A subtending arc on a circle with a radius of 4.5 centimeters has an arc length of 8π. What is the measure of the angle subtended by the arc?

Answers

Answer 1
I hope this helps you
A Subtending Arc On A Circle With A Radius Of 4.5 Centimeters Has An Arc Length Of 8. What Is The Measure

Related Questions

Which of the following ratios is not equivalent to 6:10?

3/5
9/15
48/80
24/45

Answers

The answer is 24/45

Let's check out all choices:
a) 6:10 = 3:5
    6 * 5 = 10 * 3
    30 = 30
Therefore, equivalent!

b) 6:10 = 9:15
    6 * 15 = 10 * 9
    90 = 90
Therefore, equivalent!

c) 6:10 = 48:80
    6 * 80 = 10 * 48
    480 = 480
Therefore, equivalent!

d) 6:10 = 24:45
    6 * 45 = 10 * 24
    270 ≠ 240
Therefore, inequivalent!

The ratio that is not equivalent to 6:10 is 24/45, as it simplifies to 8/15 instead of 3/5 like the other options.

To determine which of the given ratios is not equivalent to 6:10, we can simplify the ratio 6:10 or convert it to a fraction and then reduce it to its simplest form. In fraction form, 6:10 can be written as 6/10, which simplifies to 3/5 when both the numerator and the denominator are divided by their greatest common divisor, which is 2.

3/5 is clearly equivalent to 3/5, so this option is not the one we're looking for.9/15 also simplifies to 3/5 (divide both by 3).48/80 simplifies to 3/5 as well (divide both by 16).24/45, however, simplifies to 8/15 when both the numerator and the denominator are divided by 3. This is not equivalent to 3/5.

Therefore, the ratio that is not equivalent to 6:10 is 24/45.

sophia is saving money for a new bicycle. The bicycle will cost at least $623. Sophia makes $8.22 per hour.

Which inequality could be used find the number of hours Sophia needs to work to make enough money to buy a new bicycle?

$8.22h > $623
$8.22h ≤ $623
$8.22h ≥ $623
$8.22h < $623

Answers

$8.22h greater than or equal to $623

Answer:

C.[tex]8.22 h\geq[/tex]$ 623

Step-by-step explanation:

We are given that Sophia is saving money for a new bicycle.

The bicycle will  cost atleast $623.

Sophia makes $8.22 per hour.

We have to find the inequality that could be used to find the number of hours Sophia needs to work to make enough money to buy a new bicycle.

Let Sophia works h hours to make enough money to buy a new bicycle.

Sophia makes money per hour =$8.22

Total money made by Sophia in h hours =[tex]8.22 h[/tex]

According to question

[tex]8.22 h\geq [/tex]$623

Hence, option C is true.

jika f(x)= 1/2 x - 1 dan g(x)= 2x 4. Maka nilai (gof)^-1 (10) adalah ...
a. -9
b. -8
c. 8
d. 9
e. 10

Answers

I hope this helps you

Find the area of a triangle with sides of length 6 and 26 and included angle 74 degrees.

Answers

area of triangle = 1/2 bh

A = 1/2(6)(26)

A = 78

What is the absolute value or −|9| = −9?

Answers

-|9| = -9

but if it was | -9 |, it would equal 9

What number is in the tenths place?

123.456

Answers

the 2 because starting from left to right it is hundreds hundreds, ten's, ones

The digit in the tenths place of the number 123.456 is 4. In the general context of decimals and rounding, if the following digit (hundredths place) is 5 or higher, the tenths place is rounded up when dropped.

The number in the tenths place of 123.456 is 4. When looking at decimal numbers, the first digit to the right of the decimal point represents the tenths place. To illustrate, the number 123.456 can be broken down as (1  imes 10^2) + (2  imes 10^1) + (3  imes 10^0) + (4  imes 10^-1) + (5  imes 10^-2) + (6  imes 10^-3), where the digit 4 is in the tenths place and holds the value of four-tenths or 0.4.

