What is the frequency of radiation whose wavelength is 0.84 nm ? express the frequency in inverse seconds to three significant digits?
A mass m = 17 kg is pulled along a horizontal floor with no friction for a distance d =5.8 m. then the mass is pulled up an incline that makes an angle θ = 35° with the horizontal and has a coefficient of kinetic friction μk = 0.39. the entire time the massless rope used to pull the block is pulled parallel to the incline at an angle of θ = 35° (thus on the incline it is parallel to the surface) and has a tension t =88 n. 1) what is the work done by tension before the block goes up the incline? (on the horizontal surface.) 418.1 j submit 2) what is the speed of the block right before it begins to travel up the incline? 7.01 m/s submit 3) what is the work done by friction after the block has traveled a distance x = 3 m up the incline? (where x is measured along the incline.) -159.67 j submit 4) what is the work done by gravity after the block has traveled a distance x = 3 m up the incline? (where x is measured along the incline.) -286.67 j submit 5) how far up the incline does the block travel before coming to rest? (measured along the incline.)
Final answer:
The student's problems require applying the concepts of work and energy to determine the effects of tension, friction, and gravity on a block moving on a surface and up an incline.
Explanation:
The student's question pertains to the work done by various forces on a block which is initially pulled along a horizontal surface and then up an incline. To solve problems like these, we rely on concepts from physics including work, energy, and the effects of forces on motion.
Work done by Tension on a Horizontal Surface
On a horizontal surface with no friction, the work done by tension is given by Work = force × distance. Since the force of tension is parallel to the displacement, the work done is simply the product of tension (T) and the distance (d).
Speed Before Incline
The speed of the block before it goes up the incline can be found using the work-energy principle. The work done on the block is equal to the change in its kinetic energy.
Work Done by Friction and Gravity on an Incline
When the block is pulled up an incline with friction, both the force of friction and gravity do work against the direction of motion. The work done by friction is the product of frictional force, distance, and the cosine of the angle between the force and the displacement (which is 180 degrees, so cos(180°) = -1).
Distance Traveled Up the Incline Before Rest
To find how far up the incline the block travels before coming to rest, we need to equate the work done against friction and gravity with the initial kinetic energy of the block. This will require solving for distance in the work-energy equation.
What statement is true about a spring?
What occurs when a ball Falls from a balcony?
A. The earth moves toward the ball.
B. Neither the ball nor the earth actually move.
C. The earth moves away from the ball.
D. The ball moves but not the earth
What distance does the car cover in the first 4.0 seconds of its motion?
The car's velocity to be 2.4 m/s, and the distance covered in the first 4 seconds to be 4.8 meters.
From the given parameters and the provided graph, we're tasked with determining the velocity of a car and the distance it covers within a specific time interval. The total distance traveled by the car (S) is 12 meters, and the total time taken is 8 seconds. To find the velocity (V), we use the formula for the area of a trapezium.
Firstly, using the area of a trapezium formula, where S = 1/2 (a + b) * V, with a and b representing the parallel sides of the trapezium formed by the graph:
Given that a = 2 and b = 8, we substitute these values into the formula:
12 = 1/2(2 + 8) * V
24 = 10V
V = 24/10
V = 2.4 m/s
Thus, the velocity of the car is calculated to be 2.4 m/s.
Next, within the first 4 seconds, the shape of the distance covered by the car forms a triangle on the graph. Utilizing the formula for the area of a triangle, which is 1/2 * base * height, where the base is the time (4s) and the height is the speed (V = 2.4 m/s):
S = 1/2 * 4 * 2.4
S = 4.8 m
Hence, the distance covered by the car within the first 4 seconds of its motion is 4.8 meters.
In summary, by calculating the velocity using the area of a trapezium and determining the distance covered within a specific time interval using the area of a triangle, we find the car's velocity to be 2.4 m/s, and the distance covered in the first 4 seconds to be 4.8 meters.
The question probable may be;
A car in stop-and-go traffic starts at rest, moves forward 12 m in 8.0 s, then comes to rest again. The velocity-versus-time plot for this car is given in the figure. What distance does the car cover in the first 4.0 seconds of its motion?
What is the mass of a 14.0 cm3 cube of fresh water (density 1.00 g/cm3)?
