a. The value for the centripetal acceleration is g downward.
(correct answer on plato just did the mastery for this one)
At the top of the loop, where a roller coaster car is just maintaining contact with the track, its centripetal acceleration equals the acceleration due to gravity, which is 9.8 m/s².
Explanation:The value of the centripetal acceleration at the top of the loop, where a roller coaster car just maintains contact with the track, is equal to the acceleration due to gravity, which is 9.8 m/s². This can be deduced from the balancing forces at the top of the loop. In this situation, the force due to gravity is acting downwards while the centripetal force is also acting downwards - directed towards the center of the circular path. Therefore, these forces must match at the top of the loop for the car to just maintain contact with the track. This gives us the equation for centripetal acceleration, ac = g , where ac is the centripetal acceleration and g is the acceleration due to gravity.
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What is the volume of a gold nugget that weight 2.20kg. the density of gold is 19g/cm^3 ...?
If the speed of a ball increased from 1m/s to 4m/s, by how much would kinetic energy increase
Lava blown out of a volcano in explosive eruption is called pumice. True False
The claim that lava blown out of a volcano is called pumice is False; pumice is a volcanic rock formed from cooling lava with trapped gas, not the lava itself.
Explanation:The statement that lava blown out of a volcano in an explosive eruption is called pumice is False. Pumice is not lava itself, but rather a type of volcanic rock that forms when frothy lava cools and solidifies with a high volume of gas bubbles trapped inside. Pumice is a vesicular felsic igneous extrusive rock that is light enough to float on water due to its numerous gas bubble cavities giving it a very low density.
Pumice is characterized by a frothy texture and typically takes on a whitish, light grayish, or very light brown color. Most notably, pumice has a high porosity because of the many gas bubbles that were present in the originating lava. While pumice results from volcanic eruptions, it is the solid portion that forms from rapidly cooling lava with trapped gas bubbles, distinguishing it from molten lava ejected during an eruption.
In the context of volcanic fragmental rocks such as tuff, pumice fragments can be found within a light-colored volcanic ash. These rocks are formed by explosive volcanic eruptions that blast solid fragments and ash into the atmosphere.
a fisherman hooks a trout and reels in his line at speed of 4 inches/second. assume tip of fishing rod is 12 ft above the water directly above the fisherman and the fish is pulled horizontally directly towards the fisherman. Find the horizontal speed of the fish when it is 20 ft from the fisherman. ...?
Answer:
v = 4.66 inch/s
Explanation:
As we know that the height of the rod and the distance from the fisherman is related to each other as
[tex]x^2 + y^2 = L^2[/tex]
now differentiate it with respect to time
[tex]2x\frac{dx}{dt} + 0 = 2L\frac{dL}{dt}[/tex]
here we know that
[tex]\frac{dL}{dt} = 4 inch/s[/tex]
now when
x = 20 ft and y = 12 ft then the length of the line is given as
[tex]L^2 = 12^2 + 20^2[/tex]
[tex]L = 23.3 ft[/tex]
now from above relation
[tex]\frac{dx}{dt} = \frac{L}{x}(\frac{dL}{dt})[/tex]
now we have
[tex]v_x = \frac{23.3}{20} (4 inch/s)[/tex]
[tex]v_x = 4.66 inch/s[/tex]
Which of these is the best method to estimate the speed at which a star is moving away from Earth?
measure the star's red shift
calculate the pitch due to changes in frequency of light
calculate the parallax due to changes in Earth's position
measure the star's blue shift ...?
Answer A. Red shift. verified 12/21/18 per test results.
a car traveling at a speed of 13 meters per second accelerates uniformly to a speed of 25 meters per second in 5.0 seconds.
-a truck traveling at a constant speed covers the same total distance as the car in the same 5.0 second interval. Determine the speed of the truck.
-Calculate the magnitude of the accelerate of the car during this 5.0 second interval.
