A student wonders whether removing the nucleus from a cell would result in a new prokaryotic cell. Why would this procedure fail to produce a prokaryotic cell?

Answers

Answer 1
well assuming the original cell is a prokaryotic, you wouldn't be able to remove the nucleus because prokaryotic cells don't have a nucleus to begin with. if this doesn't help then: The cell would lack genetic information.

Answer 2

Answer:

Removing the nucleus from the cell would not make it prokaryote because there are more characteristics that makes a cell prokaryote.

A eukaryotic cell has nucleus as well as membrane bound organelles found in the cytoplasm.

Even if the student will remove nucleus from the cell, the membrane bound cell organelles will remain in the cell.

Hence, only removing the nucleus from the cell would not make it a new prokaryotic cell.


Related Questions

A dysbarism injury refers to the signs and symptoms related to changes in

Answers

Answer:  "barometric pressure" .
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List five proteins of the myofilaments and describe their physical arrangement

Answers

The five proteins of the myofilaments are the following:

1.  Myosin, shaped like a golf club, with two polypeptides intertwined to form a shaftlike tail and a double globular head, or cross-bridge, projecting from it at an angle.

2. Fibrous actin is like a bead necklace—a string of subunits called globular (G) actin. Each G actin has an active site that can bind to the head of a myosin molecule.

3. Tropomyosin. It blocks the active sites of six or seven G actins and prevents myosin cross-bridges from binding to them when a muscle fiber is relaxed.

4. Troponin a smaller calcium-binding protein bound to each tropomyosin molecule.

5. Titin (connectin), run through the core of a thick filament, emerge from the end of it, and connect it to a structure called the Z disc.





Final answer:

The five proteins of the myofilaments in muscle fibers are actin, myosin, tropomyosin, troponin, and alpha-actinin. Actin is the main component of thin filaments, while myosin is the main component of thick filaments. Tropomyosin blocks the binding sites on actin, troponin regulates the interaction between actin and myosin, and alpha-actinin attaches thin filaments to the Z disc.

Explanation:

The myofilaments in muscle fibers are composed of various proteins. The five proteins of the myofilaments are:

Actin: Actin is the primary component of thin filaments. It has binding sites for myosin attachment.Myosin: Myosin is the main component of thick filaments. The tail of a myosin molecule connects with other myosin molecules to form the central region of a thick filament near the M line, while the heads align on either side of the thick filament where the thin filaments overlap.Tropomyosin: Tropomyosin is a protein that blocks the binding sites on actin, preventing actin-myosin interactions when the muscles are at rest.Troponin: Troponin consists of three globular subunits. One subunit binds to tropomyosin, one subunit binds to actin, and one subunit binds Ca²+ ions.Alpha-actinin: Alpha-actinin is a protein that attaches thin filaments to the Z disc.

Greg is hooked up to an eeg and his brain is producing smooth waves at a rate of about 10 per second. greg is most likely:

Answers

Final answer:

Greg's brain is likely producing alpha waves which indicate a state of relaxed wakefulness or the early stages of sleep, known as stage 1 sleep.

Explanation:

If Greg is hooked up to an EEG (electroencephalogram) and his brain is producing smooth waves at a rate of about 10 per second, Greg is most likely in a state of wakefulness or very relaxed wakefulness. These types of brainwaves are known as alpha waves, which are commonly associated with a state of relaxed alertness, typically with eyes closed, and are present in the frequency range of 8-12 Hz. The presence of alpha waves indicates that Greg is probably not in a deep sleep state but could be in the early stages of sleep, known as stage 1 sleep, where alpha waves are prevalent before transitioning into theta waves as sleep deepens.

Nicoli suffered a stroke in the left hemisphere of his brain. which skill is most likely to have been affected?

Answers

The skill which will be affected is LANGUAGE.
The left hemisphere of the brain is responsible for controlling analytic thought, logic, language, writing, number skills, etc. The left hemisphere of the brain also controls the right side of the body.

Given the sequence of dna below, what would be the sequence of bases on the daughter strand after dna replication? ggccggctacca

Answers

According to Watson and Crick, in double stranded helical DNA the bases are hydrogen bonded in the following order:

adenine (A) base pairs with thymine (T) through two hydrogen bonds

Guanine (G) base pairs with Cytosine (C) through three hydrogen bonds.

So, if we have a DNA sequence of GGCCGGCTACCA, its corresponding daughter strand will have following sequence i.e., CCGGCCGATGGT

What diagnostic procedure would be used to measure the patient's hearing loss?