A proton travels through uniform magnetic and electric fields. the magnetic field is in the negative x direction and has a magnitude of 2.04 mt. at one instant the velocity of the proton is in the positive y direction and has a magnitude of 1930 m/s. at that instant, what is the magnitude of the net force acting on the proton if the electric field is (a) in the positive z direction and has a magnitude of 4.70 v/m, (b) in the negative z direction and has a magnitude of 4.70 v/m, and (c) in the positive x direction and has a magnitude of 4.70 v/m?
a. the net force magnitude in case (a) is [tex]7.53 * 10^-^1^8 N[/tex].
b. the net force magnitude in case (b) is also [tex]7.53 * 10^-^1^8 N[/tex].
c. the net force magnitude in case (c) is approximately [tex]6.40 * 10^-^1^5 N.[/tex]
a. Electric force:
Force = q * E
= ([tex]1.602 * 10^-^1^9[/tex] C) * (4.70 V/m)
= [tex]7.53 * 10^-^1^8[/tex] N (pointing in the positive x direction)
b. Magnetic force:
The magnetic force will now create a force in the negative y direction with magnitude:
Force = q * v * B, where v is the proton velocity and B is the magnetic field
Force = [tex](1.602 * 10^-^1^9 C) * (1930 m/s) * (2.04 x 10^-^3 T) \\= 6.40 * 10^-^1^5 N[/tex]
c. Net force:
Net force = electric force + magnetic force (vector sum)
Net force magnitude = √(([tex]7.53 *10^-^1^8 N)^2 + (6.40 * 10^-^1^5 N)^2)[/tex]
Net force magnitude ≈ [tex]6.40 * 10^-^1^5[/tex] N
A tennis player receives a shot with the ball (0.0600 kg) traveling horizontally at 22.0 m/s and returns the shot with the ball traveling horizontally at 35.5 m/s in the opposite direction. (assume the initial direction of the ball is in the −x direction.) (a) what is the impulse delivered to the ball by the tennis racket?
suppose the same amount of heat is applied to two bars. they have the same mass, but experience different changes in temperature. are the specific heat capacities the same for the two bars? explain.
If both bars are made of a good conductor, then their specific heat capacities must be different. If both are metals, specific heat capacities of different metals can vary by quite a bit, eg, both are in kJ/kgK, Potassium is 0.13, and Lithium is very high at 3.57 - both of these are quite good conductors.
If one of the bars is a good conductor and the other is a good insulator, then, after the surface application of heat, the temperatures at the surfaces are almost bound to be different. This is because the heat will be rapidly conducted into the body of the conducting bar, soon achieving a constant temperature throughout the bar. Whereas, with the insulator, the heat will tend to stay where it's put, heating the bar considerably over that area. As the heat slowly conducts into the bar, it will also start to cool from its surface, because it's so hot, and even if it has the same heat capacity as the other bar, which might be possible, it will eventually reach a lower, steady temperature throughout.
Because angular momentum is conserved, an ice-skater who throws her arms out will
Final answer:
An ice-skater who pulls her arms in will spin faster due to the conservation of angular momentum, as a reduction in her moment of inertia results in an increased rotation speed to keep the angular momentum unchanged.
Explanation:
Because angular momentum is conserved, an ice-skater who throws her arms out will experience a change in their rotation speed when altering their body's configuration. When a figure skater on ice extends her arms while spinning, she has a certain angular momentum, which depends on her rotation speed and the distribution of her mass—or her moment of inertia. With arms extended, her moment of inertia is greater. If she pulls her arms in, she reduces her moment of inertia, but because no external torque is acting on her, her angular momentum must stay constant. To maintain the same angular momentum with a smaller moment of inertia, her rotation speed—or angular velocity—must increase. Therefore, when an ice skater pulls in her arms, she spins faster; this is a classic demonstration of the conservation of angular momentum.
The formula for angular momentum (l) is defined as l = mvR, where m is the mass, v is the linear speed, and R is the radius of the orbit or the distance from the axis of rotation. When the skater pulls her arms inward, 'R' decreases, and since mass ('m') remains unchanged, the speed ('v') must increase for the angular momentum to stay conserved. This result in an increased rate of spin, which is also seen as an increase in rotational kinetic energy due to the work done by the skater to pull her arms closer to her body.
Which of the following BEST explains why stability is an important skill for athletes?
