What are volume and density? How do they relate to each other?
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Density= It is the mass divided by the volume. Density is defined as the mass per unit volume.
Volume= the quantity of three-dimensional space enclosed by a closed surface, for example, the space that a substance (solid, liquid, gas, or plasma) or shape occupies or contains.
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Density expresses the proportional relationship between mass and volume of the substance. If the density of a particular substance is given in grams per milliliter, it indicates the number of grams present in 1 milliliter of that substance.
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What happens to the frequency of a wave if its energy increases?
The wavelength decreases as the frequency increases.
Explanation:The wavelength λ is the distance between successive peaks in a wave.
The frequency f of a wave is the number of complete waves that pass a point in a given time.
Answer: The frequency of a wave will increase.
Explanation:
The relation between the energy and the frequency is as follows;
[tex]E=h\nu[/tex]
Here, h is the planck's constant and [tex]\nu[/tex] is the frequency of the wave.
The energy of the wave is directly proportional to the frequency of the wave. The frequency is inversely proportional to the wavelength. If the energy of the wave increases then the wavelength of the wave decreases.
If the energy of the wave increases then the frequency of the wave will increase.
A 1100-kg car pulls a boat on a trailer. (a) what total force resists the motion of the car, boat, and trailer, if the car exerts a 1900-n force on the road and produces an acceleration of 0.550 m/s2 ? the mass of the boat plus trailer is 700 kg. (b) what is the force in the hitch between the car and the trailer if 80% of the resisting forces are experienced by the boat and trailer?
The total resistive force against the car, boat, and trailer is 910 N. The force experienced in the hitch between the car and the trailer is 728 N.
Explanation:This is a classic problem that involves applying Newton's second law and the concept of net force. Newton's second law states that Force = mass * acceleration. Let's begin with the first part of the question.
Given that the car has a mass of 1100 kg and it accelerates at 0.550 m/s2, and uses a force of 1900 N, we realize that this force is not just accelerating the car, but also overcoming some resistance. The total force exerted by the car is the sum of the force to overcome the resistance and the force to accelerate both the car and the trailer. We calculate this total force as follows:
Force_moving = (Mass_car + Mass_trailer) * Acceleration
Force_moving = (1100 kg + 700 kg) * 0.550 m/s2
Force_moving = 990 N
The resistive force then is the difference between the force the car exerts on the road and the force needed to move: Force_resistance = Force_exerted – Force_moving = 1900 N – 990 N = 910 N
In the second part of the question, we’re asked to figure out the force in the hitch between the car and the trailer, if 80% of the resisting forces are experienced by the boat and trailer. We simply take 80% of the resisting force:
Force_hitch = 0.80 * Force_resistance = 0.80 * 910 N = 728 N
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The total resisting force to the motion of the car, boat, and trailer is 910N. The force in the hitch between the car and the trailer, experiencing 80% of the resisting force, is 728N.
Explanation:The subject of this question pertains to Newton's Second Law of Motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
(a) We can use this equation to calculate the total a total force that resists the motion of the car, boat, and trailer: F = ma. Here, F is the net force, m is the total mass (car + boat + trailer), and a is the acceleration. Plugging in the given values (F = (1100kg + 700kg) * 0.550m/s²), we find the net force is 990 N. Since the car is exerting a force of 1900 N, the force resisting the motion can be found by subtracting this net force from the force exerted by the car (1900N - 990N), which gives 910 N.
(b) If 80% of the resisting forces are experienced by the boat and trailer, then the force on the hitch would be 80% of the total resisting force, i.e., 0.8 * 910 N = 728 N.
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A rocket experiences a constant force even as the amount of fuel in its fuel tanks decreases. What happens to the acceleration of the rocket as it runs out of fuel?
A - The acceleration decreases because the mass increases.B - The acceleration increases because the mass increases.C - The acceleration decreases because the mass decreases.D - The acceleration increases because the mass decreases.
We can answer this question by looking at Newton's second law:
[tex]F=ma[/tex]
which can be rewritten as
[tex]a=\frac{F}{m}[/tex]
where F is the force experienced by the rocket, m is its mass, a is its acceleration. In the rocket's case, the mass of the rocket decreases (because the fuel in the tank decreases), while the force remains constant, so the ratio F/m increases, and therefore the acceleration of the rocket increases.
