A rock is dropped from a bridge. what happens to the magnitude of the acceleration and the speed of the rock as it falls?

Final answer:

Snell's Law is the physical principle that defines the relationship between the angles of incidence and refraction when light transitions between two different media, mathematically expressed as n1 sin θ1 = n2 sin θ2.

Explanation:

Snell's Law, also known as the law of refraction, describes the relationship between the angles of incidence and refraction when a light ray passes through the interface between two different media. This fundamental physical principle is expressed mathematically as n1 sin θ1 = n2 sin θ2, where 'n1' and 'n2' are the indices of refraction of the first and second media, respectively, and 'θ1' and 'θ2' are the angles of incidence and refraction. Snell's Law is crucial for understanding phenomena such as the bending of light, and it has applications in fields like optics and engineering.

The velocity of the wrench 4 seconds after being dropped is -128 ft/sec, indicating it is moving downwards.

To determine the velocity of the wrench 4 seconds after it was dropped from the top of the building, we use the height function s(t) = -16[tex]t^2[/tex] + 375, which represents the wrench's position over time.

The velocity at any time t is given by the derivative of the position function, which is v(t) = s'(t).

Calculating the derivative, we get v(t) = -32t. Therefore, the velocity of the wrench at t = 4 seconds is v(4) = -32(4) = -128 ft/sec. The negative sign indicates that the wrench is moving downwards.

B. Valence Electrons

_________________

Reason:

The valence electrons are the number of electrons in an outer shell of an atom that can participate in forming chemical bonds with other atoms. Atoms with a relatively empty outer shell will want to give up electrons.

Answer:

A magnetic field

Explanation:

Refraction is the bending of light rays as they pass through different mediums due to a change in speed, explained by the refractive index and described by Snell's law. It's observable in everyday phenomena and is crucial for the functionality of optical instruments like telescopes.

Refraction refers to the change in direction of a light ray as it passes through variations in matter, such as moving from air into water or glass. This bending occurs due to a change in the light's speed between different mediums. Each material has a refractive index, which dictates how much the light will bend. This index is the ratio of the speed of light in a vacuum to that in the material. For example, when looking into a pond, a stick that is partially submerged in water appears bent at the water's surface; this visual effect is due to refraction.

The extent of refraction follows Snell's law, which relates the angle of incidence to the angle of refraction, keeping in mind the refractive indices of the two media. This law is the foundational principle behind the design of lenses, prisms, and various optical instruments like refracting telescopes.

In astronomy, refraction is observed when light from celestial bodies enters Earth's atmosphere at various angles. Due to the atmosphere's density variations, stars appear slightly higher in the sky than they truly are, as the light they emit is refracted. The amount of this refraction can be calculated, and is negligible near the zenith but increases towards the horizon.

The 10 kg cart and 5 kg cart under different net forces will move to the left but with different accelerations. Despite the larger force acting on the 10 kg cart, the lighter 5 kg cart will actually accelerate at a greater rate.

Comparing the motion of a 10 kg cart experiencing a net force of 12 N to the left and a 5 kg cart experiencing a net force of 8 N to the left involves the principles of Newton's second law of motion, F=ma. For the 10 kg cart, the acceleration is found by dividing the force by mass(12 N / 10 kg), which equals 1.2 m/s² to the left. For the 5 kg cart, the acceleration is (8 N / 5 kg), which equals 1.6 m/s² to the left.