Answers

The diagnostic procedure used to measure the patient's hearing loss are as follows:
1. Physical examination that includes examining any earwax or inflammation due to an infection.
2. Tuning Fork Test: This test is done to detect hearing loss by strucking a tuning fork that produces sound.
3. Audiology Hearing Test: It is also known as Audiometer test. In this test the Audiologist presents a variable range of sound to detect the hearing loss.

This condition occurs when the heart is too weak to pump blood to the body:

Answers

dilated cardiomyopathy i believe 

Platyhelminths (flatworms) have practically no fossil record

Answers

The answer TRUE they do not have a fossil record.

True I have researched that they do not have any fossil record

An infant of a diabetic mother is admitted to the neonatal intensive care unit. what is the priority nursing intervention for this infant?

Answers

If an infant of a diabetic mother is admitted to the neonatal intensive care unit, the nurse should EVALUATE THE EFFECT OF MOTHER GLUCOSE LEVEL IN THE INFANT BY PERFORMING A BLOOD TEST ON THE NEWBORN. This test is known as Heel Stick Blood Test. It is used to determine the blood glucose level in the infant.

In a solution of a carbonated beverage, the water is the Blank Space __________.



solute


solvent


saturated


precipitate

Answers

B is correct water is a solvent.

Answer:

b

Explanation:

A location has the conditions stated below. warm ocean water winds to carry air upwards Which of these weather conditions is most likely to occur in the location?
a. blizzard
b. lightning
c. tornadoes
d. hurricanes

Answers

Final answer:

The presence of warm ocean water and rising air currents indicates the likely occurrence of hurricanes in the described location.

Explanation:

The weather conditions most likely to occur in a location with warm ocean water and winds carrying air upwards are hurricanes. These conditions are conducive to the formation of tropical cyclones, which can drastically alter the physical and cultural landscape if they reach land. In the North Atlantic Ocean and the Caribbean Sea, this type of weather pattern is called a hurricane. Hurricanes develop over water that is warmer than 80 °F, with rapidly rising humid air that creates strong wind currents, heavy rains, and a cyclonic pattern due to the rotation of the earth.

Give a man a fish and hell eat for a day teach him to fish and get rid of him

Answers

This is very true but I don't see the question
Hope this is what you are asking for:

When discussing foreign aid, Nelson employed a modern version of the saying and called it a “Chinese proverb”: Foreign aid—“You give a poor man a fish and you feed him for a day. You teach him to fish and you give him an occupation that will feed him for a lifetime.

Hope this helps :))

What are the diference between aerobic and anaerobic cellular respiration?

Answers

Aerobic respiration uses oxygen to produce ATP. Anaerobic respiration uses inorganic molecules to produce ATP. I hope that answered your question, my friend. :)

Answer:

Living organisms use energy released by respiration for their life functions. There are two types of respiration - aerobic respiration and anaerobic respiration. Two of these processes are different due to following reasons:

1. Requirement of oxygen: Aerobic respiration requires oxygen to breakdown glucose. Anaerobic respiration does not requires oxygen to breakdown glucose.

2. Breakdown of glucose: In aerobic respiration glucose is broken down completely into byproducts whereas, in anaerobic respiration glucose is not broken down completely.

3. End products: In aerobic respiration the byproducts are carbon dioxide and water whereas in anaerobic respiration in animals : lactic acids and in plants and yeast: carbon dioxide and ethanol.

4. Amount of energy production: In aerobic respiration, the energy released is in large amount due to complete breakdown of glucose whereas, in anaerobic respiration the energy is less due to incomplete glucose breakdown. Aerobic respiration produces 36-38 ATP molecules whereas, anaerobic respiration produces 2-36 ATP molecules.

5. Reaction site: In aerobic respiration, the reaction site is mitochondria or cytoplasm and in anaerobic respiration, the reaction site is only cytoplasm.  

Infant rats deprived of their mothers' grooming touch produce:

Answers

less growth hormones and a lower metabolic rate 
Final answer:

Infant rats deprived of their mothers' grooming touch can produce depressive-like symptoms during adolescence. Negative early life experiences can alter brain function and lead to behavioral issues later in life. Maternal-infant bonding and social contact are important for healthy development in rats and other animals.