Therefore, the correct answer is
D - The acceleration increases because the mass decreases.
why is the scatterplot the most commonly used type of graph in science?
What is the wavelength of an earthquake wave if it has a speed of 5 km/s and a frequency of 11 Hz?
A wheel with radius 0.487 m rotates 5.75 times every second. find the period of this motion.
To find the period of a wheel that rotates 5.75 times per second, use the formula T = 1/f, resulting in a period of 0.174 seconds.
Explanation:To find the period of the motion for a wheel that rotates 5.75 times every second, we can use the relationship between frequency (f) and period (T). The frequency is the number of revolutions per second, which we're given as 5.75 revolutions per second. The period is the time it takes to complete one revolution. The formula that relates frequency and period is T = 1/f.
Plugging in the given frequency:
T = 1/5.75
Calculating this gives us:
T = 0.174 s
Therefore, the period of this motion, which is the time it takes the wheel to make one complete revolution, is 0.174 seconds.
The cold virus causes disease when it enters the _____ of the human body.
The cold virus causes disease when it enters the mucous membranes of the human body such as the nasal cavity.
The cold virus causes disease when it enters the mucous membranes of the human body, particularly the nasal cavity. The most common groups of cold viruses include rhinoviruses, coronaviruses, and adenoviruses. These viruses are transmitted through direct contact such as shaking hands, and droplet transmission which occurs when an infected person coughs or sneezes. The rhinoviruses in particular thrive in cooler temperatures found in the nasal passages, leading to symptoms such as runny nose, congestion, and sneezing.
Symptoms of a cold are a result of the body's inflammatory response to the viral infection. This response generates the typical signs of a cold, but the condition is usually self-limiting and resolves on its own within 1-2 weeks.
Starting from rest, a ball of mass 2 kg experiences a constant force of 8 n. what is the final kinetic energy (in j) of the ball after it has traveled a distance of 8 m?
A ball is starting from the rest and has a mass of 2 kg, then the final kinetic energy of the ball that travelled to a distance of 8 m is 144.
What is Kinetic energy?An item or particle's motion gives it kinetic energy, which it might use to move. By exerting a net force on an item, work is done, which transfers energy; as a result, the object accelerates and obtains kinetic energy.
A moving item or particle's ability to move depends on both its mass and velocity. This is known as kinetic energy.
[tex]Force= Mass * Acceleration[/tex]
a=F/m
= 8 N / 2 kg= 4m/s²
Now find the final velocity,
[tex]v_f^2[/tex] = [tex]V_i[/tex]²+2ad
= 0²+(2) × (4) × (18) = 144
[tex]v_f^2[/tex] = √144
[tex]v_f[/tex] = 12
Now find the kinetic energy of the ball,
KE = 1/2 mv²
KE= (0.5) × (2) × (12)²
KE = 144
Therefore, the kinetic energy of the ball is 144.
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A coin completes 18 spins in 12 seconds. The centripetal acceleration of the edge of the coin is 2.2 m/s2. The radius of the coin is m.
Answer:
2.5 cm
Explanation:
Number of spins in 12 seconds = 18
Number of spins in 1 second = 18 / 12 = 1.5
Number of spins in one second is called frequency.
f = 1.5 rps
ac = 2.2 m/s^2
Let r be the radius of coin
Centripetal acceleration, ac = r x w^2
2.2 = r x ( 2 x 3.14 x 1.5) ^2
2.2 = r x 88.7364
r = 0.025 m = 2.5 cm
Answer: 0.025 m or 2.5m
Explanation:
The number of spins given in 12 seconds = 18
So the number of spins in 1 second will be
= 18 / 12 = 1.5rps
The above result is the frequency because it is the number of spins in one second
Let f be frequency
f = 1.5 rps
Using centripetal acceleration given
Ca = 2.2 m/s^2
m is the radius of the given coin
Using the formula
Centripetal acceleration, = m x w^2
Knowing that w = 2πf
2.2 = m x ( 2 x 3.14 x 1.5) ^2
2.2 = m x 88.7364
m = 0.025 m
All of the following are properties of metals except: Question 1 options: malleable ductile luster brittle
A brick is dropped from rest from the top of a building through air (air resistance is present) to the ground below. how does the brick's kinetic energy just before reaching the ground compare with the gravitational potential energy at the top of the building? set zero height at the ground level. the comparison cannot be made since the information of air resistance is not given. kinetic energy just before reaching the ground < gravitational potential energy at the top of the building kinetic energy just before reaching the ground = gravitational potential energy at the top of the building kinetic energy just before reaching the ground > gravitational potential energy at the top of the building
The correct answer is kinetic energy just before reaching the
ground < gravitational potential energy at the top of the building.