Regarding rounding to the tenths place, if you had a number like 1,459.08 and need to round it, you would look at the digit in the hundredths place which is 8. Since the first dropped digit is 5 or higher, you round up, resulting in 1,459.1.

what is the domain of the composite function G ( F ( x ) )

Answers

B x>2 .....................

on a map the scale is 1 inch equals 60 miles. how many miles would be in 3.5 inches?

Answers

If one inch is 60 then 3 would be 60*3 which is 180. The .5 s half of one so the half of 60 is 30. Add that to 180 and 180+30=210.

The answer is 210 miles
210 miles because since 1 inch = 60 miles and you have 3.5 inches you would simply multiply 60 by 3.5.

22 is 33 1/3% of what number

Answers

66 is ure answer because im a math expert
33 and 1/3=33.33333333333333333333 forever
percent means parts out of 100
33.3333%=33.333333/100=0.33333333 forever
note: 0.333333333 forever=1/3

'of' means multiply

22 is 33 1/3% of what translates to
22=0.33333333 times what
22=1/3 times what
times both sides by 3/1
66=3/3 times what
66=what

the number is 66

divide both sides

Which of the following represents the general term for the sequence 2, 4, 6, 8, 10, . . .?

n + 1
2n
2n - 1

Answers

a(n)=a(1)+(n-1)d=
a(n)=2+(n-1)2=2+2n-2=2n

Answer:

Option (b) is correct.

The general term of the sequence is 2n

Step-by-step explanation:

Given : The  sequence 2, 4, 6, 8, 10, . . .

We have to find the representation of the general term of the given sequence 2, 4, 6, 8, 10, . . .

Consider the given sequence 2, 4, 6, .....

The general term of an arithmetic sequence is given by [tex]a_n=a+(n-1)d[/tex]

where, a = first term

d is common difference

For the given sequence a = 2

and d = 2

Then [tex]a_n=2+(n-1)2=2+2n-2=2n[/tex]

Thus, The general term of the sequence is 2n

which set of data could be used for the box-and-whisker plot shown below

Answers

There is no box and whisker plot, therefore, I can't help you.

Answer:

therers no box

Step-by-step explanation:

Find the equation of the straight line parallel to 2y=3x-7 and passing though the point (0.5,-1)

Answers

2y=3x-7 
y = 3/2x - 7/2
y = 1.5x - 3.5 so slope = 1.5
line parallel so it has same slope = 1.5

y +1 = 1.5(x - 0.5)
y + 1 = 1.5x - 0.75
y = 1.5x  - 1.75

answer: equation y = 1.5x  - 1.75

What is the equation of a line with a slope of –2 that passes through the point (6, 8)?

Answers

y = mx + b
slope(m) = -2
(6,8)...x = 6 and y = 8
now we sub and find b, the y int
8 = -2(6) + b
8 = -12 + b
8 + 12 = b
20 = b
so ur equation is : y = -2x + 20

Answer with explanation:

Slope of Line= -2

The line passes through the point , (6,8).

⇒Equation of line passing through point , (a,b) having slope ,m is

y -b = m (x -a)

⇒≡Equation of line passing through point , (6,8) having slope ,-2 is

→y -8 = -2× (x -6)

→y -8 = -2 x + 12⇒⇒ Using Distributive property of multiplication with respect to Subtraction

→2 x + y= 12 + 8

2 x + y=20

Required Equation of line.

What is 25 divided by 625?

Answers

25/ 625 = 5 / 125 = 1/15

The number of days between Aug. 9 and Jan. 3 is

Answers

147 days is between aug 9 and jan 3

In ∆ABC shown below, ∡BAC is congruent to ∡BCA. Given: Base ∡BAC and ∡ACB are congruent.
Prove: ∆ABC is an isosceles triangle.