Explanation:

Infant rats deprived of their mothers' grooming touch produce depressive-like symptoms during adolescence (Raineki et al., 2012). Research has shown that negative early life experiences, such as abusive treatment or isolation, can alter brain function and lead to behavioral issues later in life (Raineki et al., 2012; Moriceau & Sullivan, 2006; Harlow & Harlow, 1962; Harlow, 1971). This highlights the importance of maternal-infant bonding and social contact for healthy development in rats and other animals.

Describe how mutations could lead to drug resistance in the RT enzyme. Include physical, molecular, and biochemical reasons.

Answers

Final answer:

Mutations in the RT enzyme can confer drug resistance by modifying the enzyme's structure, hindering drug binding, or altering enzyme affinity for the drug. Physical barriers can also prevent drug penetration, while biochemical changes may enable the enzyme to degrade the drug, rendering it ineffective.

Explanation:

Mutations can lead to drug resistance in the reverse transcriptase (RT) enzyme through several mechanisms, including enzymatic modification of the drug, modification of the antimicrobial target, and prevention of drug penetration or accumulation. For RT inhibitors, mutations in the viral enzyme can alter its structure in such a way that the drug no longer binds effectively, thereby rendering the drug ineffective. This biochemical alteration can result from a direct change in the amino acid sequence of the enzyme that affects its active site or the overall conformation. Moreover, if the RT enzyme undergoes mutation that results in an altered affinity for the antiretroviral drugs, this can also lead to the development of resistance.

Physical changes in the viral envelope can impede drug penetration, preventing the drug from reaching effective concentrations within the viral cell. In the context of molecular changes, mutations in the viral genome can lead to structural changes in the target enzyme that prevent drug binding. Additionally, biochemical mechanisms include the possibility of viral enzymes evolving to degrade the drug, similar to how bacterial enzymes such as ß-lactamases break down antibiotics like ß-lactams.

These resistance mechanisms highlight the complexity and challenge of developing treatments for viral infections such as HIV, where the RT enzyme is a key target. The propensity for rapid mutation and evolution in the viral genome necessitates the use of combination drug therapies to minimize the development of drug-resistant strains.

How are the products represented in the chemical equation for photosynthesis?

A) O2 + 6CO2
B) C6H12O6 + 6H2O
C) 6CO2 + 6H2O
D) C6H12O6 + 6O2

Answers

The correct option is D.
During the process of photosynthesis, carbon dioxide and water react together in the presence of sunlight energy to form glucose and oxygen. Glucose and oxygen are the product of photosynthesis. The chemical formula for glucose is C6H12O6 and that of oxygen is O2.

Answer:

d

Explanation:

it just is

Briefly describe the chicken experiment. Why is it relevant?

Answers

The chicken experiment serves to explain how behavioral conditioning may be applied to any species. By identifying an appropriate reward for the subject in question, that subject may be taught any physically possible random behavior. Then, if witnessed, the behavior is able to be learned and mimicked by other members of the same or even different species.

A lung cell maintains homeostasis. Of what is this an example?

A: intercellular communication
B: intracellular communication
C: ion channel-linked receptor
D: enzyme-linked receptor

Answers

The right answer is A: intercellular communication.

An example of intercellular communication is the one between the kidney, liver and lungs to preserve water-soluble homeostasis.

Angiotensinogen, an inactive protein produced by the liver, circulates in the blood. It is the precursor of the active peptides angiotensin I and II, and the only substrate of renin.

In the event of a drop in the pressure in the renal artery, renin (an enzyme sometimes considered as a hormone) is secreted in the kidney by differentiated myoepithelial cells of the arteriole afferent of the juxtaglomerular apparatus. There are also other stimuli promoting renin secretion: decreased natremia in the distal convoluted tubule, ß-agonists, hyperkalemia, PGI2 and stimulation of juxta-glomerular cells by the sympathetic nervous system)

The angiotensinogen is cleaved by the renin and forms a decapeptide called "angiotensin I", inactive.

Angiotensin I will then be converted primarily to angiotensin II by a carboxypeptidase, the angiotensin converting enzyme. This enzyme, secreted by the liver, acts at the pulmonary level.

Answer:

The answer is Intracellular Communication

Explanation:

A lung cell maintains homeostasis is an example of intracellular communication. The concept of intracellular communication includes an anterograde and retrograde signaling network between nucleus and the two organelles, enabling this interactive exchange of information essential for cellular hemostasis.

Why is the interphase the longest phase in the cell cycle?

