Find the radius of a circle with circumference of 55.3 yd^2. Round to the nearest tenth.
Polygon ABCD is reflected and dilated to give polygon PQRS. The coordinates of the preimage are (2, 2), (6, 8), (12, 8), and (16, 2). The coordinates of the image are (11, 15),
(9, 12), (6, 12), and (4, 15). What is the scale factor of the dilation?
Answer: The scale factor of the dilation is 0.5.
Explanation:
It is given that ABCD is polygon which is reflected and dilated , then we get PQRS.
The vertices of ABCD are (2, 2), (6, 8), (12, 8), and (16, 2) respectively. The vertices of image PQRS are (11, 15),(9, 12), (6, 12), and (4, 15) respectively.
The reflection affects the coordinates but does not affect the length of the sides.
But when we talk about dilation it affects the length of sides according to the scale factor or a constant factor.
If a line segment AB is dilated by scale factor k then length of A'B' is k times length of AB.
[tex]|A'B'|=k\times |AB|[/tex] .... (1)
So we have to find any side length of preimage and the side length of that side in image. it means we have to find AB and PQ.
Use distance formula to find the side length.
[tex]D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex]AB=\sqrt{(8-2)^2+(6-2)^2}=\sqrt{36+16}=2\sqrt{13}[/tex]
[tex]PQ=\sqrt{(9-11)^2+(12-15)^2}=\sqrt{4+9}=\sqrt{13}[/tex]
It is noticed that the size of side in preimage is [tex]2\sqrt{13}[/tex] and the size of same side in image is [tex]\sqrt{13}[/tex].
Using equation (1), we get
[tex]\sqrt{13}=k \times 2\sqrt{13}[/tex]
[tex]k=\frac{1}{2}[/tex]
[tex]k=0.5[/tex]
Hence, the value of scale factor is 0.5.
You are serving bratwurst and hamburgers at your annual picnic. You want at least three bratwursts or hamburgers for each of your 40 guests. Bratwursts cost $1.35 each and hamburgers $1.2 each. Your budget is $175.
Let x be the number of bratwursts and y the number of hamburgers. whiichs system of inequalities represents this situation?
Options:
x+y<=40 1.35x+1.2y>=175
x+y<=40 1.35x+1.2y<=175
x+y>=120 1.35x+1.2>=175
x+y>=120 1.35x+1.2<=175
...?
Answer:
Option D -[tex]x+y\geq 120[/tex] , [tex]1.35x + 1.2y \leq 175[/tex]
Step-by-step explanation:
Given : You want at least three bratwursts or hamburgers for each of your 40 guests. Bratwursts cost $1.35 each and hamburgers $1.2 each. Your budget is $175.
To find : Which system of inequalities represents this situation?
Solution :
Let x be the number of bratwursts and y the number of hamburgers.
You want at least three bratwursts or hamburgers for each of your 40 guests.
i.e, you want at least [tex]3\times(40)=120[/tex] bratwursts or hamburgers.
We can write the equation as,
Number of bratwursts + number of hamburgers at least 120
[tex]x+y\geq 120[/tex]
Bratwursts cost $1.35 each and hamburgers cost $1.2 each. Your budget is $175.
We can write equations as ,
Cost of bratwursts + cost of hamburgers at most 175
[tex]1.35x + 1.2y \leq 175[/tex]
Therefore, The system of linear equation form is [tex]x+y\geq 120[/tex], [tex]1.35x + 1.2y \leq 175[/tex]
Hence, Option D is correct.
(URGENT-15 Points) Can someone help me/check my answers for this? Thank you! For the first screenshot, my answers for 1-5 are: (1) 79.2 (2) 12.4 (3) 78 and 82 (4) 76 and 84 (5) 74 and 86. I am stuck on questions 6-8 (#8 is on the second screenshot at the top...). On the second screenshot, I'm not sure how to answer question (9) based on the dot-plot on the first screenshot. For (10), if it's asking for the mean of these numbers, I got 23.8. If it's just asking for the sum, I got 119. For 11-12, the means aren't the same because this mean (#10) is based on the random sample generated from the original number of grades, while the first mean (#2) was based on the total population of grades for the entire class. It would make sense that the second mean would be smaller than the first. I'm giving away 15 points to the person who can help me with this and check my answers! I'd really appreciate it! :)
The formula for the area of a square can be written as A = s^2 and means “area equals side-squared”. Explain how the formula for the area of a square can be derived from the formula for the area of a rectangle.
The area of a square, represented as A = s², is derived from the formula for the area of a rectangle (A = w × h) where the width and height are equal in a square, hence the side (s) is squared (s × s).
The formula for the area of a square is derived from the area of a rectangle because a square is a special type of rectangle where all sides are equal.
