Alex has 48 stickers. This is 6 times the number of stickers max has. How many many stickers does max have?

Answer:To find the image of B, first find the scale factor for the dilation. The scale factor should be greater than 1 because the image of A is farther from the origin than A. Divide the coordinates of the image of A by the coordinates of A: –6/–4 = 3/2 and 9/6 = 3/2, so the scale factor is 3/2. Now, apply the dilation to B by multiplying the coordinates by 3/2 to get ((3/2)(1), (3/2)(4)), or (3/2, 6).

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Answer:

Measure of angle s is 22°

Step-by-step explanation:

Given that lines a and b are parallel. Horizontal parallel lines a and b intersect with another line making 8 angles, the top right angle of line a is labeled 158° and the top left angle of line b is labeled s degrees

we have to find the measure of angle s.

As ∠1 and 158° and on straight line hence are supplementary

i.e ∠1+158°=180°

⇒ ∠1=180°-158°=22°

Also, angle s and ∠1 are alternate interior angles.

As a and b are parallel then alternate interior angles are equal.

Hence, ∠s=∠1=22°

Measure of angle s is 22°

Answer:

Three sides with the same length because that is what an equilateral triangle is.

Step-by-step explanation:

area of painting = 13 * 17 = 221 square inches

221 * 0.30 = 66.30

 the price would be $66.30

Answer: Niko needs 9 marshmallows and 6 graham crackers to make 3 s'mores.

Step-by-step explanation:

Let x be the number of marshmallows , y be the number of graham crackers and z be the number of s'mores.

Then according to given question

Niko uses 12 marshmallows and 8 graham crackers to make 4 s'mores

gives the equation 12x+8y=4z

If we divide whole equation by 4 , we get the quantity of x and y to make z such that

[tex]\frac{1}{4}(12x+8y)=\frac{1}{4}(4z)\\\Rightarrow3x+2y=z[/tex]

Now to make 3 s'mores, we need to multiply the equation by 3 such that

[tex]3\times(3x+2y)=3\times\ z\\\Rightarrow\ 9x+6y=3z[/tex]

Thus Niko needs 9 marshmallows and 6 graham crackers to make 3 s'mores.

The rates of 7 inches per 9 hours and 42 inches per 54 hours do form a proportion, as demonstrated by cross-multiplying the two ratios which resulted in equal cross products (378 inch-hours on both sides).

To determine if the two rates form a proportion, we need to compare the ratios of inches to hours for both scenarios. For the first rate, we have 7 inches in 9 hours, and for the second rate, we have 42 inches in 54 hours. A proper proportion exists when two ratios are equivalent.

Let's set up our two ratios:

Now, we will test if these ratios form a proportion by creating a fraction out of each ratio and then cross-multiplying.

(7 inches / 9 hours) = (42 inches / 54 hours)

Cross multiply:

7 inches * 54 hours = 378 inch-hours

42 inches * 9 hours = 378 inch-hours

Since the cross products are equal, the two rates indeed form a proportion.

The dimensions that give the minimum surface area are a radius of approximately 2.83 cm and a height of approximately 0.64 cm.

To find the dimensions of the closed cylinder that give the minimum surface area, we need to express the surface area of the cylinder in terms of one variable.

Let's use the radius, r, as the variable.

The surface area of a closed cylinder is given by the formula: A = 2πr² + 2πrh, where h is the height of the cylinder.

Since we are given that the volume of the cylinder is 40 cm³, we can use the formula for the volume of a cylinder to express h in terms of r: V = πr²h = 40 cm³.

Substituting this expression for h in terms of r into the surface area formula, we get:

A = 2πr² + 2πr(40 / (πr²)) = 2πr² + (80 / r).

To find the dimensions that give the minimum surface area, we need to find the value of r that minimizes A.

To do this, we take the derivative of A with respect to r and set it equal to zero:

A' = 4πr - (80 / r²) = 0. Solving this equation, we find that r = √(20/π) ≈ 2.83 cm.

So, the radius that gives the minimum surface area is approximately 2.83 cm.