A.
Without good stability, athletes cannot participate in sports.
B.
Without good stability, athletes are too clumsy to perform well.
C.
Good stability helps athletes improve their speed.
D.
Good stability helps athletes deal with their injuries.
Answer;
B. Without good stability, athletes are too clumsy to perform well.
Explanation;
Stability refers to the resistance to both linear and angular acceleration, or resistance to disruption of equilibrium.
Developing and enhancing core strength and stability helps athletes to maximize their power output and enhance game day performance. Additionally, Improving core strength and stability can also help athletes reduce their risk of injury.
Stability is an important skill for an athlete because without good stability, athletes are too clumsy to perform well.
Option B is correct
What is stability an for athlete?Stability is the ability of an athlete retain controls for more than the average distance of a movement, This does not mean an athlete will no be displace but the ability to regain shape is stability
Therefore, without good stability, athletes are too clumsy to perform well.
Option B is correct
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Teams A and B are in a tug-of-war challenge. Team A wins the challenge. What can be said about Team A?
Answer:
Team A exert more force on ground.
Explanation:
In Tug of war since both teams are pulling two ends of a string or rope so here the net force on the string along with two teams would be zero
So in order to win the game each team has to exert force on the ground.
When team exert more force on the ground then due to the reaction force of ground on the team in opposite direction will help the team to pull the rope towards them
So here if Team A wins the game then the force exerted by that team on the ground must be more due to which the reaction force by ground on the team is of larger magnitude and hence they wins the game
In a tug-of-war, Team A's victory means they exerted a larger force than Team B, creating a net force that caused the movement of the rope towards their side.
In a tug-of-war challenge, if Team A wins, it can be said that Team A exerted a larger force on the rope than Team B. This is because the winning team in a tug-of-war is the one that pulls the rope towards their side over the center line, overcoming the opposing team's efforts. Force in physics is a measure of the interaction between two objects, and in this case, the interacting objects are the two teams exerting forces on the rope. The team that wins is the one that manages to exert a net force that is greater than that of the opposing team, resulting in the movement of the rope towards the winning team's side.
A skydiver is descending with a constant velocity. Consider air resistance. Diagram the forces acting upon the skydiver
The forces acting on the skydiver is downward force due to his own weight, and drag force acting upwards due to air resistance.
At a constant speed, the upward acceleration of the skydiver is zero. The downward acceleration is equal to acceleration due to gravity. The upward force is equal to downward force.
The sketch of the forces acting on the skydiver is presented below using simple diagram;
↑ N
Ф
↓ W
Thus, the forces acting forces acting on the skydiver is downward force due to his own weight, and drag force acting upwards due to air resistance.
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Write a paragraph showing the relationship between chemistry and physical based on what you've learned from the periodic table
Final answer:
The periodic table symbolizes the relationship between chemistry and physics by organizing elements based on their atomic numbers and grouping them by shared properties, influencing their chemical reactivity and physical states.
Explanation:
The relationship between chemistry and physics can be explored through the study of the periodic table, a fundamental tool in the chemical sciences. The periodic table not only lists elements by increasing atomic number but also groups them by shared physical and chemical properties. For example, elements that are gases, liquids, or solids at room temperature can be predicted based on their placement in the periodic table. Similarly, an element's chemical reactivity is indicated by its grouping, which suggests its tendency to combine and form chemical bonds. The table, conceptualized by Dmitri Mendeleev, reflects the periodic trends in electron configuration which underpin both the chemical behaviors and physical properties, such as electrical conductivity. Indeed, the understanding of such properties has been instrumental in technical advancements, such as the use of silicon in electronics due to its semiconductor properties. Thus, the periodic table encapsulates the core principles bridging chemistry and physics.
A 2-ft-thick block constructed of wood (sg = 0.6) is submerged in oil (sg = 0.8), and has a 2-ft-thick aluminum (specific weight = 168 lb/ft3) plate attached to the bottom as indicated in fig. p2.146. (a) determine completely the force required to hold the block in the position shown. (b) loca
Final answer:
The behavior (rising or falling) of a wooden block in oil based on buoyancy and calculating the wood's density, which is found to be 600 kg/m³ based on its specific gravity.