The formula for the area of a rectangle is A = w × h, where w is the width and h is the height. In the case of a square, the width and height are the same, which we call the side length s. Therefore, the formula A = s imes s, or A = s², naturally follows for finding the area of a square.
To visualize this, consider placing a square on graph paper. Each side of the square touches the same number of squares on the graph paper because the sides are of equal length.
When you multiply the side length by itself, you are effectively counting the total number of squares inside the square, which gives the area in square units. This visual method confirms that the area of a square is indeed the side length squared.
Which algebraic expression means “three more than a number squared”?
a) 2n+3
b) 2n-3
c) n^2+3
d) n^2-3
Option C is the correct anwser, Hope this helps :)
jake goes to the grocery store and buys 3 apple, 2 cans of soup, and 1 box of cereal. the apples cost $0.89 each; the soup costs $2.98 per can; and the box of cereal costs $4.99.
Answer:
c=(3 x 0.89)+(2.98)+4.99
Step-by-step explanation:
A = bh/2
A' = b'h/2 + bh'/2
b' = (A' - bh'/2)(2/h) can someone explain this. its steps to the derivative of bh/2.
Answer:
To find A' they used the rule of multiplication, which is:
the derivative of a product of two terms is the first term times the derivative of the second term plus the second term times the derivative of the first.
To find b' they just isolated b'
Step-by-step explanation:
The revenue from selling x shirts is r(x) = 11x.
The cost of buying x shirts is c(x) = 6x + 20.
The profit from selling x shirts is p(x) = r(x) – c(x).
What is p(x)?
A. p(x) = 5x + 20
B. p(x) = 17x + 20
C. p(x) = 17x – 20
D. p(x) = 5x – 20
HELP!!give me the correct answer!! thank you
Answer:
Correct answer is: D p(x)=5x-20: Apex
Step-by-step explanation:
The value of the profit function is equal to 5x - 20. The correct option is D.
Given that:
Revenue function: r(x) = 11x
Cost function: c(x) = 6x + 20
To find the profit function, we need to subtract the cost function from the revenue function:
p(x) = r(x) - c(x)
Substituting the given revenue and cost functions and calculated as:
p(x) = 11x - (6x + 20)
Simplifying above expression as:
p(x) = 11x - 6x - 20
Combining like terms as:
p(x) = 5x - 20
Therefore, the value of the profit function is equal to 5x - 20. The correct option is D.
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When you see a traffic light turn red, you apply the brakes until you come to a stop. Suppose your initial speed was 11.2 m/s, and you come to rest in 34.7 m. How much time does this take? Assume constant deceleration.
...?
Mrs.ulrich has 3 times as many markers as colored pencils.the total number of markers and colored pencils is 84.how many markers does mrs.ulrich have
A box contains 13 transistors, 3 of which are defective. if 3 are selected at random, find the probability that
a. All are defective
b. None are defective
a. Probability all defective: [tex]\( \frac{1}{286} \)[/tex]. b. Probability none defective: [tex]\( \frac{60}{143} \)[/tex].
To solve this problem, we can use the concept of probability.
a. Probability that all selected transistors are defective:
When selecting the first transistor, the probability of choosing a defective one is [tex]\( \frac{3}{13} \)[/tex], as there are 3 defective transistors out of 13 total.
After the first defective transistor is chosen, there are 2 defective transistors left out of 12 total transistors.
So, the probability of choosing a second defective transistor given that the first one was defective is [tex]\( \frac{2}{12} \).[/tex]
Similarly, for the third selection, the probability of choosing a defective transistor given that the first two were defective is [tex]\( \frac{1}{11} \)[/tex].
To find the probability that all three selected transistors are defective, we multiply the individual probabilities:
P(All defective) = [tex]\frac{3}{13} \times \frac{2}{12} \times \frac{1}{11}[/tex]
P(All defective) = [tex]\frac{3 \times 2 \times 1}{13 \times 12 \times 11}[/tex]
P(All defective) = [tex]\frac{6}{1716}[/tex]
P(All defective) = [tex]\frac{1}{286}[/tex]
So, the probability that all selected transistors are defective is [tex]\( \frac{1}{286} \).[/tex]
b. Probability that none of the selected transistors are defective:
This is essentially the complement of the event that all selected transistors are defective. Since there are 3 defective transistors out of 13, the remaining 10 transistors are not defective.
So, to find the probability that none are defective, we select 3 out of the 10 non-defective transistors.
P(None defective) = Number of ways to choose 3 non-defective transistors/Total number of ways to choose 3 transistors
P(None defective) = [tex]\frac{{\binom{10}{3}}}{{\binom{13}{3}}}[/tex]
P(None defective) = [tex]\frac{{120}}{{286}}[/tex]
P(None defective) = [tex]\frac{{60}}{{143}}[/tex]
So, the probability that none of the selected transistors are defective is [tex]\( \frac{{60}}{{143}} \).[/tex]
distance can be represented by absolute value.true or false.?
