Final answer:
The biceps muscles need to produce a force of 2000 N to hold the 200 N barbell in static equilibrium.
Explanation:
To hold the 200 N barbell in static equilibrium, the biceps muscles need to produce a force equal to the weight of the barbell. The moment arm of the barbell about the elbow joint is 40 cm, so the torque exerted by the barbell is calculated as:
Torque = Force x Moment Arm
Torque = 200 N x 40 cm = 8000 N·cm
The moment arm of the elbow flexor muscles is 4 cm. To maintain static equilibrium, the torque exerted by the biceps muscles must be equal and opposite to the torque exerted by the barbell:
Torque biceps = Torque barbell
Force biceps x Moment Arm biceps = Force barbell x Moment Arm barbell
Force biceps x 4 cm = 200 N x 40 cm
Force biceps = (200 N x 40 cm) / 4 cm
Force biceps = 2000 N
Determine the total number (#/cm3) of energy states in silicon between ev and ev ? 3 kt at (i) t ? 300 k and (ii) t ? 400 k. (b) repeat part (a) for gaas
To determine the density of states in silicon or GaAs at specific energies, one needs to use the formula related to effective mass and semiconductor band structure. The question does not provide enough information to perform these calculations, and additional data is required.
Explanation:The question implies determining the number of energy states within a certain energy range in silicon and gallium arsenide (GaAs) semiconductors at different temperatures. The challenge is to understand the concept of density of states (DoS) and how it varies with energy and temperature. The density of states is a function that describes the number of states per interval of energy at each energy level available to be occupied by electrons or holes. At T = 300 K and T = 400 K, we would use the DoS formula, which depends on effective mass and energy of the semiconductor material. However, the question as provided does not include enough information or specific parameters to calculate the density of states for silicon and GaAs between given energy levels and at specific temperatures.
To find the density of states at E = 0.80 eV, E = 2.2 eV, and E = 5.0 eV, you would use a formula related to the effective mass of the electrons and the structure of the semiconductor band. However, without the actual formulas or values specific for silicon and GaAs, it is not possible to calculate the exact density of states at these energy levels. Furthermore, the additional information provided in the challenge problems discusses concepts like the free electron gas model and the Fermi factor but is not directly applicable to calculating the density of states without further context.
Which of the following is an example of velocity?
A. 25 east
B. 50 mph east
C. 100 mph
D. 100 miles east
50 mph east,because Velocity is a physical vector quantity both magnitude and direction are needed to define it.
What is velocity?
When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time.
Uniform motion an object is said to have uniform motion when object cover equal distance in equal interval of time within exact fixed direction. For a body in uniform motion, the magnitude of its velocity remains constant over time.
50 mph east,because Velocity is a physical vector quantity both magnitude and direction are needed to define it.
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Plants in a tropical rain forest usually have
A) thick, fleshy stems.
B) large broad leaves.
C) long vertical roots.
D) spiny or thorn skin.
Answer:
B broad leaves
Explanation:
Plants in a tropical rainforest usually have large as well as broad leaves. The correct option is B.
What is a tropical rainforest?Tropical rainforests are rainforests that occur in tropical rainforest climate areas where there is no dry season and all months have an average precipitation of at least 60 mm. They are also known as lowland equatorial evergreen rainforest.
Tropical rainforests are dominated by broad-leaved trees that form a dense upper canopy and contain a diverse array of vegetation and other life. They are one of Earth's largest biomes (major life zones).
Large leaves also allow tropical plants to capture more sunlight energy, which, when combined with a ready supply of water, allows for rapid growth.
Thus, the correct option is B.
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1. How does boiling differ from evaporation?
Boiling can take place at any temperature, while evaporation takes place at a specific temperature.
Boiling is a change from a liquid to a gas, while evaporation is a change from a gas to a liquid.
Boiling takes place throughout a liquid, while evaporation takes place at the surface.
2.
In which states of matter can materials take the shape of their containers?
solid and liquid
solid and gas
liquid and gas
3.
Which is true according to the kinetic theory?
All particles of matter move very quickly.