A roast turkey is taken from an oven when its temperature has reached 185°F and is placed on a table in a room where the temperature is 75°F. The graph shows how the temperature of the turkey decreases and eventually approaches room temperature. By measuring the slope of the tangent, estimate the rate of change of the temperature after an hour.
Final answer:
The student's question requires estimating the rate of change of the turkey's temperature after cooling for an hour, which is determined by the slope of the tangent on the temperature graph. This mathematical concept also has a real-life application in ensuring that turkey is cooked to a safe internal temperature of 165°F using a food thermometer.
Explanation:
The student's question involves calculating the rate of change of the turkey's temperature after allowing it to cool for an hour. To accomplish this, one would measure the slope of a tangent line drawn on the graph at the point corresponding to one hour post removal from the oven. The slope of the tangent represents the rate at which the turkey's temperature is changing at that specific time—essentially, how quickly it is approaching room temperature.
While this problem is primarily mathematical, it involves knowledge about cooking temperatures as context. This includes knowing the safe internal temperatures for various meats—a roast turkey should reach a safe minimum internal temperature of 165°F to ensure it is safe to consume. The mathematics involved in graphing and calculating slopes can help in ensuring that these safety standards are followed by providing precise information about how quickly the food is cooling and when it has reached a safe temperature.
When using a food thermometer to check for these safe temperatures, the concepts of rates of change are at work as the thermometer relays how quickly the internal temperature is reaching the desired heat level. This practical application shows the importance of mathematical concepts in everyday life.
The estimated rate of change of the temperature of the turkey after an hour is about -10°F per minute, indicating it is cooling down.
Understanding the Concept of Rate of Change:
The rate of change of temperature is represented by the slope of the tangent line on the graph at a specific time. In this case, after one hour, we can look at the graph to find the corresponding temperature and its change over a small time interval.
Finding the Slope at t = 1 hour:
The slope of the tangent line at a point on a graph is calculated using the formula:
[tex]\text{slope} = \frac{\Delta y}{\Delta x}[/tex]
where [tex]\Delta y[/tex] is the change in temperature and [tex]\Delta x[/tex] is the change in time.
Locate the point on the graph that corresponds to 1 hour after placing the turkey on the table. Let's say the temperature at that point is roughly 150°F (you would need to confirm this from the actual graph).
Let's assume that right before the 1-hour mark (at approximately 59 minutes), the temperature was about 160°F.
Calculate the Change:
Change in temperature:
[tex]\Delta y = y_1 - y_0 = 150 - 160 = -10 \text{ F}[/tex]
Change in time:
[tex]\Delta x = 60 - 59 = 1 \text{ minute}[/tex]
Calculate the Slope:
Now apply the values into the slope formula:
[tex]\text{slope} = \frac{\Delta y}{\Delta x} = \frac{-10 \, \text{F}}{1 \, \text{min}} = -10 \, \text{F/min}[/tex]
when light waves passes straight through an object, it is called?
Transmission
Explanation;Light waves are types of waves that are electromagnetic waves, meaning they do not require material medium for transmission. Light is transmitted as a transverse wave such that the vibration of particles is perpendicular to the direction of wave motion.A material medium enables the transmission of a wave by the vibration of particles, atoms or molecules. The vibration of particles in a medium helps in the transmission of a wave such that energy is transferred from one point to another due to the disturbance caused by the wave.A 3.5-inch (diameter) floppy disk in a computer rotates with a period of 2.0*10^-1s. If the angular speed is 31.4 rad/s. Whats is the liner speed? ...?
Final answer:
The linear speed of a point on a 3.5-inch floppy disk rotating at 31.4 rad/s is calculated using the formula v = r⋅ω, resulting in a linear speed of 1.396 m/s.
