A good baseball pitcher can throw a baseball toward home plate at 93 mi/h with a spin of 1510 rev/min. How many revolutions does the baseball make on its way to home plate? For simplicity, assume that the 60 ft path is a straight line.

Explanation:

Below is an attachment containing the solution.

The distance covered by a freely falling object in a certain time is calculated by the formula d = 1/2 * g * t^2 where d is the distance, g is acceleration due to gravity and t is time. When plugging in the values g = 32 ft/sec^2 and t = 5 sec, we find that the object would have fallen 400 ft in the first 5 seconds.

In physics, the distance that a free-falling object covers is given by the formula d = 1/2 * g * t^2, where g is the acceleration due to gravity. In typical physics problems, g is approximated as 32 feet/second^2 on Earth. If we plug t = 5 sec into the equation, we get:

d = 1/2 * 32 ft/sec^2 * (5 sec)^2 = 400 ft.

Therefore, the object would have fallen 400 ft in the first 5 seconds of free fall.

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Answer:

W = 3.4x0³ J.

Explanation:

The work done by the man is given by the following equation:

[tex] W = F_{t}\cdot d [/tex]     (1)

where W: is the work, Ft is the total force and d: is the displacement = 4.25 m.  

We need to find first the total force Ft, which is:

[tex] Ft = Fm + W [/tex]

where Fm: is the force exerted by the man = 535 N, W: is the weight = m*g*sin(θ), m: is the mass of the man, g: is the gravitational acceleration = 9.81 m/s², and θ: is the angle = 20.0°.  

[tex] F_{t} = Fm + W = 500 N + 90.0 kg*9.81 m/s^{2} * sin(20.0) = 802.0 N [/tex]

Hence, the work is:

[tex] W = 802.0 N \cdot 4.25 m = 3.4 \cdot 10 ^{3} J [/tex]  

Therefore, the work done by the man is 3.4x10³ J.  

I hope it helps you!      

Answer:

Carrier Wave

Explanation:

A carrier wave is described or known as the continuous electromagnetic radiation, of constant amplitude and frequency, which is being given out or released by a transmitter. It is modulated in direct proportion to the signal,that is voice or music, which is meant to be transmitted or broadcasted.

It is mostly used for the transmission of information such as speech and music which can be seen in radio communication.

Answer:

C. It decreases

Explanation:

The pressure law states that for a constant volume of gas in a sealed container the temperature of the gas is directly proportional to its pressure. This can be easily understood by visualizing the particles of gas in the container moving with a greater energy when the temperature is increased.

A common example is cooking gas when refilled, there is a perceptible change in the temperature of the cylinder.

Answer:

Using lighter material in car construction, improving energy efficiency by enhancing engine design or replacing the engine with more efficient technologies.

Explanation:

Using lighter materials in the car construction, reducing the potential energy required to accelerate and to move the car, as well as energy losses due to rolling friction. There is evidence of such benefits by replacing steel and aluminium parts with components made of composite materials.  

Improving the design of internal combustion engines to minimize energy losses and accordingly, improving energy efficiency. A more radical approach is replacing internal combustion engines with electric engines, which offer higher efficiencies. Such conclusions can be easily inferred from model based on Work-Energy Theorem and Principle of Energy Conservation:

[tex]\eta_{engine} \cdot U_{engine} = \frac{1}{2} \cdot m_{car} \cdot v^{2} + \mu_{r} \cdot m_{car} \cdot g \cdot \Delta s[/tex]

Answer:

qa/qb = 0.3125

Explanation:

Let the distance of the point from first charge (qa) be ra.

Likewise, let the distance of the point from the second charge (qb) be ra

Now, from the question, ra=0.15m

While rb = 0.48m

Normally, we know that:

The electric potential due to a point charge, q, at a point located at a distance, r, away from it is given by the equation;

V = q/(4π(ϵo)r)

We know that 1/(4π(ϵo)) cam be said to ne K.

Therefore, V = Kq/r

Where K = 9 × 10^(9) V.m/C

Now, since from the question, the electric potential at the point is the same due to each of the charges, their electric potential will be the same, thus;

Va = Vb

So, (Kqa) / ra = (Kqb) / rb

This gives us; qa / ra = qb / rb

So rearranging, we get;

qa/qb = ra/rb = 0.15/0.48 = 0.3125

The ratio qB/qA of the charges is 3.2.