Explanation:
Applying Archimedes' principle, which states that the buoyant force on a submerged object is equal to the weight of the fluid displaced by the object, can solve this problem. Since the block is submerged in oil with a specific gravity (sg) of 0.8, and has an attached aluminum plate, the overall density and buoyancy of the system are affected, leading to a complex calculation that incorporates the densities of the wood, aluminum, and oil.
The block will rise if its combined density (wood and aluminum) is less than that of the surrounding oil. Since wood has a lower specific gravity than oil, it tends to float, but the attached aluminum plate, with a specific weight of 168 lb/ft³, increases the system's density. Whether it rises or falls will depend on the overall density compared to the oil's density.
The density of the wood can be derived from its specific gravity. The specific gravity is the ratio of the density of the wood to the density of water (1000 kg/m³). Therefore, a specific gravity of 0.6 indicates the wood's density is 600 kg/m³.
A karate expert breaks a stack of bricks with his bare hand. If the force applied is 520 newtons and the impact time is 5.0 × 10-4 seconds, what is the value of impulse?
in rutherford's gold foil experiment what kind of particles in dense atomic nuclei caused some alpha particles to bounce straight back from the gold foil
Answer: POSITIVE
Explanation:
What element behaves MOST like magnesium?
Which of the following statements is true? 1 mL = 1 g 1 g = 1 oz 1 mL = 1 cm3 1 g = 1 cm
A high-speed flywheel in a motor is spinning at 500 rpm when a power failure suddenly occurs. the flywheel has mass 40.0 kg and diameter 76.0 cm . the power is off for 35.0 s and during this time the flywheel slows due to friction in its axle bearings. during the time the power is off, the flywheel makes 180 complete revolutions.
A car, initially at rest, travels 20 m in 4 s along a straight line with constant acceleration. the acceleration of the car is:
Final answer:
To find the car's constant acceleration, we use the formula s = ½at², substituted with the given values to calculate the acceleration, which is found to be 2.5 m/s².
Explanation:
The question involves finding the constant acceleration of a car that starts from rest and travels 20 m in 4 s along a straight line. To find the acceleration, we can use the formula for motion under uniform acceleration, s = ut + ½at², where s is the distance covered, u is the initial velocity, t is the time, and a is the acceleration. Given that the car starts from rest, u is 0, which simplifies the formula to s = ½at².
Rearranging the formula to solve for acceleration (a), we get a = 2s/t². Plugging in the values, a = 2*20/4² = 2.5 m/s². Therefore, the acceleration of the car is 2.5 m/s².
Which best describes the energy used to pluck guitar strings to make sound?
As he is catching a 2.5 kg package, your friend exerts a downward force of 1.0x10^1 N. If the package was still moving upwards at 6.7 m/s at the start of his catch, how much time will it take to bring him to a stop?
F = ma
A = F / m = 1 x 10^1 + (2.5) (9.3) / 2.5 = 1 x 10^1 + 24.5 /2.5 = 34.5 / 2.5 = 13.8 m/s^2
By using kinematic equation, V = 4 + ak
0 = 6.7 – 13.8 t
13.8t = 6.7
T = 6.7 / 13.8 = 0.4855 sec
A boat has a mass of 6800 kg. its engines generate a drive force of 4100 n, due west, while the wind exerts a force of 830 n, due east, and the water exerts a resistive force of 1200 n due east. what is the magnitude and direction of the boat's acceleration?
A boat has a mass of 6800 kg. its engines generate a drive force of 4100 n, due west, while the wind exerts a force of 830 n, due east, and the water exerts a resistive force of 1200 n due east, the boat's acceleration is approximately [tex]\(0.301 \, \text{m/s}^2\)[/tex] due west.