Explanation:
The question is about determining the linear speed of a point on a 3.5-inch floppy disk that rotates with an angular speed. The linear speed v can be calculated using the formula v = r⋅ω, where r is the radius of the disk and ω is the angular speed. Given the diameter of the disk is 3.5 inches, we must first convert it to the radius in meters which is 0.04445 meters (since 1 inch = 0.0254 meters). Therefore, the linear speed is v = 0.04445 m × 31.4 rad/s = 1.396 m/s.
if samples of silver and lead each had volumes to 1 cm^3 which sample would have the greater mass and what would the difference in the mass be
Chandra notices that her bicycle tires have a higher pressure during the hot summer than during the cold winter. Which gas law explains her observation? Explain your answer.
The Gay-Lussac law can clarify this, which states that if the temperature rises in the summer, the pressure should rise as well in order for K to remain constant.
What is Gay-Lussac law?Gay-law Lussac's is most commonly associated with Joseph-Louis Gay-law Lussac's of combining volumes of gases, which was discovered in 1808 and published in 1809.
It can also refer to the proportionality of a gas's volume to its absolute temperature at constant pressure.
The law is named after the French chemist who discovered the relationship between a gas's pressure and absolute temperature. Joseph gay lussac was his name.
The Gay-Lussac law, which states that if the temperature rises in the summer, the pressure must rise as well in order for K to remain constant, can help to clarify this.
Thus, the Gay-Lussac law can explain her observation.
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Which of the following is true of both nuclear fusion and nuclear fission?
a.
They both require a high energy input.
b.
They both occur without byproducts.
c.
They both have a high energy output.
d.
They both involve large atoms breaking into smaller atoms.
Answer:
c. They both have a high energy output.
Explanation:
- Nuclear fusion is the process in which two lighter nuclei combine together into a heavier nucleus
- Nuclear fission is the process in which a heavier nucleus breaks apart into smaller nuclei
In both cases, a huge amount of energy is released. In fact:
- In the nuclear fusion, the mass of the heavier nucleus is slightly lower than the sum of the masses of the two initial nuclei: this means that part of the initial mass has been converted into energy, according to the equation
[tex]E=mc^2[/tex]
and we can see that even for small amount of mass, m, the energy released is huge
- In the nuclear fission, the mass of the final products is less than the mass of the initial heavier nucleus, so again, part of the initial mass has been converted into energy, according to the equation
[tex]E=mc^2[/tex]
a. They both require a high energy input. No. Fission doesn't require ANY energy input to get going.
b. They both occur without byproducts. No. The by-products of fission are the biggest real problem in commercial nuclear power . . . where to put the bad stuff that's left over.
c. They both have a high energy output. Yes !
d. They both involve large atoms breaking into smaller atoms. No. 'Fission' involves large nucleii breaking into smaller ones. 'Fusion' is exactly the opposite ... combining small nucleii into more complex ones.
The express train can travel 100 miles per hour. This information describes the train's
Answer
acceleration.
direction.
speed.
velocity.
...?
Answer:
Speed
Explanation:
The information "100 miles per hour" describes that the train travels 100 miles of distance in a time period of 1 hour. we know that the speed is defined as the distance traveled by an object in unit interval of time with no information about the direction of motion. hence the information "100 miles per hour" about the express train describes the speed of the train.
Explain what happens to the particles in a substance during a physical change.
Explanation:
Physical change is a change in which there is no change in chemical composition of the substance.
For example, when we freeze liquid water then it changes into solid, that is, only physical state of water has changed and no change in chemical composition.
Therefore, in a physical change there is change only in the arrangement, energy and movement of particles.
A 200. N wagon is to be pulled up a 30 degree incline at constant speed. How large a force parallel to the incline force is needed? Assume no friction. ...?
Answer:
F = 100 N
Explanation:
Since the wagon is pulled along the inclined plane upwards so here the component of the weight of the wagon will act down the plane.
There is no friction force on the wagon so here in order to move the wagon upwards along the plane we require a force along the plane upwards which must be of same magnitude as that the magnitude of weight along the plane downwards.
now the component of weight along the inclined is given as
[tex]F = Wsin\theta[/tex]
[tex]F = 200 sin30[/tex]
[tex]F = 200(0.5) [/tex]
[tex]F = 100 N[/tex]
To pull a 200 N wagon up a 30-degree incline at constant speed, a parallel force of 100 N is needed. This calculation assumes no friction. It is derived using the component of the gravitational force parallel to the incline.