The electric potential owing to a point charge Q at a distance r from the charge is given as:

V = kQ / r

where k is the electrostatic constant.  

Since the potentials due to charges A and B are equal at the given spot, we can write:

VA = VB

Substituting the values:

kQA / 0.15 = kBQB / 0.48

Simplifying:

qB/qA = 0.48 / 0.15 = 3.2

Answer:

How much energy does it take to melt a 16.87 g ice cube? ΔHfus = 6.02 kJ/mol How much energy does it take to melt a 16.87 g ice cube? = 6.02 kJ/mol

A. 108 kJ

B. 102 kJ

C. 5.64 kJ

D. 936 kJ

E. none of the above

5.64 kJ

Explanation:

The Heat of fusion is the heat energy required to dissolve a given mass of ice at melting point.

The heat energy required to dissolve ice can be calculated using the expression below;

Q = ΔH[tex]_{f}[/tex] x m ...............................................1

where Q is the heat energy required;

           ΔH[tex]_{f}[/tex]  is the heat of fusion for ice;

           m is the mole

All the parameters above are provided in the question except m, so to get m we use the molar mass of water (also for ice) which is 18.01528 g/mol .

This means that 18.01528 g of ice is contained in one mole, therefore the mole for 16.87 g of ice is given as;

[tex]m = \frac{16.87g}{18.015g/mol}[/tex]

m = 0.9364 mole of ices

Now the parameters are complete, we are given;

ΔH[tex]_{f}[/tex]  = 6.02 kJ/mol

m = 0.9364 mol

Q =?

Substituting into equation 1, we have

Q =  6.02 kJ/mol x 0.9364 mol

Q = 5.64 kJ

Therefore, the energy required to melt 16.87 g of ice is 5.64 kJ

The energy required to melt a 16.87 g ice cube can be calculated by first converting the mass to moles and then multiplying by the enthalpy of fusion. The calculated energy is 5.64 kJ.

The amount of energy required to melt an ice cube can be calculated using the enthalpy of fusion, which is given as 6.02 kJ/mol for ice. In order to make the conversion, we need to convert the mass of the ice cube from grams to moles. Since the molecular weight of water is approximately 18.015 g/mol, the 16.87 g ice cube amounts to 0.937 mol of ice. We then multiply this amount by the enthalpy of fusion to obtain the required energy. Thus, Energy = (0.937 mol) * (6.02 kJ/mol) = 5.64 kJ. Therefore, it would take about 5.64 kJ of energy to melt the 16.87 g ice cube.

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Answer:

He will need to support the joint above and below the deformity, this will allow the xray to be taken without generating more damage to the child.

I hope you find this information useful and interesting! Good luck!

Answer:

a. the work done by the gravitational force on Block A is less than the work done by the gravitational force on Block B.

b. the speed of Block A is equal to the speed of Block B.

c. the momentum of Block A is less than the momentum of Block B.

Explanation:

a. The  work done by the gravitational force is equal to:

w = m*g*h

where m is mass, g is the standard gravitational acceleration and h is height. Given that both blocks are released from rest at the same height, then, the bigger the mass, the bigger the work done.

b. With ramps frictionless, the final speed of the blocs is:

v = √(2*g*h)

which is independent of the mass of the blocks.

c. The momentum is calculated as follows:

momentum = m*v

Given that both bocks has the same speed, then, the bigger the mass, the bigger the momentum.

The work done by gravitational force on blocks A and B is equal as the work is independent of the path. Both blocks have the same speed when they reach the final height due to the conversion of potential energy into kinetic energy. However, the momentum of Block B is greater due to its larger mass.

This question is about the principles of work, energy and momentum in physics. Let's address each part of it:

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Answer:

38 m

Explanation:

Number of turns=N=100

Magnetic field=B=0.50 T

Frequency of the generator=f=60 Hz

Rms value of emf=[tex]E_{rms}=120 V[/tex]

We have to find the length of the wire from which the coil is made.