Therefore, despite the 10 kg cart experiencing a larger force, the 5 kg cart actually accelerates at a greater rate due to its lighter mass. This illustrates the principle that net force not only depends on the magnitude of the force but also on the mass of the object it is acting on.

https://brainly.com/question/13447525

#SPJ2

Answer:

c

Explanation:

Answer:

The correct answer is option D

Explanation:

Wave Energy is given by

[tex]= \frac{1}{2} M(w^2 *A^2*\frac{1}{2})\\[/tex]

Wave energy is directly proportional to the square of the amplitude.

thus,

[tex]\frac{E1}{E2} = \frac{A1^2}{A2^2} \\\frac{3}{E2} = \frac{2^2}{4^2} \\E2 = 12 units\\[/tex]

The officer conclude that the driver exceeded the speed limit as the speed was 69mph.

speed = distance /time

speed  = 30 miles / 26 minute

speed = 30 miles /26 minute x 60 minutes/1 hour

speed = 900 miles/13 hours

speed = 69 mph.

the prevailing maximum pace limit for cars on expressways is a hundred and twenty km and on national highways, the maximum velocity restriction is 100 mph.

Velocity limits in India vary by way of nation and car type. In April 2018, the Union Ministry of street shipping and Highways constant the most velocity limit on expressways at a hundred and twenty km/h, for national highways at one hundred km/h, and for urban roads at 70 km/h for the M1 class of vehicles.

Learn more about the speed limit here: https://brainly.com/question/13819357

#SPJ2

Answer:

Explanation:

I agree with what the first person said

Final answer:

The correct answer is that the melting point and freezing point of a substance are always the same, illustrating the equilibrium between the solid and liquid states of that substance at a specific temperature, such as 0°C for water.

Explanation:

The correct answer to which of the following is true about melting and freezing points is: The melting point is always the same as the freezing point. This principle is crucial in understanding the thermal properties of substances. The temperature at which a substance changes from solid to liquid (melting point) is the same temperature at which it changes from liquid to solid (freezing point) when the process is reversible and under the same pressure conditions. For instance, with water (H₂O), this equilibrium occurs at 0°C, illustrating that at this temperature, the solid and liquid states of H₂O are in equilibrium (H₂O (s) = H₂O (l)).

It's essential to refute common misconceptions like the melting point being higher than the freezing point or that these concepts apply differently to liquids and gases. All materials, whether solid, liquid, or gas at room temperature, have characteristic melting/freezing points that do not depend on their state at room temperature but rather on their inherent thermal properties.

The answer is 1350 N

The decomposition of CaCO3 in a container with a piston results in the formation of CO2 gas, which increases the volume and hence work done is -2265 Joules. If the reaction was in an open container, the work done would be zero as there is no opposing force and volume change in the container.

The decomposition of Calcium carbonate i.e. CaCO3, leads to the formation of calcium oxide and carbon dioxide, as shown by the equation CaCO3(s) → CaO(s)+CO2(g). The process is a type of expansion work, which can be calculated using the formula W=PΔV, where W = work, P = pressure and ΔV = change in volume. Carbon dioxide being gas increases the volume. For 1 mole of CO2 at STP, the volume is approximately 22.4 liters or 22.4*10^-3 m^3. As we know Pressure = 1 atm = 1.01325*10^5 Pascals, work done = - PΔV = -1.01325*10^5 Pascals * 22.4*10^-3 m^3 = -2265 Joules.

Now if instead of a piston, the container was open to the atmosphere, the work done would be different as the work will depend on the volume change. In an open container, the system does work but due to no restriction or expansion against any opposing force, the work done is zero since the pressure outside and inside the container is same (atmospheric pressure) and there is no volume change in the container.

https://brainly.com/question/34137415

#SPJ12

The work done during the complete decomposition of 1.0 mol of CaCO3 at 800°C and 1.0 atm is -88.07 L·atm or -8920.3 J. This work would be the same if the container were open to the atmosphere.

To find the work done during the complete decomposition of 1.0 mol of calcium carbonate (CaCO3), we follow these steps:

Using the ideal gas law (PV = nRT) at 800°C (which is 1073 K):

Since work done is calculated by w = -PΔV:

Conclusion: The work done during the complete decomposition of 1.0 mol of CaCO3 at 800°C and 1.0 atm is -88.07 L·atm or -8920.3 J. This work would be the same if the container were open to the atmosphere because the external pressure remains 1.0 atm.