We have,
In the absence of air resistance, when the brick is dropped from rest, it will convert all its initial potential energy (due to its height above the ground) into kinetic energy as it accelerates downward.
However, with air resistance present, some of the initial potential energy is converted into other forms of energy, such as heat, due to the work done by air resistance.
As a result, the brick's kinetic energy just before reaching the ground will be less than the gravitational potential energy it had at the top of the building.
Thus,
kinetic energy just before reaching the ground < gravitational potential energy at the top of the building.
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The kinetic energy of the brick just before reaching the ground is greater than the gravitational potential energy at the top of the building.
Explanation:The kinetic energy of the brick just before reaching the ground is greater than the gravitational potential energy at the top of the building.
When the brick is dropped from rest, it starts accelerating due to the force of gravity. As it falls, the brick's gravitational potential energy is converted into kinetic energy, increasing its speed. The brick's kinetic energy just before reaching the ground is at its maximum, while its gravitational potential energy at the top of the building is at its minimum. Therefore, the comparison is such that the kinetic energy just before reaching the ground > gravitational potential energy at the top of the building.
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A wire is wrapped around a piece of iron, and then electricity is run through the wire. What happens to the iron?
A roller coaster car rapidly picks up speed as it rollsdown a slope. As it starts down the slope its speed is 4m/s. But 3 seconds later, at the bottom of the slope, its speed is 22m/s. What is its average acceleration?
A coin dropped from the top of a precipice takes 5.00 s to hit the ground. How high is the precipice?
A) 49.1 m
B) 245 m
C) 123 m
D) 25.5 m
what is the main difference between protons and neutrons
Answer: charges
Explanation: protons are positively charged while neutrons have no charge at all
A statement that can be proven by observation or measurement is known as a(n): a. opinion b. value c. fact d. belief Please select the best answer from the choices provided
A statement that can be proven by observation or measurement is known as a fact , therefore the correct answer is option C
what is the scientific investigation?Scientific investigation is the process of looking for answers by doing extensive research and finding the answers through experimental results.
The scientific investigation very much relies on true experimental results that can be supported by evidence.
A scientific fact, also known as empirical evidence, is the outcome of persistent, meticulous observation or measurement by experimentation or another method. The development of scientific hypotheses depends on these.
Theories and facts are two distinct concepts. Facts, which can be observed and/or evaluated, and theories, which are scientists' justifications and assessments of the facts, are clearly distinguished in the scientific method.
Thus, a statement that can be proven by observation or measurement is known as a fact , therefore the correct answer is option C
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What is the function of a diaphragm in a film camera
Why is it misleading to describe atmospheric pressure as simply the weight of the air only pressing down on a surface?
With your hand parallel to the floor and your palm upright, you raise a 3-kg book upward with an acceleration of 2 m/s2. what is the magnitude of force that your hand exerts on the book while it is accelerating?
Answer:
35 N
Explanation:
We are using Newton's law of motion.
Here is what we know:
(T-w)= ma
w = 3 kg (we will change to Newtons in a second)
a = 2m/s^2
rearrange equation to solve for T (tension)
T = ma+w
all we need is mass
Now to get the correct mass we need to divide its weight by the gravitational field strength(in our case it is just gravity) but first we want our weight of 3kg to be in Newtons.
1 kg = 9.81 N
w = (3)(9.81) = 29.4N
Now that our weight is 29.4N we need to divide that by gravity.
m = [tex]\frac{29.4}{9.8}[/tex]
Now that we have mass we can plug in our numbers
[tex](\frac{29.4}{9.8}*2)+29.4 = 35.4N[/tex]
Plugging that into our calculator gives us the answer 35.4 or 35 N
(feel free to correct me if my reasonings for any of this stuff is incorrect)
The magnitude of force that your hand exerted on the book while it accelerates is 35.4 N.
The given parameters;
mass of the book, m = 3 kgacceleration of the book, a = 2 m/s²The magnitude of force that your hand exerted on the book while it accelerates is the tension on your hand.