We can then use the volume formula to find the corresponding height: h = 40 / (π(2.83)²) ≈ 0.64 cm.

Therefore, the dimensions giving the minimum surface area are a radius of approximately 2.83 cm and a height of approximately 0.64 cm.

Answer:

The cost would be $ 5.38.

Step-by-step explanation:

Given,

The price of 5 pounds of cheese = $ 13.45,

So, the price of 1 pounds of cheese = [tex]\frac{\text{Price of }5\text{ pounds of cheese}}{5}[/tex]

[tex]=\frac{13.45}{5}[/tex]

[tex]=\$ 2.69[/tex]

Thus, the price of 2 pounds of cheese = 2 × price of each pound of cheese

= 2 × 2.69

= $ 5.38

Answer:

The factored form of [tex]4a^3b^5-16a^5b^2+12a^2b^3[/tex] is [tex]4a^2b^2\left(ab^3-4a^3+3b\right)[/tex].

Step-by-step explanation:

To find the factored form of [tex]4a^3b^5-16a^5b^2+12a^2b^3[/tex] you must:

Apply exponent rule: [tex]a^{b+c}=a^ba^c[/tex]

[tex]a^2b^3=a^2b^2b,\:a^5b^2=a^2a^3b^2,\:a^3b^5=a^2ab^2b^3[/tex]

So, we can write our expression as [tex]4a^2ab^2b^3-16a^2a^3b^2+12a^2b^2b[/tex].

Next, rewrite 12 as [tex]3\cdot \:4[/tex] and -16 as [tex]4\cdot \:4[/tex]

[tex]4a^2ab^2b^3+4\cdot \:4a^2a^3b^2+3\cdot \:4a^2b^2b[/tex]

Factor out common term: [tex]4a^2b^2[/tex]

Therefore,

[tex]4a^3b^5-16a^5b^2+12a^2b^3= 4a^2b^2\left(ab^3-4a^3+3b\right)[/tex]

Answer:

FALSE

Step-by-step explanation:

The amount of interest paid depends on the method adopted by the lender. There are several methodologies for applying interest, so that each sector will adhere to the most convenient modality. The interest paid by you will be the result of this choice and may for example have a daily, monthly, semi-annual or annual impact. Obviously all interest charged must be clearly described in a contract and must be considered legal in the state legal apparatus.

The maximum value of the electric current is [tex]I_{max}=\dfrac{1}{3}[/tex]

the minimum value of the electric current is [tex]I_{min}=-\dfrac{1}{3}[/tex]

The given expression for electric current is [tex]I=\cos(\omega t)+\sqrt{8}\sin(\omega t)[/tex] where [tex]\omega \neq 0[/tex].

Differentiate the given function with respect to [tex]t[/tex]-

[tex]\dfrac{dI}{dt}=\dfrac{d(\cos(\omega t)+\sqrt 8 \sin(\omega t))}{dt}\\\dfrac{dI}{dt}=-\omega \sin(\omega t)+\sqrt 8 \omega \cos(\omega t)[/tex]

Equate the derivative to 0-

[tex]\dfrac{dI}{dt}=0\\-\omega \sin(\omega t)+\sqrt 8 \omega \cos(\omega t)=0\\\sin(\omega t)=\sqrt 8 \cos (\omega t)\\\tan (\omega t)=\sqrt 8\\\omega t=\tan^{-1}\sqrt 8\\\omega t=2n\pi-2\tan^{-1}\sqrt 2}\\or,\\\omega t=2n\pi+2\tan^{-1}\sqrt {1/2}}[/tex]

[tex]2n\pi[/tex] is the period of sine and the cosine trigonometric function.

So, the maximum value of the electric current is

[tex]I_{max}=\cos(2\tan^{-1}\sqrt {1/2})\\I_{max}=\dfrac{1}{3}[/tex]

Also, the minimum value of the electric current is

[tex]I_{min}=\cos(2\tan^{-1}\sqrt {2})\\I_{min}=-\dfrac{1}{3}[/tex]

Learn more about maximum and minimum values of the functions here:

https://brainly.com/question/13581879?referrer=searchResults