The answer is A. Acceleration.

Answer:

the average kinetic energy of water particles

Explanation:

The answer is option a.

During a washing machine's spin cycle, the force that acts on the clothes is directed outward, which is a result of the centrifugal force.

In the context of a washing machine's spin cycle, the force that acts on the clothes is directed outward. This is due to the principle of centrifugal force, a type of inertial force that acts on an object moving in a circular path. The centrifugal force pushes the clothes against the wall of the washing machine drum when it rotates, effectively helping to draw water out of the clothes.

This centrifugal force pushes the clothes away from the center of rotation, causing them to stick to the drum's inner surface during the spin cycle.

Therefore, the answer is option a.

https://brainly.com/question/545816

#SPJ3

The two cars have equal speeds at approximately t = 3.85 seconds. The speeds of the cars at that time are approximately 3.15 cm/s and 5.2 cm/s, respectively. The cars pass each other at approximately t = 1.83 seconds.

To determine the time when the two cars have equal speeds, we need to find the time when their velocities are equal. The velocity of the first car is given by the equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. Setting the velocities of the two cars equal to each other, we have:

-4.2 + 2.6t = 5.2

Solving for t, we find:

t = (5.2 + 4.2) / 2.6

t ≈ 3.85 seconds

So, at approximately t = 3.85 seconds, the two cars have equal speeds.

(b) To find their speeds at that time, we substitute the value of t into the equation for velocity:

V1 = -4.2 + 2.6(3.85)

V1 ≈ 3.15 cm/s

V2 = 5.2

So, at t = 3.85 seconds, the speeds of the cars are approximately 3.15 cm/s and 5.2 cm/s, respectively.

(c) To find the time(s) when the cars pass each other, we can compare their positions. The position of the first car is given by the equation:

x1 = x1o + u1t + (1/2)at^2

x1 = 13.5 - 4.2t + (1/2)(2.6)t^2

The position of the second car is given by:

x2 = 8.5 + 5.2t

Setting these two equations equal to each other and solving for t, we have:

13.5 - 4.2t + (1/2)(2.6)t^2 = 8.5 + 5.2t

Simplifying, we get:

(1.3)t^2 + 9.4t - 5 = 0

Using the quadratic formula, we find two possible values of t:

t ≈ -2.43 seconds, t ≈ 1.83 seconds

Since time cannot be negative, we discard t = -2.43 seconds. Therefore, the cars pass each other at approximately t = 1.83 seconds.

Final answer:

To find the length of a pendulum with 1.0 seconds on the Moon, we use the formula for a pendulum's period, adjust the acceleration due to gravity to the Moon's 1.63 m/s², and solve for the pendulum's length.

Explanation:

The subject question inquires about the length of a pendulum on the Moon that has a period of 1.0 seconds, taking into consideration that the Moon's gravity is 1/6th that of Earth's. The formula for the period of a simple pendulum is T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.

On Earth, assuming the acceleration due to gravity (g) is approximately 9.81 m/s², the length (L) for a pendulum with a period (T) of 1.0 seconds can be calculated using this formula. However, since we are interested in the situation on the Moon where g is 1/6th that of Earth's, we would have to adjust the acceleration due to gravity in our formula to be 1.63 m/s² (since 9.81 m/s² divided by 6 equals approximately 1.63 m/s²).

Accordingly, by rearranging the formula to L = T²g/(4π²), and substituting T with 1.0 second, and g with 1.63 m/s², one can compute the appropriate length of the pendulum on the Moon that would have a period of 1.0 second.

Final answer:

The length of a pendulum with a period of 1.0 second on the Moon can be calculated by rearranging the period formula for a simple pendulum, T = 2π√(L/g), and substituting in the Moon's gravity of 1.63 m/s².