Peak value of emf=[tex]E_0=E_{rms}\sqrt 2=120\times \sqrt 2=169.7 V[/tex]

Length of wire=[tex]4\sqrt{\frac{NE_0}{2\pi fB}}[/tex]

Substitute the values

Length of wire=[tex]4\times \sqrt{\frac{169.7\times 100}{0.50\times 2\pi\times 60}}[/tex]

Length of wire=38 m

Hence, the length of wire from which the coil is made=38 m

To determine the length of wire in a generator coil with 100 turns in a 0.50-T field and 120 V rms at 60 Hz, one can use the formula for rms emf of a generator and solve for the area of one turn to find the length per turn and multiply by the number of turns.

The question is asking to determine the length of wire used to make a coil in a generator. The generator has 100 turns of wire, operates with a 0.50-T magnetic field, and has an rms value of the emf of 120 V with a 60.0 Hz frequency. Assuming the turns are squares, we can use the formula for the rms value of the emf (Erms) for a generator, which is Erms = NABωrms, where N is the number of turns, A is the area of the turn, B is the magnetic field, and ωrms is the rms angular velocity. The rms angular velocity ωrms is related to the frequency (f) by the equation ωrms = 2πf/√2.

To find the side length (L) of the square turns, we rearrange the formula to solve for A and then take the square root. Once we have L, we multiply by 4 to get the perimeter of one turn and then by 100 to find the total length of wire needed for all turns.

Answer:

a) [tex]I = 113.014\,kg\cdot m^{2}[/tex], b) [tex]m = 2075.556\,kg[/tex]

Explanation:

a) The turntable has the following physical model by using Newton's laws:

[tex]F \cdot R = I \cdot \alpha[/tex]

The moment of inertia is:

[tex]I = \frac{F\cdot R}{\alpha}[/tex]

[tex]I = \frac{(300\,N)\cdot(0.33\,m)}{0.876\,\frac{rad}{s^{2}} }[/tex]

[tex]I = 113.014\,kg\cdot m^{2}[/tex]

b) The moment of inertia for a solid cylinder:

[tex]I = \frac{1}{2}\cdot m \cdot R^{2}[/tex]

The mass of the turntable is:

[tex]m = \frac{2 \cdot I}{R^{2}}[/tex]

[tex]m = \frac{(2)\cdot (113.014\,kg\cdot m^{2})}{(0.33\,m)^{2}}[/tex]

[tex]m = 2075.556\,kg[/tex]

Answer:

Explanation:

Given that

Beam current (i)=23.3µA

And the time to strike(t)=28s

Also, a fundamental charge e=1.602×10^-19C

Then, the charge quantity is given as,

q=it

Then, q=23.3×10^-6×28

q=6.524×10^-4C

Also, the number of electron N is given as

q=Ne

Therefore, N=q/e

So, N=6.524×10-4/1.602×10^-19

N=4.072×10^15

There are 4.072×10^15 electrons strike the tube screen every 28 s.

When The fundamental charge is 1.602 × 10−19 C So, There are [tex]4.072\times 10\wedge 15[/tex] electrons that strike the tube screen every 28 s.

Given that information as per the question

Beam current (i) is =23.3µA

And also the time to strike(t)=28s

Also, a fundamental charge e=[tex]1.602\times10\wedge -19C[/tex]

Then, the charge quantity is given as,

q is =it

Then, q=[tex]23.3\times 10\wedge-6×28[/tex]

q is =[tex]6.524\times10\wedge -4C[/tex]

Also, When the number of electron N is given as

Now, q=Ne

Therefore, N is =q/e

So, N is = [tex]6.524\times10-4/1.602\times10\wedge-19[/tex]

N is = [tex]4.072\times 10\wedge 15[/tex]

Therefore, There are [tex]4.072\times 10\wedge 15[/tex] electrons that strike the tube screen every 28 s.

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Answer:

349 m

Explanation:

Parameters given:

Mass of climber, m = 92.6 kg

Amount of food calories = 735

1 food calorie = 103 calories

735 food calories = 75705 calories

1 joule is equal to 0.239 calories. Therefore, 75705 calories will be 316749.72 joules.

Hence, this is the amount of work the climber must do work off the food he ate.