Construct a perpendicular bisector from point B to line segment AC.
Label the point of intersection between this perpendicular bisector and line segment AC as point D.
m∡BDA and m∡BDC is 90° by the definition of a perpendicular bisector.
∡BDA is congruent to ∡BDC by the definition of congruent angles. Line segment AD is congruent to line segment DC by _______1________.
∆BAD is congruent to ∆BCD by the _______2________. Line segment AB is congruent to line segment BC because corresponding parts of congruent triangles are congruent (CPCTC).
Consequently, ∆ABC is isosceles by definition of an isosceles triangle.

options are:
a)1. Angle-Side-Angle (ASA) Postulate
2. corresponding parts of congruent triangles are congruent (CPCTC)

b) 1. corresponding parts of congruent triangles are congruent (CPCTC)
2. Angle-Side-Angle (ASA) Postulate

c) 1. the definition of a perpendicular bisector
2. Angle-Side-Angle (ASA) Postulate

d) 1. corresponding parts of congruent triangles are congruent (CPCTC)
2. the definition of a perpendicular bisector

Answers

Refer to the image attached.

Given: [tex]\angle BAC[/tex] and [tex]\angle BCA[/tex] are congruent.

To Prove: [tex]\Delta ABC[/tex] is an isosceles triangle.

Construction: Construct a perpendicular bisector from point B to line segment AC.  Label the point of intersection between this perpendicular bisector and line segment AC as point D.

Proof:

Consider [tex]\Delta BDA, \Delta BDC[/tex]

[tex]\angle BDA = \angle BDC= 90^\circ[/tex]

(By the definition of perpendicular bisector)

[tex]AD=DC[/tex] (By the definition of perpendicular bisector)

So, Line segment AD is congruent to DC by the definition of perpendicular bisector.

[tex]\angle BAC[/tex] = [tex]\angle BCA[/tex] (given)

So,  [tex]\Delta BDA \cong \Delta BDC[/tex] by ASA congruence postulate.

∆BAD is congruent to ∆BCD by the ASA congruence Postulate.

Line segment AB is congruent to line segment BC because corresponding parts of congruent triangles are congruent (CPCTC).

So, Option C is the correct answer.

What is the solution to the system of linear equations
A. (-3,0)
B. (-3,3)
C. (0,2)
D. (3,1)

Answers

the answer is c. (0,2)

Denise has $78.22. she wants to buy a computer that cost $29.99. about how much money will denise has left

Answers

Denise has $50 left.

How do I find dy/dx of the equation 4x^3-3xy^2+y^3=28 at the point (3,4)?

Answers

Final answer:

To find dy/dx of the equation 4x^3 - 3xy^2 + y^3 = 28 at the point (3,4), you can use implicit differentiation and solve for dy/dx.

Explanation:

To find dy/dx of the equation 4x^3 - 3xy^2 + y^3 = 28 at the point (3,4), we need to use implicit differentiation. We differentiate both sides of the equation with respect to x, treating y as a function of x. Thus, we get:

12x^2 - 3y^2 - 3x(2y(dy/dx)) + 3y^2(dy/dx) = 0

Now we substitute x = 3 and y = 4 into the equation and solve for dy/dx:

12(3)^2 - 3(4)^2 - 3(3)(2(4)(dy/dx)) + 3(4)^2(dy/dx) = 0

On monday, deborah ran 3 2/5 miles and on tuesday she ran 4 1/5 miles how many miles did she run on these 2 days togehter

Answers

Final answer:

Deborah ran a total of 7 3/5 miles combined on Monday and Tuesday. This was determined by adding 3 2/5 miles and 4 1/5 miles together after converting them to improper fractions.

Explanation:

On Monday, Deborah ran 3 2/5 miles and on Tuesday she ran 4 1/5 miles. To find the total distance Deborah ran over these two days, we need to add the two distances together. When working with mixed numbers, it's often easiest to convert them to improper fractions before adding.

3 2/5 miles is the same as (3 × 5 + 2)/5 = 17/5 miles.
4 1/5 miles is the same as (4 × 5 + 1)/5 = 21/5 miles.

Adding these two fractions:

17/5 miles + 21/5 miles = (17 + 21)/5 miles

= 38/5 miles

= 7 3/5 miles

So, Deborah ran a total of 7 3/5 miles on Monday and Tuesday combined.

A bag contains only red and blue marbles. Yasmine takes one marble at random from the bag. The probability that she takes a red marble is 1 in 5. Yasmine returns the marble to the bag and adds five more red marbles to the bag. The probability that she takes one red marble at random is now 1 in 3. How many red marbles were originally in the bag?

