Answer:
D. No the answer is not reasonable. it should be about 10 pounds.
I took the test.
Answer:
No, the answer is not reasonable. It should be about 10 pounds.
Step-by-step explanation:
Given,
The quantity of hot dog bought by Jill's club = [tex]4\frac{2}{5}[/tex] pounds,
Hot dog = [tex]3\frac{1}{2}[/tex] pounds
Hamburger = [tex]2\frac{3}{10}[/tex] pounds
So, the total quantity of meat they bought
[tex]=4\frac{2}{5}+3\frac{1}{2}+2\frac{3}{10}[/tex]
[tex]=\frac{22}{5}+\frac{7}{2}+\frac{23}{10}[/tex]
[tex]=\frac{44+35+23}{10}[/tex] ( Adding fractions ),
[tex]=\frac{102}{10}[/tex]
[tex]=10.2\text{ pounds}[/tex]
Since, [tex]8\frac{1}{2}=\frac{17}{2}=8.5[/tex]
[tex]\implies 8.5\neq 10.2[/tex]
Hence, the student's answer is not reasonable it should be about 10 pounds.
Third option is correct.
Drag each tile to the correct box. Arrange the equations in order from least to greatest bed on their solution. Equation A: 5( x-6)+3x=3/4(2x-8) Equation B: 2.7(5.1x+4.9)=3.2+28.9 Equation C: 5(11x-18)=3(2x+7)
Answer:
B
C
A
Step-by-step explanation:
Find the value of x in each equation then compare the solutions from the least to the greatest
In A
5( x-6)+3x=3/4(2x-8) ------------Open brackets
5x-30+3x=3/2x-6
5x+3x-30=3/2x-6
8x-3/2x=-6+30---------------collect like terms
16x-3x=48
13x=48-----------------dived both sides by 13
x=48/13 = 3.7
In B
2.7(5.1x+4.9)=3.2+28.9-------------open bracket
13.77x+13.23=32.1
13.77x=32.1-13.23---------------collect like terms
13.77x=18.87
x=18.87/13.77----------------------divide both sides by 13.77
x=1.37
In C
5(11x-18)=3(2x+7)--------------------open brackets
55x-90=6x+21
55x-6x=21+90-----------------------collect like terms
49x=111----------------------------------divide both sides by 49 to get x
x=111/49 = 2.27
From the solutions, the least value of x is in B, then C ,and finally A
Equation B:[tex]\(x \approx 1.371\)[/tex]
Equation C:[tex]\(x \approx 2.2653\)[/tex]
Equation A: [tex]\(x = \frac{48}{13}\)[/tex]
Order from least to greatest: B, C, A.
To solve each equation, let's start by simplifying each side of the equation step by step.
Equation A:[tex]\(5(x-6) + 3x = \frac{3}{4}(2x - 8)\)[/tex]
Step 1: Distribute the numbers:
[tex]\(5x - 30 + 3x = \frac{3}{4}(2x) - \frac{3}{4}(8)\)[/tex]
Step 2: Combine like terms:
[tex]\(8x - 30 = \frac{3}{2}x - 6\)[/tex]
Step 3: To get rid of the fraction, multiply both sides by 2:
(16x - 60 = 3x - 12)
Step 4: Move all (x) terms to one side by subtracting (3x) from both sides:
(16x - 3x - 60 = -12)
Step 5: Combine like terms:
(13x - 60 = -12)
Step 6: Add 60 to both sides to isolate (x):
13x = 48
Step 7: Divide both sides by 13 to solve for (x):
[tex]\(x = \frac{48}{13}\)[/tex]
Equation B: 2.7(5.1x + 4.9) = 3.2 + 28.9
Step 1: Distribute the number:
13.77x + 13.23 = 32.1
Step 2: Move the constant to the other side by subtracting 13.23 from both sides:
13.77x = 18.87
Step 3: Divide both sides by 13.77 to solve for (x):
x ≈ 1.371
Equation C: (5(11x - 18) = 3(2x + 7)
Step 1: Distribute the numbers:
55x - 90 = 6x + 21
Step 2: Move all (x) terms to one side by subtracting (6x) from both sides:
55x - 6x - 90 = 21
Step 3: Combine like terms:
49x - 90 = 21
Step 4: Add 90 to both sides to isolate (x):
49x = 111
Step 5: Divide both sides by 49 to solve for (x):
x ≈ 2.2653
Now, let's order these solutions from least to greatest:
[tex]\(x= 1.371\)[/tex] (from Equation B)
[tex]\(x = 2.2653\)[/tex] (from Equation C)
[tex]\(x = \frac{48}{13}\)[/tex] (from Equation A)
So, the order from least to greatest based on their solutions is Equation B, Equation C, and then Equation A.
