A real estate agent sells a house for $92,000. She receives a 6% commission on the sale of the house.

How much did she earn on the sale?

Round your answer to the nearest cent.

need answer in 10 mins. or less

The cost to print 1200 copies is $52.00.

The given data tells us that 320 copies cost $43.20. Each set of 40 copies costs $0.40, so 320 copies are 8 sets (320/40). The variable cost for 320 copies is 8 × $0.40 = $3.20.

We can then determine the fixed setup cost by subtracting the variable cost from the total cost for 320 copies: $43.20 - $3.20 = $40.00.

The total cost C for printing x copies can be expressed as:

C = fixed setup cost + variable cost per set × (x/40)

So the total cost for 1200 copies is:

C = $40.00 + $0.40 × (1200/40)

Calculating this, we get:

C = $40.00 + $0.40 × 30 = $40.00 + $12.00 = $52.00

Therefore, the cost to print 1200 copies is $52.00.

56.69 - 0.145(56.69)

= 56.69 - 8.22

= 48.47

the formula for discount price

Subtract the final price from the original price. Divide this number by the original price. Finally, multiply the result by 100. You've obtained a discount in percentages.

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a. There could be 5 different choices and b. There could be 6 different choices.

Multiplication is the mathematical operation that is used to determine the product of two or more numbers. If an event can occur in m different ways and if following it, a second event can occur in n different ways, then the two events in succession can occur in m × n different ways.

Given tha the number of different kinds of soups = 2

The number of different kinds of salad = 3

(a) If you are having either soup or salad, then the total number of choices you have;

2 + 3 = 5

Hence, the total number of choices you have 5.

(b)  If you are having both soup and salad, then the number of choices you have;

2 x 3 = 6

Hence, the total number of choices you have 6.

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The probability of correctly guessing the combination will be 1/7140.

A permutation is an act of arranging items or elements in the correct order. Combinations are a way of selecting items or pieces from a group of objects or sets when the order of the components is immaterial.

A lock has a disk with 36 numbers written around its edge. The combination of the lock is made up of three numbers.

The total number of the events will be

Total event = ³⁶C₃

Total event = 36! / [(36 - 3)! x 3!]

Total event = 7140

The favorable number of the event will be one.

Then the probability of correctly guessing the combination will be

P = 1 / 7140

The probability of correctly guessing the combination will be 1/7140.

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Final answer:

To find how fast the distance between two ships is changing, we calculate the distance they have covered, form a right triangle, and use the Pythagorean theorem and related rates to find that the distance is changing at approximately 8.94 km/h at 4:00 PM.

Explanation:

To determine how quickly the distance between ship A and ship B is changing, we can use the concept of related rates from calculus. At noon, the ships are 170 km apart. Ship A travels east (towards ship B) at 30 km/h, and ship B travels north at 25 km/h. By 4:00 PM, four hours have passed.

First, let's calculate the distance each ship has traveled after 4 hours. Ship A would have covered 30 km/h * 4h = 120 km eastward. Ship B would have traveled 25 km/h * 4h = 100 km northward.

Next, we need to calculate the distance between the two ships at 4:00 PM. Since ship A is moving east and ship B is moving north, they are traveling at right angles to each other. The distance between the two ships forms the hypotenuse of a right triangle, with the sides being the distances traveled by each ship. Using the Pythagorean theorem, the distance between the two ships at 4:00 PM (D) is:

² = (170 km - 120 km)² + (100 km)²

² = (50 km)² + (100 km)²

² = 2500 km² + 10000 km²

= √12500 km²

= 111.80 km (approx)

Finally, we have to find the rate at which this distance is changing. Let x be the east-west distance from ship B to ship A, and y be the northward distance ship B has covered. Taking the derivative of the Pythagorean relation we have, x² + y² = ², with respect to time (t) gives us:

2x(/) + 2y(/) = 2(/)

Given that dx/dt = -30 km/h (since it's decreasing as ship A sails east) and dy/dt = 25 km/h, we can solve for d/dt:

2*50*(-30) + 2*100*(25) = 2*111.80*(d/dt)

-3000 + 5000 = 223.60*(d/dt)

2000 = 223.60*(d/dt)

d/dt = 2000 / 223.60

d/dt = 8.94 km/h (approx)

Therefore, the distance between the ships is changing at approximately 8.94 km/h at 4:00 PM.

Answer:

152.4 cm

Step-by-step explanation:

Wesly is 5 feet and 3 inches tall. Since there are 12 inches in one foot, 5 feet has 60 inches. This means Wesly is 63 inches tall. If one inch is 2.54 cm then 60(2.54) is Wesly's height in centimeters. 60(2.54) = 152.4

Dawn has 6 slices of Pie A and 3 slices of Pie B remaining.

Dawn brought two pies to a bake sale. Pie A was cut into 8 slices and Pie B was cut into 6 slices. She sold 2 slices of Pie A and 3 slices of Pie B. To calculate how much pie Dawn has remaining, we need to subtract the slices sold from the total slices in each pie. So, for Pie A, we have 8 slices - 2 slices = 6 slices remaining. And for Pie B, we have 6 slices - 3 slices = 3 slices remaining. Therefore, Dawn has a total of 6 slices of Pie A and 3 slices of Pie B remaining.

