Step 2: Finding the length and width

The area of the rectangle  = length x breath

width x length=  [tex]12y^2+21y^5.[/tex]

Taking[tex]3y^2[/tex] commonly from each term, we get

width x length= [tex](3y^2)(4 + 7y^3)[/tex]

Answer:

7j+7

Step-by-step explanation:

2j+4j+j+7

combine like terms

7j+7

Sorry I don't really know how to explain it, but you just have to combine terms with the same unit

Answer:

[tex]5[/tex]

First Method:

This isn't the only method, but it seems the least likely to result in an incorrect answer.

If [tex]x=1[/tex] and [tex]y=-2[/tex], find the solution to:

[tex]3xy+7x^2-3x^2y+3y^2x-2x^2-2xy+4x^2y-2y^2x[/tex]

[tex]3xy+7x^2-3x^2y+3y^2x-2x^2-2xy+4x^2y-2y^2x\\3(1)(-2)+7(1)^2-3(1)^2(-2)+3(-2)^2(1)-2(1)^2-2(1)(-2)+4(1)^2(-2)-2(-2)^2(1)[/tex]

[tex]3(-2)+7-3(-2)+3(-2)^2-2-2(-2)+4(-2)-2(-2)^2[/tex]

[tex]3(-2)+7-3(-2)+3(-2)^2-2-2(-2)+4(-2)-2(-2)^2[/tex]

[tex]3(-2)+7-3(-2)+3(4)-2-2(-2)+4(-2)-2(4)[/tex]

[tex]3(-2)+7-3(-2)+3(4)-2-2(-2)+4(-2)-2(4)\\-6+7-3(-2)+3(4)-2-2(-2)+4(-2)-2(4)\\-6+7+6+3(4)-2-2(-2)+4(-2)-2(4)\\-6+7+6+12-2-2(-2)+4(-2)-2(4)\\-6+7+6+12-2+4+4(-2)-2(4)\\-6+7+6+12-2+4-8-2(4)\\-6+7+6+12-2+4-8-8\\[/tex]

[tex]-6+7+6+12-2+4-8-8\\7+4+6+12-6-2-8-8\\11+18-8-16\\29-24\\5[/tex]

Our final answer is [tex]5[/tex].

Here's another method:

If [tex]x=1[/tex] and [tex]y=-2[/tex], find the solution to:

[tex]3xy+7x^2-3x^2y+3y^2x-2x^2-2xy+4x^2y-2y^2x[/tex]

[tex]3xy+7x^2-3x^2y+3y^2x-2x^2-2xy+4x^2y-2y^2x\\3(1)y+7(1)^2-3(1)^2y+3y^2(1)-2(1)^2-2(1)y+4(1)^2y-2y^2(1)\\[/tex]

[tex]3(1)y+7(1)^2-3(1)^2y+3y^2(1)-2(1)^2-2(1)y+4(1)^2y-2y^2(1)\\3y+7-3y+3y^2-2-2y+4y-2y^2\\3y^2-2y^2+3y-3y-2y+4y+5\\y^2+2y+5[/tex]

[tex]y^2+2y+5\\(-2)^2+2(-2)+5\\4-4+5\\5[/tex]

Answer:

Therefore,

[tex]Discriminant=-3[/tex]

Step-by-step explanation:

Given:

[tex]7x^{2}-5x+1=0[/tex]

To Find:

Discriminant = ?

Solution:

For a Quadratic Equation ax²+bx+c=0

The Discriminant is given as

[tex]Discriminant=b^{2}-4ac[/tex]

On comparing we get

[tex]a=7\\b=-5\\c=1[/tex]

Substituting the values we get

[tex]Discriminant=(-5)^{2}-4\times 7\times 1\\Discriminant=25-28\\Discriminant=-3[/tex]

Therefore,

[tex]Discriminant=-3[/tex]

To find the number of 2 kg and 4 kg sugar bags in the shipment, we use a system of equations. By setting x as the number of 2 kg bags and y as the number of 4 kg bags, we determine that there are 750 bags of 2 kg sugar and 350 bags of 4 kg sugar.

To solve the problem of determining how many 2 kg bags and 4 kg bags of sugar are in the shipment of 1100 bags with a total mass of 2900 kg, we need to set up a system of equations and solve for the variables representing the quantities of each type of bag. Let's denote x as the number of 2 kg bags and y as the number of 4 kg bags.

The first equation represents the total number of bags:
x + y = 1100.

The second equation represents the total weight of the bags:
2x + 4y = 2900.

We can solve these equations using substitution or elimination methods. For simplicity, let's multiply the first equation by 2 and subtract it from the second equation:

Now that we know y, we can substitute it back into the first equation to find x:

Therefore, there are 750 bags of 2 kg sugar and 350 bags of 4 kg sugar in the shipment.

Answer:

x = 3

Step-by-step explanation:

Given

3x = x + 6 ( subtract x from both sides )

2x = 6 ( divide both sides by 2 )

x = 3

Answer:

Step-by-step explanation:

3x = x + 6.....subtract x from both sides

3x - x = x - x + 6

2x = 6 ...divide both sides by 2

(2/2)x = 6/2

1x = 6/2

x = 3 <=====

Answer:

Balanced chemical equations only show formulae, not names. A balancing number, written in normal script, multiplies all the atoms in the substance next to it.