John owns an engine which receives heat input from a reservoir at 600 K and loses heat to a sink at 300 K. What is the maximum possible efficiency of this engine?
A.
25 percent
B.
50 percent
C.
75 percent
D.
100 percent
Answer:
D. 100 percent
Step-by-step explanation:
it is 100 percent because the reservoir is putting out 600k, but loses 300k, which would be easy to think it would be 50 percent because 300k is half of 600k, but however its peek outage is putting out 600k, therefore 600k = 600k, 100%.
Which members are in the sample
Answer:
20, 26, 35, 18
Step-by-step explanation:
So starting at row 129, we look at the sequence two-digits at a time without overlapping. If that number is between 01 and 43, then they get selected.
The first two digits are 20. That fits between 01 and 43, so that member gets selected.
Next, we have 26. That also fits.
After that we have 64. Nope, too high.
98 and 44 are also too high.
35 fits though. So does 18.
So the members that get selected are 20, 26, 35, 18.
If you have 14 1/2 dozen boxes of envelopes, and you order 3 1/4 dozen more, how many dozen boxes will you have in all?
The answere is 213 boxes
If you add 3 dozens to 14 dozens of boxes of envilopes , then you get 17 dozens of boxes of envilopes.Then of you sum up the 1/2 (2/4 ) with the 1/4.You get 3/4. Finally, you add 17 dozens to 3/4 of a dozen you get 17 3/4 dozens( wich is 213 boxes )
PLEASE HELP ME SOLVE THIS QUESTION!!
***quickest and shortest way***
Answer:
1/4 bag for each batch.
Step-by-step explanation:
Start with 4 bags. If the cake requires 1/4 bag, then 3 3/4 bags of flour are left over for the cookies. That's rather a nice number when you are dealing with 15 batches of cookies.
Start by changing the 3 3/4 into a decimal.
3 3/4 = 3.75
Now divide 3.75 by 15
3.75 / 15 = 0.25 bags which is 1/4 bag. You only have to come up with one value so this one will do.
Jimmy is trying to dive down and touch the bottom of the pool. On his first try he makes it 1/3 of the way to the bottom. On his second try he makes it 3/5 of the way to the bottom. Jimmys second dive was deeper than his first dive by what fraction of the pool?
Answer:
Jimmy's second dive was [tex]\frac{4}{15}[/tex] of the pool deeper than the first one
Explanation:
We are given that:
First dive was [tex]\frac{1}{3}[/tex] of the way to the bottom
Second dive was [tex]\frac{3}{5}[/tex] of the way to the bottom
We know that the second dive was deeper than the first one since [tex]\frac{3}{5} > \frac{1}{3}[/tex]
To know how much deeper the second dive was compared to the first one, we will simply subtract the depth of the first dive from that of the second one
Therefore:
The second dive was [tex]\frac{3}{5} - \frac{1}{3} = \frac{9}{15} - \frac{5}{15} = \frac{4}{15}[/tex] of the pool deeper than the first one
Hope this helps :)
Final answer:
Jimmy's second dive was 4/15 of the pool deeper than his first dive, calculated by finding a common denominator and subtracting the fractions representing the depth of each dive.