Answers

If there are x red marbles initially then 1/5 is a probability in it's lowest form cancelled down from: 
1/5 = x/5x 
so there are 5x total marbles, x red and 4x blue. 
Add 5 new red and the new probability is: 
(x+5)/(5x+5) = 1/3 
3x+15 = 5x+5 
2x = 10 

originally there were: 

x = 5 red 
4x = 20 blue 
marbles. 

*************** 
there are now: 

x+5 = 10 red 
4x = 20 blue 
marbles.

hope it helps

What does 28 tens divided by 4 equal?

Answers

7 tens. does that make sense!

You calculate this by first understanding that '28 tens' means 280, and then dividing 280 by 4. So, 28 tens divided by 4 equals 70.

The phrase '28 tens' refers to 28 multiplied by 10, 28 x 10 = 280.

To find the result of dividing this by 4, we calculate 280 ÷  4 = 70.

Therefore, 28 tens divided by 4 equals 70.

Find the volume of the solid formed by rotating the region inside the first quadrant enclosed by y=x^3 and y=9x about the x-axis.
...?

Answers

First solve x³=9x

[tex]x^3-9x=0 \\x(x^2-9)=0 \\x(x-3)(x+3)=0 \\x=0, x=3,x=-3[/tex]

We can ignore x = -3 because it is not in the first quadrant.

So our integral is going to go from x=0 to x=3.

Now we can use the formula
[tex]V=\int_{a}^{b}\pi f(x)^2dx[/tex]
[tex]\int\limits_{0}^{3}(\pi (9x)^2-\pi(x^3)^2)dx \\\int\limits_{0}^{3}(\pi (9x)^2-\pi(x^3)^2)dx \\\pi\int\limits_{0}^{3}(81x^2-x^6)dx \\2\times \int\limits_{0}^{3}[\pi(9x)^2-\pi(x^3)^2]dx \\\pi\left[81\frac{x^3}{3}-\frac{x^7}{7}\right]_{0}^{3} \\ \\\frac{2916\pi}{7}[/tex]
Final answer:

The volume of the solid formed by rotating the region enclosed by y = x^3 and y = 9x about the x-axis in the first quadrant can be found by integrating from 0 to 3, the square of the outer and inner radius, multiplied by π. Solve the integral to get the volume.

Explanation:

To find the volume of the solid formed by rotating the region enclosed by y = x^3 and y = 9x about the x-axis, we need to use the method of discs/washers. The volume V is given by the following integral:

 ∫[a,b] π(r(x)^2 - R(x)^2) dx

For our given curves, r(x) = 9x and R(x) = x^3 since 9x ≥ x^3 for 0 ≤ x ≤ 3. Therefore, we get:

 V = ∫[0,3] π[(9x)^2 - (x^3)^2] dx

Solving this integral will yield the volume of the solid:

 V = π ∫[0,3] (81x^2 - x^6) dx

Calculating this integral will give the volume of the solid.

Learn more about Volume of solid here:

https://brainly.com/question/23705404

#SPJ11

Find equations of the tangent lines to the curve
y = (x − 1)/(x + 1)
that are parallel to the line
x − 2y = 3.

Answers

Final answer:

To find the tangent lines to the curve y = (x - 1)/(x + 1) that are parallel to the given line, convert the given line to slope-intercept form to find the slope, take the derivative of the curve to find where its slope matches the line's slope, and utilize these points to write the equations of the tangent lines.

Explanation:

To find the equations of the tangent lines to the curve y = (x − 1)/(x + 1) that are parallel to the line x − 2y = 3, we first need to find the slope of the given line by rewriting it in slope-intercept form (y = mx + b), where m is the slope. Rewriting x − 2y = 3 gives us y = ⅓x - ⅓; thus, the slope (m) is ⅓.

Next, we find the derivative of the curve, y' = dy/dx, which will give us the slope of the tangent at any point x. Taking the derivative of y = (x − 1)/(x + 1) using the quotient rule or another differentiation method, we find a general expression for y'. We then set y' equal to ⅓ to find the points where the slope of the tangent is equal to the slope of the given line.