Explanation:

The length of a pendulum that has a period of 1.0 second on the Moon, where gravity is 1/6th of Earth's gravity, can be found using the formula for the period of a simple pendulum, T = 2π√(L/g). On Earth, where the standard acceleration due to gravity, g, is approximately 9.81 m/s², a 1.0-second period requires a certain pendulum length. However, on the Moon, the acceleration due to gravity is only 1.63 m/s².

We can rearrange this formula to solve for the length (L) of the pendulum on the Moon: L = (T² * g) / (4π²). By substituting T for 1.0 second and g for 1.63 m/s², the length of the pendulum on the Moon can be calculated.

Using the provided formula, we get L = (1.0² seconds² * 1.63 m/s²) / (4π²) which gives us the length of the pendulum on the Moon. You would then perform the calculation to find the exact value for L.

Answer: Atmosphere can be broadly divided into four distinct layers based on their altitude and temperature.

These layers are- Troposphere, Stratosphere, Mesosphere, and Thermosphere.

1) Troposphere ( extends upto 18 km from earth surface)- a layer that is closest to the surface of earth. It is called zone of weather as all the weather phenomenon ( such as storm, wind, precipitation, formation of clouds) occur in this layer. Temperature decreases with altitude in this layer.

2) Stratosphere (extends from 18 km to 50 km) - a layer above troposphere, where temperature increases with increase in altitude.

A boundary between stratosphere and mesosphere where temperature remains constant as elevation increases  is called Stratopause.

3) Mesosphere (extends 50 km upto 85 km) - a layer above stratosphere, where temperature decreases with increase in altitude.

A boundary between mesosphere and thermosphere, where temperature remains constant as elevation increases  is called Mesopause.

4) Thermosphere (extends from 85 km upto 600 km)-  a layer above mesosphere, where temperature again increases with increase in altitude. It is an extremely hot layer because of absorption of X rays and UV rays.

Thus, correct match for the question is-  

Troposphere -A) Layer closest to the Earth where all weather occurs.

Mesosphere- E) begins between 50-60km and decreases in temperature as elevation increases.

Mesopause- C) temperature remains constant as elevation increases.

Stratosphere -B) temperature increases as elevation increases.

Stratopause -D) temperature remains at a constant zero degrees Celsius as elevation increases.

Final answer:

The layers of the atmosphere can be matched with their descriptions based on the temperature profile as follows: Troposphere - layer closest to the Earth where all weather occurs. Mesosphere - begins between 50-60 km and decreases in temperature as elevation increases. Stratosphere - temperature increases with an increase in elevation. Stratopause - temperature remains constant as elevation increases. Mesopause - temperature remains at a constant zero degrees Celsius as elevation increases.

Explanation:

The layers of the atmosphere can be matched with their descriptions based on the temperature profile as follows:

Final answer:

To eliminate the parameter t and find a rectangular equation for the plane curve defined by the parametric equations x = 6 cos t, y = 6 sin t; 0 ≤ t ≤ 2π, we can square both equations and then add them together. The rectangular equation for the plane curve is x^2 + y^2 = 36.

Explanation:

To eliminate the parameter t and find a rectangular equation for the plane curve defined by the parametric equations x = 6 cos t, y = 6 sin t; 0 ≤ t ≤ 2π, we can square both equations and then add them together. This will eliminate the parameter t and give us a rectangular equation. Let's do the calculations:

x^2 = (6 cos t)^2 = 36 cos^2 t

y^2 = (6 sin t)^2 = 36 sin^2 t

Adding the two equations together: x^2 + y^2 = 36 (cos^2 t + sin^2 t) = 36

So, the rectangular equation for the plane curve is x^2 + y^2 = 36. This means that option C is the correct answer.

As the time to run up the stairs increases, the power developed decreases..

When analyzing the relationship between time and power, it's essential to consider the fundamental definition of power as the rate at which work is done.

This can also be understood using the formula for power -

Power (P) = Work (W) / Time (t)

When the time (t) increases and the work (W) remains constant, the power output (P) decreases.

Thus, as the time required to run up the stairs increases, the power developed by that person decreases.