Explanation:
Jimmy's second dive was 3/5 of the way to the bottom of the pool, which is deeper than his first dive at 1/3 of the way. To find out how much deeper the second dive was compared to the first, we subtract the two fractions:
Second dive - First dive = 3/5 - 1/3
To subtract fractions, they must have a common denominator. Multiplying top and bottom of 3/5 by 3 and 1/3 by 5 gives us:
9/15 - 5/15 = 4/15
Therefore, Jimmy's second dive was 4/15 of the pool deeper than his first dive.
Please please help me out
Answer:
The measure of angle y is [tex]m\angle y=54\°[/tex]
Step-by-step explanation:
we know that
The inscribed angle is half that of the arc it comprises.
[tex]m\angle y=\frac{1}{2}(108\°)=54\°[/tex]
What is the product?
8(–1)
8(-1) = -8
When a positive and a negative number is being multiplied the product is always negative, but when a negative and a negative number is being multiplied the product is positive
Hope this helped!
~Just a girl in love with Shawn Mendes
Anyone know the answer to this?
Answer:
[tex]2^{n-1}[/tex]
Step-by-step explanation:
Square 1 has 2^0 pennies.
Square 2 has 2^1 pennies.
Square 3 has 2^2 pennies.
Square 4 has 2^3 pennies. The exponent of 2 is 1 less than the square number, so ...
Square n has 2^(n-1) pennies.
through (-1,2) parallel to y=-4x+3
Answer:
y = -4x - 2
Step-by-step explanation:
Parallel has same slope
so
y - 2 = -4(x + 1)
y - 2 = -4x - 4
y = -4x - 2
Equation
y = -4x - 2
These are the means and standard deviations for samples of prices from two different brands of shoes. Brand A Brand B Mean: $50 Mean: $40 Standard deviation: $5 Standard deviation: $8 Select the two true statements.
(a) The average price of brand A is higher than average price of brand B
(b) The price of brand B is more spread out than the price of brand A.
Mean of the distributions
The mean of the distributions for the individual samples is given as;
Mean of Brand A = $50
Mean of Brand B = $40
Standard deviation of the samplesStandard deviation of Brand A = $5
Standard deviation of Brand B = $8
From the mean and standard deviation of the samples we can conclude the following;
The average price of brand A is higher than average price of brand B.The price of brand B is more spread out than the price of brand A.Learn more about standard deviation here: https://brainly.com/question/12402189
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Final answer:
The two true statements are that Brand A's prices are less spread out than brand B's prices (C), reflected in the smaller standard deviation, and that Brand A has a higher average price than brand B (D), as indicated by their respective means.
Explanation:
The question involves comparing means and standard deviations for samples of prices from two different brands of shoes, Brand A and Brand B. To select the two true statements among the given options, we consider the provided statistics for each brand:
Brand A: Mean = $50, Standard deviation = $5Brand B: Mean = $40, Standard deviation = $8Now let's analyze the statements:
A. Brand A has a lower average price than brand B - This statement is false because the mean of Brand A ($50) is higher than the mean of Brand B ($40).B. Brand A's prices are more spread out than brand B's prices - This statement is false as well because Brand A has a smaller standard deviation ($5) compared to Brand B ($8), indicating less spread.C. Brand A's prices are less spread out than brand B's prices - This statement is true, reflecting the smaller standard deviation for Brand A.D. Brand A has a higher average price than brand B - This statement is true as explained earlier.Therefore, the two true statements are C and D: Brand A's prices are less spread out than brand B's prices, and Brand A has a higher average price than brand B.
How many vertices does a dodecahedron have
Answer:
20
Step-by-step explanation:
A dodecahedron is a three-dimensional figure made out of 12 regular pentagons. It resembles a soccer ball, just more rough on the edges.
So, it has 12 faces made out of regular pentagons. Each summit/vertex is a meeting point for 3 different pentagons.
So, you can easily calculate the number of vertices:
How many pentagon vertices in total?
12 pentagons with 5 vertices / pentagon = 60 vertices in total
But each vertex meets with two others... so you have to divide the number of total vertices by 3... so 60 / 3 = 20.