After determining the x-values where the tangent has the correct slope, we calculate the corresponding y-values on the curve and use these points to write the equations of the tangent lines in the form y = mx + b, substituting the slope (⅓) and our found points (x, y).

Final answer:

To find the equations of the tangent lines to the given curve that are parallel to the given line, we differentiate the curve's equation to find its slope, equate it to the slope of the given line, solve for x, substitute the values back into the curve's equation to find the corresponding y-values, and use the point-slope form of the equation of a line to find the equations of the tangent lines.

Explanation:

To find the equations of the tangent lines to the curve y = (x − 1)/(x + 1) that are parallel to the line x − 2y = 3, we can use the slope of the given line as the slope of the tangent lines. The slope of the given line is 1/2, so the slope of the tangent lines is also 1/2.

Next, we can differentiate the equation of the curve y = (x − 1)/(x + 1) with respect to x to find the slope of the curve at any point. Taking the derivative, we get dy/dx = 2/(x + 1)².

Since the tangent lines are parallel to the given line, their slopes are equal. Therefore, we can equate the slope of the curve to the slope of the tangent lines and solve for x:

2/(x + 1)² = 1/2

Solving this equation, we get x = -1 or x = 1.

Substituting these values of x back into the equation of the curve, we can find the corresponding y-values. The coordinates of the points where the tangent lines intersect the curve are (-1, -2) and (1, 2).

Finally, we can use the point-slope form of the equation of a line to find the equations of the tangent lines:

Tangent line at (-1, -2): y + 2 = (1/2)(x + 1)

Tangent line at (1, 2): y - 2 = (1/2)(x - 1)

15-28i=3m+4ni find the values of m and n that make this equation true

Answers

since it easy u must equal the real # with the real # and the same for complex

so that 15+3*m =0 m=-5
-28 =4n n= -7

Final answer:

The values of m and n that satisfy the equation 15 - 28i = 3m + 4ni are m = 5 and n = -7 after equating and solving the real and imaginary parts separately.

Explanation:

To find the values of m and n that make the equation 15 - 28i = 3m + 4ni true, we must equate the real parts and the imaginary parts of both sides of the equation separately. The real part of the left side of the equation is 15, and the imaginary part is -28i. Similarly, for the right side, the real part is 3m, and the imaginary part is 4ni.

Equate the real parts: 15 = 3m
Dividing both sides by 3, we get m = 5.

Equate the imaginary parts: -28i = 4ni
Dividing both sides by 4i, we get n = -7.

Hence, the values that satisfy the equation are m = 5 and n = -7.

How many solutions does the following equation have?

3x + 6 = 3(x + 2)

Answers

3x+6=3(x+2)
3x+6=3x+6
minus 6 both sides
3x=3x
divide by 3
x=x

true

therefor all numbers work for x

there are infinite soltuions

find the limit 3/x^2-6x+9 as x approaches 3 ...?

Answers

Lim [3 / (x^2 - 6x + 9)] = Lim [3 / (x -3)^2]    ...(by factoring)

Find the side limits:

x -->3 +    =>  Lim [3 / (x -3)^2] = 3/0 = ∞

x -->3 -    =>  Lim [3 / (x -3)^2] = 3/0 = ∞

Then the limit is ∞

Write the following number in scientific notation:
0.000721

Note from userneedshelp12: I do not understand scientific notation at all. So, if you help, will you please explain how you got your answer?

Answers

scientific notations are easy once you get the hang of it. basically you're just trying to rewrite a really big or small number in a more easy to understand format. you have to move the decimal point to make a that is above 1 (1 is included) and less than 10, so you just keep moving the decimal point to the right until you get to 7.21 since that is between 1 and 10, but you're not done. now you have to write how far the decimal place moved in this case it moved 4 to the right so you write 7.21x10^-4. if instead your example was 72100 then it moves 4 to the left and you have 7.21x10^4.