To determine the force needed to pull a 200 N wagon up a 30-degree incline at a constant speed, we need to analyze the components of the gravitational force acting on the wagon.
The gravitational force acting down the incline is given by: F_parallel = F_gravity * sin(theta)Given that the gravitational force (weight) is 200 N and the incline angle (theta) is 30°, we use the sine function:F_parallel = 200 N * sin(30°)Since sin(30°) = 0.5F_parallel = 200 N * 0.5 = 100 NTherefore, a force of 100 N parallel to the incline is needed to pull the wagon up at a constant speed, assuming no friction.
13. Abrasion erodes the desert surface by *
a. Creating blowouts
b. Cutting and polishing exposed rock surfaces
c. Depositing loess across the landscape
d. Creating a stony surface layer
If you are given distance and a period of time what can you calculate
speed
i took the test just know and put velocity and it was wrong. it said the answer was speed
Given distance and a period, we can calculate speed, angular velocity, frequency, and even time dilation effects. Speed is calculated using the formula v = d/t.
If you are given distance and a period, you can calculate several interesting physics concepts. One fundamental calculation would be speed or velocity since speed equals distance divided by time (v = d/t). If the movement occurs at a constant speed, this is straightforward. However, suppose the speed varies or involves a pendulum or circular motion. In that case, you can dive into more specific calculations such as angular velocity, frequency, and time dilation effects in relativity for movements approaching the speed of light.
For example, the period T of an object moving back and forth with a constant speed v over a distance 2L, such as a pendulum, can be calculated using T = 2L/v. Similarly, the frequency, f, of such an oscillating system is found using f = 1/T. These concepts apply to various systems, including satellites orbiting a planet where the period is related to the orbital distance from the center of the celestial body.
2 Resistors of resistance, R = (100 +- 3) Ohm, R2 = (200+-4)Ohm are connected in Parallel and Series.
Find the absolute error and % error in the measurement of equivalent resistance are in each combinations I.e Series and Parallel.. ??
The absolute error and % error in the measurement of equivalent resistance are :
Series → 7 Ohm and 2%Parallel → 5 Ohm and 7%Further explanationElectrical circuits can generally be divided into two types , i.e :
1. Series CircuitIn series circuit, the electric current flowing on each resistor is always the same as the total current.
To find the total resistances you can use the following formula:
[tex]\large {\boxed {R_s = R_1 + R_2 + R_3 + ...} }[/tex]
2. Parallel CircuitIn parallel circuits, the electrical voltage at each resistor is always the same as the source voltage.
To find the total resistances you can use the following formula:
[tex]\large {\boxed {\frac{1}{R_p} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + ...} }[/tex]
Let's tackle the problem now !
Given:
[tex]R_1 = 100 \pm 3 ~ Ohm[/tex]
[tex]R_2 = 200 \pm 4 ~ Ohm[/tex]
Unknown:
Absolute Error = ?
% Error = ?