Answer:
12 faces
Step-by-step explanation:
~apex
A manufacturer makes closed cubic containers from sheet metal. How many square centimeters of sheet metal will a 27,000 cm 3 container need?
let's recall that a cube is just a rectangular prism with all equal sides, check picture below.
[tex]\bf \textit{volume of a cube}\\\\ V=s^3~~ \begin{cases} s=&length~of\\ &a~side\\ \cline{1-2} V=&27000 \end{cases}\implies 27000=s^3\implies \sqrt[3]{27000}=s\implies 30=s \\\\[-0.35em] ~\dotfill\\\\ \textit{surface area of a cube}\\\\ SA=6s~~\begin{cases} s=&length~of\\ &a~side\\ \cline{1-2} s=&30 \end{cases}\implies SA=6(30)\implies SA=180[/tex]
Suppose that a coin is tossed 5 times. how many different outcomes include at least two heads
26 different outcomes include at least two heads.
There are [tex]26[/tex] different outcomes that include at least two heads when a coin is tossed [tex]5[/tex] times.
The total number of outcomes when a coin is tossed [tex]5[/tex] times is [tex]\(2^5 = 32\)[/tex], since each toss has [tex]2[/tex] possible outcomes (heads or tails).
To find the number of outcomes with at least two heads, we can find the total number of outcomes with exactly one head and no heads, and subtract that from the total number of outcomes.
1. Number of outcomes with no heads: There is only [tex]1[/tex] outcome with no heads ([tex]5[/tex] tails).
2. Number of outcomes with exactly one head: This can be calculated using combinations. There are [tex]5[/tex] ways to choose which toss will be heads, and for each of these, the remaining [tex]4[/tex] tosses must be tails. So, there are [tex]\(5 \times 1 = 5\)[/tex]outcomes with exactly one head.
Therefore, the number of outcomes with at least two heads is:
[tex]\[ 32 - 1 - 5 = 26 \][/tex]
Solve for x.
1/10(x - 3) = -40
A) -403
B) -397
C) -7
D) -1
Answer:
-397Step-by-step explanation:
This may look daunting, but let us approach it step by step.
Step 1: Remove the Parenthesesmultiply 1/10 by x - 3
0.1x - 0.3 = -40
Step 2: Add 0.3In algebra, the goal is always to undo all the operations and get back to the original problem so that the mystery value can be determined. In this case since 0.3 was removed, we must add it back.
0.1x = -39.7
Step 3. Divide by 0.10.1x/0.1 = x
39.7/0.1 = -397
Step 4. Preliminary AnswerAnswer seems to be B. -397, but we should still check it.
Step 5: Check0.1(-397) - 0.3 = -40
-39.7 - 0.3 = -40
-40 = -40 Correct
If the answer was incorrect, this would show that there had been a flaw in our calculations. But everything checks out, so we are done!
Step 6: Final AnswerOur final answer is B. -397.
PLEASE MARK BRAINLIEST
Answer:
The answer is -397
Step-by-step explanation:
this is a geometry I question please explain your answer ty
Answer:
B. <Q = <R
Step-by-step explanation:
Angles are related to their intercepted arcs. An intercepted arc is found by finding the arc segment on a circle whose endpoints connect with the segments that make up an angle.
In this case, TQ and SQ make up <Q, so TS is the intercepted arc of <Q. However, TR and SR make up angle <R as well, making TS the intercepted arc of <R as well.
This means that because the angles share an intercepted arc, they are congruent.
Find the volume of the square pyramid below
Answer:
A
Step-by-step explanation:
The volume (V) of a pyramid is
V = [tex]\frac{1}{3}[/tex] area of base × perpendicular height (h)
area of square base = 4² = 16 and h = 4, hence
V = [tex]\frac{1}{3}[/tex] × 16 × 4 = [tex]\frac{64}{3}[/tex] = 21 [tex]\frac{1}{3}[/tex] ft³
A bag contains 26 tiles showing a different letter from A to Z. Each player draws a letter tile at random. Player 1 wins if the letter is in his or her name. Player 2 wins if the letter is in his or her name. If the letter is in both their names then no one wins. Nathan and Katie play the game. Is this a fair game? If not, who has the advantage?