The particles that make up gases are densely packed.
The particles that make up solids do not move.
All particles of matter are in constant motion.
4.
A graph shows how the temperature of a substance changes as energy is added steadily over time. Which part of the graph would indicate a phase change is taking place?
a steep, downward sloping line
a steep, upward sloping line
a flat, horizontal line
5.
Which statement describes the kinetic energy of a particle?
It is attracted to particles of the opposite charge.
It is much larger than particles of another substance.
It moves quickly after a collision with another particle.
6.
Which model best describes the particles of a solid and their motion?
beads moving around in a rattle
bricks cemented together in a wall
students walking through a crowded hall
people seated in an auditorium
7.
Which word expression describes how to calculate pressure?
force multiplied by area
force divided by area
area divided by force
area minus force
8.
Which is the phase change in which a substance changes from a gas to liquid?
condensation
vaporization
boiling
evaporation
9.
What does a graph representing Charles’s law show?
Volume decreases as pressure increases.
Volume decreases as temperature increases.
Volume increases at the same rate as temperature.
Volume increases at the same rate as pressure.
10.
According to Boyle’s law, the volume of a gas is inversely proportional to its pressure if the _____.
number of particles and temperature decreases
number of particles and temperature increases
temperature and number of particles are constant
temperature reaches absolute zero
11.
When does raising the temperature of a gas increase its pressure?
when volume is increased and the number of particles is constant
when volume and the number of particles are constant
when volume is increased and the number of particles is increased
12.
Which of these phase changes does not involve changing a liquid into a gas?
sublimation
evaporation
vaporization
A street light is on top of a 12 foot pole. a person who is 5 feet tall walks away from the pole at a rate of 4 feet per second. at what speed is the length of the person's shadow growing
Final answer:
The rate at which the length of the person's shadow is growing is \(\frac{{48}}{{5}}\) feet per second.
Explanation:
In this problem, we can use similar triangles to determine the rate at which the length of the person's shadow is growing. Let's consider the situation at a particular moment when the person is a certain distance away from the pole. At this moment, the length of the person's shadow is the distance from the pole to the person multiplied by the ratio of the height of the pole to the height of the person. Let's call this length S. The rate of change of S, which represents the speed at which the length of the person's shadow is growing, can be determined using derivatives. To find this rate, we need to differentiate the expression for S with respect to time (t), since the person is moving and therefore the distance from the pole is changing over time.
The length of the person's shadow (S) can be expressed as:
S = \(\frac{{12}}{{5}}x\)
where x is the distance from the pole to the person at a particular moment.
To find the rate of change of S with respect to time (\(\frac{{dS}}{{dt}}\)), we differentiate the expression for S:
\(\frac{{dS}}{{dt}} = \frac{{12}}{{5}}\frac{{dx}}{{dt}}\)
Since the person is moving away from the pole at a rate of 4 feet per second, \(\frac{{dx}}{{dt}} = 4\). Plugging this value into the equation, we can calculate the rate at which the length of the person's shadow is growing:
\(\frac{{dS}}{{dt}} = \frac{{12}}{{5}} \cdot 4 = \frac{{48}}{{5}}\) feet per second
By using similar triangles and differentiating with respect to time, we find that the length of the person's shadow is growing at a rate of approximately 2.86 feet per second.
The question involves calculating the rate at which the length of a person's shadow grows as they walk away from a street light. To start, we can use similar triangles to relate the heights and shadows of the pole and the person. Given:
Height of the pole (H1) = 12 feetHeight of the person (H2) = 5 feetPerson's walking speed = 4 feet/secondLet the distance of the person from the pole be x, and the length of the shadow be s. By similar triangles, we have:
(Height of the pole)/(Total distance from the pole to the tip of the shadow) = (Height of the person)/(Length of the shadow)
This converts to:
12/(x + s) = 5/s
Cross multiplying gives us:
12s = 5(x + s)
Which simplifies to:
12s = 5x + 5s
Rearranging terms gives us:
7s = 5x
So, s = (5/7)x
Next, we differentiate both sides of this equation with respect to time (t), noting that both s and x are functions of time:
ds/dt = (5/7)dx/dt
Given that the rate at which the person walks (dx/dt) is 4 feet per second, we find:
ds/dt = (5/7) * 4 = 20/7 ≈ 2.86 feet per second
Thus, the length of the person's shadow is growing at a rate of approximately 2.86 feet per second.