Find the product for 7 x 2/3
The word product is the answer to a multiplication problem.
7 x 2/3
7/1 x 2/3
(7 x 2)/(1 x 3)
Answer: 14/3
What is the product of 1.5 and 2.8 is 4.2?
The product of 1.5 and 2.8 is correctly calculated as 4.2, in accordance with the rules of significant figures.
Explanation:The statement "1.5 and 2.8 is 4.2" seems to imply a multiplication between 1.5 and 2.8 resulting in 4.2. However, this is a misconception. The actual product of multiplying 1.5 by 2.8 is 4.2. To confirm this, you multiply the two numbers: 1.5 × 2.8 equals 4.2.
In significant figures, if the numbers 1.5 and 2.8 were part of a calculation with inexact numbers, the answer would be limited by the smallest number of significant figures present in the inexact numbers. In this case, as both 1.5 and 2.8 have two significant figures, the product is correctly expressed with two significant figures as 4.2.
A computer uses 239 watts per hour. How many watts would it use if it is on for 8 days?
Answer:
29 watts
Step-by-step explanation:
239 ÷ 8 = 29.875
Carrots sell for $2.10 per pound, and crackers sell for $2.90 per pound. Glen bought some carrots and some crackers. The total weight was 2.3 pounds and cost $6.03.
How many pounds of carrots and how many pounds of crackers did Glen buy?
Note: Please give a direct answer
On a coordinate grid, both point (−4, −1) and (2, 6) point are reflected across the y-axis. what are the coordinates of the reflected points?
f(x) = sin(x^2 - 2)
find points of discontinuity, if any ...?
Let f and g be two functions whose second derivatives are defined. Then (f · g) '' = f · g '' + f '' · g. true or false?
The statement (f · g)'' = f · g'' + f'' · g is false. The second derivative of a product of two functions is given by a different formula.
The statement (f · g)'' = f · g'' + f'' · g is false.
The second derivative of a product of two functions, f(x) and g(x), is given by (f · g)'' = f''g + 2f'g' + fg''.
To see why the given statement is false, consider the example where f(x) = x and g(x) = x^2. The left-hand side is 0, but the right-hand side is not zero, so the statement does not hold true.
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can someone help me please Write 243 in exponential form ...?
The exponential form of 243 is: 243 = 3⁵.
To write 243 in exponential form, you need to express it as a power of a base number.
The most common base used for this purpose is 3.
243 can be written as: 243 = 3⁵
Here's the reasoning:
[tex]\[ 3 \times 3 = 9 \][/tex]
[tex]\[ 9 \times 3 = 27 \][/tex]
[tex]\[ 27 \times 3 = 81 \][/tex]
[tex]\[ 81 \times 3 = 243 \][/tex]
So, 243 is 3 raised to the power of 5.
Therefore, 243 In exponential form is: [tex]\[ 243 = 3^5 \][/tex]
What is the factored form of the expression?
s^4 – 16
A. (s - 2)^2(s + 2)^2
B. (s - 2)(s + 2)
C. (s - i)(s + i)(s - 2)(s + 2)
D. (s - 2i)(s + 2i)(s - 2)(s + 2)
Solve -2.5n + 8.7 > 5.45.
n < 1.3
n > 1.3
n < -5.66
n > -5.66
Answer:
N < 1.3
Step-by-step explanation:
Go thank the answer above! :)
How many permutations of the letters ABCDEFG contain:
a.) the string BCD?
b.) the string CFGA?
c.) the strings BA and GF?
The number of permutations of ABCDEFG containing BCD, CFGA, and BA & GF are 120, 24, and 120, respectively.
Explanation:In permutations, the order of the items is important. For all these problems, we're asked how many permutations of the letters ABCDEFG contain a specific string. To solve this, we can initially treat the required string as a single item.
For BCD, we consider 'BCD' as one letter, so now we have 5 letters (A,E,F,G,BCD). The number of permutations for 5 items is 5P5 = 5! = 120. For CFGA, we consider 'CFGA' as one letter, so now we have 4 letters (B,D,E,CFGA). The number of permutations for 4 items is 4P4 = 4! = 24. For BA and GF, we consider 'BA' and 'GF' as one letter each, so now we have 5 letters (C,D,E,BA,GF). The number of permutations for 5 items is 5P5 = 5! = 120. Learn more about Permutations here:https://brainly.com/question/23283166
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6375/10000 in simplest form
The diagonal of a square is x units. What is the area of the square in terms of x?