Answer:
no
Step-by-step explanation:
Nathan has 6 letters in his name so he has a higher chance of winning
No, Katie has the advantage.
Katie has 5 distinct letters.
Nathan has 4 distinct letters.
They have one overlap (a).
Katie can expect to win 4 out of 26 games.
Nathan can expect to win 3 out of 26 games.
Since Katie has more distinct letters, she has the advantage, so it is not a fair game.
Please please help me
Answer:
(a)
Step-by-step explanation:
The line y = x + 1 has a solid circle at x = 2 indicating that x is valid for this value, thus
y = x + 1 for x ≤ 2
The line y = x + 2 has an open circle at x = 2 indicating that x = 2 is not part of the solution but that values greater than 2 are valid, that is
y = x + 2 for x > 2
The definition for the function is (a)
At Eagle Rock High School, the probability that a student takes theatre and choir is 0.078. The probability that a student takes choir is 0.26. What is the probability that a student takes theatre given that the student is taking choir?
Final answer:
The probability that a student takes theatre given that the student is taking choir is found using conditional probability and is calculated to be 0.3, or 30%.
Explanation:
To find the probability that a student takes theatre given that the student is taking choir, we use the definition of conditional probability. In this scenario, the probability of a student taking theatre and choir (joint probability) is given as 0.078, and the probability of a student taking choir (marginal probability) is 0.26.
The formula for conditional probability is:
P(A | B) = P(A and B) / P(B)
Let A represent the event of a student taking theatre, and B represent the event of a student taking choir. Substituting the given values into the formula yields:
P(A | B) = 0.078 / 0.26
Performing the division gives us:
P(A | B) = 0.3
Therefore, the probability that a student takes theatre given that the student is taking choir is 0.3, or 30%.
Information about the recycling drive at school is shown in the table. Let A be the event that the item pulled out of the recycling bin is a plastic bottle, and let B be the event that a tenth grader recycled that item. Which statement is true about whether A and B are independent events? A and B are independent events because P(A∣B) = P(A). A and B are independent events because P(A∣B) = P(B). A and B are not independent events because P(A∣B) ≠ P(A). A and B are not independent events because P(A∣B) ≠ P(B).
Answer:
the answer is c
Step-by-step explanation:
The events are illustrations of probability, and the events A and B are not independent events because P(A∣B) ≠ P(A)
How to determine the true statement?From the complete table, we have the following parameter:
P(A∣B) ≠ P(A)
Two events A and B are independent if
P(A∣B) = P(A)
Given that:
P(A∣B) ≠ P(A)
It means that the events are not independent.
Hence, the events A and B are not independent events because P(A∣B) ≠ P(A)
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Express in scientific notation 1,789
Answer:
[tex]1.789*10^{3}[/tex]
Answer: 1.789 × 10 to the third power
Step-by-step explanation: the answer would be 1.789 x 10 to the third power because the A term has to be between 1 and 10
The City Zoo collected $100 in one morning. An adult ticket is $5 each, and a child's ticket is $3. How many different combinations of adult and children's tickets would have totaled $100?
5
6
7
8
Final answer:
To calculate the number of different combinations of adult and children's tickets that would total $100, we can set up an equation: 5x + 3y = 100. We can find possible values of 'x' and 'y' that satisfy the equation. There are 6 different combinations of adult and children's tickets that would have totaled $100.
Explanation:
To calculate the number of different combinations of adult and children's tickets that would total $100, we can set up an equation:
5x + 3y = 100
Where 'x' represents the number of adult tickets and 'y' represents the number of children's tickets. We need to find whole number solutions for 'x' and 'y'.
We can start by finding the possible values of 'x' and 'y' that satisfy the equation and add up to $100. The possible combinations are:
x = 0, y = 33
x = 5, y = 31
x = 10, y = 29
x = 15, y = 27
x = 20, y = 25
x = 25, y = 23
Therefore, there are a total of 6 different combinations of adult and children's tickets that would have totaled $100.