Answer:

15

Count down from 21 and count up from 9 till you have the same number.

21 9

20 10

19 11

18 12

17 13

16 14

15 15

Now they are the same height.

Step-by-step explanation:

When a seesaw is level, the height of both ends above the ground is the average of the heights when one end is lifted. In this case, both ends are 15 inches above the ground when the seesaw is level.

The question is asking for the height of the ends of a seesaw when it is in a level or balanced position. A seesaw balances when it is level, and both ends are at the same height. Considering the given details, one end is 9 inches and the other is 21 inches above ground, when they switch positions due to the seesaw's pendulum-like movement. But when the seesaw is level, both ends are at the same height. Therefore, the height of both ends of the seesaw when it is level is the average of 9 inches and 21 inches. You calculate this average by adding the two given distances and dividing by 2. So:

((9 inches + 21 inches) / 2) = 15 inches

So, when the seesaw is level, both ends are 15 inches above the ground.

https://brainly.com/question/21623981

#SPJ2

Answer:

i would say wait abought 50 mins

Step-by-step explanation:

i dont know whow to explain i might be wrong but its some whaere around 50 mins irl

Using Newton's Law of Cooling with a cooling constant of 0.035, it will take approximately 42.53 minutes for the brownies to cool from 400 degrees F to 160 degrees F.

To estimate the time it would take for brownies to cool from 400 degrees F to 160 degrees F using Newton's Law of Cooling, we can use the equation [tex]T(t) = T_s + (T_0 - T_s)e^{(-kt)[/tex], where T(t) is the temperature of the object at time t, T_s is the surrounding temperature, T_0 is the initial temperature of the object, and k is the cooling constant (0.035 in this case).

First, set T(t) = 160 degrees F (the desired temperature), T_s = 70 degrees F (room temperature), and T_0 = 400 degrees F (initial temperature of brownies). Plug in the values into the equation: 160 = 70 + (400 - 70)e^(-0.035t).

Simplify and solve for t. Subtract 70 from both sides: 90 = 330e^(-0.035t). Divide both sides by 330: 90/330 = e^(-0.035t), which simplifies to 0.2727 ≈ e^(-0.035t).

Take the natural logarithm of both sides to solve for t: ln(0.2727) = -0.035t. Solving for t gives t ≈ -ln(0.2727)/0.035, which calculates to approximately t ≈ 42.53 minutes.

Hence, the brownies should cool to 160 degrees F in about 42.53 minutes.

Answer:

Option D.

8.05 inches

Step-by-step explanation:

Let

x ----> Length of Foot in inches

y ----> Length of Forearm in inches

we have

[tex]y=1.11x-0.83[/tex]

For x=8 in

substitute the value of x in the linear equation and solve for y

[tex]y=1.11(8)-0.83=8.05\ in[/tex]

Answer:

[tex]A'(-3,0),B'(8,3),C'(2,-9)[/tex]

Step-by-step explanation:

we know that

the triangle is translated 4 units right and 6 units down

so

The rule for the translation is

[tex](x,y) -----> (x+4,y-6)[/tex]

Applying the rule for the translation find the image of each vertex

1) [tex]A(-7,6) -----> A'(-7+4,6-6)[/tex]

[tex]A(-7,6) -----> A'(-3,0)[/tex]

2) [tex]B(4,9) -----> B'(4+4,9-6)[/tex]

[tex]B(4,9) -----> B'(8,3)[/tex]

3) [tex]C(-2,-3) -----> C'(-2+4,-3-6)[/tex]

[tex]C(-2,-3) -----> C'(2,-9)[/tex]

Answer:

3

Step-by-step explanation:

30 x 3

Answer:

y=1/2x -2. Hope this helps!

The required fraction is [tex]\bold{\frac{1}{3}}[/tex]

Solution:

Given:

Cost of 32 ounces tub = $6

Cost of 8 ounces tub = $2

To find:

what fraction of the cost of the large tube is the small tub.

From the given, here we can understand that the large tub is the 32 ounces tub and the smaller one is the 8 ounces tub.

Let k be the required fraction.

Therefore, [tex]\bold{k\times6=2}[/tex]

On solving we get,

[tex]\bold{\Rightarrow k=\frac{2}{6}\rightarrow k=\frac{1}{3}}[/tex]

Amount spent by the wife is $70

Step-by-step explanation:

Given:

the total amount  = $200

Amount spent on Lunch = $15.00

They buy three items at $20.00 each

The wife spends twice what her husband spends

They return home with $20.00 cash.

To Find:

Amount spent by the wife  = ?

Solution:

Initially after spending $15.00 on lunch they balance cash with them will be

200 - 15.00 = $185

Then they are buy 3 items each of which costs $20.00

So the balance after buying the 3 items will be

= 200 - 3(20)

= 185- 60.00

= $125

Now the wife is spending twice what her husband spends

so let the amount spent be the husband be x then the amount spent by the wife will be 2x.

Now  after spending 2x+x amount they are  left with $20.00

that is

125 -2x+x  = 20

125 -3x = 20

125 -20 = 3x

105 = 3x

[tex]x = \frac{105}{3}[/tex]

x = 35

So the wife will be spending 2(35) = $70

Answer:

-6/5

Step-by-step explanation:

-2 2/5=-12/5

1/2*-12/5=-12/10=-6/5