Simplify the given expression:

4/3-2i

Answers

The answer is [tex]\frac{12+8i}{13} [/tex]

[tex] \frac{4}{3-2i} = \frac{4(3+2i)}{(3-2i)(3+2i)} \\ \\ (a-b)(a+b) = a^{2} -b^{2} \\ \\ \frac{4(3+2i)}{(3-2i)(3+2i)} = \frac{4*3+4*2i}{3 ^{2}- (2i)^{2} }= \frac{12+8i}{9- (2)^{2}(i)^{2} }= \frac{12+8i}{9-4(i)^{2}} \\ \\ (i)^{2} = -1 \\ \\ \frac{12+8i}{9-4(i)^{2}}== \frac{12+8i}{9-4*(-1)}}= \frac{12+8i}{9+4} = \frac{12+8i}{13} [/tex]

Combine as indicated by the signs. Write answer in descending powers of x.
(x+6/x^2+8x+15) + (3x/x+5) - (x-3/x+3) ...?

Answers

Final answer:

The student is required to combine three algebraic fractions with different denominators using factoring to find a common denominator and then simplify the expression.

Explanation:

The question entails a topic in algebra, specifically with respect to combining expressions with different denominators, which requires finding a common denominator, and working with signs and exponents. The problem presents three fractions that should be combined: (x+6)/(x^2+8x+15), (3x)/(x+5), and (x-3)/(x+3).

Firstly, note that the denominator x^2+8x+15 can be factored into (x+3)(x+5). This will allow us to identify a common denominator for all three fractions, which is (x+3)(x+5). We rewrite the fractions so that each has the common denominator:

(x+6)/((x+3)(x+5))(3x)/(x+5) will be rewritten as (3x)(x+3)/((x+3)(x+5))(x-3)/(x+3) will remain as (x-3)/(x+3) because it already has part of the common denominator

Now we simply combine these three fractions over the common denominator:

((x+6) + (3x)(x+3) - (x-3)) / ((x+3)(x+5))

After the combination, the terms must be simplified and ordered in descending powers of x, which is the final answer.

Descending powers of x is [tex]\[ \frac{2x^2 + 8x + 15}{(x + 3)(x + 5)} \][/tex].

To combine the given expressions, we need to find a common denominator and then combine the numerators. Here are the expressions given:

[tex]\[ \frac{x}{x^2 + 8x + 15} + \frac{3x}{x + 5} - \frac{x - 3}{x + 3} \][/tex]

First, let's factor the quadratic denominator in the first term if possible and identify the common denominator:

The quadratic [tex]\( x^2 + 8x + 15 \)[/tex] can be factored into [tex]\( (x + 3)(x + 5) \)[/tex], since 3 and 5 are factors of 15 that add up to 8.

Now we have:

[tex]\[ \frac{x}{(x + 3)(x + 5)} + \frac{3x}{x + 5} - \frac{x - 3}{x + 3} \][/tex]

The common denominator will be [tex]\( (x + 3)(x + 5) \)[/tex].

Now, let's rewrite each fraction with the common denominator:

The second term already has [tex]\( x + 5 \)[/tex] in the denominator, so we multiply the numerator and denominator by [tex]\( x + 3 \)[/tex]to have the common denominator.

[tex]\[ \frac{3x}{x + 5} \rightarrow \frac{3x(x + 3)}{(x + 5)(x + 3)} \][/tex]

The third term has [tex]\( x + 3 \)[/tex] in the denominator, so we multiply the numerator and denominator by \( x + 5 \) to have the common denominator.

[tex]\[ \frac{x - 3}{x + 3} \rightarrow \frac{(x - 3)(x + 5)}{(x + 3)(x + 5)} \][/tex]

Now all terms have a common denominator, and we can combine them as follows:

[tex]\[ \frac{x}{(x + 3)(x + 5)} + \frac{3x(x + 3)}{(x + 3)(x + 5)} - \frac{(x - 3)(x + 5)}{(x + 3)(x + 5)} \][/tex]

Combine the numerators while keeping the denominator the same:

[tex]\[ \frac{x + 3x(x + 3) - (x - 3)(x + 5)}{(x + 3)(x + 5)} \][/tex]

Now, let's expand and simplify the numerator:

