A mall distribution center processes as many as 150,000 pieces of mail each day. The mail is sent via ground and air. Each land carrier takes 2000 pieces per load and each air carrier 1500 pieces per load. The loading equipment is able to handle as many as 200 loads per day.

Let x be the number of loads by land carriers and y the number of loads by air carriers. Which system of inequalities represents the situation?

Options:
1500x+2000y>=150,000 x+y>=200
2000x+1500y>=150,000 x+y>=200
2000x+1500y<=150,000 x+y<=200
1500x+2000y<=150,000 x+y<=200 ...?

Option 2 - 8 x 1 = 8 is the correct alternative.

We have the options as mentioned in the question.

We have to determine which is an example of Identity Property of Multiplication.

The identity property of multiplication says that the product of 1 and any number is that number.

According to the question -

Using the Identity Property of Multiplication -

8 x 1 = 8

Hence, Option 2 is the correct alternative.

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Answer:  They work for 2.5 hours to gift wrap  65 boxes.

Step-by-step explanation:

Since we have given that

Number of boxes Jack can wrap = 28

Time taken by him = 2 hours

Number of boxes Walter can wrap = 36

Time taken by him = 3 hours

Work done by Jack in  1 hour is given by

[tex]\frac{2}{28}\\\\=\frac{1}{14}[/tex]

Work done by Walter in 1 hour is given by

[tex]\frac{3}{36}\\\\=\frac{1}{12}[/tex]

So, Work done by both Jack and Walter in 1 hour is given by

L.C.M. of [tex](\frac{1}{14},\frac{1}{12})[/tex] is [tex]=\frac{l.c.m.\ of \ numerator}{h.c.f\ of\ denominator}=\frac{1}{2}[/tex]

Number of units done by Jack is given by

[tex]\frac{\frac{1}{2}}{\frac{1}{14}}\\\\=\frac{14}{2}\\\\=7\ units[/tex]

Number of units done by Walter is given by

[tex]\frac{\frac{1}{2}}{\frac{1}{12}}\\\\=\frac{12}{2}\\\\=6\ units[/tex]

So, Let the number of hours be 't' .

[tex]7t+6t=\frac{1}{2}\times 65\\\\13t=\frac{1}{2}\times 65\\\\t=\frac{1}{2}\times \frac{65}{13}\\\\t=\frac{5}{2}\\\\t=2.5\ hours[/tex]

So, They work for 2.5 hours to gift wrap  65 boxes.

The Answer is B.

I took the unit review, as well as did the math myself,

Answer:

Step-by-step explanation:

A straight line can either have 1 y-intercept or infinitely many y intercepts. The only case in which there are infinitely many y-intercepts is when the line represents the y-axis itself. On y-axis, x is always 0. So the line that represents the y-axis is the line x=0. However, it is not a linear equation. In short, only the line representing y-axis has more than 1 y-intercepts. There cannot be such a linear equation(function).

A linear equation cannot have more than one y-intercept. Having multiple y-intercepts would violate the definition of a function as each input (x-value) should only be associated with one output (y-value). Therefore, a linear equation with multiple y-intercepts suggests an error.

In the field of mathematics, specifically in algebra and graphing, a linear equation cannot have more than one y-intercept. The y-intercept of a linear equation is the point at which the line crosses the y-axis on a coordinate plane. Linear equations are represented by the formula y = mx + b, where 'm' is the slope of the line and 'b' is the y-intercept. If an equation were to have more than one y-intercept, it would violate the definition of a function, which states that each input (or x-value) is only associated with one output (or y-value). Hence, if a linear equation was portrayed as having more than one y-intercept, it would imply an error in the equation or in the graph itself.

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This type of a discount is:

       A.   A sale

Sale--

A sale is a transaction between two parties one is a buyer and other is seller in which the goods or services are provided by the seller at a lower rate as compared to the normal price of it.

The price so lowered is known as a discounted price and the price at which the item is to be sold is known as a sale price.

Here the store is keeping the basketball shoes at a sale which is displayed on window as:

      "Basketball Shoes – 20% off."

            Hence, the correct option is: Option: A

                                A. A sale

Answer:the answer is the one given below, you need to use A=Pe^rt

Step-by-step explanation:

P= amount of money invested

r=interest rate percentage in decimal form

t=time in years

A=total money in account ️

Answer:

the answer is b.63

Step-by-step explanation:

Hello, I can help you with this

Step 1

to solve this you must divide the money Mr Smith has by the price of a stock per share, it is

Money Mr smith has = $200

The price of a stock is $3.17

[tex]\frac{200 usd}{3.17\frac{usd}{share} }\\ =63.09\ shares\\\\[/tex]

he cand by  whole shares, so he can buy exactly 63 shares

so, the answer is b.63

I really hope it helps, Have a great day.

The results of the expression are 8 2/7 ; 16.286 and 16 respectively.

Using the expression given :

Now we divide:

A.)

456 / 28 = 16 remainder 8

Now we have :

8 8/28

= 8 2/7

B.)

As a decimal :

456 / 28

= 16.286

C.)

Rounded to the nearest whole number:

456 / 28

= 16.286

≈ 16

Final answer:

To divide 456 by 28: as a mixed number is 16 2/7, as a decimal rounded to two places is 16.29, and to the nearest whole number is 16.

Explanation:

To divide 456 by 28, we start by performing the division to find the quotient and the remainder. Firstly, 456 divided by 28 equals 16 with a remainder of 8.

Answering the three parts:

The information provided seems to be examples of rounding and significant figures from various arithmetic operations but does not directly relate to the division of 456 by 28, which is our primary focus. Please note that while rounding to the nearest whole number or to two decimal places, it's important to correctly evaluate the quotient that the specific calculation yields.

Final answer:

To express[tex]\(\sqrt{x^3}\)[/tex] as a fractional exponent, it is rewritten as[tex]\(x^{\frac{3}{2}}\),[/tex] correlating the square root operation to the power of \[tex](\frac{1}{2}\)[/tex]and multiplying by the exponent 3.

Explanation:

To change the radical[tex]\(\sqrt{x^3}\)[/tex]to an algebraic expression with fractional exponents, we can use the property that any root can be expressed as a power with a fractional exponent. The square root of a variable to some power can be represented by raising the variable to the power of half the original exponent.

In this case,[tex]\(\sqrt{x^3}\)[/tex]can be written as [tex]\(x^{\frac{3}{2}}\).[/tex] This is because the square root operation is equivalent to raising to the power of[tex]\(\frac{1}{2}\),[/tex] and when we multiply the exponents [tex]\(3 \times \frac{1}{2}\),[/tex] we get[tex]\(\frac{3}{2}\).[/tex]