HELP HELP!!
What is the distance between the vertices of the graphs corresponding to y = x2 + 2 and y = 3x2 + 2?
A.0
B.2
C.3
D.4
Answer:
0
Step-by-step explanation:
[tex]p_1:~~y = x^2+2\\p_2:~~y = 3x^2+2\\ \\ V{p_1} = \Big(-\dfrac{b}{2a}, -\dfrac{\Delta}{4a}\Big) = \Big(-\dfrac{0}{2}, -\dfrac{0^2-4\cdot 2}{4}\Big) = \Big(0,2\Big) \\ \\ Vp_2 = \Big(x_V, -\dfrac{\Delta}{4a}\Big) = \Big(0, -\dfrac{0^2-4\cdot 3 \cdot 2}{4\cdot 3}\Big) = \Big(0,2\Big) \\ \\ \\ \text{The distance is }0,~~\text{Because the vertices are equal.}[/tex]
The distance between the vertices of the graphs is 0.
Explanation:The distance between the vertices of the graphs corresponding to y = x2 + 2 and y = 3x2 + 2 can be found by finding the x-coordinates where the graphs intersect. To do this, we set the two equations equal to each other:
x2 + 2 = 3x2 + 2
Subtracting 2 from both sides gives: x2 = 3x2
Subtracting x2 from both sides gives: 0 = 2x2
Dividing both sides by 2 gives: 0 = x2
This equation has only one solution: x = 0. Therefore, the distance between the vertices of the graphs is 0.
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(10.02)
The point (−3, 1) is on the terminal side of angle θ, in standard position. What are the values of sine, cosine, and tangent of θ? Make sure to show all work.
Answer:
Part 1) [tex]sin(\theta)=\frac{\sqrt{10}}{10}[/tex]
Part 2) [tex]cos(\theta)=-3\frac{\sqrt{10}}{10}[/tex]
Part 3) [tex]tan(\theta)=-1/3[/tex]
Step-by-step explanation:
we know that
The angle is in the second quadrant so the sine is positive, the cosine is negative and the tangent is negative
step 1
Find the radius r applying the Pythagoras theorem
[tex]r^{2}=x^{2} +y^{2}[/tex]
substitute the given values
[tex]r^{2}=(-3)^{2} +(1)^{2}[/tex]
[tex]r^{2}=10[/tex]
[tex]r=\sqrt{10}\ units[/tex]
step 2
Find the value of [tex]sin(\theta)[/tex]
[tex]sin(\theta)=y/r[/tex]
substitute values
[tex]sin(\theta)=1/\sqrt{10}[/tex]
Simplify
[tex]sin(\theta)=\frac{\sqrt{10}}{10}[/tex]
step 3
Find the value of [tex]cos(\theta)[/tex]
[tex]cos(\theta)=x/r[/tex]
substitute values
[tex]cos(\theta)=-3/\sqrt{10}[/tex]
Simplify
[tex]cos(\theta)=-3\frac{\sqrt{10}}{10}[/tex]
step 4
Find the value of [tex]tan(\theta)[/tex]
[tex]tan(\theta)=y/x[/tex]
substitute values
[tex]tan(\theta)=-1/3[/tex]
Use this formula to find the value of a house with appreciation: A = V (1+r)Y
When Henry bought his house for $135,700, he was told that it would appreciate at a rate of five percent per year. If this remains true, how much will his house be worth in four years?
Answer:
[tex]A=\$164,944.20[/tex]
Step-by-step explanation:
we know that
[tex]A=V(1+r)^{Y}[/tex]
In this problem we have
[tex]r=5\%=0.05[/tex]
[tex]V=\$135,700[/tex]
[tex]Y=4\ years[/tex]
substitute in the formula and solve for A
[tex]A=\$135,700(1+0.05)^{4}=\$164,944.20[/tex]
A copy machine depreciates at the rate of 15% each year. If the original cost of the copy machine was $20,000, what is the approximate value of the machine at the end of 3 years?