Work done is given as:

W = Force * distance

W = m * g * h

h = W/(m * g)

h = 316749.72/(92.6 * 9.8)

h = 349 m

Answer:

The bucket was the dropped from 56 th floor.

Explanation:

Given that,

Height of floor = 4.9 m

Height of 14 floor = 68.6 m

Time taken = 1 sec

We need to calculate the speed of the bucket

Using equation of motion

[tex]s=ut+\dfrac{1}{2}gt^2[/tex]

Put the value into the formula

[tex]68.6=v\times1+\dfrac{1}{2}\times9.8\times(1)^2[/tex]

[tex]v=68.6-\dfrac{1}{2}\times9.8\times(1)^2[/tex]

[tex]v=63.7\ m/s[/tex]

We need to calculate the time

Using equation of motion

[tex]v=u+gt[/tex]

[tex]t=\dfrac{v}{g}[/tex]

Put the value into the formula

[tex]t=\dfrac{63.7}{9.8}[/tex]

[tex]t=6.5\ sec[/tex]

We need to calculate the distance

Using equation of motion

[tex]s=ut+\dfrac{1}{2}gt^2[/tex]

[tex]s=0+\dfrac{1}{2}gt^2[/tex]

Put the value into the formula

[tex]s=\dfrac{1}{2}\times9.8\times(6.5)^2[/tex]

[tex]s=207.025\ m[/tex]

We need to calculate the number of floor

[tex]n=\dfrac{s}{h_{f}}[/tex]

Put the value into the formula

[tex]n=\dfrac{207.025}{4.9}[/tex]

[tex]n=42.25\approx42[/tex]

The bucket was the dropped from

[tex]f=14+42= 56[/tex]

Hence, The bucket was the dropped from 56 th floor.

Answer:

D. When the dense, positive alpha particle passes close to a positive nucleus of gold, the alpha particle repels and hits the screen at point X.

Explanation:

D)When the dense, positive alpha particle passes close to a positive nucleus of gold, the alpha particle repels and hits the screen at point X.

The gold nucleus and alpha particle are both definitely charged therefore there is a repulsive pressure between the (gold) nucleus and the alpha particle. This causes the alpha particle to be deflected through a massive angle.

Maximum alpha debris surpassed instantly through the gold foil, which implied that atoms are ordinarily composed of open space. a few alpha particles had been deflected barely, suggesting interactions with different definitely charged particles in the atom.

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Answer:

Definitely Spinning permanent magnets within an array of fixed permanent magnets

Explanation:

Any relative motion between magnets (be they permanent or electromagnetic) and a coil of wire will induce an electric current in the coil.

What will not induce an electric current is the relative motion between the two coils of wire (because there is no change in magnetic field), or the relative motion between two magnets (there are no coils of wire to induce the current into).

Therefore, spinning permanent magnets within an array of fixed permanent magnets does not induce an electric current.

Answer:

Spinning permanent magnets within an array of fixed permanent magnets

Explanation:

Answer:

a. Rotational inertia: 5.21kgm²

b. Magnitude of it's angular momentum: 123.32kgm²/s

Explanation:

Length of the rod = 3.46m

Weight of the rod = 12.8 N

Angular velocity of the rod= 226 rev/min

a. Rotational Inertia (I) about its axis

The formula for rotational inertia =

I = (1/12×m×L²) + m × ( L ÷ 2)²

Where L = length of the rod

m = mass of the rod

Mass of the rod is calculated by dividing the weight of the rod with the acceleration due to gravity.

Acceleration due to gravity = 9.81m/s²

Mass of the rod = 12.8N/ 9.81m/s²

Mass of the rod = 1.305kg

Rotational Inertia =

(1/12× 1.305 × 3.46²)+ 1.305 ( 3.46÷2)²

Rotational Inertia =  1.3019115 + 3.9057345

Rotational Inertia = 5.207646kgm²

Approximately = 5.21kgm²

b. The magnitude of the rod's angular momentum about the rotational axis is calculated as

Rotational Inertia about its axis × angular speed of the rod.