The igneous feature shown in this photograph is:
An exceptional standing jump would raise a person 0.79 m off the ground. to do this, what force must a 79 kg person exert against the ground? assume the person crouches a distance of 0.19 m prior to jumping, and thus the upward force has this distance to act over before he leaves the ground.
A combination of the skill-related fitness components can determine one's performance in a specific sport. true or false
Dee is on a swing in the playground. the chains are 2.5 m long, and the tension in each chain is 450 n when dee is 55 cm above the lowest point of her swing. tension is a vector directed along the chain, measured in newtons, abbreviated n. what are the horizontal and vertical components of the tension at this point in the swing
The horizontal and vertical components of the tension at the given point in the swing are 281.6 N and 351 N respectively.
Given data:
The length of chain is, L = 2.5 m.
The magnitude of tension on each chain is, T = 450 N.
Distance above the lowest point is, d = 55 cm = 0.55 m.
In problem, first we need to obtain the angle of inclination made by string horizontally.
So, the angle inclined by the string with horizontal is given as,
[tex]cos \theta =\dfrac{L-d}{L}\\\\cos \theta =\dfrac{2.5-0.55}{2.5}\\\\\theta = cos^{-1}(\dfrac{1.95}{2.5})\\\\\theta=38.74^{\circ}[/tex]
Now, the horizontal component of tension force acting on the string is,
[tex]T_{H}=T \times cos \theta\\T_{H}=450 \times cos 38.74\\T_{H}=281.6 \;\rm N[/tex]
And, the vertical component of tension force acting on the string is,
[tex]T_{V}=T \times sin \theta\\T_{V}=450 \times sin 38.74\\T_{V}=351 \;\rm N[/tex]
Thus, the horizontal and vertical components of the tension at this point in the swing are 281.6 N and 351 N respectively.
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A 5.22-kg object passes through the origin at time t = 0 such that its x component of velocity is 5.10 m/s and its y component of velocity is -2.82 m/s. (a) what is the kinetic energy of the object at this time?
The kinetic energy of the object at t = 0 is approximately 66.27 Joules.
Explanation:To calculate the kinetic energy of the object, we can use the equation: KE = 0.5 * m * v^2. Given the mass of the object is 5.22 kg and the x-component of velocity is 5.10 m/s, we can substitute these values into the equation:
KE = 0.5 * 5.22 kg * (5.10 m/s)^2
Calculating this gives us a kinetic energy of approximately 66.27 Joules.
What is the kinetic energy of a 1400 kg car traveling at a speed of 30 m/s (≈65mph)?
Answer:
Kinetic Energy (K.E) of the car is 630000 J
Explanation:
Kinetic energy (K.E) of a body is the energy of the body in motion and it is given by the product of half its mass (m) and the square of its velocity (v). It is expressed in Joules.
Mathematically written as;
K.E = [tex]\frac{1}{2}[/tex] x m x [tex]v^{2}[/tex]
According to the question,
The mass m of the car is 1400kg
=> m = 1400kg
The speed (velocity) of the car is 30m/s
=> v = 30m/s
Substituting these values into the equation above gives;
K.E = [tex]\frac{1}{2}[/tex] x 1400 x [tex]30^{2}[/tex]
K.E = 630000 J
Therefore the kinetic energy of the car is 630000Joules
The kinetic energy of a 1400 kg car traveling at 30 m/s is calculated using the kinetic energy formula, resulting in a total energy of 630,000 Joules or 630 kJ.
The answer is 630,000 Joules or 630 kJ.
Kinetic energy is a fundamental concept in physics, representing the energy of an object in motion. It depends on two factors: the object's mass (m) and its velocity (v). The formula for kinetic energy is KE = 0.5 * m * v^2. Essentially, the greater an object's mass or speed, the more kinetic energy it possesses. This energy is vital in understanding various natural phenomena, such as the motion of vehicles, the flight of birds, and the behavior of particles in atomic and subatomic physics. It is also crucial in engineering and everyday applications.