The tension on your hand while the book accelerates is calculated using Newton's second law of motion;
F = ma
T = ma + w
T = ma + mg
T = m(a + g)
T = 3(2 + 9.8)
T = 35.4 N
Thus, the magnitude of force that your hand exerted on the book while it accelerates is 35.4 N.
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A dog sledding team is comprised of a 80.0 kg musher (the person driving the sled), a 21.0 kg sled and four dogs. assume each dog\'s pull is fully transmitted to the sled, applied parallel to the ground and the sled travels along level ground. how much power does each dog supply to pull the sled/driver system at a constant speed of 8.80 m/s where the coefficient of friction between the sled and the snow is 0.150? (the acceleration due to gravity is 9.81 m/s2.)
To find the force in the coupling between the dogs and the sled, use the equation F = ma where F is the force and m is the total mass. For the power supplied by each dog, calculate P = Fv where P is power, F is force, and v is velocity.
Explanation:The magnitude of the force in the coupling between the dogs and the sled: To calculate the force in the coupling, you can use the equation F = ma, where m is the total mass of the sled and rider, and a is the acceleration of the system. By using the force exerted by each dog and the acceleration calculated from that force, you can determine the force in the coupling. Power supplied by each dog: Power is defined as P = Fv, where F is the force applied and v is the velocity. Calculate the total force applied by all four dogs and the velocity of the sled, then use this information to determine the power supplied by each dog.
Two masses m1 = 5.40 kg and m2 which has a mass 80.0% that of m1, are attached to a cord of negligible mass which passes over a frictionless pulley also of negligible mass. If m1 and m2 start from rest, after they have each traveled a distance h = 2.00 m, use energy content to determine the following.
(a) speed v of the masses
To determine the speed of the masses after traveling a distance of 2.00 m, we can use the principle of conservation of energy.
Explanation:To determine the speed of the masses after traveling a distance of 2.00 m, we can use the principle of conservation of energy. The initial potential energy of the system is equal to the final kinetic energy. The potential energy is given by m1gh, where g is the acceleration due to gravity and h is the distance traveled. The kinetic energy is given by (1/2)m1v^2 + (1/2)m2v^2, where v is the speed of the masses.
Given that m2 has a mass of 80.0% of m1, m2 = 0.80 * m1. Plugging this information into the equation and solving for v, we get:
v = √(2gh / (m1 + m2))
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What was his average swimming speed during the second half of the race if he tied the record, which was at an average speed of 2.05 m/s?
I believe this question has additional detail which stated that during the 1st half, his speed was 2.01 m/s. From this we can calculate his speed during the second half, v2, using the formula:
v_ave = (v1 + v2) / 2
2.05 m/s = (2.01 m/s + v2) / 2
v2 = 2.09 m/s
Identify the total number of protons and neutrons in the nucleus of the most common isotope of manganese
According to kinetic-molecular theory, if the temperature of a gas is raised from 100 °c to 200 °c, the average kinetic energy of the gas will ________.
Actually the Kinetic Energy, which is also known as the energy of motion is directly proportional to temperature. So the higher the temperature is, the faster the gas particles move so they have possess more kinetic energy.
This temperature is in absolute units so we convert to Kelvin:
200 C = 473.15 K
100 C = 373.15 K
So the amount increase is:
473.15 / 373.15 = 1.268
It will increase by a factor of 1.268 or 126.8%
The average kinetic energy of the gas will increase by a factor of 1.27
[tex]\texttt{ }[/tex]
Further explanationThe Ideal Gas Law that needs to be recalled is:
[tex]\large {\boxed {PV = nRT} }[/tex]
P = Pressure (Pa)
V = Volume (m³)
n = number of moles (moles)
R = Gas Constant (8.314 J/mol K)
T = Absolute Temperature (K)
Let us now tackle the problem !
[tex]\texttt{ }[/tex]
Given:
initial temperature of the gas = T₁ = 100°C = 373 K
final temperature of the gas = T₂ = 200°C = 473 K
Asked:
ratio of average kinetic energy of the gas = Ek₁ : Ek₂
Solution:
[tex]Ek_1 : Ek_2 = \frac{3}{2}kT_1 : \frac{3}{2}kT_2[/tex]
[tex]Ek_1 : Ek_2 = T_1 : T_2[/tex]
[tex]Ek_1 : Ek_2 = 373 : 473[/tex]
[tex]Ek_2 = \frac{473}{373} Ek_1[/tex]
[tex]Ek_2 \approx 1.27 \times Ek_1[/tex]
[tex]\texttt{ }[/tex]
Conclusion:The average kinetic energy of the gas will increase by a factor of 1.27 if the temperature of a gas is raised from 100°C to 200°C.