Angular speed of the rod is calculated as= (Angular velocity of the rod × 2π)/60

= (226×2π) /60

= 23.67 rad/s

Rotational Inertia = 5.21kgm²

The magnitude of the rod's angular momentum about the rotational axis

= 5.21kgm²× 23.67 rad/s

= 123.3207kgm²/s

Approximately = 123.32kgm²/s

Answer:

a) Q = 80,000 cal

b) Q = 100,000 cal

c) Q = 540,000 cal

d) Q = 720,000 cal

Explanation:

a)1 kg from 0⁰ Ice to 0⁰ water, the heat produced is latent heat of fusion

[tex]Q_{l} = ML_{f}[/tex] = 1 * 80

[tex]Q_{l}[/tex] = 80 kCal = 80,000 cal

b) 1 kg of O°C ice water to 1 kg of 100°C boiling water

Specific heat capacity, c =  1000cal/kg.C

[tex]Q_{c} = mc \delta T\\Q_{c} = 1 * 1000 * (100 - 0)\\Q_{c} =100000 cal[/tex]

c) 1 kg of 100°C boiling water to 1 kg of 100°C steam

Latent heat of vaporization is needed for this conversion

[tex]Q_{v} = ML_{v} \\L_{v} = 540 kCal/kg\\Q_{v} =1* 540 \\Q_{v} = 540 kCal = 540000 cal[/tex]

d)  1 kg of O°C ice to 1 kg of 100°C steam.

Q = [tex]Q_{L} + Q_{c} + Q_{v}[/tex]

Q = 80,000 + 100,000 + 540,000

Q = 720,000 cal

Final answer:

To change 1 kg of ice at 0°C to water at 0°C, 80 kcal of energy is required. To change 1 kg of water at 0°C to boiling water at 100°C, 100 cal of energy is required. To change 1 kg of boiling water at 100°C to steam, 540 kcal of energy is required.

Explanation:

The quantity of heat required to change the phase of a substance is given by the equation Q = mL, where m is the mass of the substance and L is the heat of fusion or heat of vaporization. For example, to change 1 kg of ice at 0°C to water at 0°C, the energy required is Q = (1 kg)(80 kcal/kg) = 80 kcal. To change 1 kg of water at 0°C to boiling water at 100°C, the energy required is Q = (1 kg)(1 cal/g °C)(100°C) = 100 cal. To change 1 kg of boiling water at 100°C to steam, the energy required is Q = (1 kg)(540 kcal/kg) = 540 kcal.

Answer:

E) are almost circular, with low eccentricities.

Explanation:

Kepler's laws establish that:

All the planets revolve around the Sun in an elliptic orbit, with the Sun in one of the focus (Kepler's first law).

A planet describes equal areas in equal times (Kepler's second law).

The square of the period of a planet will be proportional to the cube of the semi-major axis of its orbit (Kepler's third law).

[tex]T^{2} = a^{3}[/tex]

Where T is the period of revolution and a is the semi-major axis.

Planets orbit around the Sun in an ellipse with the Sun in one of the focus. Because of that, it is not possible to the Sun to be at the center of the orbit, as the statement on option "C" says.

However, those orbits have low eccentricities (remember that an eccentricity = 0 corresponds to a circle)

In some moments of their orbit, planets will be closer to the Sun (known as perihelion). According with Kepler's second law to complete the same area in the same time, they have to speed up at their perihelion and slow down at their aphelion (point farther from the Sun in their orbit).

Therefore, option A and B can not be true.

In the celestial sphere, the path that the Sun moves in a period of a year is called ecliptic, and planets pass very closely to that path.  

Answer: Heat Energy

Explanation:

Heat is energy in its most disordered form. heat energy is the random jostling of molecules and is therefore not organized. As cells perform the chemical reactions that generate order within, some energy is inevitably lost in the form of heat. Because the cell is not an isolated system, the heat energy produced by the cell is quickly dispersed into the cell's surroundings where it increases the intensity of the thermal motions of nearby molecules. This increases the entropy of the cell's environment and keeps the cell from violating the second law of thermodynamics.

Answer: Separately derived system

Explanation: A separately derived system is used to describe a premise wiring system whose power is derived from a source of electrical energy such as transformer, solar photovoltaic cell or generator. A separately derived system has no direct connection to any conductor from another system or doesn't generate it's power from any direct connection to a conductor from another system or source except those from established from bonding or grounding connections. Separately derived systems usually generate it's power on it's own.