The kinetic energy of an object can be calculated using the formula: Kinetic Energy = 0.5 * mass * speed². In this case, the mass of the car is 1400 kg and the speed is 30 m/s. To calculate the kinetic energy, you would substitute these values into the formula:
Kinetic Energy = 0.5 * 1400 kg * (30 m/s)²
Therefore, Kinetic Energy = 0.5 * 1400 * 900
So, the kinetic energy of the car is 630,000 Joules or 630 kJ.
Hence The answer is 630,000 Joules or 630 kJ.
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Here is a 95% confidence interval estimate of the proportion of all jobs applicants who test positive when they are tested for drug use: 0.0262 < p < 0.0499 (based on data from quest diagnostics). which of the statements correctly interprets this confidence interval?
A toy projectile is fired from the ground vertically upward with an initial velocity of 26.5 m/s. The project arrives at its maximum altitude in 2.7s.
What is the velocity of the projectile when it hits the ground? How?
What current would it need to carry in order to experience a very modest 1.0×10−3n⋅m torque?
The current required in the loop to experience the given torque is [tex]\boxed{6.366\times{{10}^2}\,{\text{A}}}[/tex] or [tex]\boxed{636.6\,{\text{A}}}[/tex] .
Further Explanation:
Given:
The diameter of the circular loop is [tex]20\,{\text{cm}}[/tex] .
The torque experienced by the circular loop is [tex]1.0\times{10^{-3}}\,{\text{N}}\cdot{\text{m}}[/tex] .
Concept:
Since the circular loop is kept in the effect of the Earth’s Magnetic field, it will experience a magnetic torque due to the magnetic lines of force passing through the area of cross-section of the loop.
The torque experienced by the loop is expressed as:
[tex]\boxed{\tau =BIA}[/tex]
Here, [tex]\tau[/tex] is the torque experienced, [tex]B[/tex] is the magnetic field, [tex]I[/tex] is the current in the loop and [tex]A[/tex] is the area of cross-section of the loop.
The strength of the Earth’s magnetic field is [tex]5\times{10^{-5}}\,{\text{T}}[/tex] .
Substitute the values in the above expression.
[tex]\begin{aligned}1.0\times{10^{-3}}&=\left({5\times{{10}^{-5}}}\right)\timesI\times\left({\pi \times{{\left({\frac{d}{2}}\right)}^2}}\right)\\I&=\frac{{1.0\times{{10}^{-3}}}}{{5\times{{10}^{-5}}\left({\pi {{\left({\frac{{0.20}}{2}}\right)}^2}}\right)}}\\&=6.366\times{10^2}\,{\text{A}}\\\end{aligned}[/tex]
The current required in the loop to experience the given torque is [tex]\boxed{6.366\times{{10}^2}\,{\text{A}}}[/tex] or [tex]\boxed{636.6\,{\text{A}}}[/tex] .
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Answer Details:
Grade: College
Subject: Physics
Chapter: Electromagnetism
Keywords:
Earth’s magnetic field, torque, maximum torque, maximum current, through the loop, experience a modest torque, T=BIA, 636 A, wire is oriented.
A horizontal pipe of diameter 0.985 m has a smooth constriction to a section of diameter 0.591 m . the density of oil flowing in the pipe is 821 kg/m3 . if the pressure in the pipe is 8100 n/m2 and in the constricted section is 6075 n/m2 , what is the rate at which oil is flowing
To find the rate at which oil is flowing through a constricted pipe with different diameters and pressures, apply the principle of continuity.
A horizontal pipe of diameter 0.985 m has a smooth constriction to a section of diameter 0.591 m. The pressure in the pipe is 8100 N/m2, and in the constricted section, it is 6075 N/m2. The density of oil flowing in the pipe is 821 kg/m3.
To find the rate at which oil is flowing, we can apply the principle of continuity, which states that the product of the cross-sectional area and the fluid velocity is constant in a pipe with steady flow.