Answers

Interphase is the longest phase because of DNA duplications, replication, chromosomes division take place, so it takes more time for the cell cycle

Interphase is the longest phase in the cell cycle largely due to the various critical processes that occur during this stage, which include cell growth, DNA replication, and preparation for division. These processes are divided among three subphases: G1, S, and G2. The S phase, where DNA replication occurs, is particularly time-consuming, taking up around 10-12 hours. In contrast, the Mitotic phase only lasts approximately 1 hour. The extended time in Interphase ensures accurate duplication of chromosomes and prepares the cell for a successful division.

The length of Interphase can be attributed to the vital activities a cell must undertake to maintain proper function and to prepare for cell division. During the G1 phase, which can last from a few hours to several days, the cell grows, performs its specific functions, and prepares for DNA replication. The S phase is where the entire genomic DNA is replicated which is a complex process and therefore quite lengthy. Following this, in the G2 phase, the cell synthesizes proteins and makes the necessary preparations for mitosis. Since these processes are so crucial and require meticulous work to prevent errors, the interphase generally occupies about 90% of the cell cycle's duration.

Both mitosis and meiosis begin with a diploid cell that contains replicated chromosomes. Explain the main differences between the two processes and what types of daughter cells produced by each

Answers

mitosis- finishes with 2 genetically identical daughter cells, 2n, diploid, and the chromosomes are seperated

meiosis- finishes with 4 daughter cells that are genetically different and half the original dna, n, haploid, the homologous chromosomes are seperated first then the sister chromatids are split up. during prophase 1, the tetrad of homologs cross over giving one way genetic diversity can occur. metaphase 1 has the law of independent assortment which is another way genetic variation occurs

A scientist is working with methane (CH4) and butane (C4H10). Which statement best compares these chemicals?
They are two different types of molecules that each contain the same number of atoms.
They are two different types of atoms that are each made up of a different number of elements.
They are compounds made of the same two elements, but each contain different numbers of atoms.
They are matter made of the same two compounds, but each contain different types of elements.

Answers

its is c i just did it in ed

Answer : The correct option is, They are compounds made of the same two elements, but each contain different numbers of atoms.

Explanation :

The methane and butane is a hydrocarbon in which the carbon and hydrogen are bonded through covalent bond. Methane and butane are the homologous series of alkane.

Methane and butane are the compounds which is made up of the same elements but each of the compound contains different number of atoms.

In methane [tex](CH_4)[/tex], there are 4 number of hydrogen atoms and 1 number of carbon atom.

In butane [tex](C_4H_{10})[/tex], there are 10 number of hydrogen atoms and 4 number of carbon atoms.

Hence, the best statement is, they are compounds made of the same two elements, but each contain different numbers of atoms.

A particular population of chickens has a frequency for the dominant allele as 0.70 and a frequency for the recessive allele as 0.30. Which expression is the correct way to calculate the frequency of individuals that are heterozygous?

A) (0.70) x (0.30)

B) (0.70) - (0.30)

C)2 x (0.70) x (0.30)

D)2 x (0.70 - 0.30)

Answers

The Hardy-Weinberg equation is as follows:

p² + 2pq + q² = 1

Where p is the frequency of the homozygous dominant genotype, q is the frequency of the homozygous recessive genotype and 2pq is the frequency of the heterozygous genotype. Using the 2pq term here,

Frequency of heterozygous = 2 * 0.7 * 0.3

Therefore, option is correct.

The correct expression to calculate the frequency of heterozygous chickens with dominant allele frequency of 0.70 and recessive allele frequency of 0.30 is 2 x (0.70) x (0.30), which corresponds to Hardy-Weinberg principle expression 2pq.

To calculate the frequency of individuals that are heterozygous in a particular population of chickens with a frequency for the dominant allele (A) as 0.70 and a frequency for the recessive allele (a) as 0.30, we use the Hardy-Weinberg principle for a gene with two alleles. According to this principle, if p represents the dominant allele frequency and q represents the recessive allele frequency, then the expression for heterozygous individuals is 2pq. Thus the correct expression to calculate the frequency of heterozygous individuals is 2 x (0.70) x (0.30), which corresponds to option C.

We can see this application in examples of other populations mentioned, for instance, a gene pool with allele frequencies of 0.6 for R and 0.4 for r demonstrates that a heterozygous frequency can be calculated using 2pq. In this example, the frequency of heterozygous individuals (Rr) would be 2(0.6)(0.4), which also applies to our chicken population problem.