$12,282.5 (20000x0.85x0.85x0.85)
The value of the copy machine depreciates at a rate of 15% each year. After calculating the depreciated value for 3 consecutive years, the copy machine that initially cost $20,000 is worth approximately $12,282.50 after 3 years.
Explanation:The original cost of the copy machine is $20,000. Given that the copy machine depreciates, or loses value, at a rate of 15% each year, we need to calculate the value of the copy machine each year for 3 years by subtracting 15% of its current value.
In the first year, the value of the copy machine would be $20,000 - (15% of $20,000) = $20,000 - $3,000 = $17,000. In the second year, we will take 15% off $17,000, so the value will be $17,000 - (15% of $17,000) = $17,000 - $2,550 = $14,450. Finally, in the third year, we will take 15% off $14,450, so the final value is $14,450 - (15% of $14,450) = $14,450 - $2,167.50 = $12,282.50. So, the approximate value of the machine at the end of 3 years is $12,282.50.Learn more about Depreciation here:https://brainly.com/question/17827672
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What should the balance be in Diane's register?
Will give BRAINLIEST
Answer:
The balance of Dianne's register should be $359.41
Step-by-step explanation:
We can begin at the ending balance on the bank statement at $578.30
Then a check is written for $219.25, so a debit
Next a deposit is made for $140.36, so a credit
Then a withdrawal is made for $140.00, so a debit
This means we can make the equation
[tex]578.30-219.25+140.36-140.00=359.41[/tex]
HELP PLEASE!!
Question 1 (2 points)
Generalize the pattern by finding the nth term.
6, 10, 14, 18, 22,
A. 4n
B. 4n + 2
C. 4n + 10
D. 6n + 4
Answer:
B. 4n+2
Step-by-step explanation:
You are given the pattern 6, 10, 14, 18, 22
Rewrite it as
[tex]a_1=6\\ \\a_2=10\\ \\a_3=14\\ \\a_4=18\\ \\a_5=22[/tex]
Note that
[tex]a_2-a_1=a_3-a_2=a_4-a_3=a_5-a_4=4[/tex]
This means that given pattern is a part of arithmetic sequence with
[tex]a_1=6\\ \\d=4[/tex]
So, the nth term of this arithmetic sequence is
[tex]a_n=a_1+(n-1)d\\ \\a_n=6+4(n-1)\\ \\a_n=6+4n-4\\ \\a_n=4n+2[/tex]
A candle manufacturer sells cylindrical candles in sets of three. Each candle in the set is a different size. The smallest candle has a radius of 0.5 inches and a height of 3 inches. The other two candles are scaled versions of the smallest, with scale factors of 2 and 3. How much wax is needed to create one set of candles? A. 27 π cubic inches B. 36 π cubic inches C. 53 π cubic inches D. 86 π cubic inches E. 98 π cubic inches
Answer:
A. 27 π cubic inches
Step-by-step explanation:
The volume of a cylinder is calculated using the formula;
[tex]Volume=\pi r^2h[/tex]
From the given information, the smallest candle has a radius of 0.5 inches and a height of 3 inches.
We substitute [tex]r=0.5[/tex] and [tex]h=3[/tex] into the given formula.
The vlume of the smallest candle is
[tex]Volume=\pi \times0.5^2\times 3[/tex]
[tex]Volume=\frac{3}{4}\pi in^3[/tex]
from the given information, the other two candles are scaled versions of the smallest, with scale factors of 2 and 3.
The volume of the other two candles will be [tex]2^3\times \frac{3}{4}\pi=6\pi in^3[/tex] and [tex]3^3\times \frac{3}{4}\pi=\frac{81}{4}\pi in^3[/tex]
The wax needed to create one set of candle is
[tex]\frac{3}{4}\pi+6\pi+\frac{81}{4}\pi=27\pi\: in^3[/tex]
The correct answer is A
Answer:
27 pi in³
Step-by-step explanation:
I just took a test on Plato/Edmentum with this question and this was the right answer
~Please mark me as brainliest :)