By applying the principle of continuity, you can calculate the rate at which oil is flowing through the pipe.
Consider an airplane flying at a pressure altitude of 31500 ft and a density altitude of 28000 ft. calculate the outside air temperature. (round the final answer to the nearest whole number.)
Final answer:
The outside air temperature is approximately 3375 °C.
Explanation:
The outside air temperature can be calculated using the density altitude and pressure altitude. The formula to calculate the temperature is:
T = T0 + (d × 120)
Where:
T is the outside air temperature
T0 is the temperature at sea level
d is the difference between the pressure altitude and the density altitude, divided by 1,000 (d = (PA - DA) / 1000)
Plugging in the given values, we have:
T = 15 + (28 × 120)
T = 15 + 3360
T = 3375
So, the outside air temperature is approximately 3375 °C.
If the thrower takes 0.90 s to complete one revolution, starting from rest, what will be the speed of the discus at release?
The discus, after completing one revolution in 0.90 seconds starting from rest, will be released at a speed of approximately 6.98 rad/s.
Explanation:This question is related to the concept of rotational motion in physics. As it is stated that the discus thrower takes 0.90s to complete one revolution, and the discus is starting from rest, the rotational speed or the angular velocity (ω) can be calculated using the formula ω = 2π/T, where T is the period of rotation which is the time to complete one revolution. Substituting the given values into the formula gives us ω = 2π/0.90 s which is approximately 6.98 rad/s.
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To determine the speed of a discus at release, given the time for one revolution is 0.90 seconds, we first find the angular velocity to be approximately 6.98 rad/s. Then, using the radius of the circle, we can calculate the linear speed. For a radius of 1 meter, the speed is approximately 6.98 m/s.
When calculating the speed of the discus at release, we first need to determine the angular velocity. Given that the thrower completes one revolution in 0.90 seconds, we can use the formula for angular velocity:
ω = 2π / T
where ω is the angular velocity and T is the period of one revolution. Substituting the given values, we get:
ω = 2π / 0.90 s ≈ ( 2 x 3.14 ) / 0.90s ≈ 6.98 rad/s
Next, to find the linear speed at release, we use the relationship between linear speed (v), angular velocity (ω), and radius (r):
v = ωr
Assuming we know the radius of the circle in which the discus is being rotated, we can substitute r. If r is, for example, 1 meter, then:
v ≈ 6.98 rad/s * 1 m ≈ 6.98 m/s
Therefore, the speed of the discus at release would be approximately 6.98 meters per second.
A day on a distant planet observed orbiting a nearby star is 21.5 hours. also, a year on the planet lasts 59.1 earth days.* calculate the average angular speed of the planet about its own axis of rotation in radians per second, with the second as measured on earth.
The average angular speed can be calculated by dividing the total rotation of the planet (2π radians) by the time taken for one rotation (converted to seconds). This gives an average angular speed of approximately 8.11x10-5 radians per second.
Explanation:The first step in tackling this problem is understanding what angular speed is. Angular speed is the rate at which an object moves through an angle. It is measured in radians per second. In your case, you want to find the angular speed of the planet about its own axis of rotation.
To do this, we need to recall that one complete rotation is 2π radians. Since one day on this distant planet lasts 21.5 hours, we convert this to seconds (1 hour = 60 minutes = 3600 seconds). So, 21.5 hours is 21.5 x 3600 = 77400 seconds.
The angular speed (ω) is therefore calculated by dividing the total rotation (2π radians) by the time (t) taken for one rotation. That is ω = 2π/t. Substituting for t in this formula, we get ω = 2π/77400 = 8.11x10-5 radians per second. Note that this answer is an approximation, and actual planetary motion can be influenced by a number of factors.
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What is the strength and direction of the electric field 3.560 cm?
Which of the following is not a force causing plate motion?
A. Gravity
B. Ridge push
C. Slab pull
D. Basal drag
D IS WRONG
Gravity is not a direct force causing plate motion in the context of plate tectonics; instead, key forces include ridge push, slab pull, and basal drag, with slab pull being the predominant mechanism.