The study of health and disease within a geographic context and from a spatial perspective is

Answers

the study of health and disease within a geographic context and from a spatial perspective is medical geography.

God bless!

An abnormal heart rhythm resulting from impulses coming from a locus of tissue in the area of the atrioventricular node is called _______.

Answers

is called - Junctional rhythm

Which process requires dna to undergo duplication before it can proceed?

Answers

meiosis and mitosis process requires dna to undergo duplication before it can proceed. Meiosis has two rounds of genetic separation and cellular division while mitosis only has one of each. In meiosis homologous chromosomes separate leading to daughter cells that are not genetically identical. In mitosis the daughter cells are identical to the parent as well as to each other.

Scientists use specific levels of organization to analyze the biosphere. The Everglades are a large area of subtropical wetlands in Florida. Various species of plants and animals can be found in the Everglades, including panthers, cypress trees, herons, and alligators. mc020-1.jpg The group of ecosystems on Earth that feature climate, vegetation, and wildlife similar to the Everglades is a biosphere. a community. a population. a biome.

Answers

The correct answer is a biome.  

Biomes are very enormous ecological regions on the surface of the Earth, with plants and animals amending to their surroundings. They are usually illustrated by abiotic elements like geology, climate, soils, and vegetation. A biome is generally not considered as an ecosystem, however, in a manner, it can appear like a huge ecosystem.  



Answer:

The anwser is Biome

Explanation:

Have a nice day <333

Felicia smacks her thumb with a hammer while building a doghouse. the sense of ________ provides her brain with information about the pain she feels.

Answers

Nociception is the physiological sense that signals the brain about damaged nerves or tissue. Felicia's nociceptors, or pain sensory receptors, respond to the damaging stimulus of the hammer on her thumb by sending information to the spinal cord and brain, making her feel physical pain, thus allowing her to react to the situation in an appropriate manner. Even though her pain receptors are usually silent (or dormant), they react instantaneously to the damage.

The sense of touch provides Felicia's brain with information about the pain she feels when smacking her thumb with a hammer while building a doghouse.

The sense of touch provides Felicia's brain with information about the pain she feels when smacking her thumb with a hammer while building a doghouse. The pain receptor cells in her thumb send electrical signals to her brain, which interprets these signals as the sensation of pain.

Learn more about sense of touch here:

https://brainly.com/question/33710813

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Which tree species is a pioneer species in north american forests?

Answers

Final answer:

In North American forests, pioneer species like annual plants and grasses are the first to recolonize an area after a disturbance, leading to a sequence of ecological succession that culminates in a stable climax community.

Explanation:

A pioneer species is a species that is the first to colonize previously disrupted or damaged ecosystems, beginning a chain of ecological succession that ultimately leads to a more biodiverse steady-state ecosystem. In North American forests, especially after disturbances like forest fires, annual plants are usually the first to grow back, followed by quickly growing and spreading grasses and forbs. As the environment changes due to their growth, other plants, such as birch trees and fireweed, can move in, and organic matter from these species improves the soil. Over time, these are succeeded by intermediate species like shrubs, and small pine, oak, and hickory trees. Eventually, this leads to the formation of a climax community, a stable ecosystem that remains until the next disturbance.

Are biogenic amine neurotransmitters such as dopamine considered to be proteins

Answers

No, biogenic amine neurotransmitters such as dopamine are not considered to be proteins, because it simply means that dopamine has at least one amine functional group in its molecular structure.
It is a biogenic substance with one or more amine groups, this is called a biogenic amine.

What general type of microscope uses bright illumination and multiple glass lenses?

optical
dark
electron
compound

Answers

It should be the light/compound microscope

Answer:

The correct answer is compound microscope.

Explanation:

The compound microscope is an optical microscope that has more than one objective lens. They are especially used to examine transparent objects, or cut into sheets so thin that they are transparent. It is also used to increase or enlarge the images of objects and organisms not visible to the naked eye, this is achieved through two optical systems (which are each made with one or more lenses) and these act consecutively achieving its mission of expanding or increase the images of organism and objects observed.

The common compound microscope is made up of three systems: The mechanical system is made up of a series of pieces in which the lenses that allow movement for focusing are installed. The optical system comprises a set of lenses arranged in such a way that it produces the increase of the images that are observed through them. The lighting system comprises the parts of the microscope that reflect, transmit and regulate the amount of light necessary to perform the observation through the microscope.

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