Final answer:

Dawn originally had two pies, with Pie A cut into 8 slices and Pie B cut into 6 slices. She sold two slices from Pie A and three from Pie B, leaving her with a total of 9 slices remaining from both pies.

Explanation:

To determine how much total Pie Dawn has remaining after selling some slices, we can use simple subtraction.

Dawn originally had two pies:
Pie A was cut into 8 slices, and she sold 2 slices.
Pie B was cut into 6 slices, and she sold 3 slices.

To find out how much of each Pie is left, we subtract the number of slices sold from the total number of slices:

Pie A remaining: 8 - 2 = 6 slices

Pie B remaining: 6 - 3 = 3 slices

To find the total amount of Pie remaining, we add the slices remaining from Pie A and Pie B:

Total Pie remaining: 6 (from Pie A) + 3 (from Pie B) = 9 slices

Dawn is left with 9 slices of Pie in total after the sales.

The classmate's claim is incorrect, as a parabola cannot pass through two points with the same x-coordinate but different y-values, making it impossible for a single quadratic function to pass through points (3,4), (5,-2), and (3,0).

The error in your classmate's assertion that he can write the equation of a quadratic function that passes through the points (3,4), (5,-2), and (3,0) lies in the fact that a quadratic function is a parabola, and no parabola can pass through two points that have the same x-coordinate but different y-values. In other words, any vertical line (like x=3) can intersect a parabola at most once because a quadratic function has only one y value for each x value. Since (3,4) and (3,0) both have the x-coordinate of 3 but different y-coordinates, they cannot both lie on the same parabola. The equation of a quadratic function is typically written as [tex]y = ax^2 + bx + c[/tex], where a, b, and c are constants. To pass through specific points, these constants must be determined such that the function satisfies the coordinates of the points. However, due to the reason explained, no set of constants will satisfy the condition for the mentioned points.

Answer:

45

Step-by-step explanation:

We know that,

If we have the numbers of the form xyz.

This gives that, x is placed at the hundredth place, y is placed at the tens place and z is located at ones place.

Since, we need a number between 20 and 50 having both tens and ones place.

We can take any number from 20 to 50.

For e.g. Let us take 45.

In 45, 4 is placed at the tens place and 5 is placed at the ones place.

Hence, 45 is the number between 20 to 50 having both tens and ones place.

Answer:

75% of the planets have moons

Step-by-step explanation:

In order to calculate this you just have to do a simple rule of three, in which you will use 888 as the 100 percent and you want to discover what percentage of that does 666 represents:

[tex]\frac{888}{100} \frac{666}{x} \\x=\frac{666*100}{888}\\ x=75\\[/tex]

So you have that 666 is the 75% of 888, that means that 75% of the planets have moons.

When selecting three batteries at random with replacement, there are 125 points in the sample space. When selecting three batteries at random without replacement, there are 60 points in the sample space.

To determine the number of points in the sample space when selecting three batteries at random with replacement, we use the counting principle. Since there are 5 batteries, each with an equal likelihood of being selected, and we are selecting three batteries, we can calculate the number of points in the sample space as follows:

Number of points = Number of possible outcomes for the first battery * Number of possible outcomes for the second battery * Number of possible outcomes for the third battery

Since there are 5 batteries, the number of possible outcomes for each battery is 5. Therefore,

Number of points = 5 * 5 * 5 = 125

So, there are 125 points in the sample space when selecting three batteries at random with replacement.

When selecting three batteries at random without replacement, the number of points in the sample space will be different. We can calculate it using a similar approach, but taking into account that once a battery is selected, it is removed from the bag and cannot be selected again. Therefore, for the first battery, there are 5 possible outcomes. For the second battery, there will be 4 possible outcomes since one battery has already been selected. For the third battery, there will be 3 possible outcomes. Therefore,

Number of points = 5 * 4 * 3 = 60

So, there are 60 points in the sample space when selecting three batteries at random without replacement.

The number of possible outcomes for selecting three batteries with replacement is 125. For selecting three batteries without replacement, the total is 60. The counting principle multiplies the number of options for each choice to calculate the sample space.

When selecting three batteries from a bag containing five different brands at random, the number of points in the sample space can be determined using the counting principle. The sample space represents all possible outcomes of an experiment.

a. Sampling with replacement

When batteries are selected with replacement, after each selection, the chosen battery is put back into the bag, making it available for the next selection. Thus, for each pick of the three batteries, there are five choices. The total number of points in the sample space for selecting three batteries with replacement is therefore 5 × 5 × 5 = 125.

b. Sampling without replacement

When batteries are selected without replacement, the chosen battery is not put back in the bag, which means the options decrease with each selection. The first pick has five choices, the second pick will have four (since one battery is already picked), and the third pick will have three. The total number of points in the sample space for selecting three batteries without replacement is therefore 5 × 4 × 3 = 60.