The question pertains to the forces that are responsible for plate tectonics and plate motion. It is a common misconception that gravity is a direct force causing plate motion; however, in the context of tectonic plates, gravity is not a force that directly initiates their movement. In tectonic plate motion, the key driving forces are ridge push, slab pull, and basal drag. Ridge push occurs at mid-ocean ridges, where newly formed lithosphere pushes plates apart. Slab pull is the force exerted by a subducting plate that pulls the rest of the plate after it as it descends into the mantle due to its higher density. Basal drag is the force exerted by the mantle's convection currents on the base of the tectonic plates.
Gravity, while essential in providing the overall setting by influencing the density and buoyancy of rocks, does not directly move the plates on its own. Rather, gravity contributes indirectly to gravitational sliding, which pulls lithospheric plates down from the elevated mid-ocean ridges due to the height difference. However, current evidence supports slab pull as the predominant mechanism over ridge push and gravitational sliding.
A kite 100 ft above the ground moves horizontally at a speed of 12 ft/s. at what rate is the angle (in radians) between the string and the horizontal decreasing when 200 ft of string have been let out?
Final answer:
The angle between the string and the horizontal is decreasing at a rate of -0.4 radians/second.
Explanation:
In order to solve this problem, we can use trigonometry and the chain rule from calculus. Let's denote the angle between the string and the horizontal as θ. We need to find the rate at which this angle is decreasing (dθ/dt) when 200 ft of string have been let out.
First, we can find the length of the string using the Pythagorean theorem: 100^2 + r^2 = (100+r)^2, where r is the length of the horizontal portion of the string. Solving this equation gives us r = 50 ft.
Next, we can differentiate the equation with respect to time using the chain rule: d/dt (100^2 + r^2) = d/dt ((100+r)^2). Simplifying the equation and solving for dθ/dt gives us dθ/dt = -100/(r+r^2/100).
Plugging in r = 50 ft, we can find dθ/dt = -0.4 radians/second.
If 2 automobiles have the same velocity, do they have the same acceleration?
A car is driving along a circular track of diameter d=.85km at a constant speed of v=28.5m/s. write an expression for the magnitude of the acceleration a of the car in terms of the given parameters
Answer: a = (2 v²)/d = 1.9 m/s²
Explanation:
In circular motion, the acceleration is given by:
a = v²/r = v²/(d/2) = (2 v²)/d
where v is the velocity and r is the radius of the circular path in which the vehicle is moving. d is the diameter of the circular path.
It is given that:
v = 28.5 m/s
r = d/2 = 0.85 km /2 = 0.425 km = 425 m
⇒ a = (28.5 m/s)²/425 m = 1.9 m/s²
An expression for the magnitude of the acceleration (a) of the car in terms of the given parameters is: [tex]A_c = \frac{2V^2}{D}[/tex]
Given the following data:
Diameter, D = 0.85 kmSpeed, V = 28.5 m/s.To write an expression for the magnitude of the acceleration (a) of the car in terms of the given parameters:
The acceleration of an object along a circular track is referred to as centripetal acceleration.
Mathematically, the centripetal acceleration of an object is given by the formula:
[tex]A_c = \frac{V^2}{r}[/tex] .....equation 1
Where:
Ac is the centripetal acceleration.r is the radius of the circular track.V is the velocity of an object.But, [tex]Radius, \;r = \frac{D}{2}[/tex] .....equation 2
Substituting the eqn 2 into eqn 1, we have:
[tex]A_c = \frac{V^2}{\frac{D}{2}}[/tex]
Simplifying further, we have:
[tex]A_c = \frac{2V^2}{D}[/tex]
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Microwave ovens emit microwave energy with a wavelength of 12.4 cm. what is the energy of exactly one photon of this microwave radiation?