Newton's second rule of motion, which states that the net force exerted on an object is equal to the product of its mass and acceleration, can be used to determine the boat's acceleration:
[tex]\[F_{\text{net}} = m \cdot a\][/tex]
Given:
Mass (m) = 6800 kg
Engine force ([tex]\(F_{\text{engine}}\)[/tex]) = 4100 N (due west)
Wind force ([tex]\(F_{\text{wind}}\)[/tex]) = 830 N (due east)
Water resistive force ([tex]\(F_{\text{water}}\)[/tex]) = 1200 N (due east)
Net force ([tex]\(F_{\text{net}}\)[/tex]) is the vector sum of all the forces acting on the boat:
[tex]\[F_{\text{net}} = F_{\text{engine}} + F_{\text{wind}} + F_{\text{water}}\][/tex]
Convert the eastward forces to negative values since they are acting in the opposite direction:
[tex]\[F_{\text{net}} = 4100 \, \text{N} - 830 \, \text{N} - 1200 \, \text{N}\][/tex]
Calculate [tex]\(F_{\text{net}}\)[/tex]:
[tex]\[F_{\text{net}} = 2050 \, \text{N}\][/tex]
Now we can use Newton's second law to find the acceleration (a):
[tex]\[F_{\text{net}} = m \cdot a\][/tex]
[tex]\[a = \dfrac{F_{\text{net}}}{m}\][/tex]
Plug in the values:
[tex]\[a = \dfrac{2050 \, \text{N}}{6800 \, \text{kg}}\][/tex]
Calculate the magnitude of the acceleration:
[tex]\[a \approx 0.301 \, \text{m/s}^2\][/tex]
Thus, the boat's acceleration is approximately [tex]\(0.301 \, \text{m/s}^2\)[/tex] due west.
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The magnitude of the boat's acceleration is approximately 0.304 m/s² towards the west.
Explanation:To find the magnitude and direction of the boat's acceleration, we need to consider the net force acting on the boat. The net force is equal to the sum of all the forces acting on the boat. In this case, we have a drive force of 4100 N due west, a wind force of 830 N due east, and a resistive force of 1200 N due east. Using Newton's second law, we can calculate the net force:
Net force = (4100 N) - (830 N + 1200 N) = 4100 N - 2030 N = 2070 N
The acceleration of the boat can be calculated using the formula:
Acceleration = Net force / Mass = 2070 N / 6800 kg ≈ 0.304 m/s²
The magnitude of the boat's acceleration is approximately 0.304 m/s² and the direction is towards the west.
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which of the following statements is false about the distances between planets earth and the sun
Answer;
The distance from the sun to Neptune is about the same as the distance from Neptune to the next closest star, Proxima Centauri
Explanation;
When a planet like earth is closer to the sun the heat of the sunlight warms the surface of the planet hence,a planet like Neptune is far away from sun, the sunlight can't reach the planet and it's surface becomes cold so,the distance of the sun and planet is the main factor effecting the temperature.
This is when minerals break on specific planes.
What is the current widely accepted theory about global climate change and what are some predictions associated with it?
The widely accepted theory about global climate change is :
The formation of CO₂ by carbon and oxygen Formation of CO₂The formation of CO₂ by the mixture of carbon and oxygen is a widely accepted theory because of its effect on global climate change. the predictions regarding this theory includes some positives and negatives.
some of the positive predictions is :
Improved growth of crops because plants absorb C0₂ during photosynthesissome negative predictions include
Rising sea levelsspread of carbon related diseasesHence we can conclude that The widely accepted theory about global climate change is The formation of CO₂ by carbon and oxygen.
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what occurs when a swimmer pushes through the water to swim?
A baseball (m=145g) traveling 40 m/s moves a fielder's glove backward 27 cm when the ball is caught. part a what was the average force exerted by the ball on the glove? express your answer to two significant figures and include the appropriate units.
Final answer:
The average force exerted by the ball on the glove is approximately 857 N.
Explanation:
To calculate the average force exerted by the ball on the glove, we can use the equation:
F = m × Δv / Δt
where F is the average force, m is the mass of the ball, Δv is the change in velocity, and Δt is the time taken.
In this case, the mass of the ball is given as 145g, which is equal to 0.145 kg. The change in velocity of the ball is given as 40 m/s, since it travels from an initial speed of 40 m/s to a final speed of 0 m/s when caught. The time taken is calculated by converting the distance the glove moves to meters (27 cm = 0.27 m) and dividing it by the final speed of the ball. Therefore, Δt = 0.27 m / 40 m/s = 0.00675 s.
Now we can substitute the given values into the formula to find the average force:
F = (0.145 kg × 40 m/s) / 0.00675 s ≈ 857 N
Therefore, the average force exerted by the ball on the glove is approximately 857 N.
What is the instantaneous acceleration of the object at time = 9.5 seconds?
−20 m/s2
0 m/s2
20 m/s2
−10 m/s2