Solution:
In Series Circuit :[tex]R_s = R_1 + R_2[/tex]
[tex]R_s = ( 100 \pm 3 ) + ( 200 \pm 4 )[/tex]
[tex]\large {\boxed {R_s = 300 \pm 7 ~ Ohm} }[/tex]
Absolute Error = 7 Ohm% Error = (7/300) x 100% ≈ 2%In Parallel Circuit :[tex]\frac{1}{R_p} = \frac{1}{R_1} + \frac{1}{R_2}[/tex]
[tex]\frac{1}{R_p} = \frac{R_2}{R_1 ~ R_2} + \frac{R_1}{R_2 ~ R_1}[/tex]
[tex]\frac{1}{R_p} = \frac{R_1 + R_2}{R_1 ~ R_2}[/tex]
[tex]R_p = \frac{R_1 ~ R_2}{R_1 + R_2}[/tex]
[tex]R_p = \frac{100 \times 200}{100 + 200}[/tex]
[tex]R_p = \frac{20000}{300}[/tex]
[tex]R_p = \frac{200}{3} ~ Ohm[/tex]
[tex]R_p \approx 67 ~ Ohm[/tex]
To find the % Error , we will use this following formula :
[tex]\frac{\Delta R_p}{R_p} = \frac{\Delta R_1}{R_1} + \frac{\Delta R_2}{R_2} + \frac{\Delta (R_1 +R_2)}{R_1 + R_2}[/tex]
[tex]\frac{\Delta R_p}{R_p} = \frac{3}{100} + \frac{4}{200} + \frac{7}{300}[/tex]
[tex]\frac{\Delta R_p}{R_p} = \frac{11}{150}[/tex]
[tex]\frac{\Delta R_p}{R_p} = \frac{11}{150} \times 100{\%}[/tex]
[tex]\frac{\Delta R_p}{R_p} \approx 7{\%}[/tex]
[tex]Absolute ~ Error = \Delta R_p[/tex]
[tex]Absolute ~ Error = \frac{11}{150} \times \frac{200}{3}[/tex]
[tex]Absolute ~ Error = \frac{44}{9}[/tex]
[tex]Absolute ~ Error \approx 5 ~ Ohm[/tex]
[tex]\large {\boxed {R_p = 67 \pm 5 ~ Ohm} }[/tex]
Learn moreThe three resistors : https://brainly.com/question/9503202A series circuit : https://brainly.com/question/1518810Compare and contrast a series and parallel circuit : https://brainly.com/question/539204Answer detailsGrade: High School
Subject: Physics
Chapter: Current of Electricity
Keywords: Series , Parallel , Measurement , Absolute , Error , Combination , Resistor , Resistance , Ohm
Every year, new records in track and field events are recorded. Let's take a historic look back at some exciting races.
In 1989, Carl Lewis established a world record when he ran the 100. meter dash in 9.92 seconds. What was his average speed (in m/s) for the race? Remember to include your data, equation, and work when solving this problem.
Answer: His average speed (in m/s) for the race was 10.08 m/s
Explanation:
Given data
Total distance traveled , D= 100 meter
Total time taken , T= 9.92 seconds
>The average speed([tex]V_{avg}[/tex] ) of an object is the total distance traveled by the object divided by the total time taken to cover that distance .i.e.,
[tex]V_{avg}=\frac{D}{T}=\frac{100}{9.92}\, \frac{m}{s}=10.08\: \frac{m}{s}[/tex]
Thus his average speed (in m/s) for the race was 10.08 m/s
A parachutist with a camera descends in free fall at a speed of 10m/s. The parachutist releases the camera at an altitude of 50m. A) How long does it take the camera to reach the ground? B) What is the velocity of the camera before it hits the ground?
The camera takes approximately 2.02 seconds to reach the ground after being released by the parachutist, and just before hitting the ground, the velocity of the camera is approximately 29.8 m/s.
Explanation:To solve for the time it takes for the camera to reach the ground (A) and the velocity of the camera before it hits the ground (B), we can use the equations of motion under the influence of gravity. Assuming the acceleration due to gravity (g) is 9.8 m/s², and the initial velocity of the camera (u) is 10 m/s (since it's released in free fall by the parachutist moving downward at this speed).
Part A: Time to Reach the Ground
We use the equation: s = ut + 0.5gt², where s is the distance (50m), u is the initial velocity, and t is the time in seconds. Plugging in the values, we get:
50 = 10t + 0.5*9.8*t²
Solving this quadratic equation for t, we find that the time taken for the camera to reach the ground is approximately 2.02 seconds.
Part B: Velocity Before Hitting the Ground
The final velocity (v) can be found using the equation: v = u + gt. Substituting u = 10 m/s, g = 9.8 m/s², and t = 2.02s:
v = 10 + 9.8*2.02 ≈ 29.8 m/s
Therefore, the velocity of the camera just before it hits the ground is approximately 29.8 m/s.
if the velocity of a car is halved, the centripetal force required to keep it in path of constant radius is (multiplied,divided) by what ...?