square units
square units
2x square units
square units
Let
b------> the length side of a square
we know that
the area of a square is equal to
[tex]A=b^{2}[/tex]
Find the length side of the diagonal applying the Pythagoras Theorem
[tex]d^{2}=b^{2}+b^{2}[/tex]
[tex]d^{2}=2b^{2}[/tex]
[tex]d=b\sqrt{2}\ units[/tex]
Remember that
[tex]d=x\ units[/tex] -----> given problem
substitute
[tex]d=b\sqrt{2}\ units[/tex]
[tex]x=b\sqrt{2}\ units[/tex]
Solve for b
[tex]b=\frac{x\sqrt{2}}{2}\ units[/tex]
Substitute in the formula of area
[tex]A=(\frac{x\sqrt{2}}{2})^{2}[/tex]
[tex]A=\frac{x^{2}}{2}\ units^{2}[/tex]
therefore
the answer is
[tex]\frac{x^{2}}{2}\ units^{2}[/tex]
The area of the square in terms of x is [tex]\( \frac{x^2}{2} \),[/tex] obtained by using the Pythagorean theorem and the formula for the area of a square.
To find the area of the square in terms of [tex]\(x\),[/tex] we need to first understand the relationship between the diagonal and the side length of a square.
In a square, each diagonal divides the square into two congruent right triangles. Using the Pythagorean theorem, we can find the relationship between the diagonal [tex](\(x\))[/tex] and the side length of the square [tex](\(s\)).[/tex]
The Pythagorean theorem states:
[tex]\[ \text{Hypotenuse}^2 = \text{Adjacent side}^2 + \text{Opposite side}^2 \][/tex]
For a square:
[tex]\[ x^2 = s^2 + s^2 \][/tex]
[tex]\[ x^2 = 2s^2 \][/tex]
Now, we can solve for [tex]\(s\)[/tex] in terms of [tex]\(x\):[/tex]
[tex]\[ s^2 = \frac{x^2}{2} \][/tex]
[tex]\[ s = \sqrt{\frac{x^2}{2}} \][/tex]
[tex]\[ s = \frac{x}{\sqrt{2}} \][/tex]
The area [tex](\(A\))[/tex] of a square is given by:
[tex]\[ A = s^2 \][/tex]
Substituting the expression for s in terms of x :
[tex]\[ A = \left(\frac{x}{\sqrt{2}}\right)^2 \][/tex]
[tex]\[ A = \frac{x^2}{2} \][/tex]
Therefore, the area of the square in terms of x is [tex]\( \frac{x^2}{2} \).[/tex]
The question probable may be:
The diagonal of a square is x units. What is the area of the square in terms of x?
A company has tow electric motors consume varying amounts of power. The power consumed by each motor is a function of the time (t in minutes) for which it runs. The cost of power (in $) to run one motor is given by the function Ca(t)=t^2-2t+5. The cost of running the second motor is given by Cb(t)=3t+2. Which gives the total cost of running both motors?
C(t)=3t^3-6t^2+15t
C(t)=2t^2-4t+10
C(t)=t^2+t+7
C(t)=3t^3+6t^2-15t
Answer:
Option (c) is correct.
The total cost of running both motors is [tex]t^2+t+7[/tex]
Step-by-step explanation:
Given : The cost of power (in $) to run one motor is given by the function [tex]C_a(t)=t^2-2t+5[/tex] and The cost of running the second motor is given by [tex]C_b(t)=3t+2[/tex]
We have to find the total cost of running both motors.
Since we are given the cost to run each motors so, total cost will be the sum of running both motors.
Let C(t) be the total cost of running both motors.
[tex]C(t)=C_a(t)+C_b(t)[/tex]
Substitute,
[tex]C_a(t)=t^2-2t+5[/tex]
and [tex]C_b(t)=3t+2[/tex]
We get,
[tex]C(t)=t^2-2t+5+3t+2[/tex]
Simplify, we get,
[tex]C(t)=t^2+t+7[/tex]
Thus, The total cost of running both motors is [tex]t^2+t+7[/tex]
Evaluate the following expression.
153^0
Franko's pizza is selling their pizzas 35% cheaper than usual. if a pizza normally costs $12.00, how much is it now?
Solve for x.
log6(2x + 3) = 3 ...?
The value of x that satisfies the original equation is 106.5. To solve the given logarithmic equation, convert it to its exponential form and simplify. Subtract 3 from both sides, and finally divide by 2 to find that x equals 106.5.
Explanation:To solve for x in the equation log6(2x + 3) = 3, we can convert the logarithmic equation into its exponential form. This means that we interpret the equation as 6 raised to the power of 3 equals 2x + 3:
63 = 2x + 3
The next step is to simplify. 6 to the power of 3 is 216:
216 = 2x + 3
We can now solve for x by first subtracting 3 from both sides:
216 - 3 = 2x
213 = 2x
And then dividing by 2:
x = 213 / 2
x = 106.5
Thus, the value of x that satisfies the original equation is 106.5.