An isolated power system is isolated from other systems, using bonding or grounding for safety, and may include an isolation transformer. Electrical safety devices like circuit breakers or fuses prevent thermal hazards, and a three-wire system enhances both thermal and shock safety.

The student's question refers to an "isolated power system" which is a type of electrical distribution system. An isolated power system is unique because it is separated from other power systems. It has no direct connection with the circuit conductors of another system, with the exception of connections through bonding or grounding. This premise of design is intended to enhance safety, and it usually involves the use of an isolation transformer to prevent shock. Moreover, it avoids a sudden increase in the voltage that could disrupt the power supply.

Electrical safety devices, such as circuit breakers and fuses, are critical in such systems to interrupt excessive currents and prevent thermal hazards. The three-wire system, which is essential for safety in modern household and industrial wiring, utilizes live/hot, neutral, and earth/ground wires. The neutral wire and the case of any connected appliance are both grounded, which means they are connected to the earth to ensure they exist at zero volts, providing an alternative return path for the current through the earth, thereby guarding against thermal and shock hazards.

The electric field inside the hollowed insulator can be calculated considering the missing charge in the cylindrical hole. This electric field is uniform and its magnitude is E = ρ.b/ϵ0; where ρ is the uniform charge density and ϵ0 is the permittivity constant. The direction of the electric field is from the axis of the cylinder toward the hole for positive ρ and opposite for negative ρ.

The question refers to the electric field inside a hollowed cylindrical insulator. This is a physics problem related to the study of electrostatics. The concept of electric field refers to the influence exerted in the space around a charged object, which can result in forces on other charged objects.

We know the electric field inside a uniformly charged insulator is zero because charges move to the surface in an insulator. In this case, though, the insulator is not uniform; it has a cylindrical hole. So, we must calculate the contribution from the missing charge in the hole.

The electric field generated by the missing volume, dV, with charge density ρ is given by Coulomb's law, where the electric field corresponds to the charge divided by the square of the distance: E = k.Q/R^2.

Because the volume dV, at radius r from the axis of the cylinder has a charge equal to the volume of the cylindrical disk multiplied by ρ, we have dQ = ρ.dV and thus E = k.ρ.dV/R^2. Integrating over the total volume of the cylindrical hole, we find that the electric field is uniform and its magnitude, E, is given by E = ρ.b/ϵ0, where ϵ0 is the permittivity constant.

The direction of the E is from the axis of the cylinder towards the hole if ρ is positive, because positive charges repel, and vice versa if ρ is negative.

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To find the electric field inside the hole of the insulating cylinder, we use the superposition principle and Gauss's law, resulting in a uniform electric field due to the subtracted cylindrical charge distribution.

The question is asking for the magnitude and direction of the electric field inside a cylindrical hole bored inside another charged cylindrical insulator. To determine the electric field (ES) inside the hole, we apply the principle of superposition, which involves considering the charge distribution that would have been present had there been no hole and subtracting the charge distribution of a cylinder of radius a with charge density -ρ, placed such that it would carve out the hole.

Using Gauss's Law, the electric field due to the entire charged cylinder without the hole would be zero inside the cylinder. Therefore, the electric field inside the hole is solely due to the cylindrical charge distribution we subtracted. Since the cylindrical charge distribution is symmetric, the electric field ES within the hole will also be uniform and directed radially outward from the axis of the imaginary cylinder we subtracted. The magnitude of ES can be calculated using Gauss's Law and considering the symmetry of the problem.

Answer:

3.1216 m/s.

Explanation:

Given:

M1 = 0.153 kg

v1 = 0.7 m/s

M2 = 0.308 kg

v2 = -2.16 m/s

M1v1 + M2v2 = M1V1 + M2V2

0.153 × 0.7 + 0.308 × -2.16 = 0.153 × V1 + 0.308 × V2

= 0.1071 - 0.66528 = 0.153 × V1 + 0.308 × V2

0.153V1 + 0.308V2 = -0.55818. i

For the velocities,

v1 - v2 = -(V1 - V2)

0.7 - (-2.16) = -(V1 - V2)

-(V1 - V2) = 2.86

V2 - V1 = 2.86. ii

Solving equation i and ii simultaneously,

V1 = 3.1216 m/s

V2 = 0.2616 m/s

Answer:

Explanation:

When it was approaching, the wavelength is blue-shifted and the rest wavelength when it was receding the wavelength is redshifted.