Answer:
If the velocity of a car is halved, the centripetal force required to keep it in path of constant radius becomes one fourth of the initial force.
Explanation:
The centripetal force is required to move an object in circular path. Mathematically, the formula of the centripetal force is given by :
[tex]F=\dfrac{mv^2}{r}[/tex]
Here,
m is the mass of the object
v is the velocity of object
r is the radius of the circular path
If the velocity of the car is halved, v'=v/2
New centripetal force is given by :
[tex]F'=\dfrac{mv'^2}{r}[/tex]
[tex]F'=\dfrac{1}{4}\times \dfrac{mv^2}{r}\\\\F'=\dfrac{1}{4}\times F[/tex]
New centripetal force becomes one fourth of the initial force, when the velocity of a car is halved.
Final answer:
When the velocity of a car is halved, the centripetal force required to keep it in a path of constant radius is divided by four.
Explanation:
When the velocity of a car is halved, the centripetal force required to keep it in a path of constant radius is divided by four. This is because the centripetal force is directly proportional to the square of the velocity and inversely proportional to the radius of the circular path.
For example, let's say the original velocity of the car is v and the centripetal force required is F. When the velocity is halved to v/2, the centripetal force becomes (v/2)² = F/4.
Therefore, the centripetal force required to keep a car in a path of constant radius is divided by four when the velocity is halved.
A protostar forms when a ________ collapses under the force of gravity.
A. white dwarf
B. black dwarf
C. nebula
D. supernova ...?
Answer:
C .Nebula
Explanation:
Protostar is an early stage in the formation of a star. Main sequence star is formed after the protostar heats up to almost 10 million kelvin temperature.
The interstellar medium fills the entire space, which appears to be seemingly empty. It is comprised of gas and dust. Hydrogen is the most abundant element in this medium, which is spread across and fills the space.
Under the influence of gravity, pressure and temperature, these clouds of gas and dust come together forming nebula. Hydrogen and helium in this nebula, under high temperature conditions form protostars.
what phenomenon naturally warms earth's lower atmosphere and surface
A metal sphere with a mass of 80.0g rolls along frictionless surface at 20.0m/s and strikes a stationary sphere having a mass of 200.0g. The First sphere stops completely. At what speed does the second sphere move away from the point of impact
...?
Answer:
8.0 m/s
Explanation:
By the law of conservation of momentum, the total momentum before the collision must be equal to the total momentum after the collision:
[tex]p_i=p_f[/tex]
The total momentum before the collision is given only by the momentum of the first sphere, since the second sphere is stationary (so its speed is zero and its momentum is zero as well):
[tex]p_i = m_1 u_1 =(80.0 g)(20.0 m/s)=1600 g m/s[/tex]
The total momentum after the collision is given only by the momentum of the second sphere, since the first sphere completely stops, so:
[tex]p_f = m_2 v_2[/tex]
Using conservation of momentum, we find
[tex]p_i=m_2 v_2\\1600 g m/s = (200.0 g) v_2 \\v_2 = \frac{1600 g m/s}{200.0 g}=8.0 m/s[/tex]
The second sphere moves away with a speed of 8 m/s after the collision, derived using the principle of conservation of momentum
To determine the speed of the second sphere after the collision, we need to use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.
Given:
Mass of the first sphere (m1) = 80.0 g = 0.080 kgVelocity of the first sphere before collision (v1) = 20.0 m/sMass of the second sphere (m2) = 200.0 g = 0.200 kgVelocity of the second sphere before collision (v2) = 0 m/sAfter the collision, the first sphere stops completely. Therefore, its final velocity (v'1) is 0 m/s.
The total momentum before the collision:
pinitial = m1 * v1 + m2 * v2 pinitial = 0.080 kg * 20.0 m/s + 0.200 kg * 0 m/s pinitial = 1.6 kg·m/sAfter the collision, let the velocity of the second sphere be v'2.