[tex]\texttt{ }[/tex]
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Answer detailsGrade: High School
Subject: Physics
Chapter: Pressure
Block b rests upon a smooth surface. if the coefficients of static and kinetic friction between a and b are μs = 0.4 and μk = 0.3, respectively, determine the acceleration of each block if p = 6 lb
Given
Weight of the block A, Wa = 20 lb, weight of block B Wb = 50 lb. Applied force to block A, P = 6lb, coefficient of static friction µs = 0.4, coefficient of kinetic friction µk = 0.3. If a force P is applied to the body, no relative motion will take place until the applied force is equal to the force of friction Ff, which is acting opposite to the direction of motion. Magnitude of static force of friction between block A and block B, Fs = µsN, where N is reaction force acting on block A. Now, resolve the forces Fx = max. P = (mA + mB)a,
6 = (20 / 32.2 + 50 / 32.2)a
2.173a = 6
A = 2.76 ft/s^2
To check slipping occurs between block A and block B, consider block A:
P – Ff = mAaA
6 – Ff = 1.71
Ff = 4.29 lb
And also,
N = wA. We know static friction,
Fs = µsN
Fs = 0.4 x 20
Fs = 8lb
Frictional force is less than static friction. Ff < Fs
Therefors, acceleration of block A, aA = 2.76 ft/s^2, acceleration of block B aB = 2.76 ft/s^2
Between blocks 'a' and 'b', the coefficients of friction come into play. If the force transmitted from block 'b' to 'a' is greater than the maximum static friction, block 'a' will move and its acceleration can be calculated.
Explanation:The smooth surface implies there is no friction between block 'b' and the surface. However, there is friction between blocks 'a' and 'b'. Hence, the given coefficients of static and kinetic friction, μs = 0.4 and μk = 0.3 would apply there. If the force 'p' was applied to block 'b', since there is no friction between 'b' and the surface, 'b' would move freely with acceleration a = F/m (F: applied force, m: mass of the block).
For block 'a', the acceleration would depend on whether the frictional force is able to resist the force being applied through block 'b'. The static friction is given by μs * N (N: Normal force - equal to the weight of block 'a' in this case), which has to be overcome to set the block motion. Once it starts moving, kinetic friction, given by μk * N, comes into effect. If the force transmitted from block 'b' to 'a' is greater than the maximum static friction, block 'a' will start to move and its acceleration can be calculated by subtracting the kinetic friction from the transmitted force and dividing by the mass of block 'a'.
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compare the bouyant force of water and the weight of a piece of wood that floats on the water
Describe the relationship of the Earth’s lithosphere to the asthenosphere.
The Earth's soft putty-like Asthenosphere carries the Lithosphere (which is like a giant jig-saw puzzle fit around the Earth), and the giant continents on its back.
Lithosphere floats on the top of Asthenosphere
Explanation:The earth crust is made up of tectonic plates and these tectonic plates are always in flow. Together the earths crust and mantle beneath it is called lithosphere. On the other hand the area beneath the mantle is called the asthenosphere. Actually lithosphere is solid in nature and asthenosphere is semi solid or liquid nature. The lithosphere floats on the asthenosphere.
Which structure is found in all EUKARYOTIC cells? Large central vacuole, Golgi apparatus, flagella, cilia
Answer:
Golgi apparatus.
Explanation:
during the first 50s a truck traveled at constant speed of 25m/s . Find the distance that it traveled
The truck, traveling at a constant speed of 25m/s for 50 seconds, covers a distance of 1250 meters.
Explanation:To calculate the distance the truck travels during the first 50 seconds at a constant speed, we can use the formula for distance based on speed and time:
Distance (d) = Speed (v) × Time (t)
Given that the truck's speed is 25m/s and the time is 50 seconds, we plug these values into the formula:
d = 25m/s × 50s
Upon multiplying, we find the main answer:
d = 1250 meters
Therefore, the truck traveled a total distance of 1250 meters in the first 50 seconds.