[tex]\[ x + 3x^2 + 9x - (x^2 + 2x - 15) \][/tex]

[tex]\[ x + 3x^2 + 9x - x^2 - 2x + 15 \][/tex]

Combine like terms:

[tex]\[ 3x^2 - x^2 + x + 9x - 2x + 15 \][/tex]

[tex]\[ 2x^2 + 8x + 15 \][/tex]

Now, let's put it all over the common denominator:

[tex]\[ \frac{2x^2 + 8x + 15}{(x + 3)(x + 5)} \][/tex]

This is the simplified expression in descending powers of \( x \). Since the numerator is already in descending powers of \( x \), this is the final answer. There is no further simplification possible because the numerator and the denominator do not have common factors other than 1.

Other Questions
Which characteristic of coastal dynamics limits the abundance of aquatic organisms? Consistent water depth levels Consistent water temperatures Varied tidal action Varied water salinity Describe the hybrid orbitals used by the central atom and the types of bonds formed in o3 what led to the creation of the cistercian order. explain how it is different from the benedictine order what is the bloody kansas A tree or plant can live without its bark or epidermis.TrueFalse 1. Why are there so many astronomical observatories in southern Arizona?A) Many bilingual people live there.B) The state's open and high spaces are great for observation.C) Its warm and dry weather is Ideal.D) The border states are cooperative.2. Why Have schools and families in the Spanish-Speaking world historically included classes in manners?A) They do not have time to teach their children at home.B) They do not have the money to teach their children at homeC) They want to train their children to live in other countriesD) They believe that a child who is trained in manners will be a better adult3. What is one reason that bilingual schools are a benefit over full-immersion schools?A)because all the students will be able to understand each otherB) Because the textbooks work out betterC) Because the English- Speaking students learn SpanishD) Because the Spanish speaking students learn English4. Why is it helpful for adults in south Texas to speak both English and Spanish?A) it is required by lawB) It makes it easier to find a jobC) bilingual people make more moneyD) bilingual people can read goverment documents What makes some collisions elastic and others inelastic?Question 17 options:If there is energy lost in the collision to sound, heat, etc., the collision is inelastic.If there is no loss of kinetic energy in the collision, it is inelastic.If the collision involves bouncing, it is elastic.If the collision involves sticking together, it is elastic. Please help!!! It's about the types of quantities if they are proportional or not if there is a constant number. Between 1830 and 1850, immigrants who moved to American cities oftenfaced dangerous and crowded living conditions.earned high wages as skilled laborers in factories.worked in service jobs as police officers or firemen.fled to work on farms, as they had in their home countries. what role did technology play in the scientific revolution? Divide 28x3 + 42x2 - 35x by 7x When joining two independent clauses with a coordinating conjunction, where do you place the comma? A model is made of a car. The car is 8 FEET long and the model is 10 INCHES long. What is the ratio of the length of the car to the length of the model? a)10:8 b)48:5 c)5:48 d)8:10 Choose the answer.Add.34.231 + 45.23 A. 38.754 B. 79.434 C. 79.461 D. 79.462 Authors can create an in-depth characterization moment by emphasizing the consistency of a character for a long time, and then changing that character in some very minor way.TrueFalse which word is the pronoun that names the speaker in the sentence "We found one more member for the book club" sally is x years old and her sister ann is 4years younger. If the product of their ages is 140, form an equation in x and solve it to find ann's age WILL UPVOTE!Question 3 (Multiple Choice)Your friend has learned recipes for several sugary pies and cakes and wants you to be the "tester" for each one. What type of peer pressure is this?A) HealthyB) IncreasedC) PositiveD) Negative identify the underlined phrase in the sentence the idea of alien life (proposed many years ago) has not yet been proven(according to the letter) the wedding is june 25thMikayla's homeroom teacher, (mr. Jones) is very proud of her(talking) is not allowed in class Two charged particles Q1 and Q2 are a distance r apart with Q2=5Q1.Compare the forces they exert on one another when F1 is the force Q2 exerts on Q1 and F2 is the force Q1 exerts on Q2a)F2=-5F1b)F2=5F1c)F2=F1d)F2=-F1