Any planet is an extremely faint light source compared to its parent star. Comets are considered as the most primitive objects in the Solar System.

Using physics concepts of Ohm's law, resistance calculation, and electric field magnitude calculation, we can find the current in copper and silver sections, the electric field magnitudes, and the potential difference in silver section. The potential difference across the silver section will be the same as that applied across the entire wire due to copper's negligible resistance.

The student's question is related to electricity and magnetism, a branch of physics. In the scenario described, the resistance (R) of each wire section can be found using the formula R = ρL/A, where ρ is resistivity, L is length, and A is cross-sectional area. Here, resistivity needs to be known from Table 27.2.

Once the resistance of each wire section is known, Ohm's law (V = IR) can be used to find the current (I) in each section. The same current will flow in both sections of the wire since it is a series circuit. The potential difference across each section can then be calculated using Ohm's law.

The magnitude of the electric field E in each section can be calculated from E = V/d, where V is the potential difference across the section and d is its length.

The potential difference across the silver section is the same as the potential difference applied across the entire wire because the copper wire has negligible resistance compared to silver.

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Answer:

Total angle through which the wheel has turned 58.9s after it begins rotating is 1709.52 rad

Explanation:

The image attached would offer a better explanation

Answer:

The answer to the question is;

The total angle through which the wheel has turned 58.9 s after it begins rotating is approximately 1709.67 rad.

Explanation:

To solve the question we note the equation for the motion of the flywheel as

ω₂ = ω₁ + α·t

Where:

ω₁ = Initial angular velocity = 0 rad/s as the body is initially at rest

ω₂ = Final angular velocity

α = angular acceleration = 1.35 rad/s²

t = Time = 28.3 s

Plugging in the values, we find ω₂

ω₂ = 0 + 1.35 rad/s²× 28.3 s = 38.205 rad/s

Since the acceleration is constant, only the mean velocity is required to determine the angle traveled during the first 28.3 seconds thus

Average velocity

ω[tex]_{average}[/tex]= [tex]\frac{Final .Velocity +Initial . Velocity}{2} = \frac{\omega_2+\omega_1}{2} = \frac{38.205 rad/s+0 rad/s}{2}[/tex]

= 19.1025 rad/s

The total angle traveled in 28.3 s is ω[tex]_{average}[/tex] × time

= 19.1025 rad/s × 28.3 s = 540.60075 rad

After this the remaining time left is

58.9 s - 28.3 s = 30.6 s

Since the flywheel is moving at a constant velocity of 38.205 rad/s during the last 30.6 s we have

Angle traveled in 30.6 s at an angular velocity of 38.205 rad/s is given by

Angle traveled = Time × Angular velocity = 30.6 s × 38.205 rad/s

= 1169.073 rad

Therefore, the total angle traveled by the flywheel in 58.9 s is given by

540.60075 rad + 1169.073 rad = 1709.67375 rad ≈1709.67 rad.

the total angle traveled by the flywheel in 58.9 s ≈ 1709.67 rad.

Answer:

The acceleration of the refrigerator is [tex]a= 0.056 ms^{-2}[/tex]

Explanation:

The expression of the equation of the net force acting on the refrigerator is as follows;

F-f= ma

Here, F is the applied force, f is the force of friction, m is the mass and a is the acceleration.

It is given in the problem that you're having a hard time pushing a refrigerator having mass 355 kg across the kitchen floor. The force of your own push is 993 N. The force of friction opposing your own push is 973 N.

Put F= 993, f= 973 N and m = 355 kg in the above expression of the equation to calculate the acceleration of the refrigerator.

993 - 973 = (355)a

20 = 355 a

[tex]a= 0.056 ms^{-2}[/tex]

Therefore, the acceleration of the refrigerator is [tex]a= 0.056 ms^{-2}[/tex].