The total momentum after the collision:
pfinal = m1 * v'1 + m2 * v'2 pfinal = 0.080 kg * 0 m/s + 0.200 kg * v'2 pfinal = 0.200 kg * v'2Since momentum is conserved, pinitial = pfinal:
1.6 kg·m/s = 0.200 kg * v'2Solving for v'2:v'2 = 1.6 kg·m/s / 0.200 kg = 8 m/sThus, after the collision, the second sphere moves away with a speed of 8 m/s.
A 490 n (her weight due to gravity) woman is standing on bathroom scale. what is the woman's mass in kilograms
I solid iron ball of mass 770kg is used on a building site. The ball is suspended by a rope from a crane. The distance from the point of suspension to the centre of the mass of the ball is 12 m.The ball is pulled back from the vertical and then realeased, it falls through a vertical height of 1.6m and strikes the wall: What is the speed of the ball just before impact? ...?
The speed of the ball just before impact is calculated using the conservation of energy principle, translating the potential energy into kinetic energy and solving for velocity to obtain 5.60 m/s.
The speed of the ball just before impact on the building site, we can make use of the principle of conservation of energy. Initially, when the ball is held at a height, it possesses potential energy. When released, this potential energy is converted into kinetic energy just before impact. Given the height it falls through, we can calculate its final speed using the equation for potential energy (PE) and kinetic energy (KE):
PE = KE at the point of release and just before impact,
mgh = ½ mv²,
where m is the mass of the ball, g is the acceleration due to gravity (approximately 9.81 m/s²), h is the height, and v is the final speed. After rearranging and solving for v, we get v = √(2gh).
Inserting the values: v = √(2 * 9.81 m/s² * 1.6 m) = √(31.392) = 5.60 m/s. Therefore, the speed of the ball just before impact is approximately 5.60 meters per second.
What type of pollution did the Clean Water Act succeed in limiting?
sewage is the answer because it's what the water was filled with most
The Chinese Exclusion Act of 1882
1barred employers in U.S. cities from hiring Chinese workers.
2prohibited Chinese laborers from entering the country.
3stripped Chinese Americans of their U.S. citizenship.
4forced Chinese children to attend segregated schools. ...?
Answer: The answer is 2. Prohibited the Chinese laborers from entering the country.
Explanation: The Chinese Exclusion Act of 1882 was a federal law in the United States signed by President Chester. It effectively halted Chinese immigration. I hope your answer is very helpful, please mark me as Brainliest and have a wonderful day! :D
Consider the following geometric solids.
A sphere with a ratio of surface area to volume equal to 0.08 m-1.
A right circular cylinder with a ratio of surface area to volume equal to 2.1 m-1.
What results would you expect if these two models were compared in a diffusion test?
A. The rate of diffusion would be the same for the two models.
B. The rate of diffusion would be faster for the right cylinder.
C. The rate of diffusion would be slower for the right cylinder.
D. The rate of diffusion would be faster for the sphere.
Before answering this question, first we have to understand the effect of ratio of surface area to volume on the rate of diffusion.
The rate of diffusion for a body having larger surface area as compared to the ratio of surface area to volume will be more than a body having less surface area. Mathematically it can written as-
V∝ R [ where v is the rate of diffusion and r is the ratio of surface area to volume]
As per the question,the ratio of surface area to volume for a sphere is given [tex]0.08m^{-1}[/tex]
The surface area to volume ratio for right circular cylinder is given [tex]2.1m^{-1}[/tex]
Hence, it is obvious that the ratio is more for right circular cylinder.As the rate diffusion is directly proportional to the surface area to volume ratio,hence rate of diffusion will be more for right circular cylinder.
Hence the correct option is B. The rate of diffusion would be faster for the right cylinder.
which radiation has a higher frequency than visible light
Answer:
Ultraviolet radiation
Explanation:
Apex