The energy of the photon emitted is about 1.60 × 10⁻²⁴ Joule
Further explanationThe term of package of electromagnetic wave radiation energy was first introduced by Max Planck. He termed it with photons with the magnitude is :
[tex]\large {\boxed {E = h \times f}}[/tex]
E = Energi of A Photon ( Joule )
h = Planck's Constant ( 6.63 × 10⁻³⁴ Js )
f = Frequency of Eletromagnetic Wave ( Hz )
The photoelectric effect is an effect in which electrons are released from the metal surface when illuminated by electromagnetic waves with large enough of radiation energy.
[tex]\large {\boxed {E = \frac{1}{2}mv^2 + \Phi}}[/tex]
[tex]\large {\boxed {E = qV + \Phi}}[/tex]
E = Energi of A Photon ( Joule )
m = Mass of an Electron ( kg )
v = Electron Release Speed ( m/s )
Ф = Work Function of Metal ( Joule )
q = Charge of an Electron ( Coulomb )
V = Stopping Potential ( Volt )
Let us now tackle the problem !
Given:
λ = 12.4 cm = 12.4 × 10⁻² m
h = 6.63 × 10⁻³⁴ Js
c = 3 × 10⁸ m/s
Unknown:
E = ?
Solution:
[tex]E = h \times \frac{c}{\lambda}[/tex]
[tex]E = 6.63 \times 10^{-34} \times \frac{3 \times 10^8}{12.4 \times 10^{-2}}[/tex]
[tex]E \approx 1.60 \times 10^{-24} ~ Joule[/tex]
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Subject: Physics
Chapter: Quantum Physics
Keywords: Quantum , Physics , Photoelectric , Effect , Threshold , Wavelength , Stopping , Potential , Copper , Surface , Ultraviolet , Light
A balloon is inflated from 0.0100 l to 0.500 l against an external pressure of 10.00 atm. how much work is done in joules? 101.3 j = 1 l atm
Answer:
-496.37 J
Explanation:
P(V2-V1) = 10(.5-.01)
10(.49) =4.9
L x ATM = 4.9 x 101.3= 496.37 J
External pressure means negative therefore its -496.37J
The work done in this scenario can be calculated by multiplying the change in volume, external pressure, and a conversion factor. In this case, the work done is 494.9 J.
Explanation:The work done in this scenario can be calculated using the formula:
Work = change in volume * external pressure * conversion factor
Given:
Initial volume (V1) = 0.0100 l
Final volume (V2) = 0.500 l
External pressure = 10.00 atm
First, we need to find the change in volume:
Change in volume = V2 - V1 = 0.500 l - 0.0100 l = 0.490 l
Next, we can calculate the work done:
Work = change in volume * external pressure * conversion factor
= 0.490 l * 10.00 atm * 101.3 J/l atm
= 494.9 J
Therefore, the work done in joules is 494.9 J.
for humans, why is the characteristic of climate regularity important?
If a 400 N force is applied to a 10 kg object, how fast will it accelerate?
a) 40 m/s2
b) 40000 m/s2
c) 4000 m/s2
d) 4 m/s2
A truck with a heavy load has a total mass of 9100 kg. it is climbing a 15â incline at a steady 15 m/s when, unfortunately, the poorly secured load falls off! immediately after losing the load, the truck begins to accelerate at 1.5 m/s2.
Answer:
Our answer is 3380kg
Explanation:
The force required to move the truck at constant speed in the given case is.
F=Mg sin∅ =(9100kg)(9.8m/s²)sin15° =2.31×10⁴ N
The net force on the truck after the mass is fell down from the truck is
Fnet =F- mg sin∅
ma= F-mg sin∅
m(1.5m/s²) =( 2.31 × 10⁴N) -m(9.8m/s²)sin 15°
Solve for m.
m((1.5m/s²) +(9.8m/s²)sin 15°) =(2.31 ×10⁴ N))
m = 5720kg
Mass of load is.
Δm =M -m =(9100kg) -(5720kg) =3380kg
A regulation NBA basketball court is 94 feet long. If Wale runs the length of the court (from left to right) in 5 seconds, what is his velocity?
When temperature increases, all BUT ONE of the following increases as well. That is A) wavelength. B) heat energy. C) kinetic energy. D) molecular motion.
Answer: A. Wavelength
Explanation: USAtestprep