The refrigerator's acceleration is 0.0563 m/s², calculated by subtracting the force of friction from the pushing force and then dividing by the refrigerator's mass.

To find the acceleration of the refrigerator, we first need to calculate the net force acting on it. The net force is the difference between the force of the push and the force of friction.

Step 1: Calculate the Net Force

Net Force = Force of the push - Force of friction
Net Force = 993 N - 973 N
Net Force = 20 N

Step 2: Apply Newton's Second Law of Motion

According to Newton's Second Law of Motion, the acceleration (a) can be calculated using the formula:

a = Net Force / Mass

Substituting the known values:

a = 20 N / 355 kg
a ≈ 0.0563 m/s²

The refrigerator's acceleration when being pushed across the kitchen floor is approximately 0.0563 meters per second squared.

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Answer:

Where the height of the cap is less than or equal to the radius of the bore of the plastic pipe then the ⇵⇵shear stress  is less than o equal to 60 psi.

Explanation:

Shear stress = F/A

where F = Applied force

A = Cross sectional area of the member experiencing the force

If the cap covers a section of the pipe of height, h then the area = 2πrh

Where the 60 psi pressure is acting on the pipe bore, we have P₀ = 60 psi  = F₀/A₀ where A₀ = area of pipe bore ≈ πr². Therefore if F₀ = F then we have

F₀/A₀ = F₀/πr² and F/A = F₀/2πrh = where h greater than or equal to 0.5×r then the shear stress is less than or equal to 60 psi

To calculate the shear stress in the adhesive, use the formula for shear stress and the given pressure and area.

To calculate the shear stress present in the adhesive, we can use the formula for shear stress:

Shear stress = Force / Area

In this case, the force exerted by the water pressure on the capped end of the pipe is equal to the pressure multiplied by the area of the capped end. Since the water pressure is given as 60 psi, we need to convert it to a consistent unit, such as Pascals. 1 psi is equal to approximately 6895 Pascals. The area of the capped end can be calculated using the formula for the area of a circle: Area = pi * radius^2.

Once we have the force and area, we can substitute them into the formula for shear stress to find the value.

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Augmented reality has the potential to superimpose digital data over real photos so that GPS maps can be combined with real pictures of stores and streets to help people locate their position.

Explanation:

An engaging perception of an original globe atmosphere, where by computer-generated perceptual knowledge the transformation of real-world entities take place and also by multiple sensory modalities, involving somatosensory, visual, auditory, haptic and olfactory forms, thus known as augmented reality.

AR app uses GPS and camera from a smartphone to deploy an augmented reality-enabled GPS navigation system. As in the web, AR tool termed as Real View Navigation is accessible to all Android and iOS clients. Google is brought its first virtual reality walking directions, now recognized as Live Experience on Google Maps.

Answer:

height of tower= 78.48 meters

Explanation:

So here are your givens:

time(t)= 4 s.

initial velocity(u) = 0 m/s

acceleration due to gravity (g)= 9.81 m/s^2

distance(s)=s meters

using one of Newton's equation of motion ;

[tex]s=ut+\frac{1}{2} gt^{2} \\s=0(4)+\frac{1}{2}(9.81)(4)^{2} \\s=\frac{1}{2} (9.81)(16)\\s=\frac{156.96}{2} \\s=78.48[/tex]

height of the tower from the ground=total distance covered by bearing

height of tower= 78.48 meters

Final answer:

The shot tower needs to be at least 78.4 meters tall for a ball bearing to solidify in 4.0 seconds given the acceleration due to gravity.

Explanation:

Calculating the Height of the Shot Tower

To determine how high the tower must be for a ball bearing to solidify in 4.0 seconds, we can use the kinematic equation for free-fall motion without initial velocity, which is h = 1/2gt², where h is the height, g is the acceleration due to gravity (9.8 m/s² on Earth), and t is the time in seconds. For t = 4.0 seconds, we get:

h = 1/2 * 9.8 m/s² * (4.0 s)²

h = 1/2 * 9.8 * 16

h = 4.9 * 16

h = 78.4 meters

Therefore, the shot tower must be at least 78.4 meters tall to allow a ball bearing to solidify in mid-air within 4.0 seconds before impact.